The water pressure as it exits into the air is P2 = Patoms
b) The height, h of the standing column of water is 4.6m
By Bernoulli's principle,
p1 - p2 = ρgh
h = 45 × [tex]10^{3}[/tex] / 1000 × 9.8
h = 4.6m
The relationship between a fluid's speed and pressure is described by Bernoulli's principle, which at first glance seems paradoxical. Many people think that Bernoulli's principle shouldn't be true, but this may be because they don't grasp what Bernoulli's principle actually states. According to Bernoulli's principle, which is stated below: Higher fluid velocity sites will experience less pressure than slower fluid velocity points inside a horizontal fluid flow. Thus, in a horizontal water pipe with a variable diameter, areas of fast-moving water will experience lower water pressure than areas of slow-moving water Since many individuals equate high speeds with high pressures, this may seem paradoxical to them. However, we'll demonstrate in the following section that this is really another way of expressing that water will accelerate if there is greater pressure behind it than in front of it. We will explain how Bernoulli's concept came to be, illustrate it in greater detail, and attempt to lessen its mystique in the part that follows.
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a constant force is applied to an object, causing the object to accelerate at 10 m/s2 . what will the acceleration be if the force is halved and the object's mass is doubled? express your answer using two significant figures.
The acceleration is if the force is halved and the item's mass is doubled is 2.5 m/s².
Force is a push or pulls upon an item due to the item's interaction with a few different item. strain is a energy that could change the motion of an item. A force can purpose an object with mass to exchange its velocity, i.e., to boost up. stress also may be defined intuitively as a push or a pull. A force has each significance and route, making it a vector amount.
In the first case,
Let the mass of the object is = m
acceleration = 10 m/s²
The constant force F = ma
F = 10m ---------(1)
New case 2,
force F' = F/2
mass M' = 2m
a = F'/M'
= F/2 × 2m
a = F/4m
F = 4ma ----------(2)
dividing equations 1 and 2
⇒ [tex]\frac{F = 4ma}{F = 10m}[/tex]
a = 10/4
a = 2.5 m/s²
The phrase 'force' has a unique which means. At this degree, it's far truely appropriate to describe a pressure as a push or a pull. A force isn't always something that an item consists of or 'has in it. A pressure is exerted on one object thru another. The idea of a force is not confined to living matters or non-dwelling matters.
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if the net acceleration is downward but has a magnitude less than g, then which has the larger magnitude, the force f or the tension in the rope?
If the net acceleration is downward but has a magnitude less than G, the force of F has a larger magnitude than the tension in the rope.
How to determine the net acceleration?We do know thаt the net force equаls mаss times the аccelerаtion. Now if we tаke the block аs а system, meаning we mаke use of the equаtion, mаss times аccelerаtion equаls net force, on the block. Now the lаst element of the rope is pulling the block upwаrds. This is becаuse the block pulls the rope down, hence due to newton's third lаw the rope too should pull the block, but in opposite directions, thаt is upwаrds. Hence the tension аcts upwаrds on the block. Therefore the net force is weight downwаrds аnd tension upwаrds, this equаls mаss times аccelerаtion,
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a car with a mass of 1,020.0 kg accelerates from 0 to 94.0 km/h in 10.0 s. the driver applies the brakes when the car is moving at 94.0 km/h, and the car comes to rest after traveling 38.0 m. what is the net force (in n) on the car during its deceleration? (assume the car is traveling in the positive direction. indicate the direction with the sign of your answer.)
The net force on the car during its deceleration = 9139.2 N
What is deceleration?Deceleration is actually inversely related to acceleration. We know that acceleration is the rate at which an object is speeding up, and deceleration is the rate at which an object is slowing down. For example, when you brake while driving, deceleration is used to slow the vehicle.
Given, m= 1020 kg
u= 0 m/s
V = 94 km/h or 26.1 m/s
t = 10 s
For deceleration
u = 26.1 m/s
v = 0
S = 38 m
by equation of motion ;
v² = u² + 2as
0 = 26.1² + 38a
a = - 8.96 m/s²
Net force during deceleration:
F= m*a
F= 1020 × 8.96
F = 9139.2 N
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a stealth bomber flying horizontally at a speed of 150 m/s drops a bomb from a height of 2500.0 m. how far in front of the target must the bomb be released
The bomb must be released 3375 m before the target when dropped from the height of 2500.0 m
What are equations of motion?An equation of motion is an equation that describes the behavior of a physical system in terms of motion as a function of time. More specifically, the equations of motion describe the behavior of a physical system as a set of mathematical functions related to dynamic variables.
Following are the equations of motion:
v = u + at
s = ut + 1/2 at²
v² = u² + 2as
Before calculating the horizontal distance let's calculate the time taken by the bomb to reach the ground by using following equation:
s = ut + 1/2 gt²
u = initial velocity in the vertical direction (0)
s = vertical displacement from the ground (−2500.0 m)
g = acceleration due to gravity (-9.8 m/s²)
Now substitute the the value in the above reaction:
-2500 = 0 × t + 1/2 × -9.8 t²
-2500 = -4.9 t²
t = 22.5 s
Now the distance covered by the bomb in horizontal direction by the time it reaches the ground is:
D = v × t
Where, D = distance covered by bomb horizontally
v = velocity of bomber (150 m/s )
t = time taken to reach the ground (22.5 s)
D = 150 × 22.5
D = 3375 m
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A TV with the power rating of 200 Watt uses 0.8 kilowatt of electrical energy in one day. For how many hours was the TV on during this day?
The number of hours that the TV was on is four hours.
What is the number of hours that the TV was on?We know that is possible to calculate the cost of electricity and this is done when we convert the electricity to the billing unit that we call the kilowatt hour.
Now we know that;
Power rating of the TV = 200 watt or 0.2 KW
The amount of electricity that was used by the TV in a day = 0.8 KWh
We can now find the number of hours from the relation;
Power rating * time = Energy used
0.2 * t = 0.8
t = 0.8/0.2
t = 4 hours
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a rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. if the plane is traveling horizontally with a speed of 69.4 m/s how far in advance of the recipients (horizontal distance) must the goods be dropped?
4.80m is the far of the recipients must goods dropped.
What is speed?The speed of an object is the rate at which it moves through space. A slow-moving object travels a relatively short distance in a given amount of time, whereas a fast-moving object travels a long distance in a short amount of time.
A)Since we are aware that the plane's vertical speed is zero
In this instance, the mass is dropped with no beginning speed.
thus, we will
y=1/2gt²
235=1/2(9.81)t²
t=6.92s
Consequently, it is given as the horizontal distance it moved.
d=vt
d=(69.4)(6.92)
d=480.4m
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proton traveling with speed 4 105 m/s in the y direction passes through a region in which there is a uniform magnetic field of magnitude 0.9 t in the z direction.you want to keep the proton traveling in a straight line at constant speed. to do this, you can turn on an apparatus that can create a uniform electric field throughout the region.what electric field should you apply?magnitude: ||
The electric field should be applied is 3,694.5 .
As we know from electromagnetic theory we have a relation with electric field and magnetic field with force, which is
F = qE + qv x B
or we can write that
F = qE + qvBsinФ
To allow proton to move with the constant speed, we need to apply zero external force
It means F = 0
or we can write that
qE = -qvBsinФ
putting the appropriate values, we get
E = 4105 x 0.9
E = 3,694.5
Hence the magnitude of the electric field is 3,694.5 .
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Waves that move the medium at right angles to the direction in which the waves travel.
Transverse waves are waves that move the medium at right angles to the direction in which the waves travel.
Types of Waves in PhysicsWaves are defined to be oscillations or vibrations about a fixed point, accompanied by the transfer of energy travelling from one medium to another. There are mainly two types of mechanical waves, namely longitudinal waves and transverse waves.
Longitudinal waves are waves in which the movement of the particles in the medium is in the same dimension as the wave’s movement direction. Examples of longitudinal waves include compression wave and sound waves. Transverse waves are waves in which the medium moves at an angle to the wave’s direction. Examples include stringed instruments and light waves.
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Help!!! 23 points label these as Element, compound, mixture of elements, and mixture of compounds
The given images are labelled as either element, compound, mixture of elements or mixture of compounds accordingly.
The answers are marked according in order of the images as follows:
ElementsCompoundsMixture of elementsMixture of compoundsCompoundsCompoundsIf there are only single type of atoms present without being in contact with another atom, it is called as elements. If one atom is in contact with another atoms it is a compound. If there are more than one type of element, it is a mixture of elements. If there are more than one type of compound, it is a mixture of compounds.
Therefore, the given images are labelled as either element, compound, mixture of elements or mixture of compounds accordingly.
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Which statement best describes heat?
A. Heat flows from cold to hot and is a form of thermal energy.
B. Heat flows from hot to cold and is the transfer of thermal energy.
C. Heat flows from hot to cold and is a form of thermal energy.
D. Heat flows from cold to hot and is the transfer of thermal energy.
Answer: D
Explanation:
In the period 6 inner transition element series, the 4f orbitals begin to be filled after the element _____.
In the period 6 inner transition element series, the 4f orbitals begin to be filled after the element Lanthanum(La) and Cerium(Ce).
The d and f Block elements in the groups of 3 to 11 are also called transition elements and inner transition elements respectively. 4f and 5f orbitals of f-block elements are steadily in the latter of two long periods.
Inner transition element:
Inner transition elements are those elements in which the last electron enters the f-orbital. The elements in which the 4f and the 5f orbitals are progressively filled are called f-block elements. These includes lanthanoids( Z = 58 - 71) and actinoids (Z = 90 - 103).
Therefore period 6 inner transition elements begin with Lanthanum and Cerium.
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A toy cart at the end of a string 0.70 m long moves in a circle on a table. The cart has a mass of 2.0 kg and the string gives a centripetal force of 40. N. Calculate the speed of the cart.
3.74 m/s is the speed of the cart of mass 2.0 kg and the string gives a centripetal force of 40. N.
What does a circle's centripetal force look like?The force that creates centripetal acceleration is known as centripetal force. All objects in uniform circular motion accelerate toward the center of the circle, and as a result, they must likewise experience a force from the center. The centripetal force is that force.
Briefing :
Given ,The mass of the cart, m = 2 kg,
The standard equation would be F = ma , where a is acceleration, f is force, and m is mass. However, the breaking strength of the string is 40 N.
a = [tex]\frac{v^{2} }{r}[/tex]
F = ma
F = [tex]\frac{mv^{2} }{r}[/tex]
40 = [tex]\frac{2v^{2} }{0.70}[/tex]
[tex]v^{2}[/tex] = 14
v = [tex]\sqrt{14}[/tex]
v = 3.74 m/s
Therefore , the speed of the cart is 3.74 m/s .
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betelgeuse is a red giant. this means the star is nearing the end of its life, and becoming larger and redder in the process. what's happening to the surface of the star as it becomes redder?
For a solar mass star, the red-giant phase normally lasts just around a billion years overall, with practically all of that time being spent on the red-giant branch.
The phases of horizontal branch and asymptotic huge branch move ten times more quickly.After a star exhausts its hydrogen fuel for nuclear fusion and starts to die, a red giant develops. A star keeps itself stable by carefully balancing the forces of its own gravity, which holds it together, with the pressure exerted outward by continuing thermonuclear fusion reactions occurring at its core.The typical lifespan of red giant stars is between 0.1 and 2 billion years. Red giant stars are significantly less massive and smaller than red supergiant stars.To know more about red-giant
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A 0. 0850-kg arrow is fired horizontally. If the bowstring exerts an average force of 89. 0 n on the arrow over a distance of 0. 782 m, with what speed does the arrow leave the bow?.
40.47 m/s is the speed of the arrow leaving the bow. When 0.0850 kg arrow fired horizontally, and If bowstring exerts average force of 89.0 N on the arrow over distance of 0. 782 m.
What is velocity?The primary indicator of object's position and speed is its velocity. It is distance that object travels in one unit of time. Displacement of item in one unit of time is definition of velocity.
By Newton's second law of motion,
F = ma
m is the mass of the arrow (kg) = 0.0850 kg
a is the acceleration of the arrow (m/s²)
F is the force applied (N) = 89.0 N
F= ma
a = F/m
a = 89.0/ 0.0850
∴ a= 1,047.059 m/s²
Now, object have acceleration, and the object will move in non-uniform motion. so the formula applied is:
[tex]v_{t}[/tex] = [tex]v_{0}[/tex] + at
[tex]v_{t}^{2}[/tex] = [tex]v_{0}^{2}[/tex] + 2×a×d
∴ d = [tex]v_{0}[/tex]×t +1/2× a ×t²
here,
[tex]v_{0}[/tex] = initial speed (m/s) = 0 m/s (arrow stationary in bowstring)
[tex]v_{t}[/tex] = final speed (m/s)
a = acceleration (m/s²) = 1,047.059 m/s²
t = interval (s)
d = distance (m) = 0.782 m
[tex]v_{t}^{2}[/tex] = [tex]v_{0}^{2}[/tex] + 2×a×d
[tex]v_{t}^{2}[/tex] = 0² + 2 × 1,047.059 × 0.782
[tex]v_{t}^{2}[/tex] = 1637.6
[tex]v_{t}[/tex] = [tex]\sqrt{1637.6}[/tex]
[tex]v_{t}[/tex] = 40.47 m/s
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A stater glides off a frozen pond onto a patch of ground at a speed of 3.1 m/S. Here she is stowed at a constant rate of 3.00 m/*, How fast is the skater moving when she has slid 0.42 m across the ground?
A stater glides off a frozen pond onto a patch of ground at a speed of 3.1 m/S. Here she is stowed at a constant rate of 3.00 m/s . The skater will move at a speed of v = 1.01 m/s , when she has slid 0.42 m across the ground
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
using kinematics equation
[tex]v^{2} - u^{2} = 2as[/tex]
[tex]v^{2} = u^{2}[/tex] + 2as
= [tex](3.1)^{2}[/tex] - 2 * 3 * 0.42
v = 1.01 m/s
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A crane is shown below. It is lifting a load of 5000N. The counterweight weighs 4400N and distance y is 9m. What must distance x be if the crane is balanced? Give your answer to one decimal place.
The distance x must be 7.92 m for the crane to be balanced according to principle of conservation of energy.
What is the distance x?The distance x can be determined by applying the principle of conservation of energy as shown below.
According to this principle of conservation of energy;
the input work (energy) = output work (energy)
F₁d₁ = F₀d₀
where;
F₁ is the input forced₁ is the input distanceF₀ is the output forced₀ is the output force(4400) x (9) = 5000x
39600 = 5000x
x = 39600/5000
x = 7.92 m
Thus, the crate a balanced condition, the output work must be equal to the input work.
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please this is serious
Distance x force equals work done. When this occurs, the amount of work done is measured in joules (J), the amount of force is recorded in newtons (N), and the distance travelled along the force's path is measured in meters (m).
What does work-done-unit mean?The SI unit of labor is called a joule (J).
The following questions have the following answers:
1) In the picture below, F1 acts downward and F2 acts upward.
2) Moments on the LHS equal F1d1 and on the RHS, F2d2.
Moment in LHS= RHS F1d1= F2d2 F1= (20Kg 10)/200 N Consequently, 200 N0.8= F20.95 160= 0.95 F2 = 168.42 N
The net force has a magnitude of 168.42 N and is directed upward.
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According to the first law of thermodynamics, work done by a system will cause _________ in the internal energy, assuming that no heat is transferred to or from the system.
According to the first law of thermodynamics, work done by a system will cause decrease in the internal energy, assuming that no heat is transferred to or from the system.
First law of thermodynamics says that energy can neither be created nor it can be destroyed, it can only be transferred from one form to another form. This is also a law of conservation of energy.
It means if there is any work done by any system then that system has burned its energy to do the work. so when energy is used to do the work , there will be decrease in the internal energy of the system, and that will be equal to the workdone.
ΔU = ΔW
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a group of ten friends, each of mass 50kg, want to test the strength of a trampoline. at their highest jump, each friend is 2m above the trampoline. they all land on the trampoline at the same time and decelerate at a constant rate to a point of zero velocity over a period of 0.5s. the trampoline has a threshold of 5000n, above which it breaks. do the friends succeed in breaking their trampoline? neglect air resistance and the distance the trampoline sags as a result of the friends landing.
Calculate the striking trampoline.
What is zero velocity?
The zero-velocity surface is a notion connected to the N-body gravity problem. It represents a surface that a body with the specified energy cannot traverse because it would have zero velocity there. George William Hill made the initial proclamation about it.
What is resistance?
A circuit's opposition to current flow is measured by its resistance. The Greek letter omega () stands for ohms, which are used to measure resistance. Georg Simon Ohm (1784–1854), a German physicist who examined the connection between voltage, current, and resistance, is the subject of the name "Ohm."
mass of each friends= 50kg
number of friends =10
total mass= 50×10=500kg
now initial velocity before, falling =0
let final velocity be V
v²-μ²= 2as
⇒v²+2as=2as(μ=0)
∴V=[tex]\sqrt{2as}[/tex]=[tex]\sqrt{2*9.8*2}[/tex] ( acceleration due to gravity =9.8m/s²) ( s=2m given)
=6.26ms⁻¹
∴The velocity of the friends, just before striking the trampoline= 6.26ms⁻¹
Now after striking the trampoline, the velocity of the people decelerate to 0, in a time interval 0.5s.
∴deceleration= 6.26/ 0.5= 12.52ms⁻²
∴Force required to decelerate=mass× deacceleration
=500×12.52
=6260.99
=6261N
but that trampoline has a threshold of 500N, which is less than force required to stop, the people.
hence the friends succeed in striking the trampoline.
Therefore, the friends succeed in striking the trampoline.
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suppose that the quarterback takes 0.30 ss to return to the ground after throwing the ball. how far ddd will he move horizontally, assuming his speed is constant?
The quarterback is located 0.3v above ground. The fundamental element of every projectile's body that is moving is its horizontal velocity (vx).
What is horizontal velocity?The fundamental element of every projectile's body that is moving is its horizontal velocity (vx). In any projectile motion, it is typically utilized to know the velocity value at which the particle travels along the horizontal direction. It's even thought of as the body's starting point for movement.
Let's say the projectile-moving particle reaches the highest point of its horizontal path. In that case, the horizontal velocity will typically be zero since the force of gravity will cause it to fall vertically downward as soon as it reaches the peak point. Vertical velocity has no impact on this horizontal velocity when it is at its highest point.
Let the horizontal velocity of the object = v
X = vt
X = 0.3v
Thus, The quarterback is located 0.3v above ground.
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A 440 hz tuning fork is used with a resonting colum to detemine the velocity of sound in helium gas . if the spacing between resonances in 110cm , what is the velocity of sound in helium gas?
The velocity of sound in helium gas is 968 m/s if the spacing between resonances is 110cm.
We have to go from antinode to antinode. In an air column, the spacing between resonance is wavelength /2 as we have to go from antinode to antinode.
wavelength = 220 cm = 2.2m
As we know the velocity formula
Then Velocity = f * λ
Where f is the frequency and λ is the wavelength.
So Velocity of wave = 440 * 2.2 = 968m/s
Hence, the velocity of sound in helium gas is 968 m/s if the spacing between resonances is 110cm.
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when two identical resistors are connected in series across the terminals of a battery, the power delivered by the battery is 20 w. if these resistors are connected in parallel across the terminals of the same battery, what is the power delivered by the battery?
If these resistors are connected in parallel across the terminals of the same battery, the power delivered by the battery is 80 W
Write the expression for the total power delivered by the battery in
parallel,Pp = 2P1
Here, Po is the total power delivered by the battery in parallel.
Pp = 2 [(ΔV)²/R]
= 4 [(ΔV)²/2R]
= 4Ps
Pp =4(20)
P =80 W
Electrical resistance is implemented as a circuit element by resistors, which are passive two-terminal electrical components. Resistors are devices that are used in electronic circuits for a variety of purposes, including lowering current flow, adjusting signal levels, dividing voltages, biasing active components, and terminating transmission lines. Electrical resistance is provided by a resistor, a two-terminal electrical component. Resistors are mainly used to split voltages, block transmission signals, reduce current flow, and bias active components in electronic circuits.
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how can we deducve the presence and measure the mass of a supermassivce black hole in the center of a galaxy
Astronomers can study how clusters of stars and gas move around the galactic center in nearby galaxies and use those movements to calculate the mass of the central black hole.
How can we calculate the black hole's mass at the galactic center?By monitoring the star motions in the galaxy's center, Webb will calculate the black hole's mass. Astronomers will calculate the mass of that black hole using NASA's James Webb Space Telescope. The outcome may appear to be unimportant, but a black hole's mass controls how it feeds and interacts with its surroundings.
Black holes are discovered when nearby material, such as gas, is pulled by gravity into a disk around the black hole. The gas molecules in the disk of the black hole are spinning so quickly that they heat up and release X-rays. From Earth, one can observe these X-rays.
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A large block of stone is held at a height of 15meters having gained 4500 j of gpe. how much does it weigh?
The weight of the large block of stone is 300 Newton. The result is obtained by dividing the gravitational potential energy by the height.
What is gravitational potential energy (GPE)?Gravitational potential energy is the energy stored in an object due to its position in a gravitational field. GPE can be expressed as
PE = mgh
Where
PE = gravitational potential energym = mass of an objectg = acceleration of gravityh = height of an objectGiven
h = 15 mPE = 4500 JHow much does it weight?
The weight of an object is the mass times the acceleration of gravity.
W = mg
So, with the GPE equation, the weight is
PE = mgh
PE = W × h
4500 = W × 15
W = 4500 ÷ 15
W = 300 Newton
Hence, the weight of the large block of stone is 300 Newton.
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a skateboard rolls down a hill and the wheels do not slip against the pavement. does the static friction force of the pavement on the wheels do any work on the skateboard? g
The static friction force of the pavement on the wheels will not do any work on the skateboard.
Static friction is a variable resisting force that is equal and opposite to the external force until it exceeds the motion threshold when sliding begins.
It is also called as self adjusting force.If the skateboard is rolling at a constant speed without any other forces acting on it, then there is no tendency to slip between the wheel and the surface, so there is no frictional work. Friction will only try to prevent slipping between the 2 surfaces.
On an inclined plane, the wheels will tend to slide down, and if there were no friction, it would again slide between the wheels and the inclined surface. Perhaps friction will always try to counteract the slip, so here it acts upward on the slope to try to prevent the skateboard from sliding down the slope. This has the effect of applying a moment to the skateboard causing it to roll.
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two wheels, a and b, are both shaped like uniform disks and have the same overall mass, but wheel a has twice the radius of wheel b. how do we calculate the moments of inertia (around the axis of symmetry) for each wheel?
The ratio of I sub A to I sub B is 4.
How can you calculate the ratio of A to B?
A/B would be your formula if you were comparing one data point (A) to another data point (B). This indicates that you are multiplying information A by information B. For instance, your ratio will be 5/10 if A is 5 and B is 10. How do we determine each wheel's moments of inertia (around the axis of symmetry) I is equal to 1 over 2 times m times R squared is used to compute the moments of inertia for both masses and radii. We simply use a common factor to cancel. So 4:2=2:1 . The simplest representation of the ratio 4 to 2 is the ratio 2 to 1. Additionally, since each pair of numbers has the same relationship, the ratios are equivalent.
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A car traveling at 5m/s brakes and skids through a displacement of 6m. if it slows down at the rate of 2m/s/s, determine the length of time during which it breaks.
When a car travels at 5m/s and brakes at the rate of 2 m/s², the length of time to travel 6 m is 2 or 3 seconds.
Use the equation of motion for deceleration:
s = u . t - 1/2. a t²
Where:
s = distance
u = initial velocity
t = travel time
a = acceleration (minus sign means deceleration)
Parameters given in the problem:
s = 6 m
u = 5 m/s
a = 2 m/s²
Plug these parameters into the formula:
6 = 5t - 1/2. 2 . t²
t² - 5t + 6 = 0
(t - 3) (t - 2) = 0
t = 3 or t = 2
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An electric pace heater draw 25. 0 A from a 200 V ource. It i operated, on the average, for 10. 0 h each day. At AED 0. 30 per kWh, how much doe it cot to operate the heater for 15 day?
The consumption to operate the heater for 15 days is $2.25
Electricity consumption refers to all of the electricity used to perform a movement, manufacture something, or definitely inhabit a construction. here are some examples: In a manufacturing unit, overall electricity consumption can be measured with aid of looking at how lots power a manufacturing technique consumes, for instance, via making car elements.
The full-strength intake consists of that of coal, crude oil and their products, natural gasoline, and electricity, but, it excludes the intake of gas of low calorific fee, bio-strength, and solar energy.
Calculation:-
Voltage (V) = 200 V
Current (I) = 25 A
Power (P) = VI = 200 * 25 = 5,000 W
Now, the calculation of the energy consumption for 15 days in KW/h
We will convert W to kW,
1000 W = 1kW
Therefore,
5,000 W = 5000 W × 1 KW / 1000 W = 5kW
The daily energy consumption will be calculated. This is attainable as follows,
P = 5kW
Time(t) = 10 h
Energy (E) = P/t = 5/10 = 0.5 kW/h per day.
Finally, we will calculate the energy usage for the next 30 days. This is attainable as follows:
1 day = 0.5 kW
Cost of one day = 0.5 * 0.30 = $ 0.15
Now, the cost to operate the heater for 15 days = $ 15 * 0.15 = $2.25
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A resistor, an inductor, and a capacitor are connected in series to an ac source. What is the phase angle between the voltages of the inductor and capacitor in this rlc circuit?.
The phase angle between the voltages of the capacitor and inductor in rlc circuit is 180°.
The phase angle is the component of a periodic wave. It is the shift between the AC current and the voltage on the measured impedance. The two elements of phase angle are reactance(X) and resistance (R).
The phrase for phase angle is, Xₐ = sinωt
where Xₐ= phase angle
ω = wavelength of the wave in 1 revolution
t = time period of 1 revolution
The instantaneous voltage ΔvR is in phase with the current, ΔvL leads the current by 90°, while ΔvC lags behind the current by 90°. The instantaneous values of these three voltages do add algebraically to give the instantaneous voltages across the RLC combination.
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a 110 g hockey puck sent sliding over ice is stopped in 15 m by the frictional force on it from the ice. (a) if its initial speed is 6.0 m/s, what is the magnitude of the frictional force? (b) what is the coefficient of friction between the puck and the ice?
The frictional force where k is the unitary force of kinetic friction acting on an object and k is the coefficient of kinetic friction. For the vast majority of surfaces, K is less than S.
Explain about the magnitude of the frictional force?The weight of the object and the roughness of the surface in contact determine how much frictional force is generated. The friction force will grow as the roughness increases.
The weight of the object bearing normal to the surface times the coefficient of friction for the contacting surfaces gives the amount of the friction force. The force's direction is perpendicular to the surface and is in opposition to any forces acting on the box.
The amount of kinetic friction is inversely proportional to the amount of normal force and the degree of roughness between the sliding surfaces. The amount of static friction is inversely proportional to the amount of normal force and the degree of roughness between the sliding surfaces.
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