A two-state system is in an environment at temperature 500 K. The energy of state 1 is 4.1e-20 J, and the energy of state 2 is 5.7e-20 J. Let be the probability of finding the system in state 1, and be the probability of finding the system in state 2. What is the ratio

Answers

Answer 1

Complete Question

A two-state system is in an environment at temperature 500 K. The energy of state 1 is[tex]E_1=4.1e-20 J[/tex], and the energy of state 2 is [tex]E_2= 5.7e-20 J[/tex]. Let P(1) be the probability of finding the system in state 1, and be the probability of finding the system in state 2. What is the ratio P(2)/P(1)

Answer:

 [tex]X=0.0984[/tex]

Step-by-step explanation:

From the question we are told that:

Temperature T=500 K

Energy of state 1 [tex]E_1=4.1e-20 J[/tex],

Energy of state 2 is [tex]E_2= 5.7e-20 J[/tex]

Generally the equation for Probability of finding the system in state is mathematically given by

 [tex]P(1)=e ^{\frac{-E_1}{KT}}[/tex]

Therefore

For Probability of finding the system in state 1 [tex]P(1)[/tex]

 [tex]P(1)=e ^{\frac{-E_1}{KT}}[/tex]

Where

   K is Boltzmann constant

   [tex]K=1.38*10^{-23}[/tex]

 [tex]P(1)=e ^{\frac{-(4.1e-20 J)}{1.38*10^{-23}*500}}[/tex]

For Probability of finding the system in state 1 [tex]P(2)[/tex]

 [tex]P(2)=e ^{\frac{-(5.7e-20 J)}{1.38*10^{-23}*500}}[/tex]

Generally the equation for The Ratio of [tex]P(2)[/tex] and [tex]P(2)[/tex] is mathematically given by

 [tex]X=\frac{P(2)}{p(1)}[/tex]

 [tex]X=e ^{\frac{E_1-E_2}{KT}}[/tex]

 [tex]X=e ^{\frac{-(4.1-5.7)e-20 J)}{1.38*10^{-23}*500}}[/tex]

 [tex]X=0.0984[/tex]


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Answer:

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Step-by-step explanation:

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Answers

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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