According to Inc, 79% of job seekers used social media in their job search in 2018. Many believe this number is inflated by the proportion of 22- to 30-year-old job seekers who use social media in their job search. Suppose a survey of 22- to 30-year-old job seekers showed that 308 of the 370 respondents use social media in their job search. In addition, 281 of the 370 respondents indicated they have electronically submitted a resume to an employer.
A) Conduct a hypothesis test to determine if the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that use social media in their job search. Use α = 0.05.
1) State the null and alternative hypothesis.
2) Find the value of the test statistic.
3) Find the p-value.
B) Conduct a hypothesis test to determine if the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer. Using α = 0.05, what is your conclusion?
1) State the null and alternative hypothesis.
2) Find the value of the test statistic.
3) Find the p-value.

Answer:I think it’s 1/5 but if u have another attemp and it’s wrong somehow do 1/3

Step-by-step explanation:

Answer:

3/4 or 1/3

Step-by-step explanation:

Answer:

n=-18

Step-by-step explanation:

subtract 8 from both sides.

then you do -10 subtracted by 8 and thats -18.

Answer:

its the second one bc if u multiply 8.34 times 5305 it equals to 44243.7 the diameter of the pool was jus to throw u off it was unneeded information.

Step-by-step explanation:

the answer is -4 and 3

hope that helped

Answer:

Radius: 3.5

Diameter: 7

i might be wrong tho im sorry !!

The answer:

Radius = 3.5cm

Diameter = 7cm

Answer:

25 7 x 5 is 35

Step-by-step explanation:

hope this helps have a good rest of your afternoon :) ❤

Answer:

5 times 5 is 25.

Step-by-step explanation:

Hope this helps you dude

s h r e k (in a maid outfit)

Answer:

59 or infant

Step-by-step explanation:

she will either live to be 59 each time or she will live to be a undying God like being

Answer:

Hello your question is poorly written below is the complete question

An actuary has discovered that policyholders are three times as likely to file two claims as to file four claims. If The number of claims filed has a Poisson distribution. Compute the variance of the number of claims filed. You can use, without a proof, what is the variance of a Poisson distribution is equal to its mean

answer : variance = 2

Step-by-step explanation:

compute the variance of the number of claims filed

x = number of claim filed

For Poisson distribution

mean = variance = Л

∴ Variance = 2

Answer:

9040

10215.20

Step-by-step explanation:

compound interest that compounds yearly works as follows

PV(1+i)^n

just plug in the numbers

8000(1.13)^1= 9040

8000(1.13)^2=10215.20

Answer:

he is the answer

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

(x−1)(x−2)

Step-by-step explanation:

Answer:

b= -15

Step-by-step explanation:

First combine like terms 9-16= -7

Left 3b-7= -52

Next add 7 to both sides

Left 3b= -45

Finally divide

So b= -15

Answer:

3

Step-by-step explanation:

30 + 18 = 48

5 + 3 = 8, 6 x 8 = 48

If this was helpful vote brainliest :)

Answer:

286 minutes

Step-by-step explanation:

can you give brainlest or good review

Answer:

Hello!

Let's call X to the number of minutes of long-distance calls you plan to make.

The cost of plan A is given by 25%2B0.05X

The cost of plan B is given by 5%2B0.12X

Plan B is advantageous when its cost is lower than plan A's. Therefore, we set the inequality

5%2B0.12X+%3C+25%2B0.05X

And then solve for X. This will give us the range of minutes for which B is more convenient.

Subtract 5 from both sides of the inequality to get:

0.12X+%3C+20%2B0.05X

Now subtract 0.05X:

0.12X+-+0.05X+%3C+20

0.07X%3C20

Finally, divide by 0.07 to get:

X+%3C+20%2F0.07

X++%3C+285.71

So plan B is advantageous if you plan to use less than 286 minutes of long distance calls.

I hope this helps!

Step-by-step explanation:

Answer:

34.5

Step-by-step explanation:

Given the data:

X : 18; 18; 21; 22; 25; 26; 27; 29; 30; 31; 31; 33; 36; 37; 37; 41; 42; 47; 52; 55; 57; 58; 62; 64; 67; 69; 71; 72; 73; 74; 76; 77.

The 37th Percentile :

37/100(n + 1)th term

n = sample size = 32

Therefore,

0.37(32 + 1)th term

0.37(33)th term = 12.21 th term

(12th + 13th) term ÷ 2

(33 + 36) / 2

69 / 2

34.5

The 37th percentile is 34.5

Answer:

The answer is below

Step-by-step explanation:

El número de personas que vieron solo A = n (A) = 17

El número de personas que vieron solo B = n (B) = 17

El número de personas que vieron solo C = n (C) = 23

El número de personas que vieron A y B = n (A ∩ B) = 6

El número de personas que vieron A y C = n (A ∩ C) = 8

El número de personas que vieron B y C = n (B ∩ C) = 10

El número de personas que vieron las tres películas = n (A ∩ B ∩ C) = 2

1) Número de estudiantes que han visto dos películas = n (A ∩ B) + n (A ∩ C) + n (B ∩ C) = 6 + 8 + 10 = 24

2)

n (A∩ B '∩ C') = n (A) -n (A ∩ B) -n (A ∩ C) -n (A ∩ B ∩ C) = 17-8-6-2 = 1

n (A'∩ B ∩ C ') = n (B) -n (A ∩ B) -n (B ∩ C) -n (A ∩ B ∩ C) = 17-6-10-2 = 1

n (A'∩ B '∩ C) = norte (C) -n (UNA ∩ C) -n (B ∩ C) -n (UNA ∩ B ∩ C) = 23-8-10-2 = 3

estudiantes que no han visto = 55 - n (A∩ B '∩ C') -n (A'∩ B ∩ C ') - n (A'∩ B ∩ C') - n (A ∩ B) -n ( B ∩ C) -n (UNA ∩ C) -n (A∩ B ∩ C) = 55-1-1-3-6-8-10-2 = 24

3)

número de alumnos que no han visto =

4)

número de estudiantes que vieron solo A = n (A∩ B '∩ C') = 1

Answer and Step-by-step explanation: This function is a probability density function of a random variable X:

[tex]f(x)=\frac{3(8x-x^{2})}{256}[/tex]

and to calculate probabilities, we will have to integrate it:

[tex]P(X<x)=\int\limits^x_0 {\frac{3}{256}(8x-x^{2}) } \, dx[/tex]

Solving:

[tex]P(X<x)=\frac{3}{256}(4x^{2}-\frac{x^{3}}{3} )[/tex]

Then:

a. P(X < 5)

[tex]P(X<5)=\int\limits^5_0 {\frac{3}{256}(8x-x^{2}) } \, dx[/tex]

[tex]P(X<5)=\frac{3}{256}(100-\frac{125}{3} )[/tex]

[tex]P(X<5)=\frac{3}{256}(\frac{300-125}{3} )[/tex]

[tex]P(X<5)=\frac{175}{256}[/tex]

P(X < 5) = 0.683

b. P(X < 9)

Since density function's upper limit is 8, probability of x < 9 is 100% or 1.

So, P(X < 9) = 1

c. P(5 < X < 7)

[tex]P(5<X<7)=\int\limits^7_5 {\frac{3}{256}(8x-x^{2}) } \, dx[/tex]

[tex]P(5<X<7)=\frac{3}{256}[4(7)^{2}-\frac{7^{3}}{3}-4(5)^{2}+\frac{5^{3}}{3}][/tex]

[tex]P(5<X<7)=\frac{3}{256}[96-\frac{218}{3} ][/tex]

[tex]P(5<X<7)=\frac{70}{256}[/tex]

P(5 < X < 7) = 0.273

d. P(X > 3)

[tex]P(X>3)=\int\limits^8_3 {\frac{3}{256}(8x-x^{2}) } \, dx[/tex]

[tex]P(X>3)=\frac{3}{256}[256-\frac{512}{3}-36+9 ][/tex]

[tex]P(X>3)=\frac{3}{256}(229-\frac{512}{3} )[/tex]

[tex]P(X>3)=\frac{175}{256}[/tex]

P (X > 3) = 0.683

e. P(X < x) = 0.95

[tex]0.95=\int\limits^x_0 {\frac{3}{256}(8x-x^{2}) } \, dx[/tex]

[tex]\frac{3}{256}[\frac{12x^{2}-x^{3}}{3} ] =0.95[/tex]

[tex]\frac{12x^{2}-x^{3}}{256}=0.95[/tex]

[tex]12x^{2}-x^{3}=243.2[/tex]

[tex]-x^{3}+12x^{2}-243.2=0[/tex]

Solving this cubic equation, we have three values for x:

x₁ = -3.909

x₂ = 8.992

x₃ = 6.917

The value of x will the one between 0 and 8, which are the limits of the function. So, value of x which gives a probability of 0.95 is x = 6.917.

Answer:

Should be $11.25

Step-by-step explanation:

Since 25% is 1/4 you can just divide 45 by 4.

45/4 = 11.25

Answer: 33.75. 25% of 45 is 11.25. So 45-11.25=33.75

Step-by-step explanation:

Answer:

5/1

Step-by-step explanation:

Answer:

5/1

Step-by-step explanation:

Answer:

X = log(0.96)(0.85)

Step-by-step explanation:

Given that on an island, the deer population has been decreasing by 4% per year and the current population is 792 deer, assuming that the deer population continues to decrease by 4% per year, to determine the number of years it will take for the deer population to decrease from 792 deer to 674 deer the following calculation must be performed:

792 x 0.96 ^ X = 674

X = 3.95

So, rounded to whole numbers, it will take 4 years for the deer population to drop to 674.

Answer:

divide the numerator by the denomantor

Step-by-step explanation:

A fraction in which the numerator is smaller than the denominator, like 1/3 or 2/5 is called a proper fraction. A fraction in which the numerator is larger than or equal to the denominator, like 5/2, 17/3, or 6/6 is called an improper fraction. (To put it another way, a fraction with a value less than 1 is a proper fraction. A fraction with a value greater than or equal to 1 is an improper fraction.)

As we have shown above, mixed numbers can be written as improper fractions. Similarly, improper fractions can be written as mixed numbers.

Answer:

[tex]Mean = 68.9[/tex]

[tex]s^2 =18.1[/tex] --- Variance

Step-by-step explanation:

Given

[tex]\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}[/tex]

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

[tex]x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5[/tex]

For 59 - 66

[tex]x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5[/tex]

For 67 - 74

[tex]x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5[/tex]

For 75 - 82

[tex]x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5[/tex]

For 83 - 90

[tex]x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5[/tex]

So, the table becomes:

[tex]\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}[/tex]

The mean is then calculated as:

[tex]Mean = \frac{\sum fx}{\sum f}[/tex]

[tex]Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}[/tex]

[tex]Mean = \frac{2547.5}{37}[/tex]

[tex]Mean = 68.9[/tex] -- approximated

Solving (b): The sample variance:

This is calculated as:

[tex]s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}[/tex]

So, we have:

[tex]s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}[/tex]

[tex]s^2 =\frac{652.8}{36}[/tex]

[tex]s^2 =18.1[/tex] -- approximated

Answer:

it's 3.4

Step-by-step explanation:

hope this helps have a nice day