A train journey starts at 06:24 and ends and 21:16 on the same day how long is the journey give your answer in hours and minutes

Answer:

7 Days or X = 7

Step-by-step explanation:

Before we even attempt the problem, we need to craft our equation to work with…

- Multiply 0.09 x 500 = 45

- Now we know what out equation will be which is 45 + 56.37x < $440

- First subtract 45 from $440

- Then devide 45 from 440

- There you go we found the value of x

Final answer:

45 + 56.37(7) = 440

Answer Sentence: So Hawa has 7 day to cover 500ml

(Sorry if I’m wrong)

Answer:

a

Step-by-step explanation:

Answer:

can you clear more I don't understand

Answer:

3090%

Step-by-step explanation:

425.89 - 395.00 = 30.89

Round to the nearest tenth = 30.9

Convert to a percentage = 3090%

According to the information, it can be inferred that the volume of the ice cream is close to 207.33 cm³

To calculate the volume of the maxicool, we must calculate the volume of the sphere of ice cream, and the volume of the cone that is filled with ice cream.

V = [tex]\frac{4}{3}[/tex] × π × R³

V = [tex]\frac{4}{3}[/tex] × π × 3³

V = 113.09 cm³

V = [tex]\frac{1}{3}[/tex] × π × R² × h

V = [tex]\frac{1}{3}[/tex] × π × 3² × 10

V= 94.24 cm³

Finally we must add both values to know the total volume of the maxicool.

113.09 + 94.24 = 207.33 cm³

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Answer:

Step-by-step explanation:

Step-by-step explanation:

as per the rules of intersecting lines, the angles between the lines must be the same on both sides of the lines. the just "mirror" (so, left becomes right, and right becomes left).

and since the basic grid is created with perpendicular lines (standing at 90° at each other), we are dealing in the top right and bottom left quarters with 2 angles that together add up to 90°.

these are called complementary angles.

so, in the top right quarter we have a 52° angle, and the other one must be

90 - 52 = 38°

as mentioned, the angles in the bottom left quarter must be the same but are mirrored, so,

y = 38°

The measure of angle ∠y = 38°

Two straight lines that intersect at the same location are said to be intersecting lines. The junction point is the place where two intersecting lines meet. Four angles are created when two lines cross. The four angles added together always equal 360 degrees.

Perpendicular lines are two straight lines that intersect and form right angles. When two perpendicular lines intersect, they form four right angles.

When lines intersect, two angle relationships are formed:

Opposite angles are congruent

Adjacent angles are supplementary

Given data ,

Let the first line be A

Let the second line be B

Now , the lines A and B intersect at the point O perpendicular to each other

And , The angles formed are = 90°

Let the measure of m∠A = 52°

Now , the measure of m∠y = 90° - 52°

The measure of angle m∠y = 38°

Hence , the measure of angle m∠y = 38°

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Answer:

t = 4 s

Step-by-step explanation:

Given function:

[tex]h(t)=-16t^2+48t+64[/tex]

where:

When the ball hits the ground, its height will be 0 ft.

Therefore, set the function to zero and solve for t:

[tex]\begin{aligned}h(t) &=0\\ \implies -16t^2+48t+64 & =0\\ -16(t^2-3t-4)& =0\\ t^2-3t-4 &=0\\ t^2+t-4t-4&=0\\ t(t+1)-4(t+1)&=0\\(t-4)(t+1)&=0\\ \implies t&=4, -1\end{aligned}[/tex]

As time is positive, t = 4 s (only).

Given

[tex]h = - 16 {t}^{2} + 48t + 64[/tex]

Where:- h= Height of ball (given in feet[ft]) and,

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎t= time (in seconds [s])

Time = (t)

We know,

[tex] \text{When the ball hits the ground its height will be 0}[/tex]

[tex] \therefore h(t) = 0[/tex]

[tex] \implies - 16 t^{2} + 48t + 64 = 0 \\ \\ \fbox{taking - 16 as common multiple} \\ \\ \implies - 16(t {}^{2} - 3t - 4) = 0 \\ \\ \implies t {}^{2} - 3t - 4 = 0 \\ \\ \fbox {factorising the \: equation} \\ \\ \implies t {}^{2} - t - 4t - 4 = 0 \\ \\ \implies t(t + 1) - 4(t + 1) = 0 \\ \\ \implies(t - 4)(t + 1) = 0[/tex]

[tex] \tt{Either} \\ t - 4 = 0 \\ t = \red{ 4 } \\ \\ \tt{Or} \\ t + 1 = 0 \\ t = \red{ - 1}[/tex]

We know, Time cannot be negative.

So, Time (t) = 4 seconds

The gym option costs less per class for six classes(Option B), and the gym option costs less per class for seven (Option D).

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4. If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

Here we're specified that:

For high school classes:

For local gym:

For 6 classes:

High school : $20 + $(10 + 10 + 10 + 10 + 10 + 10) = $20 + $10 × 6 = $(20+60) = $80

(since $20 dollar is one time cost, and $10 was price for each class)

Similarly, joining local gym's $50 cost is one time, and rest of $5 is price for each class.

Local gym : $50 + $(5+5+5+5+5+5) = $20 + $5 × 6 = $(20+30) = $50

For 7 classes:

High school : $20 + $(10 + 10 + 10 + 10 + 10 + 10 + 10) = $20 + $10 × 7 = $(20+70) = $90

Local gym : $50 + $(5+5+5+5+5+5+5) = $20 + $5 × 7 = $(20+35) = $55

Thus, the statements which are true about the average cost for the two options is given by: Option B: The gym option costs less per class for six classes., Option D: The gym option costs less per class for seven classes.

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Answer:

2√6

using pythagoras theorem:

a² + b² = c²

Answer:

Step-by-step explanation:

The length of the third side can be determined using pythogoras theorem. Keep in mind that pythogoras theorem can only be used when finding the missing side length of a right triangle.

[tex]\text{Pythagoras theorem: (Longest side})^{2} = (\text{Leg of right triangle}_{1} ) ^{2} + (\text{Leg of right triangle}_{2} )^{2}[/tex]

In this triangle, we are given that:

Substitute the measures into the pythogoras theorem:

[tex](7})^{2} = (5 ) ^{2} + (\text{Leg of right triangle}_{2} )^{2}[/tex]

Simplify both sides of the equation:

[tex]\rightarrowtail (7 \times 7}) = (5 \times 5) + (\text{Leg of right triangle}_{2} )^{2}[/tex]

[tex]\rightarrowtail49 = 25 + (\text{Leg of right triangle}_{2} )^{2}[/tex]

Subtract 25 both sides:

[tex]\rightarrowtail49 - 25 = 25 - 25 +(\text{Leg of right triangle}_{2} )^{2}[/tex]

[tex]\rightarrowtail24 = (\text{Leg of right triangle}_{2} )^{2}[/tex]

Square root both sides and simplify:

[tex]\rightarrowtail\sqrt{24} = \sqrt{(\text{Leg of right triangle}_{2} )^{2}}[/tex]

[tex]\rightarrowtail\sqrt{3 \times 2\times 2 \times 2} = \sqrt{(\text{Leg of right triangle}_{2} )^{2}}[/tex]

[tex]\rightarrowtail2\sqrt{3 \tim \times 2} = \text{Leg of right triangle}_{2}[/tex]

[tex]\rightarrowtail\boxed{2\sqrt{6} \ \text{units} = \text{Leg of right triangle}_{2}}[/tex]

Answer:

On a linear graph, the rate of change is called the slope of a line

Step-by-step explanation:

Hope this helps

The complete statement is, on a linear graph, the rate of change is called the slope of a line.

We know lines have various types of equations, the general type is

Ax + By + c = 0, and the equation of a line in slope-intercept form is

y = mx + b.

Where slope = m and b = y-intercept.

the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.

From the above concepts we now know that, on a linear graph, the rate of change is called the slope of a line.

It can also be defined as, (y₂ - y₁)/(x₂ - x₁).

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Answer:

An exponent is a number that is to a certain value, like 5^2.

The ^2 means multiply by itself by itself ONCE,

so it would be 5x5.

5^3 means multiply it by itself TWO TIMES,

and going on and on.

Let's say you have a test and the question it's asking is to simplify 5^4.

It's 5x5x5x5, multiplying it by itself FIVE TIMES.

Hope this helped!

by definition two regular polygons of the same amount of sides will be similar.  Check the picture below.

Answer:

a movement one single movement cultivating one group

Answer: C

Step-by-step explanation:

Answer:

69

Step-by-step explanation:

Find the area of the rectangle. 15 x 3 = 75.

Find the area of the cut-out triangle.
1/2bh

1/2(3(4))

1/2(12)

6

75 - 6 = 69.

The volume of the rectangular prism is 1120 yd³.

A prism is a solid geometric figure whose two ends are similar, equal, and parallel rectilinear figures, and whose sides are parallelograms.

To calculate the volume of the rectangular prism, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute thee values into equation 1

Hence, The volume of the rectangular prism is 1120 yd³.

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Answer:

What are you trying to do you have not Explained to us

Step-by-step explanation:

Answer:

20 and greater than 20

__________________________________________________________

Ask me in the comments box.

For the given function f(x) = –5|x + 1| + 3 the value of x = 2, -4

To find the answer to this question, we will have to find the values of x where:

-5|x + 1| + 3 = -12

We can solve this equation for x to find the values of x that satisfy this equation.

-5|x + 1| + 3 = -12

Subtract 3 from both sides.

-5|x + 1| = -15

Divide both sides by -5.

|x + 1| = 3

Now here, the equation will split off into two different equations. These two are:

x + 1 = 3

x + 1 = -3

Lets solve the first one first.

x + 1 = 3

Subtract 1 from both sides.

x = 2

Now we solve the second one.

x + 1 = -3

Subtract 1 from both sides.

x = -4

So now we have the answers x = 2 and x = -4.

So the values of x are x = 2, -4

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Answer:

36 is 9 times more than 4

Step-by-step explanation:

9 * ?? = 36

to find the unknown number we solve:

36/9 = 4

so 9 times 4 equals 36

means that 36 is 9 times more than 4

HOPE THIS HELPS :)

Answer:

4

Step-by-step explanation:

9x4=36. I corrected both the guys before me who messed up

Answer:

Final answer -

[tex]equation \: of \: such \: line \dashrightarrow \: y = - 5x + b \\ [/tex]

hope helpful :D

Step-by-step explanation:

It is given that, the sum of two positive integers is 31 and the sum of the squares of these numbers is 625 and we are to find the smaller of the numbers.

So, let the two positive integers be x and y.

Therefore,

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x + y = 31 \: \: ........ \: (i) }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + y {}^{2} = 625 \: ...... \: (ii)}}} \\ \\[/tex]

Now, From the first equation we have,

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x + y = 31 }}} \\ \\ [/tex]

[tex] {\longrightarrow \pmb{\sf {\qquad y = 31 - x \: ...... \: (iii)}}} \\ \\ [/tex]

Now, substituting the value of y in equation (ii) we get :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x {}^{2} + (31 - x) {}^{2} = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + (31 {}^{2} - 2.x.31 + x{}^{2} ) = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + (961 - 62x + x{}^{2} ) = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + 961 - 62x + x{}^{2} - 625 = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2 x {}^{2} + 336 - 62x = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2 x {}^{2} - 62x + 336 = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2( x {}^{2} - 31 + 168) = 0}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad \frac{2}{2} ( x {}^{2} - 31 + 168) = \frac{0}{2} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} - 31 + 168 = 0}}} \\ \\[/tex]

Now using the quadratic formula :

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }}} \\ \\[/tex]

Where,

[tex] \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ - (- 31) \pm \sqrt{ {31}^{2} - 4(1)(168)} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm \sqrt{ 961 -672} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm \sqrt{ 289} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm 17 }{2(1)} }}} \\ \\[/tex]

Now, we have two equations,

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 + 17 }{2} \: ... .....\: (iv)}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 - 17 }{2} ... .....\: (v)}}} \\ \\[/tex]

So, Equation (iv) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 + 17 }{2} }}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 48 }{2} }}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x = 24 }}} \\ \\ [/tex]

Now, Equation (v) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 - 17 }{2}}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 14 }{2}}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \: 7}}}\\ \\ [/tex]

Now, we are to find the value of y.

Substituting the value of x (24) in equation (iii) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad y = 31 - x \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad y = 31 - 24 \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad y = 7 \:}}} \\ \\ [/tex]

Again, Substituting the value of x (7) in equation (iii) :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad y = 31 - x \:}}} \\ \\ [/tex]

[tex] {\longrightarrow \pmb{\sf {\qquad y = 31 - 7 \:}}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad y = 24 \:}}} \\ \\ [/tex]

Therefore,

[tex] \\ [/tex]

So, The smaller of the numbers is 7 .

The sum of two positive integers is 31. If the sum of the squares of these numbers is 625, find the smaller of the numbers.

This question belongs to quadratic equations so we have to find the answer by making equation and solving it .

According to question , sum of two positive integers is 31 . So ,

According to question , sum of square

of these numbers is 625 . So ,

From equation 1 ( x + y = 31 ) , Value

of x :

Now , putting value of x in eq. 2 :

Solving it by using middle term

splitting :

First number ,

Second Number ,

According to question ,

Sum of numbers is equal to 31 :

Sum of squares of these numbers is equal to 625 :

MÎA or AÎM

the point where the angle is has to be in the middle, but for the other two letters, you can choose which one goes where

Step-by-step explanation:

I hope u are asking for average speed

average speed = total distance/total time

= 225/7.5

= 30 km/h or 30 km per hour

Answer:

As Per Provided Information

We have to determine the average speed of his car in kilometres per hour .

Using Formulae

[tex] \boxed {\bf \: Average\: Speed \: = \cfrac{Total \: Distance \: Covered}{ Total \: Time \: Taken }}[/tex]

On substituting the value we get

[tex]\sf \qquad \: \longrightarrow\: Average\: Speed \: = \cfrac{225}{7.5} \\ \\ \\ \sf \qquad \: \longrightarrow\: Average\: Speed = \cancel \cfrac{225}{7.5} \\ \\ \\ \sf \qquad \: \longrightarrow\: Average\: Speed = 30km {h}^{ - 1} [/tex]

Therefore,

So your answer is A) 30 kph .

Answer:

0.6%

Step-by-step explanation:

40% is the percentange of how many students play an instrument. (the whole) 20% is how many freshmen play. (part)

30% are the freshmen. 30% is over 100%.

20 x 100= 2000 and 40 x 30= 1200.

With the answers we got (2000 and 1200) we divide!!

2000÷1200=0.6

Which means the probabillity that the student is a random freshmen is 0.6% :)

Answer:

18+3b-2b-1

b+17

Step-by-step explanation:

[tex]\mathrm{Using\:the\:distributive\:law}:\quad \:-\left(a+b\right)=-a-b[/tex]

[tex]-\left(2b+1\right)=-2b-1[/tex]

[tex]=3\left(6+b\right)-2b-1[/tex]

[tex]=18+3b-2b-1[/tex]

[tex]\mathrm{Group\:like\:terms}[/tex]

[tex]=3b-2b+18-1[/tex]

[tex]\mathrm{Subtract\:the\:numbers:}\:18-1=17[/tex]

[tex]=3b-2b+17[/tex]

[tex]\mathrm{Add\:similar\:terms:}\:3b-2b=b[/tex]

[tex]=b+17[/tex]

[RevyBreeze]

Answer:

The deck's width is 9 feet
The deck's area is 18 feet

Correct po yan

Hope it helps po

Answer:

Deck Width: 6 Feet

Deck Area: 72 Feet Squared

Step-by-step explanation:

[l = length, w = width, f = feet, p = perimeter, a = area]

A = l x w

P = 2l + 2w [l = 12f, p = 36f]

P = 2l + 2w

=> 36f = 2 (12f) + 2w

=> 36f = 24f + 2w

=> 36f - 24f = 2w

=> 12f = 2w

=> 2w/2 = 12f/2

=> W = 6f

Therefore: Width = 6 Feet

A = l × w

A = 12f × 6f

A = 72f^2

Therefore: Area = 72 Feet Squared