By using components of the centripetal force, it can be calculated as Radius of the curvature of the track is 557.5 m
According to the centripetal force, the force is
[tex]F_{c} = \frac{mv^{2} }{r}[/tex]
where m is the mass of the object , v is the velocity and r is the radius of the curvature.
This Fc will have two components, FccosФ and FcsinФ.
FccosФ = mg
1.1 mgcosФ = mg
cosФ = [tex]\frac{1}{1.1}[/tex]
so, sinФ = 0.416
Now, FcsinФ = [tex]\frac{mv^{2} }{r}[/tex]
1.1mgsinФ = [tex]\frac{mv^{2} }{r}[/tex]
r = 557.478
r = 557.5 m
Hence the radius of the curvature is 557.5 m.
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On level ground, how much farther can a person jump on the moon as compared to the earth if the takeoff speed and the angle are the same? The free-fall acceleration on the moon is one-sixth what it is on Earth.
The person can jump 6 times higher on the moon compared to Earth.
What is the maximum height jumped by an object?The maximum height an object can Jump is the height vertical displacement of the object during an upward motion.
Mathematically, the maximum height an object can jump is given as;
H = u²sin²θ/2g
where;
u is the initial velocity of the objectθ is the angle of projection of the objectg is acceleration due to gravityh is the maximum height of jumpWhen a person moves to the moon, the acceleration due to gravity becomes ; ¹/₆
The new height the object can jump is calculated as follows;
H = u²sin²θ/(2 x ¹/₆g)
H = 6( u²sin²θ/2g)
Thus, the person will jump higher on the moon due to lesser acceleration due to gravity.
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How many g are in a pack containing 10 tablets of 500 mg each? *
5g
50g
100g
500g
Answer:
5 g
Explanation:
500 mg x 10 = 5000 mg
5000 x 10^-3 g = 5 g
Hello..!
To solve the problem and calculate the number of pills in the package, we will use the conversion factor.
The conversion factor or unit factor is a conversion method that is based on multiplying by one or more fractions where the numerator and denominator are equal quantities expressed in different units of measure, so that each fraction is equivalent to the unit.
Find out that 1 gram has a total of 1000 mg.
Problem:
How many g are in a carton containing 10 tablets of 500 mg each?
According to the previous text we can say that the conversion factor would be:
[tex] \: \: \: \: \: \qquad \qquad \large \sf\dfrac{1\ g}{1000\ mg}[/tex]
Now we must find out that the box has a total of 10 pills of 500 mg, so to know how many grams the box has we must know how many grams only one pill weighs:
[tex] \sf \qquad\boxed{\boxed{ \sf\large 500\ mg*\dfrac{1\ g}{1000\ mg}= 0.5\ g}}[/tex]
We know that a pill weighs 0.5 grams, now to calculate how many grams the box weighs we must multiply the total pills by the weight of just one pill:
[tex]\qquad \boxed{\boxed{ \sf\large 0.5\ g\times 10= 5\ g}}[/tex]
We conclude that one box contains 5 grams of tablet, option 1.
[tex]\begin{gathered}\rule{7cm}{0.01mm}\\\texttt{Good studies! :D}\\\rule{7cm}{0.01mm}\end{gathered}[/tex]
How long does it take a car to travel 330 m at a speed of 30.0 m/s
It will take 11 seconds for a car to travel 330 m at a speed of 30.0 m/s
By going through the formula of calculating the speed of the vehicle
that is, S=D/T
We get the equation T=D/S.........(i)
Where T stands for Time
D stands for Distance
S stands for Speed
Now, as per the given question
Distance(D)= 330 meters
Speed(S)= 30.0 meters per second
Time(T)= ?
Putting the values in equation (i),
T=330 meters/30 meters per second
T = 11 seconds.
Therefore, A car moving at a speed of 30.0 meters per second will traverse 330 meters in 11 seconds.
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Which of the following is not a density-dependent factor limiting a population growth?
a) intra-specific competition
b) switching behavior of a predator
c) a stress syndrome that alters hormone levels
d) a limited number of available nesting site
Answer:A.
i know its a, i did quiz
a mass m is attached to an ideal massless spring. when this system is set in motion with amplitude a, it has a period t. how does the period of the motion change if the amplitude of the motion is increased to 2a? explain.
System is set in motion with an amplitude of a and a period of T. If the amplitude of the motion is increased to 2a, the period of the motion changes.
A straightforward harmonic oscillator's period is independent of its amplitude. with the graphs of acceleration and velocity produced by the time derivatives. These oscillators also show how kinetic and potential energy can be transferred.
The acceleration of the mass increases proportionally with the increase in force, causing the mass to travel farther in the same amount of time. Therefore, increasing the amplitude has no overall impact on the oscillation's period.
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Which has the most kinetic energy from its motion?
Multiple choice question.
cross out
A)
a 1,100-kg car traveling 60 km/h
cross out
B)
a 2,000-kg truck traveling 50 km/h
cross out
C)
a 900-kg car traveling 80 km/h
cross out
D)
a 300-kg motorcycle traveling 100 km/h
Among the given options the vehicle that has the most kinetic energy is a 900-kg car traveling 80 km/h
KE = 1 / 2 m v²
KE = Kinetic energy
m = Mass
v = Velocity
For A,
m = 1100 kg
v = 60 km / h
KE = 1 / 2 * 1100 * 60²
KE = 1980000 J
KE = 1980 KJ
For B,
m = 2000 kg
v = 50 km / h
KE = 1 / 2 * 2000 * 50²
KE = 2500000 J
KE = 2500 KJ
For C,
m = 900 kg
v = 80 km / h
KE = 1 / 2 * 900 * 80²
KE = 2880000 J
KE = 2880 KJ
For D,
m = 300 kg
v = 100 km / h
KE = 1 / 2 * 300 * 100²
KE = 1500000 J
KE = 1500 KJ
KEc > KEb > KEa > KEd
Therefore, the 900-kg car traveling 80 km/h has the most kinetic energy
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2. Hot-air balloons are a fun way to travel around the globe.
A. In what layer can a hot-air balloon travel?
B. Why can't a hot-air balloon go to higher layers?
20points
The layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere. its can't a go to higher layers because it would be affected by density.
What is troposphere?The troposphere servesv as the lowest layer of Earth's atmosphere however it has the mass (about 75-80%) of the atmosphere and most of tthe types of clouds can be seen in the troposphere, then the weather occurs within this layer.
It should be noted that the troposphere has the highest density, as well as the greatest air pressure, however the water vapor, and a temperature range from 62, layer that the hot-air balloon can travel to, in the layer of the atmosphere is troposphere.
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How many moles of CaCo2 are in 50g of calcium carbonate
A small nail stuck in your car tire moves on a circular path with a radius of 35 cm. when the nail has traveled a linear distance of 5.5 m, through what angle has the tire rotated in both radians and degrees?
To cover 5.5 meters in a straight line, the tire rotated at an angle of 15.714rad.
What is a circle's simple definition?To put it simply, a circle is a spherical shape without any corners or line segments. In geometry, it has the shape of a closed curve.
A definition from Euclid
A circle is a plane figure that is bounded by a single curved line and in which all straight lines drawn from any point inside the circle to the boundary are equal. Its center is the point, and its circumference is the bounding line. — Book I of Euclid's Elements.
Given,
circular path with a radius of 35cm,
Circumference of car tire is 2πr = 2×3.14×0.35 = 2.198m
For traveling a distance of 5.5m
5.5 = angle in rads ×radius
angle = 5.5/0.35
angle = 15.714 rad
To cover 5.5 meters in a straight line, the tire rotated at an angle of 15.714rad.
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if the test section is designed to have a velocity of 200 m/s, determine the mach number, temperature and pressure in the test section. is the pressure in the test section greater than or less than the surrounding atmospheric pressure?
The test section's pressure is lower than the ambient pressure.
What exactly does pressure mean?In the physical sciences, pressure is defined as the perpendicular force per unit area or the stress at a particular location within a confined fluid.
Given,
Diameter of Test section, d₂ = 0.5m
Area, A₂ = π/4d₂² = π/4×0.5² = 0.19635m²
Now, At Inlet,
Po = 101325Pa
To = 288 k
s = 122 kg/m³
(a) Using Bernoulli Theorem, i'n Test Section,
Po = [tex]P_{t}[/tex] +1/2γ [tex]v_{t^{2} }[/tex]
101325 = [tex]P_{t}[/tex] + ½ (1.22) (200) ²
[tex]P_{t}[/tex] = 76925 Pa
[[tex]v_{t}[/tex] = 200m/s]
Now,
Static Temperature, [tex]T_{t}[/tex]
[tex]T_{0}[/tex] = [tex]T_{t}[/tex] +v²/2[tex]c_{p}[/tex]
288 = [tex]T_{t}[/tex] +200²/2×1005
[tex]T_{t}[/tex] = 268.09k.
Thus,
[tex]M_{t}[/tex] = [tex]v_{t}[/tex]/[tex]\sqrt{\nu RT_{t} }[/tex]
[tex]M_{t}[/tex] = 200/1.4×287×268
[tex]M_{t}[/tex]= 0.609
The test section's pressure is lower than the ambient pressure.
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two workers are sliding 260 kg crate across the floor. one worker pushes forward on the crate with a force of 450 n while the other pulls in the same direction with a force of 370 n using a rope connected to the crate. both forces are horizontal, and the crate slides with a constant speed. what is the crate's coefficient of kinetic friction on the floor?
To find out the kinetic friction, using the coefficient friction formula.
What is kinetic friction?
A force that acts between moving surfaces is called "kinetic friction." A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' kinetic friction coefficients will determine how much force is applied.
What is coefficient friction?
A measure of the degree of friction between two surfaces is the coefficient of friction. A coefficient of friction is determined by calculating the resistance to motion at the intersection of two surfaces made of the same or different materials.
UK
U-coefficient of friction
K-Kinetic friction
Using UK
450+370-f=m*o
f=820=UK*260*9.8
UK=2.548
820/2.548
UK= 321.8210361
Therefore the coefficient of kinetic friction is 321.8210361
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a 70 kg man is floating at rest near his spaceship. he throws a 1.5 kg wrench away from the ship at a speed of 10 m/s in order to move himself toward it. with what speed does he move toward the ship?
0.218 m/s speed does he move toward the ship.
use the formula from conservation of Momentum
mu + MV = (m-M)V'
u = o
so
MV = (m-M)V'
V' = (1.5 * 10)/(70-1.5)
V' = 0.218 m/s
What is speed?The most crucial scientific notion is measurement. Base or physical fundamental units are used to quantify a wide range of quantifiable quantities. One such measurable metric is speed, which calculates the ratio between the distance an object travels and the time needed to cover that distance. Let's explore speed in-depth in this session.
The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.
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For a force to do work on an object, some of the force must act in the________________
as the object moves.
Answer:
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What is the condition for a force to do work on a body ?
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What is the condition for a force to do work on a body ?
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Solution
The condition of force to do some work is that the force should be along the direction of displacement.
work is done when the object moves through a certain distance in a particular direction after the force had been applied on it.
Work Done = Force x Distance x Cos theta
For work to be done, the force must be applied and must not be zero.
The body on which the force is applied must move in one direction or the other and hence the S must not be zero.
The force must not be applied at 90 degrees angle upon the object as Cos 90 equals zero.
At rest, a car's horn has a frequency of 395 Hz. Car A passes car B on the street in the same direction. If car A is traveling at 22.0 m/s and car B is traveling at 19.5 m/s, what frequency does car B hear when car A honks? (speed of sound =343 m/s) (Unit=Hz) please help I'll give 100 points
Car A's frequency is determined to be 398.4 Hz.
What is the frequency heard by car A?The frequency heard by car A is calculated using the following equation.
f = fs(v - v₀) / (v - vs)
where;
v is the speed of sound = 343 m/s
v₀ is the speed car B = 19.2 m/s
vs is the speed of car A = 22 m/s
fs is the frequency of car A = 395 Hz
f is the frequency of car B = ?
f = 395(343 - 19.2) / (343 - 22)
The frequency will be calculated as below,
f = 395(1.0087)
f = 398.4 Hz
Therefore, car A's frequency is determined to be 398.4 Hz.
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two copper wires (in different circuits) carry the same current, but wire a has twice the radius of wire b. if the drift speed of the conducting electrons in wire a is 0.1 mm/s, what is the drift speed of the conduction electrons in wire b? assume the number density of conducting electrons is the same in both wires.
4 is the drift speed of the conduction electrons in wire b.
I = neA [tex]V_{d}[/tex]
[tex]V_{d}[/tex] = [tex]\frac{I}{neA}[/tex]
= [tex]\frac{I}{ne\pi r^{2} }[/tex]
[tex]V_{d}[/tex] [tex]\alpha[/tex] [tex]\frac{1}{r^{2} }[/tex]
r' = 2r
A' = [tex]\pi 2r^{2}[/tex]
= 4[tex]\pi r^{2}[/tex]
[tex]\frac{Vd'}{Vd}[/tex]= [tex]\frac{r^{2} }{2r^{2} }[/tex] = 1/4
[tex]V_{d}[/tex] = 4
What is drift speed?Subatomic particles like electrons move in random directions all the time. When electrons are exposed to an electric field, they move randomly but slowly drift in one direction, the direction of the applied electric field. The net speed at which these electrons drift is called the drift speed. Curvature can be defined as follows:
The average speed of charged particles (eg electrons) in a material under the influence of an electric field. the SI unit of yard speed is m/s. It is also measured in [tex]m^2[/tex]/(V.s).
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A spherical object has a certain density. If it is compressed under high pressure to half of its original diameter, its density will now be.
The following formula can be used to determine an object's density if it is spherical.
ρ = 3/4 x π x r³
Here, r denotes the spherical object's radius.
and is a constant in mathematics with the value 22/7.
Assume that the object's initial diameter is d.
As a result, it will have a radius of = d/2 = 0.50d.
Let's enter this value and calculate density as 1.
ρ₁ = 3/4 x π x (r)³
ρ₁ = 1/2 x 22/7 x (0.5d)³
The object is currently being compressed so that its diameter is reduced to a fourth of what it was.
The object's new diameter would be d/2 = 0.50d.
The new radius would be 0.50d/2 = 0.25d as a result.
Find the new density 2 now.
ρ₂ = 1/2 x 22/7 x (0.25d)³
Compare numbers 1 and 2 now.
3/4 x 22/7 x (0.25d)3 divided by 3/4 x 22/7 x (0.5d)3 equals 2/1.
1/2 and 22/7 can be canceled here.
ρ₂/ρ₁ = (0.25d)³ / (0.5d)³
d is terminated.
ρ₂/ρ₁ = 0.125
ρ₂ = 0.125 ρ₁
The original density is 1, and the revised density is 2.
Since its new density would be 0.125 times that of its original, we can conclude that.
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What is the total momentum before the collision?
Answer:
When two objects collide the total momentum before the collision is equal to the total momentum after the collision (in the absence of external forces). This is the law of conservation of momentum. It is true for all collisions.
Explanation:
...
Answer:
When two objects collide the complete momentum before the collision is similar to the complete momentum afterwards the collision (in the absence of outside forces) . This is the law of conservation of momentum . it's accurate for all collisions .
an object is 16.0cm from a concave mirror whose focal length is 10.0cm. (a) how far is the image from the mirror? answer: cm (b) what is the magnification? include any sign answer: (c) is the image real or virtual? answer: (d) is the image upright or inverted? answer:
The distance of the image is 26.67 cm
The magnification is -1.67
The image is real
The image is inverted
The focal length of the concave mirror = 10 cm
The distance of the object from the concave mirror = 16 cm
The distance of the image can be found using the formula1/p + 1/q = 1/f
where p is the distance of the object
q is the distance of the image
f is the focal length
1/q = 1/f - 1/p
1/q = (p - f)/fp
q = fp / (p - f)
q = 16 x 10 / ( 16 - 10)
= 160 / 6
= 26.67 cm
The distance of the image from the concave mirror is 26.67 cm
The magnification of the concave mirror can be found usingM = -q/p
where M is the magnification
M = -26.67 / 16
= -1.67
The distance of the image is positive, so the image is realThe magnification value is negative, so the image is inverted.Learn more about the concave mirror is
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which answer would you choose if the rocks fall out through a hole in the floor of the car, one at a time?
The car speeds remains constant.
Using the following equation for momentum:
Pi=Pf
(c=car and r=rock)
McVc + MrVr = McV'c + MrV'r
Initially
Vc=Vr=Vi
and since rocks are being dropped directly downward, final momentum of the rocks (being dropped one at a time) should be zero because their falling down, out of the railroad car.
So:
Vi( Mc+Mr) = McV'c V'c = [Vi(Mr+Mc)] / Mc
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the force F acting on a body along a circular path depends on a mass of the body (m),velocity(v) and radius (r) of the circular path.obtain the expression for the force by dimensional analysis method(take constant k to be 1)
the required equation for centripetal force is F = k m¹ v¹ r⁻¹.
A particle traveling uniformly in a circle experiences a centripetal force, F, which is dependent on the mass (m), velocity (v), and radius (r) of the circle.
the F formula using the dimensions method is
Suppose F = k mᵃvᵇrⁿ. (i)
Where a, b, and n are the respective powers of m, v, and r and k is the dimensionless constant of proportionality.
Upon putting the measurements of various amounts in (i)
we get
[M¹L¹T‐²] = Mᵃ[LT‐¹]ᵇ Lⁿ
=> [M¹L¹T‐²] = Mᵃ Lᵇ Lⁿ T⁻ᵇ
=> [M¹L¹T-²] = Mᵃ Lᵇ⁺ⁿ T⁻ᵇ
on comparing both sides we get
a = 1
b+n = 1
-b = -2 => b = 2
Then n = -1
Onputting these values in (i),
we get
F = k m¹ v¹ r⁻¹
Or
F=k(mv²)/r
This is the required equation for centripetal force.
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The place kicker on a football team kicks a ball from ground level with an initial speed of 8.40 m/s at an angle of 21.0° above the horizontal. How long is the ball in the air, in seconds, before it lands on the ground again? You may neglect air resistance.
Answer:
See below
Explanation:
Vertical component of the kick-off velocity is 8.4 sin21° = 3.01 m/s
Find the time-point where vertical velocity = 0 the ball is in the air for twice this long ( as it still has to fall back down to the ground)
vf = vo + at
0 = 3.01 m/s - 9.81 t shows t = .307 twice this is .614 sec
( what a sorry kick !)
which of the glass lenses above, when placed in air, will cause rays of light (parallel to the central axis) to converge?
Convex lenses when placed in the air, will cause rays of light (parallel to the central axis) to converge.
Converging lenses, commonly referred to as convex lenses, have thicker centers and narrower upper and lower margins. The edges are outwardly curled. This lens has the ability to concentrate a beam of parallel light rays coming from the outside onto a spot on the opposite side of the lens.
The image created is referred to be a genuine image when it is inverted relative to the object. On a screen, this kind of image can be recorded. When the object is positioned at a point farther than one focal length from the lens, a converging lens creates a true image.
A virtual image is one that cannot be produced on a screen and is formed when the image is upright in relation to the object. When an item is positioned within one focal length of a converging lens, a virtual image is created. It creates an enlarged image of the object on the same side of the lens as the image. It serves as a magnifier.
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The ball is about to hit the ground.
It has a kinetic energy store of 110 J.
Ignoring the effects of friction, what is the maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground?
The maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground is 110 J
Since the effects of friction is ignored, there is no loss of energy as heat. So the entire elastic potential energy store of the ball is converted into kinetic energy store.
Elastic potential energy = Kinetic energy
Kinetic energy = 110 J
Elastic potential energy = 1 / 2 k x²
Kinetic energy = 1 / 2 m v²
k = Spring constant
x = Displacement
m = Mass
v = Velocity
If friction is ignored,
1 / 2 k x² = 1 / 2 m v²
v / x = √ ( k / m )
Therefore, the maximum elastic potential energy store of the ball is 110 J
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when a star is moving towards us (the earth) due to a planet orbiting it and tugging on it, we see a blue shift in the star's spectrum. this corresponds to what in terms of its radial velocity?
When the radial velocity is positive, it means the distance between the objects is or was becoming closer; when it is negative, it means the distance between the source and the observer is or was getting closer.
What is radial velocity?The portion of a particle's velocity that is moving in the direction of its radius vector. or radial motion, which is the speed at which an observer approaches or recedes from a celestial body or other source of radiation in the line that connects the two: speed in the visual field.
This technique is one of the detection methods that enables us to calculate an exoplanet's mass, a crucial factor in the hunt for worlds similar to Earth and other extraterrestrial life.
Radial velocity has been used to locate hundreds of distant planets and was the first effective approach for exoplanet discovery. Because stars do not need to be continuously monitored as they do with transit photometry, it is perfect for ground-based telescopes.
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he coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collides with a rigid surface. for an object with a coefficient of 0.76, what fraction of the object's kinetic energy is lost during a single collision? the coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collides with a rigid surface. for an object with a coefficient of 0.76, what fraction of the object's kinetic energy is lost during a single collision? 42% 58% 17% 51%
A single collision results in a loss of 42% of the object's kinetic energy.
How to calculate coefficient of restitution?Kinetic energy is equal to 0.5 x mass x v2.
kinetic energy coming in = 0.5 x m x v2
v/u = Coefficient of restitution
0.76 = v/u
v = 0.76u
Kinetic energy expended = 0.5 x m x 0.76²
Kinetic energy expended = 0.5 x m x 0.5776
Kinetic energy expended = 0.5776 (0.5 x m x )
The kinetic energy that is coming in is 0.5 x m x x2.
kinetic energy expended = 0.5776 x (incoming kinetic energy)
The entering kinetic energy is equal to 57.76% of the exiting kinetic energy, as can be seen from the above.
A loss of energy of 100 - 57.76 = 42.24%
Therefore, a single collision results in a loss of 42.24% of the object's kinetic energy.
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a 0.111 kg hockey puck moving at 55 m/s is caught by a 80 kg goalie at rest. with what speed does the goalie slide on the (frictionless) ice?
The goalie slides on the frictionless ice at a speed of 0.076 m/s.
collision energy equals collision momentum
What generates momentum?An object's momentum will vary as a result of a force applied for a specific length of time. In other words, an uneven force an object regardless of whether it is speeding up or slowin accelerates g down. When a force exerted against an object's motion slows it down.
The puck weighs 0.111 kg in terms of mass.
Hockey puck velocity is 55 meters per second.
Goalkeeper weight: 80 kg
Goalkeeper's speed is 0 meters per second.
Following the rule of linear momentum conservation, (0.111 kg 55 m/s) + (80 kg 0 m/s) = (0.111 kg + 80 kg) V V = (6.105 / 80.111) = 0.076 m/s (0.111 kg 55 m/s) + (0.111 kg + 80 kg) V = 0.076 m/s
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according to karl popper, a discipline that claims to be a science is really a pseudoscience like astrology if it:
A scientific theory should make testable predictions and if those predictions are found to be incorrect the theory should be dismissed.
He argued that science advances best through the use of deductive reasoning, known as critical rationalism, as its primary emphasis. Popper coined the term critical rationalism to describe his philosophy. Popper rejected the empiricist view that basic statements are infallible.
Karl Popper was a scientific realist against his will. Despite his own limitations regarding the forms of acceptable scientific reasoning and the extent of empirical evidence, he advocated a very real conception of scientific goals and outcomes. A significant contribution stems from his rejection of induction in empirical science.
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How does a white dwarf differ from a neutron star? how does each form? what keeps each from collapsing under its own weight?.
An electron degenerate object is a white dwarf, whereas a neutron star is a neutron degenerate object. A white dwarf is less compact and has a larger radius than a neutron star.
How is a white dwarf transformed into a neutron star?A white dwarf would collapse into a denser entity known as a neutron star if it reached the Chandrasekhar limit and nuclear reactions were to stop. This would happen if nuclear reactions continued to occur.
How is a white dwarf prevented from exploding into a neutron star?White dwarf stars are prevented from collapsing by the fact that electrons are fermions, while neutron stars are prevented from collapsing by the fact that electrons are fermions.
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a nearsighted man has a far point of 300 cm. what kind of corrective lens should be prescribed for him?
The diverging lens/concave lens is used as a corrective lens is used for a nearsighted person
Nearsightedness is also known as myopia where the person with myopia will be able to see the near object but far objects will look blurry.
Myopia is corrected with lenses called "minus power lenses". They are concave in shape and help the eye to focus light properly. Myopia causes distant objects to appear blurry. Prescription glasses or contact lenses can usually correct this blurry distance vision. Myopic eyes have a stronger ability to focus than normal eyes. Focus in front of the retina, not on the retina. Lenses used to correct nearsightedness work by reducing the eye's ability to focus.
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if there is no air resistance, what is the net if there is 10 n of air resistance, what is the net force? what is the acceleration?? what is the acceleration?
If there is no air resistance, what is the net if there is 10 n of air resistance, what is the net force,the net force of an object is 0N and acceleration is 6N.
When compared to displacement and velocity, acceleration is like the wrathful, flaming dragon of motion variables. People may be terrified of it, it might be harmful, and if it's enormous, it draws your attention. When you're in a fast-turning corner in a car or go-kart or when you're in a plane during takeoff, you can feel your own acceleration.
Since velocity depends on both speed and direction, you can only accelerate by changing either one or the other, if not both. The object will be moving faster if the acceleration is pointing in the same direction as the velocity. Additionally, the item will slow down if the acceleration is pointing in the opposite direction from the direction of the velocity.
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