Alissa surveys a random sample of 50 students at her school about the country
they would most like to visit. The table shows her results. Based on the sample,
can Alissa conclude that there are probably fewer students at her school who
want to visit Japan than Australia? Explain your reasoning.

There are two problems please help

Answer:

3(x-6)=3x-18

Step-by-step explanation:

Answer:

6 Hours

Explanation:

Linear Equation: mx+b=y

x variable: Hour

Hourly Fee: $15(x)

(Initial) Rent Fee: $25

Balance: $100

Equation:

15x+25=100

15x+25-25=100-25 -- Separate the constant terms from the x by subtracting 25 from both sides.

15x=100

15x/15=100/15 -- Isolate the x variable by dividing 15 from both sides.

x=6.6.. -- Round down to 6 (not 7) because you can't afford to snowboard for 7 hours with less than $15.

x=6 Hours

answer: 6 hours

Step-by-step explanation:

I did this on a paper

Answer:

y-18=14

add 18 on both sides

y=32

plug that into the equation below

3(Y+5)

3(32+5)

add 32 and 5

3(37)

multiply

3

....

3 x 37 = 111

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's find the circumference of given circle ~

Circumference :

[tex]\qquad \tt\dashrightarrow \:c =2 \pi r[/tex]

where,

now, let's calculate circumference ~

[tex]\qquad \tt  \dashrightarrow \:c = 2 \times \pi \times 3[/tex]

[tex]\qquad \tt  \dashrightarrow \:c = 6 \pi \: \: yd[/tex]

Now, let's plug in approximate value of pi :

[tex]\qquad \tt  \dashrightarrow \:c = 6 \times 3.14 \: \: [/tex]

[tex]\qquad \tt \dashrightarrow \:c = 18.84 \: \: yd[/tex]

Answer:

15.6204994

Step-by-step explanation:

[tex]15.6204994^{2} = 244\\so\\\sqrt{244} = 15.6204994[/tex]

hope this helps!

65%= 234

100%= 234÷65×100

100%= 360

75%= 360÷100×75

75%= 270

Answer:

75 inches cubed

Step-by-step explanation:

V=lwh

2 1/2 = 2.5

4 = 4

7 1/2 = 7.5

2.5 x 4 x 7.5=75

75 cubic inches

Slope = change in y / change in x

slope = (0 - 13) / (7 - -14)

slope = -13/28

Answer:

4240 in²

rectangle prism area: 2(wl+hl+hw)

=======

area:

Why do the leaves drop:

Hope that helps!

Answer:

Step-by-step explanation:

The figure has 2 triangular and 3 rectangular faces.

This is a right triangular prism.

Find the area of each face and add up to get the total surface area.

Each triangle has base of 10 and height of:

Total surface area is

Answer:

Area is 24 unit ²

Step-by-step explanation:

Given :-

To find:-

Solution:-

We know , The formula for finding area of triangle is 1/2×b×h

putting the known values ,

Area = 1/2 × 8 × 6 unit²

Area = 24 unit²

Given Information :-

⠀⠀

⠀

To Find :-

⠀

⠀

Solution :-

⠀

To find the percentage of expenditure, we must know how much amount does he really spend, thus :

⠀

➥ Expenditure = Earnings - Savings

➥ Expenditure = Rs. 9600 - Rs. 2400

➥ Expenditure = Rs. 7200

⠀

Now, we can find the percentage,

⠀

[tex] \sf \hookrightarrow Percentage_{expenditure} = \dfrac{Expenditure}{Earnings} \times 100 \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{7200}{9600} \times 100 \qquad \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{72 \cancel{00}}{96 \cancel{00}} \times 100 \qquad \quad \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{ \cancel{72}}{ \cancel{96}} \times 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \cancel \frac{3}{4} \times 100 \qquad \qquad \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = 0.75 \times 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \underline{ \boxed{ \orange {\frak{75\%}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ [/tex]

Thus, the percentage of his expenditure is 75%.

⠀

[tex] \underline { \rule{227pt}{2pt}}[/tex]

⠀

Answer:

5%

Step-by-step explanation:

Earns= Rs 640

Spends= Rs 608

Saves= (Rs 640 - Rs 608) =Rs 32

therefore, 32/640x100

Step-by-step explanation:

question no. 21 answer

8 units

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

By using Distance formula ~

[tex]\qquad❖ \: \sf \: \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } [/tex]

[tex]\qquad❖ \: \sf \: \sqrt{ ( - 8 - ( - 8)) {}^{2} + ( - 8 - 5) {}^{2} } [/tex]

[tex]\qquad❖ \: \sf \: \sqrt{0 + ( - 13) {}^{2} } [/tex]

[tex]\qquad❖ \: \sf \: \sqrt{169} [/tex]

[tex]\qquad❖ \: \sf \:13 \: \: units[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

The distance between the points is 13 units

Answer: 75.36

Step-by-step explanation: Lenght of arc=2nr
=2nx12in

=75.36

lenght of arc of sector=120/360x75.36

=25.12

A best example of an out-of-pocket cost is: C. A deductible.

An out-of-pocket cost can be described as a cost you pay from your own personal reserve, which may include coinsurance, deductibles, copays, and some services covered by an individual's health plan.

Out-of-pocket cost may be reimbursed.

Thus, a best example of an out-of-pocket cost is: C. A deductible.

Learn more about out-of-pocket cost on:

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Answer: C. A deductible

Step-by-step explanation:

Answer:

-21/8 or -2 5/8

Step-by-step explanation:

The lake change is the same for all 7 years so you can subtract -3/8 seven times.

-3/8-3/8-3/8-3/8-3/8-3/8-3/8 = -21/8

as a mixed number it's -2 5/8

Answer:

799.04

Step-by-step explanation:

First take the area of the rectangle, which would be 50 × 20 = 1000.

Then find the area of the circle. The area of a circle is [tex]\pi r^{2}[/tex].  Since the question says to use 3.14 for pi, your area would be 3.14 × 8².

8² equals 8 × 8 which is 64 and 3.14 times 64 is 200.96.

Since the circle is not part of the shaded area, you subtract the area of the rectangle by the area of the circle. 1000 - 200.96 is 799.04

Answer:

Your answer would be 12cm

Step-by-step explanation:

I just take a quiz and got it right.

[tex] \: [/tex]

Step-by-step explanation:

It is given that, the height of a triangle is 3cm, and its base is 3cm and we are to find the area of triangle.

[tex] \: [/tex]

To find the area of the triangle, we have to know this formula :

[tex]\\ {\longrightarrow \pmb{\frak {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times Base \times Height \:}}} \\ \\ [/tex]

Now, substituting the values in the formula :

[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times 3 \times 3 \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times 9 \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{9}{2} \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad Area_{(Triangle)} = \: 4.5 \:}}} \\ \\ [/tex]

Therefore,

Answer:

4.5cm^2

Step-by-step explanation:

Find area of a square 3*3=9

Half of a square is 9/2=4.5

Null hypothesis (H0): The mean level of the chemical in tomatoes from this producer is equal to or less than the recommended level of 0.4 ppm.

Given that, the maximum acceptable level of a certain toxic chemical in vegetables has been set at 0.4 parts per million (ppm).

Alternative hypothesis (H1): The mean level of the chemical in tomatoes from this producer is greater than the recommended level of 0.4 ppm.

To test the claim, we will use a one-tailed hypothesis test with a significance level of 0.05. The test statistic is calculated by subtracting the mean of the sample from the mean of the population, and dividing the result by the standard deviation of the population.

Test statistic = (Sample mean - Population mean) / Standard deviation of population

Test statistic = (0.465 - 0.4) / 0.21

Test statistic = 2.38

Since the test statistic is positive, we can reject the null hypothesis. The P-value for this test statistic is 0.0095, which is less than 0.05.

Therefore, the data provides sufficient evidence to support the claim that the mean level of the chemical in tomatoes from this producer is greater than the recommended level of 0.4 ppm.

Learn more about the random sample here:

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#SPJ1

First lets write an equation to help us solve this.

26.25=3x+5.25

x=7

26.25 - 5.25 = 21.

21/3 = 7.

Answer:

You can bowl 7 games.

Step-by-step explanation:

To begin, you need shoes.

-$5.25

So, we would do $26.25 minus the amount for shoes $5.25

$26.25-$5.25 = $21

You now have $21 to spend on bowling the games. Since it is $3 each game, we can do the equation $21 = $3x. We can do this becuase you have $21 to spend and each game costs $3. So we can put x for how many games and 3 as the price of each game. Now, we simplify to get x alone. This will be how many games you can bowl.

21 = 3x

Divide by 3 on both sides

7 = x

So, you can bowl 7 games.

The value of the $6000 annuity given annual compounding is $124,836.12.

The value of the annuity can be determining using this formula: amount deposited x annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

$6000 x [(1.155^10) - 1/0.155] = $124,836.12

To learn more about annuities, please check: https://brainly.com/question/24108530

Answer:

what do you want to ask brother...

Step-by-step explanation:

or you post this by mistake.....

Answer: 1/4

Step-by-step explanation: 1/8 plus 1/8 is 2/8. it can be simplified to 1/4

Answer:

(425-330)/n=A

Step-by-step explanation:

=======================================================

Explanation:

1 unit along the grid represents 5 feet in real life.

A 1 unit by 1 unit square on the graph paper represents a 5*5 = 25 square foot area in real life.

This means we multiply by 25 when going from the floor plan's area to the real world area.

44*25 = 1100 square meters is the area of the room in real life when the floor plan says the area is 44 sq units.

Answer:

6x-3(2x-5)=9

6x-6x+15=9

15=9

no sollution

Use L'Hopital's rule twice:

[tex]\displaystyle \lim_{x\to0^+} \frac1{\sin^2(x)} \int_{\frac x2}^x \sin^{-1}(t) \, dt = \lim_{x\to0^+} \frac1{\sin^2(x)} \left(\int_0^x \sin^{-1}(t) \, dt - \int_0^{\frac x2} \sin^{-1}(t) \, dt\right) \\\\ = \lim_{x\to0^+} \frac{\sin^{-1}(x) - \frac12 \sin^{-1}\left(\frac x2\right)}{2\sin(x)\cos(x)} ~~~~~~~~~~ (LHR) \\\\ = \lim_{x\to0^+} \frac{2\sin^{-1}(x) - \sin^{-1}\left(\frac x2\right)}{2\sin(2x)} \\\\ = \lim_{x\to0^+} \frac{\frac2{\sqrt{1-x^2}} - \frac1{2\sqrt{1-\frac{x^2}4}}}{4\cos(2x)}  ~~~~~~~~~~ (LHR) \\\\ = \lim_{x\to0^+} \frac{\frac2{\sqrt{1-x^2}} - \frac1{\sqrt{4-x^2}}}{4\cos(2x)}[/tex]

The remaining limand is continuous at x = 0, and the limit is

[tex]\displaystyle \lim_{x\to0^+} \frac1{\sin^2(x)} \int_{\frac x2}^x \sin^{-1}(t) \, dt = \frac{2-\frac12}4 = \boxed{\frac38}[/tex]