An acorn falls from rest from the top of a 19m tall oak tree. How long does it take for the acorn to fall to the ground? How fast is the acorn going before it hits the ground?

Explanation:

V=lander f. where,

v is the velocity of the sound wave

f is the frequency of sound wave(Hz)

L is the wavelength

so we simply just divide 2500 by 8.2 that gives us 304.88ms-¹

hopefully I get this right!

Bureaucracy theory explains the basis of the systematic formation of any organization and ensures efficiency and economic effectiveness.

Bureaucracy is the theory proposed by Max Weber. It forms the ideal model for the management and administration of the organization and ensures its efficiency of organization into focus.

It includes six basic principles. They are Authority Hierarchy, Division of labor, impersonality, Career Orientation, Formal rules and regulations, and Selection process.

The characteristics of bureaucracy include: It can control and regulate the behavior of people in an organization. It is the organization that has the power to make decisions. The organizations have certain rules to follow by the people.

Bureaucracy is found in large organizations like governments and corporations. It has standardized methods, and procedures to practice. It doesn't allow any flexibility for the organization.

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(a) Because the particles are all separated by the same distance, the distances for F13 and F14 are the same as for F12.

(b) Because particle 4 is three spacings distant from particle 2, the distance for F24 is 3d.

To calculate the net electrostatic force on a given particle, calculate the electrostatic force due to each of the other particles and then add them vectorially.

(a) The electrostatic force between two particles with charges q₁ and q₂ separated by a distance r is given by Coulomb's law as:

F = (1/4πε₀) × |q₁q₂| / r²

where ε₀ is the electric constant.

Using this formula, calculate the electrostatic force on particle 1 due to particle 2, which is:

F12 = (1/4πε₀) × |q₁q₂| / d² = (1/4πε₀) × 4e × e / (0.048 m)²

Similarly, calculate the electrostatic force on particle 1 due to particle 3 and particle 4:

F13 = (1/4πε₀) × |q₁q₃| / d² = (1/4πε₀) × 4e × e / (0.048 m)²

F14 = (1/4πε₀) × |q₁q₄| / (2d)² = (1/4πε₀) × 4e × 12e / (0.096 m)²

The distances for F13 and F14 are the same as for F12 because the particles are all separated by the same distance.

Add the forces vectorially:

F1net = F12 + F13 + F14

The direction of the net force will depend on the signs of the charges and their relative positions.

(b) To find the net electrostatic force on particle 2 due to the other particles, use the same method.

F21 = F12 (since the force is equal and opposite)

F23 = (1/4πε₀) × |q₂q₃| / d² = (1/4πε₀) × e × e / (0.048 m)²

F24 = (1/4πε₀) × |q₂q₄| / (3d)² = (1/4πε₀) × e × 12e / (0.144 m)²

The distance for F24 is 3d because particle 4 is three spacings away from particle 2.

Add the forces vectorially:

F2net = F21 + F23 + F24

The direction of the net force will depend on the signs of the charges and their relative positions.

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a. The energy will be 7350 Joules.

b. Due Due to the object remaining at rest, its kinetic energy is zero.

c. The value obtained is v is 17.1 m/s.

d. When the object was initially at rest at 30 m, all of its energy was putative energy which totalled 7350 J.

PE = mgh = (25 kg)(9.8 m/s^2)(30 m) = 7350 J

Additionally, PE at 5 m is PE = mgh = (25 kg)(9.8 m/s^2)(5 m) = 1225 J. As enforced by the rule of conservation of energy, PE = KE at any point during the fall. Bearing this in mind, at 5 m KE equals 1225 J.

When the object was initially at rest at 30 m, all of its energy was putative energy which totalled 7350 J.

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a) A = 8.0 m South

Since the vector is directly along the South direction, there is no x component.

x component: 0 m

y component: -8.0 m (negative because it's southward)

Component form: A = (0, -8.0)

b) B = -15.0 m at 30° East of North

To find the components, we can use the following relationships:

x component: B_x = B * sin(θ)

y component: B_y = B * cos(θ)

B_x = -15.0 * sin(30°) = -15.0 * 0.5 = -7.5 m

B_y = -15.0 * cos(30°) = -15.0 * (sqrt(3)/2) ≈ -12.99 m

Component form: B ≈ (-7.5, -12.99)

c) C = 12.0 m at 25° South of West

x component: C_x = -C * cos(θ) (negative because it's westward)

y component: C_y = -C * sin(θ) (negative because it's southward)

C_x = -12.0 * cos(25°) ≈ -10.85 m

C_y = -12.0 * sin(25°) ≈ -5.16 m

Component form: C ≈ (-10.85, -5.16)

d) D = 10.0 m at 53° West of North

x component: D_x = -D * sin(θ) (negative because it's westward)

y component: D_y = D * cos(θ)

D_x = -10.0 * sin(53°) ≈ -8.0 m

D_y = 10.0 * cos(53°) ≈ 6.0 m

Component form: D ≈ (-8.0, 6.0)

It will take the toy  5.02 seconds to reach the ground, The speed at which the toy hits the ground is 49.0 m/s.

Free fall is the motion of an object falling solely under the influence of gravity. In free fall, the object experiences an acceleration of 9.8 m/s^2 downwards towards the ground (assuming no air resistance), regardless of its mass or size.

a. To determine the time it takes for the toy to reach the ground, we can use the formula for the height of an object in free fall:

h = (1/2)gt^2

Where h is the initial height, g is the acceleration due to gravity, and t is time.

At the instant the toy is dropped, its initial height above the ground is h = 120.0 m, and the acceleration due to gravity is g = 9.8 m/s^2. Thus, we can rearrange the formula to solve for time:

t = sqrt(2h/g)

t = sqrt(2(120.0 m)/(9.8 m/s^2)) = 5.02 s

So, it will take the toy approximately 5.02 seconds to reach the ground.

b. To find the speed at which the toy hits the ground, we can use the formula for final velocity in free fall:

v = sqrt(2gh)

Where v is the final velocity, g is the acceleration due to gravity, and h is the initial height. At impact, the initial height of the toy is 0 m. Therefore:

v = sqrt(2gh)

v = sqrt(2(9.8 m/s^2)(120.0 m))

v = 49.0 m/s

So, the speed at which the toy hits the ground is approximately 49.0 m/s.

Hence, The toy will fall to the earth in 5.02 seconds, hitting the ground at a speed of 49.0 m/s.

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Answer: check the pic

Explanation:

Answer: the answer is 0.009N

Explanation:   as we know,    force =KqQ/R^2

                                                   F= 9*10^9*3.5*10^-6*3.5*10^-6/(3.5)^2

                                                   F=9*10^-3N

Wire 1 in cross section; the wire is long and straight, carries a current of 4.20 mA out of the page, and is at distance d₁ = 2.58 cm from a surface. Wire 2. which is parallel to wire 1 and also long, is at horizontal distance d-5.05 cm from wire 1 and carries a current of 6.88 mA.

To find the x component of the magnetic force per unit length on wire 2 due to wire 1, we can use the formula for the magnetic force between two parallel current-carrying wires we get

F = μ₀I₁I₂/(2πd)

Where F is the magnetic force per unit length, μ₀ is the magnetic constant (4π x [tex]10^{-7}[/tex]Tm/A), I₁ and I₂ are the currents in the wires, and d is the distance between the wires.

In this problem, we need to find the x component of the magnetic force per unit length on wire 2 due to wire 1. We can break down the problem into components by considering the direction of the magnetic field due to wire 1 at the position of wire 2. The magnetic field due to wire 1 will be perpendicular to both wire 1 and wire 2, and will be directed into the page.

To find the x component of the magnetic force, we need to consider the component of the magnetic force that is perpendicular to wire 2. This component will be directed along the x axis, and will have a magnitude of

[tex]F_{x}[/tex] = Fsinθ

Where θ is the angle between the direction of the magnetic force and the x axis. Since the magnetic force is directed into the page, θ is 90 degrees, and sinθ = 1.

Substituting the values given in the problem, we get

F = (4π x [tex]10^{-7}[/tex]Tm/A)(4.20 x[tex]10^{-3}[/tex] A)(6.88 x [tex]10^{-3}[/tex]A)/(2π*0.0258 m)

F = 3.99 x [tex]10^{-10}[/tex] N/m

Therefore, the x component of the magnetic force per unit length on wire 2 due to wire 1 is

[tex]F_{x}[/tex] = Fsinθ= (3.99 x [tex]10^{-10}[/tex] N/m)(1) = 3.99 x [tex]10^{-10}[/tex] N/m

Hence, the x component of the magnetic force per unit length on wire 2 due to wire 1 is 3.99 x [tex]10^{-10}[/tex] N/m.

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The magnitude of the electric field between the plates is 5.87 × 10^5 N/C.

The electron gains kinetic energy as it is accelerated across the gap of the capacitor. This energy is equal to the work done on the electron by the electric field between the plates of the capacitor. We can use this relationship to determine the magnitude of the electric field.

The kinetic energy gained by the electron can be expressed as:

K = (1/2)mv^2

where K is the kinetic energy, m is the mass of the electron, and v is its velocity. The work done on the electron by the electric field is given by:

W = qEd

where W is the work done, q is the charge of the electron, E is the electric field, and d is the distance between the plates.

Since the electron is negatively charged, it will be accelerated from the negative plate (-Q) to the positive plate (+Q) of the capacitor. The charge on an electron is -1.602 × 10^-19 C. Therefore, the work done on the electron is:

W = qEd = (-1.602 × 10^-19 C)(E)(0.94 m)

The kinetic energy gained by the electron is equal to the work done on it by the electric field, so:

K = W = (1/2)mv^2

Substituting the known values and solving for the electric field gives:

E = (2qK) / (md^2) = (2(-1.602 × 10^-19 C)(0.5m_e(27 m/s)^2)) / ((9.11 × 10^-31 kg)(0.94 m)^2)

where m_e is the mass of the electron.

E = 5.87 × 10^5 N/C

Therefore, the magnitude of the electric field between the plates is approximately 5.87 × 10^5 N/C.

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The orange orb has a surface area, temperature, and a net rate of heat transmission per unit surface area of:

To solve this problem, using the equation that combines rates of heat transfer via radiation, emissivity, and surface area of object:

P_net = εσA(T_orb⁴ - T_sur⁴)

where P_net = net rate of heat transfer via radiation,

ε = emissivity of the object (which is given as 0.418),

σ = Stefan-Boltzmann constant, 5.67 x 10⁻⁸ W/m²K⁴,

A = surface area of the object,

T_orb = temperature of the object, and

T_sur = temperature of the surroundings.

First, find the net rate of heat transfer via radiation:

P_net = 384 W - 362 W = 22 W

Plug in the given values and solve for the surface area:

22 W = 0.418 x 5.67 x 10⁻⁸ W/m²K⁴ x A x (T_orb⁴ - 273⁴)

Solving for A:

A = 4πr² = 4π (d/2)² = 4π (0.1 m)² = 0.1257 m²

where assuming the orange orb is a sphere with a diameter of 0.1 m.

Solve for the temperature of the orange orb:

22 W = 0.418 x 5.67 x 10⁻⁸ W/m²K⁴ x 0.1257 m² x (T_orb⁴ - 273⁴)

T_orb⁴ - 273⁴ = 22 W / (0.418 x 5.67 x 10⁻⁸ W/m²K⁴ x 0.1257 m²) = 97417 K⁴

Taking the fourth root of both sides:

T_orb = (97417 K⁴ + 273⁴)^(1/4) = 363.7 K

Calculate the net rate of heat transfer per unit surface area:

P_net/A = 22 W / 0.1257 m² = 175.1 W/m²

Therefore, the surface area of the orange orb is 0.1257 m², its temperature is 363.7 K (90.5°C), and the net rate of heat transfer per unit surface area is 175.1 W/m².

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(a) Ax=2.00 m and Ay--1.00 m, the angle of the vector is  153.4⁰.

(b) Ax=2.00 m and Ay= 1.00 m, the angle of the vector is 26.6⁰.

(c) Ax= -2.00 m and Ay 1.00 m, the angle of the vector is 333.43⁰.

(d) Ax= -2.00 m and Ay = -1.00 m, the angle of the vector is 206.6⁰.

The angle of the vectors is known as the direction of the vectors and it is calculated as follows

(a) Ax=2.00 m and Ay--1.00 m, the angle of the vector;

tan θ = Ay/Ax

tan θ = (-1/2)

θ = arc tan (-1/2)

θ = -26.6⁰ = (180 - 26.6⁰)  = 153.4⁰ (2nd quadrant).

(b) Ax=2.00 m and Ay= 1.00 m, the angle of the vector;

tan θ = Ay/Ax

tan θ = (1/2)

θ = arc tan (1/2)

θ = 26.6⁰ (1st quadrant).

(c) Ax= -2.00 m and Ay 1.00 m, the angle of the vector;

tan θ = Ay/Ax

tan θ = (-1/2)

θ = arc tan (-1/2)

θ = -26.6⁰ = (360 - 26.6⁰) =  333.43⁰ (4th quadrant).

(d) Ax= -2.00 m and Ay = -1.00 m, the angle of the vector;

tan θ = Ay/Ax

tan θ = (1/2)

θ = arc tan (1/2)

θ = 26.6⁰ =  (180 + 26.6⁰) = 206.6⁰ (3rd quadrant).

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if I'm here, and you are not, then the difference between the space of being here or not is it presence itself. Space is a three-dimensional continuum containing positions and directions.

A three-dimensional continuum that contains locations and directions is called space. Physical space is frequently imagined in three linear dimensions in classical physics. Modern physicists often believe that it eventually becomes a part of spacetime, an unbounded continuum of four dimensions. It is believed that grasping the idea of space is essential to comprehending the physical cosmos. Philosophers dispute on whether it is a thing in and of itself, a connection between entities, or a component of a conceptual framework.

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Answer:

C

Explanation:

Since we can't go to the center of Earth, we have to rely on indirect observations of the materials of the interior. The seismic waves are generated by earthquakes and explosions that travel through Earth and across its surface. Thanks to that, it reveals the structure of the interior of the planet. Thousands of earthquakes occur every year, and each one provides a glimpse of the Earth's interior.

Visualizing your objectives aids in sustaining inspiration by making your ambitions more perceptible and attainable.

By contemplating the actions required to reach a desired outcome, individuals can foster lucidity and guidance, thereby pleasing them with determination for moving forward. Additionally, focusing on the process of accomplishment through visualization helps divide the steps needed to attain those objectives, thus reducing their complexity, making it less menacing, and rendering them easier to achieve.

Various strategies towards increasing self-discipline were also proposed: setting apparent goals, creating schedules, sidestepping enticement, and practicing mindfulness amongst others.

Personally, I find that determining clear-cut aims and scheduling activities are the most productive tactics to pursue. This approach establishes definite targets and creates an environment that favors concentration whereby dedicating time for working towards set purposes becomes convenient.

This system constructs accountability while instilling discipline as daily progression is made toward target achievements during scheduled times - this encourages further motivation and commitment.

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Note that this prompt has to do with Vision Setting, motivation and Self Discipline.

The connection between maintaining motivation and visualization is undeniable. Visualization involves the creation of a mental image that represents your desired outcome, allowing you to keep your eyes on the prize, which helps increase motivation levels.

Note that, breaking down the steps needed to achieve your goals through visualization can make the process less daunting while ensuring consistent progress towards success. Mental checkpoints where achievements are recognized further strengthen one's resolve, thus fueling motivation for even greater accomplishments.

Developing self-discipline is crucial and comes with various techniques for improving it. Optimizing productivity can sometimes be challenging for individuals like myself who struggle with distractions while working.

Fortunately, creating a detailed schedule has always been an effective solution for managing such situations. By factoring-in designated time slots within this timetable per individual tasks, focusing intently can be achieved without succumbing to environmental disturbances experienced in regular work environments.

To additionally promote personal drive during these sessions of focus-creation we should endeavor attainable objectives which will boost our overarching mission amid these intentional work segments.

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The coefficient of kinetic friction between the block and the horizontal surface is approximately 0.32, The correct choice is a.

We can use conservation of energy to solve this problem. Initially, the block has kinetic energy, which is gradually dissipated by friction until it comes to rest at the maximum displacement from equilibrium.

The initial kinetic energy of the block is:

K = (1/2) * mv²

where m is the mass of the block and v is its speed. Plugging in the given values, we get:

K = (1/2) * (2.0 kg) * (2.6 m/s)² = 6.76 J

At the maximum displacement from equilibrium, all of this energy has been dissipated by friction and converted into potential energy stored in the spring:

U = (1/2) * k * x²

where k is the spring constant and x is the maximum displacement from equilibrium. Plugging in the given values, we get:

U = (1/2) * (250 N/m) * (0.20 m)² = 5 J

Since energy is conserved, we can set K equal to U:

K = U

(1/2) * mv² = (1/2) * k * x²

Solving for the coefficient of kinetic friction, we get:

μk = (kx² - mv²) / (mgx)

where g is the acceleration due to gravity. Plugging in the given values, we get:

μk = [(250 N/m) * (0.20 m)² - (2.0 kg) * (2.6 m/s)²] / [(2.0 kg) * (9.81 m/s²) * (0.20 m)]

μk ≈ 0.32

Option a is correct.

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Answer:
The force between the two balloons can be calculated using Coulomb's law:

F = k * (q1 * q2) / r^2

Substituting the given values, we get:

F = 9 × 10^9 * (5 × 10^-9 * (-4 × 10^-9)) / (0.025)^2

F ≈ -1.44 × 10^-4 N

The force between the two balloons is approximately -1.44 × 10^-4 N. The negative sign indicates that the force is attractive.

The value of the heat changes is as follows:

The heat quantity of the cup, Qcup is calculated using the formula below:

Q = mcΔT

where;

The heat absorbed by the glass cup, Qcup will be:

Qcup = 104 * 0.385 * (15.4- 22.0)

Qcup = -271 J

The heat absorbed by the water, Qwater will be:

Qwater = 330 * 4.184 * *(15.4 - 22.5)

Qwater = -12284 J

The mass of the ice, Mice, that melted will be:

Heat absorbed by ice = Heat released by water + heat released by cup

-MiceΔHf = Qwater + Qcup

where

Mice = -(Qwater + Qcup) / ΔHf

Mice = -(-1228 - 271) / 333.55

Mice = 38.95 g

Finally, the heat absorbed by the ice will be:

Qice = mcΔT

Qice = (38.95 g) (2.108 J/g°C) (15.4°C - (-8.7°C))

Qice = 3951 J

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(i) To show that chlorophyll is necessary for photosynthesis.

ii) Starch test and potassium iodide are mainly used for the test.

iii) Variegated leaf/Coleus leaf (leaf having non-green and green regions)

iv) After performing the starch test, part A turns blue-black with Iodine solution and part B turns brown with the Iodine solution.

The process of photosynthesis can be influenced by various elements, encompassing:

1. Illumination intensity: The generation of photosynthesis necessitates energy from light; hence, lighting strength is a crucial commodity. Plants possess a limit of tolerance in regards to the luminosity they receive, so excessive or insufficient amounts of light most likely lead to reduced rates of photosynthesis.

2. Levels of Carbon Dioxide: Carbon dioxide plays an essential role as it responds within the process of photosynthesis, making its environmental abundance consequential. Higher carbon dioxide volumes increase photosynthetic velocity while low capacities have a decremental effect on the reaction's rate.

3. Temperature: This chemical recation is quite temperature-sensitive. Elevated temperatures can instigate denaturation of enzymes involved in this intricate process whereas extremely cool conditions decrease reaction celerity.

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the new volume of the gas is 3.49 L when An external force performs 180 J of work as it compresses the gas at constant pressure.

An ideal gas is a theoretical gas comprised of numerous randomly moving point particles that do not interact with one another. The ideal gas notion is valuable because it obeys the ideal gas law, which is a simplified equation of state, and is susceptible to statistical mechanics analysis. Work is pressure times change in volume.

Given,

initial Volume V₁ = 3.5 L

initial pressure P = 7.9 × 10⁴ Pa

Work = 180J

Work W = PΔV

180 J = 7.9 × 10⁴ Pa × ( 3.5L - V₂ )

2.27 × 10⁻³ =  0.0035m³ - V₂

3.5 - 2.27 × 10⁻³  = V₂

V₂ = 3.49 L

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The unstretched length of the bungee cord is  29.4 m.

Simple harmonic motion is a type of periodic motion in which the displacement of an object from its equilibrium position is directly proportional to the force acting on it and is always directed towards the equilibrium position. It is characterized by a sinusoidal pattern of motion and has many real-world applications, including in oscillations of springs and pendulums.

We can solve this problem by applying the principles of simple harmonic motion (SHM) to the bungee jumper's oscillations.

Let's begin by finding the period of oscillation, T. The time it takes for the bungee jumper to reach the lowest point and return to the same point is one period of oscillation. From the problem, we know that the bungee jumper completes 6 cycles (5 low points plus the initial jump) in 28.0 s. Therefore, the period of oscillation is:

T = 28.0 s / 6 = 4.67 s

Next, we can use the formula for the period of an object undergoing SHM to find the spring constant, k, of the bungee cord:

T = 2π √(m/k)

where m is the mass of the bungee jumper. Rearranging this formula to solve for k, we get:

k = (4π²m) / T²

Substituting the given values, we get:

k = (4π² × 50.0 kg) / (4.67 s)² = 360 N/m

So the spring constant of the bungee cord is approximately 360 N/m.

To find the unstretched length of the bungee cord, we can use the fact that the bungee jumper comes to rest 27.0 m below the level of the bridge. At this point, all of the potential energy from the initial jump has been converted into elastic potential energy stored in the bungee cord. Therefore, the total energy of the system is:

E = mgh = (1/2)kx²

where h is the height from which the bungee jumper initially jumped (we assume that there is no air resistance), and x is the unstretched length of the bungee cord.

Substituting the given values, we get:

(50.0 kg)(9.81 m/s²)(27.0 m) = (1/2)kx²

Solving for x, we get:

x = √[(2mgh)/k] = √[(2 × 50.0 kg × 9.81 m/s² × 27.0 m) / 360 N/m] ≈ 29.4 m

Hence, the unstretched length of the bungee cord is approximately 29.4 m.

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The coefficient of friction between the two surfaces is  tan α.

option B.

The coefficient of friction between two surfaces that are in contact is the ratio of the  force of friction to normal reaction.

Mathematically, the formula for coefficient of friction is given as;

μ = Ff/Fn

where;

For the given diagram,

Ff = mg sinα

Fn = mg cosα

The coefficient of friction;

μ = mg sinα/mg cosα

μ = sinα/cosα = tan α

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Acceleration of the skydiver during the free fall is 4.13 m/s².

1) Mass of the skydiver, m = 83 kg

Weight, W = mg = 83 x 9.8

W = 813.4 N

Free fall acceleration is the acceleration that a body travelling in free fall experiences due to only the gravitational pull of the earth. This is the acceleration brought on by gravity.

Since there is no air resistance, the acceleration of the skydiver during the free fall is the acceleration due to gravity, g.

Freebody diagram is given in Fig.1.

2) Mass of the skydiver, m = 78 kg

Air resistance acting on him, F' = 470 N

mg - 470 = ma

813.4 - 470 = ma

a = 343.4/83

a = 4.13 m/s²

Freebody diagram is given in fig.2.

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The equivalence resistance rounded off to two significant digits is

The equation used to work out the equivalent resistance of two resistors in parallel is as follows:

1/Req = 1/R1 + 1/R2

When R1 and R2 are set at 43 Ohms, we can fill in the placed values like so:

1/Req = 1/43 + 1/43

Simplifying to reduce the equation

1/Req = 2/43

cross multiplying the sides of the equation:

2 x Req = 43

Isolating Req

Req = 43/2

Req = 21.5 Ohms

Req = 22 Ohms to 2 significant figures

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The distance an object moves if 25J of work is done with 3.0N of force is 8.33 m.

For a given amount of force, F, and a given distance, d, the formula for calculating work done is as follows:

Work done = Force x distance

So, the distance would be,

Work done / force = 25/3 = 8.33 m.

Work is the energy exerted by an object when it applies a force to move another object over some distance.

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Answer:

No, positive charges cannot be liberated by the photoelectric effect.

Explanation:

Answer: The answer is 7.75v

Explanation; As we know,

                                    power dissipated= (voltage)^2/resistance

                                             0.4w = v^2/150  

                                                 v^2=0.4w*150ohm

                                                   v^2=60

                                                     v=7.75v

The work done by the woman is independent of the time taken to lift the barbell, as long as the distance lifted remains constant.

The work done by the woman lifting the barbell can be calculated using the formula:

work = force x distance

Assuming the force required to lift the barbell remains constant, the work done is directly proportional to the distance lifted.

Therefore, if the woman lifts the barbell 2.0 m in 5.0 s, the work done is:

work1 = force x distance1 = force x 2.0 m

If she lifts it the same distance in 10 s, the work done is:

work2 = force x distance2 = force x 2.0 m

Since the distance lifted is the same in both cases, the work done by the woman is the same, and can be expressed as:

work1 = work2 = force x 2.0 m

Therefore, the work done by the woman is independent of the time taken to lift the barbell, as long as the distance lifted remains constant.

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