Answer:
B
Step-by-step explanation:
The answer is B because when you simplify it you get -3x + 10 = 0. Since this is no longer a quadratic equation, you can't solve it using the quadratic formula.
Answer:
B
Step-by-step explanation:
5x^2 -3x+10 = 5x^2
Subtracting 5x^2 from each side
5x^2-5x^2 -3x+10 = 5x^2-5x^2
-3x+10 =0
We cannot use the quadratic formula since a =0
A baseball team plays in a stadium that holds 50000 spectators. When the ticket price is $10, the average attendance is 27000. When the price is lowered to $6, the average attendance rose to 39000. Find a demand function, D(q), where q is the quantity or number of spectators and D(q) is linear.
Answer:
the answer is below
Step-by-step explanation:
Demand seems to be based on price.
Therefore we must consider two things:
that "x" is equal to the price and that "y" is equal to the average attendance.
Thus:
the two points would be:
(x1, y1) = (10,27000)
(x2, y2) = (6.39000)
The slope of a straight line is given by:
m = (y2-y1) / (x2-x1)
we replace:
m = (39000 - 27000) / (6 - 10) = 12000 / -4 = -3000
The equation of a straight line can be expressed like this
y = m * x + b.
where
m is the slope and b is the y-intercept.
we replace
y = -3000 * x + b.
To solve for b, replace x and y with the value of one of the points on the line.
We choose (6.39000). and we replace:
39000 = -3000 * 6 + b
39000 = -18000 + b
39000 + 18000 = b
b = 57000.
if we replace we have:
the equation becomes y = -3000 * x + 57000
since it is the demand and * x is the price.
t = d (x), therefore the equation becomes
d (x) = -3000 * x + 57000.
d (x) = 57000 - 3000 * x.
when x = 0, the price is 0 and the demand will be 57000, which will be more than the stadium can contain because the stadium can only contain 50,000.
So:
when x = 6, the price is 6 and the demand is 57000 - 18000 = 39000.
when x = 10, the price is 10 and the demand is 57000 - 30000 = 27000.
These are Helen’s top three financial goals: create an emergency fund, save for a new guitar, and invest in her company’s stock. Select one attribute that matches each goal. Goal Attribute Create an emergency fund by next fall. specific, timely Save $50 per month to purchase a new guitar. timely, measurable Invest $130 in company stock. specific, timely
Answer:
1. timely
2. measurable
3. specific
Step-by-step explanation:
Josie ran a lap in 45.23 seconds.
Erica ran a lap in 43.11 seconds. How
much longer did it take Josie to rut
the lap?
Answer: 2.12 seconds
Step-by-step explanation:
From the question, we are informed that Josie ran a lap in 45.23 seconds while Erica ran a lap in 43.11 seconds.
To calculate the extra amount of time it took Josie to complete the lap, we subtract Erica's time from Josie's time. This will be:
= 45.23 seconds - 43.11 seconds
= 2.12 seconds
the density of ethanol is 1.09g/cm^3 the density of propylene is 0.97g/cm^3 80 litres of ethanol are mixed with 148 litres of propylene to make 228 litres of antifreeze work out the density of the antifreeze in g/cm^3
Answer:
The density of the final mixture is 1.012 g/cm³.
Step-by-step explanation:
To calculate the density of the final mixture we need to know the mass of each solution used is. We will also need to convert the volumes from litres to cm³, to do that we can just multiply 1000.
For the ethanol:
[tex]mass = volume*density\\mass = (80*1000)*1.09 = 87,200 \text{ g}\\[/tex]
For the propylene:
[tex]mass = (148*1000)*0.97 = 143,560 \text{ g}[/tex]
So the mass in the final mix is the sum of both:
[tex]mass_{final} = 87200 + 143560 = 230,760 \text{ g}[/tex]
Therefore the density is:
[tex]density_{final} = \frac{230760}{228000} = 1.012 \text{ }\frac{g}{cm^3}[/tex]
The density of the antifreeze is 1.01 g/cm³
Equations are used to show the relationship between two or more numbers and variables.
Let x represent the density of the antifreeze in g/cm^3.
1 cm³ = 0.001 L
80 L = 80000 cm³; 148 L = 148000 cm³, 228 L = 228000 cm³
Hence:
(1.09 * 80000) + (0.97 * 148000) = x * 228000
228000x = 230760
x = 1.01 g/cm³
The density of the antifreeze is 1.01 g/cm³
Find out more at: https://brainly.com/question/21667661
Find the area in square centimeters of the composite shape shown below. Enter only a number as your answer.
Answer:
136 cm^2
Step-by-step explanation:
you can divide the shape into two shapes:
first : draw a line ⊥ to BC from point E to point F
rectangle : DCEF : Area = L*W=7*13=91 cm^2
the other shape AEBF is a trapezoid:
Area of AEBF= [(a+b)/2] h where a and b are the base and h is the height
height =18-13=5
a=7, b=11
A=[(7+11)/2]*5=45 cm^2
add the two areas : 45+91=136 cm^2
hope it works, many ways to find the area
Answer:
the answer is 49
Step-by-step explanation:
18+13+11+7=49
please simplify this
Answer:
[tex]\frac{3\sqrt{2} }{2}[/tex]
Step-by-step explanation:
Which is a perfect square?
6’1
6’2
6’3
6’5
Answer:
6^2 is the answer
Step-by-step explanation:
just trust me ik
PLEASE HELP Use the squared identities to simplify 2cos2x cos2x.
Answer:
D
Step-by-step explanation:
The correct option is option D as 2cos²(x)cos²(x) simplifies as follows:
2cos²(x)cos²(x) = {3 + 4cos(2x) + cos(4x)} / 4
Simplification:The given expression is : 2cos²(x)cos²(x)
The square identity for cosine is given by:
2cos²(x) -1 = cos(2x)
Thus,
2cos²(x) = {cos(2x) +1}
simplifying again,
cos²(x) = {cos(2x) +1}/2
Simplifying the above using squared identities:
2cos²(x)cos²(x) = {cos(2x) +1}cos²x
= {cos(2x) +1} {{cos(2x) +1}/2}
[tex]= \frac{\{cos(2x) +1\}^2}{2}\\\\=\frac{cos^2(2x)+2cos(2x)+1}{2}\\\\=\frac{\frac{cos(4x)+1}{2}+2cos(2x)+1}{2}\\\\=\frac{3+4cos(2x)+cos(4x)}{4}[/tex]
so,
2cos²(x)cos²(x) = {3 + 4cos(2x) + cos(4x)} / 4
Hence option D is correct.
Learn more about squared identities:
https://brainly.com/question/14613683?referrer=searchResults
Which equation is true?
The function f(x) is given by the set of ordered pairs.
{(1,0), (-10,2), (0,6), (3,17), (-2,-1)}
OH(- 10) = 1
f(2)= - 10
f(0) = 6
f(1) = - 10
Answer:
c f(0)=6
Step-by-step explanation:
they match
A large park in the shape of a rectangle is 8 km long and 6 km wide. How much shorter is your walk if you have to walk diagonally across the park than along the two sides of it?
Answer: The road is 4 miles shorter across the park
Step-by-step explanation: There are two right triangles
Answer:4 KM
Step-by-step explanation:
6km+4km=10km
Both sides 14 KM
[tex]\sqrt{6^{2} +4^{2}} =Diagonally[/tex]
Diagonally 10 KM
14KM-10KM=4KM
Find the total surface area in square kilometers, of the 3-dimensional
figure shown below.
Enter only a number as your answer.
[tex]\displaystyle\bf\\\textbf{We have a prism with a rectangular triangle base.}\\\\Base~area\!:~~Ab=\frac{3\times4}{2}=\frac{12}{2}=6~km^2\\\\Lateral~area\!:~~Al=(3+4+5)\times9=12\times9=108~km^2\\Total~area\!:~~At=2\times Ab+Al=2\times 6+108=12+108=\boxed{\bf120~km^2}\\[/tex]
You cannot tessellate six-sided regular polygons by themselves.
A. True
B. False
Answer:
This statement is B. False
Step-by-step explanation:
You CAN tesselate six-sided regular polygons by themselves therefore, this statement is FALSE.
Hope this helped! :)
Answer:
Step-by-step explanation:
Factor 24m - 12p 72 to identify the equivalent expressions. choose two answers Choices: A.6(4m 2p 12) B.2(12m-6p 36) C.12(2m-p 6) D.24(m-12p 3)
Answer:
thats tough
Step-by-step explanation:
What is the range of the function?
1
2
2
3
9
4
16
A. (2, 4, 9, 16)
B. {1, 2, 3, 4, 9, 16)
c. {1, 2, 3, 4)
D. {1,2}
Answer:
Im pretty sure its B
Step-by-step explanation:
Lincoln is measuring the angles of quadrilateral WXYZ to determine whether it is congruent to the quadrilateral below.
Quadrilateral R S T Q. Angle R is 140 degrees, angle S is 94 degrees, angle T is 79 degrees, and angle Q is 47 degrees.
Which pair of measurements are possible if they are congruent figures?
Measure of angle W = 47 degrees and Measure of angle X = 94 degrees
Measure of angle X = 94 degrees and Measure of angle Z = 79 degrees
Measure of angle W = 47 degrees and Measure of angle Y = 140 degrees
Measure of angle X = 140 degrees and Measure of angle = 94 degrees
Answer:
None of these
Step-by-step explanation:
The congruent occurs when the two diagrams are matched with each other in terms of the same sides and same angles
In other terms, we can say that if both quadrilaterals contain the same sides and same angles so we called as congruent
As we can see in the figure that there is only angles are given but not the sides that are totally different
Hence, none of these is the right answer
Answer:
D.) Measure of angle X = 140 degrees and Measure of angle = 94 degrees
Step-by-step explanation:
3kg of butter is packed into small packets of 75gm each to be supplied to a restaurant. How many such packets can be made? If 10 such small packets are put into a box, how many such boxes can be made?
Answer:
4
Step-by-step explanation:
Converting 3kg to grams,
3 kg * = 3000 g
If we divide 3000 g by 75, we will determine how many packets of butter there are.
3000 / 75 = 40.
40 packets of butter. If 10 go into a box, that means that
40 / 10 = 4 boxes.
Hence 4 such boxes can be made
Answer:
4 boxes can be made
Step-by-step explanation:
→ First work out the amount of small packets there are
3 kg = 3000g
3000 ÷ 75 = 40
→ Now we know that there are 40 small packets and one box can hold 10 packets so,
1 box = 10 packets
? boxes = 40 packets
40 ÷ 10 = 4
→ 4 boxes can be made
Select the points that are solutions to the system of inequalities select all that apply
Answer:
B. (2, 4)
D. (10, -1)
Step-by-step explanation:
The solution sets must be in the shaded region of the systems of inequalities. It cannot be on either lines because both lines are dotted. In that case, only B and D work because they are inside the shaded regions while the other points are not.
Answer:
B. (2, 4)
D. (10, -1)
Step-by-step explanation:
To be a solution, a point must be in the shaded part of the graph.
Answer: (2, 4), (10, -1)
Find the number of 4-digit numbers that contain at least three even digits.
Answer:
1234
Step-by-step explanation:
Answer:
2625
Step-by-step explanation:
First let's see all the possible combinations.
(Even=E, Odd= O)
1) EEEO
2) EEOE
3) EOEE
4) OEEE
5) EEEE
Now let's see what E and O possibly could be
E = 0, 2, 4, 5, 6 and 8 (5)
O = 1, 3, 5, 7, 9 (5)
Now we are just simply gonna multiply
1) EEEO = 4*5*5*5
2) EEOE = 4*5*5*5
3) EOEE = 4*5*5*5
4) OEEE = 5*5*5*5
5) EEEE = 4*5*5*5
The even contains a 0, so you can't put 0 in, so (5-1=4), there are only 4 digits for the even.
500 times 4 = 2000
5⁴ = 625
2000+625= 2625
Given the transition matrix P and the? initial-state matrix Upper S 0S0 ?below, find Upper P Superscript 4P4 and use Upper P Superscript 4P4 to find Upper S 4S4. A B Upper PPequals= A B left bracket Start 2 By 2 Matrix 1st Row 1st Column 0.8 2nd Column 0.2 2nd Row 1st Column 0.3 2nd Column 0.7 EndMatrix right bracket 0.8 0.2 0.3 0.7 ?; Upper S 0S0equals= left bracket Start 1 By 2 Matrix 1st Row 1st Column 0.1 2nd Column 0.9 EndMatrix right bracket
Answer:
[tex]S^4=\left[\begin{array}{ccc}0.56875&0.43125\end{array}\right][/tex]
Step-by-step explanation:
[tex]\text{Initial-State Matrix}, S_0=\left[\begin{array}{ccc}0.1&0.9\end{array}\right][/tex]
[tex]\text{Transition Matrix}, P=\left[\begin{array}{ccc}0.8&0.2\\0.3&0.7\end{array}\right][/tex]
First, we are to determine [tex]P^4[/tex].
[tex]P^2=\left[\begin{array}{ccc}0.8&0.2\\0.3&0.7\end{array}\right]\left[\begin{array}{ccc}0.8&0.2\\0.3&0.7\end{array}\right]=\left[\begin{array}{ccc}0.8*0.8+0.2*0.3&0.8*0.2+0.2*0.7\\0.3*0.8+0.7*0.3&0.3*0.2+0.7*0.7\end{array}\right]\\\\=\left[\begin{array}{ccc}0.7&0.3\\0.45&0.55\end{array}\right][/tex]
[tex]P^4=(P^2)^2=\left[\begin{array}{ccc}0.7&0.3\\0.45&0.55\end{array}\right]\left[\begin{array}{ccc}0.7&0.3\\0.45&0.55\end{array}\right]\\=\left[\begin{array}{ccc}0.7*0.7+0.3*0.45&0.7*0.3+0.3*0.55\\0.45*0.7+0.55*0.45&0.45*0.3+0.55*0.55\end{array}\right]\\\\=\left[\begin{array}{ccc}0.625&0.375\\0.5625&0.4375\end{array}\right][/tex]
Therefore:
[tex]S^4=S_0P^4[/tex]
[tex]=\left[\begin{array}{ccc}0.1&0.9\end{array}\right]\left[\begin{array}{ccc}0.625&0.375\\0.5625&0.4375\end{array}\right]\\=\left[\begin{array}{ccc}0.1*0.625+0.9*0.5625&0.1*0.375+0.9*0.4375\end{array}\right]\\\\S^4=\left[\begin{array}{ccc}0.56875&0.43125\end{array}\right][/tex]
Answer:
CaCl2, MgO, Na2O
Step-by-step explanation:
Got it right on edg. 2020
Write an equation for the following: a) The ellipse has foci (2, 0) and (–2, 0) and vertices (4, 0) and (–4, 0). b) The ellipse is centered at the origin, has axes of lengths 8 and 4, its major axis is horizontal.
Answer:
a) [tex]\frac{x^2}{16} +\frac{ y^2}{12} = 1[/tex]
b) [tex]\frac{x^2}{64} +\frac{ y^2}{16} = 1[/tex]
Step-by-step explanation:
a)
The vertices are located in the x-axis, so we have a horizontal ellipse.
The equation of an ellipse is given by:
[tex]\frac{(x - h)^2}{a^2} +\frac{ (y - k)^2}{b^2} = 1[/tex]
The coordinates of the foci and the vertices are given by:
Foci: [tex]F(h \pm c, k)[/tex]
Vertices: [tex]V(h\pm a, k)[/tex]
Comparing the coordinates with the values given, we have that:
h = 0, k = 0, c = 2, a = 4
To find the value of b we can use the following equation:
[tex]c^2 = a^2 - b^2[/tex]
[tex]4 = 16 - b^2[/tex]
[tex]b^2 =12[/tex]
So the equation of the ellipse is:
[tex]\frac{x^2}{16} +\frac{ y^2}{12} = 1[/tex]
b)
If the ellipse is centered at the origin, we have:
h = 0, k = 0
The major axis is 'a' and the other axis is 'b', so we have:
a = 8, b = 4.
So the equation is:
[tex]\frac{x^2}{64} +\frac{ y^2}{16} = 1[/tex]
Help !!!! Match the written mathematical operation to the equivalent symbolic form
Answer:
The matched pairs are:
(A, 4), (B, 1), (C, 2) and (D, 3)
Step-by-step explanation:
The complete question is:
Match each description of an algebraic expression with the symbolic form of that expression :
A. 2 terms; variables = x and y
B. 3 terms; variables = x and y; constant = 3
C. 2 terms; variable = x; constant = 4.5
D. 3 terms; variables = x and y; constant = 2
1. x - 2y + 3
2. 4.5 - 2x
3. 4.5x + 2 - 3y
4. 4.5y - 2x
Solution:
A. 2 terms; variables = x and y ⇒ 4. 4.5y - 2x
B. 3 terms; variables = x and y; constant = 3 ⇒ 1. x - 2y + 3
C. 2 terms; variable = x; constant = 4.5 ⇒ 2. 4.5 - 2x
D. 3 terms; variables = x and y; constant = 2 ⇒ 3. 4.5x + 2 - 3y
please answer
what is 2y^4 x 5y^3
it is the answer of your question
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
(2y4 • 5) • y3
STEP
2
:
Equation at the end of step 2
(2•5y4) • y3
STEP
3
:
Multiplying exponential expressions
3.1 y4 multiplied by y3 = y(4 + 3) = y7
Final result :
(2•5y7)
I WILL MARK BRAINLIEST IF ANSWER IN LESS THAN 5 MINUTES!!!!!!! tory is buying bananas. she has 15 dollars and bananas are 2.45 each. how many bananas can she buy?
Answer:
6 bananas
Step-by-step explanation:
Divide the dollars by the price for bananas
15/2.45
6.12244898
Round down because she cannot buy part of a banana
6 bananas
Look at the picture
Answer:
Your answer is E
Step-by-step explanation:
To make sure, plug the values in the place of N
[tex]-2 <-1, 0, 1, 2, 3, 4, 5, 6, \\ -1, 0, 1, 2, 3, 4, 5, 6, \leq 6[/tex]
Drag each step and justification to the correct location on the table. Each step and justification can be used more than once, but not all steps and justifications will be used.
Order each step and justification that is needed to solve the equation below.
please help me
Answer/Step-by-step explanation:
Below are the steps to take in solving the given equation, as well as justification forf each step:
[tex] \frac{2}{3}y + 15 = 9 [/tex] => Given
[tex] \frac{2}{3}y + 15 - 15 = 9 - 15 [/tex] => subtraction property of equality
[tex] \frac{2}{3}y = - 6 [/tex] => simplification
[tex] \frac{2}{3}y * \frac{3}{2} = - 6 * \frac{3}{2} [/tex] => multiplication property of equality
[tex] y = - 9 [/tex] => simplification
Simplify the expression -3÷(-3/5)
Answer:
the answer is 5 if it was helpful please give 5 star
At the beginning of an experiment, a scientist has 356 grams of radioactive goo. After 210 minutes, her sample has decayed to 44.5 grams. Find a formula for G ( t ) , the amount of goo remaining at time t . Keep at least 5 decimal places.
Answer: [tex]\bold{G(t)=356e^{-0.59413t}}[/tex]
Step-by-step explanation:
Use the decay formula: [tex]P=P_oe^{kt}[/tex] where
P is the remaining amount of the sampleP₀ is the original amount of the samplek is the decay ratet is the time (in hours)Given: P = 44.5, P₀ = 356, k = unknown, t = 210 minutes (3.5 hours)
[tex]44.5=356e^{k(3.5)}\\\\\\\dfrac{44.5}{356}=e^{3.5k}\\\\\\0.125=e^{3.5k}\\\\\\ln(0.125)=3.5k\\\\\\\dfrac{ln(0.125)}{3.5}=k\\\\\\-0.59413=k[/tex]
Input P₀ = 356 and k = -0.59413 into the decay formula
[tex]\large\boxed{P=356e^{-0.59413t}}[/tex]
Divide the following:
a) 25.2 divided by 0.6
b) 70.625 divided by 1.25
Answer:
25.2/0.6 = 4270.625/1.25 = 56.5you can do the normal operation
or use a calculator
Planes A and B intersect.
Which describes the intersection of line m and line n?
m
O point w
O point X
O point Y
O point Z
Answer:
Hello!
____________________
Your answer would be (A) O point W.
Step-by-step explanation: Intersection of the two lines is defined as the point where the two lines cross or meet each other.
It is given that the lines m and n intersect each other, which means that they must be intersecting each other at some point.
From the figure, it can be seen that in plane A, the lines m and n intersect each other at point W, thus point W is the point of intersection of the two line m and n.
Hence, option A is correct.
Hope this helped you!
Answer: point w hope this helped
Step-by-step explanation:
HELPPPP ME ASAP PLEASEEE DO STEP BY STEPPPP Distribute and simplify the following: x(3x + 2)(-2x + 1)
Answer:
-6x^3 - x^2 + 2x
Step-by-step explanation:
We can first start with distributing the x using the distributive property
(3x^2 + 2x)(-2x+1) Remember that when x is multiplied with 3x, it increases the exponent to 3x^2)
Now we use FOIL to distribute (First, Outside, Inside, Last)
-6x^3 + 3x^2 - 4x^2 + 2x
We can combine the like terms (3x^2 and - 4x^2) into -x^2
-6x^3 - x^2 + 2x