A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what distance from the left end of the rod should a 0.6kg mass be hung to balance the rod?
a.48 cm
b. 50 cm
c. 45 cm
d. the rod can not be balanced with this mass. e.42 cm
NO LINKS. ​

Answers

Answer 1

Answer:

correct  is C

Explanation:

In this exercise we will use the rotational equilibrium relationships. Let's set the datum at the pivot point and counterclockwise rotations as positive

             

as the bar is uniform its center of mass coincides with its geometric center

          x_{cm} = 0.25 cm

the distance from the fulcrum is

          x₁ = 0.40 - xcm

          x₁ = 0.40 - 0.25

          x₁ = 0.15 m

         Στ = 0

         w_bar 0.15 - W x = 0

         x = 0.15 w_bar / W

         x = 0.15 m_{bar} / M

let's calculate

         x = 0.15 0.2 /0.6

         x = 0.05 m

this distance is measured from the pivot point of the positive side, if we measure from the left end of the bar

          X = 0.4 + 0.05

          X = 0.45 m = 45 cm

correct  is C


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otinni oSame lage ta dili pud ko ka comment sa live Ni madamstin

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it can be used to locate underwater objects

What is the purpose of a tuner in a radio?

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Answer:

A tuner is a subsystem that receives radio frequency (RF) transmissions and converts the selected carrier frequency and its associated bandwidth into a fixed frequency that is suitable for further processing, usually because a lower frequency is used on the output.

hope it helps ya mate.

Answer:

The tuner selects only the signal of a specific frequency and rejects the rest.

Explanation:

pf

I want the answer and that’s all

Answers

Answer:

Cuboid?

Explanation:

A student must determine how the mass of a block affects the period of oscillation when the block is attached to a vertical spring. The value of the spring constant is known. The student writes the following experimental procedure.

1. Use an electronic balance to measure the mass of the block.
2. Attach the block to the vertical spring.
3. Displace the block from the system's equilibrium position to a new vertical position.
4. Release the block from rest.
5. Use a meterstick to measure the vertical displacement of the center of mass of the block from the system's equilibrium position to its maximum vertical position above the equilibrium position.
6. Use a stopwatch to measure the time it takes for the system to make ten complete oscillations.
7. Repeat the experiment for different vertical displacements and block masses.

Which of the following steps of the procedure should the student revise to make the determination? Justify your selection.

a. Step 3, because the student must specify whether the new vertical position should be above or below the system's equilibrium position.
b. Step 5, because the meterstick should be used to measure total displacement of the system from its lowest vertical position to its highest vertical position.
c. Step 6, because the stopwatch should be used only to measure the time it takes for the system to make 1 complete oscillation.
d. Step 7, because the experiment should not be repeated for different vertical displacements and block masses.

Answers

Answer:

the step that the student should change is step 7

Explanation:

The movement of the spring with block is a simple harmonic type movement, so the procedure proposed by the student is correct, but we must take some care.

Step 3 is important since each movement will be started with similar conditions, also if any displacement is very large we can get out of the linear approximation of Hooke's law, for which we need to know the equilibrium point, since from this point displacements will be measured.

Step 6 should be changed to measure various oscillations to find the average period and thus decrease the error in the time reading.

Step 7 is wrong since the objective of the experiment is to analyze the effect of different masses in the period of oscillation and this step prevents this objective from being carried out.

In conclusion, the step that the student should change is step 7

The step that should be revised to make the determination is c. Step 6, because the stopwatch should be used only to measure the time it takes for the system to make 1 complete oscillation.

Why should step 6 be revised?

The student is trying to find the effect of the mass of the block on the period of oscillation in different vertical displacements.

The best way to do this is to measure the time taken per oscillation as this would show a much clearer picture to find the effect of the mass on the oscillation. Timing 10 oscillations will yield incorrect results.

In conclusion, option C is correct.

Find out more on measuring the effect of mass on oscillation at https://brainly.com/question/14745507.

what do you mean by wave
optics​

Answers

Answer:

hope it helps.

stay safe healthy and happy.
In physics, physical optics, or wave optics, is the branch of optics that studies interference, diffraction, polarization, and other phenomena for which the ray approximation of geometric optics is not valid.

State the role of an electromotive force (EFF) in a current flow

Answers

Answer:

The emf source acts as a charge pump, moving negative charges from the positive terminal to the negative terminal to maintain the potential difference. This increases the potential energy of the charges and, therefore, the electric potential of the charges.

Explanation:

MARK AS BRAINLEST!!

1. Which of the following statement is correct?
A. You should panic when earthquake hits.
B. You should run while the earthquake is going on,
C. You should not follow what the proper authorities will tell you.
D. You should prepare an emergency plan to cope with the disaster.
2. What should you do during an earthquake?
A. You should run out of the house.
B. You should duck, cover, and hold.
C. You should panic and stay only inside the house.
D. You should lock your door so that nobody can enter,​

Answers

Answer:

1.

D. You should prepare an emergency plan to cope with the disaster.

2.

B. You should duck, cover, and hold.

Explanation:

Because Panic and stress are the main reasons that make the situation worse during natural disasters. Disasters are aggravated when people add chaos to the equation. It's important not to panic during an earthquake. You must maintain a rational state of mind so that you don't do something regretful out of fear.

1. Which of the following statement is correct?

A. You should panic when earthquake hits. ❌

B. You should run while the earthquake is going on. ❌

C. You should not follow what the proper authorities will tell you. ❌

[tex]\sf\purple{D.\:You \:should \:prepare\: an \:emergency \:plan\: to \:cope\: with\: the\: disaster. }[/tex]✅

........................................................................

2. What should you do during an earthquake?

A. You should run out of the house. ❌

[tex]\sf\pink{B.\:You\: should \:duck,\: cover, \:and \:hold.}[/tex] ✅

C. You should panic and stay only inside the house. ❌

D. You should lock your door so that nobody can enter. ❌

........................................................................

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Wave A is being decreased in temperature, and Wave B is moving from a liquid to a gas
medium
6. Which statement can be made about both waves? (1 point)
They will speed up.
They will increase the density of their medium.
They will slow down.
They will decrease the density of their medium.

Answers

Answer:

They will speed up, and decrease in density.

Explanation:

This is because, when water is heated, the molecules will spread apart, and bounce off each other. It gives them more space, and they are less tight packed, so it can move around freely.

a shopping bag can provide an upward force of 65N before breaking. A shopper puts 5 kg of groceries in the bag. If the shopper tries to lift the bag with an upward acceleration of 2 m/s/s, will the bag break?

Answers

Answer:

Since Force is Mass * Acceleration, the equation would be:

5kg * 2m^2 = 10N

(10N is less than 65N)

Therefore, it would not be enough force for the bag to break.

What is the frequency of a 5 m wave traveling at the speed of 200 m/s

Answers

Explanation:

f=v/wavelength

=200/5

=40Hz

Which statement is true about the part of the electromagnetic spectrum that human eyes can detect?

It contains ultraviolet, visible, and infrared light.

It is divided into nine ranges of wavelengths.

It is divided into seven ranges of wavelengths.

It contains only the colors of the rainbow and television waves.

Answers

Answer:

A. it contains ultraviolet, visible, and infrared light

Answer:

It is divided into seven ranges of wavelengths

Explanation:

i took the test

An african bush elephant has a mass of 5,900 kg and is on a skateboard traveling to the
left at 10 m/s. What is her momentum?

Answers

The momentum is zero. The elephant broke the skateboard

Every household has at least one refrigerator, many hotels have ice makers. you may have wondered how much heat energy a refrigerator / ice maker takes
from water to make ice. Compute the amount of energy an
ice maker extracts from 200g of water at 34°c to manufacture ice at 0°c.​

Answers

That sounds so hot sheashh

Answer:

1.heading

2.photo

3.boldface text

4.caption

5.bulleted list

Explanation:

you welcome

leafy greens are considered the healthiest vegetable because of their ___ nutrients profile

Answers

Dense because food do be dense tho

i need help with these questions thank u

Answers

Answer:

duvergentv boundaries

A physics professor demonstrates the Doppler effect by tying a 900 Hz sound generator to a 1.0- m -long rope and whirling it around her head in a horizontal circle at 100 rpm .
1. What is the difference between the highest frequency heard by a student in the classroom and the initial frequency of the sound generator?
2. What is the difference between the lowest frequency heard by a student in the classroom and the initial frequency of the sound generator?

Answers

Hi how was your day today person

A 20" round duct is 275' in length. The duct is carrying 2,900 CFM at a friction loss of 0.12 inches WG per 100 feet.

What is the total friction loss through the duct?

Answers

50500000 FACTION : uo/80

A 1,700 kg car is accelerated at 2.8 m/s? What force was needed to produce this acceleration?

Answers

Answer:

[tex]4,760\:\mathrm{N}[/tex]

Explanation:

From Newton's 2nd Law, we have [tex]\Sigma F=ma[/tex]. Substituting given values, we get:

[tex]F=1700\cdot 2.8,F=\boxed{4,760\:\mathrm{N}}[/tex]

A neutral metal can is mounted on a foam stand. A positively

charged balloon is brought near. The can is touched on the

opposite side.

Answers

Answer:

Negative

Positive

Explanation:

When a positive charge balloon is brought near the neutral metal can, the positive charge in the ballon, delocalization and arrangement of like charges occurs. The positive charge then flow to the an end while the negative charges flows to the other end.

Thus, after being touched, the charge on the can is negative.

And, If not touched, the charge on the ballon remains positive.

After being touched, the charge on the can is negative and the charge on the balloon is positive.

What is charging by friction?

When the two materials are rubbed each other, then the electric charged generated between them.

This charging of materials due to the rubbing or two materials against each other, is called the charging by friction.

This force of attraction or repulsion is identified by the sign of the particular charge. According to the property of interacting charges-

Like charges-For the like charges, when two charges same charges (positive-positive or negative -negative) interact to each other, then the charges repel each other.Unlike charges-For the unlike charges, when two charges interact to each other, then the charges attract each other.

Here, the neutral metal can is mounted on a foam stand. A positively charged balloon is brought near. The can is touched on the opposite side.

The positive charge on the balloon, make it to lose the electron. By this, the balloon become positively charged.

The atom on the opposite side have an excess of electron. Thus, the can become negatively charged.

Hence, after being touched, the charge on the can is negative and the charge on the balloon is positive.

Learn more about the charging by friction here;

https://brainly.com/question/8418256

The nuclear reactions inside a star, such as our
sun, convert hydrogen into helium by means of a
process
known as?

Answers

Answer:

fusion

Explanation:

The nuclear reactions inside convert hydrogen into helium by means of a process known as fusion. It is this nuclear reaction that gives a star its energy. Fusion takes place when the nuclei of hydrogen atoms with one proton each fuse together to form helium atoms with two protons.

A force of 20 N acts on a smaller piston of a hydraulic press with an area of ​​10 dm2. How much force does the liquid act on a larger piston of 120 cm2?​

Answers

Answer:

166.67 N

Explanation:

Applying Pascal's principle,

Presure in the smaller piston(P') = Pressure in the bigger piston(P)

But,

Pressure = Force/Area

Pressure in the smaller piston(P') = Force applied to the smaller piston(F')/Area of the smaller piston(A')

Pressure in the bigger piston(P) =  Force applied to the bigger piston(F)/Area of the bigger piston(A)

F'/A' = F/A.................. Equation 1

Make F the subject of the equation

F = F'A/A'.............. Equation 2

From the question,

Given: F' = 20 N, A = 120 cm², A' = 10 dm² = (10×100) = 1000 cm²

Substitute these values into equation 2

F = 20(1000)/120

F = 166.67 N

May
SHOW YOUR WORK IN ALL QUESTIONS. Acceleration due to gravity: a = 9.81 m/s2
1.) (a) A ball is dropped from 4 meters above the ground. If it begins at rest, how long does it take
to hit the ground?
(b) A ball is thrown upward at 4 meters per second starting from ground level. How long does it
take for the ball to return to the ground?
(c) If a ball that is 4 meters above the ground is thrown horizontally at 4 meters per second,
how long will it take for the ball to hit the ground?
(d) In question (c) above, how far will the ball travel in the horizontal direction before it hits th
ground?
(e) Drop a ball from a height of 2 meters and, using a stopwatch, record the time it takes to
reach the ground. Repeat this two more times and record all the times in the table belov-
then find the average time. Be sure to release the ball from rest rather than throwing it
or down.
Test Number
Time (seconds)​

Answers

Answer:

a)  t = 0.90 s, b)  t = 0.815 s, c)  t = 0.90 s, d)  x = 3.6 m, e)  t = 0.639 s

Explanation:

all these exercises are about kinematics

a) The body is released from rest,  

           y = y₀ + v₀ t - ½ g t²

in this case when reaching the ground y = 0 and its initial velocity is vo = 0

           0 = y₀ + 0 - ½ g t²

           t² = 2 y₀ / g

           t² = 2 4 /9.81

           t² = 0.815

            t = √0.815

           t = 0.90 s

b) It is thrown upwards at v₀ = 4 m / s

         y = y₀ + v₀ t - ½ g t²

in this case the initial and final height is the same

        y = y₀ = 0

        0 = v₀ t -1/2 g t²

        t = 2 v₀ / g

        t = 2 4 /9.81

        t = 0.815 s

c) the ball is at y₀ = 4 m and its initial velocity is horizontal v₀ = 4 m / s

        y = y₀ + v_{oy} t - ½ g t²

        0 = y₀ + 0 - ½ g t²

        t² = 2 i / g

        t² = 2 4 / 9.81

        t² = 0.815

        t = 0.90 s

d) the horizontal distance traveled is

        x = v₀ₓ t

        x = 4 0.90

        x = 3.6 m

e) We can calculate the time to fall from I = 2 m

        y = y₀ + v_{oy} t - ½ g t²

        0 = y₀ + 0 - ½ g t²

        t² = 2 y₀i / g

        t² = 2 2 /9.81

        t² = 0.4077

        t = 0.639 s

Therefore, when making measurements, you should find readings around this value.

A force of 20 N acts on a smaller piston of a hydraulic press with an area of ​​10 dm2. How much force does the liquid act on a larger piston of 120 cm2?​

Answers

Answer:

166.6 N

Explanation:

Given that,

Force, F₁ = 20 N

Area, A₁ = 10 dm² = 1000 cm²

We need to find the new force if the area of the larger piston is 120 cm². According to Pascal's law,

[tex]F_1A_1=F_2A_2\\\\F_2=\dfrac{F_1A_1}{A_2}\\\\F_2=\dfrac{20\times 1000}{120}\\\\F_2=166.7\ N[/tex]

So, the force on the larger piston is equal to 166.7 N.

Car A of mass 1200kg traveling at 10m/s , collided in too the back of the car B, which is stationary. Following the collision,. The two cars stick together and travel at 6m/s. What is the mass of a car B?

Answers

Answer:

Car B has a mass of 800 kg.

General Formulas and Concepts:

Momentum

Law of Conservation of Momentum: [tex]\displaystyle m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v_{f}[/tex]

Explanation:

Step 1: Define

Identify variables

[Given] m₁ = 1200 kg

[Given] v₁i = 10 m/s

[Solve] m₂

[Given] v₂i = 0 m/s

[Given] vf = 6 m/s

Step 2: Solve for m₂

Substitute in variables [Law of Conservation of Momentum]:                       (1200 kg)(10 m/s) + m₂(0 m/s) = (1200 kg + m₂)(6 m/s)Multiply:                                                                                                             12000 kg · m/s = (1200 kg + m₂)(6 m/s)Isolate m₂ term:                                                                                                2000 kg = 1200 kg + m₂Isolate m₂:                                                                                                         800 kg = m₂

Answer:

Explanation:

Caraofmass1200kg

Blackbody radition is white give reasons.?​

Answers

Answer:An object that absorbs ALL radiation falling on it, at all wavelengths, is called a blackbody. When a blackbody is at a uniform temperature, its emission has a characteristic frequency distribution that depends on the temperature. ... As its temperature increases further it becomes yellow, white, and ultimately blue-white

Explanation:

explain the reason why water wet glass why Mercury does not​

Answers

Answer:

Mercury does not wet the glass because the cohesive force with the drops is stronger than the adhesive force between the drops and glass.

...https://www.toppr.com › ask › en-us › question › merc..

Explanation:

A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what distance from the left end of the rod should a 0.6kg mass be hung to balance the rod?
a.48 cm
b. 50 cm
c. 45 cm
d. the rod can not be balanced with this mass. e.42 cm​

Answers

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

[tex]15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm[/tex]

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

A ball is dropped freely from the top of a ten-floor building in which each floor is measured to be 2 m. Then the velocity of the ball at which it would hit the ground is ?

Answers

Answer:

19.80 m/s

Explanation:

From the question given above, the following data were obtained:

Height of each floor = 2 m

Total Height (h) = 2 × 10 = 20 m

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

The velocity at which the ball will hit the ground can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 20)

v² = 0 + 392

v² = 392

Take the square root of both side

v = √392

v = 19.80 m/s

Thus, the ball will hit the ground with a velocity of 19.80 m/s

How far an object moves from a reference point is known as
type your answer...

Answers

Answer:

distance

hope it helps

Explanation:

-

A hammer taps on the end of a 5.0-mm-long metal bar at room temperature. A microphone at the other end of the bar picks up two pulses of sound, one that travels through the metal and one that travels through the air. The pulses are separated in time by 9.00 ms.

Required:
What is the speed of sound in this metal?

Answers

Answer:

896.5 m/s

Explanation:

Given that :

Length of metal bar, λ= 5 m

Velocity in air, v = 343 m/s

Change in air frequency : = λ / v

f = 5 / 343 = 0.0145772 s = 14.5772 ms

Seperation time = 9ms

Change in time, t = 14.5772 - 9 = 5.5772 ms

Recall :

Velocity = Distance / time

V = 5m / 5.5772 * 10^-3 s

V = 896.50720 m/s

Velocity = 896.5 m/s

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