Answer:
Agility and Flexibility.
Explanation:
Agility for change of direction and Flexibility to stretch his arm
How did our Sun form? *
A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to
fuse together.
Many smaller stars became fused together by gravity
It broke off from a larger star in the universe.
Two gas giants from another solar system became fused together by gravity.
Answer: A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to fuse together
Explanation:
why does ice melt faster in water than in oil when both liquids are at the same temperature
Answer:
Because water has a high specific heat, each little bit of water flowing past can give lots of thermal energy to the ice cube. Oil has a smaller specific heat, and so more oil has to flow past to give the same amount of heat energy to the ice cube. ... Colder oil will melt ice less rapidly than warmer oil or water
A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for 3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?
Answer:
Explanation:
A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for 3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?
The final velocity of the 4.0 kg mass is equal to 22 m/s.
What is Newton's second law of motion?According to Newton’s second law of motion, the force acting on the object equals the mass of that object times its acceleration for a constant mass.
The acceleration of an object depends on two variables, one is the mass of the object and another is the net force acting. The acceleration of an object is directly proportional to the force acting on the body and inversely proportional to its mass.
The equation of Newton’s second law can be represented as follows:
F = ma
or, a = F/m
Given, the initial velocity of the mass, u = 10m/s
The mass, m = 4.0 Kg
The force acting on the mass, F = 16 N
The acceleration of the mass will be: a = F/m
a = 16/4 = 4 m/s²
From the 1st equation of motion: v = u + at
The velocity after t = 3 sec can be calculated:
v = (10) + (4) × (3)
v = 10 + 12
v = 22 m/s
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What is the salt formed in the second sample reaction?
Answer:
This powder is sodium chloride. In the second reaction (sulfuric acid with copper(II) oxide) the resulting solution was blue in colour. When this solution was heated a small amount of white powder was noted.
Explanation:
i saw it on quizlet
After the initial experiment, students wondered how a person's weight would influence the results. They conducted a second experiment to determine if the mass of an object affected friction, assuming the types of surfaces remained constant. A spring scale was attached to a wooden block (1 kg). The block was placed on a wooden board and the spring scale was used to pull the block. The magnitude of the force required to start the block moving was recorded in the data table. The experiment was repeated using two, three, and four blocks. The data can be seen in the data table at the top of the page. What is the relationship between static friction and weight?
Answer:
The greater the weight of the person, the more static friction.
Explanation:
USATestPrep
Particle track detectors are used to measure the speed of particles if the lifetime of the particle is known. Particle-X has a lifetime of 256.2 ps. These particles are created in an experiment inside the detector by a given reaction. The particles leave 10.7 cm long tracks on average before they decay into other particles not observable by the detector. What is the average speed of the particles in terms of the speed of light
Answer:
the average speed of the particles in terms of the speed of light is 0.81c
Explanation:
Given the data in the question;
[tex]t_p[/tex] = 256.2 ps = 256.2 × 10⁻¹² s
speed of light c = 2.99 × 10⁸ m/s
d = 10.7 cm = 0.107 m
we know that; Average speed v = d/t ------- let this be equation 1
Also, given that 256.2 ps is the lifetime of particle X frame, proper time will be;
t = Y[tex]t_p[/tex] = [tex]t_p[/tex] / √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) --------- let this be equation 2
Next, we input equation 2 into equation 1'
v = d / [ [tex]t_p[/tex] / √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) ]
v = d/[tex]t_p[/tex][ √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) ]
v[tex]t_p[/tex]/d = √( 1 - [tex]\frac{v^2}{c^2}[/tex] )
we square both sides
( v[tex]t_p[/tex]/d )² = (√( 1 - [tex]\frac{v^2}{c^2}[/tex] ) )²
v²[tex]t_p[/tex]²/d² = 1 - [tex]\frac{v^2}{c^2}[/tex]
v²[tex]t_p[/tex]²/d² + [tex]\frac{v^2}{c^2}[/tex] = 1
v²( [tex]t_p[/tex]²/d² + [tex]\frac{1}{c^2}[/tex] ) = 1
v²( ([tex]t_p[/tex]²c² + d²)/d²c² ) = 1
∴
v² = (d²c²) / ([tex]t_p[/tex]²c² + d²)
v = √[ (d²c²) / ([tex]t_p[/tex]²c² + d²) ]
v = (dc) / √([tex]t_p[/tex]²c² + d²)
so we substitute
v = (0.107 m × c) / √( (256.2 × 10⁻¹² s)²(2.99 × 10⁸ m/s)² + (0.107 m )²)
v = 0.107c / √( 0.00586814 + 0.011449 )
v = 0.107c / √( 0.01731714 )
v = 0.107c / 0.1315946
v = 0.81c
Therefore, the average speed of the particles in terms of the speed of light is 0.81c
There is a bottleneck in producing masses higher than4He, because there are no mass-5or mass-8 stable nuclides. For older stars with high densities and high temperatures (T>100 million K), three alpha particles can form12C. This occurs by two alpha particles firstforming8Be, and then8Be reacting with another alpha particle to form12C before8Be candecay back to two alpha particles.a) Explain why this can only happen in very hot stars and high density.b) Calculate how much energy is given up when three alpha particles form12C.
Answer:
Explanation:
a)
To pass the Coulomb barriers and undergo nuclear fusion, alpha particles must be burned at high temperatures. As a result, the ignition temperature needed for this reaction is 5.4168 × 10¹⁰ K. Helium must be burned at a high temperature and density. As a result, this must occur for hot stars with high densities.
b)
The amount of energy given up can be calculated as follows:
[tex]_2He^4 + _2He^4 \to _4Be^8 ---- (1) \\ \\ _4Be^8 + 2_He^4 \to _6C^{12} ---(2)[/tex]
where;
[tex]M(_2He^4) = 4.002603 \ u \\ \\ M(_4Be^8) = 8.005305 10 \ u[/tex]
Therefore, from the reaction (1);
[tex]Q = \Big ( M(_2He^4) + M(_2He^4) - M(_4Be^8) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 2(4.002603 \ u) - (8.00530510 \ u) \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= -0.092 \ MeV}[/tex]
From the second reaction:
[tex]Q = \Big ( M(_4Be^8) + M(_2He^4) - M(_6C^{12}) \Big ) ( 931.5 \ MeV) \\ \\ = \Big ( 8.00530510 \ u +4.002603 \ u -12 \ u \Big) \Big ( 931.5 \ MeV/u \Big) \ \\ \mathbf{= 7.37 \ MeV}[/tex]
Which has the least gravitational force?
Answer: Mount Nevado Huascarán
Explanation: Mount Nevado Huascarán in Peru has the lowest gravitational acceleration, at 9.7639 m/s2, while the highest is at the surface of the Arctic Ocean, at 9.8337 m/s2
State Newton’s Universal Law of Gravitation.
Answer:
This law states that every particle attract every other particle in the universe with a force that is directly proportional to the product of their mass and inversely proportional to the square of the distance between the center
Which is the correct formula for calculating speed?
A. speed - distance - time
B. speed = distange + time
C. speed = distance - time
D. speed = distance - acceleration
Answer:
speed=distance/time
Explanation:
its distance over time like division
what foxes need to eat to
stay alive
Answer:
They eat meat and vegetation.Answer:
Meat and vegetation...Please Help!!!
For A&B
Answer:
A. 40N
B. 5m/s
Explanation:
A.
Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:
Area of a triangle = (1/2)bh
A=(1/2)*8*10
=40
ANSWER: 40N
B.
Impulse = mass * velocity
40 = 8v
v = 5
ANSWER: 5m/s
A ball is rolling down a hill. Wich action would slow the ball down?
what is the movement of energy by waves
Answer; thermal energy
Explanation:
'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.
gravitational potential is the energy due to an object's:
a. motion
b. spring stretch or compression
c. position in a gravity field
d. chemical bonds.
position in a gravitation field (c)
Answer:
The answer is C. position in a gravity field
Speed and time play a major factor in:
Scrimmage
Tactical movement
Situation awareness
Drill
Answer:
Tactical movement
Explanation:
Speed and time play a significant factor in Tactical movement. The correct option is B.
What is a Tactical movement?Tactical movement refers to the coordinated and strategic movement of military units or teams to achieve a specific objective. It is a fundamental aspect of military operations and involves the use of various tactics and techniques to move troops and equipment safely and efficiently on the battlefield.
Tactical movement can involve various modes of transportation, such as on foot, in vehicles, or by air. It also involves the use of cover and concealment to avoid detection by the enemy, and the use of communication and signal systems to coordinate movements and maintain situational awareness.
The success of the tactical movement depends on many factors, including the terrain and weather conditions, the size and composition of the units involved, the available resources and equipment, and the tactics and strategies employed by both friendly and enemy forces. It requires careful planning, training, and execution to ensure that the movement is successful and achieves the desired outcome.So, tactical movement is an essential component of military operations, and plays a critical role in achieving victory on the battlefield.
Here in the Question,
Tactical movement refers to the movement of military units or teams in a coordinated and strategic manner to achieve a specific objective. In such movements, speed and time are critical factors because they determine the success or failure of the mission. The speed of movement can help to surprise the enemy, take advantage of a weakness in their defense, or seize a key position before they can respond. Time is also important because the longer it takes to achieve the objective, the more likely the enemy is to detect and counter the movement. Therefore, tactical movement requires careful planning and execution to ensure that the right units move at the right speed and at the right time to achieve the desired outcome.
Therefore, the correct option is B i.e Tactical movement.
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What is the gravitational potential energy of a 4 kg bowling ball 1 m above the ground?
Answer:
40 J
Explanation:
Gpe= mgh
=4*10*1
=40
If you were to find 2 fossils, give the reasons for the way you might be able to tell which fossil is older?
Answer:
Relative Dating
Explanation:
Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages. Absolute dating is used to determine a precise age of a fossil by using radiometric dating to measure the decay of isotopes, either within the fossil or more often the rocks associated with it.
A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Answer:
the distance in meters traveled by a point outside the rim is 157.1 m
Explanation:
Given;
radius of the disk, r = 50 cm = 0.5 m
angular speed of the disk, ω = 100 rpm
time of motion, t = 30 s
The distance in meters traveled by a point outside the rim is calculated as follows;
[tex]\theta = \omega t\\\\\theta = (100 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m[/tex]
Therefore, the distance in meters traveled by a point outside the rim is 157.1 m
1. You are given a bottle that contains 4.59 cm of a metallic solid. The total mass of the bottle
is 35.66 g. The empty bottle weighs 14.23 g. What is the density of the solid?
You and a friend are playing with a bowling ball to demonstrate some ideas of Rotational Physics. First, though, you want to calculate the Rotational Kinetic Energy of the bowling ball as it rolls down a sidewalk without slipping. This means it has both linear kinetic energy and rotational kinetic energy. A bowling ball can be modeled as a solid sphere rotating about its center. This bowling ball has a mass of 6.40 kg and a radius of 0.130 m. You'll need to look up the equation for the Moment of Inertia in your textbook. It is rotating with an angular velocity of 16.0 radians / second in the counter-clockwise (or positive) direction. You can use this to determine the linear velocity of the bowling ball (since it is rolling without slipping). What is the Total Kinetic Energy of the bowling ball
Answer:
K_{total} = 19.4 J
Explanation:
The total kinetic energy that is formed by the linear part and the rotational part is requested
[tex]K_{total} = K_{traslation} + K_{rotation}[/tex]
let's look for each energy
linear
[tex]K_{traslation}[/tex] = ½ m v²
rotation
[tex]K_{rotation}[/tex] = ½ I w²
the moment of inertia of a solid sphere is
I = 2/5 m r²
we substitute
[tex]K_{total}[/tex] = ½ mv² + ½ I w²
angular and linear velocity are related
v = w r
we substitute
K_{total} = ½ m w² r² + ½ (2/5 m r²) w²
K_{total} = m w² r² (½ + 1/5)
K_{total} = [tex]\frac{7}{10}[/tex] m w² r²
let's calculate
K_{total} = [tex]\frac{7}{10}[/tex] 6.40 16.0² 0.130²
K_{total} = 19.4 J
Piano tuners tune pianos by listening to the beats between the harmonics of two different strings. When properly tuned, the note A should have the frequency 440 Hz and the note E should be at 659 Hz. The tuner can determine this by listening to the beats between the third harmonic of the A and the second harmonic of the E. A tuner first tunes the A string very precisely by matching it to a 440 Hz tuning fork. She then strikes the A and E strings simultaneously and listens for beats between the harmonics. What beat frequency indicates that the E string is properly tuned
Answer:
The beat frequency = 2.0 Hz
Explanation:
From the given information
The 3rd harmonic frequency of the note is equivalent to thrice note A fundamental frequency.
i.e.
[tex]f_{3A} = 3f_A[/tex]
where;
[tex]f_A =[/tex] note A fundamental freq.
replacing 440 Hz for [tex]f_A[/tex]
[tex]f_{#a} = 3 (440 \ Hz)[/tex]
[tex]f_{3A} = 1320 Hz[/tex]
However, the 2nd harmonic of the E is equivalent to two times the fundamental frequency of the note E.
i.e.
[tex]f_{2E} = 2f_E[/tex]
[tex]f_E =[/tex] note E fundamental freq.
replacing 659 Hz for [tex]f_E[/tex]
[tex]f_{2E} = 2(659)[/tex]
[tex]f_{2E} = 1318 \ Hz[/tex]
Finally, the beat frequency when the E string is properly tuned is:
[tex]\Delta f = f_{3A}-f_{2E}[/tex]
[tex]\Delta f = 1320 \ Hz - 1318 \ Hz[/tex]
[tex]\Delta f = 2.0 \ Hz[/tex]
Thus, the beat frequency = 2.0 Hz
Determine the activity of the sample of cerium when the sample was 80 seconds old
Answer is in a photo. I can only upload it to a file hosting service. link below!
bit.[tex]^{}[/tex]ly/3a8Nt8n
What structure is represented by the letter C?
PLEASE HELP!!!!!!!!!!!!!
Choose 1 answer:
A) Lysosome
B) Nucleus
C) Vacuole
D) Mitochondria
Answer:
The picture is blacked out.
Answer:
If I'm correct the answer would be A) Lysosome.
The attachment is black so I can't promise you that it's the one you're looking for. But I did it on khan
: A small block with mass 0.130 kg is attached to a string passing through a hole in a frictionless, horizontal surface. The block is originally revolving in a circle with a radius of 0.800 m about the hole with a tangential speed of 4.00 m/s. The string is then pulled slowly from below, shortening the radius of the circle in which the block revolves. The breaking strength of the string is 30.0 N. What is the radius of the circle when the string breaks
Answer:
r = 0.0173 m = 1.73 cm
Explanation:
Here, the centripetal force of the block will be providing the required breaking tension in the string:
[tex]Tension = Centripetal Force\\T = F_c\\\\T = \frac{mv^2}{r} \\\\r = \frac{mv^2}{T}\\[/tex]
where,
r = radius = ?
m = mass of block = 0.13 kg
v = tangential spee of block = 4 m/s
T = Breaking Strength = 30 N
Therefore,
[tex]r = \frac{(0.13\ kg)(4\ m/s)^2}{30\ N}[/tex]
r = 0.0173 m = 1.73 cm
When finding the radius of the string at the point it breaks, the tangential
velocity is assumed to be constant.
The radius when the string breaks is [tex]\underline{6.9 . \overline 3 \times 10^{-3}} \ m[/tex]Reasons:
The mass of the small block, m = 0.130 kg
Initial radius of the circle of rotation = 0.800 m
Tangential velocity, v = 4.00 m/s
The radius of the path of rotation is reduced as the string is pulled
Breaking strength of the string = 30.0 N
Required:
The radius of the circle when the string brakes
Solution:
[tex]Centripetal \ force = \dfrac{m \cdot v^2}{r}[/tex]
Where;
r = The radius of the circle of rotation
When the string brakes, w have;
Centripetal force = Breaking strength of the string = 30.0 N
Which gives;
[tex]\displaystyle r = \mathbf{\dfrac{m \cdot v^2}{Centrifugal \ force}} = \frac{0.130 \times 4^2}{30} =6.9\overline 3 \times 10^{-2}[/tex]
The radius of the circle when, the string breaks r = [tex]\underline{6.9\overline 3 \times 10^{-2}} \ m[/tex]
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The magnetic field due to a utility wire is 0.10 mT when you are at a distance of 10 meters from it. What current (in Amperes) flows through the wire?
Answer:
I = 5000 A
Explanation:
We will use Ampere's Law to calculate the current:
[tex]B = \frac{\mu I}{2\pi r}\\\\[/tex]
where,
B = Magnetic Field Strength = 0.1 mT = 1 x 10⁻⁴ T
μ = Permeability of Free Space = 4π x 10⁻⁷ N/A²
I = Current = ?
r = radius = 10 m
Therefore,
[tex]1\ x\ 10^{-4}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(I)}{2\pi(10\ m)}\\\\I = \frac{(1\ x\ 10^{-4}\ T)(2\pi (10\ m))}{4\pi\ x\ 10^{-7}\ N/A^2}[/tex]
I = 5000 A
PLASES HELP ASAP
A baseball bat company is testing a new alloy that they claim will improve the power of its bats for very weak or low-power batters. Given the provided data of three bat compositions, swing force, and resulting ball travel distance, what conclusion can be made regarding their new alloy? A) There is no hypothesis provided. B) The hypothesis of the company is refuted. C) The hypothesis of the company is verified. D) The hypothesis was neither verified or refuted.
Answer:
B.
Explanation:
I'm not sure if it's the right answer but I think it is. I hope I helped out in some way.
The more mass an object has,the less inertia the object has. True or False
Answer:
This is true. objects that have a greater mass has greater interia. which also means objects that have a less mass has also less interia.
Explanation:
i hope this helps!!!
Does time stop in a black hole
Answer:
In standard GR, nothing exists at the center of a black hole. The center of a black hole is a singularity, and because GR fails at that point it is simply removed from the manifold. That means that the singularity is not part of spacetime.
To answer your question more realistically, we believe that GR is an approximate theory that fails well before you reach the center. Unfortunately, we have no good alternative theory with which to answer the question in the region where GR fails. We simply don’t have any data from that regime and it is very hard to formulate a good theory without data. So there very well could be time at the center, but we simply don’t have a good way to even guess.
Answer:
Black hole is a region of space having a gravitational field so intense that no matter or radiation can escape
Actually time can't be stop.
although black hole slower a time
Explanation:
Time never cannot be stop totally.
Please PLEASE HELP ASAP
A student placed four objects on a plastic tray: a rock, an eraser, a wood block, and an ice cube. The student slowly lifts the tray and measures the height at which each object begins to slide in order to compare the friction of each object. The table above shows the results. In a separate experiment the student used the same objects and tray, but glued a piece of gritty sandpaper to the tray. What results would be expected? A) The items would slide faster at the same heights. B) The items would start to slide when the tray is not lifted as high. C) The items would not slide at all, no matter how high the tray is raised. D) The tray would need to be raised higher before the items start to slide.
Answer:
D) The tray would need to be raised higher before the items start to slide.
Explanation:
The tray would need to be raised higher due to the gritty sandpaper causing it to have more grip or fraction between the two surfaces. In the first experiment it would have a smooth surface to slide across but in the second experiment it would have a rougher surface to slide across.
Example: It would be like taking two different kinds of shoes like tennis shoes and football cleets. Then seeing which one has more traction when going up a hill.
Hope this helps!!