The statement that a teacher sitting in her rolling chair pushes against the wall and moves in the opposite direction exemplifies the third law of motion by Newton.
What is Newton's third law of motion?Newton's third law of motion states that for every action, there is an equal and opposite reaction.
This law describes the nature of a force as the result of a mutual and simultaneous interaction between an object 1 and a second object 2.
According to Newton's third law of motion, whenever two objects A and B interact with each other, they both exert equal but opposite forces upon each other.
Therefore, the statement that a teacher sitting in her rolling chair pushes against the wall and moves in the opposite direction exemplifies the third law of motion by Newton.
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At Boston's Fenway Park, it is 310 feet (94.5 m) from homeplate to the left field wall The Green Monster which is 30 feet (9.2 m) high. If a batter hits a baseball at an initial height of 0.9 m, given the following velocities, does it clear the wall, hit the wall, or fall short?
If the velocity of x direction is 25 m/s
If the velocity of y direction is 20.5 m/s
Find the maximum height
Baseball will hit the wall due to less height from the The Green Monster wall.
from the data, we have in
velocity of x direction is 25 m/s
velocity of y direction is 20.5 m/s
now, the horizontally:
velocity=distance/time
time=distance/velocity
time=94.5/25
t=3.76sec
now for vertically: we will apply kinematics equation
s=ut+[tex]\frac{at^2}{2}[/tex]
now putting the values,
s=77.08-69.27
s=7.80m
now,
the initial height from baseball hit=0.9m
now, total height=0.9+7.80
s=8.7
8.7 m is less than wall height
so it will hit the wall
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A skateboarder initially traveling at 1.8 m/s accelerates at a rate of 1.5 m/s² for 2.5 s. How far does the skateboarder go in this time?
The skateboarder will travel a distance of 9.19 m
We know that,
a = ( v - u ) / t
Δv = ( v + u ) / 2 ( If acceleration is constant )
Δv = d / t
where,
a = Acceleration
v= Final velocity
u = Initial velocity
t = Time taken
d = Displacement
Δv = Average velocity
Given that,
u = 1.8 m / s
a = 1.5 m / s²
t = 2.5 s
a = ( v - u ) / t
1.5 = ( v - 1.8 ) / 2.5
v = 3.75 + 1.8
v = 5.55 m / s
Δv = ( 5.55 + 1.8 ) / 2
Δv = 3.675 m / s
d = Δv * t = 3.675 * 2.5
d = 9.19 m
If the initial and final velocity is known, average velocity can be calculated by taking the average value of initial and final velocity, if the acceleration is constant.
Therefore, the skateboarder will travel a distance of 9.19 m
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A pelican flying along a horizontal path drops a fish from a height of 7.8 m. The fish travels 12.0 m horizontally before it hits the water below. What is the pelican’s initial speed? At what velocity does the fish hit the water?
Answer:
The pelican was travelling at approximately [tex]9.5\; {\rm m\cdot s^{-1}}[/tex] when it dropped the fish.
The fish hit the water at approximately [tex]16\; {\rm m\cdot s^{-1}}[/tex].
(Assumption: air resistance on the fish is negligible; [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex].)
Explanation:
During the descent:
In the horizontal direction, the fish travels at a constant velocity.In the vertical direction, the fish accelerates downwards at a constant rate of [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex] under gravity.Since acceleration in the vertical direction is constant, make use of the SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] to find the duration [tex]t[/tex] of the descent:
The vertical position of the fish changed by [tex]x = 7.8\; {\rm m}[/tex] during the entire descent. The vertical acceleration of the fish is [tex]a = g = 9.81\; {\rm m\cdot s^{-2}}[/tex]The pelican was flying horizontally when it dropped the fish. Thus, the initial velocity of the fish in the vertical direction is [tex]v_{0} = 0\; {\rm m\cdot s^{-1}}[/tex]. The equation becomes [tex]x = (1/2)\, a\, t^{2}[/tex].Rearrange this equation to find the duration of the descent, [tex]t[/tex]:
[tex]\begin{aligned} t &= \sqrt{\frac{2\, x}{a}} \\ &= \sqrt{\frac{2 \times 7.8\; {\rm m}}{9.81 \; {\rm m\cdot s^{-2}}} \\ &\approx 1.261\; {\rm s}\end{aligned}[/tex].
The vertical speed of the fish right before impact would be:
[tex]\begin{aligned} v_{y} &= a\, t \\ &\approx 9.81\; {\rm m\cdot s^{-2}} \times 1.261\; {\rm s} \\ &\approx 12.37\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].
In the horizontal direction, the speed of the fish was constant- same as the initial speed of the pelican. The fish travelled a horizontal distance of [tex]x = 12.0 \; {\rm m}[/tex] within the [tex]t \approx 1.26\; {\rm s}[/tex] of the descent. As a result, the horizontal velocity of the fish would be:
[tex]\begin{aligned} v_{x} &= \frac{x}{t}\\ &\approx \frac{12.0\; {\rm m}}{1.261\; {\rm s}} \\ &\approx 9.52\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].
Hence, the initial speed of the pelican would be approximately [tex]9.5\; {\rm m\cdot s^{-1}}[/tex].
Thus, right before impact:
The fish would be travelling at a horizontal velocity of [tex]v_{x} \approx 9.52\; {\rm m\cdot s^{-1}}[/tex].The fish would be travelling at a vertical velocity of [tex]v_{y} \approx 12.37\; {\rm m \cdot s^{-1}}[/tex].Apply the Pythagorean Theorem to find the overall velocity of the fish at that moment:
[tex]\begin{aligned} v &= \sqrt{{v_{x}}^{2} + {v_{y}}^{2}} \\ &\approx \sqrt{{(9.52\; {\rm m\cdot s^{-1}})}^{2} + {(12.37\; {\rm m\cdot s^{-1}})}^{2}} \\ &\approx 16\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
In other words, the fish would hit the water at approximately [tex]16\; {\rm m\cdot s^{-1}}[/tex].
Can a measurement ever be exact? Why or why not?
There is no such things as an exact measurement there can never be a perfect instrument or measurer.
What is measurement?The term measurement has to do with the process of obtaining the value of a quantity. We know that measurements are done in order to give us an idea of the magnitude of a quantity. In every measurement, there is an instrument that is used for the measurement. For instance, if I want to measure length, I may have to use a meter rule to do it.
Now, there are two ways that error could be introduced into a measurement;
1) By the instrument that is used
2) By the error of the measurer
Hence, there is no such things as an exact measurement there can never be a perfect instrument or measurer.
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Aliens are bombarding the Earth with asteroids from an orbit of 100km. If they launch the
asteroid with a speed of 100.0m/s, how long do the earthlings have to evacuate their city?
Distance is the overall motion of an object with no regard to its path. we can define distance as how much floor an item has included no matter it's beginning or ending point.
Given,
Distance = 100km
=100000
Speed =100m/sec
Distance=speed × time
Time= [tex]\frac{distance}{speed}[/tex]
Time =100000/100
time =1000 sec
Distance is a numerical or on occasion qualitative size of how far apart items or factors are. In physics or regular usage, the space might also check with a physical length or an estimation primarily based on other standards.
Displacement is described because of the alternate the function of an item. it's miles a vector amount and has a course and value. it's miles represented as an arrow that points from the beginning role to the very last function. as an example- If an item moves from A role to B, then the item's function modifications.
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1. Brittney Vargas undergoes 2 displacements while playing field hockey. First, she goes
26.5 m, West. She then turns and goes 18.7 m, South. What is Brittney's resultant
displacement? (Magnitude and direction!!!)
The resultant displacement is 32.4 m due west of south.
What is the displacement?The term displacement has to do with the change in the position of a body in a particular direction. Displacement is a vector quantity. We have to find the resultant displacement algebraically;
Hence;
Resultant displacement = √((26.5)^2 + 18.7)^2
Resultant displacement = 32.4 m due west of south
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Q. If the amplitude of the two
waves are 3 units and unit
respectively. Show by the
principle of superposition
that the ratio of the
amplitudes Of the stationary
wave at an antinode and
node is 2:1
That would be the proportion between the difference and the total of the two amplitudes (when they are in phase, or as they say, "add coherently") (when they are out of phase or "add destructively").
What is a wave's amplitude?The amplitude of a wave is the maximum displacement of a particle on the medium from its rest point. The distance between the rest and the crest can be thought of as the amplitude. Measuring the amplitude from the rest position to the trough position is another method of determining it.
How can amplitude be determined?The height between the center line and the peak is known as the amplitude (or to the trough). Alternatively, we might multiply the height from highest to lowest places by 2.
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A bicycle was traveling at 7.6 m/s when it decided to accelerate at a rate of 4.2 m/s² over 89 m. What was its final velocity?
The final velocity of the bicycle with initial velocity 7.6m/s and acceleration 4.2 m/s² is 28.4 m/s.
What is Velocity?
velocity is defined as the displacement per unit time.
What is Acceleration?
Acceleration is defined as the rate of change of velocity per unit time
i.e.
acceleration = (final velocity (v)-initial velocity)/time taken (t)
given:
initial velocity of the bicycle (u) = 7.6m/s
acceleration of the bicycle (a)=4.2m/s²
displacement of the bicycle=89m
using newtons third law of motion :
v²-u²=2×a×s
using the given value in question we get
v² = (7.6)²+2×4.2×89
v=28.4 m/s
the final velocity of the bicycle with initial velocity 7.6m/s and acceleration 4.2 m/s² is 28.4 m/s.
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A river is moving east at vWE = 2.29 m/s. A boat starts from the dock heading θ = 39.3 degrees north of west at vBW = 7.18 m/s, relative to the water. The river is w = 1130 m wide.
What is the speed of the boat, in m/s, with respect to Earth?
Answer:
The speed of the boat, in m/s, with respect to Earth, is vBE = 7.52 m/s.
Explanation:
vBE = vBW + vWE
vBE = 7.18 m/s + 2.29 m/s
vBE = 7.52 m/s
If one oscillation has 3.0 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?
The ratio of their amplitudes is 3.
The relation between energy and amplitude is as follows:
[tex]E_{1} = \frac{1}{2} KA_{1} ^{2}[/tex]
[tex]E_{2} =\frac{1}{2} KA_{2} ^{2}[/tex]
As, we know , one oscillation has 3.0 times the energy of a second one of equal frequency and mass i.e.,
[tex]E_{1} = 3E_{2}[/tex]
So, [tex]\frac{1}{2} KA_{1} ^{2} = 3(\frac{1}{2}KA_{2} ^{2} )[/tex]
[tex]A_{1} ^{2} = 3A_{2} ^{2}[/tex]
[tex]\frac{A_{1}^{2} }{A_{2}^{2} } = 3[/tex]
Therefore, the ratio of their amplitudes is 3.
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Many traffic lights charge when a car roll up intersection. How does the light sense the presence of car? Describe briefly.
Answer:
There are a few ways that traffic lights can sense the presence of a car. One way is by using inductive loops that are installed on the road. These loops detect changes in the magnetic field caused by a car passing over them. Another way is by using infrared sensors that detect the heat signature of a car.
Explanation:
Hope this helps!
A circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA (milliAmps). Determine the new current if the voltage of the power supply was ...increased by a factor of 3 and the resistance was held constant
If the voltage of the power supply is increased by a factor of 3 and the resistance was held constant, the new current will be 0.008 A or 8 mA
What is Power ?Power is the rate at which work is done. Electrical power is measured in Watt.
Given that a circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA Determine the new current if the voltage of the power supply was increased by a factor of 3 and the resistance was held constant
Let the
initial voltage = VNew voltage = 3VResistance = RInitial current = 24 mANew current = ?From the power formula, power will always be constant. That is, initial power will be the same with new power
Since P = IV
24/1000 V = I × 3V
0.024V = 3IV
V cancels out
3I = 0.024
I = 0.024/3
I = 0.008 A
Therefore, the new current will be 0.008 A.
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Two point charges Q₁ = +6.00 nC and Q₂ = -2.00 nC are separated by 45.0 cm.
(a) What is the electric potential at a point midway between the charges?
V
(b) What is the potential energy of the pair of charges?
J
What is the significance of the algebraic sign of your answer?
Positive work must be done to separate the charges.
Negative work must be done to separate the charges.
Answer:
(a) The electric potential at a point midway between the charges is 160 V.
(b) The potential energy of the pair of charges is -2.4x10⁻⁷ J.
What is electrical potential energy?
The effort necessary to assemble a system of point charges by bringing them close together, as in the system from an infinite distance, is defined as the electric potential energy of the system. Alternatively, the electric potential energy of any given charge or system of charges is defined as the total work performed by an external agent in moving the charge or system of charges from infinity to the current configuration without acceleration.
Explanation:
The electric potential at a point between two point charges Q₁ = +6.00nC and Q₂ = -2.00 nC separated by 45.0 cm is found to be 160 V and the potential energy of the pair of charges is -2.4 x 10⁻⁷ J.
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Two small objects A and B are fixed in place and separated by a distance of 3.00 cm in a vacuum. Object A has a
charge of +2.00 С and object B has a charge of -2.00 C. How many electrons must be removed from object A and
placed on object B to make the electrostatic force into an attractive force with a magnitude of 68.0 N.
The number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]
We know that,
E = k [tex]q_{1}[/tex] [tex]q_{2}[/tex] / r²
where,
E = Electrostatic force
k = Coulomb's constant
[tex]q_{1}[/tex], [tex]q_{2}[/tex] = Point charges
r = Distance between two charges
Given that,
[tex]q_{1}[/tex] = 2 + ne C
[tex]q_{2}[/tex] = - 2 - ne C
r = 3 cm
k = 9 * [tex]10^{9}[/tex] N m² / C²
E = - 68 N ( Since it is attractive )
- 68 = 9 * [tex]10^{9}[/tex] ( 2 - ne ) ( - 2 + ne ) / ( 3 * [tex]10^{-2}[/tex] )²
68 * [tex]10^{-4}[/tex] / 3 * [tex]10^{9}[/tex] = ( 2 - ne )²
2.27 * [tex]10^{-12}[/tex] = ( 2 - ne )²
1.5 * [tex]10^{-6}[/tex] = 2 - ne
ne = 1.98
n = 1.98 / 1.6 * [tex]10^{-19}[/tex] = 1.24 * [tex]10^{19}[/tex]
The given problem is an electrostatic attractive force because the two point charges are unlike charges. If the charges are like, then the electrostatic force will be repulsive.
Therefore, the number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]
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how much would i weigh on the star methuselah i weigh 100 pounds
Your weigh on the star methuselah is 38 pounds.
For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.
The element mercury has the atomic number 80 and the symbol Hg. Formerly called hydrargyrum from the Greek words Hydor (water) and Argyros, it's also known as quicksilver (silver). the sole other metallic element that is known to be liquid at standard circumstances for temperature and pressure is the halogen bromine, while metals like cesium, gallium, and rubidium melt just above temperature. Mercury may be a heavy, silvery d-block element.
Worldwide deposits of mercury, primarily as cinnabar, are found (mercuric sulfide). Grinding either synthetic mercuric sulfide or natural cinnabar yields the red color vermilion.
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A race car traveling at 33 m/s accelerates at a rate of 0.8 m/s2 for 20 s. What is the final speed of the race car?
A. 42.4 m/s
B. 61.3 m/s
C. 49.0 m/s
D. 10.4 m/s
The final speed of the race car, given the data is 49 m/s (Option C)
What is acceleration?The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the timeWith the above formula, we can determine the final velocity of the car. Details below:
How to determine the final velocity of the car Initial velocity (u) = 33 m/sAcceleration (a) = 0.8 m/s²Time (t) =20 s Final velocity (v) = ?a = (v – u) / t
0.8 = (v – 33) / 20
Cross multiply
v – 33 = 0.8 × 20
v – 33 = 16
Collect like terms
v = 16 + 33
v = 49 m/s
Thus, the final velocity of the car is 49 m/s (Option C)
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Study Island!!!!!
The average annual snowfall values for four different cities are shown in the table below.
which of the following conclusions could be made from this data?
A. It snows more in Green Bay than in Buffalo on average.
B. It snows less in Green Bay than in Kalamazoo on average.
C. It snows more in Kalamazoo than in Buffalo on average.
D. It snows less in Buffalo than in Bristol on average.
Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.
.
What snow implies?The term snows is known to be a kind of a small white crystals of ice that is known to be formed as a result of direct water vapor of the air.
It is known to be a measure or a mass of snowflakes that is said to have fallen to earth.
Therefore, from the data, one can see that the snow fell a lot in Buffalo and from it one can also see that Kalamazoo has almost times 2 of the snow in Green Bay.
Therefore, Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.
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what is the velocity of a car that traveled a total of 75 km north in 1.5 hours
Answer:
Velocity is distance + direction / time
so your answer is
75 km north / 1.5 hours
75/1.5 km north/ hours =
50 km / hours north
What is the amperage of a current flowing through a wire that has a resistance of 30 ohms if the voltage is 90 volts?
12 ohms
2700 amps
3 amps
4 volts
A person weighs 1,913 N on earth. They are taken to a planet where the gravity is 0.6 times the gravity of earth. What is their new weight?
Answer: gravity of earth = 9.8 n/s , new weight of the body on other planet = mg = 1.913 ×6×9.8=112..5
Explanation:
jasmine broke the antenna k. her radio receiver how will this most likely affect jasmine radio?
Answer:An antenna is an array of conductors, that is connected to the receiver or transmitter.
It transmits and receives radio waves in the horizontal directions or in a particular direction.
It may include a parasitic elements, and reflectors that can serve to direct the radio waves into a beam like pattern or some other patter.
Explanation:
It will not capture modulated radio waves.
An object is moving forward along a straight path. Find the object’s position relative to it’s starting point if it moves 12.8 cm/s for 0.5 min.
The distance traveled by the object from its initial position is 384 cm.
Distance is the sum of an object's movements, regardless of direction. Without respect to the object's starting or finishing positions, distance can be defined as the amount of space it has traveled.
An object is moving in a straight path.
The speed of the object from its initial position is 12.8 cm/s.
The object is moving for 05 minutes.
Then, t = 0.5 min = 0.5 × 60 = 30 seconds.
Now, the speed of an object is the distance of the object per unit time.
Therefore,
s = d / t
d = s × t
d = ( 12.8 cm/s ) × ( 30 s )
d = 384 cm
Hence, the object's position from its initial position is 384 cm.
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How many acres are in 1 square mile? One acre is equal to 43,560 ft2.
Answer:
There are 640 acres in 1 square mile I think
If you were a member of Congress, what legislation would you introduce if acid rain from a coal
There are many reasons. The easiest solution is because the rain that we remember acidic has a low pH; it has a better amount of hydrogen ions.
Acid rain manipulation implies three adjustments a notably extra complicated and cumbersome regulatory program beneath the Clean Air Act, new emission manipulation prices for initial rollback requirements and next offsets, and on account of these, new impediments to utility and commercial plant creation, expansion, and modernization.
The Acid Rain application (ARP) has brought widespread discounts in sulfur dioxide (SO2) and nitrogen oxide (NOX) emissions from fossil fuel-fired strength flora, full-size environmental and human fitness blessings, and a ways lower-than-anticipated prices.
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the magnitude of B-3A
Answer:
the magnitude of b 3A
Explanation:
2b 1 a
A fishing boat leaves a marina with a constant speed of 3.4 m/s. A speedboat leaves the marina 12 s later with an initial speed of 2.8 m/s and an acceleration of 1.7 m/s2. Let the time the speedboat leaves the marina be t = 0 and let the direction of travel of both boats be the positive x direction.
Write position-time equations for fishing boat.
Express your answer in terms of t .
When does the speedboat catch up with the fishing boat?
(a) The position-time equations for fishing boat is x = 3.4t + 40.8
(b) The time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.
Position-time equations for fishing boat
The position-time equations for fishing boat will be obtained by applying the principle of relative velocity as follows;
Let the time when the speedboat catches up = t
let the total time spent by fishing boat = t + 12
Distance traveled by the fishingx = 3.4(t + 12)
x = 3.4t + 40.8
Distance between between the fishing boat and speed boatfishing boat is moving at a constant speed = 3.4 m/s
speed boat started moving 12 seconds later,
distance between the boats = 3.4 m/s x 12 s = 40.8 m
final velocity of the speedboatv = u + at
v = 2.8 + 1.7t
set up the following equation to determine the time when the two boats meet.
vt - x = 40.8
t(2.8 + 1.7t) - (3.4t + 40.8) = 40.8
2.8t + 1.7t² - 3.4t - 40.8 = 40.8
1.7t² - 0.6t - 81.6 = 0
solve the quadratic equation using formula method as shown below;
a = 1.7, b = -0.6, c = -81.6
t = 7.1 seconds
Thus, the time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.
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Number of Humans
(Billions)
The World's Population Growth
7.0-
6.0
5.0-
4.0
3.0
2.0-
1.0-
0
1000
1200
+
1400
1600
1800
2000
Answer: The world population increased from 1 billion in 1800 to around 8 billion today. The world population growth rate declined from around 2% per year 50
Explanation:
3. Describe what black holes are?
Answer: a place in space where gravity pulls so much that even light can not get out.
Answer:
black holes are holes that can suck this world with its high gravity
A bike accelerates from 0 m/s to 15 m/s over the span of 5 seconds. How fast is the bike
traveling after 2.5 seconds?
The bike is travelling at 22.5 m/s after 2.5 s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the acceleration Initial velocity (u) = 0 m/sFinal velocity (v) = 15 m/sTime (t) = 5 sAcceleration (a) =?a = (v – u) / t
a = (15 – 0) / 5
a = 3 m/s²
How to determine the final velocity in the first 2.5 s Initial velocity (u) = 15 m/sAcceleration (a) = 3 m/s²Time (t) = 2.5 s Final velocity (v) = ?a = (v – u) / t
3 = (v – 15) / 2.5
Cross multiply
v – 15 = 3 × 2.5
v – 15 = 7.5
Collect like terms
v = 7.5 + 15
v = 22.5 m/s
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the velocity (v) of dimension of a, b and c.
According to the given statement The dimension of a, b and c is LT⁻² , L and T.
What do we mean by dimension?She took exact measurements of the room's length, width, height, and depth in one direction (for example, the distance between the ceiling and the floor of a room). The space was unexpectedly small in all three of its dimensions. Dimensions include length, breadth, and height. One dimension is that of a line, two dimensions are those of a square, and three dimensions are those of a cube (3D).
Briefing:According to the principle of dimensional homogenity
Dimension of v = dimension of at = dimension of b/t+c
Dimension of a = [tex]\frac{[\mathrm{v}]}{[\mathrm{t}]}=\frac{\mathrm{LT}^{-2}}{\mathrm{~T}}=\left[\mathrm{LT}^{-2}\right][/tex]
Dimension of b = [v][t]=[LT −1 T]=[L]
Dimension of c = [t]=[T]
According to the given statement The dimension of a, b and c is LT⁻² , L and T.
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