Answer:
220km
Explanation:
A truck traveling at 62 mph brakes to a stop in 175 feet. what was the average acceleration and stopping time?
The average acceleration is -7.09 m/s² and the stopping time is 3.87 sec.
Given,
Final velocity, v = 0
Initial velocity, u = 62 mph
Converting mph to km/h and to m/s, we get
u = 99.2 km/h
Or, u = 27.5 m/s
Displacement, s = 175 feet
Or, s = 53.3 meter
By using the third equation of motion, we get
v² - u² = 2as
0 - (27.5)² = 2 × a × 53.3
Or, acceleration(a) = -7.09 m/s²
Now, by the first equation of motion,
v = u + at
Or, - u = at
-27.5 = -7.09 × t
Or, t = 27.5/7.09
t = 3.87 sec
The stopping time (t) is 3.87 sec
Hence, the average acceleration is -7.09 m/s², and the time is 3.87 sec.
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A 0.050 m solution of the weak acid ha has [h3o ] = 3.77 x 10-4 m. what is the ka for the acid?
a) 5 x 10-3 m
b) 2.8 x 10-6 m
c) 8.0 x 10-7 m
d) 7.0 x 10-8 m
A 0.050 M solution of the weak acid HA has [H3O+] = 3.77 × 10-4 M. What is the Ka for the acid b) 2.8 x 10-6 m.
What is a weak acid solution?Weak acids are acids that do not dissociate completely in solution. A weak acid, in other words, is any acid that is not a strong acid. A weak acid's strength is determined by how much it dissociates: the more it dissociates, the stronger the acid.
Buffering Techniques
They are created by combining a weak acid with its conjugate base or a weak base with its conjugate acid.In an aqueous solution or water, a weak acid partially dissociates into its ions. A strong acid, on the other hand, completely dissociates into its ions in water. A weak acid's conjugate base is a weak acid, while a weak acid's conjugate acid is a weak acid.To learn more about weak acid solution refer to
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Person of weight 80 kg jumped off a platform of height 1 m and safely landed on their feet. what is the magnitude of the momentum change during the collision?
The momentum change is 125440 kg.m/s.
We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by
P = m . v
where P is momentum, m is mass and v is velocity.
Momentum also can be defined by kinetic energy
KE = 1/2 . m . v²
KE = P² / 2m
where KE is kinetic energy
From the question above, we know that:
m = 80 kg
h = 1 m
g = 9.8 m/s²
By conservation of energy, the initial kinetic energy is zero because of the person is in static condition. Hence, the initial momentum is
KEo = Po² / 2m
Po = 0 kgm/s
After the jump, the person will have maximum kinetic energy before landing which can be written
KE = PE
P² / 2m = m . g . h
P² = 2m² . 9.8 . 1
P² = 2.80² . 9.8 . 1
P² = 125440 kg.m/s
The momentum change is
ΔP = P - Po
ΔP = 125440 - 0
ΔP = 125440 kgm/s
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How much work, in kj, can a spring whose spring con-stant is 3 kn/cm produce after it has been compressed 3 cm from its unloaded length?
The work done by the spring in kilojoules is 13.5 KJ.
Spring constant of the spring = 3 KN/cm
[tex] = 3 \times 10 ^{7} \: N/m[/tex]
Spring has been compressed to 3 cm.
So, the displacement covered by the spring = 3 cm
[tex] = \frac{3}{100} = 0.03 \: m[/tex]
Work done by the spring is,
[tex]Work \: done = \frac{1}{2} Spring \: constant × (Displacement ) ^{2} [/tex]
[tex]W = \frac{1}{2} Kx ^{2} [/tex]
[tex]W = \frac{1}{2} \times 3 \times 10 ^{7} \times (0.03) ^{2} [/tex]
[tex]W = 13500 \:Joules[/tex]
Thus, the work done by the spring is 13500 Joules.
Now, the work by the spring in kilojoules is,
[tex]1 \: Kilojoules =1000 \: Joules[/tex]
[tex]1 \: KJ = 1000 \: J[/tex]
[tex]1 \: J = \frac{1} {1000} \:K J[/tex]
[tex]13500 \: J = \frac{13500}{1000}[/tex]
[tex] = 13.5 \: KJ[/tex]
Therefore, the work done by the spring in kilojoules is 13.5 KJ.
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Is there any difference between frame of reference and reference point in physics?
Answer: A frame of reference is a reference point combined with a set of directions. A frame of reference is similar to the idea of a reference point. A frame of reference is defined as a reference point combined with a set of directions. For example, a boy is standing still inside a train as it pulls out of a station.
Explanation: hope this helps!!!!
Imagine you put a canon on the top of a very tall mountain you start firing cannonballs horizontally and each time you add more gun powder to the canon which makes the next cannonball travel further before hitting the ground is it possible that at some point the cannonball will miss the ground what does this have to do with the orbit of the moon
Answer:
Yes
Explanation:
For an object in orbit,
Centripetal force = Gravitational force
mv^2/r = GMm/r^2
v = [tex]\sqrt{GM/r[/tex]
Thus, as long as you get the velocity of the cannonball to be as fast or faster than the value of v above, assuming the effects of air resistance is negligible, then you will get an orbiting cannonball
A(n) ____ option for wimax is one in which a fixed-dish antenna points at the wimax tower from a rooftop or pole.
A(n) line of sight option for WiMAX is one in which a fixed-dish antenna points at the WiMAX tower from a rooftop or pole
There are two components to a WiMAX system:
A WiMAX tower, which functions similarly to a cell phone tower, A single WiMAX tower can cover an area as vast as 3,000 square miles (8,000 square kilometers), or very nearly that.
A WiMAX receiver could be a tiny box, PCMCIA card, or they could be integrated into a laptop like WiFi access is currently.
WiMAX tower stations can establish direct wired connections with high bandwidth to the Internet. It can also establish a line-of-sight microwave link with another WiMAX tower. WiMAX is able to give coverage to remote rural regions thanks to this link to a second tower (commonly referred to as a backhaul) and a single tower's capacity to cover up to 3,000 square miles.
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*2–20. determine the angle θ for connecting member a to the plate so that the resultant of f a fa and f b fb is directed along the positive x axis. also, what is the magnitude of the resultant force?
The angle θ for connecting member a to the plate so that the resultant of f a fa and f b fb is directed along the positive x axis are:
Fa=8sin54.93 in x direction
Fb=6sin40 in x direction
Resultant=10.4
What is magnitude?The term magnitude is defined as the “how much of a quantity”. For instance, magnitude can be used for explaining the comparison between the speeds of a car and a bicycle. It can also be used to explain distance travelled by an object or to explain the amount of an object in terms of its magnitude.
In Physics, magnitude is defined as maximum extent of the size and the direction of an object. Magnitude is used as a common factor in the vector and scalar quantities. By definition, we know that the scalar quantities are those quantities that have magnitude only. Whereas the vector quantities are those quantities that have both magnitude and direction.
There are the different ways in which magnitude can be used. Some of them are:
Magnitude of the earthquakeMagnitude of the charge on an electronMagnitude of the forceMagnitude of the displacementMagnitude of the gravitational force.The magnitude of a number, unlike magnitude of a physical quantity, is not relative to a scale or set of units: the magnitude of 100 is 100. By contrast, magnitude of a ruler is 12 in inches but is 30.48 in centimeters. Outside of the pure mathematics one has to be careful to specify the units in which the magnitude of some quantity is measured.
Therefore magnitude of resultant is:
=[tex]\sqrt{8sin54+936sin40}[/tex]
=10.4
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a key falls from a bridge that is 45 m above the water. it falls directly into a model boat, moving with constant velocity, that is 12 m from the point of impact when the key is released. what is the speed of the boat?
Answer:
H = 1/2 g t^2 time t for an object to fall a distance H
t = (2 H / g)^1/2 = (2 * 45 / 9.80)^1/2 = 3.03 sec for the key to fall 45 m
V = 12 m / 3.03 m/s = 3.96 m/s
a wrench 30 cm long lies along the positive y-axis and grips a bolt at the origin. a force is applied in the direction 0, 4, −3 at the end of the wrench. find the magnitude of the force needed to supply 130 n · m of torque to the bolt. (round your answer to the nearest whole number.)
The magnitude of force required to apply 130 n.m of torque to the bolt is 722.
f = magnitude of force
F = Vector force.
F = f [(0 i + 4 j - 3 k)] (02 + 42 + (-3)2)) = (f/5) (4 j - 3 k)
r = 30 cm = 0.30 m
[tex]\tau[/tex] = Torque = 130
Using the formula
[tex]\tau[/tex] = r x F
130 = (0.30 j) x (f/5) (4 j - 3 k)
130 = (f/5) (-0.9 i)
f = 130 x 5 /0.9 = 722
Hence, 722 is the magnitude of the force needed to supply 130 n.m of torque to the bolt.
What do you mean by the magnitude of force?The magnitude of force is the measure of how strong an impact a physical force has. This can be used in many different situations, such as when you are determining whether or not someone is injured. The police use this measurement to determine if they need to call for backup or evacuate the scene. It is also used in engineering and construction to calculate the amount of pressure that needs to be applied in order for a structure to withstand damage.To learn more about magnitude of force, visit:
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a truck pulls a trailer with a frictional force of 870 n and a coefficient of friction of 0.23. what is the trailer s normal force in n?
A truck that pulls a trailer with a frictional force of 870 n and a coefficient of friction of 0.23 has a normal force of 3782.6 N.
What does frictional force mean?The force that is produced by any two surfaces while coming into contact and sliding against one another is referred to as frictional force.
The following variables impact the frictional force: Surface roughness and the amount of force pressing them together have the biggest impact on these forces.
What triggers friction?The imperfections present between the two surfaces in contact are what produce friction.
Even the smoothest surfaces include tiny abnormalities, and when two surfaces interact with one another, these irregularities cause friction. The friction increases as the imperfections get bigger.
Frictional force can be formulated as
F = uN
here N is the normal force.
⇒N = f/u = 870/0.23
⇒ N = 3782.6N
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Please in complete sentences I already did the first slide but i put it there so you can i have an idea about what its asking
Answer:
The prospect of giving a presentation fills some people with dread, while others relish the experience. However you feel, presenting your work to an audience is a vital part of professional life for researchers and academics. Presentations are a great way to speak directly to people who are interested in your field of study, to gather ideas to push your projects forward, and to make valuable personal connections.
The volume of air in the room is 76.4 m³. The density of the air is 1.2 kg/m³.
Calculate the mass of air in the room.
Answer:
The mass of air in the room is 91.68 kg.
Explanation:
In order to find the mass of air in the room, given that the volume of the air is 76.4 m³ and its density is 1.2 kg/m³, we can use the following formula:
[tex]\boxed{\mathrm {Mass = Density \times Volume}}[/tex]
Substituting the given values into the equation, we get:
[tex]\mathrm{Mass = 1.2 \: kg/m^3 \times 76.4 \: m^3}[/tex]
[tex]= \bf 91.68 \: \mathrm{\bf kg}[/tex]
We have that this is an exercise on the density of liquids and gases.
We have that your data is:
Volume (v) = 76.4 m³Density (d) = 1.2 kg/m³.Mass (m) = ?To calculate the mass. We multiply the density by the volume. Therefore, we apply the following formula:
m = d·v
We substitute our data in the formula and solve
m = (1.2 kg/m³)·(76.4 m³)
m = 91.7 kg
Therefore, the mass of air in the room is 91.7 kg.
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A body is thrown upwards vertically with a velocity of 60m/s. Calculate it’s velocity the height attained after 3 seconds the maximum height attained
The velocity of the body will be 30.6 m/s.
The object's highest vertical point during its trajectory is at its maximum height. Before it reaches the highest point, the item is flying upward; once it reaches that point, it is falling.
The velocity of the body is 60 m/s when thrown vertically upwards.
The maximum height attained by the body after 3 seconds.
Then, the initial velocity of the body is :
u = 60 m/s
t = 3 seconds
Then, using the equation of motion:
v = u - gt , the negative sign indicates that the body is moving opposite to gravity.
Therefore,
v = 60 - (9.8)(3)
v = 60 - 29.4
v = 30.6 m/s
Hence, the final velocity of the body when thrown upwards before it comes to stop is 30.6 m/s.
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Refer to photo , there are seven questions .
In terms of the four forces acting on an airplane, what needs to happen so the forces are balanced? what do we call it when all four forces are balanced on an airplane?
For the four forces to be balanced, thrust must be equal to drag, and lift must equal weight. When this happens we say the airplane is cruising.
The force that resists an aircraft's motion through the air is called drag. Every component of the aircraft produces drag, including the engines. A mechanical force is a drag. It is created when a solid body interacts with and contacts a fluid (liquid or gas). It is not produced by a force field in the sense of a gravitational field or an electromagnetic field, in which two objects can interact without coming into touch with one another.
The solid body needs to be in touch with the fluid for drag to be produced. There won't be any drag if there is no fluid. The velocity difference between a solid object and a fluid causes drag.
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A scientist reads relevant literature and designs her experiment. She repeats her experiment several times and collects an entire set of data every time. As compared to a single data set, the multiple data sets lead her to modified conclusions.
How is skepticism important to the progress of science in this scenario?
In this scenario, skepticism is important to the progression of science as it led to collection of several complete data sets.
In the given scenario, the scientist is performing a experimental scientific method. It is based on observations, hypothesis and experiments. This method is done because of skepticism. Since she performs the experiment multiple times, it leads to collection of several complete data sets.
Skepticism is different from denial. Skepticism allows scientists to come to a logical conclusion with evidence that can be confirmed by others. If a person is in denial, they would simply reject any information that is different from their beliefs even though they were presented with evidence disproving their theory.
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you drive in a straight line at 16.0 m/sm/s for 10.0 minmin, then at 28.0 m/sm/s for another 10.0 minmin.
The average speed is 22 m/s. so, the value is less than 23.0 m/s.
Given:
Time T1 = 16.0 m/s, 10.0 min
Time T2 = 28.0 m/s, 10.0 min.
Average speed = distance / time ;
v = [ 16×10 ×60 + 28×10×60 ] / [ 10×60 + 10×60 ]
v = 22 m /s
What is a real speed?The Actual Speed is the calculated velocity at which the axis is presently moving, as computed from the alternate within side the Transducer Counts repute register. The Actual Speed is in function devices according to second.
Speed has the dimensions of distance divided via way of means of time. The SI unit of velocity is the metre in keeping with the second (m/s), however, the maximum not unusual place unit of velocity in regular utilization is the kilometre in keeping with the hour (km/h) or, within side the US and the UK, miles in keeping with the hour (mph). For air and marine travel, the knot is normally used.
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a jet fighter pilot wishes to accelerate from rest at 5 g to reach mach-3 (three times the speed of sound) as quickly as possible. experimental tests reveal that he will black out if this acceleration lasts for more than 4.9 s . use 331 m/s for the speed of sound.
The greatest speed pilot can reach with an acceleration of 5g before he blacks out is 240 m/s.
The acceleration due to gravity is g.
g = 9.8 m/s²
The acceleration of the jet is,
[tex]Acceleration = Mass \times Gravity[/tex]
[tex]a = m \times g[/tex]
[tex]a = 5 \times 9.8[/tex]
[tex]a = 49 \: m/s ^{2} [/tex]
The acceleration of the jet is 49 m/s².
Let the speed of sound be v.
[tex]v = 331 \: m/s[/tex]
Let the initial velocity of the jet be
[tex]Let \: the \: initial \: velocity \: of \: the \: jet \: [/tex]
[tex]be \: v _i.[/tex]
[tex]v _i = 0[/tex]
The time at which the pilot will black out with 49 m/s² acceleration = 4.9 s
Let the time taken to reach Mach 3 be t.
Then the final velocity will be,
[tex]v _f = 3 \times v[/tex]
[tex]v _f = 3 \times 331[/tex]
[tex]v _f = 993 \: m/s[/tex]
[tex]v _f = v _i + at[/tex]
[tex]993 = 0 + (49)t[/tex]
[tex]t = 20.26 \: s[/tex]
Thus, the time taken to reach Mach 3 is 20.26 s.it is greater than the time interval at which the pilot will black out. So the pilot will black out.
The greatest speed pilot can reach with an acceleration of 5g before he blacks out is,
[tex]v _f = 0 +( 49 \times 4.9)[/tex]
[tex]v _f = 240.1 \: m/s[/tex]
Therefore, the greatest speed pilot can reach with an acceleration of 5g before he blacks out is 240 m/s.
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Explain why atomic theory has changed
What does electric shock do to the human body?
Burns and shocks nerves
Overheats tissues and disrupts nerve functions
Disrupts nerve functions and decreases blood flow
Slows metabolic rate
Burns and shocks nerves are what electric shock does to the human body.
Option A
This is further explained below.
What does electric shock do to the human body?Generally, In order for an electric current to go through the body, nerves are a kind of tissue that presents extremely low resistance.
Pain, tingling, numbness, and trouble moving a limb are some of the symptoms that may result when nerves are damaged by an electric shock.
Other symptoms include difficulties moving a limb altogether. These effects could go away with time, but they might also remain permanently.
In conclusion, Electric shock causes the human body to burn and jolt its nerves.
Choice A
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A student walked 100 meters North, then 100 meters West. How many more meters did the student walk compared to their total displacement from their starting point?
A. The total distance walked is about 71 meters less than the student’s displacement.
B. The total distance walked is double the magnitude of the student’s displacement.
C. The total distance walked is about 59 meters more than the student’s displacement.
D. The total distance walked is equal to the magnitude of the student’s displacement.
Answer:
C. The total distance walked is about 59 meters more than the student’s displacement.
Explanation:
The total distance walked is equal to the magnitude of the student’s displacement is the correct option. The correct answer is (D).
The student walked 100 meters North.
Then, the student walked 100 meters West.
Total distance walked = √(North distance)² + (West distance)²
Total distance walked = √(100)² + (100)²
Total distance walked = √(10000 + 10000)
Total distance walked = √20000
Total distance walked = 141.42 meters
Displacement = √(North distance)² + (West distance)²
Displacement = √(100)² + (100)²
Displacement = √(10000 + 10000)
Displacement = √20000
Displacement = 141.42 meters
The student's total distance walked is 141.42 meters, and their displacement is also 141.42 meters.
The total distance walked to the displacement:
Total distance walked = 141.42 meters
Displacement = 141.42 meters
So, the correct option is D) The total distance walked is equal to the magnitude of the student’s displacement.
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an airplane is flying at a standard altitude of 5 km. a pitot tube mounted at the nose measures a pressure of 0.957 bar. assume the airplane is flying at high subsonic speed and flow is compressible. calculate the velocity of airplane.
The velocity of the airplane will be 301.85 meters per second.
What is the velocity?The velocity of the airplane is given as,
v = m√(γRT)
Where γ is the polytropic index (1.14), R gas constant, and T is the temperature.
An airplane is flying at a standard altitude of 5 km. A pitot tube mounted at the nose measures pressure of 0.957 bar.
From the table, the static pressure (p) and static temperature (T) will be 54019.91 Pa and 255.5 K.
Then the static density is given as,
P = p / RT
P = 54019.91 / (287 x 255.5)
P = 0.737 kg / m³
We know that the formula
[tex]\begin{aligned} \left ( \dfrac{P_o}{P} \right )^{\frac{\gamma -1}{\gamma }} &= 1 + \dfrac{\gamma - 1}{2}m^2\\\\\left ( \dfrac{0.957 \times 10^5}{54019.91} \right )^{\frac{1.4 -1}{1.4}} &= 1 + \dfrac{1.4- 1}{2}m^2\\ \end{aligned}[/tex]
On simplifying, we have
m = 0.9421 kg
Then the velocity of the airplane is given as
v = 0.9421 × √(1.4 × 287 × 255.5)
v = 301.85 m/s
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The half-life of the isotope br3574 is 25.4 minutes. if a 4.0-mg sample is given to a patient, how much of the isotope remains after 90.0 minutes?
half-life of the isotope br3574 is 25.4 minute The amount of isotope remained after 90min = 0.01g
number of periods= time/ half life
= 90/25,=3.6
so at each time 4/3.6=1.1, 1.1/7.2= 0.15 and 0.15/10.8=0.01g
The period of time it takes for one-half of a radioactive isotope to decay is known as the half-life. A given radioactive isotope's half-life is constant; it is unaffected by external factors and independent of the isotope's starting concentration.
or
Half-life is the length of time it takes for a radioactive element to decay to half of its initial value. This suggests that a source's activity has a half-life when it takes time for it to decrease to half its initial value
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the engineer of an intercity train observes a rock slide blocking the train's path 210.0 m ahead and activates the train's emergency brakes. the train decelerates uniformly at 1.6 m/s2 for 12.10 s before reaching the rock slide. what is the speed with which the train reaches the rock slide?
The speed with which the train reaches the rock slide is 19.36 m/s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the initial velocityFinal velocity (v) = 0 m/sTime (t) = 12.1 sDeceleration (a) = –1.6 m/s²Initial velocity (u) =?The initial velocity of the train can be obtained as illustrated below:
–1.6 = (0 – u) / 12.1
Cross multiply
0 – u = –1.6 × 12.1
– u = –19.36
Divide both sides by –1
u = –19.36 / –1
u = 19.36 m/s
Thus, the train uses 19.36 m/s to reach the rock slide
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A person walks clockwise a three-quarter circle of radius 5m from point A to point B. What distance
did the person travel?
23.55 m
7.07 m south west
7.07 m north east
7.07 m north west
Answer:
circumference of circle = 2 π R
S (distance traveled) = 3/4 * 2 π R
S = .75 * 2 * π 5 = 23.55 m
Jollibee takes in Php 190,000 in an 8-hour period. Write a direct variation equation for the
relationship between income and number of hours. Estimate how many hours it would take
the restaurant to earn Php 1,000,000.
The direct variation equation is I = kh and it will take 42.1 hours for the restaurant to earn Php 1,000,000.
The direct variation equation has the form y = kx, where k is the constant proportionality. It is a linear equation with two variables.
In an 8-hour period, Jollibee takes in Php 190000.
The direct variation equation is given as y = kx, where y is directly proportional to x.
Hours worked (h) directly affect income (I), where k is the variational constant.
Therefore,
I = k × h
190000 = k × (8)
k = 23750 / 190000
Now, when the restaurant earns Php 1,000,000.
Therefore, using the direct variation equation:
Income = variable constant × number of hours
I = k × h
1,000,000 = (23750) × h
h = 1,000,000 / 23750
h = 42.1 hours
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What is the minimum diameter of a steel wire if it is to support a mass of 80 kg?
The minimum diameter of a steel wire if it is to support a mass of 80 kg is 1.41 * 10⁻³ m.
What will be the minimum diameter of a steel wire if it is to support a mass of 80 kg?The minimum diameter, d of the steel wire can be calculated thus:
Stress, α = Force/areaα = 5.0 × 10⁸ Pa.
mass, m = 80 kg
Force = 80 * 98 = 784 N
Area = force/α
area = 784/5.0 × 10⁸
area = 1.57 * 10⁻⁶
Area = πd²/4
d = √(4 * area/π)
d = √(4 * 1.57 * 10⁻⁶ * 7/22)
diameter = 1.41 * 10⁻³ m
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Note that the complete question is given below:
What is the minimum diameter of a steel wire if it is to support a mass of 80 kg? The elastic limit of steel is 5.0 × 10⁸ Pa.
when a certain spring is expanded 10 centimeters from its natural position and held fixed, the force necessary to hold it is 2000 dynes. find the work w required to stretch the spring an additional 10 centimeters.
The amount of work needed to extend the spring another 10 centimeters is 176774150.
[tex]\begin{aligned}F &=k x \\2000 &=k \times 10 \\k &=200 \text { dyne } / \mathrm{cm}\end{aligned}[/tex]
[tex]\begin{aligned}W=\int_{10}^{20} k x d x &=\left[\frac{1}{2} k x^2\right]_{10}^{20} \\&=\frac{1}{2} x^{200}\left[20^2-10^2\right] \\&=30000]_{\text {ergs }}\end{aligned}[/tex]
volume of the components:
[tex]\begin{aligned}d v \Rightarrow \pi r^2 d h & \Rightarrow \pi 20^{2} dh\\d v & \Rightarrow 400 \pi d h \\\text { mass } \Rightarrow d m=e d v &=62.5 \times 400 \pi d h \\&=25000 \pi d h\end{aligned}[/tex]
Pumping it to the pool's top requires work
[tex]\begin{aligned}d w &=d m g(10-h)\\d w &=25000 \pi g(10-h) d h \\w &=\int_0^{10} 25000 \pi g(10-h) d h \\w &=\int_0^{10} 25000 \times 3.14 \times 32.17(10-h) d h \\&=2525945\left(10 h-\frac{h^2}{2}\right)_0^{10} \\&=2525345 \times 50 \\&=126267250 \quad \text { foot } \quad \text { pound }\end{aligned}[/tex]
work is necessary to pump 2 feet above: (10+2=12)
[tex]\begin{aligned}w &=2525345\left(12^h-\frac{h^2}{2}\right) \\&=176774150\end{aligned}$$[/tex]
Hence, the amount of work needed to extend the spring another 10 centimeters is 176774150.
What do you mean by work and energy?The transfer of energy from one thing to another is referred to as doing work when two objects are involved in a physics experiment.
As a capacity for work, energy is another definition. When an object is moved in a direction parallel to the direction of the force, this is referred to as doing work.
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12000J is the amount of work required to stretch the spring an additional 10 centimeters.
What do you mean by work?Work is the energy that is moved to or from an item by applying force along a displacement in physics. It is frequently modeled as the result of force and displacement in its most basic form. When a force is applied, it is said to have a component that points in the direction of the displacement of the application point. When a force at its application point contains a component that points in the opposite direction of the displacement, it is said to be doing negative work.
According to the question:
force on a soring, f = k×Δd
from the equation, k = 120
Force required to stretch an additional 10cm f' = 120×10
=1200
Work done to stretch the spring, w= 1200*10 = 12000J
Hence, the work done to stretch the spring is 12000J.
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Why does the total amount of energy before and after
any energy transformations remain the same?
Answer:
Energy cannot be created or destroyed
The total amount of energy remains the same even though it may change forms. The amount of energy before and after any energy transformations remain the same because energy cannot be created or destroyed.
Explanation: