There are approximately 3.72 x 10⁴¹ ways that Anna can hand out 1 treat to each of the 36 children who come to her door.
Anna has 2 dozen Rollo bars, which is equivalent to 2 x 12 = 24 Rollo bars.
She also has 1 dozen apples, which is equivalent to 1 x 12 = 12 apples.
So, Anna has a total of 24 + 12 = 36 treats to hand out.
Now, she needs to hand out 1 treat to each of the 36 children who come to her door.
This can be thought of as selecting 1 treat from the total of 36 treats for each child, without replacement, as each child can only receive 1 treat.
The number of ways to do this is given by the concept of permutations, denoted by "nPr", which is calculated as;
nPr = n! / (n - r)!
where n is the total number of items (treats) to choose from, and r is the number of items (treats) to choose.
In this case, n = 36 (total number of treats) and r = 36 (number of children).
Plugging in the values, we get;
36P36 = 36! / (36 - 36)! = 36! / 0! = 36!
Since 0! (0 factorial) is equal to 1, we can simplify further:
36! / 1 = 36!
36! ≈ 3.72 x 10⁴¹
So, there are 3.72 x 10⁴¹ ways that Anna can hand out 1 treat to each of the 36 children who come to her door.
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Emilio and Belle each want to run for president of their school's student body council. In order to do so, they must collect a certain number of signatures and get a nomination. So far, Emilio has 28 signatures, and Belle has 25. Emilio is collecting signatures at an average rate of 8 per day, whereas Belle is averaging 9 signatures every day. Assuming that their rate of collection stays the same, eventually the two will have collected the same number of signatures. How many signatures will they both have? How long will that take?
After 3 days, Emilio will have collected 28 + 8(3) = 52 signatures, and Belle will have collected 25 + 9(3) = 52 signatures as well.
To determine the number of signatures both Emilio and Belle will have, we can set up an equation:
28 + 8x = 25 + 9x
where x is the number of days it takes for both of them to collect the same number of signatures.
Simplifying the equation, we get:
3x = 3
x = 1
So it will take them one more day for Belle to collect the same number of signatures as Emilio.
To find out how many signatures they will both have, we can substitute x=1 into either of the equations and solve for the number of signatures. Let's use Emilio's equation:
28 + 8(1) = 36
Therefore, both Emilio and Belle will have 36 signatures.
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-k -> Find the maximum Likelihood Estimates of t When pre f(t) = (1-tjok ott For K=Ogl K
The maximum likelihood estimate of t is at the endpoint t = 0.
We have,
To find the maximum likelihood estimates of t, follow these steps:
1. Write down the likelihood function L(t) for the given pdf f(t).
The likelihood function is the same as the pdf, which is:
L(t) = (1 - t)^k
2. Take the natural logarithm of the likelihood function, ln(L(t)), to make it easier to work with:
ln(L(t)) = ln((1 - t)^k)
3. Use the properties of logarithms to simplify the expression:
ln(L(t)) = k x ln(1 - t)
4. Differentiate ln(L(t)) with respect to t to find the critical points that might correspond to the maximum likelihood estimate:
d(ln(L(t))) / dt = - k / (1 - t)
5. Set the derivative equal to zero and solve for t:
- k / (1 - t) = 0
Since k is nonzero, this equation implies that there is no solution for t in the interval [0, 1].
Thus, the maximum likelihood estimate of t does not occur at a critical point in the interval.
6. Since there are no critical points, we must check the endpoints of the interval, t = 0 and t = 1, to find the maximum likelihood estimate.
The likelihood function L(t) = (1 - t)^k has its maximum value at the endpoint where the derivative is positive.
In this case,
The derivative -k / (1-t) is positive when t = 0.
Thus, the maximum likelihood estimate of t is at the endpoint t = 0.
Thus,
The maximum likelihood estimate of t is at the endpoint t = 0.
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A wall with 18m and 4. 5 meters wide is to be painted. A square window with 1. 6 meters lessens or save the area. How big the wall to be painted?
The total area of the wall that needs to be painted is approximately 78.44 square meters.
Width of the wall = 18 meters
Height of the wall = 4.5 meters
Width of the square window = 1.6 meters
Calculating the area of the wall -
Area of the wall = Width × Height
= 18 × 4.5
= 81 square meters
Calculating the area of the square window -
Area of the square window
= Width of window × Width of window
= 1.6 × 1.6
= 2.56 square meters
Calculating the remaining area to be painted -
Remaining area to be painted = Area of the wall - Area of the square window
= 81 square meters - 2.56 square meters
= 78.44 square meters
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suppose you have an chessboard but your dog has eaten one of the corner squares. can you still cover the remaining squares with dominoes? what needs to be true about ? give necessary and sufficient conditions (that is, say exactly which values of work and which do not work). prove your answers.
Yes, you can still cover the remaining squares with dominoes. The necessary and sufficient condition for this to work is that the chessboard originally had an even number of squares.
A standard chessboard has 64 squares. If one corner square is missing, we are left with 63 squares. Each domino covers exactly 2 squares, so we need 31.5 dominoes to cover the remaining squares. Since we cannot use half a domino, this means we need a whole number of dominoes. Therefore, the number of squares must be even.
Conversely, if the chessboard originally had an even number of squares, then we can remove any one square and still have an odd number of squares left. Since each domino covers 2 squares, it is easy to see that we can always cover an odd number of squares with dominoes, by placing one domino vertically in the middle of the board. Therefore, in this case we can also cover the remaining squares with dominoes.
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Find an interval of t-values such that c(t) = (cos t, sin t) traces the upper half of the unit circle (in the counter-clockwise direction), interval = Note: Use lowercase "pi" for pi. Example answer: [0,1 ].
The interval of t-values such that c(t) = (cos t, sin t) traces the upper half of the unit circle (in the counter-clockwise direction) is [0, pi].
To see why this is the case, recall that the unit circle is given by the equation x^2 + y^2 = 1, where (x,y) are the coordinates of a point on the circle. The upper half of the unit circle corresponds to the set of points (x,y) where y is positive or zero. We want to find the values of t for which c(t) lies on the upper half of the unit circle.
Using the definition of c(t), we have c(t) = (cos t, sin t). The y-coordinate of c(t) is sin t, so we want, sin t to be positive or zero. Since sin t is positive in the first and second quadrants of the unit circle, and zero at t = 0 and t = pi, we have that c(t) traces the upper half of the unit circle when t is in the interval [0, pi].
To see that c(t) traces the upper half of the unit circle in the counter-clockwise direction, note that as t increases from 0 to pi, c(t) moves counterclockwise around the unit circle, starting at (1,0) and ending at (-1,0). Thus, the interval [0, pi] corresponds to one-half of a full counterclockwise rotation around the unit circle, which is exactly the upper half of the circle.
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Given x = 22 10-((5/25)*100), x is ________. 3,180 3,180 12 12 31. 998 31. 998 13. 5
Using BODMAS, where x = x = 22 + 10-((5/25)*100), x is 12. (Option D)
What is the calculation for the above ?Bracket, Of, Division, Multiplication, Addition, and Subtraction are abbreviated as BODMAS.
The BODMAS is used to describe the sequence in which a mathematical equation operates. The BODMAS is also known as PEDMAS in certain places, which stands for Parentheses, Exponents, Division, Multiplication, Addition, and Subtraction.
Sure, using BODMAS, we get
x = 22 + 10 - ((5/25) x 100)
= 22 + 10 - (0.2 x 00)
= 22 + 10 -20
= 12
Thus, x is equal to 12. (Option D)
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you are testing the claim that the proportion of men who own cats is smaller than the proportion of women who own cats. you sample 100 men, and 35% own cats. you sample 80 women, and 90% own cats. find the test statistic, rounded to two decimal places.
The test statistic is -5.02
To test the hypothesis that the proportion of men who own cats is smaller than the proportion of women who own cats, we can use a two-sample z-test for the difference in proportions.
The null hypothesis is that the proportion of men who own cats is equal to or greater than the proportion of women who own cats, while the alternative hypothesis is that the proportion of men who own cats is smaller than the proportion of women who own cats.
We can calculate the test statistic using the following formula:
z = (p1 - p2) / sqrt(p*(1-p)*(1/n1 + 1/n2))
where
p1 is the proportion of men who own cats (0.35)
p2 is the proportion of women who own cats (0.9)
p is the pooled proportion [(x1 + x2) / (n1 + n2)] = [(0.35100 + 0.980)/(100+80)] = 0.62
n1 is the sample size of men (100)
n2 is the sample size of women (80)
Plugging in the values, we get:
z = (0.35 - 0.9) / sqrt(0.62*(1-0.62)*(1/100 + 1/80)) = -5.02
Rounding this to two decimal places, the test statistic is -5.02.
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PLEASE HELP
Which of the following sentences is written in indicative mood?
If the coach would give a pep talk, then the team would play better.
The team plays much better after a pep talk from their coach.
Will the team play better after a pep talk from their coach?
If I were the coach, I'd give the team a pep talk.
The sentence written in the indicative mood is: "The team plays much better after a pep talk from their coach."
What is indicative mood ?The grammatical mood known as the indicative is employed to state or inquire about facts.
The verb forms in the indicative mood show that the action or state described is actually occurring or has already occurred. For instance, the statement "I am walking to the store" is suggestive since it is a factual statement describing an action that is now occurring.
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You are going to calculate what speed the kayaker 's are paddling, if they stay at a constant rate the entire trip, while kayaking in Humboldt bay.
key information:
River current: 3 miles per hour
Trip distance: 2 miles (1 mile up, 1 mile back)
Total time of the trip: 3 hours 20 minutes
1) Label variables and create a table
2) Write an equation to model the problem
3) Solve the equation. Provide supporting work and detail
4) Explain the results
Answer:
1) Variables:
- Speed of the kayaker (unknown, let's call it x)
- Speed of the current = 3 mph (given)
- Distance kayaked one way = 1 mile (given)
- Total distance covered (round trip) = 2 miles (given)
- Total time of the trip = 3 hours 20 minutes = 3.33 hours (converted to hours for convenience)
Table:
Photo attached.
2) The equation to model the problem is:
distance = rate × time
Using this equation for each kayaking portion, we get:
1 = (x - 3) t
1 = (x + 3) t
We also know that the total time of the trip is 3.33 hours:
t + t = 3.33
2t = 3.33
t = 1.665
3) Now we can solve for x by substituting t = 1.665 in either of the above equations:
1 = (x - 3) (1.665)
x - 3 = 0.599
x = 3.599
Thus, the kayakers are paddling at a speed of 3.599 miles per hour.
4) The kayakers are paddling at a speed of 3.599 miles per hour. This solution is obtained by calculating the average speed of the kayakers over the entire trip, taking into account the opposing speed of the river current. The kayakers are traveling faster downstream (with the current) than upstream (against the current).
Step-by-step explanation:
PLS HELP ASAP THANKS
The given quadratic equation is in vertex form.
option B.
What is the form of the quadratic equation?The form of the given quadratic equation is calculated as follows;
The general form of a parabola given as;
y = a(x - h)² + k
Where;
h, k is the vertex of the parabolaThe given quadratic equation is, y = ¹/₂(x - 2)² + 4, the vertex of this equation is;
a = 1/2
h = 2
k = 4
Therefore, the vertex of the parabola is (2, 4), and we can conclude that the equation is in vertex form.
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Geometry: find how much glass is needed to build.
The amount of glass needed = surface area of the triangular prism = 2,646 cm².
What is the Surface Area of a Triangular Prism?The glass has a triangular prism shape. Therefore, the amount of glass needed to build the showcase is calculated by finding the surface area of the image given.
Surface area = amount of glass needed = Perimeter of triangular face * length of prism + 2 * base area of triangular face
= (S1 + S2 + S3) * L + bh
We are given the variables as:
S1 = 15 cm
S2 = 15 cm
S3 = 24 cm
L = 45 cm
b = 24 cm
h = 9 cm
Plug in the values:
Surface area = (15 + 15 + 24) * 45 + 24 * 9 = 2,430 + 216
amount of glass needed = 2,646 cm²
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PLEASE HELP THIS IS MY LAST QUESTION (07.05 MC)
The graph below represents the function f(x) = (x + 2)(x - 2)(x - A) which has a y-intercept of 12.
The missing value A is
-15
-10 -5
838
30
25
20
15
10
15
Step-by-step explanation:
The y-axis intercept occurs when x = 0
put in 0 for 'x' and compute the intercept as
(0+2)(0-2)(0-A) = 12
-4 ( -A) = 12
4A =12
A = 3
The flow rate y (m3/min) in a device used for air-quality measurement depends on the pressure drop x (in. of water) across the device’s filter. Suppose that for x values between 5 and 20, the two variables are related according to the simple linear regression model with true regression line y = –.12 + .095x.a. What is the expected change in flow rate associated with a 1-in. increase in pressure drop? Explain.b. What change in flow rate can be expected when pressure drop decreases by 5 in.?c. What is the expected flow rate for a pressure drop of 10 in.? A drop of 15 in.?d. Suppose σ = .025 and consider a pressure drop of 10 in. What is the probability that the observed value of flow rate will exceed .835? That observed flow rate will exceed .840?e. What is the probability that an observation on flow rate when pressure drop is 10 in. will exceed an observation on flow rate made when pressure drop is 11 in.?
The probability that an observation on flow rate when pressure drop is 10 in. will exceed an observation on flow rate made when pressure drop is 11 in. is .7602.
a. The expected change in flow rate associated with a 1-in. increase in pressure drop is the slope of the regression line, which is .095 m3/min per in. of water. This means that for each additional inch of pressure drop, we can expect the flow rate to increase by an average of .095 m3/min.
b. When pressure drop decreases by 5 in., we can expect the flow rate to decrease by an average of .095 * (-5) = -.475 m3/min.
c. For a pressure drop of 10 in., the expected flow rate can be calculated by plugging x = 10 into the regression line equation: y = -.12 + .095(10) = .838 m3/min.
d. To find the probabilities, we need to standardize the flow rate values using the formula z = (y - μ) / σ, where μ is the mean flow rate and σ is the standard deviation. For a pressure drop of 10 in., the expected flow rate is .838 m3/min, so
P(Y > .835) = P(Z > (.835 - .838) / .025) = P(Z > -.12) = .4522
P(Y > .840) = P(Z > (.840 - .838) / .025) = P(Z > .08) = .4681
where Z is a standard normal random variable.
e. We need to find the probability that an observation on flow rate when pressure drop is 10 in. will exceed an observation on flow rate made when pressure drop is 11 in. This can be done by subtracting the mean flow rate for each pressure drop from their respective observations, and then finding the probability that the difference is positive. Let Y_10 and Y_11 denote the flow rates for pressure drops of 10 in. and 11 in., respectively. Then the probability of interest is:
P(Y_10 - Y_11 > 0) = P((Y_10 - μ_10) - (Y_11 - μ_11) > -(μ_11 - μ_10))
where μ_10 and μ_11 are the mean flow rates for pressure drops of 10 in. and 11 in., respectively. Since the regression line is linear, we can find the mean flow rate for any given pressure drop x using the equation μ = -.12 + .095x. Therefore,
μ_10 = -.12 + .095(10) = .758 m3/min
μ_11 = -.12 + .095(11) = .853 m3/min
Substituting these values into the probability expression gives:
P(Y_10 - Y_11 > 0) = P((Y_10 - .758) - (Y_11 - .853) > -.095)
We know from part (a) that the standard deviation of the flow rate is σ = .095 m3/min per in. of water. Therefore, the standard deviation of the difference Y_10 - Y_11 is
σ_diff = sqrt(σ^2 + σ^2) = sqrt(2)*σ = .134 m3/min
Using the formula for a standardized normal variable, we have:
P((Y_10 - .758) - (Y_11 - .853) > -.095) = P(Z > (-.095 / .134)) = P(Z > -.71) = .7602
where Z is a standard normal random variable. Therefore, the probability that an observation on flow rate when pressure drop is 10 in. will exceed an observation on flow rate made when pressure drop is 11 in. is .7602.
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determine the amount of fence needed to enclose a rectangular garden with length 30 feet and width 41 feet.
Answer:
142 ft
Step-by-step explanation:
We have to find the perimeter of the rectangular garden.
length = 30 ft
Width = 41 ft
[tex]\sf \boxed{\text{\bf Perimeter of rectangle =2*( length + width)}}[/tex]
= 2 * (30 + 41)
= 2 * 71
= 142 ft
You will need 142 feet of fence to enclose the rectangular garden with length 30 feet and width 41 feet. To determine the amount of fence needed to enclose a rectangular garden with length 30 feet and width 41 feet, follow these steps:
1. Identify the dimensions of the rectangular garden. In this case, the length is 30 feet and the width is 41 feet.
2. Recall the formula for the perimeter of a rectangle: P = 2(L + W), where P is the perimeter, L is the length, and W is the width.
3. Plug in the given dimensions: P = 2(30 + 41).
4. Calculate the sum inside the parentheses: P = 2(71).
5. Multiply by 2 to find the perimeter: P = 142 feet.
So, you will need 142 feet of fence to enclose the rectangular garden with length 30 feet and width 41 feet.
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2-1/3-2/+1 in its simplest fraction
Answer:
7/3
Step-by-step explanation:
2-1/3-2/+1 in its simplest fraction is equal to 7/3.
the top of a silo is a hemisphere with a radius of 8 feet.the cylindrical body of the silo shares the same radius as the hemisphere and has a height of 40 feet.
A truck hauling grain To the silo has a rectangular container attached to the back that is 8' ft In length 5ft in Width and 4' ft height.
Determine the number of truck loads of grain required to fill an empty silo
help please
The number of truck loads of grain required to fill an empty silo is 51.97
How to solve for the truck loadsVolume of the hemisphere = 2/3)πr^3,
Volume of hemisphere would be
[tex]hemisphere = (2/3)\pi (8 ft)^3 = 268.08 ft^3[/tex]
Volume of cylinder = πr^2h
Then we will have
[tex]cylinder = \pi(8 ft)^2(40 ft) \\= 8046.72 ft^3[/tex]
Total volume
[tex]V_hemisphere + V_cylinder = 8314.80 ft^3[/tex]
[tex](8 ft)(5 ft)(4 ft) = 160 ft^3[/tex]
Number of truck loads
= 8314.80 ft^3 / 160 ft^3
= 51.97
Hence the number of truck loads of grain required to fill an empty silo is 51.97
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You have been contracted to complete a square garden landscape. You must order enough bushes and gravel to cover your current project. The client will supply the other materials. Each bush you order will cover one square foot area. One bag of gravel will cover one square foot area as well. The bushes cost $45 each and the bags of gravel will cost $18 each. You will need to add $75 to the total cost of supplies to pay for shipping and tax; you would also like to make $450. How much do you need to charge the client for this job?
You have been contracted to complete a square garden landscape. You will need to add $75 to the total cost of supplies to pay for shipping and tax; you would also like to make $450, then we need to charge the client $63[tex]x^2[/tex] + 525 for this job.
Let's denote the length and width of the square garden by x. Then, the area of the garden is given by A = [tex]x^2[/tex].
To complete the landscape, we need to cover the garden with bushes and gravel. The area of the garden is [tex]x^2[/tex] square feet, so we need to order [tex]x^2[/tex] bushes and [tex]x^2[/tex] bags of gravel.
The cost of the bushes is $45 per bush, so the total cost for the bushes is [tex]45x^2[/tex]. The cost of the gravel is $18 per bag, so the total cost for the gravel is [tex]18x^2.[/tex]
The total cost of the supplies is the sum of the cost of the bushes and the cost of the gravel, plus $75 for shipping and tax:
Total cost = [tex]45x^2 + 18x^2 + 75 = 63x^2 + 75[/tex]
We also want to make a profit of $450, so the amount we need to charge the client is:
Total cost + Profit = 63x^2 + 75 + 450 = 63[tex]x^2[/tex] + 525
Therefore, we need to charge the client $63[tex]x^2[/tex] + 525 for this job.
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WILL GIVE BRAINLIEST The following data shows the grades that a 7th grade mathematics class received on a recent exam. {98, 93, 91, 79, 89, 94, 91, 93, 90, 89, 78, 76, 66, 91, 89, 93, 91, 83, 65, 61, 77} Part A: Determine the best graphical representation to display the data. Explain why the type of graph you chose is an appropriate display for the data. (2 points) Part B: Explain, in words, how to create the graphical display you chose in Part A. Be sure to include a title, axis label(s), scale for axis if needed, and a clear process of how to graph the data. (2 points)
A) The best graphical representation for the given data is a histogram.
B) The histogram of the given data is illustrated below.
Part A:
A histogram is a type of bar graph that shows the frequency distribution of a set of continuous or discrete data. The given data is a set of discrete data, and a histogram is the most appropriate graph to display the distribution of these data.
Part B:
To create a histogram for the given data, we need to follow these steps:
In summary, to create a histogram for the given data, we need to provide a title, label the x and y-axes, choose an appropriate scale for the x-axis, plot the data, and add final touches to make the graph more informative and visually appealing.
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define a method that recieves 2 ints as input parameters and returns true or false depending on whether or not the first nubmer is twice the second
Python Program to Find Whether a Number is a Power of Two. The function power of two is defined. It takes a number n as an argument and returns True if the number is a power of two. If n is not positive, False is returned. If n is positive, then n & (n – 1) is calculated.
To define a function that receives two numbers as input parameters and returns true or false depending on whether or not the first number is twice the second, follow these steps:
1. Define the function with a name, e.g., "is_twice," and specify the two input parameters, e.g., "num1" and "num2."
2. Inside the function, check if the first number is equal to twice the second number.
3. Return True if the condition is met; otherwise, return False.
Here's the function definition:
```python
def is _ twice (num1, num2):
if num1 == 2 * num2:
return True
else:
return False
```
Now you can call this function with two numbers as input parameters, and it will return true or false based on the condition mentioned.
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What is the value of the postfix expression 32 * 2 | 53 - 84/ * ? Select one: O a. 30 " O b. 12 O c. 32 O d. 15
The value of the postfix expression 32 * 2 | 53 - 84/ * is 15.
Here's how to solve it:
1. Start from the left and work towards the right.
2. Multiply 32 and 2 to get 64.
3. Use the bitwise OR operator (|) on 64 and 53. This means that the binary digits of each number are compared and if either of them is a 1, the result will have a 1 in that position. In this case, 64 is 1000000 in binary and 53 is 110101 in binary. When we use the bitwise OR operator, we get 1001101, which is 77 in decimal.
4. Subtract 77 from 53 to get -24.
5. Divide 84 by -24 to get -3.5.
6. Finally, multiply -3.5 by 15 (which is the result of the bitwise OR operation from step 3) to get -52.5.
So, the value of the postfix expression is -52.5, which rounds up to -53, or 15 when the absolute value is taken. Therefore, the correct answer is d. 15.
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Write the following absolute value function as a piecewise function.
please help
The absolute value function as a piecewise function is
f(x) = -(-x^2 + 9x - 18), x < 3 and x > 6f(x) = -x^2 + 9x - 18, 3 ≤ x ≤ 6Writing the absolute value function as a piecewise function.Given that
f(x) = |-x^2 + 9x - 18|
When the expression is factored, we have
f(x) = |-(x - 3)(x - 6)|
Set the expression in the absolute bracket to 0
This gives
-(x - 3)(x - 6) = 0
When the equation is solved for x, we have
x = 3 and x = 6
These values represent the boundaries of the piecewise function
So, we have
f(x) = -(-x^2 + 9x - 18), x < 3 and x > 6
f(x) = -x^2 + 9x - 18, 3 ≤ x ≤ 6
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Find the probability that a randomly
selected point within the circle falls in the
red-shaded triangle.
24
13
10
13
P = [?]
Enter as a decimal rounded to the nearest hundredth.
Enter
The probability that the random;y selected point will be in the triangle = 0.33
How to solve for the probabilitysolve for area covered by the trangke
The area of the triangle is guven as 1/2 x b * h
b = base
h = height
The base = 10
The height = 24
The area = 1 / 2 x 10 x 24
= 240 / 2
= 120
Then we know that the complte angle of a cirle = 360 degrees
The probability that the random;y selected point will be in the triangle = 120 / 360
= 12 / 36
= 0.33
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Answer.
0.23
find area of triangle =120 then find area of circle= 530.66 then divide area of triangle by area of circle
9. 2 worksheet number #2 in exercies 1 and 2 copy and compelete the table write your anwsers in the simplest form
Fron the sine rule of a right angled triangle, the missing values of table are
Row 1 : [tex]3\sqrt{3}[/tex], 8, 5 ;Row 2 : [tex]11\sqrt{3}[/tex], [tex]8 \sqrt{3}[/tex] ;Row 3 : 22, [tex]6\sqrt{3}[/tex], 10.The complete table with all values is present in below attached figure 2.
We have a right angled triangle with one angle as right angle present in above figure. We have to complete the table present below the figure. The measure of angles of triangle except right angle are 60° and 45°. Also, the side lengths of triangle are 'a', 'b' and 'c' units. Using the sine rule, [tex]\frac{a}{sin(A)} =\frac{ b}{sin (B)} = \frac{c}{sin(C)}[/tex]
Here, A = 30°, B = 60°, C = 90° so, [tex]\frac{a}{sin(30°)} = \frac{ b}{sin(60°)} = \frac{c}{sin(90°)} [/tex]
From the Trigonometry Ratio table of
sin(90°) = 1[tex]sin(60°) = \frac{\sqrt{3}}{2}[/tex][tex]sin(30°) = \frac{1}{2} [/tex]So, [tex] \frac{ a}{ \frac{1}{2} } = \frac{b}{ \frac{ \sqrt{3} }{2} } = \frac{c}{1} [/tex]
[tex]2a= \frac{2b}{ \sqrt{3} } = c [/tex]
Now, consider the first column of table where, a = 11, from equation (1),
[tex]2× 11 = \frac{ 2b}{\sqrt{3}}[/tex]
=> [tex]b = 11\sqrt{3}[/tex] and 2× 11 = c
=> c = 22
Consider the second column of table, where b = 9 then, [tex]a = \frac{2× 9} {\sqrt{3}}[/tex]
=> [tex]a = 2× 3\sqrt{3} = 6\sqrt{3}[/tex]
and [tex] 2a = 2× 6\sqrt{3} = c[/tex]
=> [tex] c = 12\sqrt{3}[/tex]
Consider the third column of table, where c =16 then, 2a = c = 16
=> a = 8
and [tex] c = \frac{2b}{\sqrt{3} }= 16 [/tex]
=> [tex]b = \frac{16\sqrt{3}}{2 } = 8\sqrt{3}[/tex].
Consider the fourth column of table, where [tex]b = 5\sqrt{3}[/tex], then
[tex] 2a = \frac{2× 5\sqrt{3}}{\sqrt{3}} = 10[/tex]
=> a = 5
and [tex] c = \frac{2× 5\sqrt{3}}{\sqrt{3}} = 10[/tex]. Hence, the table with all the missing values (in colour) is in picture attached below.
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Complete question:
The above figure complete question.
9. 2 worksheet number #2 in exercies 1 and 2 copy and compelete the table write your anwsers in the simplest form
Express cos K as a fraction in simplest terms.
M
√51
12
K
The value of Cos K as a fraction in simplest terms is K= 42.3⁰
What is Pythagoras theorem?Pythagoras Theorem states that “In a right-angled triangle”, “the square of the hypotenuse side is equal to the sum of squares”. This theorem can be used to derive the base, perpendicular and hypotenuse formulas
CosK = Adj/Hypo
where the Adj = ?
Hypo = 12 Using pyth. rule to find adj
12² = (√51)² + x²
= 144 = 51 + x²
144-51 = x²
93 = x²
x = √93 = 9.6
Then Applying CosK = Adj/Hypo
CosK = √51/9.6
Cos K = 7.1/9.6
Cosk = 0.7396
Making K the subject of the relation we have
K = cos⁻0.7396
K= 42.3⁰
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A playhouse is in the shape of a regular octagonal pyramid with a side length of 3 feet and a slant height of 12 feet. The wood used to build the walls of the playhouse costs $4 per square foot. What is the cost of the wood for the walls of the playhouse?
The cost of the wood for the walls of the playhouse is $1141.44.
To calculate the cost of the wood for the walls of the playhouse, we need to find the surface area of the walls and then multiply it by the cost per square foot.
The surface area of the walls of an octagonal pyramid can be calculated by finding the area of each trapezoidal face and adding them up. Since the side length of the pyramid is 3 feet and the slant height is 12 feet, we can use the Pythagorean theorem to find the height of each trapezoidal face:
h = √(12² - (3/2)²)
h = √(144 - 2.25)
h = √(141.75)
h ≈ 11.89 feet
The area of each trapezoidal face is:
A = 1/2 * (b1 + b2) * h
A = 1/2 * (3 + 3) * 11.89
A ≈ 35.67 square feet
There are 8 trapezoidal faces in the octagonal pyramid, so the total surface area of the walls is:
SA = 8 * A
SA ≈ 285.36 square feet
Finally, we can calculate the cost of the wood for the walls by multiplying the surface area by the cost per square foot:
Cost = SA * $4
Cost = 285.36 * $4
Cost = $1141.44
Therefore, the cost of the wood for the walls of the playhouse is $1141.44.
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Evaluate every equation given. Answers must be in RECTANGULAR FORM. 4. D = (-5+5i](2+2i) 5. E = [tan(1- i)[cot(1+i)] -
E = tan(2) cosh(2) / sinh(2) + i cos(2) / sinh(2) in rectangular form.
We have:
D = (-5+5i)(2+2i)
= -10 - 10i + 10i - 10i^2
= -10 - 10i + 10 + 10i (since i^2 = -1)
= 0
Therefore, D = 0 + 0i in rectangular form.
We have:
E = tan(1- i) cot(1+i)
= (sin(1-i)/cos(1-i)) (cos(1+i)/sin(1+i))
= (sin(1)cos(i) - cos(1)sin(i)) / (cos(1)cos(i) + sin(1)sin(i)) * (cos(1)cos(i) - sin(1)sin(i)) / (sin(1)cos(i) + cos(1)sin(i))
= (sin(1) cosh(1) - i cos(1) sinh(1)) / (cos(1) cosh(1) + i sin(1) sinh(1)) * (cos(1) cosh(1) + i sin(1) sinh(1)) / (sin(1) cosh(1) - i cos(1) sinh(1)) (using hyperbolic identities)
= [(sin(1) cosh(1))^2 + (cos(1) sinh(1))^2] / [(sin(1) cosh(1))^2 - (cos(1) sinh(1))^2] + i [(cos(1) cosh(1) sin(1) sinh(1)) / [(sin(1) cosh(1))^2 - (cos(1) sinh(1))^2]]
= [(sin(2) sinh(2)) / (sinh(2) cos(2))] + i [(cos(2) sinh(2)) / (sinh(2) cos(2))]
= [(sin(2) / cos(2))] / [(sinh(2) / cosh(2))] + i [(cos(2) / cosh(2))] / [(sinh(2) / cosh(2))]
= tan(2) cosh(2) / sinh(2) + i cos(2) / sinh(2)
Therefore, E = tan(2) cosh(2) / sinh(2) + i cos(2) / sinh(2) in rectangular form.
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Find the ending balance if $2,000 was deposited at 4% annual interest compounded
semi-annually for 6 years.
Therefore, the ending balance after 6 years would be $2,728.31
To find the ending balance of a deposit at 4% annual interest, compounded semi-annually for 6 years, we can use the formula for compound interest.
A = P (1 + r/n)^(nt)
Where:A = the ending balance P = the principal (initial deposit) amountr = the annual interest raten = the number of times the interest is compounded per yeart = the time period (in years) For this problem, we have:P = $2,000r = 4% = 0.04n = 2 (compounded semi-annually, so twice per year)t = 6 years Using these values, we can calculate the ending balance:
A = 2000(1 + 0.04/2)^(2*6)A = 2000(1.02)^12A = $2,728.31
.
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HELP
The table represents a quadratic function.
x y
−6 23
−5 8
−4 −1
−3 −4
−2 −1
−1 8
0 23
What is the equation of the function?
y = (x + 3)2 − 4
y = (x − 3)2 + 4
y = 3(x + 3)2 − 4
y = 3(x − 3)2 + 4
Answer: y = (x + 3)2 − 4 is the equation of the function.
Step-by-step explanation:
Please help, I need a fast answer.
Which shortcut can be used to prove . There may be more than one answer. Select all that apply.
The shortcut that can be used to prove ΔAET ≅ ΔFRP is ASA (option d).
The given information includes the measure of some angles and the fact that two sides of the triangles are congruent. To prove that two triangles are congruent, you need to show that all their corresponding sides and angles are congruent.
To determine which shortcut can be used to prove that ΔAET ≅ ΔFRP, we need to check which postulate applies to the given information.
We know that angle AET is congruent to angle FRP (given), AE is congruent to FR (given), and angle T and angle P are congruent (given).
Therefore, the shortcut that applies to this situation is the ASA postulate, which states that two angles and the included side of the triangles are congruent. Thus, we can conclude that ΔAET ≅ ΔFRP by the ASA postulate.
Hence the correct option is (d).
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An experiment consists of spinning the spinner shown. All outcomes are equally likely. Find P(>5). Express your answer as a fraction in simplest form.
The probability of getting a number greater than 5 is 1/4, expressed as a fraction in simplest form.
The spinner shown has 8 equal sectors, numbered 1 through 8. Since all outcomes are equally likely, the probability of obtaining any particular outcome is 1/8.
To find the probability of getting a number greater than 5, we need to count the number of favorable outcomes and divide by the total number of possible outcomes.
There are two favorable outcomes are 6 and 8. Therefore, the probability of getting a number greater than 5 is
P(>5) = favorable outcomes / total outcomes
= 2/8
= 1/4
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-- The given question is incomplete, the complete question is given below
"An experiment consists of spinning the spinner shown. All outcomes are equally likely. Find P(>5). Express your answer as a fraction in simplest form."