Answer:
true
Explanation:
please answer asap!
What is the molarity of a KOH solution if 200 ml of the solution contains 0.6 moles KOH?
a. 0.3 M
b. 0.6 M
c. 3.0 M
d. 6.0 M
Identify the reaction type of the chemical reaction below. Check all that apply.
Mg (s)+2 HCl (aq) MgCl 2 (aq)+H 2 (g)
Answer:
The type of reaction is a single-replacement reaction.
Explanation:
Mg switches places with H, leaving H by itself.
What's a house hold item that has nuclear energy
Answer:
Electricity, Weapons, Medicine · Food Treatments, ect.
2. A plant growing in response to the sunlight.
A.Gravitropism
B.Phototropism
C.Thigmotropism
D.Hydrotropism
Answer:
phototropism
Explanation:
since photo is (light?
select two correct answers
Answer:
D and E
Explanation:
The other answers don't support steel, they support iron or are supporting both, and the question is why steel alloys are more often used
C supports both
B supports how iron's strength
A supports iron being easily shaped and bent
hope this helps
Express each of the following answers in the IUPAC format. Do not include any capitals or spaces in your name. Separate multiple substituent numbers using a comma. Use a hyphen between numbers and names. (ex: 1,2-dichloro-3-methylcyclopentane). Part A Spell out the full name of the molecule. Part B Spell out the full name of the molecule. Part C Spell out the full name of the molecule. Part D Spell out the full name of the molecule.
The full question is shown in the image attached
Answer:
See explanation
Explanation:
In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.
When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;
1. 2-methyl propane
2. 2,4-dimethyl heptane
3. 2,2,3,3-tetramethyl butane
4. 5-ethyl-2,4-dimethyl octane
How many grams of CuSO4 are required to make a 5.0 ml solution that has a concentration of 400 mg/ml?
Answer: molecular weight of CUSO4 or grams. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CUSO4, or 346.10221 grams. Note that rounding errors may occur, so always check the results.
Explanation:
In another experiment, the student titrated 50.0 mL of 0.100 M HC,H,O, with
0.100 M NaOH(aq). Calculate the pH of the solution at the equivalence point
Answer:
Eqv Pt pH = 8.73
Explanation:
HOAc + NaOH => NaOAc + H₂O
50ml(0.10M HOAc) + 50ml(0.10M NaOH) => 100ml(0.05M NaOAc) + H₂O
For neutralized system, 100ml of 0.05M NaOAc remains
NaOAc => Na⁺ + OAc⁻
Na⁺ + H₂O => No Rxn
OAc⁻ + H₂O => HOAc + OH⁻
C(i) 0.05M ----- 0M 0M
ΔC -x ----- +x +x
C(f) 0.05-x
≅ 0.05M ----- x x
Kb = Kw/Ka = [HOAc][OH⁻]/[OAc⁻] = 1 X 10⁻¹⁴/1.7 X 10⁻⁵ = (x)(x)/(0.05M)
=> x = [OH⁻] = SqrRt(0.05 x 10⁻¹⁴/1.7 x 10⁻⁵) = 5.42 x 10⁻⁶M
=> pOH = -log[OH⁻] = -log(5.42 x 10⁻⁶) = 5.27
pH + pOH = 14 => pH = 14 - pOH = 14 - 5.27 = 8.73 Eqv Pt pH
A 1.4639-g sample of limestone is analyzed for Fe, Ca, and Mg. The iron is determined as Fe2O3 yielding 0.0357 g. Calcium is isolated as CaSO4, yielding a precipitate of 1.4058 g, and Mg is isolated as 0.0672 g of Mg2P2O7. Report the amount of Fe, Ca, and Mg in the limestone sample as %w/w Fe2O3, %w/w CaO, and %w/w MgO
Answer:
A) w/w % of Fe - 2.44%
B) w/w % of Mg - 4.590%
C) w/w % of Ca - 96%
Explanation:
A) w/w % of Fe in limestone as Fe2O3 = (Mass of Fe2O3 /Mass of limestone) x 100
0.0357/1.4639 X 100
= 2.438 =2.44
B) w/w % of Mg in limestone as Mg2P2O7 = (Mass of Mg2P2O7 /Mass of limestone) x 100
= 0.0672/1.4639 X 100
= 4.590
C) w/w % of Ca in limestone as CaSO4 = (Mass of CaSO4/Mass of limestone) x 100
= 1.4058/1.4639 X 100
= 96
Answer:Fe =1.71% Ma=0.99% Ca=28.24%
Explanation:
If I have 7.0 x 10^24 formula units of magnesium chloride, how many grams of chlorine would I have?
Answer:
824 g
Explanation:
First we convert 7.0 x 10²⁴ formula units of magnesium chloride (MgCl₂) into moles, using Avogadro's number:
7.0 x 10²⁴ formula units ÷ 6.023x10²³ formula units/mol = 11.62 mol MgCl₂There are two Cl moles per MgCl₂ moles, meaning that we have (2 * 11.62) 23.24 moles of Cl
Finally we convert 23.24 moles of chlorine into grams, using chlorine's molar mass:
23.24 mol * 35.45 g/mol = 824 gWhich of the statements below about an acid-base buffer solution is/are true?
I. It can be prepared by combining a strong acid with a salt of its conjugate base.
II. It can be prepared by combining a weak acid with a salt of its conjugate base.
III. It can be prepared by combining a weak base with its conjugate acid.
IV. The pH of a buffer solution does not change when the solution is diluted.
V. A buffer solution resists changes in its pH when an acid or base is added to it.
A. I, II, and IV.
B. II, III, and V.
C. II, III, IV, and V.
D. I, II, IV, and V.
E. II, III, and IV.
Answer:
C. II, III, IV, and V.
Explanation:
Acid buffer is generally formed by the combination of a weak acid as well as the salt of the conjugate base.
Basic buffer is formed the combination of a weak base and also the salt of the conjugate acid.
On dilution the ration of the concentration terms of the salt and weak acid/base does not change. Hence the pH of the buffer solution does not change.
When acid or base is added to buffer, it resists changes in the pH.
Therefore, option (C) is correct.
Only animals and not plants can adapt to their environment true or false
Answer:
true
Explanation:
np have a good day brainliest?
What is the molarity of a 9.79 L solution that contains 0.400 mol HCI
Answer:
0.041 MExplanation:
The molarity of a solution when given the number of moles the substance and it's volume can be found by using the formula
[tex]c = \frac{n}{v} \\ [/tex]
n is the number of moles
v is the volume in L
We have
[tex]c = \frac{0.4}{9.79} \\ = 0.04058...[/tex]
We have the final answer as
0.041 MHope this helps you
Express your answer as a balanced half-reaction. Identify all of the phases in your answer.
(acidic) Cr2O7 2−(aq)⟶Cr 3+(aq)
(acidic) CrO4 2−(aq)⟶Cr(OH)4 −(aq)
(acidic) Bi 3+(aq)⟶BiO3 −(aq)
(acidic) CIO −(aq)⟶Cl −(aq)
(^for CIO - that is an i not an L)
Answer:
1. Cr₂O₇²−(aq) + 14H+ (aq) + 6e- ---->⟶2 Cr³+(aq) + 7H₂O (l)
2. CrO₄²− (aq)⟶+ 4H+ (aq) + 3e- ---> Cr(OH)₄ −(aq)
3. Bi³+ (aq) + 3H₂O (l) ---> BiO₃− (aq) + 6 H+ (aq) + 2 e-
4. CIO −(aq)⟶+ 2H+ (aq) + 2e- ---> Cl −(aq) + H₂O
Explanation:
The given equations are redox reaction equations expressed as as half reactions.
The first step is to identify whether the half-reaction is oxidation reduction.
Then the number of electrons gained or lost are added on the right side of the equation.
Appropriate H+ ions and water molecules are added where necessary since the reaction takes place in acidic environment
The atoms of elements involved in the reaction are balanced by adding the correct coefficients.
1. (acidic) Cr2O7 2−(aq)⟶Cr 3+(aq)
The half-reaction is reduction as the oxidation number of chromium changes from +6 to +3. Two Cr⁶+ ions accepts 3 electrons each to form Cr³+ ions
Cr₂O₇²−(aq) + 6e- ---->⟶2 Cr³+(aq)
Cr₂O₇²−(aq) + 14H+ (aq) + 6e- ---->⟶2 Cr³+(aq) + 7H₂O (l)
2. (acidic) CrO₄²− (aq)⟶---> Cr(OH)₄ −(aq)
The half-reaction is a reduction. One Cr⁶+ accepts 3 electrons to become Cr³+
CrO₄²− (aq)⟶+ 3e- ---> Cr(OH)₄ −(aq)
CrO₄²− (aq)⟶+ 4H+ (aq) + 3e- ---> Cr(OH)₄ −(aq)
3, (acidic) Bi³+ (aq)⟶---> BiO₃− (aq)
The half-reaction is an oxidation. One Bi³+ ion gives up two electrons to become Bi⁵+
Bi³+ (aq)⟶---> BiO₃− (aq) + 2e-
Bi³+ (aq) + 3H₂O (l) ---> BiO₃− (aq) + 6 H+ (aq) + 2 e-
4. (acidic) CIO −(aq)⟶---> Cl −(aq)
The half-reaction is a reduction. One Cl+ ion accepts two electrons to become Cl- ion.
CIO −(aq) + 2e-⟶---> Cl −(aq)
CIO −(aq)⟶+ 2H+ (aq) + 2e- ---> Cl −(aq) + H₂O
Try moving an electron from the metal to the non metal.What happens?
Answer:
Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.
Explanation:
How many grams of hydroxide pellets, NaOh are required to prepare 50.0ml of a 0.150 M solution ?
A.0.300g
B.3.00g
C.2.00g
D.200.g
E. 0.025 M
Identify the Lewis base in this balanced equation: 6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus. H2O Cr3+ Cr(H2O)63+
The Lewis base that we can see in the equation is [tex]H_{2} O[/tex]
What is the Lewis base?We have to bear in mind that the Lewis base is the substance that is able to donate a pair of electrons. The substances that is able to accept the pair of electrons is what we call the Lewis acid.
The Lewis acid must possess a space for the addition of an electron pair while the Lewis base would have to be a specie that has a lone pair of electrons or has a negative charge. Thus the water molecule would serve as a Lewis base in this regard.
Learn more about Lewis base;https://brainly.com/question/15570523
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Answer:
6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus.
✔ H2O or A.)
Cr3+
Cr(H2O)63+
If the number of moles of a gas doubles, its volume will also double
according to
*
Please hurry! What is the answer to this?
Explanation:
Boyle's Law
A mixture of water and water vapor is present in a closed vessel at 20 degrees Celsius. the total pressure of the system is 755.0 mmHg. Partial pressure of water vapor at 20 degrees Celsius equals 17.5 mm Hg. What is the partial pressure of H2
Answer:
737.5 mmHg
Explanation:
Ptotal=PH2O+PH2
P is the pressure and since we have Ptotal and PH2O, we can solve for PH2
755=17.5+x
755-17.5=x
x=737.5
A chemist titrates 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid. How many mL of NaOH will be required to titrate to the endpoint
[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]
0.15N × 50mL = 0.2N × (Vbase)
75mL = Volum of base
37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.
How to calculate volume?The volume of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
C1 = initial concentrationC2 = final concentrationV1 = initial volumeV2 = final volumeC1 = 0.200MC2 = 0.150MV1 = ?V2 = 50mL0.2 × V1 = 0.150 × 50
0.2V1 = 7.5
V1 = 7.5/0.2
V1 = 37.5mL
Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.
Learn more about volume at: https://brainly.com/question/26416088
Helen is studying the properties of solids. She is comparing the wooden cube and the steel cube shown in the picture below.
mc065-1
Which property is the same for the two cubes?
color
luster
texture
volume
the experimental control is the ?
A. Dependent variable
B. Design of the experiment.
C. Outcome of the experiment
D. the standard against which the results are measured .
Answer:
D. In an experiment, one of the variables will be giving a placebo and the other, a treatment
Explanation:
Photosynthesis, the process by which green plants and certain other organisms transform light energy into chemical energy. During photosynthesis in green plants, light energy is captured and used to convert water, carbon dioxide, and minerals into oxygen and energy-rich organic compounds.
Because a water molecule has a negative end and a positive end it displays?
Answer:
A water molecule displays polarity by having negative and positive ends. Due to this charge difference, a water molecule is called a dipole.
Explanation:
What is the fundamental different between combustion and nuclear reaction
Answer:
Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclear.
3. Convert the word equations below to symbolic:
Sodium + chlorine sodium chloride
• Calcium + bromine ---- calcium bromide
• Potassium + water → potassium hydroxide + hydrogen
ot
Answer:
1)2Na + Cl2 ----> 2NaCl
2)Ca + Br2 ---->CaBr2
3)K + H2O -----> KOH + H2
I will mark brainliest
What kind of weather forms with an occluded front?
Answer:Occluded fronts usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.
Explanation:
Calculate the pH of a solution with [H+] = 1.8 x 10^-5 M
Answer:
4.74
Explanation:
pH= -log[H+]
pH= -log(1.8 x 10^-5)= 4.74
How many moles of OH−(aq) (hydroxide ions)are present in the balanced redox reaction?
NO3−(aq) + ClO−(aq) + H2O(l) → NO(g) + ClO2−(aq) + OH−(aq)
Draw a structural formula for the organic product formed by treating butanal with the following reagent: NaBH4 in CH3OH/H2O You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Do not include lone pairs in your answer. They will not be considered in the grading. Include counter-ions, e.g., Na , I-, in your submission, but draw them in their own separate sketcher. Do not draw organic or inorganic by-products.
Answer:
Please find the solution in the attachment file.
Explanation:
Help (also tell me what the phenotype and genotypes are)
Answer:
genotype are the organism's hereditary information for example DNA
phenotype are the organism's physical characteristics for example your eyes or hair
or how your nose looks