Answer: 540 g m/s.
Explanation:
Answer: A.
A momentum of 540 gram meters per second!
Explanation: On Edge!!
A satellite is orbiting Earth at a speed of approximately 4,000 m/s. Which of these distances is most likely the orbital radius of the satellite’s motion?
The radius of the satellite's motion is 2.49 × 10⁷ m
Since the centripetal force, F = mv²/r equals the gravitational force, F' = GMm/r² on the satellite,
F = F'
mv²/r = GMm/r²
v² = GM/r
Making r subject of the formula, we have
r = GM/v² where r = radius of satellite's motion, G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.972 × 10²⁴ kg and v = speed of satellite = 4,000 m/s.
Substituting the values of the variables into the equation, we have
r = GM/v²
r = 6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg/(4,000 m/s)²
r = 39.83324 × 10¹³ Nm²/kg ÷ 16 × 10⁶ m²/s²
r = 2.4895775 × 10⁷ m
r ≅ 2.49 × 10⁷ m
So, the radius of the satellite's motion is 2.49 × 10⁷ m.
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Answer:
25.0 million meters
Explanation:
What happens to the volume of a fixed amount of gas if both the pressure and the absolute temperature are doubled
Answer: no change in volume
Explanation:
help me solve please
Answer:
please check the image
Explanation:
I hope this image helps you please follow the steps. Thank you
Answer:
1kg/```````2
Explanation:
solution
a
(2) A 800 g block is pushed up an inclined plane (angled at 18°) with a velocity of 11.8 m/s. The first block slides up the
incline a distance of 2.2 m and strikes a second block with a mass of 300 g also moving at 3.4 m/s up the incline.
The two blocks hit and stick together. Determine the following:
(i) The maximum vertical height of the two blocks when they stop.
(ii) The time needed for the blocks to reach the bottom of the incline after the moment of impact.
(u = 0.19)
this is my attachment answer hope it's helpful to you
A concave mirror has a centre of curvature of 24.0 cm. An object 2.5 cm tall is placed 40.0 cm in front of the mirror.
a) At what distance from the mirror will the image be formed?
b) What is the height of the image?
Answer:
Object distance should be 48
Explanation:
in pic
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- A cylinder of volume 5.0 x 103 cm3 contains air at a pressure of 8.0 x 105 Pa.
A leak develops so that air gradually escapes from the cylinder until the air in the cylinder
is at atmospheric pressure. The pressure of the atmosphere is 1.0 x 105 Pa.
Calculate the volume of the escaped air, now at atmospheric pressure. Assume that the
temperature stays constant.
Answer:
10
Explanation:
if you put 10 your right
what makes us think that the star system cygnus x-1 contains a black hole?
Answer:
Explanation:
What makes us think that the star system Cygnus X-1 contains a black hole? It emits X-rays characteristic of an accretion disk, but the unseen star in the system is too massive to be a neutron star.
En el siguiente circuito se conectan tres resistencias, cuyos valores son: 2 Ω, 3 Ω y 5 Ω. ¿Cuál es el valor de la resistencia total en el circuito? y ¿A qué tipo de circuito corresponde la imagen?
Answer:
Oh wow, that's a long answer. I don't know what voltage is on the circuit.
a box takes 350 N to start moving the coefficient of static friction is 0.35. what is the weight of the box?
Answer:
101.937 kg
Explanation:
The force needed to get the box moving must just cancel the static friction force:
F = µsmg = 0.35•m•9.81 = 350 ---> m = 350 / (0.35•9.81) = 101.937 kg
Again, with units shown, and using 1 N = 1 kg•m/s2:
0.35•m•9.81(m/s2) = 350 N
solving for m:
m = 350 N / (0.35•9.81 m/s2) = (350 kg•m/s2) / (3.434 m/s2 ) = 101.937 kg
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what is the relationship between area, force, and pressure?
Answer: Pressure is proportional to force and inversely proportional to area.
Explanation:
hannah drove 360 mi in 5.2 hours. What was her average speed?
What mass M will cause this system accelerate e 0.75 m/s²?
Answer:
5.54 [kg].
Explanation:
1) if m₁=6; g=9.81; a=0.75 and m₂ - reqired mass, then
2) it is possible to write: m₁*a=m₁*g-m₂*g, and
3) [tex]m_2=\frac{m_1(g-a)}{g}; \ => \ m_2=\frac{6*(9.81-0.75)}{9.81}=5.54[kg].[/tex]
a soccer ball is kicked at an angle of 35° and it lands on even ground.
A) What angle will produce the same range?
B) Which angle of the two will produce the highest ball?
C) Which angle of the two will produce the ball that is in the air the longest?
D) What angle in this situation would produce the furthest range?
Hi there!
A)
The angle that will produce the same range is the compliment of 35°.
Thus, kicking the ball at 55° will result in the same range.
We can prove this by using the derived range equation:
[tex]R = \frac{v^2sin2\theta}{g}[/tex]
An angle of 35° yields:
[tex]R = \frac{v^2sin(2*35)}{g} = .939R[/tex]
An angle of 55° yields:
[tex]R = \frac{v^2sin(2*55)}{g} = .939R[/tex]
Both are the same, thus indicating that 55° produces the same range.
B)
The angle of 55° will produce the higher ball because the VERTICAL component of the ball's velocity is greater compared to kicking the ball at 35° degree.
sin(55) > sin(35)
C)
The angle of 55° will result in the ball being in the air the longest because when a ball is in the air (assuming no air resistance), the ball experiences an acceleration due to gravity of -9.8 m/s², causing the vertical velocity to decrease until it eventually reaches 0 m/s at the top of its path. A greater initial vertical velocity means that it will take longer for the ball to fall.
We can prove this using:
vf = vi + at
0 = vy - 9.8t
vy/9.8 = t
Greater vy (vertical component of velocity) ⇒ greater time taken.
D)
The angle that would result in the furthest range is 45°.
We can prove this using calculus. Recall the above range equation:
[tex]R = \frac{v^2sin2\theta}{g}[/tex]
We can take the derivative and use the first-derivative test to find its critical point:
[tex]\frac{dR}{d\theta} = \frac{v^22cos2\theta}{g} = 0[/tex]
Evaluate:
[tex]v^22cos2\theta = 0 \\\\cos2\theta = 0 \\\\2\theta = 90^o\\\\\boxed{\theta = 45^o}[/tex]
A. The angle that will produce the same range as a 35° kick is 53°.
B. The angle that produces the highest ball is 45°.
C. The angle that produces the ball that is in the air the longest is 45°.
D. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.
A. The range of a projectile is the horizontal distance it travels before it hits the ground. The range of a projectile is determined by the initial velocity, the angle of projection, and the acceleration due to gravity.
For a given initial velocity, the range of a projectile is maximized when the angle of projection is 45°. However, if the ground is not level, the range of a projectile can be maximized at other angles.
In the case of a soccer ball kicked at an angle of 35°, the range will be maximized at an angle of 53°. This is because the range of a projectile is maximized when the vertical component of the initial velocity is equal to the horizontal component of the initial velocity.
The angle of 53° is the angle that produces a vertical component of the initial velocity that is equal to the horizontal component of the initial velocity when the ball is kicked at an angle of 35°.
Therefore, the angle that will produce the same range as a 35° kick is 53°.
B. The angle that produces the highest ball is 45°.
C. The angle that produces the ball that is in the air the longest is 45°.
D. The angle that produces the furthest range depends on the initial velocity and the acceleration due to gravity. There is no single angle that will produce the furthest range for all initial velocities and accelerations due to gravity.
To know more about angle here
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Which object has the most thermal energy?
A. A 6 kg rock at 10°C
B. A 10 kg rock at 10°C
C. A6 kg rock at 15°C
D. A 10 kg rock at 15°C
Answer:
D is the answer
Explanation:
D is the most highest one so
the answer is D
Answer:
10 kg rock at 15 degrees celcius
how do astronomers determine the origin of a meteorite that reaches earth?
Researchers begin their study by identifying the rock type and then dating the meteorite
Explanation:
.
During cellular respiration, cells absorb what ?and use it to release energy from food
Answer:
Cellular respiration is the process in which cells break down glucose, release the stored energy, and use the energy to make ATP.
Explanation:
If the resistor is connected in series, the voltage across the wire changes. (true or false)
1. On a pirate map, X marks the spot. Does that X represent the position or
displacement of the treasure? *
A deer runs 5 km through the woods in 9 min and then walks 7 km in 2 hours. Find its average speed in km/h.
how many tries did it take to invent the lightbulb?
1 point
What is the acceleration of a bicyclist moving at a constant speed of 10
m/s for 5 seconds? *
PLEASE HELP HURRY
Answer:
0
Explanation:
The bicyclist is not speeding up or slowing down so there is no acceleration.
Which statement indicates that motion has occurred?
A. The reference point has changed.
B. The position of the object has changed.
C.The object has not changed.
D. The object being described has changed
[tex] \huge \mathcal{Question}[/tex]
Help ! FBD (free body diagram) required
Select all correct choices ~
Thanks for Answering ! have a great day ~
[tex] \huge \bf༆ Answer ༄[/tex]
According to the given question,
Normal reaction = mg Cos 37° + ma Cos 53°
here,
m = mass of the block = 1 kg
a = Acceleration of wedge = 5 m/s²
g = Acceleration due to gravity = 10 m/s²
Calculation : - [tex] \sf \: mg \cos(37) + ma \cos(53) [/tex][tex] \sf \: \bigg(1 \times 10 \times \dfrac{4}{5} \bigg) + \bigg( 1 \times 5 \times \dfrac{3}{5} \bigg)[/tex][tex] \sf(2 \times 4) + (1 \times 3)[/tex][tex] \sf8 + 3[/tex][tex] \sf11 \: N[/tex]The Correct choice is C
[tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
when a single star with a mass equal to the sun dies, it will become a
When a single star with a mass equal to the sun dies, it will become a: white dwarf.
A star is a giant celestial (astronomical) object which comprises a luminous sphere of plasma bounded together by its own gravitational force.
A single star can be defined as a type of star that moves through space alone.
Generally, a star is mainly composed of two (2) hot gases and these are:
I. Hydrogen (H).
II. Helium (He).
Based on Astronomy, when a star runs out of hydrogen, depending on its mass, it would either turn into any of the following:
A planetary nebula.A supernova.A white dwarf.Similarly, when a single star with a mass equal to the sun dies, it will turn into a white dwarf.
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why the max Static frictional force is a Little bit bigger than the sliding frictional force
SOMEONE PLEASE HELP ME IM GOING INSANE 4 Select the correct answer. A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled 2.0 x 107 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour? O A. -3.77 x 10-2 meters/second OB. -2.77 x 10-3 meters/second OC. -2.62 x 10-2 meters/second D. -5.55 x 103 meters/second
Hi there!
Since we are dealing with such large distances, we can approximate.
Recall that the equation for speed is:
displacement / time = velocity
OR:
d/t = v
Begin by converting one hour to seconds:
1 hr = 3600 sec
Now, we can solve for velocity:
(-2.0 × 10⁷) / 3600 = -5555.6 m/s ⇒ D: -5.55 × 10³ m/s
A force acts on an object. Which option describes an action that could prevent the object from moving
Answer:
Friction or tension
Explanation:
Friction stops an object from moving in the presence of force
The weight of a cart with a mass of 150 kg is ___ N. (Use 9.8
m/s2 for the acceleration due to gravity.)
Answer:
1470 N
Explanation:
Weight = m*g
So 150 kg * 9.8 m/s^2 = 1470 N
how many gallons of gasoline are consumed in the us daily?
Explain why we draw straight lines to show rays of light?
Answer:
Because light always travels in straight line.
Explanation:
The fact that light travels can be demonstrated by putting an object in its path. If the object is opaque the result is a degree of blackness on the other side of it which is due to the absence of the light. ... As light does appear to travel in straight lines then light is usually modelled as straight lines in drawings.
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