Answer: negative acceleration of 4 m/s^2
Explanation: i took the exam on edge
The one that most likely recounts acceleration in the given scenario would be:
A). Negative acceleration of 4 m/s^2
Given that,
The direction of the object = East
Change in Velocity = Final velocity - Initial Velocity
[tex]= 25 - 65 m/s[/tex]
[tex]= -40 m/s[/tex]
As we know,
Acceleration [tex]=[/tex] Change in Velocity ÷ time
[tex]= -40[/tex] ÷ [tex]10[/tex]
[tex]= -4[/tex] [tex]m/s[/tex]
Thus, option A is the correct answer.
Learn more about "Acceleration" here:
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A football player kicks a ball at a 30o angle from the ground with an initial velocity of 15 m/s. What is the final velocity of the ball when it hits the ground?
Given that,
Angle = 30°
Initial velocity = 15 m/s
We need to calculate the time of flight
Using formula of time of flight
[tex]T=\dfrac{2u\sin\theta}{g}[/tex]
Where, u = initial velocity
g = acceleration due to gravity
Put the value into the formula
[tex]T=\dfrac{2\times15\sin30}{9.8}[/tex]
[tex]T=1.5\ sec[/tex]
We need to calculate the final velocity of the ball
Using equation of motion
[tex]v=u+gt[/tex]
[tex]v=15+9.8\times1.5[/tex]
[tex]v=29.7\ m/s[/tex]
Hence, The final velocity of the ball is 29.7 m/s.
WILL GIVE BRANLIET PLS HELP!!!!! AT LEAST TAKE A LOOK!!!!! I REALLY COULD USE THE HELP!!! SHARE YO SMARTNESSS!!! Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern. Do this using three different methods. The angle to the eighth maximum is 1.12°. The distance from the slits to the screen is 302.0 cm. The distance from the central maximum to the fifth minimum is 3.33 cm. The distance between the slits is 0.000250 m.
Answer:
λ = 6,108 10⁻⁷ m = 610.8 nm
λ = 5.513 10⁻⁷ m = 551.3 nm
Explanation:
Young's double slit experiment results in a pattern consisting of maxima and minima of interference, the maximums are described by the expression
d sin θ = m λ
where d of the distance between the two slits, θ is the angle from the central maximum to the given interference line, λ the wavelength of the radiation and an integer indicating the order of interference
In this exercise they give us several conditions
The first
the angle is 1.12º to the maximum m = 8
the distance between the slits d = 0.000250 m
of the initial equation
λ = d sin θ / m
λ = 0.000250 sin 1.12 / 8
λ = 6,108 10⁻⁷ m = 610.8 nm
The second
the distance from the slits to the screen is L = 302.0 cm = 3.020 m
the distance from the central maximum is y = 3.33 cm = 0.0333 m for interference m = 5
in this case we use that the angle in the experiment is small
tan θ = y / L
tan θ = sin θ / cos θ = sin θ
we substitute
sin θ = y / L
d y / L = m λ
λ = d y / L m
we calculate
λ = 0.000250 0.0333 / (3,020 5)
λ = 5.513 10⁻⁷ m = 551.3 nm
a shot putter accelerates a 7.3kg shot from rest to 14m/s in 1.5r seconds. what average power was developed?
Explanation:
[tex]power = \frac{energy \: expended}{time} [/tex]
m = 7.3kg
u = 0
v = 14m/s
t = 1.5sec
P = (0.5×7.3×14²) ÷ 1.5
P = 476.93
P = 477 watt
The power is 744 watts
The first step is to write out the parameters
mass= 7.3kg
v= 14
u= 0
time= 1.5 secs
power= energy/time
= 0.5×7.3×14²/1.5
= 0.5×7.3×196÷ 1.5
= 715.4÷ 1.5
= 477
Hence the power that was developed is 477 watts
Please see the link below for more information
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If I were to fill a water bottle full of air and go up in elevation, would the water bottle expand or shrink? If I were to fill a water bottle full of air and go down in elevation, would the water bottle expand or shrink? I am at elevation 20000 I think.
Answer:
a. It would shrink
b. It would expand
Explanation:
a. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure decreases with altitude, when we go up in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go higher. Since the atmospheric pressure exerted by the molecules of air in the atmosphere are greater than that exerted by the molecules of air in the water bottle, this causes the volume of the water bottle to decrease and thus shrinks the water bottle until the pressure balances out
b. Since the water bottle is filled with air at atmospheric pressure at 20000 ft, and since atmospheric pressure increases with decreasing altitude, when we go down in elevation.
The pressure exerted by the molecules of air in the water bottle seek to balance out the atmospheric pressure as we go lower. The water bottle expands until the atmospheric pressure outside equals the pressure inside the water bottle.this causes the volume of the water bottle to increase and thus expands the water bottle until the pressure balances out
how does gravitational pull affect planets with the same mass but different distance from the sun?
Answer:
it just pulls them at the same time
Explanation:
What is the formula for calculating the efficiency of a heat engine? Answers:
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, as shown, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 10^2 N/C and separation between the charged plates is 2.0 cm.
Determine the horizontal distance travelled by the electron when it hits the plate.
Answer:
Given that
speed u=4*10^6 m/s
electric field E=4*10^3 N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates to find the horizontal distance traveled by the electron when it hits the plate.
acceleration a=qE/m=[tex]1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}[/tex]=[tex]7*10^{14}[/tex] m/s
now we find the horizontal distance traveled by electrons hit the plates
horizontal distance
[tex]X=u[2y/a]^{1/2}[/tex]
=[tex]4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}[/tex]
=[tex]3*10^{-2}[/tex]= 3 cm
A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the speed of the satellite.
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s
A 2,100-kg pile driver is used to drive a steel beam into the ground. The pile driver falls 5.00 m before coming into contact with the top of the beam, and it drives the beam 12.0 cm farther into the ground before coming to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.
Answer:
858375 N of force is exerted on the pile driver by the beam.
Explanation:
mass of the pile driver m = 2100 kg
distance of fall = 5 m
distance through which the beam is driven = 12 cm = 0.12 m
weight of the pile driver = mg
where g = acceleration due to gravity = 9.81 m/s^2
weight of pile driver = 2100 x 9.81 = 20601 N
work done by gravity in bringing the pile driver done the 5 m height is
work = weight x distance = 20601 x 5 = 103005 J
This work by gravity is also used to do work in driving the beam into the 12 cm depth.
The force exerted by the beam on the pile driver will be proportional to the force used to do the work in driving the beam through the 12 cm depth.
equating the works, we have
103005 = F x 0.12
F = 103005/0.12 = 858375 N of force
Could anyone explain how to size of an image works in a pinhole camera?
A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1 = 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?
Answer:
0.109 m/s
Explanation:
The calculation of the volume flow rate of the water is shown below:-
Av = Velocity ([tex]\pi[/tex])(Radius)^2
= 0.87([tex]\pi[/tex])(0.2)^2
= 0.135258 m^3 / sec
= 0.109371429 m/s
or
= 0.109
So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come
Pluto was first observed in 1930, and its largest moon, Charon, was discovered in 1978. A few years after Charon’s discovery, astronomers were able to observe a series of eclipses as Pluto and Charon passed in front of one another. By studying how the brightness of Pluto and Charon changed as they eclipsed each other, astronomers were able to measure the masses and radii of both Pluto and its moon. What did these measurements imply about the average densities of Pluto and Charon?
Answer:
The average densities of both matches the expected density for objects made from water ice.
Explanation:
Charon's density is 1.2 to 1.3 g / cm3, while Pluto's density is 1.8 to 2.1 g / cm3. This was discovered in many researches and measurements of these two celestial bodies, with the objective of understanding them and promoting efficient scientific knowledge.
With the measurements of the average densities between pluto and Charon it was possible to conclude several statements about them. Firstly, it is possible to see that the two formed independently and at different times, in addition to indicating the existence of few rocks in charon, which is consistent with the average density of objects made mostly of water ice.
Would this be 5.58 g or 5.58 kg?
Answer:
Kg
Explanation:
Answer:
5.58 kg
Explanation:
The SI unit for mass is kg. A Newton is defined as:
N = kg m/s²
So the answer would be 5.58 kg.
fill in the blanks and the following paragraph should correctly describe the behavior of waves A wave is a(n)________ That carries ____ through space. Some waves travel through empty space. Other waves must travel through a material, also known as a _____. Waves transfer energy but not ______.
Answer:
1) current
2) energy
3) medium
4) matter
Explanation:
A wave is a medium that carries energy through space. Some waves travel through empty space. Other waves must travel through a material, also known as an energy. Waves transfer energy but not matter.
What is wave?A wave is a phenomenon that flows across a material medium without leaving any lasting mark. Mechanical or electromagnetic waves can be used to classify it. Transverse and longitudinal are the two main forms.
A disturbance that travels through a medium with a transfer of matter and without a transfer of energy best describes a wave.
The primary distinction between transverse and longitudinal waves is that in transverse waves, wave particles travel perpendicular to the wave's direction, but in longitudinal waves, wave particles move horizontally.
A wave is a medium that carries energy through space. Some waves travel through empty space. Other waves must travel through a material, also known as an energy. Waves transfer energy but not matter.
Hence, the correct answer for the blanks are medium,energy,and matter.
To learn more about the wave, refer to the link;
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What will happen to the astronaut when the jets produce these four forces: 10N, 10N, 9N, 9N?
Incoming solar radiation reaches the earth as visible (mostly yellow) light. After being absorbed by the Earth’s surface (heating it), this energy is radiated by the Earth at what wavelength of the electromagnetic spectrum of radiation (the answer is a single word, not a number)____
Answer:
Infrared
Explanation:
Infrared radiation is the form of light that is invisible to eye but can be felt as warmth.
Electromagnetic radiation has gamma rays, ultraviolet rays, x- rays , visible light and infrared radiation, etc.
The heated surface usually emits infrared radiations .They form a continuous spectrum.
Infra red radiation are used in different processes such as heat sensors, thermal imaging and night vision equipment.
Broadly they can be divided into three group near, middle and long infrared radiations.
These radiations can be seen with the eyes with special equipment or under certain conditions.
Which of the following would double the amount of current flowing through a piece of metal wire? Which of the following would double the amount of current flowing through a piece of metal wire? Quarter the voltage across it. Quadruple the voltage across it. Double the voltage across it. Halve the voltage across it.
Answer:
Double the voltage across it.
Explanation:
From Ohm's Law, we have the relation, as follows:
Voltage = (Current)(Resistance)
If we keep the resistance of the wire as a constant, then we get the relation between voltage and current as follows:
Voltage = (Constant) * Current
Voltage α Current
This shows that the current has a direct proportionality with the voltage. So, if we want to double the current flowing through a piece of metal wire, then we must Double the voltage across it.
It can be confirmed by formula as:
V = IR
Now, doubling the voltage:
V' = 2 IR
substituting value of IR = V:
V' = 2 V
A motor transfers 12 kJ of energy in 30 s. Calculate its power.
Answer:
power=400Watt
Explanation:
work done =12kJ=12×10³=12000j
time taken=30s
power=?
as we know that
power=work done/time taken
power=12000J/30s
power=400Watt
i hope this will help you :)
A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in 0.072 seconds.
What is the magnitude of force that the ground exerted on the egg?
0.66 N
9.2 N
13 N
180 N
Answer is 9.2 N
Answer: Magnitude of the force exerted on the egg by the ground is 9.2N
Explanation:
Given the following :
Mass of egg (m) = 150g = 0.15kg
Height(h) from which egg is dropped = 3m
velocity of egg before hitting the ground (u) = 4.4m/s
Final velocity of egg (V) = 0
Time taken (t) = 0.072s
Magnitude of the force exerted on the egg by the ground can be found by applying Newton's 2nd law:
Momentum = mass × velocity
From Newton's second law:
Force = mass × change in Velocity with time ;
That is
F = m * ΔV / t
Inputting our values
F = 0.15 * (4.4 - 0) / 0.072
F = 0.15 × (4.4 / 0.072)
F = 0.15 × 61.11
F = 9.16N
F = 9.2N
Answer:
9.2 N
Explanation:
Just took practice quiz
An apple falls out of a tree from a height of 2.3 m What is the impact speed of the apple?
Answer:
6.72 m/s
Explanation:
recall that the equations of motion may be expressed as
v² = u² + 2as
where,
v = final velocity,
u = initial velocity = 0 m/s because it is stationary before it starts falling
a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)
s = distance traveled = 2.3m
in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.
v² = u² + 2as
v² = 0² + 2(9.81)(2.3)
v² = 45.126
v = √45.126
v = 6.72 m/s
A toboggan with two riders has a total mass of 87.0 kg. A third person is pushing the toboggan with a force of 42.5 N at the top of a hill with an angle of 16°. The force of friction on the toboggan is 36.0 N. Which statement describes an accurate free-body diagram to represent the situation? (Choose one of the forces acting on the system with correct magnitude and direction.)
Options:
a) An arrow of magnitude 852.6 N points perpendicular to the slope of the hill.
b) An arrow of magnitude 6.50 N points down the slope of the hill.
c) An arrow of magnitude 78.5 N points down the slope of the hill.
d) An arrow of magnitude 852.6 N points straight down.
Answer:
d) An arrow of magnitude 852.6 N points straight down.
Explanation:
The total mass of the two riders, m = 87.0 kg
The free body diagrams of the situation described are drawn and contained in the files attached to this solution.
Note that the weight of the toboggan will act directly downwards.
Therefore, the weight of the toboggan, W = mg
W = 87 * 9.8
W = 852.6 N
Since the arrow representing the weight of the toboggan points straight down, the correct answer is that an arrow of magnitude 852.6 N points straight down.
When an object is heated it …………… and when it cools it …………………..
Answer:
When an object is heated it Expand and when it cools it Contract
Explanation:
One of the effect of heat on matter is expansion. An increase in the temperature of an object causes it to expand and a decrease causes it to contract
1. a) What equal amount of positive charge would have to be placed on the Earth and on the Moon to neutralize their gravitational attraction? b) Why don’t you need to know the lunar distance to solve this problem? c) How many kilograms of hydrogen ions (that is, protons) would be needed to provide the positive charge calculated in part a?
Answer:
A) q = 5.714 × 10^(13) C
B) Because from a above, F_e = F_g and so r² canceled out in the formulas
C) m_t = 5.964 × 10⁴ kg
Explanation:
For the gravitational attraction of the earth and moon to be neutralized, the electrostatic force must be equal to the gravitational force i.e F_e = F_g
Now, F_e = kq²/r² and F_g = GmM/r²
Equating them and making q the subject, we arrive at;
q = √(GmM/k)
Where;
G is gravitational constant = 6.67 × 10^(-11) m³/kg.s²
m is mass of moon = 7.36 × 10^(22) kg
M is mass of earth = 5.98 × 10^(24) kg
k is coulombs constant = 8.99 x 10^(9) N.m²/c²
q = √(6.67 × 10^(-11) × 7.36 × 10^(22) × 5.98 × 10^(24)/8.99 x 10^(9))
q = 5.714 × 10^(13) C
B) We don't need the lunar distance because from a above, F_e = F_g and so r² canceled out in the formulas.
C) The number of protons is given by the formula;
n = q/e
Where, e is charge of the proton = 1.6 × 10^(-19) C
n = (5.714 × 10^(13))/(1.6 × 10^(-19))
n = 3.57125 × 10^(32)
Total mass of these protons is given by the formula;
m_t = nm_p
Where m_p is mass of a single proton = 1.67 × 10^(-27) kg
m_t = 3.57125 × 10^(32) × 1.67 × 10^(-27)
m_t = 5.964 × 10⁴ kg
Figure 8-56 shows a solid, uniform cylinder of mass 7.00 kg and radius 0.450 m with a light string wrapped around it. A 3.00-N tension force is applied to the string, causing the cylinder to roll without slipping across a level surface as shown. (a) What is the angular acceleration of the cylinder? (b) Calculate the magnitude and direction of the frictional force that acts on the cylinder. Figure attached below
Answer:
a) The cylinder has an angular acceleration of 3.810 radians per square second, b) The frictional force has a magnitude of 9 newtons and has the same direction of tension force.
Explanation:
The external force exerted on string creates a tension force that tries to move the cylinder in translation, but it is opposed by the friction force between cylinder and ground that generates rolling on cylinder. The Free Body Motion on cylinder-string system is presented below as attachment. Given that cylinder is a rigid body in planar motion, two equations of equilibrium for translation and an equation of equilibrium for rotation are needed to represent the system, which are now described:
[tex]\Sigma F_{x} = T + f = M\cdot R\cdot \alpha[/tex]
[tex]\Sigma F_{y} = N - M\cdot g = 0[/tex]
[tex]\Sigma M_{G} = (T-f)\cdot R = I_{G}\cdot \alpha[/tex]
Where:
[tex]T[/tex] - Tension, measured in newtons.
[tex]f[/tex] - Friction force, measured in newtons.
[tex]M[/tex] - Mass of the cylinder, measured in kilograms.
[tex]R[/tex] - Radius of the cylinder, measured in meters.
[tex]\alpha[/tex] - Angular acceleration, measured in radians per square second.
[tex]N[/tex] - Normal force from ground exerted on cylinder, measured in newtons.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]I_{G}[/tex] - Moment of inertia of the cylinder with respect to its center of mass, measured in kilogram-square meters.
The moment of inertia of the cylinder is:
[tex]I_{G} = \frac{1}{2}\cdot M\cdot R^{2}[/tex]
a) The angular acceleration is determined by solving on first and third equation after eliminating friction force:
[tex]f = M\cdot R \cdot \alpha - T[/tex]
[tex](T-M\cdot R\cdot \alpha+T) \cdot R = I_{G}\cdot \alpha[/tex]
[tex]2\cdot T\cdot R = (I_{G} + M\cdot R^{2})\cdot \alpha[/tex]
[tex]\alpha = \frac{2\cdot T\cdot R}{I_{G}+M\cdot R^{2}}[/tex]
[tex]\alpha = \frac{2\cdot T \cdot R}{\frac{1}{2}\cdot M\cdot R^{2}+M\cdot R^{2} }[/tex]
[tex]\alpha = \frac{4\cdot T}{3\cdot M\cdot R}[/tex]
If [tex]T = 3\,N[/tex], [tex]M = 7\,kg[/tex] and [tex]R = 0.45\,m[/tex], then:
[tex]\alpha = \frac{4\cdot (3\,N)}{(7\,kg)\cdot (0.45\,m)}[/tex]
[tex]\alpha = 3.810\,\frac{rad}{s^{2}}[/tex]
The cylinder has an angular acceleration of 3.810 radians per square second.
b) The magnitude of the frictional force can be determined with the help of the following expression:
[tex]f = M\cdot R \cdot \alpha - T[/tex]
Given that [tex]T = 3\,N[/tex], [tex]M = 7\,kg[/tex], [tex]R = 0.45\,m[/tex] and [tex]\alpha = 3.810\,\frac{rad}{s^{2}}[/tex], the magnitude of the friction force is:
[tex]f = (7\,kg)\cdot (0.45\,m)\cdot \left(3.810\,\frac{rad}{s^{2}} \right)-3\,N[/tex]
[tex]f = 9\,N[/tex]
The frictional force has a magnitude of 9 newtons and has the same direction of tension force.
Write one or two sentences to compare the internal energy of a molecular gas with the internal energy of a monatomic gas.
help fast I want the correct answer please does spectral diffusion cause light to scatter
Answer: No
Explanation:
Whenever light travelling on a straight line encounters obstruction, it diffracts and scatter.
Scattering of light occurs when light passes through a rough path or a diffused surface.
But in case of spectral diffusion, which is the fluctuation in spectroscopy as a result of time dependent frequency shifts.
Spectral diffusion occurs in particular molecules initiated by excessive excitation energy.
Fluctuation in frequency does not mean diffraction of light or particles
Therefore, spectral diffusion does not cause light to scatter.
Convert Gravitational constant (G) = 6.67×10^-11 Nm²kg^-2 to cm³ g ^-1 s^-2.
Answer:
6.67×10⁻⁸ cm³/g/s²
Explanation:
6.67×10⁻¹¹ Nm²/kg²
= 6.67×10⁻¹¹ (kg m/s²) m²/kg²
= 6.67×10⁻¹¹ m³/kg/s²
= 6.67×10⁻¹¹ m³/kg/s² × (100 cm/m)³ × (1 kg / 1000 g)
= 6.67×10⁻⁸ cm³/g/s²
explain the working of a seismograph. with the help of diagram Please answer me fast
Answer:
Explanation:
Seismograph is an instrument that measures and records details of earthquakes
How does it work???
The instrument is simply a vibrating rod, or a pendulum, which
starts vibrating when tremors occur. A pen is attached to the vibrating system.
The pen records the seismic waves on a paper which moves under it. By studying
these waves, scientists can construct a complete map of the earthquake
A 2.2 kW stove burner operates on a 240 V household circuit.
Answer:
I = 9.17 A
Explanation:
We have,
Power of a stove is 2.2 kW
Voltage on which it operates is 240 V
Let us assume that it is required to find the current flowing in the circuit. Electric power is given by :
[tex]P=IV\\\\I=\dfrac{P}{V}\\\\I=\dfrac{2.2\times 10^3}{240}\\\\I=9.17\ A[/tex]
So, the current in the stove burner is 9.17 A.
A cars start from rest . after 10 seconds its acceleration become 2 meter per second find its final velocity
Answer:
[tex] \boxed{\sf Final \ velocity = 20 \ m/s} [/tex]
Given:
Initial velocity (u) = 0 m/s
Acceleration (a) = 2 m/s²
Time taken (t) = 10 seconds
To Find:
Final velocity (v)
Explanation:
[tex]\sf From \ equation \ of \ motion: \\ \sf v = u + at \\ \\ \sf v = 0 + 2(10) \\ \\ \sf v = 2 \times 10 \\ \\ \sf v = 20 \ m/s[/tex]