A woman bought some large frames for ​$18 each and some small frames for ​$8 each at a closeout sale. If she bought 21 frames for ​$​248, find how many of each type she bought.

Answer:

No, that is incorrect.

[tex]21 * 34 = 714\\20 * 35 = 700[/tex]

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Ask me in the comments box, please.

The angle between the two forces of 560 N and 222 N is 80.96°

The resultant of two vectors P and Q refer to the magnitudes of the vectors and it can be expressed by the formula [tex]\mathbf{R = \sqrt{P^2 +Q^2 +2PQ cos \theta }}[/tex]

Now, using the above equation, we can easily determine the angle between the forces of the two vectors as follows:

[tex]\mathbf{634 = \sqrt{560^2 +222^2 + 2(560 \times 222) \ Cos \theta }}[/tex]

[tex]\mathbf{401956 =313600 +49284 + 248640 \ Cos \theta }}[/tex]

[tex]\mathbf{401956 -313600 -49284 = 248640 \ Cos \theta }}[/tex]

[tex]\mathbf{39072= 248640 \ Cos \theta }}[/tex]

[tex]\mathbf{ Cos \theta = \dfrac{39072}{248640}}}[/tex]

[tex]\mathbf{Cos \theta =0.1571}[/tex]

[tex]\mathbf{ \theta =80.96^0}[/tex]

Therefore, we can conclude that the angle between the forces is 80.96°

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Answer:

0.72 meters

Step-by-step explanation:

by dividing 6.48 by 9, we get 0.72 meters

Answer:

here

Step-by-step explanation:

Answer:

30.125

the answer is 30.125 so that is the answer of this question

Answer:

Step-by-step explanation:

In order to determine the correct answer, we need to confirm it first by making the solution below:Costs: $89.95 = New Lamp $239.99 = Comforter 6 3/5% = Sales Tax (convert this to decimal and we get 6.6%)  $351.72 = Total amount the Chang's paidLet's get the total costs first which is $329.946.6% of 329.94 is $21.78The total cost with the tax would be $351.72.Therefore, the Chang's paid the correct amount. The correct answer would be option D. The Chang's family paid the correct amount for their purchases.

Answer:

SU=6

TU=6

ST=12

Step-by-step explanation:

SU and TU are equal because their hypotenuses are equal (10).

With this knowledge, you know that 2x+2=3x.

Subtracting 2x from both sides shows that x=2, so you can substitute that into the original line segment values in order to get 6 for both SU and TU. Double this to find the value of ST (12).

GH is a tangent to the given circle.

A line that only touches a circle or an ellipse at one point is said to be tangential in geometry. If a line contacts a curve at point P, that point is referred to as the point of tangency. In other words, it is described as the line that, at that particular location, indicates the slope of a curve.

As per the given diagram:

The line segments AB, AC, DC and EF are drawn in the diagram also a line GH is drawn in the diagram.

A line GH is drawn such that it's extending from both of its end towards infinity, and it touches the circle at only one point, which is G. This satisfies all the conditions for the line GH to be a tangent.

Hence, GH is a tangent to the given circle.

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C

Step-by-step explanation:

You do 5 - 2 = 3 and -y = -x so the answer would be C.

Answer:

486 square inches.

Step-by-step explanation:

126 = w + 6w + w + 6w

126 = 14w

width = 9 inches

A = wl

A = (9)(9*6)

A = 486 square inches

Answer:

8 po yan po sagot ko .. correct me if I wrong

Answer:

40 cups

Step-by-step explanation:

There are 16 cups in one gallon. So 16 * 2 1/2 = 40

Answer:

3+15=18 i guess

Step-by-step explanation:

dont judge me im only in 2 grade

Using it's concept, it is found that the sample mean package weight for Thursday is of 19 ounces.

The mean of a data-set is given by the sum of the observations divided by the number of observations.

For Thursday, the package weights in ounces are given by: {18, 19, 20, 19}.

Hence, the sample mean in ounces is of:

M = (18 + 19 + 20 + 19)/4 = 19.

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Answer:

A. x = -9

Step-by-step explanation:

6x + 8 = 3x - 19 <== subtract 3x from both sides

-3x       -3x

3x + 8 = -19 <== subtract 8 from both sides

    - 8     - 8

3x = -27 <== divide both sides by 3

/3     /3

x = -9

Hope this helps!

Answer:

[tex]\tt x=-9[/tex]

Step-by-step explanation:

[tex]\tt 6x + 8 = 3x - 19[/tex]

Subtract 8 from both sides:-

[tex]\tt 6x+8-8=3x-19-8[/tex]

[tex]\tt 6x=3x-27[/tex]

Subtract 3x from both sides:-

[tex]\tt 6x-3x=3x-27-3x[/tex]

[tex]\tt 3x=-27[/tex]

Divide both sides by 3:-

[tex]\tt \cfrac{3x}{3}=\cfrac{-27}{3}[/tex]

[tex]\tt x=-9[/tex]

The vaule of x that makes the equation true is A) x= -9.

[tex]12x\sqrt{\cfrac{3}{2}}~~ = ~~6\sqrt{3}\implies (6)(2)x\cdot \cfrac{\sqrt{3}}{\sqrt{2}}~~ = ~~6\sqrt{3}\implies \cfrac{(2x)(6\sqrt{3})}{\sqrt{2}}=6\sqrt{3} \\\\\\ \cfrac{2x}{\sqrt{2}}=\cfrac{6\sqrt{3}}{6\sqrt{3}}\implies \cfrac{2x}{\sqrt{2}}=1\implies 2x=\sqrt{2}\implies x=\cfrac{\sqrt{2}}{2}[/tex]

Answer:

Answer is -1/64

Step-by-step explanation:

Mark me the brilliant

Answer:

x = 4, 1/4

solving steps

[tex]\sf \rightarrow x + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]

make the denominators same

[tex]\sf \rightarrow \dfrac{x(x)}{x} + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]

simplify the following

[tex]\sf \rightarrow \dfrac{x^2}{x} + \dfrac{1}{x}=\dfrac{17}{4}[/tex]

join both fractions together

[tex]\sf \rightarrow \dfrac{x^2+1}{x}=\dfrac{17}{4}[/tex]

cross multiply

[tex]\sf \rightarrow 4(x^2+1)=17(x)[/tex]

simplify

[tex]\sf \rightarrow 4x^2-17(x)+4=0[/tex]

completing square

[tex]\sf \rightarrow 4x^2-16(x)-x+4=0[/tex]

factor

[tex]\sf \rightarrow 4x(x-4)-1(x-4)=0[/tex]

group the variables

[tex]\sf \rightarrow (4x-1)(x-4)=0[/tex]

simplify

[tex]\sf \rightarrow (x-4)=0, \ (4x-1) =0[/tex]

final answer

[tex]\sf \rightarrow x=4, \ x =\dfrac{1}{4}[/tex]

Answer:

[tex]\boxed{x = \dfrac{1}{4}}[/tex] and [tex]\boxed{x = 4}[/tex]

Step-by-step explanation:

Given equation:

[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]

Step-1: Convert the mixed fraction on the R.H.S into improper fraction

[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{4 \times4 + 1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{16 + 1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

Step-2: Make common denominators on the L.H.S:

[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

Step-3: Combine the denominators on the L.H.S

[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]

Step-4: Use cross multiplication

[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]

[tex]x^{2} +1} = \dfrac{17x}{4}[/tex]

[tex]4(x^{2} +1}) = {17x}[/tex]

Step-5: Simplify the distributive property

[tex]4(x^{2} +1}) = {17x}[/tex]

[tex]4x^{2} +4} = {17x}[/tex]

[tex]-17x + 4x^{2} +4} = 0[/tex]

Step-6: Change "-17x" to "-16x - x" as it is equivalent

[tex]-17x + 4x^{2} +4} = 0[/tex]

[tex](-16x - x) + 4x^{2} +4} = 0[/tex]

Step-7: Factor the common terms

[tex](-16x - x) + 4x^{2} +4} = 0[/tex]

[tex]-16x - x + 4x^{2} +4} = 0[/tex]

[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]

Step-8: Group the terms

[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]

[tex](x - 4)(4x - 1) = 0[/tex]

Step-9i: Use cross multiplication for (x - 4)

[tex](x - 4)(4x - 1) = 0[/tex]

[tex]x - 4 = \dfrac{0}{4x - 1 } = 0[/tex]

Step-9ii: Use cross multiplication for (4x - 1)

[tex](x - 4)(4x - 1) = 0[/tex]

[tex]4x - 1 = \dfrac{0}{x - 4} = 0[/tex]

Thus [tex]x - 4 = 0[/tex] and [tex]4x - 1 = 0[/tex].

Step-10: Simplify both equations

[tex]4x - 1 = 0[/tex]                  [tex]x - 4 = 0[/tex]

[tex]4x = 0 + 1[/tex]                  [tex]x = 0 + 4[/tex]

[tex]4x = 1[/tex]                          [tex]\boxed{x = 4}[/tex]

[tex]\boxed{x = \dfrac{1}{4}}[/tex]

Answer:

2x - 6x = -5-5

-4x = -10

4x = 10

x = 10/4

Therefore, x= 5/2.

Answer:

The battery seems to be charging at a rate of 1 percentage point per minute. So the battery should be fully charged at 10:11 AM.

Step-by-step explanation:

The correct factored form of the expression p³ - 125q³ is,

(p - 5q)(p² + 5pq + 25q²).

A polynomial is an algebraic expression.

A polynomial of degree n in variable x can be written as,

a₀xⁿ + a₁xⁿ⁻¹ + a₂xⁿ⁻² +...+ aₙ.

We know that if x = a is one of the roots of a given polynomial x - a = 0 is a factor of the given polynomial.

To confirm if x - a = 0 is a factor of a polynomial we replace f(x) with f(a) and if the remainder is zero then it is confirmed that x - a = 0 is a factor.

We know, a³ - b³ = (a - b)(a² + ab + b²).

Given, An expression p³ - 125q³.

= p³ - (5q)³.

= (p - 5q)(p² + p.5q + (5q)²).

= (p - 5q)(p² + 5pq + 25q²).

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Answer:

Step-by-step explanation:

Quadratic equations are commonly used in situations where two things are multiplied together and they both depend on the same variable. For example, when working with area, if both dimensions are written in terms of the same variable, you use a quadratic equation.

The value of a is equal to 3 and the value of b  is equal to 4.

A Complex Number is represented by z=a+bi, where:

a= real part

bi= imaginary number

b= imaginary part

i= [tex]\sqrt{-1}[/tex], therefore i²= -1

For solving this question, you should solve the product (-11 + 5i) * (1 – i). After that, you should compare the previous results with the result for expression ( (a + bi)* (2 + 3i) )-i. From this comparison, using the linear system you will find the variables a and b.

        (-11 + 5i) * (1 – i)=

        -11 +11i +5i -5i²

        -11 +16i -5i², as i²= -1 you can rewrite

        -11 +16i -5(-1)

        -11 +16i +5

         -6+16i

Then,

(-11 + 5i) * (1 – i)=  -6+16i

      ( (a + bi)* (2 + 3i) )-i

      (2a+3ai +2bi +3bi²) -i, as i²= -1 you can rewrite

      (2a+3ai +2bi +3b(-1)) -i

      (2a+3ai +2bi -3b) -i

     ( (2a-3b) + i(3a +2b) ) -i ,

For adding complex numbers, you must add or subtract the corresponding real and imaginary parts. Thus, you will have:

       (2a-3b) + i(3a +2b-1)

Then,

( (a + bi)* (2 + 3i) )-i=  (2a-3b) + i(3a +2b-1)

         For  (-11 + 5i) * (1 – i)=  -6+16i

                   real part = -6

                    imaginary part = 16

          For   ( (a + bi)* (2 + 3i) )-i=  (2a-3b) + i(3a +2b-1)

                   real part = 2a-3b

                    imaginary part = 3a +2b-1

                       2a-3b= -6

                       3a +2b-1=16, you can rewrite as 3a +2b=17.

Thus the system will be:

                             [tex]\begin{bmatrix}2a-3b=-6\\ 3a+2b=17\end{bmatrix}[/tex]

      2a-3b=-6    (1)

      3a+2b=17  (2)

     Multiplying equation 1 by 2 and equation 2 by 3, you can rewrite as:

      4a-6b= -12

      9a+6b=51  

    Sum the equations

     4a-6b+9a+6b= -12 +51

     13a= 39

        a=39/13=3

     Replacing the value of a=3 in equation 1, you can find b.

      2a-3b=-6    (1)

     2*3-3b= -6

     6 -3b = -6

        -3b = -6 -6

        -3b= -12

            b= -12/-3 = 4

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Answer:

42 in

Step-by-step explanation:

The lengths of the tangent segments drawn from an external point to a circle are equal.

AT and RT meet at point T

⇒ AT = RT = 9 in

RE and GE meet at point E

⇒ RE = GE = 5 in

AN and NG meet at point N

⇒ AN = GN = 7 in

Total perimeter = AT + RT + RE + GE + GN + AN

                          = 9 + 9 + 5 + 5 + 7 + 7

                          = 42 in

Hideki recognizes a $17,490.06 revenue.

Given that on January 1, 2022 Hideki Matsuyama provides services in exchange for a $10,000 zero-interest bearing note due in 4 years, and the effective interest rate for a note of this type is 15 percent, to determine how much revenue does Hideki recognize on January 1, 2022 the following calculation must be made:

Therefore, Hideki recognizes a $17,490.06 revenue.

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Answer:

Hideki recognizes a $17,490.06 revenue.

Step-by-step explanation:

Answer:

First space: 7

second space: 2

third space: -7

last space: -12

Step-by-step explanation:

To subtract, use "Add the opposite". In the problem the minus has aready been changed to adding, so you just change the second number (-7 in the first part or 7 in the second part) to their opposite sign. see image.

Answer:

-4

Step-by-step explanation:

y=2-9×(2/3)=2-6= -4