Answer:
The program in Python is as follows:
age = int(input("Age: "))
carryOn = int(input("Carry on Bags [0 or 1]: "))
checkedBags = int(input("Checked Bags [0 or greater]: "))
airFare = 300
if age >= 60:
airFare = 290
elif age <= 2:
airFare = 0
if carryOn == 1:
airFare += 10
if checkedBags == 2:
airFare += 25
elif checkedBags > 2:
airFare += 25 + 50 * (checkedBags - 2)
print("Airfare: ",airFare)
Explanation:
This gets input for age
age = int(input("Age: "))
This gets input for carry on bags
carryOn = int(input("Carry on Bags [0 or 1]: "))
This gets input for checked bags
checkedBags = int(input("Checked Bags [0 or greater]: "))
This initializes the base cost to 300
airFare = 300
This updates the base cost to 290 for adults 60 years or older
if age >= 60:
airFare = 290
This updates the base cost to 0 for children 2 years or younger
elif age <= 2:
airFare = 0
This updates the airFare if carryOn bag is 1
if carryOn == 1:
airFare += 10
if carryOn bag is 0, the airFare remains unchanged
This updates the airFare if checkedBags is 2. The first bag is free; so, only the second is charged
if checkedBags == 2:
airFare += 25
This updates the airFare if checkedBags greater than 2. The first bag is free; so, only the second and other bags is charged
elif checkedBags > 2:
airFare += 25 + 50 * (checkedBags - 2)
if checkedBags is 0 or 1, the airFare remains unchanged
This prints the calculated airFare
print("Airfare: ",airFare)
c Write a program that simulates a magic square using 3 one dimensional parallel arrays of integer type. Each one the arrays corresponds to a row of the magic square. The program asks the user to enter the values of the magic square row by row and informs the user if the grid is a magic square or not. flowchart
Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
Write a Java program named Problem 3 that prompts the user to enter two integers, a start value and end value ( you may assume that the start value is less than the end value). As output, the program is to display the odd values from the start value to the end value. For example, if the user enters 2 and 14, the output would be 3, 5, 7, 9, 11, 13 and if the user enters 14 and 3, the output would be 3, 5, 7, 9, 11, 13.
Answer:
hope this helps
Explanation:
import java.util.Scanner;
public class Problem3 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter start value: ");
int start = in.nextInt();
System.out.print("Enter end value: ");
int end = in.nextInt();
if (start > end) {
int temp = start;
start = end;
end = temp;
}
for (int i = start; i <= end; i++) {
if (i % 2 == 1) {
System.out.print(i);
if (i == end || i + 1 == end) {
System.out.println();
} else {
System.out.print(", ");
}
}
}
}
}