A teacher has $230 in a bank account to spend on school supplies and wins an additional $50 to put toward the school supplies. The teacher spends $120 on binders for students and wants to buy the classroom a new $180 tablet.

Answer: 8 14/15

Step-by-step explanation:

2 1/3 + 6 3/5 =

2+1/3 + 6+3/5=

2+6+1/3+3/5=

8+1/3+3/5=

8+(1/3+3/5)*15/15=

8+(1*15/3+3*15/5)/15=

8+(15/3 + 45/5)/15=

8+(5+9)/15=

8+14/15=8 14/15

Answer:

well 22

Step-by-step explanation:

what is the answer to the answer to the answer to the answer to the same the whole of I will tell is the best of the whole time I will tell u won't let go and see if you have any questions or concerns please visit

The length of the pieces of wire include 23.5425 inches and 75.4565 inches.

Given the total length of wire is

X+Y=100

Y=100-X

Then we bend the two pieces into squares so that the sides of each square are X/4 and (100-X)/4. Therefore

(X/4)² + [(100-X)/4]² =400

X² +10000-200X +X² =6400

X²-100X+1800=0

Solving the equation

X = 76.4565 inches and X=23.5425 inches

Therefore, the length of the pieces of wire include 23.5425 inches and 75.4565 inches.

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Number of matinee tickets = 900

Number of student tickets = 1800

Number of regular tickets = 5800

Let x be the number of matinee tickets.

In that case, the number of  student tickets is 2x.

The number of regular  tickets is (8500-x-2x) = (8500-3x).

Total money

5x + 6*(2x) + 8.50*(8500-3x) = 64600

Simplifying and solving for x

5x + 12x - 8.50*3*x + 8.50*8500  = 64600

5x + 12x - 8.50*3*x = 64600 - 8.50*8500

Solving x , we get

x = 900

Number of matinee tickets = 900

Number of student tickets = 1800

Number of regular tickets = 8500 - (900+1800) = 5800

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Answer: I hope this helps.

Step-by-step explanation:

The domain of the function is the set of all real values

The equation of the function is given as:

f(x) = |2x + 5| + 3

The above function is an absolute value function

All absolute value functions can take any value as their input

This means that the given function can take any value as its input

Hence, the domain of the function is the set of all real values

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Answer:

0.15 miles per minute or 9 miles per hour

Step-by-step explanation:

The lateral area of  right octagonal prism = 672 in^2.

An example of a prismatic uniform polyhedron is the octagonal prism, or op. There are 2 octagons as well as 8 squares in it. Each vertex connects two squares and one octagon. As the name implies, it is an octagonal-based prism.

Three-dimensional geometry is a solid figure, item, or shape comprising three dimensions—length, breadth, as well as height.. Three-dimensional structures have height, which is equivalent to thickness or depth, unlike two-dimensional shapes.

Solve for lateral surface area:

altitude = 12

base = 7

AL=8ah

Putting the value we get:

AL=8 * 12 * 7

Al = 672 in^2

the lateral area of  right octagonal prism = 672 in^2.

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Answer:

Step-by-step explanation:

-5 = n - 3

- 5 + 3 = n

-2 = n

--------------

check

-5 = -2 - 3

-5 = -5

the answer is good

The radioactive substance remaining after 43 hours is: 62.7273 mg by unitary method.

A single unit's value can be determined from the values of multiple units, and multiple units' values can be determined from the values of single units using the unitary method.

Now,

Given that 180 mg is present at t = 0 hours.

After t = 33 hours, substance left = 90mg

By unitary method, after = 1 hour, substance left = [tex]180-\frac{90}{33}=180 -\frac{30}{11}[/tex]mg

The substance left after t = 43 hours = [tex]180 - \frac{30\times43}{11}= 180 - \frac{1290}{11}=180 - 117=62.7273mg[/tex]

Hence, The radioactive substance remaining after 43 hours is: 62.7273 mg by unitary method.

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Answer:

1.25 a pound

Step-by-step explanation:

if it was 1.20 per pound it would be less money

(a)Symmetric matrix -

Let matrix A be of order 3×3 =

                                  [tex]\left[\begin{array}{ccc}1&3&8\\3&8&-4\\8&-4&6\end{array}\right][/tex]

So, the transpose of A will be -

A' =

                                  [tex]\left[\begin{array}{ccc}1&3&8\\3&8&-4\\8&-4&6\end{array}\right][/tex]

So, we can say that A=A'. So, it is symmetric.

(b) Skew - symmetric matrix -

Let us consider a matrix B =

                                  [tex]\left[\begin{array}{ccc}0&-6&4\\-6&0&7\\4&7&0\end{array}\right][/tex]

matrix B is said to be skew-symmetric if aij =−aji.

(B' =−B)

B'  =    

                                 [tex]\left[\begin{array}{ccc}0&6&-4\\6&0&-7\\-4&-7&0\end{array}\right][/tex]

(c) A + A′ is a symmetric matrix for any square matrix A with real number entries, whereas A - A′ is a skew-symmetric matrix.

Proof: If B = A + A', then B ′ = (A + A ) ′

(A + B)′ = A′ + B′, thus = A′ + (A′)′

(as (A′)′ =A) = A′ + A

= B (because B + A = B + A′)

B = A+A′ is a symmetric matrix as a result.

Let C now equal A-A′.

Why does C' equal (A-A′)′=(A′)′?

= A′ - A (Why?)

=- (A - A′) = - C

A - A′ is a skew-symmetric matrix as a result.

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[tex]~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]vertex \begin{cases} x=4\\ y=7 \end{cases}\implies y=a(x-4)^2 +7~\hfill \textit{we also know that} \begin{cases} x=6\\ y=19 \end{cases} \\\\\\ 19~~ = ~~a(6-4)^2 +7\implies 12=a(2)^2\implies \cfrac{12}{(2)^2}=a\implies 3=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\LARGE \begin{array}{llll} y=3(x-4)^2 + 7 \end{array}} ~\hfill[/tex]

Answer: there are 6 servings

Step-by-step explanation:

[tex]\displaystyle\\6\frac{3}{4}:1\frac{1}{8} =\\\\\frac{6*4+3}{4} :\frac{1*8+1}{8} =\\\\\frac{24+3}{4}:\frac{8+1}{8}=\\\\\frac{27}{4}:\frac{9}{8}=\\\\\frac{27}{4}*\frac{8}{9} =\\\\ \frac{27*8}{4*9} =\\\\\frac{3*9*4*2}{4*9} =\\\\3*2=\\\\6[/tex]

The triangle with vertices located at U(-5 , 5), K(-5 , -1), and L(1 , 2) has its centroid located at (-3 , 2).

The centroid of a triangle is the point inside the triangle where the three medians intersect. The median of a triangle is the line the connects the midpoint of a side and the opposite vertex.

To get the centroid of a triangle, use the formula given by:

C(x , y) = [(x1 + x2 + x3)/3 , (y1 + y2 + y3)/3]

where C is the centroid of the triangle located at (x , y)

x1, x2, and x3 are the x-coordinate of the vertices of the triangle

y1, y2, and y3 are the y-coordinate of the vertices of the triangle

Let Point 1(x1 , y1) = U(-5 , 5)

Point 2(x2 , y2) = K(-5 , -1)

Point 3(x3 , y3) = L(1 , 2)

Plug in the values in the formula.

C(x , y) = [(x1 + x2 + x3)/3 , (y1 + y2 + y3)/3]

C(x ,y) = [(-5 + -5 + 1)/3 , (5 + -1 + 2)/3]

C(x ,y) = (-9/3 , 6/3)

C(x ,y) = (-3 , 2)

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The total value of the furniture she sold is $4400.

Let the remaining sales be represented by x.

She receives 10% of her first $900 in sales and 15% of the balance of her sale.

This will be:

(10% × $900) + (15% × x) = 750

90 + 0.15x = 750

Collect like terms

0.15x = 750 - 90

0.15x = 660

Divide

x = 660/0.15

x = 4400

Therefore, the total value is $4400.

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Answer: End of chain

Step-by-step explanation:

Dog is at pole and cat is at 8 meters if the dog runs at 12 meters a sec and cat runs at 10 in 2 secs the dog will reach end of chain. But the dog needs 4 secs to reach cat because the dog runs 2 meters a second faster than the cat. Hope it Helps!

The expression that represents the statement "four less than the product of 2 and a number g" is 2 g - 4.

We are given a statement:

four less than the product of 2 and a number g

We need to form an expression to represent that statement.

An expression is a combination of variables and constants by using the various operations of mathematics like addition, subtraction, division and multiplication.

So, first we will find the product of 2 and a number g.

This is:

2 × g = 2 g

Now, we will subtract 4 from the expression:

2 g - 4

Therefore, the expression that represents the given statement "four less than the product of 2 and a number g" is 2 g - 4.

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The answer choice which correctly represents an equivalent expression to that which is given as in the task content is; −30 + (−70) + (−40).

It follows from the task content that the expression whose equivalent is to be determined is; −30 + (−40) + (−70).

Therefore, since it follows from the associative property of addition that;

a + b + c = a + c + b.

Therefore, same can be said for the expression as given in the task content where;

-30 + (-40) + (-70) = -30 + (-70) + (-40).

Ultimately, the required equivalent expression is; −30+(−70)+(−40); negative 30 plus open parenthesis negative 70 close parenthesis plus open parenthesis negative 40 close parenthesis

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The answer is only 1

Answer:

125

Step-by-step explanation:

105 - (-20) = 105 + 20 = 125

Answer:

21

Step-by-step explanation:

The value of x on the line segment is 8

The given parameters are:

AB = 2x + 7

AC = 7x - 3

BC = 4x - 2

The above means that the point B is on the line segment AC

So, we have:

AC = AB  + BC

This gives

2x + 7 + 4x - 2 = 7x - 3

Evaluate the like terms

-x = -8

Divide both sides by -1

x = 8

Hence, the value of x on the line segment is 8

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Answer:

3/6

Step-by-step explanation:

2/3 = 4/6

(multiply 2 by 2 = 4, multiply 3 by 2 = 6)

4/6 - 1/6 = 3/6

Answer:

2x2/3x2-1/6

4/6-1/6=3/6=1/2

he used half for the day

hope this helps or may also he correct •-•

Answer:

For sure, A and C. However, I cannot fully read the last one.

Step-by-step explanation:

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The coordinates of the image of the vertices of the polygon are A''(x, y) = (1, - 2), B''(x, y) = (2, - 2), C''(x, y) = (0, - 1), D''(x, y) = (- 1, - 2) and E''(x, y) = (- 2, - 1).

Rigid transformations are transformations applied on geometric loci such that Euclidean distances in such constructions are conserved. Translations and dilations are common examples of rigid transformations.

If we know that A(x, y) = (- 6, 0), B(x, y) = (- 3, 0), C(x, y) = (0, - 3), D(x, y) = (- 3, - 6) and E(x, y) = (- 6, - 3), then the coordinates of the image are determined below:

Translation

A'(x, y) = (- 6, 0) + (9, - 6)

A'(x, y) = (3, - 6)

B'(x, y) = (- 3, 0) + (9, - 6)

B'(x, y) = (6, - 6)

C'(x, y) = (0, - 3) + (9, - 6)

C'(x, y) = (9, - 9)

D'(x, y) = (- 3, - 6) + (9, - 6)

D'(x, y) = (6, - 12)

Dilation

A''(x, y) = (1 / 3) · (3, - 6)

A''(x, y) = (1, - 2)

B''(x, y) = (1 / 3) · (6, - 6)

B''(x, y) = (2, - 2)

C''(x, y) = (1 / 3) · (0, - 3)

C''(x, y) = (0, - 1)

D''(x, y) = (1 / 3) · (- 3, - 6)

D''(x, y) = (- 1, - 2)

E''(x, y) = (1 / 3) · (- 6, - 3)

E''(x, y) = (- 2, - 1)

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Answer:

46, 94

Step-by-step explanation:

hope this works for you :)