Answer:
25 m/s * √(1.5 m/g) ≈ 9.78 m
Explanation:
When effects of air resistance is neglected, the motion can be modeled as
x(t) = 25 m/s * t
y(t) = 1.5 m - g * t²
based on a coordinate system where the x axis is on the water level (modeled as a plane), y axis being parallel to the gravitational force and the point of origin sitting at the point on the water surface directly below the exit of the slide. The x value is the horizontal travel we’re interested in. Time t begins at the exit of the slide by this rider. g is the gravitational acceleration.
At the time when the rider hits water, we know y = 0.
0 = 1.5 m - g * t² ⇔ t = ±√(1.5 m/g)
Since we are only interested in the non-negative (not past) time range, it’s t = √(1.5 m/g)
The horizontal travel is thus:
x(√(1.5 m/g)) = 25 m/s * √(1.5 m/g) ≈ 25 * √(1.5/9.81) m ≈ 9.78 m
3. Each croquet ball in a set has a mass of 0.50 kg. The green ball, traveling at 12.0 m/s,
strikes the blue ball, which is at rest. Assuming that the balls slide on a frictionless
surface and all collisions are head-on, find the final speed of the blue ball in each of
the following situations:
a. The green ball stops moving after it strikes the blue ball.
b. The green ball continues moving after the collision at 2.4 m/s in the
same direction.
Answer:
a) v_{2f} = 12.0 m / s, b) v_{2f} = 9.6 m / s
Explanation:
This is an exercise in conservation of momentum, let's start by defining a system formed by the two balls, so that the forces during the collision have been internal and the moment is preserved.
Initial instant. Before the crash
p₀ = m v₁₀ + m v₂₀
where we use index 1 for the green ball and index 2 for the blue ball.
Final moment. After the crash
p_f = m v_{1f} + m v_{2f}
the moment is preserved
p₀ = p_f
m v₁₀ + m v₂₀ = m v_{1f} + m v_{2f}
they tell us that the blue ball is at rest before the crash
m v₁₀ = m v_{1f} + m v_{2f}
a) it is indicated that the green ball stops after the collision v1f = 0
m v₁₀ = m v_{2f}
v_{2f} = v₁₀
v_{2f} = 12.0 m / s
b) the speed of the green ball is v_{1f} = 2.4 m / s
m v₁₀ = m v_{1f} + m v_{2f}
v_{2f} = v_{1o}- v_{1f}
v_{2f} = 12.0 - 2.4
v_{2f} = 9.6 m / s
Given the displacement vector D = (4î − 8ĵ) m, find the displacement vector R (in m) so that D + R = −3Dĵ. (Express your answer in vector form.)
Answer:
--------------------------------
Explanation:
A planet follows an elliptical orbit that brings it as close as 21 million km to a star and as far as 75 million km from the star. At both of these locations the velocity of the planet makes a right angle to the direction to the star. If the planet's speed is 38 km/s when it is farthest from the star, how fast is it moving when it is closest to the star
Answer:
Explanation:
In an elliptical orbit , the angular momentum of the planet remains constant because velocity of planet makes a right angle to the direction to the star .
mvr = constant .
mv₁r₁ = mv₂r₂
v₁r₁ = v₂r₂
v₁ x 21 = 38 x 75
v₁ = 135.71 km/s .
A 1.6 kg ball is attached to the end of a 0.40 m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80 kg block that is at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3 m/s. What is the speed of the ball just after the collision
Answer:
the speed of the ball just after the collision is 1.5 m/s.
Explanation:
Given;
mass of the ball, m₁ = 1.6 kg
initial velocity of the ball, u₁ = 0
mass of the block, m₂ = 0.8 kg
initial velocity of the block, u₂ = 0
final velocity of the block, v₂ = 3 m/s
let the final velocity of the ball after collision = v₁
Apply the principle of conservation of linear momentum for elastic collision;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
1.6 x 0 + 0.8 x 0 = 1.6 x v₁ + 0.8 x 3
0 = 1.6v₁ + 2.4
-1.6v₁ = 2.4
v₁ = -2.4 / 1.6
v₁ = - 1.5 m/s
v₁ = 1.5 m/s (in opposite direction of the block)
Therefore, the speed of the ball just after the collision is 1.5 m/s.
After the first trial your sibling spills juice on the track when you run the car down the track again you measure the speed at the bottom of the track to be 2.0 MS how much of the total mechanical energy was converted to thermal energy as a car moved through the sticky juice?
Plz help asap
What is optics???????
see my percentage of answering and thanks , it's crazy
Answer:
hi..bro
make pinky sis answer as brinlist ok
have a good day
NEED HELP What color is the container for R-134a refrigerant? A. Light blue B. Yellow C. Dark green D.White and yellow
Answer:
It is A. Light blue
_____________
Hope this helps!
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╰━┳┻▅╯╲╲╲╲┃┈┈┈
┈┈╰━┳┓┏┳┓┏╯┈┈┈
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What could you do to increase the electric potential energy between two
negatively charged particles by a factor of 16?
O A. Increase the charge of one particle by a factor of 4.
B. Reduce the charge of one particle by a factor of 4.
C. Increase the charge of one particle by a factor of 16.
O D. Reduce the charge of one particle by a factor of 16.
Answer: Increase the charge of one particle by a factor of 16
Explanation:Just took the quiz
Answer:
C. Increase the charge of one particle by a factor of 16.
A frictionless piston-cylinder contains carbon dioxide gas (CO2) initially at 500oC and 2 MPa. The system is o3 cooled in an isobaric process until the final temperature becomes 350 C and the final volume is 1 m . For this process, determine: (a) The reduced pressure and the reduced temperature of the initial state. (b) The initial volume of the piston-cylinder (in m3). (c) The mass of CO2 in the piston-cylinder (in kg). (d) The total boundary work for the process (in kJ). (e) The amount of heat transfer during the cooling process (in kJ).
Answer:
(a) The reduced pressure is 0.2711 MPa
The reduced temperature is 2.54 K
(b) The initial volume of the piston is approximately 0.806 m³
(c) The mass of CO₂ is approximately 16.9884 kg
(d) The work done, W is approximately 388.023 kJ
(e) The heat transfer is approximately -2,650.1904 kJ
Explanation:
The initial temperature of the piston-cylinder, T₁ = 500°C = 773.15 K
The initial pressure of the gas, P₁ = 2 MPa
The final temperature of the gas, T₂ = 350°C
The final volume of the gas = 1 m³
(a) For an isobaric process, we have;
The reduced pressure,
[tex]P_r = \dfrac{P}{P_c}[/tex]
The critical pressure of carbon dioxide, [tex]P_c[/tex] = 7.3773 MPa
[tex]P_r = \dfrac{2 \, MPa}{7.3773 \, MPa} \approx 0.2711 \, MPa[/tex]
The reduced pressure, [tex]P_r[/tex] = 0.2711 MPa
The critical temperature, [tex]T_c[/tex] = 304.13 K
The reduced temperature, [tex]T_r[/tex], is given by the following formula;
[tex]T_r = \dfrac{T}{T_c}[/tex]
Therefore, [tex]T_r[/tex] = (773.15 K)/(304.13 K) = 2.54216947 K
The reduced temperature, [tex]T_r[/tex] ≈ 2.54 K
(b) The initial volume of the piston, V₁ = (V₂/T₂) × T₁
∴ V₁ = (1 m³/773.15) × 623.15 = 0.80598848865 m³ ≈ 0.806 m³
The initial volume of the piston, V₁ ≈ 0.806 m³
(c) The number of moles of CO₂ in the cylinder, 'n', is given according to the following formula;
n = P·V/(T·R)
The universal gas constant, n = (2 × 10⁶Pa × 1 m³)/(623.15 K × 8.3145 J/(mol·K)) ≈ 386.0124 moles
The mass of CO₂ ≈ 386.0124 moles × 44.01 g/mol = 16.9884 kg
(d) The work done, W = P·([tex]V_f - V_i[/tex])
W = 2 × 10⁶ × (1 - 0.80598848865) = 388023.0227
The work done, W ≈ 388.023 kJ
(e) The heat transfer dQ = m·[tex]c_p[/tex] ×(T₂ - T₁)
[tex]c_p[/tex] for CO₂ ≈ 1.04 kJ/(kg·K)
∴ dQ = 16.9884 × 1.04 × (350 - 500) = -2,650.1904 kJ
Therefore, the heat transfer = dQ = -2,650.1904 kJ
Why are special techniques and extinguishing agents are required to fight combustible metals fires?
A kicker punts a football from the very center of the field to the sideline 41 yards downfield. (A football field is 53 yards wide.)What is the angle between the direction of the net displacement of the ball and the 50-yard line of the field
Answer:
Ur answer is 12 sir!
Explanation:
HAve a good day sir
how could you increase the gravitational potential energy of an object without changing its mass and gravity
What is double stroking
Answer: The double stroke roll works just like the single stroke roll - it's played in a sequence of alternating strokes (roll). But instead of having one stroke per hand you'll have two, as shown on the sheet music below. You can use full wrist turns to play each stroke of the double stroke at slower speeds.
Explanation: hope this helps!
Explanation:
it is played as a sequence of alternating strokes
HELP!!! 100 POINTSSS!!!
Answer:
3
Explanation:
From the question given above, the following data were obtained:
Length (L) = 3 m
Height (H) = 1 m
Mechanical advantage (MA) =.?
The ideal mechanical advantage for the system can be obtained as follow:
MA = L/H
MA = 3/1
MA = 3
Therefore, the ideal mechanical advantage for the system is 3
Answer:
Explanation:
Mechanical Advantage is the ratio of Input Distance / Output Distance.
In this case, the output distance is to bring up the cart by 1m.
The input distance is to push the cart by 3m.
Assume an ideal machine, MA = 3/1 = 3
A 55.0 kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. The unstretched length of the cord is 15.0 m. She reaches the bottom of her motion 40.0 m below the bridge before bouncing back. Her motion can be separated into an 15.0 m free-fall and a 25.0 m section of simple harmonic oscillation. Use the principle of conservation of energy to find the spring constant of the bungee cord.
Answer:
[tex]69.06\ \text{N/m}[/tex]
Explanation:
m = Mass of bungee jumper = 55 kg
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
h = Height at the bottom = 40 m
k = Spring constant
x = Displacement of bungee cord = 25 m
Applying the principle of conservation of energy to the system we have
[tex]mgh=\dfrac{1}{2}kx^2\\\Rightarrow k=\dfrac{2mgh}{x^2}\\\Rightarrow k=\dfrac{2\times 55\times 9.81\times 40}{25^2}\\\Rightarrow k=69.06\ \text{N/m}[/tex]
The spring constant of the bungee cord is [tex]69.06\ \text{N/m}[/tex].
Need a little help here, ASAP please. The subject is simple science, not physics.
What does the power source in a circuit provide?
the means to break a circuit
a path along which electricity can flow
static electricity
a steady flow of electrons
plsssssssssssssssssss answer plss not in a meen way but plssss anwer correctly
Explanation:
The primary function of a power supply is to convert electric current from a source to the correct voltage, current, and frequency to power the load. As a result, power supplies are sometimes referred to as electric power converters. Some power supplies are separate standalone pieces of equipment, while others are built into the load appliances that they power. Examples of the latter include power supplies found in desktop computers and consumer electronics devices. Other functions that power supplies may perform include limiting the current drawn by the load to safe levels, shutting off the current in the event of an electrical fault, power conditioning to prevent electronic noise or voltage surges on the input from reaching the load, power-factor correction, and storing energy so it can continue to power the load in the event of a temporary interruption in the source power (uninterruptible power supply).
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PLEASE HELP ME WITH THIS ONE QUESTION
How many joules are needed to vaporize 125 g of liquid water at 100°C? The latent heat of vaporization is 2258 J/g.
Answer:
Q = 282,000 J
Explanation:
Given that,
The mass of liquid water, m = 125 g
Temperature, T = 100°C
The latent heat of vaporization, Hv = 2258 J/g.
We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :
[tex]Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J[/tex]
or
Q = 282,000 J
So, the required heat is 282,000 J .
Which is NOT a way to stay safe from static electricity?
a lightning rod on a building
a metal spike in an airport runway
an anti-static chain on a large truck
a run through an open field during a lightning
plssssssssssss answer not in a meen way but corrrect answer only plsssssssssssss answer correct i will drop a thx and rate yo stars ans give you brainlyest
a metal spike in an airport runway
A metal spike in an airport runway is NOT a way to stay safe from static electricity. Hence option C is correct.
What is electricity ?Electricity is a collection of physical phenomena related with the presence and motion of matter having an electric charge. Both electricity and magnetism are connected to the phenomena of electromagnetic, as defined by Maxwell's equations. Lightning, static electricity, electric heating, electric discharges, and other frequent occurrences are all connected to electricity.
An electric field is created when either a positive or negative electric charge is present. The movement of electric charges results in an electric current and a magnetic field. In most applications, a force of magnitude determined by Coulomb's law operates on a charge. Volts are commonly used to measure electric potential.
Hence option C is correct.
To know more about electricity :
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The stem cell therapy is ethical?
Which examples are ways that models can help scientists solve problems? Check all that apply.
Answer:
These are the 4 correct answers that should be on your test.
A. A model can represent something very large like the solar system.
B. A model can represent something very small like a single cell.
C. A model can represent something very complex like the flow of energy in an ecosystem.
D. A model can represent something that cannot be seen or touched.
Explanation:
a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, find the ball's kinetic, potential, and mechanical energies (a) a its initial position, (b) at 5 m above the initial position, and (c) at its maximum height
Answer:
a) [tex] E_{p} = 0 [/tex]
[tex] E_{k} = 168.7 J [/tex]
[tex] E_{m} = 168.7 J [/tex]
b) [tex] E_{p} = 73.6 J [/tex]
[tex] E_{k} = 95.8 J [/tex]
[tex] E_{m} = 169.4 J [/tex]
c) [tex] E_{p} = 169.2 J [/tex]
[tex] E_{k} = 0 [/tex]
[tex] E_{m} = 169.2 J [/tex]
Explanation:
We have:
m: is the ball's mass = 1.5 kg
v₀: is the initial speed = 15 m/s
g: is the gravity acceleration = 9.81 m/s²
a) In the initial position we have:
h: is the height = 0
The potential energy is given by:
[tex] E_{p} = mgh = 0 [/tex]
The kinetic energy is:
[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J [/tex]
And the mechanical energies:
[tex] E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J [/tex]
b) At 5 m above the initial position we have:
h = 5 m
The potential energy is:
[tex] E_{p} = mgh = 1.5*9.81*5 = 73.6 J [/tex]
Now, to find the kinetic energy we need to calculate the speed at 5 m:
[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9 [/tex]
[tex] v_{f} = \sqrt{126.9} = 11.3 m/s [/tex]
[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J [/tex]
And the mechanical energies:
[tex] E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J [/tex]
c) At its maximum height:
[tex] v_{f}[/tex]: is the final speed = 0
[tex] h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m [/tex]
Now, the potential, kinetic and mechanical energies are:
[tex] E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J [/tex]
[tex] E_{k} = \frac{1}{2}mv^{2} = 0 [/tex]
[tex] E_{m} = 169.2 J + 0 = 169.2 J [/tex]
I hope it helps you!
As Carlos and Manual both push a 4 kg box to the right across a rough floor, the box speeds up at a rate of 2.0 m/s2.(Hint, this is the acceleration.) If you assume that Manual pushes with a force strength of 8.0 N and the friction force of the floor on the box is 5.0 N, then what is the strength of the force that Carlos pushes on the box
Answer: 5 N
Explanation:
Given
Mass of box [tex]m=4\ kg[/tex]
acceleration of box [tex]a=2\ m/s^2[/tex]
Force applied by Manual [tex]F_m=8\ N[/tex]
Friction force [tex]f=5\ N[/tex]
The net force on the block is [tex]F_{net}=m\times a=4\times 2=8 \N[/tex]
Suppose [tex]F_c[/tex] is the force applied by Carlos
[tex]\Rightarrow F_m+F_c-f=F_{net}\\\Rightarrow F_c=F_{net}-F_m+f\\\Rightarrow F_c=8-8+5=5\ N[/tex]
The strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]
What is force?The force is defined as the external effort applied on any object to move it or to restrict it.
Here following information is given in the question:
Mass of the box m=4 kg
The acceleration of the box [tex]a=2\ \frac{m}{s^2}[/tex]
The force applied by the Manual [tex]F_m=8\ N[/tex]
The frictional force is [tex]F_f=5\ N[/tex]
The net force on the body will be calculated by
[tex]F_{net}=m\times a=4\times 2=8\ N[/tex]
The force that Carlos pushes on the box will be calculated by the equilibrium of the forces:
[tex]F_m+F_c-F_f=F_{net}[/tex]
[tex]8+F_c-5=8[/tex]
[tex]F_c=5\ N[/tex]
Thus the strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]
To know more about forces follow
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which of the following are true about S waves
1. they begin at an earthquakes focus
2. they can travel through liquids
3. they can travel through solids
4. they move rock at right angles to the direction of wave travel
Answer:
3. they can travel through solids
4. they move rock at right angles to the direction of wave travel
Explanation:
S waves are called transverse waves they have the ability to move past the solids. They cannot move through the liquids, these waves are perpendicular to the direction of travel. They are also called longitudinal waves, the ad is second to record on the seismograph as they slowly pass through the rocks. They have a speed of 3.4 to 7.2 km as per the boundary.Answer:
1, 3, 4
Explanation:
S waves are transverse waves, so they move rock at right angles to the direction of wave travel. Also, S waves can only travel through solids. S waves and P waves both begin at an earthquake's focus.
I need help with science please, ill give brianlist’s :
Question 1 :The size of a plant cell may change depending upon the amount of water it receives.
True
False
________________________________
Question 2: Chloroplasts are a category of organelles found in the cells of green plants.
True
False
_______________________________
Question 3: Photosynthesis in plants produces water and carbon dioxide.
True
False
Answer:
true , true, and I'm not sure about the last one!
Explanation:
Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (560 nm) on a double slit with a separation of 0.108 mm. The diffraction pattern shines on the classroom wall 3.0 m away. Calculate the fringe separation between the third order and central fringe.
Answer:
y = 4.666 10⁻² m
Explanation:
The constructive interference experiment for the double slit
d sin sin θ = m λ
Let's use trigonometry to find a sine relationship.
Tan θ = y / L
tan θ = sin θ/ cos θ
in these experiments the angles are very small
tan θ = sin θ
sin θ = y / L
[tex]d \frac{y}{L}[/tex] = m λ
y = [tex]\frac{ m \lambda \ L}{d}[/tex]
we replace the values
y = 3 560 10⁻⁹ 3.0 / 0.108 10⁻³
y = 4.666 10⁻² m
Rupert is investigating the properties of a light (effectively massless) spring. He has attached one end of the spring to a fixed horizontal rod and allowed the spring to hang vertically. The free end of the spring has a small hook to which Rupert can attach various masses. An Experiment to Determine the Spring Constant Part A Rupert finds that if he attaches a 470.0 gram mass to the hook, and then very slowly lowers the mass with his hand until the force on the mass by the spring is as large as the weight of the mass, that the spring stretches by 36.0 cm . What is the spring constant of Rupert's spring
Answer:
Explanation:
For equilibrium ,
weight of mass 470 gram = restoring force in spring
If x be extension in spring and k be spring constant
restoring force = kx
weight of mass = kx
.47 x 9.8 = k x .36
k = 12.8 N /m.
A young parent is dragging a 65 kg (640 N) sled (this includes the mass of two kids) across some snow on flat ground, by means of a rope attached to the sled. The rope is at an angle of 30 degrees with respect to the ground and the tension in the rope is 160 N. The sled is moving at a constant velocity of 1.5 m/s.
(a) Draw and label all forces acting on the kids + sled system. Indicate the relative size of each force by scaling the length of each force arrow appropriately
(b) Calculate the normal force acting on the system
(c) Calculate the force of friction acting on the system.
(d) Calculate the coefficient of friction between the sled and the snow.
Answer:
b) N = 560 N, c) fr = 138.56 N, d) μ = 0.247
Explanation:
a) In the attachment we can see the free body diagram of the system
b) Let's write Newton's second law on the y-axis
N + T_y -W = 0
N = W -T_y
let's use trigonometry for tension
sin θ = T_y / T
cos θ = Tₓ / T
T_y = T sin θ
Tₓ = T cos θ
we substitute
N = W - T sin 30
we calculate
N = 640 - 160 sin 30
N = 560 N
c) as the system goes at constant speed the acceleration is zero
X axis
Tₓ - fr = 0
Tₓ = fr
we substitute and calculate
fr = 160 cos 30
fr = 138.56 N
d) the friction force has the formula
fr = μ N
μ = fr / N
we calculate
μ = 138.56 / 560
μ = 0.247
Why do we use copper wiring?
Explanation:
The lower the level of resistivity the more electrical conductivity a metal has. Copper has low resistivity, and therefore is an excellent conductor. Copper is also less oxidative than other metals
- Atoms of different elements:
(a) Have the same atomic heat capacity.
(b) Have the same specific heat.
(c) Have the same heat capacity.