Answer:
f = 4 Hz
Explanation:
Given that,
The speed of a wave, v = 12 m/s
The wavelength of a wave, [tex]\lambda=3\ m[/tex]
We need to find the frequency of the wave. We know that the speed of wave is equal to the product of wavelength and frequency. So,
[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{12}{3}\\\\f=4\ Hz[/tex]
So, the frequency of the wave is equal to 4 Hz.
If 500mL glass beaker is filled to the brim with ethyl alcohol at a temperature of 5⁰C, how much less water would overflow under the same condition?
Answer:
The change in volume or amount of overflow is 1.79 mL . Hence, 7.56 mL of lesser water would overflow under the same condition.
Someone is whirling a hammer that has a mass of 8.5 kg in the air that is tied to a Chain 1.5 m long in a circle that makes 1 revolution in 2 seconds a. What is the centripetal acceleration f the hammer B what is the tension of the Chain
By changing the frequency of an EM wave, the _____ of the wave is changing.
a) speed
b) phase
c) amplitude
d) energy
e) both b and d
By changing the frequency of an EM wave, both the energy and phase of the wave is changing. The correct option is e.
What is the frequency?Frequency is the number of times a wave passes through a particular point in one second.
The time interval to 1° of phase change is inversely proportional to the frequency.
There is a change in phase with changing frequency.
Therefore, by changing the frequency of an EM wave, the energy and phase of the wave is changing.
The correct option is e.
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In transverse waves, the movement of the particles is _________
O in a circle
O left to right
O diagonal
O up and down
Answer:
the correct answer is up and down
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
Answer:
the f is 1.3 m
Explanation:
Given that
An object 2.0m is from the concave mirror
And, the image is 4.0m from the mirror
We need to find out the f
So,
u = -2 m
v = -4 m
1 ÷ f = 1 ÷ v + 1 ÷ u
= (-1 ÷ 4) + (-1 ÷ 2)
= -3 ÷4
f = -4 ÷ 3
= |1.3| m
Hence, the f is 1.3 m
A monkey (mass m) is swinging on a vine of length L while carrying a bunch of bananas (a large bunch, mass m/2). His swinging motion has period T and reaches maximum height during the swing h (measured from the bottom of his arc of motion). He accidentally lets go of his bananas when he is at a height of h/2. What happens to the amplitude and period of his oscillation as a result? Explain.
Answer:
Explanation:
The period of oscillation will remain unchanged because the period of oscillation of a pendulum does not depend upon the mass of the bob . Here monkey along with bunch of banana represents bob .
When the monkey and banana were at height h /2 , they have potential energy as well as kinetic energy . banana is separated from the system . It carried its total energy along with it . But the energy of monkey remained intact with it . So it will keep on moving as usual . So it will attain the same maximum height as before .
Hence the amplitude of oscillation too will remain unchanged .
It’s bungee jumping skydiving and hiking
An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 degrees Celsius and rejects heat to a room at a temperature of 20.6 degrees Celsius. Suppose that liquid water with a mass of 82.1 kg at 0.0 degrees Celsius is converted to ice at the same temperature. Take the heat of fusion for water to be Lf=3.34×105 J/kg.
A. How much heat |QH| is rejected to the room?
B. How much energy E must be supplied to the device?
Answer:
A. Q = 2.74 x 10⁷ J = 27.4 MJ
B. E = 3.91 x 10⁸ J = 391 MJ
Explanation:
A.
Heat rejected can be found as follows:
[tex]Q = mL[/tex]
where,
Q = Heat rejected = ?
m = mass = 82.1 kg
L = Latent Heat of fusion = 334000 J/kg
Therefore,
[tex]Q = (82.1\ kg)(334000\ J/kg)[/tex]
Q = 2.74 x 10⁷ J = 27.4 MJ
B.
First, we will calculate the efficiency of the Carnot Cycle as follows:
[tex]Efficiency = 1-\frac{T_1}{T_2}[/tex]
where,
T₁ = Heat intake temperature = 0°C + 273 = 273 k
T₂ = Heat rejection temperature = 20.6°C + 273 = 293.6 k
Therefore,
[tex]Efficiency = 1 - \frac{273\ k}{293.6\ k} \\\\Effciency = 0.07[/tex]
Therefore, the energy input required is:
[tex]Efficiency = \frac{Q}{E}\\\\E = \frac{Q}{Efficiency} = \frac{2.74\ x\ 10^7\ J}{0.07}[/tex]
E = 3.91 x 10⁸ J = 391 MJ
You can see things outside of a beam of light because of? I NEED HELP ASAP
Answer:
Reflected light bounces off of materials that for whatever reason cannot absorb the light. The reflected light is always whatever color it was originally. We do not see things from light that is reflected. We see things from the light that they EMIT.
A standard parallel plate capacitor is connected to a battery and is given enough time to charge fully. After it is fully charged, the capacitor is disconnected from the battery. After that, prankster Bob comes along and pulls the plates further apart from each other, doubling the distance d between the plates. How do the following quantities change? The choices are: quadruple, double, stay the same, halve, or quarter.
a) Capacitance
b) Charge on the capacitor
c) Voltage across the capacitor
d) Electric field within the capacitor
e) Energy stored in the capacitor
f) Does Bob have to do work in order to pull the plates apart? (Yes or no, and a brief explanation)
g) Are parts (e) and (f) consistent, given that the battery was disconnected?
Answer:
a) capacitance is doubled., b) Q = cte, c) oltage doubling the distance doubles, d) ΔE =0, e) U = Q² / 2C, f) W>0
Explanation:
he capacitance of a condensate is
C =[tex]\frac{ Q}{ \Delta V} =\epsilon_o \frac{A}{d}[/tex]
let's use this expression to answer the question
a) Capacitance.
Without distance, the capacitance is doubled.
Answer: Half
b) The charge.
As the battery is disconnected, no more electrons reach the capacitor, so the charge remains the same
Q = cte
c) the voltage
ΔV = E d = ([tex](\frac{Q}{\epsilon_o A}) \ d[/tex]
so the voltage doubling the distance doubles
d) The electric field between parallel plates is constant
E = Q / A eo
E =0
e) The stored energy is described by the expression
U = Q² / 2C
as capacitance decreases and discant increases, stored energy increases
f) The work to separate the positive charge, that the force must be in the same direction as the electric force
g) when the battery is disconnected the energy in the capacitor remains constant
A boat was traveling at 15 mph when a passenger threw an object at 10 mph in the same direction the boat was moving. A friend,
standing on the shore, observed the object moving with a speed of 25 mph. The passenger observed the object moving with a speed
of 10 mph. Why were the two observations different?
Answer:
the person on the boat is moving 15mph on the boat and throws the ball 10mph. you add that together its 25mph. the other person is standing on land so their is no extra speed.
Explanation:
its common
The person on the boat is moving 15 mph on the boat and throws the ball 10 mph. you add that together its 25 mph. the other person is standing on land so their is no extra speed.
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
The two observation are different because of relative speed is measured as one with observer in the rest or zero speed in other case observer is in the motion with some speed so these are different.
The person on the boat is moving 15 mph on the boat and throws the ball 10 mph. you add that together its 25 mph. the other person is standing on land so their is no extra speed.
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When you perform the skill of _____________, you must track the object before receiving it.
kicking
striking
catching
throwing
Answer:
uhh that is a hard question
Explanation:
cathcing or throwing
When you perform the skill of catching, you must track the object before receiving it. Therefore, option (C) is correct.
What are manipulative skills?Manipulative skills can be described as those skills which require the ability to handle an object or piece of equipment with control. They involve skills such as striking, kicking, dribbling, or catching a ball.
Manipulative skills involve moving an object with the hands or feet to get a goal or fulfill a task. The objects might be used as equipment or toys such as balls, bats, racquets, or jump ropes. Manipulative skills are also called object-control skills.
Types of Manipulative Skills are Bouncing, Catching, Dribbling (moving a ball with the feet), Kicking or rolling, Lifting, Pushing and pulling (the object might be a wheeled toy), Striking (such as swinging a baseball bat), Throwing, and Volleying.
Therefore, we track the object before receiving during catching,
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pls help me its due today
Answer:
pls give me brainliest
Explanation:
state the property of plastic that allows it to become electrostatically charged
(please answers ty)
Answer:
when a plastic rod is rubbed with a duster, electrons are transferred from one material to the other. The material that gains electrons becomes negatively charged. The material that loses electrons becomes positively charged.
Which of the following is a sign of puberty?
A.
intense changes in hormone balance
B.
increased height and strength
C.
development of sexual characteristics
D.
all of the above
Please select the best answer from the choices provided.
A
B
C
D
1. Three confused sled dogs are trying to pull a sled across the Alaskan snow. Tim pulls east with a force of 42 N; Sam also pulls east, but with a force of 53 N; and big Ethan pulls west with a force of 67 N. What is the net force on the sled? then find the acceleration?
2. A 944-kg dragster, starting from rest, attains a speed of 31,2 m/s in 0.670 s. a. Find the average acceleration of the dragster.
b. What is the magnitude of the average net force on the dragster during this time?
c. What horizontal force does the seat exert on the driver if the driver has a mass of 68.0 kg?
Please try to atleast answer one
Answer:
Explanation:
According to the statement, three confused sleigh dogs are trying to pull a sled across the Alaskan snow.
Forces in same direction gets added , so 35N + 42N=77N and the Net Force is 77N -53N as it is acting in opposite direction.
Net force is 25N in east to the maximum without any hassle.
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A catapult of pole length 4r throws a pumpkin from one
end of a pole which rotates about an axis at the other
end with angular speed w.
A smaller catapult of pole length r throws another
pumpkin from one end of a pole which rotates about an
axis at the other end with the same angular speed was
the first catapult.
How does the linear speed of the larger catapult's
pumpkin Vlarge compare with the smaller catapult's
pumpkin Vsmall?
Answer:
vlarge = 4vsmall
Explanation:
Khan Academy
A nurse asks a doctor about medication for a
patient in a hospital. The doctor accidentally tells
the nurse to give the patient the wrong
medication, and the nurse follows the doctor's
orders. Which type of medical error has occurred?
Answer:
medication error thats easy
Question below in photo!! Please answer! Will mark BRAINLIEST! ⬇⬇⬇⬇⬇⬇⬇
----------------------------------------------------------------------------------------------
Chose the correct answer:
-Increases
-Decreases
-Stays the same
Answer:
Decreases seems most reasonable to me but up to you.
Suppose that you wish to construct a simple AC generator with an output of 12 V maximum when rotated at 60 Hz. A magnetic field of 0.050 T is available. If the area of the rotating coil is 100 cm2, how many turns are needed?
Answer:
N = 63.6
Explanation:
The emf induced in AC generator is given as follows:
[tex]V = N\omega AB Sin\theta[/tex]
for maximum output, [tex]Sin\theta = 1[/tex]
[tex]V = N(2\pi f) AB[/tex]
where,
V = Maximum Output Voltage = 12 V
N = No. of Turns = ?
f = frequency = 60 Hz
A = Area of Coil = 100 cm² = 0.01 m²
B = Strength of Magnetic Field = 0.05 T
Therefore,
[tex]12\ V = N(2)(\pi)(60\ Hz)(0.01\ m^2)(0.05\ T)\\\\N = \frac{12\ V}{(2)(\pi)(60\ Hz)(0.01\ m^2)(0.05\ T)}[/tex]
N = 63.6
Grandma Sue (mass 80 kg) and her grandson James (mass 40 kg) are on a smooth icy surface. As Grandma Sue whizzes around the icy surface at 3 m/s in a straight line, she is suddenly confronted with scared James standing at rest directly in her path. Rather than knock him over, she picks him up and continues her uniform motion in a straight line without braking. Find the speed of Grandma Sue and James after the collision.
Answer:
v = 2 m/s
Explanation:
Here, we will use the law of conservation of momentum to solve this problem:
[tex]m_1u_1 + m_2u_2 = m_1v_1+m_2v_2[/tex]
where,
m₁ = mass of grandma = 80 kg
m₂ = mass of James = 40 kg
u₁ = initial speed of grandma = 3 m/s
u₂ = initial speed of James = 0 m/s
v₁ = v₂ = v = final speed of grandm and James = ?
Therefore,
[tex](80\ kg)(3\ m/s)+(40\ kg)(0\ m/s)=(80\ kg)(v)+(40\ kg)(v)\\\\(120\ kg)v = 240\ Ns\\\\v = \frac{240\ N.s}{120\ kg}\\[/tex]
v = 2 m/s
A coil of 27 turns is in the shape of an ellipse having a major axis of 12.0 cm and a minor axis of 9.00 cm. The coil rotates at 57rpm in a region in which the Earth's magnetic field is 74.0 microT. What is the maximum voltage induced in the coil if the axis of rotation of the coil is along its major axis and this axis of rotation is aligned perpendicular to the Earth's magnetic field
Answer:
Explanation:
Emf induced e = nBAω sinωt where n is no of turns , B is magnetic field, A is area of the coil ω is angular frequency of rotation .
maximum emf = nBAω
Given n = 27 , B = 74 x 10⁻⁶ T , A = .12 m x .09 m = 108 x 10⁻⁴ m²
ω = 2π x 57/60 = 5.966 rad/s .
Putting the values
maximum emf = 27 x 74 x 10⁻⁶ T x 108 x 10⁻⁴ m² x 5.966 rad/s .
= 1.29 x 10⁻⁴ V .
A student decides to give his bicycle a tune up. He flips it upside down (so there's no friction with the ground) and applies a force of 34 N over 0.6 seconds to the pedal, which has a length of 16.5 cm. If the back wheel has a radius of 33.0 cm and moment of inertia of 1200 kg cm^2, what is the tangential velocity of the rim of the back wheel in m/s
Answer:
[tex]V=9.2565m/s[/tex]
Explanation:
From the question we are told that:
Force [tex]F = 34 N[/tex]
Time [tex]t = 0.6 s[/tex]
Length of pedal [tex]l_p=16.5cm \approx0.165m[/tex]
Radius of wheel [tex]r = 33 cm = 0.33 m[/tex]
Moment of inertia, [tex]I = 1200 kgcm2 = 0.12 kg.m2[/tex]
Generally the equation for Torque on pedal [tex]\mu[/tex] is mathematically given by
[tex]\mu=F*L\\\mu=34*0.165[/tex]
[tex]\mu=5.61N.m[/tex]
Generally the equation for angular acceleration [tex]\alpha[/tex] is mathematically given by
[tex]\alpha=\frac{\mu}{l}[/tex]
[tex]\alpha=\frac{5.61}{0.12}[/tex]
[tex]\alpha=46.75[/tex]
Therefore Angular speed is \omega
[tex]\omega=\alpha*t[/tex]
[tex]\omega=(46.75)*(0.6)[/tex]
[tex]\omega=28.05rad/s[/tex]
Generally the equation for Tangential velocity V is mathematically given by
[tex]V=r\omega[/tex]
[tex]V=(0.33)(28.05)[/tex]
[tex]V=9.2565m/s[/tex]
Most stars are main-sequence stars, a group of stars for which size, mass, surface temperature, and radiated power are closely related. The sun, for instance, is a yellow main sequence star with a surface temperature of 5800 K. For a main-sequence star whose mass M is more than twice that of the sun, the total radiated power, relative to the sun, is approximately P/Psun = 1.5(M/Msun)3.5. The star Regulus A is a bluish main-sequence star with mass 3.8Msun and radius 3.1Rsun. What is the surface temperature of Regulus A?
Answer:
the surface temperature of Regulus A is 11724.13 K
Explanation:
Given the data in the question;
Sun's surface temperature T = 5800 K
total radiated power, relative to the sun is; P/P[tex]_{sun[/tex] = [tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex]
The star Regulus A is a bluish main-sequence star with mass 3.8M[tex]_{sun[/tex] and radius 3.1R[tex]_{sun[/tex] .
First, we determine the value power emitted by the sun or sun as follows;
P = eσAT⁴
where P is the power, e is surface emissivity, σ is Stefan Boltzmann, A is area and T is temperature.
so, lets assume emissivity of star and sun is same;
let p be power related to star and p[tex]_{sun[/tex] be power related sun.
Ratio of power radiated by star and power radiated by sun;
P/P[tex]_{sun[/tex] = eσAT⁴ / eσA[tex]_{sun[/tex]T[tex]_{sun[/tex]⁴
we know that AREA A = πR²
we input the formula for area
P/P[tex]_{sun[/tex] = eσ(πR²)T⁴ / eσ(π(R[tex]_{sun[/tex])²)T[tex]_{sun[/tex]⁴
such that we now have;
P/P[tex]_{sun[/tex] = R²T⁴ / R[tex]_{sun[/tex]²T[tex]_{sun[/tex]⁴
given that P/P[tex]_{sun[/tex] = [tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex], we substitute
[tex]([/tex] 1.5(M/M[tex]_{sun[/tex] [tex])^{3.5[/tex] = R²T⁴ / R[tex]_{sun[/tex]²T[tex]_{sun[/tex]⁴
we find temperature of the star T
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]M/M[tex]_{sun[/tex][tex])^{3.5[/tex] (R[tex]_{sun[/tex]²/R²)[tex]]^{1/4[/tex]
Given that; mass M is 3.8M[tex]_{sun[/tex] and radius R is 3.1R[tex]_{sun[/tex] .
we substitute
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]3.8M[tex]_{sun[/tex]/M[tex]_{sun[/tex][tex])^{3.5[/tex] (R[tex]_{sun[/tex]²/( 3.1R[tex]_{sun[/tex] )²)[tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 1.5[tex]([/tex]3.8[tex])^{3.5[/tex] ( 1/( 3.1)²)[tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 1.5( 106.9652 ) ( 1/(9.61) [tex]]^{1/4[/tex]
T = 5800 × [tex][[/tex] 16.69592 [tex]]^{1/4[/tex]
T = 5800 × 2.02140152
T = 11724.13 K
Therefore, the surface temperature of Regulus A is 11724.13 K
change $20.7 to pence
Answer:
1487.92 Pence Sterling (GBX)
You are riding your bicycle down the street at a speed of 14 m/s. Your bicycle frame has a mass of 6.6 kg, and each of its two wheels has mass 2.2 kg and radius 0.35 m. Each wheel can be thought of as a hollow hoop (assuming that the rim has much larger mass than the spokes). What is the total kinetic energy of the bicycle (in Joules), taking into account both the translational and rotational motion
Answer:
1078 Joules
Explanation:
The computation of the total kinetic energy of the bicycle is shown below:
Given that
mass of bicycle's frame (m) = 6.6 kg
mass of each wheel (M) = 2.2 kg
radius of each wheel (r) = 0.35 m
And, the linear speed (v) = 14 ms
Now
As we know that
Angular velocity (ω) = v ÷ r
= 140 ÷ .35
= 40 rads
Total kinetic energy = translational kinetic energy + rotational kinetic energy
= (1 ÷2 × m × v^2) + (2 × 1 ÷ 2×I × ω^2)
= (0.5 × 6.6 × [14]^2) + (M × r2 × ω^2)
= 646.8 + (2.2 × 0.35 × 0.35 × [40]^2)
= 646.8 + 431.2
= 1078 Joules
What is the atomic composition of methane
Answer:
As in chemical formula? It's CH4.
______is the amount of matter in an object. It does not change regardless
of location
__________which one
Friction
Mass
Weight
Answer:
Mass
Explanation:
The weight of an object is dependent upon the mass and the value of acceleration due to gravity:
W = mg
Since the value of acceleration due to gravity (g) changes from planet to planet. Hence, the weight of an object also changes with location.
Friction depends upon the material of surfaces and the weight.
F = (coefficient of friction)W
Since weight changes with location. Therefore, the friction also changes with location.
The mass of an object is the quantity of matter contained in the body. It remains constant anywhere in the universe.
Hence, the correct option is:
Mass
How are work and power different
Work is defined as the process of energy transfer to the motion of an object through the application of force. Power is defined as the amount of energy transferred in unit time.
An astronaut in a satellite 1600km above the Earth experience a gravitational force magnitude 700N on earth.The Earth's radius is 6400km calculate the magnitude of the gravitational force which the astronaut experience in satellite
Answer:
The magnitude of the gravitational force which the astronaut experience in satellite [tex]= 448[/tex] Newton
Explanation:
As we know
Gravitational force F = [tex]\frac{GMm}{r^2}[/tex]
Where G is the gravitational constant [tex]6.67 * 10^{-11}[/tex]
M is the mass of earth [tex]= 6* 10^{24}[/tex]
m is not given
r is the radius of earth [tex]6 400*10^3[/tex]
Substituting the given values, we get -
[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3)^2}[/tex]
[tex]m = 71.6[/tex] Kg
Gravitational force in the satellite
[tex]F = \frac{6.67*10^{−11}*6*10^{24}* m}{(6400*10^3 + 1600 *10^3)^2}\\F = 448[/tex]N