angles in a triangle

Angles In A Triangle

Answers

Answer 1

Answer:

i = 74

j = 47

Step-by-step explanation:

to find "i" add 16 & 90 which is 106. subtract 106 from 180 to get 74.

to find "j" add 43 & 90 which is 133. subtract 133 from 180 to get 47


Related Questions

The coordinates of rhombus abcd are a(-4,-2) b(-2,6) c(6,8) d(4,0). What is the area of the rhombus

Answers

First, graph the rhombus:

Area of a rhombus = Product of diagonals / 2

Find the length of the diagonals:

Distance between points:

[tex]\sqrt[\placeholder{⬚}]{(x2-x1)^2+(y2-y1)2^}[/tex]

Diagonal AC

[tex]AC=\sqrt[\placeholder{⬚}]{(6-(-4))^2+(8-(-2))^2}[/tex]

AC= 10√2

Diagonal BD

[tex]BD=\sqrt[\placeholder{⬚}]{(4-(-2))^2+(0-6)^{^2}}[/tex]

BD=6√2

Area= AC x BD / 2

Area = [(10√2) x (6√2)]/2

Area = 60

PEOPLE PLEASE HELP GO ON MY PROFIL AND HELP ME with the things i put today i really need help please help HELP HELP HELP ME PLEASE I NEED HELP!

Answers

Step-by-step explanation:

i don't knowhdjkedgeike

|x + 6| < or equal to 1
8

x < or equal to 2
x < or equal to ?

Answers

Answer: -14

Step-by-step explanation:

[tex]\frac{1}{8}|x+6| \leq 1\\\\|x+6| \leq 8\\\\-8 \leq x+6 \leq 8\\\\-14 \leq x \leq 2[/tex]

What sets does -√3,1 and 0 belong to

Answers

√2 and -√3 belong to the set of Irrational Numbers.

1 belong to the following sets:

• Rational

,

• Whole

,

• Natural

,

• Integers

0 belongs to the following sets:

• Rational

,

• Whole

,

• Integers

State if there appears to be a positive correlation, negative correlation, or no correlation. When there is a correlation, identify the relationship as linear or nonlinear.

Answers

Answer:

Negative Correlation:

Linear relationship

Explanation:

We can draw the line of best fit through the points given, and this indicates that the relationship is linear. Furthermore, the line of best fit has a negative slope (which tells us that if one variable increases, the other decreases); therefore, the data set has a negative correlation

Which equation has the solution x = 5? Select each correct answer. Responses
A) 11 + 6x = 22
B) 3x + 1 = 9
C) 18−2x=9
D) 25/x+4=9
E) x/5 + 5 = 6
F) 32−4x=12

Answers

The equation that has the same solution as x = 5 are as follows:

25 / x + 4 = 9x / 5 +  5 = 6 32 - 4x = 12

How to solve equation?

An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values.

In other words, an equation is a mathematical statement that is made up of two expressions connected by an equal sign.

The equation can be solved as follows:

The equation will have the same solution as x = 5.

Therefore,

25 / x + 4 = 9

subtract 4 from both sides of the equation

25 / x + 4 = 9

25 / x + 4 - 4 = 9 - 4

25 / x  = 5

cross multiply

5x = 25

divide both sides by 5

x = 25 / 5

x = 5

x / 5 +  5 = 6

x / 5 = 6 - 5

x / 5 = 1

cross multiply

x = 5

32 - 4x = 12

- 4x = 12 - 32

- 4x = - 20

divide both sides of the equations by - 4

x = -20 / - 4

x = 5

Therefore, the equation with same solution are 25 / x + 4 = 9, x / 5 +  5 = 6 and  32 - 4x = 12

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Please help i really need help please

Answers

Answer:

plane CGF and ABC

Step-by-step explanation:

If the measures of two angles of a triangle are 96° and 29°, what is the measure of the third angle?

Answers

Answer: measure of the third angle is 55 degrees

Step-by-step explanation: the sum of all interior angles in a triangle is always 180 so, 96+29+x=180.

125+x=180

x=55

A. 2x-1+3x=0 B. 5x-1=0 How can we get Equation B from Equation A ?

Answers

By taking x as a common factor we get:

2x - 1 + 3x = 0

(2 + 3)*x - 1 = 0

5x - 1 = 0

How to get equation B from equation A?

Let's start with equation A, it is:

2x - 1 + 3x = 0

If we group like terms, we will get:

(2x + 3x) - 1 = 0

Now we can take x as a common factor in the left term, so we get:

(2x + 3x) - 1 = 0

(2 + 3)*x - 1 = 0

Now we simplify the sum in the left term:

(2 + 3)*x - 1 = 0

5x - 1 = 0

This is equation B.

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Please help ASAP starting to fall behind! This equation really confuses me and if someone could help that would be amazing!

Given the function:

f(x) = x² - 4x - 2

Find the following values.
a) f(2)
f(2)=

b) f(4)
f(4)=

c) f(-3)
f(-3)=

Answers

The values of the functions is  ,

(a) f(2) = -6

(b) f(4) = -2

(c) f(-3) = 19

In the question ,

it is given that the function is f(x) = x² - 4x - 2

we have to find the value of f(2) , f(4) , f(-3)

Part(a)

to find f(2) , we substitute x = 2 in the function

On substituting , we get

f(2) = 2² - 4*2 - 2

= 4 - 8 - 2

= 4 - 10

= -6

Part(b)

to find f(4) , we substitute x = 4 in the function f(x)

On substituting , we get

f(4) = 4² - 4*4 - 2

= 16 - 16 -2

= 0 - 2

= -2

Part(c)

to find f(-3) , we substitute x = -3 in the function

On substituting , we get

f(2) = (-3)² - 4*(-3) - 2

= 9 + 12 -2

= 9 + 10

= 19

Therefore , The values of the functions is  , (a) f(2) = -6  , (b) f(4) = -2 ,  (c) f(-3) = 19

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Working alone, it takes Kristen 10.2 hours to harvest a field. Kayla can harvest the same field in 16.5 hours. Find how long it would take them if they worked together.

Answers

ANSWER:

13.35 hours

EXPLANATION:

Given:

Time Kristen takes to harvest = 10.2 hours

Time Kayla takes to harvest = 16. 5 hours

Let X represent the time it would take them to work together.

Here, to find the time it would take them if they worked together, let's find their mean time, using the formula below:

[tex]X\text{ = }\frac{Time\text{ taken by kristen + Time taken by Kayla}}{2}[/tex]

[tex]\begin{gathered} X\text{ = }\frac{10.2\text{ + 16.5}}{2} \\ \\ X\text{ = }\frac{26.7}{2} \\ \\ X\text{ = }13.35\text{ hours} \end{gathered}[/tex]

It would take them 13.35 hours if they worked together.

For each set of points below, determine the distance between them using the distance formula. each answer in this problem will be an integer

Answers

Distance between two coordinates:

[tex]\text{ Distance=}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Given point: b) (10, -5) and ( -6, 7)

[tex]x_1=10,y_1=-5,x_2=-6,y_2=7[/tex]

Substitute the value in the expression of distance formula

[tex]\begin{gathered} \text{ Distance=}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{Distance}=\sqrt[]{(-6-10)^2+(7-(-5))^2} \\ \text{Distance}=\sqrt[]{(-16)^2+(12)^2} \\ \text{Distance}=\sqrt[]{256+144} \\ \text{Distance}=\sqrt[]{400} \\ \text{Distance = 20 unit} \end{gathered}[/tex]

The distance between coordinates (10,-5) & (-6,7) is 20 unit

Graph the Linear equation: y = - 3/4x + 5

Answers

Based on the given linear equation of y = - 3/4x + 5, the graph is shown attached.

How to graph an equation?

When given a linear equation, you graph it by coming up with x values and then using the equation to find the corresponding y values.

The linear equation is y = - 3/4x + 5.

If the value x = -1, then y would be:

y = - 3/4x + 5

= -3/4(-1) + 5

= 5.75

If the value x = 0, then y would be:

y = -3/4(0) + 5

= 5

If the value x = 1, then y would be:

= -3/4(1) + 5

= 4.25

If the value x = 2, then y would be:

= -3/4(2) + 5

= 3.5

If the value x = 3, then y would be:

= -3/4(3) + 5

= 2.75

The points would be:
(-1, -5.75) (0, 5) (1, 4.25) (2, 3.5) (3, 2.75)

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Will and Sarah are racing across the playground. Instead of running, they are hopping. During the race, they must both hop at the same time. In one hop, Will can travel 5 feet, and Sarah can travel 4 feet.


The playground is 200 feet wide. Will wins the race after hopping 40 times. How far had Sarah hopped when Will finished the race?


I know the answer i just need explanation.

Answers

Sarah has hopped for 160ft when Will finished the race.

What is basic arithmetic?

Specific numbers and their computations employing a variety of fundamental arithmetic operations are at the center of arithmetic mathematics. Algebra, on the other hand, deals with the limitations and guidelines that apply to all other types of numbers, including whole numbers, integers, fractions, functions, and so on. Arithmetic math serves as the foundation for algebra, which always adheres to its definition. A large range of subjects fall within the broad definition of mathematics, which encompasses a very broad range of topics. Beginning with the fundamentals like addition, subtraction, and division of numbers, they then move on to more complicated topics like exponents, variations, sequence, progression, and more. This part does touch on some of the mathematical formulas and mathematical sequence. Four essential mathematical operations—addition, subtraction, multiplication, and division—are covered in basic arithmetic.

For Will

5 × 40

= 200 feet

For Sarah

4 × 40

= 160 ft

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Solve the inequality for x. Show each step of the solution.

12(x+3)>4x-8

Answers

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

12x+36>4x−8

Step 2: Subtract 4x from both sides.

12x+36−4x>4x−8−4x

8x+36>−8

Step 3: Subtract 36 from both sides.

8x+36−36>−8−36

8x>−44

Step 4: Divide both sides by 8.

8x/8 > -44/8

Therefore your answer will now equal  [tex]x > \frac{-11}{2}[/tex]

[tex]{ \boxed{ \pink{ \sf{x > - \frac{11}{2}}}}}[/tex]

Step-by-step explanation:

The given inequality is, [tex]{ \green{ \sf{12(x + 3) > 4x - 8}}}[/tex]

[tex]{ \star}[/tex]Step 1: Simplify both the sides of inequality.

[tex]{ \green{ \sf{12x + 36 > 4x - 8}}}[/tex]

[tex]{ \star}[/tex]Step 2: Now Subtract 4x from both sides.

[tex]{ \purple{ \sf{12x+36−4x> { \cancel{4x}−8{ \cancel{−4x}}}}}}[/tex]

[tex]{ \purple{ \sf{8x+36>−8}}}[/tex]

[tex]{ \star}[/tex]Step 3: Subtract 36 from both sides.

[tex]{ \blue{ \sf{8x+{ \cancel{36}{ \cancel{−36}}}>−8−36}}}[/tex]

[tex]{ \blue{ \sf{8x>−44}}}[/tex]

[tex]{ \star}[/tex]Step 4: Divide both sides by 8.

[tex]{ \orange{ \sf{ \frac{ \cancel8}{ \cancel8} x > - \frac{ \cancel{44^{ \blue{ \tt{11}}}} }{ \cancel8_{ \blue{ \tt{2}}} }}}} [/tex]

[tex]{ \boxed{ \red{ \sf{x > - \frac{11}{2}}}}} [/tex]

Astronomers use a light year to measure distance. a light year is the distance light travels in one year. The speed is approximately 300,00km/sec. how long will it take a rocket traveling 63,000km/hr to reach Alpha Centauri (the ⭐ closest to Earth other than the ). Note: Alpha Centauri is approximately 4.34 light years from Earth. which is 4.11 x 10^13 km away (when using scientific notation). one light year is 9.46 x 10^12 km.

Answers

Speed of light = 300,000 km/sec

Rocket's speed = 63,000 km/hr or 6.3 x 10⁴ km/hr

Alpha Centauri distance from Earth = 4.11 x 10¹³ km

One light year (distance) = 9.46 x 10¹² km

To solve for the time it takes it travel, we can manipulate the speed formula.

[tex]\begin{gathered} \text{speed}=\frac{dis\tan ce}{\text{time}} \\ \text{time}=\frac{dis\tan ce\text{ }}{\text{speed}} \end{gathered}[/tex]

We already have the distance of Alpha Centauri from Earth written above. We also have the speed of the rocket written above too. We will substitute those values to the formula.

[tex]\begin{gathered} \text{time}=\frac{4.11\times10^{13}\operatorname{km}}{6.3\times10^4\operatorname{km}\text{ /hr}} \\ \text{time}=0.6523809524\times10^9 \\ \text{time}=6.52\times10^8\text{ hr} \end{gathered}[/tex]

This math question please

Answers

I need 20 characters to submit this answer

Find all possible values of the expression 1/a

1/2
__<1/a<__

Answers

The possible values of the expression 1/a = 1/2 is 2

The expression is the simple fraction form = 1/a

The expression is the defined as the a sentence with a minimum of two  variables and at least one math operation.

The simple fraction is fraction that contains the numerator and denominator as whole number. The term one the top of the simple fraction called as the numerator and bottom term is called as the denominator.

Here it is given that

1/a = 1/2

Therefore the value of a = 2

Hence, the possible values of the expression 1/a = 1/2 is 2

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Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. The sample of 2100 bacteria selected from this population reach the size of 2249 bacteria in two and a half hours. Find the hourly growth rate parameter.This is a continuous exponential growth model.Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.

Answers

In this problem, we have a continuous exponential growth model

so

the equation is of the form

[tex]y=a(e)^{kt}[/tex]

where

a is the initial value ------> a=2,100

y is the number of bacteria

x ----> number of hours

so

[tex]y=2,100(e)^{kt}[/tex]

For x=2.5 hours, y=2,249 bacteria

substitute

[tex]2,249=2,100(e)^{(2.5k)}[/tex]

solve for k

apply ln both sides

[tex]\ln (\frac{2,249}{2,100})=2.5k\cdot\ln (e)[/tex]

k=0.0274

convert to percentage

k=2.74%

what is the difference written in scientific notion?0.00067 - 2.3 * 10^-5

Answers

Answer:

[tex]6.47\times10^{-4}[/tex]

Explanation:

To evaluate the difference:

[tex]0.00067-2.3\times10^{-5}[/tex]

First, rewrite the expression in the form below:

[tex]=67\times10^{-5}-2.3\times10^{-5}[/tex]

Next, factor out the powers of 10.

[tex]\begin{gathered} =10^{-5}(67-2.3) \\ =10^{-5}(64.7) \\ =64.7\times10^{-5} \\ =6.47\times10^1\times10^{-5} \\ =6.47\times10^1^{-5} \\ =6.47\times10^{-4} \end{gathered}[/tex]

Thus, the difference written in scientific notation is:

[tex]6.47\times10^{-4}[/tex]

Note: A number is in scientific notation if it is expressed as a product of a number (between 1 and 10) and a power of 10.

(8.59×10 4 )−(3.2×10 3 )

Answers

Answer:

The answer is 8.27×10^4

Answer: 8.27×10^4

Step-by-step explanation:

Beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle gym and the monkey bars. if beth places the swings at point d, how could she prove that point d is equidistant from the jungle gym and monkey bars? if segment ad ≅ segment cd, then point d is equidistant from points a and b because congruent parts of congruent triangles are congruent. if segment ad ≅ segment cd, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. if m∠acd = 90° then point d is equidistant from points a and b because congruent parts of congruent triangles are congruent. if m∠acd = 90° then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.

Answers

The angle bisector theorem states that a triangle's opposite side is divided into two halves by an angle bisector that is proportional to the triangle's other two sides.

A point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects, therefore if mACD = 90°, point D is equidistant from points A and B.

Any point on the perpendicular bisector is simply equal distance from both endpoints of the line segment on which it is drawn, according to the perpendicular bisector theorem.

The answer is that point  is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it makes up. Therefore, if a pillar is stationed at the middle of a bridge at an angle, all the points on the pillar will be equidistant from the end points of the bridge intersects.

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a standard poker deck of cards contains 52 cards, of which four are kings. suppose two cards are drawn sequentially, so that one random circumstance is the result of the first card drawn and the second random circumstance is the result of the second card drawn. find the probability that the first card is a king and the second card is not a king. (round your answer to four decimal places.)

Answers

The probability that the first card is a king and the second card is not a king is 0.0045

Suppose two cards are drawn sequentially so that one random circumstance is the result of the first card drawn and the second random circumstance is the result of the second card drawn. To find the probability that the first card is a king and the second card is not a king.

In the first case let's find the probability of drawing a king from the deck of cards,

A = ( 4/52 )

In the second case the probability of drawing a card that is not a king from the deck is,

B = ( 3/51 )

At last, to get the final probability to draw that the first card is a king and the second card is not a king we need to multiply the above two cases as,

A x B = ( 4/52 ) ( 3/51 )

         = 1/221

         = 0.0045

The probability that the first card is a king and the second card is not a king is 0.0045

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3|y|+(y-x²)
if x = -1 and y = -5

Answers

Explanation:
Parentheses first
-1^2= 1
-5-1=-6
Then we do |-5|
(the absolute value of -5 is 5)
So then we’re left with 3 x 5 - 6
Which would equal 8

Answer: 9

The table shows deshawna's science grade during four grading periods. How much greater was the percentage change in her grade from grading period 1 to 2 than from grading period 2 to 3. round to nearest tenth

Answers

Since the percent grade in period 1 was 92% and in period 2 was 96%, then the percent change from period 1 to 2 was 4%.

Since the percent grade in period 2 was 96% and in period 3 was 99%, then the percent change from period 2 to 3 was 3%.

Since 4% is 1% greater than 3%, then the percent change from grading period 1 to 2 was 1% greater than the percent change from grading period 2 to 3.

Therefore, the answer is: 1.0%.

PCA) = 1/3 P(В) = 2/9 PIAUB) = 4/9 Find P(An B). 1 1/9 ОООО 20/18 О 1/3

Answers

Solution:

Remember the following formula :

P(AUB) = P(A)+P(B)-P(AnB)

According to the data of the problem and applying the previous equation, we obtain the following equality:

[tex]\frac{4}{9}=\frac{1}{3}+\frac{2}{9}-\text{ P(A n B)}[/tex]

This is equivalent to:

[tex]\frac{4}{9}=\frac{5}{9}-\text{ P(A n B)}[/tex]

solving for P(A n B), we get:

[tex]\text{ P(A n B )= }\frac{5}{9}-\frac{4}{9}=\frac{1}{9}[/tex]

so that, we can conclude that the correct answer is:

[tex]\frac{1}{9}[/tex]

30. Solve for x: 7^/10 = 2, approximate to 4 digitsa. 6.325 b. 3.256 c. 3.265 d. 3.652 e. 3.562

Answers

• Solution

[tex]7^{\frac{x}{10}}=2[/tex]

To solve for x, we take the logarithm of both sides.

[tex]\log 7^{\frac{x}{10}}=\log 2[/tex]

Applying the law of logarithm to the equation above;

[tex]\log a^b=b\log a[/tex][tex]\begin{gathered} \log 7^{\frac{x}{10}}=\log 2 \\ \frac{x}{10}\log 7=\log 2 \\ \text{Dividing both sides by log 7;} \\ \frac{x}{10}=\frac{\log 2}{\log 7} \\ \frac{x}{10}=\frac{0.3010}{0.8451} \\ \frac{x}{10}=0.3562 \\ \text{Cross multiplying the equation;} \\ x=0.3562\times10 \\ x=3.562 \end{gathered}[/tex]

Therefore, the approximate value of x is 3.562

The correct option is E.

10. Evaluate (14-2)÷3(2-3) - 2²Mark only one oval.A. OB. 2C. 20D. 22

Answers

[tex](14-2)\div3\cdot(2\cdot3)-2^2[/tex]

Order of the operations: parentheses, exponentials, division and multiplication, addition and subtraction.

1. Solve operations in parentheses:

[tex]=12\div3\cdot6-2^2[/tex]

2. Solve exponentials:

[tex]=12\div3\cdot6-4[/tex]

3. Solve division:

[tex]=4\cdot6-4[/tex]

4. Solve multiplication:

[tex]=24-4[/tex]

5. Solve subtraction:

[tex]=20[/tex]Then, the solution for the given expression is 20

Answer: Answer is 20( please make me brainliest i just did this all in my head)

Step-by-step explanation: soo (14-2) =12  12divided by 3=4 so (2*3)= 6 so 4x6=24 24-2*2 =20 (2*2)=4 so 24-4=20 well this is confusing but i tried my best so hope my answer wasn't toooo confusing lol :)

The Beta club is selling chocolate to raise money for Beta convention. Chocolate bars sell for $1.25 each and chocolate covered almonds sell for $2.00 each. The Beta club needs to raise more than $375 for all members to attend the convention. The students can sell up to 500 bars and covered almonds altogether.

1. Write a system of inequalities that can be used to represent this situation.



2. The club sells 100 chocolate bars. What is the least number of chocolate covered almonds that must be sold to cover the cost of attending Beta convention? Justify your answer.

Answers

(1) The system of inequalities that can be used to represent this situation is 1.25x + 2y > 375  and x+y ≤ 500 .

(2) The least number of chocolate covered almonds that must be sold to cover the cost of attending Beta convention is 126 .

In the question ,

Part(1)

let the number of chocolates be "x" .

let the number of chocolates with covered almonds be "y"

price of each chocolate bar = $1.25

price of each chocolate covered almonds = $2

Beta club needs more than $375

So , according to the question

1.25x + 2y > 375

and also the students can sell up to 500 bars and covered almonds altogether.

So , x+y ≤ 500 .

Part(2)

Given , the club sells 100 chocolate bars.

substituting x= 100 in the inequality 1.25x + 2y > 375  , we get

1.25(100) + 2y > 375

125 + 2y > 375

2y > 375-125

2y > 250

y > 125

least number of chocolate covered almonds to be sold is 126 .

Therefore , (1) The system of inequalities that can be used to represent this situation is 1.25x + 2y > 375  and x+y ≤ 500 .

(2) The least number of chocolate covered almonds that must be sold to cover the cost of attending Beta convention is 126 .

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How many ways can four guests sit in a row of six chairs?

Answers

Answer:

360

Step-by-step explanation:

There are 6 spaces and 4 people.

_ _ _ _ _ _

The first person to choose a seat can choose any of the 6 seats.

The second person can choose any of the 5 remaining seats.

The third person can choose any of the 4 remaining seats.

The fourth person can choose any of the 3 remaining seats.

Now, we do 6 x 5 x 4 x 3 to figure out the total number of ways they can sit in the seats.

6 x 5 x 4 x 3 = 360 ways

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