Answer:
498 m
Step-by-step explanation:
The AAA theorem states that triangles are similar if all three corresponding angles are equal.
1. Compare triangles FHS and ILS
(a) Reason for similarity
∠F = ∠I = 90°
∠S is common.
∴ ∠H = ∠L
(b) Calculate SL
[tex]\begin{array}{rcl}\dfrac{SF}{SH} & = & \dfrac{SI}{SL}\\\\\dfrac{225}{380} & = & \dfrac{225 + 475}{SL}\\\\225SL & = & 380 \times 700\\& = & 266000\\SL & = & \textbf{1182 m}\\\end{array}[/tex]
2. Compare triangles ILS and GLE
(a) Reason for similarity
∠I = ∠G = 90°
∠L is common.
∴ ∠S = ∠E
(b) Calculate LE
[tex]\begin{array}{rcl}\dfrac{IS}{GE} & = & \dfrac{LS}{LE}\\\\\dfrac{700}{180} & = & \dfrac{1182}{LE}\\\\700LE & = & 180 \times 1182\\& = & 212800\\LE & = & \textbf{304.0 m}\\\end{array}[/tex]
3. Calculate EH
LE + EH + HS = LS
304.0 m + EH + 380 m = 1182 m
EH + 684 m = 1182 m
EH = 498 m
The distance from E to H is 498 m.
Large samples of women and men are obtained, and the hemoglobin level is measured in each subject. Here is the 95% confidence interval for the difference between the two population means, where the measures from women correspond to population 1 and the measures from men correspond to population 2:
negative 1.76 g divided by dL less than mu 1 minus mu 2 less than minus 1.62 g divided by dL
−1.76 g/dL<μ1−μ2<−1.62 g/dL. Complete parts (a) through (c) below.
a. What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in men?
Answer:
a) Because the confidence interval does not include 0 it appears that there
is a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men.
b)There is 95% confidence that the interval from −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2
c) 1.62 < μ1−μ2< 1.76
Step-by-step explanation:
a) What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in men?
Given:
95% confidence interval for the difference between the two population means:
−1.76g/dL< μ1−μ2 < −1.62g/dL
population 1 = measures from women
population 2 = measures from men
Solution:
a)
The given confidence interval has upper and lower bound of 1-62 and -1.76. This confidence interval does not contain 0. This shows that the population means difference is not likely to be 0. Thus the confidence interval implies that the mean hemoglobin level in women and the mean hemoglobin level in men is not equal and that the women are likely to have less hemoglobin than men. This depicts that there is significant difference between mean hemoglobin level in women and the mean hemoglobin level in men.
b)
There is 95% confidence that the interval −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2.
c)
If we interchange men and women then
confidence interval range sign will become positive.μ1 becomes the population mean of the hemoglobin level in menμ2 becomes the population mean of the hemoglobin level in women So confidence interval becomes:1.62 g/dL<μ1−μ2<1.76 g/dL.
There is a significant difference between the mean level of hemoglobin in women and in men.
How to interpret the confidence intervalThe confidence interval of the mean is given as:
[tex]-1.76 g/dL < \mu_1-\mu_2 < -1.62 g/dL[/tex]
The above confidence interval shows that the confidence interval is exclusive of 0.
This means that 0 is not part of the confidence interval
Since the confidence interval is exclusive of 0, then there is a significant difference between the mean level of hemoglobin in women and in men.
Read more about confidence intervals at:
https://brainly.com/question/17097944
Audrey charges a flat fee of $4 for each delivery plus a certain amount,in dollars per mile, for each mile she drives. For a distance of 30 miles, Curtis and Audrey charge the same amount
To prove that the triangles are similar by the SAS similarity theorem, it needs to be shown that
PLEASE PLEASE HELP IM BEING TIMED The two-way table represents data from a survey asking students whether they plan to attend college, travel, or both after high school. A 4-column table with 3 rows. The first column has no label with entries travel, not travel, total. The second column is labeled college with entries 43, 24, 67. The third column is labeled not college with entries 10, 5, 15. The fourth column is labeled total with entries 53, 29, 82. Which is the marginal relative frequency for students who plan to attend college? Round the answer to the nearest percent. 18% 22% 35% 82%
Answer: 82%
Step-by-step explanation:
- - - - - - - - college - - not college - - - - total
Travel - - - - 43 - - - - - - - 10 - - - - - - - - 53
Not travel - 24 - - - - - - - 5 - - - - - - - - - 29
Total - - - - 67 - - - - - - - 15 - - - - - - - - - 82
Marginal relative frequency of students who plan to attend college:
(Number of students who plan to attend the college / Total number of the students)
Number of students who plan to attend college = 67
total number of students = 82
Marginal relative frequency = 67/82
= 0.8170731
= (0.8170731) * 100%
= 81.7% = 82%
Answer:
a: 14/50
b: 15/50
c: 21/50
Step-by-step explanation:
on edge
The side length of each square is 6 units. Find the areas of the inscribed shapes.
Answer:
a) A₁ = 18 unit²
b) A₂ = 20 unit²
c) A₃ = 12 unit²
d) A₄ = 12 unit²
Step-by-step explanation:
a) Given that the side length of square is 6 units, we have;
The height of the square = The height of the triangle = 6 units
The base of the triangle = The side length of the square = 6 units
The area of a triangle A₁ = 1/2×base×height = 1/2×6×6 = 18 unit²
b) The side of the square A₂ forms an hypotenuse side to the side length 2 and 4 on sides of the circumscribing square
The length of the side = √(4^2 + 2^2) = 2·√5
A₂ = The area of a square =Side² = (2·√5)² = 20 unit²
c) The base length of the triangle, A₃ + 2 = The side length of the circumscribing square = 6 units
∴ The base length of the triangle, ₃₂ = 6 - 2 = 4 units
The height of the triangle, A₃ = The side length of the circumscribing square = 6 units
The area of a triangle A₃ = 1/2×base×height = 1/2×4×6 = 12 unit²
d) Figure, A₄, is a parallelogram;
The area of a parallelogram = Base × Height
The base of the parallelogram, A₄ + 4 = 6 units
Therefore, the base of the parallelogram, A₄ = 6 - 4 = 2 units
The height of the parallelogram = The side length of the circumscribing square = 6 units
The area of a parallelogram A₄ = 2× 6 = 12 unit².
Which equation represents the line that passes through (-6, 7) and (-3, 6)?
y=-*x+9
y=-*x+5
y=-3x – 1ly
y=-3x + 25
Answer:
y = -3x - 11
Step-by-step explanation:
(y - y1)/(x - x1) = (x2 - x1)/(y2 - y1)
(y - 7)/(x + 6) = (-3 + 6)/(6 - 7)
(y - 7)/(x + 6) = 3/-1 = -3
y - 7 = -3(x + 6)
y - 7 = -3x - 18
y = -3x -18 - 7
y = -3x - 11
What is the best first step to solve this equation 8x =25 ?
Hey there!
"8x = 25"
In order for you to solve for "x-value" (or the equation) we have to DIVIDE both of your sides by 8
8x/8 = 25/8
Cancel out: 8x/8 because that gives you the value of 1 and you don't need it at the moment (in that equation that is)
Keep: 25/8 Because it solves for your equation
Your x equals: 25/8 aka 1 1/8 aka 3.125 (you could choose any one of these as your answer because they are all correct)
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
The equations 9 x minus 10 y = 6, 8 x minus 10 y = negative 23, 9 x + 10 y = negative 16, and 8 x + 10 y = 13 are shown on the graph below. On a coordinate plane, there are 4 lines. Green line goes through (negative 2, 0.75) and (negative 2, 1.5). Blue line goes through (negative 1.75, 0) and (1, negative 2). Pink line goes through (negative 1.5, negative 2), and (1.5, 0.75). Purple line goes through (0, 1.25) and (1, 0.5). PLEASE ANSWER IS 2 MINUTES WILL GIVE BRAINLIEST Which is the approximate solution for the system of equations 8 x minus 10 y = negative 23 and 9 x + 10 y = negative 16? (–2.3, 0.5) (–2.5, 1) (–2.3, –0.5) (–2.5, –1)
Answer:
Step-by-step explanation:
The two equations are 8x-10y=-23 and 9x+10y=-16.
If you plug them both into a graphing calculator, you will see that the point where they cross (the solution) is (-2.3, 0.5).
The answer is A.
Answer:
i think it is A
Step-by-step explanation:
if right pls give brainliest
Nvm it is right pls give brainliest i need 5 to get to next rank
Simplify.
A12 over a7
Answer:
a^5.
Step-by-step explanation:
a^12 / a^7 = a^(12 - 7) = a^5.
Hope this helps!
Write a polynomial f(x) that satisfies the given conditions.
8
Degree 3 polynomial with integer coefficients with zeros -5i and
5
Answer:
f(x) = x^3 -5x^2 +25x -125
Step-by-step explanation:
For zero x=a, one of the factors is (x -a). If the polynomial has integer coefficients, its complex roots come in conjugate pairs. So, the roots are ...
roots: -5i, 5i, 5
factors: (x -(-5i))(x -5i)(x -5)
Multiplying these out gives your polynomial as ...
f(x) = (x^2 +25)(x -5)
f(x) = x^3 -5x^2 +25x -125
A paintball court charges an initial entrance fee plus a fixed price per ball. P represents the total price (in dollars) as a function of the number of balls used n P=0.80n+5.50 What is the price for 10 balls, not including the entrance fee?
Answer:
$8
Step-by-step explanation:
It says P = per ball (which will be a number, n, for balls times the fixed price) plus a set entrance fee. So we find that the price per ball is $0.80, so 10 balls cost $8.
Answer:
$8
Step-by-step explanation:
I am starting to get this but, each question is a different subject so plz help asap. Btw these are not test or quiz questions. They are just practice questions so I know how to do it before a test or quiz.
Answer:
73 degrees
Step-by-step explanation:
Given
A Shaped Frame of two congruent sides
Required
Determine the angle made with the ground
Given that there are two congruent sides, this implies that the A frame is an isosceles triangle;
Let the two angles made with the ground be represented by x
Angles in a triangle when added equals 180;
Hence;
[tex]x + x + 34 = 180[/tex]
[tex]2x + 34 = 180[/tex]
Subtract 34 from both sides
[tex]2x + 34 - 34 = 180 - 34[/tex]
[tex]2x = 180 - 34[/tex]
[tex]2x = 146[/tex]
Divide both sides by 2
[tex]\frac{2x}{2} = \frac{146}{2}[/tex]
[tex]x = \frac{146}{2}[/tex]
[tex]x = 73[/tex]
Hence, the angle with the ground is 73 degrees
Write an equation of the line that passes through the point (-6, -5) with slope 6.
A. y +5= -6(x+6)
B.y+6= -6(x+5)
C. y+6=6(x+5)
D.y+5= 6(x+6)
Answer:
The answer is option D.
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
Equation of a line from given a Slope and a point is
y - y1 = m(x - x1)
Where ( x1 , y1) is the point
Equation of the line using point (-6 , -5) and slope 6 is
y + 5 = 6(x - 6)Hope this helps you
In a school, half of the 300 students saw Zootopia, 180 students saw Finding Dory, and 45 students did not see either movie. How many students saw both movies?
Answer:
150
Step-by-step explanation:
Answer:
150 = half of 300
± 180
230
soooo 230 students
Step-by-step explanation:
Which of the following options could represent a possible set of interior angles of a triangle? 100°, 130°, and 130° 30°, 70°, and 80° 25°, 3°, and 35° 45°, 105°, and 120°
Answer:
2) 30, 70, 80
Step-by-step explanation:
Well there has to be 3 angles that all add up to 180°.
1)
100+130+130
=360
2)
30+70+80
= 180
3)
25+3+35
=63
4)
45 + 105 + 120
=150
150+120
270
what is a continent To eliminate the terms and solve for y in the fewest steps, by which constants should the equations be multiplied by before adding the equations together? First equation: 9x + 3y = -18 Second equation: 8x + 7y = 10
Answer:
To eliminate solve for y, we need to eliminate x and we will do that by multiplying the first equation by 8 and multiply the second equation by 9.
y=6
Step-by-step explanation:
In the equations:
9x + 3y = -18 -----------------------------------------------------------------(1)
8x + 7y = 10 --------------------------------------------------------------------(2)
To solve for y, we will have to eliminate x
To eliminate x, we will follow the steps below;
multiply equation (1) through by 8 and multiply equation (2) through by 9
The resulting equations are
72x + 24y = -144 ----------------------------------------------------------(3)
72x + 63y = 90 -----------------------------------------------------------(4)
Then we will go ahead and subtract equation (4) from equation (3)
39y =234
divide both-side of the equation by 39
39y /39=234/39
y=6
3. In the diagram, PRST and PQWV are rectangles. Q, V
and U are midpoints of PR, PU and PT respectively.
Find the area of the shaded region.
======================================================
Work Shown:
A = area of trapezoid RSTU
A = height*(base1+base2)/2
A = ST*(UT+RS)/2
A = 14*(5+10)/2
A = 105 square cm
-----------------------
B = area of rectangle PQWV
B = length*width
B = WV*PV
B = 7*2.5
B = 17.5 square cm
If you're curious how I got PV = 2.5, you basically cut PT = 10 in half twice. So you go from 10 to 5, then from 5 to 2.5; which works because we have a bunch of midpoints.
-----------------------
C = total shaded area
C = A + B
C = 105 + 17.5
C = 122.5
In one design being considered for the containers shaped like a rectangular prism, each
container will have a height of 114 inches and length of 74 inches. What will be the within
inches, of the container?
A.3
B.4
C.14
D.15
Answer:
your answer is A 3 inches
The Big Telescope Company sells circular mirrors. Their largest mirrors have radii of 5 meters and their smallest mirrors have radii of 1 meter. The cost of every mirror is proportional to the cube of the mirror's radius. What is the ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors? Express your answer as a common fraction.
Answer:
The answer is 1/5
Step-by-step explanation:
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minus 9 x EndFraction minus StartFraction x + 1 Over x squared minus 9 EndFraction StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction StartFraction (x + 5) (x + 4) Over x cubed minus 9 x EndFraction StartFraction negative 2 x + 11 Over x cubed minus 12 x minus 9 EndFraction StartFraction 3 (x + 2) Over x squared minus 3 x EndFraction
Answer:
[tex] \frac{(x + 5)(x + 2)}{ {x}^{3} - 9x } [/tex]First option is the correct option.
Step-by-step explanation:
[tex] \frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 } [/tex]
Factor out X from the expression
[tex] \frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9} [/tex]
Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] , factor the expression
[tex] \frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)} [/tex]
Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )
[tex] \frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)} [/tex]
Multiply the parentheses
[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)} [/tex]
When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression
[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)} [/tex]
Distribute -x through the parentheses
[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x }{x(x - 3)(x + 3)} [/tex]
Using [tex] {a}^{2} - {b}^{2} = (a + b)(a - b)[/tex] , simplify the product
[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)} [/tex]
Collect like terms
[tex] \frac{ {x}^{2} + 7x + 15 - 5}{x( {x}^{2} - 9)} [/tex]
Subtract the numbers
[tex] \frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)} [/tex]
Distribute x through the parentheses
[tex] \frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x} [/tex]
Write 7x as a sum
[tex] \frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x } [/tex]
Factor out X from the expression
[tex] \frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x} [/tex]
Factor out 2 from the expression
[tex] \frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x } [/tex]
Factor out x + 5 from the expression
[tex] \frac{(x + 5)(x + 2)}{ {x}^{3} - 9x } [/tex]
Hope this helps...
Best regards!!
The difference of the expression [tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex] is [tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]
The expression is given as:
[tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex]
Factorize the denominators
[tex]\frac{2x + 5}{x(x -3)} - \frac{3x + 5}{x(x^2 - 9)} - \frac{x + 1}{x^2 - 9}[/tex]
Apply the difference of two squares to the denominators
[tex]\frac{2x + 5}{x(x -3)} - \frac{3x + 5}{x(x - 3)(x + 3)} - \frac{x + 1}{(x - 3)(x + 3)}[/tex]
Take LCM
[tex]\frac{(2x + 5)(x + 3) - 3x - 5 -x(x + 1) }{x(x - 3)(x + 3)}[/tex]
Expand the numerator
[tex]\frac{2x^2 +6x + 5x + 15 - 3x - 5 -x^2 - x }{x(x - 3)(x + 3)}[/tex]
Collect like terms
[tex]\frac{2x^2 -x^2 - x +6x + 5x - 3x+ 15 - 5 }{x(x - 3)(x + 3)}[/tex]
Simplify
[tex]\frac{x^2+7x+ 10 }{x(x - 3)(x + 3)}[/tex]
Factorize the numerator
[tex]\frac{(x+5)(x+ 2) }{x(x - 3)(x + 3)}[/tex]
Expand the denominator
[tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]
Hence, the difference of the expression [tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex] is [tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]
Read more about equivalent expressions at:
https://brainly.com/question/2972832
Translate into an algebraic expression and simplify if possible. C It would take Maya x minutes to rake the leaves and Carla y minutes, what portion of the leaves do they rake in one minute if they work together?
Answer:
in one minute they rake [tex]\frac{y+x}{xy}[/tex] leaves working together.
Step-by-step explanation:
If Maya rakes the leaves in x minutes, then, in one minute she rakes [tex]\frac{1}{x}[/tex] leaves.
In the case of Carla, if she rakes the leaves in y minutes, in one minute she rakes [tex]\frac{1}{y}[/tex] leaves.
Therefore, to know the portion of leaves they can rake in one minute working together, we need to sum up both of the portions each one of them rake in one minute, this gives us: [tex]\frac{1}{x}+ \frac{1}{y}[/tex]
Now, to simplify this expression:
[tex]\frac{1}{x}+ \frac{1}{y} =\frac{y+x}{xy}[/tex]
Thus, in one minute they rake [tex]\frac{y+x}{xy}[/tex] leaves.
Figure A is a scale image of Figure B. What is the value of x?
Answer:
x = 5.4
Step-by-step explanation:
Multiply 7.2 by 3/4 to find the equivalent ratio.
Answer:
5.4Step-by-step explanation:
[tex] \frac{7.2}{x} = \frac{4}{3} [/tex]
Apply cross product property
[tex]4x = 7.2 \times 3[/tex]
Multiply the numbers
[tex]4x = 21.6[/tex]
Divide both sides of the equation by 4
[tex] \frac{4x}{4} = \frac{21.6}{4} [/tex]
Calculate
[tex]x = 5.4[/tex]
Hope this helps..
best regards!!
is the folllowing shape a square? how do you know
Answer:If it has 4 equal sides
If the angles are 90°
Hope this may helps you
Answer:
A square is characterized by
4 equal sides.Each angle measures 90°Diagonals meet and bisect each other at 90°Opposite sides are parallel and equal.Diagonals are equal.Hope this helps ;) ❤❤❤
What is the sine value of pi over 6? negative 1 over 2 1 over 2 negative square root 3 over 2 square root 3 over 2
Answer:
1/2
Step-by-step explanation:
[tex]sin(\frac{\pi }{6} )=\frac{1}{2}[/tex]
sin(pi) = 0
sin(7pi/6) = -1/2
sin(pi/6) = 1/2
sin 3pi/2 = -1
sin pi/2 = 1
sin pi/3 = √3/2
sin 4pi/3 = -√3/2
Answer:
1/2
Step-by-step explanation:
I got it right on the exam.
If a equals 15, then what number does 2a - 5 equal?
Answer:
25
Step-by-step explanation:
a=15
2(15)-5=25
30-5=25
Answer:
25
Step-by-step explanation:
The problem substituting a for 15 would be 2(15)-5
2*15 is 30, then -5 is 25.
If some of the omitted variables, which you hope to capture in the changes analysis, in fact change over time within entity, then the FE estimator a. will be unbiased only when allowing for heteroskedastic-robust standard errors. b. may still be biased. c. will only be unbiased in large samples. d. will always be unbiased.
Answer:
d. will always be unbiased.
Step-by-step explanation:
When some of variables are omitted the estimator on indulge charge regressor may still be unbiased. If there is a special case where T = 2 then the FE estimator will be unbiased. Fixed effect regression model has different intercepts.
Which way would you choose to solve 3/x=6/14 ?
Explain your reasoning.
Answer:
I'd cross multiply to solve this equation.
Step-by-step explanation:
Since we have a fraction where we're finding a ratio:
[tex]\frac{3}{x} = \frac{6}{14}[/tex],
I'd find it easiest to cross multiply. This is because we are finding an equivalent to a ratio, so cross multiplication works best here.
Let's solve it.
[tex]14\cdot 3 = 42\\42\div6=7[/tex]
x = 7
Hope this helped!
The surface area of a sphere is 3000 m square units. What is the volume of the sphere to the nearest hunderedth?
Answer:
The answer is
15448m³Step-by-step explanation:
To find the volume of the sphere we must first find the radius
Surface area of a sphere = 4πr²
where r is the radius
From the question surface area = 3000m²
3000 = 4πr²
Divide both sides by 4π
750/π = r²
Find the square root of both sides
r = 15.45 cm
Volume of a sphere is 4/3πr³
So we have
4/3π(15.45)³
= 15448.06
= 15448m³ to the nearest hundredth
Hope this helps you
Karen has $600. She spent $240 on clothes. What percentage of money did she have left?
Answer: She had 60% of the money left
Step-by-step explanation:
240/600=0.4
0.4 = 40%
100%-40%=60%
Answer:
60%
Step-by-step explanation:
LETS MAKE IT INTO A FRACTION
FIRST LETS CALCULATE HOW MUCH SHE SPENT
=240/600
WE CAN SIMPLIFY BY DIVIDING THE EQUATION BY 10
=24/60
LETS DIVIDE BY 6
=4/10
DIVIDE BY 2
=2/5
NOW LETS CALCULATE HOW MUCH SHE HAS LEFT
THE EASIEST WAY IS TO SUBTRACT
5/5-2/5=3/5
3/5 IS ALSO EQUAL TO 60/100
SO KAREN HAS 60% OF HER MONEY LEFT
HOPE I HELPED
PLS MARK BRAINLIST
(DESPERATELY TRYING TO LEVEL UP)
✌
solve for n: 5n-14<1
Answer: n< 3
Step-by-step explanation:
5n - 14 < 1 . add 14 to both sides
5n -14 +14 < 1 + 14
5n +0 < 15
5n < 15 divide both sides by 5 .5n/5 = 15/5
n < 3