AABC Is dilated by a scale factor of 3 with the origin as the center of dilation to form AA' BC. The slope of AB is -1.2. The length of AB is
p units, the length of AC is qunits, and the length of BC is runits.
The slope of A' B' is The length of A'C' is
units.

Answers

Answer 1

Answer:

The slope of new figure A'B'C' = -1.2

A'B' = 3p units

A'C' = 3q units

Step-by-step explanation:

The value of each of the corresponding length of dilated figures (new image) = scale factor multiplied by the corresponding length in original figure.

scale factor = 3

Length of AB = p units

the length of AC = qunits

the length of BC = runits

A'B' = 3p units

A'C' = 3q units

B'C' = 3r units

slope of new figure = slope of previous figure

The slope remains the same = -1.2

Answer 2

The slope of the new figure is mathematically given as

dS=1.2

What is the slope of the new figure?

Question Parameter(s):

The slope of AB is -1.2.

The length of AB is punits

The length of AC is qunits

The length of BC is runits.

Generally, the lengths of the new region are mathematically given as

A'B' = 3p units

A'C' = 3q units

B'C' = 3r units

In conclusion, with the new region consistent in its increase across all regions the slope will remain

dS=1.2

Read more about Arithmetic

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Related Questions

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Answers

Answer:

[tex] \frac{(x + 5)(x + 2)}{ {x}^{3} - 9x } [/tex]

First option is the correct option.

Step-by-step explanation:

[tex] \frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 } [/tex]

Factor out X from the expression

[tex] \frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9} [/tex]

Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] , factor the expression

[tex] \frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)} [/tex]

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

[tex] \frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)} [/tex]

Multiply the parentheses

[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)} [/tex]

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)} [/tex]

Distribute -x through the parentheses

[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x }{x(x - 3)(x + 3)} [/tex]

Using [tex] {a}^{2} - {b}^{2} = (a + b)(a - b)[/tex] , simplify the product

[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)} [/tex]

Collect like terms

[tex] \frac{ {x}^{2} + 7x + 15 - 5}{x( {x}^{2} - 9)} [/tex]

Subtract the numbers

[tex] \frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)} [/tex]

Distribute x through the parentheses

[tex] \frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x} [/tex]

Write 7x as a sum

[tex] \frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x } [/tex]

Factor out X from the expression

[tex] \frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x} [/tex]

Factor out 2 from the expression

[tex] \frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x } [/tex]

Factor out x + 5 from the expression

[tex] \frac{(x + 5)(x + 2)}{ {x}^{3} - 9x } [/tex]

Hope this helps...

Best regards!!

The difference of the expression [tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex] is [tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]

The expression is given as:

[tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex]

Factorize the denominators

[tex]\frac{2x + 5}{x(x -3)} - \frac{3x + 5}{x(x^2 - 9)} - \frac{x + 1}{x^2 - 9}[/tex]

Apply the difference of two squares to the denominators

[tex]\frac{2x + 5}{x(x -3)} - \frac{3x + 5}{x(x - 3)(x + 3)} - \frac{x + 1}{(x - 3)(x + 3)}[/tex]

Take LCM

[tex]\frac{(2x + 5)(x + 3) - 3x - 5 -x(x + 1) }{x(x - 3)(x + 3)}[/tex]

Expand the numerator

[tex]\frac{2x^2 +6x + 5x + 15 - 3x - 5 -x^2 - x }{x(x - 3)(x + 3)}[/tex]

Collect like terms

[tex]\frac{2x^2 -x^2 - x +6x + 5x - 3x+ 15 - 5 }{x(x - 3)(x + 3)}[/tex]

Simplify

[tex]\frac{x^2+7x+ 10 }{x(x - 3)(x + 3)}[/tex]

Factorize the numerator

[tex]\frac{(x+5)(x+ 2) }{x(x - 3)(x + 3)}[/tex]

Expand the denominator

[tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]

Hence, the difference of the expression [tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex] is [tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]

Read more about equivalent expressions at:

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4. A number m is such that when it is divided by 30, 36, and 45 the remainder is always 7,
find the smallest possible value of m

Answers

Answer:

187

Step-by-step explanation:

A number m is such that when it is divided by 30, 36 and 45 the remainder is always 7.

We should first find the LCM of 30, 36 and 45

We get that the LCM of the three numbers is 280 (working attached).

So now;

[tex]\frac{180}{30}[/tex] = 6

[tex]\frac{180}{36}[/tex] = 5

[tex]\frac{180}{45}[/tex] = 4

But we need a number that leaves a remainder of 7 so we add 7 to 180 to get; 180 + 7 = 187.


Solve this linear equation for x: 7 + 4 (5/4x - 1) = 18

Answers

Answer:

x=3

Step-by-step explanation:

7+4(5/4x-1)=18

7+5x-4=18

3+5x=18

5x=15

x=3

Answer:

x = 3

Step-by-step explanation:

18 = 7 + 4([tex]\frac{5}{4}[/tex]x - 1)

18 = 7 + 5x - 4

18 = 3 + 5x

15 = 5x

x = 3

Quadrilateral ABCD is a kite. A kite. Angle A is 90 degrees, angle B is unknown, angle C is 130 degrees, angle D is unknown. What is the measure of angle B? degrees

Answers

Answer:

70 degrees

Step-by-step explanation:

(360 - 90 - 130)/2=70

The step function g(x) is defined as shown. g(x) = StartLayout Enlarged left-brace 1st row 1st column negative 3, 2nd column x less-than-or-equal-to 0 2nd row 1st column 2, 2nd column 0 less-than x less-than-or-equal-to 4 3rd row 1st column 5, 2nd column 4 less-than x less-than-or-equal-to 10 EndLayout

Answers

Answer:

{–3, 2, 5}

Step-by-step explanation:

The range refers to the values for the axis i.e to be dependent when there is a defined function

And the range is the combination of the integer i.e to be compounded by these three values  

Data provided in the question

-3 , x ≤ 0

2, 0 < x ≤ 4

5, 4 < x ≤ 10

Based on the above information, the range of g(x) is {-3,2,5}

Hence, the correct option is c.

Answer:

C

Step-by-step explanation:

Complete the equation: x2+10x+__=(__)^2 A. 25; x+5 B. 25; x−5 C. 10; x+10 D. 10; x−10

Answers

Answer:

Answer A)  25, and x+5

Step-by-step explanation:

You need to complete the square by adding a constant that makes the quadratic expression a perfect square of a binomial. So base your analysis on the fact that the coefficient accompanying the square term of x is one, and the fact that the middle term has coefficient 10 which is twice "5" so 5 is the likely candidate for the binomial that goes squared: (x + 5) and the square of 5 (25) is what you need to add as constant term to get the perfect square of a binomial:

[tex]x^2+10x+25=(x+5)^2[/tex]

Large samples of women and men are​ obtained, and the hemoglobin level is measured in each subject. Here is the​ 95% confidence interval for the difference between the two population​ means, where the measures from women correspond to population 1 and the measures from men correspond to population​ 2:

negative 1.76 g divided by dL less than mu 1 minus mu 2 less than minus 1.62 g divided by dL

−1.76 g/dL<μ1−μ2<−1.62 g/dL. Complete parts​ (a) through​ (c) below.

a. What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in​ men?

Answers

Answer:

a) Because the confidence interval  does not include  0​ it appears that there

is  a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men.

b)There is​ 95% confidence that the interval from  −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2

c)   1.62 < μ1−μ2< 1.76

Step-by-step explanation:

a) What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in​ men?

Given:

95% confidence interval for the difference between the two population​ means:

−1.76g/dL< μ1−μ2 < −1.62g/dL

population 1 =  measures from women

population 2 =  measures from men

Solution:

a)

The given confidence interval has upper and lower bound of 1-62 and -1.76. This confidence interval does not contain 0. This shows that the population means difference is not likely to be 0. Thus the confidence interval implies that the mean hemoglobin level in women and the mean hemoglobin level in​ men is not equal and that the  women are likely to have less hemoglobin than men. This depicts that there is significant difference between mean hemoglobin level in women and the mean hemoglobin level in​ men.

b)  

There is​ 95% confidence that the interval −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2.

c)

If we interchange men and women then

confidence interval range sign will become positive.μ1 becomes the population mean of the hemoglobin level in menμ2 becomes the population mean of the hemoglobin level in women So confidence interval becomes:

                                          1.62 g/dL<μ1−μ2<1.76 g/dL.

There is a significant difference between the mean level of hemoglobin in women and in men.

How to interpret the confidence interval

The confidence interval of the mean is given as:

[tex]-1.76 g/dL < \mu_1-\mu_2 < -1.62 g/dL[/tex]

The above confidence interval shows that the confidence interval is exclusive of 0.

This means that 0 is not part of the confidence interval

Since the confidence interval is exclusive of 0, then there is a significant difference between the mean level of hemoglobin in women and in men.

Read more about confidence intervals at:

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solve a+1= √b+1 for b

Answers

1. a+1=sqrt(b+1)
2. b+1=(a+1)^2
3. b=a^2+2a

So the third option is correct.

Answer: The Third one is correct

Step-by-step explanation:

Can someone help me ASAP???!!

Answers

Answer:

25x  ²−49y ²

Step-by-step explanation:

We need to find product of (5x+7)(5x−7y)

By using identity (a+b)(a−b)=a −b  ²

We have a=5x,b=7y

Thus (5x+7y)(5x−7y)=(5x)  ²−(7y)  

let me know if it was helpful

25x² - 49y²

Step-by-step explanation:

To Find:

The product of (5x - 7y)(5 x + 7)

How to solve:

Just need to use the formula of a² - b² = (a+b)(a-b)

let's assume a = 5x and b = 7x

Solution:

(5x - 7y)(5 x + 7) = (5x)² - (7y)²

= 25x² - 49y²

Hence required answer is 25x² - 49y².

Find the angle between the given vectors to the nearest tenth of a degree. u = , v = (2 points)

Answers

Answer:

3.6°

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the angle between the given vectors to the nearest tenth of a degree.

u = <8, 7>, v = <9, 7>

we will be using the formula below to calculate the angle between the two vectors;

[tex]u*v = |u||v| cos \theta[/tex]

[tex]\theta[/tex] is the angle between the two vectors.

u = 8i + 7j and v = 9i+7j

u*v = (8i + 7j )*(9i + 7j )

u*v = 8(9) + 7(7)

u*v = 72+49

u*v = 121

|u| = √8²+7²

|u| = √64+49

|u| = √113

|v| = √9²+7²

|v| = √81+49

|v| = √130

Substituting the values into the formula;

121= √113*√130 cos θ

cos θ = 121/121.20

cos θ = 0.998

θ = cos⁻¹0.998

θ = 3.6° (to nearest tenth)

Hence, the angle between the given vectors is 3.6°

A survey asks "would you like to see more or less government spending on natural disasters?" Of the 1496 respondents, 723 responded "more" or "much more". The population of interest consists of

A) the proportion of American adults who would respond "more" or "much more"

B) the 723 respondents who responded "more" or "much more"

C) the 1496 respondents

D) all American adults

E) the proportion of respondents who responded "more" or "much more"

Answers

Answer:

D) all American adults

Step-by-step explanation:

The 1496 respondents are the sample of the survey that was used to represent the population of interest, which is the total population from which the sample was drawn and the population from which the researchers want to find conclusions.

Looking at the alternatives, the only one that fits the description is alternative D) all American adults .

Any answers on this?

Answers

Answer:

40

Step-by-step explanation:

We're given an angle that forms a linear pair, and we're given an isosceles triangle. The angle to the right of 110 is 70, since they have to add up to 180. Since this is an isosceles triangle (denoted by the two dashes), we know that the other base angle has to be 70. 70 + 70 = 140; all angles add up to 180 so 180 - 140 = 40 degrees.

Answer:

40 degrees

Step-by-step explanation:

Since this is an isosceles triangle the 2 bottom angles are congruent

The bottom angles will be 70 degrees bc the exterior angle is 110 and 180-110=70

Because a triangle adds up to 180 degrees you need to use the equation 70 + 70 + x = 180 and you should get x = 40 degrees

Graph this compound inequality: 2.5 < x < 4.5
-5 4
-3
-2
-1 0
+ ++ +
1 2 3 4 5
o
Drag a point to the number line.

Answers

Answer:

Please find the attached the required inequality graph

Step-by-step explanation:

Given that inequality is 2.5 ≤ x ≤ 4.5, we have;

The region in the given inequality is the region between 2.5 and 4.5 inclusive

Therefore, to represent 2.5 ≤ x ≤ 4.5 on the number line, we have;

A closed circle (representing the less than or equal to inequality symbol, showing inclusiveness) at 2.5, another closed circle at 4.5 (representing the less than or equal to inequality symbol, showing inclusiveness) and the region between 4.5 and 2.5 shaded.

What is the perimeter of a triangle that has two sides measuring 7 centimeters and a third side measuring 9 centimeters?

Answers

The answer is 23cm just add the sides

The perimeter is the sum of all of the lengths of the sides. To find the perimeter, add together the length of each side.

For this triangle, our side lengths are 7, 7, and  9.

7 + 7 = 14

14 + 9 = 23

The perimeter of a triangle that has two sides measuring 7 centimeters and a third side measuring 9 centimeters is 23 centimeters.

Hope this helps!! :)


A shopkeeper sold an article at 20 % discount and made a loss of Rs 90. If he had
sold it at 5 % discount, he would have gained Rs 90. Find the cost price and the
marked price of the article.

Answers

Answer:

The cost price of the article is Rs 1050

The marked price of the article Rs 1200

Step-by-step explanation:

The given discount on the article = 20%

The amount loss  = Rs 90

With a discount of 5% the amount gained = Rs 90

Let the cost price of the article = X

Let the marked price of the article = Y

Therefore, we have;

(1 - 0.2) × Y = X - Rs 90

(1 - 0.5) × Y = X + Rs 90

Which gives;

0.8·Y = X - Rs 90 .......................(1)

0.95·Y = X + Rs 90.....................(2)

Subtracting equation (1) from equation (2), we have;

0.95·Y-0.8·Y = X + Rs 90 - (X - Rs 90) = X - X + Rs 90 + Rs 90 = Rs 180

0.15·Y = Rs 180

Y = Rs 180/0.15 = Rs 1200

Therefor, the marked price of the article = Rs 1200

From;

0.8·Y = X - Rs 90, we have;

0.8×Rs 1200 = X - Rs 90

X = 0.8× 1200 + 90 = Rs 1050

Therefore, the cost price of the article = Rs 1050.

A school has 6 3/4 kg of detergent in stock. During ' Use Your Hands ' campaign, each class will be given 3/8 kg of detergent. There are 28 classes in the school.
(a) What fraction of the school will be supplied with the detergent in stock?
(b) How much detergent will be required altogether for the whole school?
(c) How much more detergent does the school need to order?
(d) If the school gives out the detergent in stock to the 15 lower secondary classes first,
(i) how much detergent will be given out;
(ii) how much detergent in stock will be left?

Answers

Answer:

Step-by-step explanation:

Total stock available = 6 x 3/4 = 18/4

Detergent given to each class=3/8

Total number of classes in the school = 28

Total detergent required by the school=3/8*28

=42/4

a. Fraction if the school who will get the detergent=18/42

b. Total required detergent for the whole school= 42/4

c. School needs to order = 42/4 - 18/4  

= 24/4

= 6

d. i. Detergent given out to 15 classes = 15 x 3/8

= 45/8

ii. There will be no detergent left in stock

how many digits are in the decimal expansion of 2^34

Answers

Answer:

2^34 = 17179869184

I hope this helps :)

evaluate 1/2^-2x^-3y^5 for x=2 and y=-4

Answers

Answer:

[tex] - \frac{1}{32} [/tex]

Step-by-step explanation:

Given,

x = 2

y = - 4

Now, let's solve:

[tex] \frac{1}{ {2}^{ - 2} \: {x}^{ - 3} \: {y}^{5} } [/tex]

plug the values

[tex] \frac{1}{ {2}^{ - 2} \: {(2)}^{ - 3} \: {( - 4)}^{5} } [/tex]

A negative base raised to an odd power equals a negative

[tex] \frac{1}{ {2}^{ - 2} \times {2}^{ - 3} \times {( - 4}^{5}) } [/tex]

Determine the sign of the fraction

[tex] - \frac{1}{ {2}^{ - 2} \times {2}^{ - 3} \times {4}^{5} } [/tex]

Write the expression in exponential form with a base of 2

[tex] - \frac{1}{ {2}^{ - 2} \times {2}^{ - 3} \times {2}^{10} } [/tex]

Calculate the product

[tex] - \frac{1}{ {2}^{5} } [/tex]

Evaluate the power

[tex] - \frac{1}{32} [/tex]

Hope this helps...

Best regards!!

heLp would be appreciated for the image below :))

Answers

Answer:

A

Step-by-step explanation:

The line from the vertex to the base is a perpendicular bisector and divides the isosceles triangle into 2 right triangles.

Using Pythagoras' identity in either of the 2 right triangles, then

([tex]\frac{1}{2}[/tex] x )² + 3² = ([tex]\sqrt{45}[/tex] )²

[tex]\frac{1}{4}[/tex] x² + 9 = 45 ( subtract 9 from both sides )

[tex]\frac{1}{4}[/tex] x² = 36 ( multiply both sides by 4 to clear the fraction )

x² = 144 ( take the square root of both sides )

x = [tex]\sqrt{144}[/tex] = 12 → A

verify the trigonometric identity: tan(2π - x) = tan(-x)

Answers

Answer:

See Below

Step-by-step explanation:

Taking Right Hand Side to verify the identity:

tan ( 2π - x)

Resolving Parenthesis

tan 2π + tan (-x)

We know that tan 2π = 0

0 + tan (-x)

=> tan(-x) = Left Hand Side

Hence Proved

Answer:

[tex]\boxed{ \sf {view \: explanation}}[/tex]

Step-by-step explanation:

[tex]\Rightarrow \sf tan ( 2\pi - x)=tan(-x)[/tex]

[tex]\sf Apply \ distributive \ law.[/tex]

[tex]\Rightarrow \sf tan (2\pi) + tan (-x) =tan(-x)[/tex]

[tex]\sf Apply : tan(2\pi) =0[/tex]

[tex]\Rightarrow \sf 0 + tan (-x) =tan(-x)[/tex]

[tex]\Rightarrow \sf tan (-x) =tan(-x)[/tex]

[tex]\sf Hence \ verified.[/tex]

Solve for x. 3 1 2 140

Answers

Answer:

Hey there!

Angle QRS is 70, and since it is located on the circle, we have a useful formula. If 141x-1 is called y, then 70 is half of that.

Thus, we have 141x-1=140

141x=141

x=1

Hope this helps :)

Which of the following options could represent a possible set of interior angles of a triangle? 100°, 130°, and 130° 30°, 70°, and 80° 25°, 3°, and 35° 45°, 105°, and 120°

Answers

Answer:

2) 30, 70, 80

Step-by-step explanation:

Well there has to be 3 angles that all add up to 180°.

1)

100+130+130

=360

2)

30+70+80

= 180

3)

25+3+35

=63

4)

45 + 105 + 120

=150

150+120

270

A 10-sided die numbered 1 to 10 is rolled once. Find these probabilities.
A. Pr(8)
B. Pr(odd)
C. Pr(even)
D. Pr(less than 6)
E. Pr(prime) (remember that 1 is not prime)
F. Pr(3 or 8)
G. Pr(8, 9 or 10)
H. Pr(greater than 9)

^please explain what’s a “die” all I know was “dice” but dice is 6 sided yea?
^and please explain the answer... I’m international student so I still need some explanation for the questions and answers thank you

Answers

Answer:

A. Pr(8)   = 1/10

B.  Pr(odd)  = 1/2

C.  Pr(even)  = 1/2

D. Pr(less than 6)  = 1/2

E.  Pr(prime) = 2/5

F. Pr(3 or 8)  = 1 / 5

G. Pr(8, 9 or 10) = 3/10

H. Pr(greater than 9)  = P(10) = 1/10

Step-by-step explanation:

We assume a FAIR 10-faced die, meaning there is an equal probability of throwing any one of the ten numbers.

With 10 possible outcomes each with equal probability, the probability of throwing any number is 1/10.

(It is preferable to work with fractions in probability because fractions are exact numbers, while decimals can often be rounded, or truncated).

A. Pr(8)   means probability of throwing an 8,  therefore Pr(8) = 1/10

B. Pr(odd)  there are 5 odd number from 1 to 10, so Pr(odd) = 5/10 = 1/2

C. Pr(even)  there are 5 even number from 1 to 10, so Pr(even) = 5/10 = 1/2

D. Pr(less than 6)  there are 5 numbers less than 6 (between1 to 10),

       so Pr(less than 6) = 5/10 = 1/2

E. Pr(prime) (remember that 1 is not prime)

   A prime number is an integer not divisible by any number except one and itself.

   Between 1 to 10, the four prime numbers are 2,3,5,7

   therefore Pr(prime) = 4/10 = 2/5

F. Pr(3 or 8)  

(3 or 8) make 2 successful outcomes out of 10, so Pr(3 or 8) = 2/10 = 1 / 5

G. Pr(8, 9 or 10)

similarly, (8,9 or 10) make three successful possible outcomes out of 10, so

P(8,9 or 10) = 3/10

H. Pr(greater than 9)

there is only one successful outcome, namely "10" out of 10 possible outcomes.  So

P(greater than 9) = P(10) = 1/10

1. please explain what’s a “die” all I know was “dice” but dice is 6 sided yea?

A die is singular for dice, which can take up any number of faces.  With a 10-faced solid, we can make a 10-faced die numbered 1 to 10.

2. and please explain the answer... I’m international student so I still need some explanation for the questions and answers thank you

See solutions above.

Answer:

Remember that standard probabilities are defined as the ratio between the number of favorable cases, and the total number of possible events.

In this case, we have a 10-sided die, which means its faces are numbered from 1 to 10, which gives us 10 total number of possible events. In other words, the denominator of the ratio is going to be 10.

Now we're able to find each probability.

(A) Probability of getting an 8:

[tex]P_{8} =\frac{1}{10}=0.10[/tex]

The numerator is 1 because there's only one number 8 in the die, that means the number of favorable cases is 1, and, as we said before, the total number of possible events is 10.

(B) Probability of getting an odd number:

[tex]P_{odd} =\frac{5}{10}=0.5[/tex]

The numerator is 5 because there are 5 odd numbers from 1 to 10. In other words, there are 5 favorable cases to this probability.

(C) Probability of getting an even number:

[tex]P_{even}=\frac{5}{10}=0.5[/tex]

There are 5 even numbers from 1 to 10, that's why we had the same probability.

(D) Probability of getting a number less than 6:

We know that there are only 5 numbers less than 6 for this die.

[tex]P_{<6}=\frac{5}{10}=0.5[/tex]

(E) Probability of getting a prime number:

A prime number is such that it can be divided only by itself and the unit. So, there are four prime numbers from 1 to 10, which are 2, 3, 5, 7.

[tex]P_{prime}=\frac{4}{10}=0.4[/tex]

(F) Probability of getting 3 or 8:

When we are going to find the probability of an event "or" another, we must sum those favorable cases.

[tex]P_{3 \ or \ 8} =\frac{1+1}{10}=\frac{2}{10}=0.2[/tex]

(G) Probability of getting 8, 9, or 10:

In this case, we need to some all three favorable cases. The die has only one 8, one 9 and one 10. So, the probability is

[tex]P_{8,9,10}=\frac{1+1+1}{10}=\frac{3}{10} =0.3[/tex]

(H) Probability of getting a number greater than 9:

We know that there's only one number greater than 10 on such die.

[tex]P_{>10}=\frac{1}{10}=0.1[/tex]

Lastly, "die" refers to this special 10-sided dice. In other problems, you can find "a die" with more faces even. But, in general, "die" refers to a dice.

Translate into an algebraic expression and simplify if possible. C It would take Maya x minutes to rake the leaves and Carla y minutes, what portion of the leaves do they rake in one minute if they work together?

Answers

Answer:

in one minute they rake [tex]\frac{y+x}{xy}[/tex] leaves working together.

Step-by-step explanation:

If Maya rakes the leaves in x minutes, then, in one minute she rakes [tex]\frac{1}{x}[/tex] leaves.

In the case of Carla, if she rakes the leaves in y minutes, in one minute she rakes [tex]\frac{1}{y}[/tex] leaves.

Therefore, to know the portion of leaves they can rake in one minute working together, we need to sum up both of the portions each one of them rake in one minute, this gives us: [tex]\frac{1}{x}+ \frac{1}{y}[/tex]

Now, to simplify this expression:

[tex]\frac{1}{x}+ \frac{1}{y} =\frac{y+x}{xy}[/tex]

Thus, in one minute they rake [tex]\frac{y+x}{xy}[/tex] leaves.

Solve the following equation for x .​ ​ 9=x2+2 ​ ​

Answers

Answer:

X=3.5

Step-by-step explanation:

9=x2+2

9-2=x2

(9-2)÷2=x

In a school, half of the 300 students saw Zootopia, 180 students saw Finding Dory, and 45 students did not see either movie. How many students saw both movies?

Answers

Answer:

150

Step-by-step explanation:

Answer:

150  =  half of 300

± 180

230

soooo 230 students

Step-by-step explanation:

please Evaluate 27 times ( 1/3) to the 3 power. A). 1 B). 3 C). 9 D). 27

Answers

Answer:

you want to follow PEMDAS so you would multiply 27 by 1/3 to get 81.003, which you would round to 81, then you would multiply 8 to the third power and you would get 512.

Step-by-step explanation:

27(1/3)^3

81^3

512

In an examination 1/3 of the total student used unfair means and out of which 1/4 caught red handed while cheating. If 5 student caught red handed then find the total number of student appeared in exam

Answers

Answer:

total number of students =60

Step-by-step explanation:

total number of students 60

used unfair means 1/3= 20

1/4 caught red handed 1/4 of 20= 5

I believe this is pretty easy but it's: solve for x using common denominators 3/4(x+2)=x/(x+3) Answer choices below:

Answers

Answer:

x = [tex]\frac{3}{4}[/tex]

Step-by-step explanation:

Given

[tex]\frac{3}{4(x+2)}[/tex] = [tex]\frac{x}{x+2}[/tex]

multiply numerator/ denominator of [tex]\frac{x}{x+2}[/tex] by 4, thus

[tex]\frac{3}{4(x+2)}[/tex] = [tex]\frac{4x}{4(x+2)}[/tex]

Since the denominators are common , equate the numerators, that is

4x = 3 ( divide both sides by 4 )

x = [tex]\frac{3}{4}[/tex]

hurry please!! The equation cos35°=a/25. What is the length of the line BC? Round to the nearest 10th

Answers

Answer:

25 is the same lenghth rounded

Step-by-step explanation:

aproximitly it rounded to the 10

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