Answer:
0.00222km/s
Explanation:
[tex]Distance = 0.2km\\Time = 1\:minute \:30\:seconds = 90\:seconds\\\\Average \:speed =?\\\\Average \:speed = \frac{0.2}{90} \\A.V = 0.002222\\A.V =0.00222[/tex]
Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.8 km/h due east. Runner B is initially 4.2 km east of the flagpole and is running with a constant velocity of 7.6 km/h due west. How far are the runners from the flagpole when their paths cross? Answer in units of km.
Answer:
0.39 km west
Explanation:
The position of Runner A is:
x = -5.7 + 8.8 t
The position of Runner B is:
x = 4.2 − 7.6 t
When the positions are equal:
-5.7 + 8.8 t = 4.2 − 7.6 t
16.4 t = 9.9
t = 0.604
Plug into either equation to find the position at this time:
x = -5.7 + 8.8 (0.604)
x = -0.39
The runners are 0.39 km west of the flagpole when they meet.
A 1200N load is to be lifted with 200N effort using a first class lever. At what distance
from the fulcrum must the effort be applied when the load is 15 cm away from the
fulcrum?
[Ans: 90 cm]
Explanation:
Hey there!!
Let's simply work with it.
Here,
load = 1200N
Effort = 200N
Load distance = 15cm
We have,
According to the principle of lever.
L×LD = E×ED.
1200×15 = 200× ED.
18000 = 200ED.
[tex]ed = \frac{18000}{200} [/tex]
Therefore, Effort Distance = 90cm.
Hope it helps....
If length of wire is doubled keeping the diameter constant ,its Youngs modulus will be
Answer:
Y = Stress / Strain = (F / A) / (l / L) where l is the change in length
Since L is doubled and A remains the same one would expect l, the change in length to also double so Y remains the same.
As an example think of hanging a weight from a spring and the same weight from a similar spring of twice the length - one would expect the longer spring to show twice the extension of the shorter spring.
A number n plus 7 is less than or equal to 9.
Answer:
n=2
Explanation:
n+7=9
n=9-7
n=2
+ -= -
A uniformly charged rod (length = 2.0 m, charge per unit length = 3.0 nC/m) is bent to form a semicircle. What is the magnitude of the electric field at the center of the circle? Select one: O a. 64N/C b. 85N/C c. 34N/C 3 d. 133Njc -j e.48N/C
Answer:
The magnitude of the electric field at the center of the circle is 85 N/C
The correct option is b. 85 N/C
Explanation:
Please see the attachments below
What is the "symbol" and "unit" of Temperature?
What is the difference between velocity and vector
Answer:
vector is a physical quantity while velocity is a vector physical quantity
How do you find the number of ELECTRONS in an atom of an element?
Answer:
M-A=N
Explanation:
M-A=N
Here is an example.
The equation above means that the atomic number (A) subtracted from the average atomic mass (M) equals the combined amount of neutrons and protons. Since we know that 35 17Cl is Chlorine (this is because Chlorine (Cl) is the 17th number on the periodic table and has the average atomic mass of 35), we can insert our data into the equation and end up with the following:
35-17=18.
From here, we can tell that we have a mix of neutrons and protons, with the total being 18. Since the atomic number is 17, we can reasonably assume that there are 17 protons and 1 neutron.
But we still need to find the number of electrons. Fortunately, the number of electrons is always equivilant to the number of protons and the atomic mass, so we know that the number of electrons is 17.
So, we have;
17 Protons
1 Neutron
17 Electrons
which of the following is the longest distance A 5000 centimeters B 30 000 millimeters C 500 meters D 0.400 kilometers
Answer:
C
Explanation:
first we convert km,m,cm into mm then compare them
The longest distance is 0.400 Km among all the given distances. Therefore, option (D) is correct.
What are SI units of metric length?The metric system can be defined as a system that is used for the measurement that uses the liter, meter, and gram as base units of length, capacity, and weight respectively.
In the metric system, the SI unit of length is represented as a meter which can be defined as the metric length that is traveled by light in a vacuum within 1⁄29979258 seconds.
Some of the other units of distance include Kilometres, Millimetres, nanometers, Centimetres, Meters, and Decimeters.
Conver all the given distance into meters:
A) 5000 cm = 5000 × 10⁻² m = 50 m
B) 30000 mm = 30000 × 10⁻³ m = 30 m
C) 500 m = 500 × 1 = 500 m
D) 0.400 Km = 0.4 × 10³ = 400 m
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A suspect isnleading the police on a car chase the officer reports that the suspect is traveling north at 100 miles per hour the officer has reported the suspects
Answer:
Velocity.
Explanation:
It is given that, the officer reports that the suspect is traveling north at 100 miles per hour. It means the suspect covers a distance of 100 miles every hour and moving in North direction.
It shows the velocity of the suspect. This is because his speed and direction are given. Velocity is a vector quantity.
So, the officer has reported the suspect's velocity.
Randy has a sheet of paper. He cuts a square out of the center. Which of the following physical properties of the paper changes
Answer:
Mass
Explanation:
Answer:
mass
Explanation: less room is taken up
A ball is dropped , find the velocity after 100 m
Answer:
Vf = 44.27 m/s
Explanation:
When a ball is dropped it is acted upon by gravitational force under free fall motion. So, in order to find its final speed we use 2rd equation of motion, as follows:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height lost = 100 m
Vf = Final Velocity = ?
Vi = Initial velocity = 0 m/s (Since, ball starts from rest)
Therefore,
(2)(9.8 m/s²)(100 m) = Vf² - (0 m/s)²
Vf = √(1960 m²/s²)
Vf = 44.27 m/s
In order to make an object stop, what direction does the unbalanced force need to be applied?
pls help
will give the brainliest!
Urgent!!!!
please answer correctly
Electrons
Coulomb
Energy
Resistance
Lower
Your physics teacher is giving you a special gift a box of mass 20 kg with a mystery surpise insie .the box is placed on a frictionsed table .what is the weigth of the box and normal reaction over it by the table ?
Answer:
F = 196.2 N
Explanation:
Use Newtons law
F = m * a
F = 20 kg * 9.81 m/s²
F = 196.2 N
Answer:
[tex]\Huge \boxed{\mathrm{196.2 \ N}}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Explanation:
Using weight formula:
[tex]\sf Weight = mass \times acceleration \ of \ gravity[/tex]
[tex]W=mg[/tex]
The mass of the box is 20 kg.
The acceleration of gravity on Earth is 9.81 m/s².
[tex]W=(20)(9.81)[/tex]
[tex]W=196.2[/tex]
The weight of the box is 196.2 N.
The net force of the box is zero, since the box is at rest. The normal force is exerted upward on it by the table.
[tex]\rule[225]{225}{2}[/tex]
A rock is dropped from a height of 371 m. Approximately how much time will it take for the rock to hit the ground ? (Assume no air resistance.)
Answer:
1hr I guess is the best answer
A rigid tank contains 10 kg of an ideal gas at a pressure of 5 atm and a temperature of 30 oC. By opening a valve half of the mass of the gas is allowed to escape. In the final pressure in the tank is 1.8 atm, the final temperature in the tank, in oC, is
Answer:
T₂ = 218.16 k = -54.84°C
Explanation:
Consider, the general gas equation:
PV = nRT
where,
P = Pressure of Gas
V = Volume of Gas
n = No. of Moles of Gas = mass in gram/Molecular Mass = m/M
R = Gas Constant
T = Temperature of Gas
Now,
PV = mRT/M
P/mT = RM/V
since, RM/V = Constant values in both final and initial states.
therefore,
P₁/m₁T₁ = P₂/m₂T₂
T₂ = P₂m₁T₁/m₂P₁
where,
T₂ = Final Temperature = ?
P₂ = Final Pressure = 1.8 atm
m₁ = Initial Mass = 10 kg
P₁ = Initial Pressure = 5 atm
m₂ = Final Mass = 10 kg/2 = 5 kg
T₁ = Initial Temperature = 30°C + 273 = 303 k
Therefore,
T₂ = (1.8 atm)(10 kg)(303 k)/(5 kg)(5 atm)
T₂ = 218.16 k = -54.84°C
A bus took 8 hours to travel 639 km. For the first 5 hours, it
travelled at an average speed of 72 km/h. What was the
average speed for the remaining time of the journey?
km/h
Answer:
93 km/h
Explanation:
Given that a bus took 8 hours to travel 639 km. For the first 5 hours, it travelled at an average speed of 72 km/h
Let the first 5 hours journey distance = F
From the formula of speed,
Speed = distance/time
Substitute speed and time
72 = F/5
F = 72 × 5 = 360 km
The remaining distance will be:
639 - 360 = 279km
The remaining time will be:
8 - 5 = 3 hours
Speed = 279/3
Speed = 93 km/h
Therefore, the average speed for the remaining time of the journey is equal to 93 km/h
Se deja caer una pelota inicialmente en reposo desde una altura de 50m sobre el nivel del suelo. ¿cuanto tiempo requiere para llegar al suelo? ¿cual sera la rapidez de la pelota justo en el momento anterior del choque ?
Answer:
a) t = 3.2 s
b) [tex]v_{f} = -32 m/s [/tex]
Explanation:
a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:
[tex] t = \sqrt{\frac{2y_{0}}{g}} [/tex]
En donde:
[tex]y_{0}[/tex]: es la altura inicial = 50 m
g: es la gravedad = 10 m/s²
[tex] t = \sqrt{\frac{2y_{0}}{g}} = \sqrt{\frac{2*50 m}{10 m/s^{2}}} = 3.2 s [/tex]
Entonces, el tiempo requerido para llegar al suelo es 3.2 s.
b) La rapidez de la pelota justo antes del choque es el siguiente:
[tex] v_{f} = v_{0} - gt [/tex]
En donde:
[tex]v_{0}[/tex]: es la velocidad inicial = 0 (dado que se deja caer en resposo)
[tex] v_{f} = v_{0} - gt = 0 - 10 m/s^{2}*3.2 s = -32 m/s [/tex]
Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).
Espero que te sea de utilidad!
Which type of electromagnetic wave is used for nuclear power and medical treatment
Answer:
Gamma rays is used for nuclear power and for medical treatment
(ab/bc, non-calculator) the position function 2 st t ( ) 4.9 396.9 , gives the height (in meters) of an object that has fallen from a height of 396.9 meters after t seconds. (a) explain why there must exist a time t , 1 2 t , at which the height of the object must be 382 meters above the ground. (b) find the time at which the object hits the ground. (c) find the average rate of change in s over the intervalt 8,9. include units of measure. explain why this is a good estimate of the velocity at which the object hits the ground. how can this estimate be improved? (d) evaluate: 3 ( ) (3) limt 3 st s t . show the work that leads to your answer. include units.
Answer:
a) y₁ = 392 m , y₂ = 377.3 m , t = 1.74 s , b) v = 83.39.8 m/s , c) v = 88.2 m/s
Explanation:
Unfortunately some data of your statement is not clear, I will try to help you as much as possible.
The equation for free fall of a body is
y = y₀ + v₀t -1/g t²
As the body is released, its initial velocity is zero, the value of the acceleration of g = 9.8 m / s², the resulting equation is
y = y₀ - 4.9 t²
a) From this equation we see that as time progresses the height decreases.
For t = 1s
y = 396.9 -4.9 1²
y₁ = 392 m
for t = 2 s
y = 396.9 - 4.9 2²
y₂ = 377.3 m
Let's find the time for the height of y = 382 m
t = √ (y₀-y) 4.9
t = √ [(396.9-382) / 4.9]
t = 1.74 s
b) when the object hits the ground y = 0
0 = y₀ - 4.9 t²
t = √ y₀ / 4.9
t = √ (396.9 / 4.9)
t = 9 s
c) the rate of change of the position is the velocity,
t = 8 s
y₈ = 396.9 - 4.9 8 2
y₈ = 83.3 m
t = 9 s
y₉= 396.9 -4.9 9 2
y₉ = 0 m
the average exchange rate
v = (x₈ -x₉) / Δt
v = (83.8 -0) / 1
v = 83.39.8 m / s
This is the average speed in the last interval so this average speed of this interval where it reaches the ground
c) The actual speed with which it reaches the ground
v = dy / dt
v = 2 (4.9) t
v = 9.8 t
for t = 9s
v = 9.8 9
v = 88.2 m / s
How to improve these results using shorter time intervals
You push on a desk with a force of 150 N to the right. Your friend pushes on the same desk with a force of 50 N to the left . What is the net force?
Answer:
The net force is 100 N to the right.
Explanation:
To solve this problem, we simply add together the forces. Since we know that there is a greater force to the right, we will designate this as the positive direction and the left as the negative direction.
To find the net force, let's add together the two forces we are given using our new positive/negative designations:
+150 N right - 50 N left
Now, we just perform simple subtraction to get:
100 N right
Therefore, the answer is that the net force is 100 N to the right.
Hope this helps!
Find the total distance a car would travel if it moves 5 km East and then turns and travels 48 km West.
Answer:
53kmExplanation:
The total distance covered by the car will be the sum total of the distance moved during the journey.
Distance moved towards east = 5 km
Distance moved towards west = 48km
Total distance covered = Distance moved towards east+Distance moved towards east
Total distance covered = 5km+48km
Total distance covered = 53km
Hence the total distance a car would travel if it moves 5 km East and then turns and travels 48 km West is 53km
what is the law of gravitation
Answer:
Newton's paw of universal gravitation states that a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance in between them
When velocity is positive and acceleration is negative, what happens to the object's motion?
Answer:
Explanation:
Acceleration is negative, if object is going forward, speed decreases, if object is going backwards, speed increases.
Hope this helped!
Have a great day!
If the acceleration and velocity have the same sign, the object will accelerate. If the acceleration is of the opposing sign as the velocity, the object will slow down.
What is acceleration?Acceleration is the rate at which velocity changes over time, both in terms of speed and direction. A point or object moving in a straight line is accelerated if it accelerates or decelerates.
A positive velocity is assigned to an object that moves in the positive direction. When an object accelerates, its acceleration vector is directed in the same direction as its motion (in this case, a positive acceleration).
A positive velocity is assigned to an object that moves in the positive direction. When an object slows down, its acceleration vector is oriented in the opposite direction as its motion (in this case, a negative acceleration).
Thus, When velocity is positive and acceleration is negative, the object's motion will slow down.
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why does light splits into different colours while passing through a prism
Answer:
Since different colours of light travel at different speeds, the refractive index is different for each colour. As a result, when light passes through the refracting surface of the prism,its components bend into different angles, causing the single beam of light to separate
What is the power in a circuit that has a current of 12 A and a resistance of 100 Ω? (Note: 1 A2·Ω = 1 W) (1 point)
Answer:
[tex] \boxed{\sf Power \ in \ the \ circuit = 14.4 \ kW} [/tex]
Given:
Current (I) = 12 A
Resistance (R) = 100 Ω
To Find:
Power (P) in the circuit
Explanation:
Formula:
[tex] \boxed{ \bold{P = I^2 R}}[/tex]
Substituting value of I & R in the equation:
[tex] \sf \implies P = {(12)}^{2} \times 100 \\ \\ \sf \implies P = 144 \times 100 \\ \\ \sf \implies P = 14400 \: A^2.\Omega \\ \\ \sf \implies P = 14400 \: W \\ \\ \sf \implies P = 14.4 \: kW[/tex]
[tex] \therefore[/tex]
Power (P) in the circuit = 14.4 kW
For each pair of vehicles, choose the vehicle that would experience the greatest force of impact in a collision. Type your answer in the column on the right. Remember, Force = mass x acceleration Vehicle A is moving at 35 mph. Vehicle B is moving at 45 mph. Truck X hits a tree. Truck Y hits a wooden fence. Vehicle Y is carrying five passengers. Vehicle C is carrying only the driver. Motorcycle A runs into a haystack. Motorcycle B runs into a concrete divider.
Answer:
I need help on this tooo
Explanation:
Which of the following can be a variable? Select all that are correct (Hint: Three are
correct)
a. F
b. X
c. 3
d. a
Find the acceleration of a car that goes from 32 m/s to 96 m/s in 8.0s
Answer:
8m/s²
Explanation:
acceleration = v-u/t
=(96-32)/8
=64/8
=8m/s²
The acceleration of the car as it goes from 32 m/s to 96 m/s is 8 m/s².
What is acceleration?
Acceleration is defined as the rate of change of velocity with respect to time. Mathematically -
a = Δv/Δt
Given is a car that goes from 32 m/s to 96 m/s in 8.0s.
We can calculate the acceleration using the formula discussed above as follows -
a = Δv/Δt
a = (v - u)/Δt
a = (96 - 32)/8
a = 64/8
a = 8 m/s²
Therefore, the acceleration of the car as it goes from 32 m/s to 96 m/s is 8 m/s².
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