Answer:
"12.122 m/s²" is the appropriate solution.
Explanation:
The given values in the question are:
Length,
l = 49.0 cm
or,
= [tex]49.0\times 10^{-2} \ m[/tex]
Time taken,
[tex]T = \frac{125}{99.0}[/tex]
[tex]=1.2626 \ s[/tex]
Now,
As we know,
⇒ [tex]T = 2 \pi\sqrt{\frac{l}{g} }[/tex]
or,
⇒ [tex]T^2=4 \pi^2[\frac{l}{g} ][/tex]
[tex]g = 4\pi^2[\frac{l}{T^2} ][/tex]
By substituting the above given values, we get
[tex]=\frac{4\times (3.14)^2\times (49.0\times 10^{-2})}{(1.2626)^2}[/tex]
[tex]=\frac{39.4384\times 49.0\times 10^{-2}}{1.59415876}[/tex]
[tex]=\frac{19.324816}{1.59415876}[/tex]
[tex]=12.122 \ m/s^2[/tex]
what's is the best definition of AVERAGE SPEED?
Answer:
The average speed is the distance travelled divided by the time taken: Average speed=Distance travelledTime taken.
What is the mass of a block if it's moving at 10 m/s and has 200 J of energy
Answer:
4kg
Explanation:
=2/2
m=(200x2)/10^2
m=400/100
m=4
4kg
What is the Ampere's Law all about?
Answer:
Amphere's law state that the sum of over element of the component of magnetic field along the direction of the element, times the element length,is proportional to the current that passes through the loop:This is the general statement of Amphere's law.
Violet light (410 nm) and red light
(685 nm) pass through a diffraction
grating with d = 3.33 x 10-6 m. What is
the angular separation between them
for m = 2?
Answer:10.03
Explanation:acellus
Efficiency of a machine is lesser than 100% , Why?
Answer:
Efficiency is the percent of work put into a machine by the user (input work) that becomes work done by the machine (output work). The output work is always less than the input work because some of the input work is used to overcome friction. Therefore, efficiency is always less than 100 percent.
A thin film of acetone (n=1.25) lies on the surface of a thick piece of water (n=1.30). White light shines down from air onto the thin layer of acetone. Destructive interference occurs for m=3 for a wavelength in air of 600 nm. What is the thickness of the thin film?
Answer:
Explanation:
The wave of light is being reflected two times while going from lower to higher refractive index mediums
So there will be phase reversal two times .
Condition of destructive index
2 μ t = ( 2m+1) λ / 2
Substituting the values
2 x 1.25 x t = ( 2 x 3 + 1 ) x 600nm / 2
2.5 t = 2100 nm
t = 840 nm .
Use the worked example above to help you solve this problem. The half-life of the radioactive nucleus _(88)^(226)text(Ra) is 1.6 103 yr. If a sample initially contains 4.00 1016 such nuclei, determine the following:________.
(a) the initial activity in curies µCi
(b) the number of radium nuclei remaining after 4.4 103 yr nuclei
(c) the activity at this later time µCi
Answer:
Explanation:
From the information given:
The half-life [tex]t_{1/2}[/tex] = 1.6103 years
The no. of the initial nuclei [tex]N_o[/tex] = [tex]4.00 \times 10^6[/tex]
Using the formula:
[tex]N = N_o exp(-\lambda t)[/tex]
where;
decay constant [tex]\lambda = \dfrac{In2}{1.6*10^3} y^{-1}[/tex]
∴
[tex]N = N_o exp ( \dfrac{-In2}{1.6*10^3}\times 4.4 \times 10^3)[/tex]
[tex]N = N_o exp (- 1.906154747)[/tex]
The number of radium nuclei N = 5.94 × 10¹⁵
The initial activity[tex]A_o = \lambda N_o[/tex]
[tex]A_o =(\dfrac{In (2)}{1.61\times 10^3 \times 365 \times 24 \times 3600}\times 4.00 \times 10^{16})[/tex]
[tex]A_o =546075.8487 \ Bq[/tex]
Since;
1 curie = 3.7 × 10¹⁰ Bq
Then;
[tex]A_o =\dfrac{546075.8487 }{3.7\times 10^{10}}[/tex]
[tex]A_o = 1.47588 \times 10^{-5}Ci[/tex]
[tex]A_o = 14.7588 \ \mu Ci[/tex]
c) The activity at a later time is:
[tex]=5.94 \times 10^{15}( \dfrac{In (2)}{1.60 \times 10^3 \times 365\times 24 \times 3600})[/tex]
[tex]= 81599.09018 \ Bq \\ \\ = \dfrac{81599.09018}{3.7\times 10^{10}} \ Ci \\ \\ = 2.20538 \times 10^6 \ Ci \\ \\ = 2.20538 \ \mu Ci[/tex]
2. Light traveling in air (n1=1) hits a piece of glass at an angle of 45 degrees. If the glass has a refractive index of 1.5, what angle should the light bend at?
Answer:
28.1 degrees
Explanation:
Use formula: [tex]N_1Sin(Angle_1) = N_2Sin(Angle_2)[/tex]
* use angles given
A man rides a bike along a straight road at a constant speed for 5 minmin, then has a flat tire. He stops for 5 minmin to repair the flat, but then realizes he cannot fix it. He continues his journey by walking the rest of the way at a constant speed, which takes him another 10 min.
Required:
Use the particle model to draw a motion diagram of the man for the entire motion described here. Number the dots in order, starting with zero.
(1) Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy source is to store antimatter charged particles in a vacuum chamber, circulating in a magnetic field, and then extract them as needed. Antimatter annihilates with normal matter, producing pure energy. What strength magnetic field is needed to hold antiprotons, moving at 5.0 x 10^7 m/s in a circular path 2.00 m in radius? Antiprotons have the same mass as protons but the opposite (negative) charge.
(2) Is this field strength obtainable with today’s technology or is it a futuristic possibility?
Solution :
The relationship between the strength of magnetic field and the radiusof a charged particle's path is obtained through Newton's second law, which is given by :
F = ma
F = qvB and [tex]$a=\frac{v^2}{r}$[/tex]
Substituting these values in the second law of Newton,
[tex]$qvB=\frac{mv^2}{r}$[/tex]
Now solving for B, we get:
[tex]$B = \frac{mv}{rq}$[/tex]
[tex]$=\frac{(1.67 \times 10^{-27})(5 \times 10^{7})}{2\times 1.6 \times 10^{-19}}$[/tex]
= 0.261 T
The field strength can be obtained by using the technology of today.
You have a 6.00 V power supply, and
a 30.0 ohm and a 75.0 ohm resistor.
Find the current flowing out of the
battery if the resistors are connected
in parallel.
Answer: 0.28 A
Explanation:
Answer:
.28
Explanation:
Acellus
what country is this
Answer:
USA
NAMELY UNITED STATES OF AMERICA
america
Explanation:
because why not
A Thomson's gazelle can run at very high speeds, but its acceleration is relatively modest. A reasonable model for the sprint of a gazelle assumes an acceleration of 4.2m/s2 for 6.5s , after which the gazelle CONTINUES at a steady speed.
a. What is the gazelles top speed?
b. A human would win a very short race with a gazelle. The best time for a 30 m sprint for a human runner is 3.6 s. How much time would the gazelle take for a 30 m race?
Answer:
The correct answer will be:
(a) 27.3 m/s
(b) 3.8 s
Explanation:
According to the question:
Acceleration,
[tex]a= 4.2 \ m/s^2[/tex]
Time,
[tex]t = 6.5 \ s[/tex]
(a)
The gazelles top speed will be:
⇒ [tex]V_{max} = at[/tex]
[tex]=4.2\times 6.5[/tex]
[tex]=27.3 \ m/s[/tex]
or,
[tex]= 27 \ m/s[/tex]
(b)
As we know,
s = 30 m
Now,
⇒ [tex]s = \frac{1}{2} at^2[/tex]
or,
⇒ [tex]t=\sqrt{\frac{2s}{a} }[/tex]
On putting the given values, we get
[tex]=\sqrt{\frac{2\times 30}{4.2} }[/tex]
[tex]=\sqrt{\frac{60}{4.2} }[/tex]
[tex]=3.78 \ s[/tex]
or,
[tex]=3.8 \ s[/tex]
3. A dog walks 12 meters to the east and then 16 meters back to the west.
For this motion, what is the distance moved?
What is the magnitude and direction of the displacemeni?
Answer:
[tex]distance = 16 + 12 \\ = 28 \: meters \\ \\ displacement = {}^{ + } 12 + {}^{ - } 16 \\ = - 4 \: meters \\ magnitude = > |s| = 4 \: meters[/tex]
Magnetic resonance imaging often need magnetic fields of a strength of around 1.50 T. The solenoid is 1.80 meters long and 75.0 cm in diameter. It is tightly wound with a single layer of 2.00 mm diameter superconducting wire.
Required:
What current is needed?
Answer:
The current needed is 2387.32 A
Explanation:
Given;
strength of the magnetic field, B = 1.5 T
length of the solenoid, L = 18 m
diameter of the solenoid, D = 75 cm = 0.75 m
diameter of the superconducting wire, d = 2 mm = 0.002 m
The number of turns of the solenoid is calculated as;
[tex]N = \frac{length \ of \ solenoid}{diameter \ of \ wire } = \frac{1.8}{0.002} = 900 \ turns[/tex]
The magnetic field strength is given by;
[tex]B = \frac{\mu_0 NI}{L} \\\\[/tex]
Where;
I is the current needed
μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A
[tex]I = \frac{BL}{\mu_0 N} =\frac{1.5 \times 1.8}{4\pi \times 10^{-7} \ \times 900} \\\\I = 2387.32 \ A[/tex]
Therefore, the current needed is 2387.32 A
Two students are balancing on a 10m seesaw. The seesaw is designed so that each side of the seesaw is 5m long. The student on the left weighs 60kg and is sitting three meters away from the fulcrum at the center. The student on the right weighs 45kg. The seesaw is parallel to the ground. The mass of the board is evenly distributed so that its center of mass is over the fulcrum. What distance from the center should the student on the right be if they want the seesaw to stay parallel to the ground?
a. 4m
b. 5m
c. 2m
d. 3m
Answer:
We can say that when we multiply both the force given by the two body and along with the distinct lengths they are situated from centre of mass (fulcrum) will be the same
So the let the distance seperated from the centre of mass on the right side where the boy sits be x
so 60×3 = 45x
=> x = (180/45)
=> x = 4 metres
Hope it helps
Is it more fun on a swing with low or high amplitude? Explain.
Explain the difference between the speed of an Electromagnetic wave and its frequency?
Answer:
Electromagnetic waves differ in their wavelengths and frequencies. The higher the frequency of an electromagnetic wave, the greater its energy. The speed of an electromagnetic wave is the product of its wavelength and frequency, so a wave with a shorter wavelength has a higher frequency, and vice versa.
Explanation:
A 1.5-kg ball is throw at 10 m/s. What is the balls momentum?
Answer : The momentum of ball is, 15 kg.m/s
Explanation :
Momentum : It is defined as the motion of a moving body. Or it is defined as the product of mass of velocity of an object.
Formula of momentum is:
where,
p = momentum = ?
m = mass = 1.5 kg
v = velocity = 10 m/s
Now put all the given values in the above formula, we get:
Therefore, the momentum of ball is 15 kg.m/s
A sound has a higher pitch than a bell. Which quantity must also be higher in this sound than in the bell?
O amplitude
O frequency
O wavelength
O speed
Answer:
frequency
Explanation:
The frequency must also be higher in this sound than in the bell because for high pitch the frequency must be high.
What is the frequency?It is defined as the number of waves that crosses a fixed point in one second, known as frequency. The unit of frequency is per second.
We have:
A sound has a higher pitch than a bell.
As we know, the sound has a high pitch if the vibration frequency is high, and a low pitch if the vibration frequency is low.
Thus, the frequency must also be higher in this sound than in the bell because for high pitch the frequency must be high.
Learn more about the frequency here:
brainly.com/question/27063800
#SPJ2
3. The load across a 12-V battery consists of a series combination
of three resistors that have a resistance of 15 12,21 12, and 24 12,
respectively. What is the current in this circuit? (5F)
a. 0.2 A
b. 2.0 A
C. 0.19 A
d. 1.9 A
Answer:
a. 0.2 A
Explanation:
Given;
voltage of the battery, V = 12 V
three resistance connected in series, R₁ = 15 Ω, R₂ = 21 Ω, R₃ = 24Ω
The equivalent resistance for series connection is calculated as;
Rt = R₁ + R₂ + R₃
Rt = 15Ω + 21Ω + 24Ω
Rt = 60 Ω
Apply Ohm's law to calculate the current n the circuit;
V = IRt
I = V/Rt
I = 12/60
I = 0.2 A
Therefore, the current in the circuit is 0.2 A
1 point
Nuclear equations like the one below show "parent" and "daughter” nuclei.
What is the mathematical relationship between the superscripts on the
left-hand side and the superscripts on the right-hand side of the nuclear
equation?
27
27
0
12 Mg
13 AL +
je
Answer:
Mg- 27 means isotope with 12 protons and 15 neutrons.
Also 27 is mass number which express sum of protons and neutrons.
In nucleus one neutrn decays to electron and proton. Mass number remain same but Al-27 nucleus contain 13 protons and 14 neutrons. Electron is ejected out from nucleus.
Calculate the force of gravity on the 1-kg mass if it were 3.2x10^6 m above Earth's surface that is, if it were one and a half
Earth radii from Earth's center).
Answer:
F= 4.3N
the question (for seo and search engine optimization to get this question to the top)
Calculate the force of gravity on the 1-kg mass if it were 3.2×106m above Earth's surface (that is, if it were one and a half Earth radii from Earth's center).
F= 4.3N
Answer:
Recuerda que la Ley de gravitación universal de Newton puede enunciarse así: “Toda partícula de
materia en el universo atrae a todas las demás partículas con una fuerza que es directamente
proporcional a las masas de las partículas e inversamente proporcional al cuadrado de la distancia que
las separa”. Ley que se puede expresar simbólicamente de la siguiente forma:
2
1 2
d
m m F ⋅ ∝
Podemos expresar la proporcionalidad de la ley de gravitación universal en forma de una ecuación
exacta introduciendo la constante de proporcionalidad G, llamada constante de gravitación universal:
2
1 2
d
m m F G ⋅ = ⋅ donde
2
Four passengers with combined mass 250 kg compress the springs of a car with worn out shock absorbers by 4.00cm when they enter it. Model the care and passengers as a single body on a single ideal spring. If the loaded has a period of vibration of 1.08 s, what is the period of vibration of the empty car?
Answer:
The time period of the empty car will be "1.00 s".
Explanation:
The given values in the question will be:
Mass,
m = 250 kg
Loaded car's time period will be:
T = 1.08 s
Shock absorbers compression,
x = 4 cm
or,
= 0.04 m
Now,
Weight of passengers will be:
⇒ [tex]F=mg[/tex]
[tex]=250\times 9.8[/tex]
[tex]=2450 \ N[/tex]
The spring constant of shock absorbers will be:
⇒ [tex]k=\frac{F}{x}[/tex]
[tex]=\frac{2450}{0.04}[/tex]
[tex]=61.250 \ N/m[/tex]
As we know,
Time period, [tex]T = 2 \pi\sqrt{\frac{M}{k} }[/tex]
On substituting the values, we get
[tex]1.08=2\pi \sqrt{\frac{M}{61250} }[/tex]
[tex]\frac{M}{61250}=0.02955[/tex]
[tex]M=0.02955\times 61250[/tex]
[tex]=1809.6 \ kg[/tex] (Total mass of car as well as its passengers)
Now,
The mass of the empty car will be:
⇒ [tex]m'=M-m[/tex]
[tex]=1809.6-250[/tex]
[tex]=1559.6 \ kg[/tex]
hence,
The time period of empty car will be:
⇒ [tex]T'=2\pi\sqrt{\frac{m'}{k} }[/tex]
[tex]=2\pi\sqrt{\frac{1559.6}{61250} }[/tex]
[tex]=2\pi \sqrt{0.0254}[/tex]
[tex]=1.003 \ s[/tex]
or,
[tex]=1.00 \ s[/tex]
What did Europeans, africans and Americans trade as a result for the Colombian exchange
A. Railroad engineering ideas
B. Computer technology
C. Film production techniques
D. Agricultural knowledge
Also under the subject I meant to put social studies not physics.
Answer: Railroad engineering ideas
PLS HELP!!!!!!!!
I will give brainliest to correct answer!!!
Answer:
i'd say 2
Explanation:
A man is weighed 450N runs up a flight of
Staires consisting of 25 steps each 10cm height
20s calculate the power
Answer:
56.25 watts
Explanation:
P = F * d / t
P = Power (it's an unknown at this point).
F = 450 N
d = 25 steps each 10 cm = 25 steps 0.1 m/step = 2.5 m
t = 20 s
Solution
P = 450 * 2.5 / 20
P = 1125/20
P = 56.25
The block slides on a horizontal frictionless surface. The block has a mass of 1.0kg and is pushed 5.0N at 45°. What is the magnitude of the acceleration of the block?
Answer:
[tex]3.5\:\mathrm{m/s^2}[/tex]
Explanation:
Newton's 2nd law is given as [tex]\Sigma F = ma[/tex].
To find the acceleration in the horizontal direction, you need the horizontal component of the force being applied.
Using trigonometry to find the horizontal component of the force:
[tex]\cos 45^{\circ}=\frac{x}{5},\\\frac{\sqrt{2}}{{2}}=\frac{x}{5},\\x=\frac{5\sqrt{2}}{2}[/tex]
Use this horizontal component of the force to solve for for the acceleration of the object:
[tex]\frac{5\sqrt{2}}{2}=1.0\cdot a,\\a=\frac{5\sqrt{2}}{2}\approx \boxed{3.5\:\mathrm{m/s^2}}[/tex]
A circuit with 220 voltage is supplied with a fuse of 10 ampere.How many bulbs of 100 watt can be safely used in the circuit
It takes 24 hours for _______?
a.Earth to circle the sun one time
b.earth to rotate on its axis one time
c. The sun to circle earth one time
d.the sun to rotate on its axis one time
Answer:
C
Explanation:
Earth rotates once in about 24 hours with respect to the Sun, but once every 23 hours, 56 minutes, and 4 seconds with respect to other, distant, stars. Earth's rotation is slowing slightly with time; thus, a day was shorter in the past. This is due to the tidal effects the Moon has on Earth's rotation.
Answer: the answer is b.
ps: the other answer is wrong, the earth rotates around the sun, and the sun doesn't rotate around the earth.
Explanation: