An 81 kg football player moving 6. 5 m/s tackles and collides with a stationary 140 kg football player. What speed will the football players have the moment after impact?

The concept of gravitational force is described by Newton's Law of Universal Gravitation.

Thus, According to this rule, every large particle in the cosmos pulls toward every other large particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of their separation.

This fundamental physical law was inferred by induction from observations.

The law can also be expressed in a more contemporary manner as follows: "Every point mass attracts every other point mass by a force pointing along the line intersecting both points." The force is inversely proportional to the square of the distance between the point masses and is proportional to the product of the two masses and gravitation.

Thus, The concept of gravitational force is described by Newton's Law of Universal Gravitation.

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For the pulley

(a) fc = 1134 lb, fi = 565 lb, (f1)a = 355 lb and f2 = 890 lb

(b) ha = 0.69 in, nfs = 15.4 and belt length = 16.53 ft

In this problem, we are given information about a belt drive system that uses a 6-inch-wide flat belt to connect two pulleys with a certain angular velocity ratio. We are asked to find various parameters, such as the tension in the belt, the center distance between the pulleys, the horsepower delivered by the small pulley, and the service factor.

To solve the problem, we need to use various formulas related to belt drive systems, such as the formula for the tensions in the tight and slack sides of the belt, the formula for the horsepower delivered by the pulley, and the formula for the service factor. We also need to use the given information about the angular velocity ratio, the width of the belt, and the diameter of the pulleys to determine the required belt length and the distance between the centers of the pulleys.

(a)

fc = 1134 lb

fi = 565 lb

(f1)a = 355 lb

f2 = 890 lb

(b)

ha = 0.69 in

nfs = 15.4

belt length = 16.53 ft

Using these formulas and the given information, we can find the required parameters for the belt drive system, including the tensions in the belt, the center distance, the horsepower delivered by the small pulley, and the service factor.

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The precision of an experimental measurement is determined by the smallest possible increment of the measuring instrument. In the case of a tuning fork, the frequency of the fork is the quantity being measured.

If a tuning fork with a larger frequency (f) is used, the resulting oscillations will be more rapid, and the time period between successive oscillations will be shorter. Therefore, measuring the frequency of a high-frequency tuning fork requires a more precise measurement of time. This could lead to a less precise measurement of the frequency because measuring short time intervals accurately can be challenging.

On the other hand, if a tuning fork with a smaller frequency (f) is used, the resulting oscillations will be slower, and the time period between successive oscillations will be longer. Measuring the frequency of a low-frequency tuning fork is less sensitive to small variations in time measurements. Therefore, using a low-frequency tuning fork may result in more precise measurements of the frequency.

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To determine the required takeoff speed at Albuquerque, we need to consider the difference in air density between sea level and the altitude of Albuquerque.

As altitude increases, air density decreases, which can have a significant effect on aircraft performance.

In particular, the reduced air density means that the airplane needs to achieve a higher ground speed in order to generate enough lift to take off.

To calculate the required takeoff speed at Albuquerque, we can use the following equation:

V2 = V1 x √(rho2/rho1)

where:

V1 = takeoff speed at sea level (given as 150 mph)

rho1 = air density at sea level (standard value of 1.225 kg/m^3)

rho2 = air density at Albuquerque (can be looked up or calculated using atmospheric models)

V2 = required takeoff speed at Albuquerque (what we want to find)

Let's assume that Albuquerque is at an altitude of 5,312 feet (the airport elevation).

Using atmospheric models or tables, we can find that the air density at this altitude is approximately 0.860 kg/m^3.

Now we can substitute the values into the equation:

V2 = 150 mph x √(0.860 kg/m^3 / 1.225 kg/m^3)

V2 = 150 mph x 0.806

V2 = 121 mph (rounded to the nearest whole number)

Therefore, the required takeoff speed at Albuquerque is approximately 121 mph. This is lower than the takeoff speed at sea level due to the reduced air density at higher altitudes.

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A larger objective lens allows more light to enter, reducing the effects of diffraction, and increasing angular resolution, resulting in a sharper image.

The primary factor that contributes to a telescope's bigger objective lens producing a sharper image than a telescope with a smaller objective lens is that the larger objective lens enables more light to enter the telescope, which minimises the effects of diffraction. The image becomes blurry and loses information due to diffraction, especially at high magnifications.

A bigger objective lens's enhanced capacity for light collection also enables a higher signal-to-noise ratio, which produces a picture with more clarity and contrast. Last but not least, a bigger objective lens can accommodate a higher angular resolution, enabling the picture to resolve more information.

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The correct question will be: What are the three main advantages of a telescope with a bigger objective lens compared to one with a smaller objective lens?

No, you will not accelerate.

Acceleration is the rate of change of velocity, which is a vector quantity that includes both magnitude and direction. If your velocity did not change in direction, then you did not accelerate.

In your case, you moved one meter in one second while facing north. Since your velocity did not change in direction, you did not accelerate. However, you did have a non-zero average speed of 1 meter per second over that one second interval. Speed is a scalar quantity that only includes magnitude, not direction. So, while you did not accelerate, you did have a non-zero speed for that short period of time.

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--The complete question is, Let's say i was standing in one spot (zero speed facing north). then i took one step (one meter) and it took me a second to do so (still facing north). did i accelerate?--

The voltage of approximately 437.5 V must be applied between the filament and target to achieve 70 eV of kinetic energy for the electrons at the sample source (ss).

To determine the voltage needed for electrons to have 70 eV of kinetic energy at the sample source (ss), we can use the equation for kinetic energy (KE) of an electron, which is KE = 1/2 * m * v^2, where m is the mass of the electron and v is its velocity.

However, we can also utilize the relationship between energy and voltage: KE = eV, where e is the elementary charge (1.6 × 10^-19 C) and V is the applied voltage.

Since we want the electrons to have 70 eV of kinetic energy, we can set KE equal to 70 eV and solve for the voltage V:

70 eV = (1.6 × 10^-19 C) * V

To find V, divide both sides by the elementary charge:

V = 70 eV / (1.6 × 10^-19 C) ≈ 437.5 V

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The work done by the second engine is 2.6 times the work done by the first engine.

The work done by an engine is given by the product of power and time. The first engine works with a constant power of P, so its work done is given by W1 = P*t, where t is the observed time.

The second engine increases its power linearly with time, and its final power is 5.2P. Let the power at time t be

P(t) = kt, where k is the rate of increase of power.

At time t=0, the power is zero, so we have

P(0) = 0.

At time t, the power is kt, so we have

P(t) = kt.

When the power reaches 5.2P, we have

P(t) = 5.2P

so kt = 5.2P, and k = 5.2P/t.

The work done by the second engine is given by

W₂  = ∫P(t)

dt from 0 to t, which evaluates to

W₂ = 1/2 × k × t²

= 1/2 × 5.2P ÷ t × t²

= 2.6P × t.

The ratio of the work done by the second engine to the first engine is

W2 ÷ W1 = (2.6P × t) ÷ (P × t) = 2.6.

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When a charged particle moves perpendicularly to a uniform magnetic field, its trajectory is a circle. Here option B is the correct answer.

When a charged particle moves perpendicularly to a uniform magnetic field, its trajectory follows a circular path. This phenomenon is known as the Lorentz force, named after the Dutch physicist Hendrik Lorentz who discovered it in the late 19th century.

The Lorentz force arises due to the interaction between the magnetic field and the charged particle's electric field. When a charged particle moves through a magnetic field, it experiences a force perpendicular to both the direction of its motion and the direction of the magnetic field. This force causes the charged particle to move in a circular path with a constant radius and a constant speed.

The radius of the circular path is determined by the particle's mass, charge, and speed, as well as the strength of the magnetic field. Specifically, the radius is proportional to the particle's momentum and inversely proportional to the magnetic field strength.

The circular motion of a charged particle in a magnetic field is fundamental to many applications in physics and engineering. For example, it is the basis of the operation of particle accelerators, mass spectrometers, and MRI machines.

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Complete question:

When a charged particle moves perpendicularly to a uniform magnetic field, what best describes its trajectory? when a charged particle moves perpendicularly to a uniform magnetic field, what best describes its trajectory?

A - a sinusoidal curve

B - a circle

C - a straight line

D - a parabola

A device that uses the pressure of fluid to move a piston that is connected to a rod is called a hydraulic cylinder. Hydraulic cylinders are commonly used in many applications where a large force is required to move heavy loads or perform work.

The hydraulic cylinder consists of a cylinder barrel, which contains a piston that is connected to a piston rod. The piston separates the cylinder into two chambers, one on each side. When pressurized fluid is supplied to one of the chambers, it forces the piston to move in the opposite direction, which in turn moves the piston rod.

The force that can be generated by a hydraulic cylinder depends on the size of the piston and the pressure of the fluid. By increasing the pressure of the fluid, a greater force can be exerted on the piston and piston rod, which allows for greater power and efficiency. Hydraulic cylinders are commonly used in heavy machinery, construction equipment, and industrial automation systems.

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a. The voltage supplied to the radio with a single nicad cell can be calculated using Ohm's Law, which states that Voltage (V) = Current (I) x Resistance (R).

The internal resistance of the nicad cell needs to be taken into account, so the total resistance in the circuit is 3.2 Ω + 0.04 Ω = 3.24 Ω. The voltage supplied can be calculated as:

V = (1.25 V - 0.04 V) - I x 3.24 Ω

Assuming a typical current draw of 100 mA (0.1 A), the voltage supplied to the radio would be:

V = (1.25 V - 0.04 V) - (0.1 A x 3.24 Ω) = 1.15 V

Therefore, the voltage supplied to the radio with a single nicad cell would be 1.15 V.

b. Similarly, the voltage supplied to the radio with a single alkaline cell can also be calculated using Ohm's Law, taking into account the internal resistance of the cell and the total resistance in the circuit:

V = (1.58 V - 0.2 V) - I x 3.4 Ω

Assuming the same current draw of 100 mA (0.1 A), the voltage supplied to the radio would be:

V = (1.58 V - 0.2 V) - (0.1 A x 3.4 Ω) = 1.01 V

Therefore, the voltage supplied to the radio with a single alkaline cell would be 1.01 V.

c. When the volume of the radio is turned up, the effective resistance of the circuit is lowered due to the change in the internal resistance of the radio.

This can cause an increase in the current draw and a decrease in the voltage supplied to the radio.

The exact effect will depend on the specific characteristics of the radio and the batteries being used, but it is generally recommended to use fresh batteries or rechargeable cells with a high capacity to ensure optimal performance.

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This means that object C must have an initial velocity of -1 m/s in the x-direction in order for all three objects to end up moving at 0.50 m/s in the x-direction after the collision.

To answer this question, we must first consider the conservation of momentum. In this scenario, we have three objects: a 2 kg object, a 3 kg object, and a 4 kg object. Let's call them A, B, and C, respectively.

Object A is moving in the x-direction with a velocity of 3 m/s, while object B is at rest. Object C has an initial velocity in the x-direction, which we need to determine.

After the collision, all three objects move at a velocity of 0.50 m/s in the x-direction. We know that the total momentum of the system must be conserved, meaning that the sum of the momentum of all three objects before the collision must equal the sum of their momentum after the collision.

Using the equation for conservation of momentum, we can set up the following equation:

(2 kg)(3 m/s) + (3 kg)(0 m/s) + (4 kg)(vx) = (2 kg)(0.50 m/s) + (3 kg)(0.50 m/s) + (4 kg)(0.50 m/s)

Solving for vx, we get:

vx = -1 m/s

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The wavelength of a radio wave can be calculated using the formula:

wavelength (λ) = speed of light (c) / frequency (f)

where the speed of light (c) is approximately 3 x 10^8 meters per second.

In this case, the frequency (f) of the radio wave is 94.8 MHz.

However, this value needs to be converted to units of hertz (Hz) before using the formula.

1 MHz = 1 million Hz, so:

94.8 MHz = 94.8 x 10^6 Hz

Now, we can substitute the values into the formula:

λ = c / f

λ = 3 x 10^8 m/s / (94.8 x 10^6 Hz)

λ = 3.16 meters

Therefore, the wavelength of the radio wave broadcast by the station is approximately 3.16 meters.

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The thickness of the oil film is approximately 607.69 nm

we can determine the thickness of the oil film and the orders of interference using the formula for constructive interference in thin films:

2 * n * t * cos(θ) = m * λ

where n is the refractive index of the oil film, t is the thickness, θ is the angle of incidence (90° since the light is incident normally), m is the order of interference, and λ is the wavelength of light.

For normal incidence, cos(θ) = cos(90°) = 1, so the formula simplifies to:

2 * n * t = m * λ

We're given that the extinction (destructive interference) occurs at wavelengths 525 nm and 675 nm. We need to find the constructive interference (bright fringes) between these wavelengths, so we'll consider the average wavelength:

λ_avg = (525 nm + 675 nm) / 2 = 600 nm

Now we can use the formula to find the thickness:

2 * 1.30 * t = m * 600 nm

We need to find the integer values of m that satisfy the equation for both 525 nm and 675 nm wavelengths.

The closest integer values that work are m = 3 for 525 nm and m = 4 for 675 nm.

Using m = 3 for the 525 nm wavelength:

2 * 1.30 * t = 3 * 525 nm
t ≈ 607.69 nm

Using m = 4 for the 675 nm wavelength:

2 * 1.30 * t = 4 * 675 nm
t ≈ 607.69 nm

The thickness of the oil film is approximately 607.69 nm, and the orders of interference are 3 for the 525 nm wavelength and 4 for the 675 nm wavelength.

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The Chumash cosmology is a complex and intricate belief system that encompasses a wide range of spiritual and cultural practices. According to Chumash tradition, the universe is divided into seven different worlds, each with its own unique characteristics and spiritual significance.

The seven worlds are often depicted as concentric circles, with the earth at the center and the other worlds arranged around it. The outermost world is the world of the sky, followed by the world of the sun, the world of the moon, the world of the stars, the world of the ancestors, the world of the spirit, and finally the world of the creator.

Each of these worlds is believed to be populated by various beings and spirits, and has its own set of rituals and ceremonies associated with it. For example, the world of the sun is associated with the summer solstice and the world of the ancestors is associated with the winter solstice.

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Prior to the Space Shuttle Columbia disaster, the orbiter had been hit by debris from the external tank and solid rocket boosters on numerous occasions.

On February 1, 2003, Space Shuttle Columbia disintegrated as it reentered the atmosphere over Texas and Louisiana, killing all seven astronauts on board. It was the second Space Shuttle mission to end in disaster, after the loss of Challenger and its crew in 1986.

Prior to the Space Shuttle Columbia disaster, the orbiter had been hit by debris from the external tank and solid rocket boosters on numerous occasions. It is difficult to determine the exact number of times, as minor debris strikes were common during launches.

However, significant incidents of debris impact occurred during STS-27 (1988) and STS-112 (2002), among others.

The Columbia disaster, which occurred during the STS-107 mission in 2003, brought attention to the dangers posed by debris strikes and led to significant changes in NASA's policies and procedures for future shuttle missions.

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The resistance of each bulb which are connected in series is 20.571 Ω.

Let's find the resistance of each bulb using the given terms:

1. Voltage of source (V_source) = 120 V
2. Number of bulbs (n) = 10
3. Power of each bulb (P) = 7.0 W

We'll use the formula P = V²/R to find the resistance of each bulb.

1: Find the total power of the series.
Total power (P_total) = n * P = 10 * 7.0 W = 70 W

2: Find the total resistance of the series.
Using the formula P_total = V_source^2 / R_total, we can find R_total:
R_total = V_source² / P_total = (120 V)² / 70 W = 14400 / 70 = 205.71 Ω

3: Find the resistance of each bulb.

Since the bulbs are connected in series, the total resistance is the sum of the individual resistances. Therefore, we can find the resistance of each bulb (R_bulb) as follows:

R_bulb = R_total / n = 205.71 Ω / 10 = 20.571 Ω

So, the resistance of each bulb is approximately 20.571 Ω.

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Using Snell's law, we can find the angle the transmitted ray will make with the normal:

[tex]n1sin(theta1) = n2sin(theta2)[/tex]

Where [tex]n1[/tex] is the refractive index of the incident medium (air), [tex]theta1[/tex] is the angle the incident ray makes with the normal, [tex]n2[/tex] is the refractive index of the second medium (glass), and [tex]theta2[/tex] is the angle the transmitted ray makes with the normal.

[tex](1.00)(sin(31)) = (1.6)(sin(theta2))[/tex]

[tex]theta2 = sin^(-1)((1.00)*(sin(31))/(1.6)) = 19 degrees (rounded to two significant figures)[/tex]

[tex]theta1 = theta_r[/tex]

where [tex]theta_r[/tex] is the angle the reflected ray makes with the normal.

The velocity of the ball as it exits the sand is 6m/s.

When the ball rolls into the sand, it experiences a force of friction acting against its motion, which causes it to slow down. The amount of frictional force depends on the properties of the sand and the ball's velocity. Assuming that the ball rolls horizontally into the sand and comes out horizontally as well, the conservation of momentum applies, which means that the momentum of the ball before it enters the sand is equal to the momentum of the ball after it exits the sand.

We can use the equation for conservation of momentum to calculate the final velocity of the ball:

Initial momentum = Final momentum

mv1 = mv2

where m is the mass of the ball, v1 is the initial velocity of the ball, and v2 is the final velocity of the ball.

Substituting the given values, we get:

2 kg x 6 m/s = 2 kg x v2

12 kg m/s = 2 kg x v2

v2 = 6 m/s

Therefore, the final velocity of the ball as it exits the sand is 6 m/s.

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Adding more mass to a 1.4-solar-mass neutron star can cause it to collapse into a black hole via a hypernova explosion.

If more mass was added to a 1.4-solar-mass neutron star, it could eventually become a black hole via a hypernova explosion. This is because the gravitational force within the star would increase, causing the star to contract and increase in density. As the density increases, the neutron star would become more and more unstable, and eventually, it would undergo a catastrophic collapse, causing a supernova explosion.

If the resulting remnant after the supernova explosion has a mass greater than about 2-3 solar masses, the gravitational force would be so strong that it would overcome the neutron degeneracy pressure and form a black hole. The process of this formation is known as a hypernova explosion, which is a type of supernova that produces a large amount of energy and ejects a significant amount of material into space.

Therefore, the most likely outcome if more mass is added to a 1.4-solar-mass neutron star is that it would eventually collapse into a black hole via a hypernova explosion.

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The carbon cycle involves both biotic (living) and abiotic (non-living) components.

Abiotic components of the carbon cycle include:

Atmosphere: The atmosphere is a major abiotic component of the carbon cycle. Carbon dioxide (CO2) is a greenhouse gas that makes up a small percentage of Earth's atmosphere (currently around 0.04%). Carbon dioxide is released into the atmosphere through processes such as respiration, combustion of fossil fuels, and volcanic eruptions. It can also be absorbed from the atmosphere through processes such as photosynthesis and dissolution in bodies of water.

Oceans: The world's oceans are a significant abiotic component of the carbon cycle. They act as a sink for carbon dioxide, absorbing large amounts of it from the atmosphere. Carbon dioxide dissolves in seawater to form carbonic acid, which can then undergo various chemical reactions to form bicarbonate ions and carbonate ions. These dissolved forms of carbon can be transported and stored in the deep ocean for long periods of time, a process known as oceanic carbon sequestration.

Soil: Soil is another abiotic component of the carbon cycle. Dead plant material and other organic matter that accumulates in soil can undergo decomposition by microorganisms, releasing carbon dioxide back into the atmosphere through a process called soil respiration. Additionally, carbon can be stored in soil as organic carbon, which can remain in the soil for years to centuries depending on environmental conditions.

Geological formations: Carbon can also be stored in abiotic reservoirs such as geological formations, including fossil fuels such as coal, oil, and natural gas. These fossil fuels are formed from ancient organic matter that has been buried and preserved in the Earth's crust over millions of years. When these fossil fuels are burned for energy, carbon is released into the atmosphere as carbon dioxide, contributing to the increase in atmospheric carbon dioxide concentrations.

These abiotic components of the carbon cycle play a crucial role in regulating the balance of carbon between the atmosphere, oceans, soil, and geological formations, and are important in understanding the overall carbon cycle and its impact on the Earth's climate.

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The total change of mechanical energy in the system is negative and is equal to [tex]-(3/2)mv^2[/tex].

The total change of mechanical energy in the system can be calculated by finding the initial mechanical energy of the system and subtracting the final mechanical energy.

The initial mechanical energy of the system is:

[tex]E_i = (1/2)mv^2 + (1/2)(2m)v^2 = (1/2)mv^2 + mv^2 = (3/2)mv^2[/tex]

Since the blocks are moving in opposite directions, they will collide and stick together. After the collision, the combined mass will be 3m and the velocity will be zero. The final mechanical energy of the system is:

[tex]E_f = (1/2)(3m)(0)^2 = 0[/tex]

The total change of mechanical energy in the system is:

[tex]ΔE = E_f - E_i = - (3/2)mv^2[/tex]

Therefore, the total change of mechanical energy in the system is negative and is equal to [tex]-(3/2)mv^2[/tex]. This indicates that some energy was lost during the collision, possibly due to friction or deformation of the blocks.

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If the generator frequency is 391 rad/s then the RMS current in the purely inductive ac circuit having a maximum voltage of 180 V and inductance of 0.16 h is 2.03 A.

We'll find the RMS current in the purely inductive AC circuit using the given terms: angular frequency (ω), maximum voltage (V_max), inductance (L), and RMS current (I_rms).

Here are the steps to calculate the RMS current:

1. Determine the impedance (X_L) of the inductor using the formula:
  X_L = ω × L
  X_L = 391 rad/s × 0.16 H
  X_L = 62.56 Ω

2. Calculate the RMS voltage (V_rms) using the formula:
  V_rms = V_max / √2
  V_rms = 180 V / √2
  V_rms = 127.28 V

3. Determine the RMS current (I_rms) using Ohm's Law:
  I_rms = V_rms / X_L
  I_rms = 127.28 V / 62.56 Ω
  I_rms = 2.03 A

The RMS current in the circuit is 2.03 A.

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Assuming the rifle recoils in the same direction as the bullet, the velocity of the rifle after recoil would be 5.44 m/s.

Velocity is a vector quantity that measures the rate of change in the position of an object. It is expressed as a speed and a direction. Velocity is a measure of the rate and direction of motion of an object, and is equal to the displacement of the object divided by the time taken for the displacement. The units of velocity are usually expressed in terms of meters per second (m/s).

This can be calculated using the equation of conservation of momentum, which states that the total momentum of a system must remain constant. Thus, the momentum of the bullet (0.01 kg× 300 m/s) must be equal to the momentum of the rifle (45 kg× v), where v is the velocity of the rifle after recoil. Solving for v yields 5.44 m/s.

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The maximum voltage induced in the loop is 82.05 volts. The EMF is negative.

The maximum voltage induced in the loop can be calculated using the formula:

EMF = -NΔΦ/Δt

Where EMF is the induced electromotive force, N is the number of turns in the loop, ΔΦ is the change in magnetic flux, and Δt is the time interval over which the change occurs.

In this case, the loop has an area of 0.08 m2 and is rotating at a constant angular speed of 87 rev/s, which corresponds to an angular velocity of 544.89 rad/s. The magnetic field is perpendicular to the axis of rotation, so the change in magnetic flux is given by:

ΔΦ = B*A*cos(θ)*Δt

Where B is the magnetic field strength, A is the area of the loop, θ is the angle between the magnetic field and the normal to the loop (which is 90 degrees in this case), and Δt is the time interval over which the change occurs.

Since the loop is rotating at a constant speed, the time interval over which the change occurs is equal to the time it takes for the loop to complete one revolution, which is:

Δt = 1/87 s

Plugging in the given values, we get:

ΔΦ = (0.08 T)*(0.08 m2)*(1)*(1/87 s) = 0.000921 Tm2/s

Next, we can calculate the induced EMF using the formula:

EMF = -NΔΦ/Δt

Plugging in the given values, we get:

EMF = -(1017)*(0.000921 Tm2/s)/(1/87 s) = -82.05 V

Since the EMF is negative, this means that the induced voltage is in the opposite direction to the direction of the current flow in the loop.

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Water at sea level can be theoretically lifted by a vacuum pump up to a maximum height of 10.3 meters.

In order to create a partial vacuum, a vacuum pump is a type of pump device that removes gas particles from a sealed space.What is the purpose of a vacuum pump?

Vacuum pumps, in the simplest terms, are mechanical devices that make it possible to remove gas and air molecules from a sealed space to produce a space free of gas and/or air. Their main functions are to clean and seal. Depending on the media being pumped through them, vacuum pumps are available in wet or dry versions.

The theoretical maximum height that water at sea level can be lifted by a vacuum pump is 10.3 meters. This value is based on the fact that atmospheric pressure can support a column of water up to 10.3 meters high. So, the correct answer is 10.3 m.

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The force needed to lift the car is 8800 N, which is its weight.

In hydraulic systems, forces are transferred from one area to another inside an incompressible fluid, such as water or oil. Most aircraft's landing gear and braking systems are hydraulic. In order to function, pneumatic systems need a compressible fluid like air.

The smaller piston received a 55 N force from the mechanic, and its surface area was 0.015 m². We may determine the pressure used by the mechanic using the pressure formula P = F/A:

P = F/A = 55 N / 0.015 m² = 3666.67 Pa

This pressure is transmitted to the larger piston with an area of 2.4 m². The force on the larger piston can be calculated using the formula F = PA:

F = PA = 3666.67 Pa x 2.4 m² = 8800 N

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To find the current flow in a series circuit with a total resistance of 180 ω and a total voltage of 120 V, we can use Ohm's law,(Ohm’s law states the relationship between electric current and potential difference. The current that flows through most conductors is directly proportional to the voltage applied to it. Georg Simon Ohm, a German physicist was the first to verify Ohm’s law experimentally.)

which states that current (I) equals voltage (V) divided by resistance (R), or

I = V/R. Therefore, the current flow in this circuit would be:

I = 120V/180Ohm

I = 0.67 amperes (A)

So, the current flow in this series circuit is 0.67 A.

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