A wire is attached to the ceiling so that the current flows south to north. A student is standing directly below the wire facing north. What is the direction of the B-field (caused by the current in the wire) at this observation point

Answers

Answer 1

Answer:

If one wraps the fingers around the wire and points the thumb in the direction of the "conventional" current the fingers will point towards the North pole - the direction of the B-field.

In this case the B-field is pointed "West".


Related Questions

How many times does the light beam shown in FIGURE 26-59 reflect from (a) the top and (b) the bottom mirror?

Answers

Answer:

5

Explanation:

The amount of energy released when 45 g of -175° C steam is cooled to 90° C is


A. 101,700 J


B. 317,781 J


C. 419,481 J


D. 417,600 J

Answers

Answer:

The answer should be choice B.

What is environmental?

Answers

Answer:

Environmental means relating to or caused by the surroundings in which someone lives or something exists. It protects against environmental hazards such as wind and sun. The form the human family takes is a response to environmental pressures.

Explanation:

I HOPE IT HELPS!!

THANX!!!

STAY SAFE!!!!

A light bulb operating at a dc voltage of 120 V has a power rating of 60 W. How much current is flowing through this bulb

Answers

Voltage=V=120VPower=P=60W

Current=I

[tex]\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{60}{120}=\dfrac{1}{2}=0.5A[/tex]

What is the electric field strength inside the capacitor? What is the potential energy of a proton at the midpoint of the capacitor?

Answers

Answer:

2.4*10^-17 J

Explanation:

E = V/d = 300 V / 3*10^-3 m = 1.0*10^5 V/m

Voltage at midpoint = E*d = 1.0*10^5 V/m * 1.5*10^-3 m = 150 V

ΔV = 300 V - 150 V = 150 V

Charge of a proton = 1.6*10^-16 C

U = qΔV = (1.6*10^-16 C)(150V) = 2.4*10^-17 J

The electric field strength inside the capacitor is 100,000 V/m, the Potential difference at the midpoint is 150V, and the potential energy of a proton at the midpoint of the capacitor is  2.403 x 10⁻¹⁷J.

What is a capacitor?

A capacitor is an electronic device that stores electrical energy in an electric field between two conducting plates separated by a dielectric material. When a voltage difference is applied across the plates, a charge is stored on each plate, creating an electric field between the plates. The capacitor can then release this stored electrical energy when needed.

The energy stored in a capacitor is given by the formula:

U = [tex]\frac{1}{2}[/tex]CV²

Where

U =the energy stored in the capacitor,

C = the capacitance of the capacitor,

V =the voltage difference across the plates.

Capacitance is a measure of the ability of a capacitor to store charge and is given by the formula:

C = εA/d

Where C = the capacitance,

ε = the permittivity of the dielectric material between the plates,

A = the area of the plates,

d =the distance between the plates.

Here in the question

To calculate the electric field strength inside the capacitor, we can use the formula:

E = V/d

Where E = the electric field strength,

V =the voltage difference between the plates,

d =the distance between the plates.

In this case, the distance between the plates is d=3mm =0.003m,

the voltage difference is between 0V to 300V.

Now, the electric field strength inside the capacitor is:

E = V/d = 300V/0.003m = 100,000 V/m

To calculate the potential energy of a proton at the midpoint of the capacitor, we can use the formula:

U = qV

Where U = the potential energy,

q =the charge of the particle,

V =the voltage difference between the plates.

In this case, we need to know the charge of the proton.

The charge of a proton = +1.602 x 10⁻¹⁹ C.

At the midpoint of the capacitor, the proton will experience a potential difference of 150V (half of the 300V voltage difference).

Now, the potential energy of the proton at the midpoint of the capacitor is:

U = qV = (1.602 x 10⁻¹⁹ C) x (150V) = 2.403 x 10⁻¹⁷J

Therefore, the electric field strength is 100,000 V/m and the potential energy of a proton at the midpoint of the capacitor is 2.403 x 10⁻¹⁷J.

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5. Apply Concepts A heat engine has an energy input of 300 J. Its output of use-
ful energy is 150 J. What is the total output of non-useful energy from the heat
engine? Explain how you know.

Answers

Given the data from the question, the total output of non-useful energy from the heat engine is 150 J

What is a heat engine?

A heat engine is a device / equipment that can convert or transfer thermal energy into useful-work. Some examples of heat engines include

refrigeratorsInternal combustion Thermal power stationfirearms  heat pumps

How to determine output non-useful energy

From the question given above, the following data were obtained:

Input energy = 300 JOutput (useful) = 150 JOutput (non-useful) =?

Output (non-useful) = Input – Output (useful)

Output (non-useful) = 300 – 150

Output (non-useful) = 150 J

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define key terms related to the muscular, skeletal, and nervous systems

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Answer:

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You are standing on roller skates if you try to throw a 20-pound bowling ball while standing on skates,
what happens. How does this show Newton 3rd law

Answers

Answer:

I'd probably drop it on my toes. That would happen.

Explanation:

Who is the father of the humans

Answers

Answer:

Adam Was the first person

Explanation:

Answer:

God is

Explanation:

Adam was the first human, Yes but God is the one who man Adam in his image and likeness, that is God looks just like the human

because we are made in God's image

Why would it be impractical to wire a home with a circuit in which all loads were connected in series.

Answers

For residences, series circuits are impracticable. Parallel circuits are practical because each appliance is controlled by its own switch, which prevents the other appliances from being turned off. A) The appliances are all turned on. The conductor wire is carrying a considerable quantity of current (arrow).

Which number represents runoff on the hydrologic cycle diagram?


1


2


3


4

Answers

Answer:

number 3

Explanation:

3 represents runoff


Runoff is the water collected after rainfall that drains from the surface area of land. It will be tricky to choose 4 which is likely a smaller waterbody draining to a bigger waterbody


hope it helped

Please answer and show formula

Answers

Voltage = 5 volts

[tex]\sf \dfrac{number \ of \ turns \ in \ primary \ coil}{voltage\ in \ primary \ coil} = \dfrac{number \ of \ turns \ in \ secondary\ coil}{voltage\ in \ secondary\ coil}[/tex]

[tex]\hookrightarrow \sf \dfrac{400}{100} = \dfrac{20}{V_2}[/tex]

[tex]\hookrightarrow \sf 400V_2}{} = 20*100[/tex]

[tex]\hookrightarrow \sf V_2 = 5 V[/tex]

What is the solution of this? ​

Answers

Answer:

1.2 is the correct answer due to the graph

Explanation:

math teacher

The answer is the third one 0.8s

static frictional Force​

Answers

Answer:

The static frictional force is the force between the magnetic forces statically and contains only two objects during this physical reaction. It results in electricity and a slight shock.

An elastic string of length 20cm stretch by 7mm under a load 50N . The strain in the spring is?

Answers

Answer:

0.035

Explanation:

7÷1000

=0.007m

0.007/0.2

=0.035

Mechanical strain of an elastic substance is the ratio of its change in length to the original length. The strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.

What is strain ?

Strain is a physical quantity used to express the change in dimension of an elastic material. It is the ratio of change in length to the original length. Stress is the force that causing the deformation.

According to Hook's law of elasticity, the strain is directly proportional to the strain. They show a linear relation. Let L be the original length of a string and its change in length be ΔL.

Thus, strain = ΔL / L

Given that, the change in length = 7 mm = 0.7 cm

original length of the string = 20 cm

strain = 0.7 cm/ 20 cm

         = 0.035

Therefore, the strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.

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In question 8 from “Problems 2”, you calculated that an archery arrow shot with an initial velocity of 45 m/s at an angle of 10 degrees would travel 70.67 m (2 d.p.) before hitting a target at the same height from which it was released. If the archery target was moved further away from the archer, discuss some kinematic-based strategies that the archer could adopt to ensure that the arrow reaches the target. Ensure that the variables discussed are relevant to your answer. Assume air resistance is negligible.

Answers

The distance traveled by the arrow and horizontal velocity are directly proportional, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.

Time of motion of the projectile

If the horizontal distance the projectile would travel before hitting the target is 70.67 m, the time of motion of the projectile is calculated as;

X = Vx(t)

t = X/Vx

t = X/Vcosθ

t = (70.67) / (45 x cos10)

t = 1.6 s

When the archery target is moved further away from the archer, the archer needs increase the initial velocity of the arrow assuming the angle of projection is constant.

Since the distance and horizontal velocity are directly proportional to each other, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.

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What are the three symbols used in Ohm's law. Explain what each symbol represents and give the units for each of the variables.

Answers

Answer:

Step by step explanation:

if a company recieved cash in advance for future services what account will need an adjusting entry? A salaries expense B cash C unearned revenue D accounts receivable

the answer is C unearned cash revenue

Answers

Answer:

D

Explanation:

The accounts receivable would need to be changed to reset the accounts if the future service received cash in advance

Two identical charges are located 1 m apart and feel a 1 N repulsive electric force. What is the charge of each particle.

Answers

The charge on each particles which are 1 m apart and feeling a repulsive force of 1 N is 1.05×10¯⁵ C

Assumption

Let the charge on each particles be q

How to determine the charge Final force (F) = 1 NDistance apart (r) = 1 mElectrical constant (K) = 9×10⁹ Nm²/C²Charge on 1st particle (q₁) = q =? Charge on 2nd particle (q₂) = q =?

The charge on each particle can be obtained by using the Coulomb's law equation as shown below:

F = Kq₁q₂ / r²

F = Kq² / r²

1 = (9×10⁹ × q²) / 1²

1 = 9×10⁹ × q²

Divide both side by 9×10⁹

q² = 1 / 9×10⁹

Take the square root of both side

q =  √(1 / 9×10⁹)

q = 1.05×10¯⁵ C

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An unbalanced force acting on an object results in ______.
A. inertia
B. friction
C. acceleration
D. faster
E. slower

Answers

Answer:

friction

Explanation:

The force of gravity on an object gives the object its _______.
A. mass
B. kilogram
C. acceleration of gravity
D. weight

Answers

Answer:

Weight

Explanation:

The force of gravity on a an object gives the object its weight.

An object of mass m is oscillating with a period T. The position x of the object as a function of time is given by the equation x(t)=Acosωt . The maximum net force exerted on the object while it is oscillating has a magnitude F. Which of the following expressions is correct for the maximum speed of the object during its motion?

Answers

What the equation given?

x(t)=Acos[tex]\omega[/tex]t

Maximum velocity occurs at the equilibrium position

So

x=0

Now

x(0)=Acos0[/tex]x(0)=A

Now

As we know the formula

[tex]\\ \rm\rightarrowtail V_max=A\omega[/tex]

These expressions can be used

The maximum speed of the oscillating object will be given by [tex]V_{max}=Aw[/tex]

What is oscillation?

An oscillation is defined as the repitative periodic motion of any object about its mean or equilibrium position.

The given equation is as follows:

x(t)=Acost

Maximum velocity occurs at the equilibrium position x=0

x(0)=Acos0

x(0)=A

Hence the maximum velocity will be  [tex]V_{max}=Aw[/tex]

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A 100 Ohm, 200 Ohm, and 400 Ohm resistors are in parallel with each other. What is the equivalent
resistance? Which resistor would draw the most current, and why?

Answers

Answer:

1/R = 1/R1 + 1/R2 + 1/R3

1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75

1/1.75 = .572

multiplying this by 100 gives us

R = 57.2 ohms

The smallest resistor (100 ohms) will draw the most current

(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)

Hi there!

We can use the following equation to solve for equivalent resistance:


[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}[/tex]

We can plug in the givens and solve.

[tex]\frac{1}{R_T} = \frac{1}{100} + \frac{1}{200} + \frac{1}{400} \\\\\frac{1}{R_T} = 0.175\\\\R_T = \frac{1}{0.175} = \boxed{57.143 \Omega}[/tex]

The resistor that would draw the most current is the 100 Ohm resistor because current chooses the path of LEAST RESISTANCE. This can also be proved mathematically with the following:

For resistors in parallel, the POTENTIAL DIFFERENCE (VOLTAGE) is the same.

Since I = V/R, a smaller 'R' means a larger 'I'. Thus, the smallest resistor would have the greatest current through it.

Which of the following is NOT an example of force. A. Gravity. B. Mass. C. A push. D. Friction.

Answers

Answer:

Mass

Explanation:

Gravity is a force (sort of keeping something in place)

A push is force (force pushing something)

Friction is force (force that resists sliding or rolling)

If a transverse wave osculates 7 times every second and the speed of the wave is 27 m/s what is the wavelength of the wave

Answers

Explanation:

formula is ˠ=vf

f=1/T

1/7

f=0.14

wavelength=27Ⅹ0.14

=3.78m

OR

7Ⅹ27

=189m

state the formula to compute average speed acquired by a vehicle to cover a distance between two points.

ty! :)​

Answers

The general speed average formula for an object is given as [Average Speed = Total Distance Traveled ÷ Total Time Taken]. SI unit of average speed is m/s.

. Stephen learned that any two objects exert a gravitational force on each other.
If the distance between two objects triples, the gravitational force between
them will change by a factor of what?
F = G mim

Answers

Explanation:

Stephen learned that any two objects exert a gravitational force on each other.

If the distance between two objects triples, the gravitational force between

Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of 9.

What is gravitational force?

The gravitational force is an unobservable force that draws things together. You remain on the ground thanks to Earth's gravity, a gravitational force is a force that also causes objects to fall.

The mathematical expression for the gravitational force is given by

F = G× m₁* m₂ / r ²

As given in the problem statement Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples,

The gravitational force between the objects is inversely proportional to the square of the distance between the object.

Thus, the gravitational force between them changes by a factor of 9.

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A vector is 0.888 m long and
points
in a
205 degree
direction.
Find the y-component of the
vector.

Answers

Answer:

Since the second quadrant ends at 180 deg,

205 will be 25 deg into the third quadrant (-x and -y)

y = -.888 sin 25 = -.375

One can also write y = .888 sin 205 = -.375

help me get a answer ​

Answers

Answer:

I think D sorry if I'm wrong

How much force is required to pull a spring 3.0 cm from its equilibrium position if the spring constant is 20 N/m?

Answers

Distance=3cm=0.03mSpring constant=k=20N/mForce=F

[tex]\\ \rm\rightarrowtail F=-kx[/tex]

[tex]\\ \rm\rightarrowtail F=-20(0.03)[/tex]

[tex]\\ \rm\rightarrowtail F=-0.6N[/tex]

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Next to her, Allen just stared at the floor of the lander muttering, Not me, not me.She glanced at Lily, who Maria had always known to be fearless, but Lily bit her lip and turned away. Javier looked positively gray, and the twins buried their faces in their hands. Someone would have to be first. Maria closed her eyes and took a few meditative breaths, waiting for someone else to volunteer, but the lander was silent. FINDING COURAGEThe radio crackled to life. Lander one, this is Mothership, do you copy?Yes, Captain Curran answered. Weve landed safely and are waiting to exit the lander, but theres just a littledisagreementover which pioneer wants to be the first to set foot on our new home.Tell them theres plenty for everyone to see, and theyre going to love it out there, the voice on the radio responded. I wish it were me instead of you; I miss the feel of real air on my face.Captain Curran flipped off the microphone. You six have lived your entire lives in space, and its a great privilege to be the first of your generation to see a new planet. The others are watching; if youre afraid, theyll be afraid. Cant any of you find the courage to set an example?Maria shifted uncomfortably in her seat and thought of her parents; they had traveled across the galaxy to find their family a new home, with clean air and good soil, and she knew this planet was for them. Ill do it, Captain, she mumbled as she slipped out of her harness and rose out of her seat. Maria couldnt shake the feeling of trepidation as she stood and watched the doors of the lander slide open.A NEW WORLDA burst of air hit Maria in the face. She scrunched up her nose as an unfamiliar assortment of odors hit her nostrils. Some smelled sweet, some disgusting, and some were just strange. There were never strange smells on the ship; everything was always the same there. What was it going to be like to live where things changed? The rest of the children gathered around the opening as she climbed down the ladder, and Maria tried to smile as she met their worried eyes. Then, suddenly, something crunched underneath her boots; she was standing on the surface of the planet, and it felt nothing like the smooth metallic halls that shed known all her life.Without letting go of the ladder, she turned around to look at the world around the lander. The soil was full of shapes and textures; there were some small, grainy pieces, then larger clumps that she could break with the toe of her boot. One piece was hard and smooth, and she let go of the ladder to pick it up. Captain, she called, I think Ive found a rock!The air was moving, and long, thin, green things bowed and danced. Grasses, Maria whispered to herself, remembering the videos in her science lessons. She let go of the ladder and took soft, slow steps and realized her arms and legs felt like they were full of lead. Natural gravity, she whispered to herself. She started to walk a little more quickly, getting used to the new sensation. She was doing what others had previously thought impossibletaking steps on a new world.A creature with gossamer wings landed on her nose, and she crossed her eyes trying to get a good look at it. Something small and furry scurried across her feet as she spun in a slow circle. Inspired, she ran as fast as she could across the foreign soil; shed never seen somewhere so big, and it was thrilling. Suddenly, a deep, low sound echoed around her. Thats the call of a hornbeast, Captain Curran shouted from the bottom of the ladder. Maria glanced back and saw that he was helping her friends take tentative first steps in the new world. Walk to your left a little, and there should be a streamflowing water on the ground; they often go there to drink, the explorers say.She started to run in that direction and then paused. Hurry up! she yelled, unable to contain her enthusiasm. Our new home is extraordinary! 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