Answer:
Newton
Explanation:
Newton's are the standard unit of force.
A 65 kg cart travels at a constant speed of 4.6 m/s. What is its kinetic energy?
Answer:
Explanation:
mass (m) = 65 kg
velocity (v) = 4.6 m/s
Kinetic energy (KE)
= 1/2 * m * v²
= 1/2 * 65 * 4.6²
= 687.7 J
hope it helps :)
Forces act on a box that is initially at rest as shown. Coefficient of friction between the object and the surface is μ=0.1.
If the box' mass is 6kg box and if it is moving with acceleration of 0.4m/s2, what distance will the box travel if it was pushed for 4s?
Answer:
3.2 m
Explanation:
From the question given above, the following data were obtained:
Coefficient of friction (μ) = 0.1
Initial velocity (u) = 0 m/s
Mass (m) = 6 Kg
Acceleration (a) = 0.4 m/s²
Time (t) = 4 s
Distance (s) =.?
The distance travelled can be obtained as illustrated below:
s = ut + ½at²
s = (0×4) + (½ × 0.4 × 4²)
s = 0 + (0.2 × 16)
s = 0 + 3.2
s = 3.2 m
Thus, the box will travel 3.2 m in 4 s.
As Carlos and Manual both push a 4 kg box to the right across a rough floor, the box speeds up at a rate of 2.0 m/s2.(Hint, this is the acceleration.) If you assume that Manual pushes with a force strength of 8.0 N and the friction force of the floor on the box is 5.0 N, then what is the strength of the force that Carlos pushes on the box
Answer: 5 N
Explanation:
Given
Mass of box [tex]m=4\ kg[/tex]
acceleration of box [tex]a=2\ m/s^2[/tex]
Force applied by Manual [tex]F_m=8\ N[/tex]
Friction force [tex]f=5\ N[/tex]
The net force on the block is [tex]F_{net}=m\times a=4\times 2=8 \N[/tex]
Suppose [tex]F_c[/tex] is the force applied by Carlos
[tex]\Rightarrow F_m+F_c-f=F_{net}\\\Rightarrow F_c=F_{net}-F_m+f\\\Rightarrow F_c=8-8+5=5\ N[/tex]
The strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]
What is force?The force is defined as the external effort applied on any object to move it or to restrict it.
Here following information is given in the question:
Mass of the box m=4 kg
The acceleration of the box [tex]a=2\ \frac{m}{s^2}[/tex]
The force applied by the Manual [tex]F_m=8\ N[/tex]
The frictional force is [tex]F_f=5\ N[/tex]
The net force on the body will be calculated by
[tex]F_{net}=m\times a=4\times 2=8\ N[/tex]
The force that Carlos pushes on the box will be calculated by the equilibrium of the forces:
[tex]F_m+F_c-F_f=F_{net}[/tex]
[tex]8+F_c-5=8[/tex]
[tex]F_c=5\ N[/tex]
Thus the strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]
To know more about forces follow
https://brainly.com/question/388851
studyhero A violin string has a length, from the bridge to the end of the fingerboard, of 50 cm. That section of the string has a mass of only 2 g. When the violinist plays an open string (the full length) a 440 Hz A-note is heard. Determine the length of the string needed to play a 528 Hz note without adjusting the tension in the string. This is accomplished by pressing on the fingerboard at the appropriate location.
Answer:
= 0.517 m
Explanation:
This is a resonance exercise where the ends of the string are fixed, therefore it has a node of them, the fundamental (longest) wavelength created has the form
λ = 2L
wave speed is related to wavelength and frequency
v = λ f
v = 2L f
let's calculate
v = 2 0.50 440
v = 440 m / s
since they indicate that the tension of the string does not change and the linear density of the string is constant, the speed of the wave also remains constant
f =[tex]\frac{v}{2L}[/tex]
let's find the length for the new resonance frequency
L = [tex]\ \frac{v}{2f}[/tex]
let's calculate
L = [tex]\frac{440}{2 \ 528}[/tex]
L = 0.5166 m
Explain why the sound waves always reach the observer after the light waves
Answer:
I think it's because the light waves travel faster than the sound waves.
The speed of light is far greater than the speed of sound hence, sound waves always reach the observer after the light waves.
What is the speed of light?Light occurs in the electromagnetic spectrum. Recall that light can be transmitted through vaccuum unlike sound.
The speed of light is far greater than the speed of sound hence, sound waves always reach the observer after the light waves.
Learn more about speed of light:https://brainly.com/question/8832859
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A 50kg bicyclist on a 10kg bicycle speeds up from 5.0m/s to 10m/s. What was the total kinetic energy after accelerating?
Answer:
Explanation:
Ek=1/2mv^2
m=50+10=60,v=10
Ek=1/2*60*100=3000J
4. If the cooling of magma takes place slowly beneath Earth's surface, the rock is that is formed
is called
a. extrusive igneous rock
b. intrusive igneous rock
c. sedimentary rock
d. metamorphic rock
please help me fast please help
Answer:
the net energy Gained per hour equals 30Kcal/h
Create a concept map that shows the relationships among the following: crest, trough, compression, rarefaction, wave length, wave frequency, amplitude, and wave
speed.
Uhm.. based on what? Can you please specify/add an image or some more text and elaborate?
What must exist for the engineering process to begin?
a. a problem
ь.a solution
c. research
d. scientific tools
Answer:
d
Explanation:
rzp-yyib-oiv
plèase jóin ón góógle mèèt
Answer:
a. a problem
Explanation:
The engineering process begins by defining a problem and completing background research on the problem.
Need a little help here, ASAP please. The subject is simple science, not physics.
Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (560 nm) on a double slit with a separation of 0.108 mm. The diffraction pattern shines on the classroom wall 3.0 m away. Calculate the fringe separation between the third order and central fringe.
Answer:
y = 4.666 10⁻² m
Explanation:
The constructive interference experiment for the double slit
d sin sin θ = m λ
Let's use trigonometry to find a sine relationship.
Tan θ = y / L
tan θ = sin θ/ cos θ
in these experiments the angles are very small
tan θ = sin θ
sin θ = y / L
[tex]d \frac{y}{L}[/tex] = m λ
y = [tex]\frac{ m \lambda \ L}{d}[/tex]
we replace the values
y = 3 560 10⁻⁹ 3.0 / 0.108 10⁻³
y = 4.666 10⁻² m
write each of the following in scientific notation, correct to 2 decimal places.
a. 0.00000123 N
b. 417 000 000 kg
c. 246800 A
d. 0,00088 mm
Answer:
The scientific notation for the each number is given below:
Explanation:
The scientific notation for the following numbers are:
a. For 0.00000123 N
1.23 × 10^-6
b. For 417 000 000 kg
4.17 × 10^8
c. For 246800 A
2.47 × 10^5
d. For 0.00088m
8.8 × 10^-4
The above represent scientific notations of each numbers
Why do scientists perform multiple trials of the same experiment?
Answer:
it's a good idea to do multiple trials, that is, do the same experiment lots of times. When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events. Multiple trials can be done at one time.
Explanation:
the last one which is to increase the likelihood of accurate experiment results
Explanation:
A 1.6-kg ball is attached to the end of a 0.40-m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80-kg block initially at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3.0 m/s. What is the speed of the ball just after the collision?a. 1.5 m/sb. 1.3 m/sc. 2.1 m/sd. 1.1 m/se. 1.7 m/s
Answer:
a. 1.5 m/s
Explanation:
We will apply the law of conservation of energy in this situation between the initial position and the lowest point of the swing:
[tex]m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\[/tex]
where,
m₁ = mass of ball = 1.6 kg
m₂= mass of block = 0.8 kg
u₁ = initial speed of ball = 0 m/s
u₂ = initial speed of block = 0 m/s
v₁ = final speed of ball = ?
v₂ = final speed of block = 3 m/s
Therefore,
[tex](1.6\ kg)(0\ m/s)+(0.8\ kg)(0\ m/s)=(1.6\ kg)(v_{1})+(0.8\ kg)(3\ m/s)\\\\v_{1} = \frac{2.4\ N.s}{1.6\ kg}\\[/tex]
v₁ = 1.5 m/s
Therefore, the correct option is:
a. 1.5 m/s
Maurice is playing some of the arcades at the county fair. At one booth he throws a 1.2-kg ball forward with a velocity of 15 m/s and hits a 0.5-kg can
at rest. The ball continues forward at 9 m/s. What is the new velocity of the can, in m/s? (Round your answer to one decimal place if necessary.)
Answer:
9.6
Hope this helps.
What is optics???????
see my percentage of answering and thanks , it's crazy
Answer:
hi..bro
make pinky sis answer as brinlist ok
have a good day
Which of the following is an example of the transformation of gravitational potential energy into motion energy (kinetic energy)?
Answer:
c
Explanation:
because a drop of water is falling and that is gravitational potential energy into motion energy
C
D
7
The sun is the original source of
energy for many of our energy
resources
Which energy resource does not
originate from the sun? *
(1 Point)
.
A. Geothermal
B. Hydroelectric
C. Waves
D. Win
Answer:
geothermal
Explanation:
geothermal energy is the heat energy obtained from within the Earth. Hence not derived from Sun's energy.
What is the increase in gravitational potential energy of an object of mass 9.00 kg when it is raised from the ground to a height of 2.41 m, in units of joules?
Answer:
23 asden
Explanation:
first clothes and shoes
A force of 100N moves a body on a horizontal frictionless surface when......
I. Friction force exerted on the body is less than 100N
II. Friction force exerted on the body is more than 100N
III. None of these
IV. Both of I and II
Answer:
I. Friction force exerted on the body is less than 100N
Explanation:
For a body to be static, the moving force must be equal to the frictional force. Since the frictional force is a force of opposition. It tends to oppose the moving force acting on an object.
Hence if the moving force is greater than the force of friction, the Force of fiction will not be able to overcome the moving hence the body will tend to move.
Therefore, for a body to move, Fm > Ff or Ff < Ff
Fm is the moving force
Ff is the force of friction
Given
Fm = 100N
For the 100N body to move the frictional force must be less than 100N
Given the displacement vector D = (4î − 8ĵ) m, find the displacement vector R (in m) so that D + R = −3Dĵ. (Express your answer in vector form.)
Answer:
--------------------------------
Explanation:
PLEASE HELP ME WITH THIS ONE QUESTION
How many joules are needed to vaporize 125 g of liquid water at 100°C? The latent heat of vaporization is 2258 J/g.
Answer:
Q = 282,000 J
Explanation:
Given that,
The mass of liquid water, m = 125 g
Temperature, T = 100°C
The latent heat of vaporization, Hv = 2258 J/g.
We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :
[tex]Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J[/tex]
or
Q = 282,000 J
So, the required heat is 282,000 J .
Which water on earth is the largest,second to the largest,3rd to the largest,fourth to the largest and 5th to the largest?
Answer:
Explanation:
There are a total of 5 differen classification for the types of bodies of water that exist on Earth. These 5 would be the following: Oceans, seas, lakes, rivers, and canals. Oceans are the biggest bodies of water on Earth. If we ranked them by their size the ranking would be the following...
Pacific Ocean - being 155,556,651 sq km. in size
Atlantic Ocean - being 76,761,938 sq km. in size
Indian Ocean - being 68,555,923 sq km. in size
Antarctic / Southern Ocean - being 20,327,001 sq km. in size
Arctic Ocean - being 14,055,930 sq km. in size
Describe the phenomenon of lightning?
A 1.6 kg ball is attached to the end of a 0.40 m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80 kg block that is at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3 m/s. What is the speed of the ball just after the collision
Answer:
the speed of the ball just after the collision is 1.5 m/s.
Explanation:
Given;
mass of the ball, m₁ = 1.6 kg
initial velocity of the ball, u₁ = 0
mass of the block, m₂ = 0.8 kg
initial velocity of the block, u₂ = 0
final velocity of the block, v₂ = 3 m/s
let the final velocity of the ball after collision = v₁
Apply the principle of conservation of linear momentum for elastic collision;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
1.6 x 0 + 0.8 x 0 = 1.6 x v₁ + 0.8 x 3
0 = 1.6v₁ + 2.4
-1.6v₁ = 2.4
v₁ = -2.4 / 1.6
v₁ = - 1.5 m/s
v₁ = 1.5 m/s (in opposite direction of the block)
Therefore, the speed of the ball just after the collision is 1.5 m/s.
An instrument that produces an electric current in the presence of
a radioactive substance is called a
a. particle accelerator.
b. Geiger counter.
c. cloud chamber.
d. bubble chamber.
Answer:
Option B, Geiger counter
Explanation:
10. John does 176 J of work lifting himself a distance of 0.40 m. How
much force must John apply to accomplish this?
O 440 m
O 440 J
O 440 N
O 70.4 J
Why do we use copper wiring?
Explanation:
The lower the level of resistivity the more electrical conductivity a metal has. Copper has low resistivity, and therefore is an excellent conductor. Copper is also less oxidative than other metals
NEED HELP What color is the container for R-134a refrigerant? A. Light blue B. Yellow C. Dark green D.White and yellow
Answer:
It is A. Light blue
_____________
Hope this helps!
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