another pls! lolllllll

Answer:

C. It is one-half the area of a square of side length 4 units.

Step-by-step explanation:

Hey there!

Well if a square has side lengths of 4 units,

the area would be 16 because of l*w.

Now the formula for the area of a triangle is,

b*h/2

b = 4

h = 4

4*4=16

16 ÷ 2 = 8

So the area of a square is 16 units^2 whereas the area of a triangle with the same dimensions is 8 units^2,

meaning the area of a triangle is one-half the area of a square.

Hope this helps :)

Answer:

Y =4

Step-by-step explanation:

Hope it helps

Answer: 24 because you add 5 for every number ex: 9+5=14

Answer:

24

Step-by-step explanation:

The difference can be calculated by subtracting the second term with the first term.

d = 14 - 9

d = 5

The difference is 5.

Add 5 to 19.

19 + 5 = 24

Step-by-step explanation:

a. The point estimate is the mean, 47 days.

b. The margin of error is the critical value times the standard error.

At 31 degrees of freedom and 98% confidence, t = 2.453.

The margin of error is therefore:

MoE = 2.453 × 10.2 / √32

MoE = 4.42

c.  The confidence interval is:

CI = 47 ± 4.42

CI = (42.58, 51.42)

d. We can conclude with 98% confidence that the true mean is between 42.58 days and 51.42 days.

e. We can reduce the margin of error by either increasing the sample size, or using a lower confidence level.

Answer:

y = -0.85 + 0.09x; $49.82

Step-by-step explanation:

1. Calculate Σx, Σy, Σxy, and Σx²  

The calculation is tedious but not difficult.

[tex]\begin{array}{rrrr}\mathbf{x} & \mathbf{y} & \mathbf{xy} & \mathbf{x^{2}}\\526 & 52.08 & 27394.08 & 276676\\625& 59.00 & 36875.00 &390625\\589 & 56.12 & 33054.68 & 346921\\409 & 25.72 & 10519.48 & 167281\\489 & 34.12& 16684.68 & 293121\\500 & 53.00 & 26500.00 &250000\\906 & 76.48 & 71102.88 & 820836\\251 &26.08 & 6546.08 & 63001\\595 & 50.60 & 30107.00 & 354025\\719 & 68.52 & 49265.88 & 516961\\\mathbf{5609} & \mathbf{503.72} &\mathbf{308049.76} & \mathbf{3425447}\\\end{array}[/tex]

2. Calculate the coefficients in the regression equation

[tex]a = \dfrac{\sum y \sum x^{2} - \sum x \sum xy}{n\sum x^{2}- \left (\sum x\right )^{2}} = \dfrac{503.7 \times 3425447 - 5609 \times 308049.76}{10 \times 3425447- 5609^{2}}\\\\= \dfrac{1725466163 - 1727851103.84}{34254470 - 31460881} = -\dfrac{2384941}{2793589}= \mathbf{-0.8537}[/tex]

[tex]b = \dfrac{n\sumx y - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}} = \dfrac{3080498 - 2825365.48}{2793589} = \dfrac{255132}{2793589} = \mathbf{0.09133}[/tex]

To two decimal places, the regression equation is

y = -0.85 + 0.09x

3. Prediction

If x = 563,

y = -0.85 + 0.09x = -0.85 + 0.09 × 563 = -0.85  + 50.67 = $49.82

(If we don't  round the regression equation to two decimal places, the predicted value is $50.56.)

Answer: A) At 90% confidence interval estimate of the population mean

is,( 25.0405 , 25.9595 )

B) YES

Step-by-step explanation:

Given that,

Point estimate = sample mean  Ж = 25.5

Population standard deviation α  = 5.3

Sample size = n =360

At 90% confidence level the z is ,

∝ = 1 - 90% = 1 - 0.90 = 0.1

∝ / 2 = 0.1 / 2 = 0.05  

Z∝/2 = Z0.05 = 1.645 ( WHEN WE USE THE Z TABLE )

Margin of error E = Z∝/2 * ( α/√n)

E = 1.645 * (5.3 / √360 )  = 0.4595

At 90% confidence interval estimate of the population mean

is

Ж - E < ц < Ж + E  

25.5 - 0.4595 <  ц < 25.5 + 0.4595  

25.0405 <  ц < 25.9595  

( 25.0405 , 25.9595 )

At 90% confidence interval estimate of the population mean

is,( 25.0405 , 25.9595 )

B) This confidence interval can be used to estimate the mean weight of all one - year old babies in the US since the mean value of 25.5 falls within the confidence values, we have sufficient evidence to

conclude that the mean weight of all one-year-old boys is 25.5

Answer:

8 pounds

Step-by-step explanation:

2 x 3 = 6 tb of chili powder in pot 2

find pounds per tablespoon: 48 / 6 = 8 pounds

Answer:

1/2 pound per tablespoon

Step-by-step explanation:

Jaden sure does like his chili!

In the first and second pot, he uses 3 pounds worth of ground beef, which means, 12 ounces of something is a pound. And because Jaden had used 3 times the amount of chili powder in the second pot, he used 6 tablespoons worth of powder. 3 pounds divided by 6 equals 1/2.

Answer:

Spinner: 50%

Die: 50%

Step-by-step explanation:

Well for the spinner it depends on the amount of numbers it has,

in this case we’ll use 6.

So The probability of landing on the even numbers in a 6 numbered spinner.

2, 4, 6

3/6

50%

Your average die has 6 sides so the odd numbers are,

1, 3, 5

3/6

50%

Answer:

13

Step-by-step explanation:

We need to write our answer in exponential form. Ask yourself the question, "What times itself 3 times will give you 2197?" Your answer is [tex]13^{3}[/tex]. This will go inside of your cube root. You now have [tex]\sqrt[3]{13^{3} }[/tex]. Since there's a power of 3 and a cube root, those cancel each other out, and your answer is 13.

Answer:

[tex]\boxed{13}[/tex]

Step-by-step explanation:

=> [tex]\sqrt[3]{2197}[/tex]

Factorizing 2197 gives 13 * 13 * 13

=> [tex]\sqrt[3]{13*13*13}[/tex]

=> [tex]\sqrt[3]{13^3}[/tex]

We know that [tex]\sqrt[3]{} = ^{1/3}[/tex]

=> [tex]13^{3 * 1/3}[/tex]

=> [tex]13^1[/tex]

=> 13

Answer:

The percent of households with rates from $100 to $115. is      [tex]P(100 < x < 115) =[/tex]94.1%

Step-by-step explanation:

From  the question we are told that  

   The  mean rate is [tex]\mu =[/tex]$ 106.50  per month

    The standard deviation is  [tex]\sigma =[/tex]$3.85

Let the lower rate be  [tex]a =[/tex]$100

Let the higher rate  be  [tex]b =[/tex]$ 115

Assumed from the question  that the data set is normally

The  estimate of the percent of households with rates from $100 to $115. is mathematically represented as

         [tex]P(a < x < b) = P[ \frac{a -\mu}{\sigma } } < \frac{x- \mu}{\sigma} < \frac{b - \mu }{\sigma } ][/tex]

here x is a random value rate  which lies between the higher rate and the lower rate so

     [tex]P(100 < x < 115) = P[ \frac{100 -106.50}{3.85} } < \frac{x- \mu}{\sigma} < \frac{115 - 106.50 }{3.85 } ][/tex]

      [tex]P(100 < x < 115) = P[ -1.688< \frac{x- \mu}{\sigma} < 2.208 ][/tex]

Where  

      [tex]z = \frac{x- \mu}{\sigma}[/tex]

Where z is the standardized value of  x

So

     [tex]P(100 < x < 115) = P[ -1.688< z < 2.208 ][/tex]

     [tex]P(100 < x < 115) = P(z< 2.208 ) - P(z< -1.69 )[/tex]

Now  from the z table we obtain that

      [tex]P(100 < x < 115) = 0.9864 - 0.0455[/tex]

     [tex]P(100 < x < 115) = 0.941[/tex]

    [tex]P(100 < x < 115) =[/tex]94.1%

Answer:

Step-by-step explanation:

[tex] \mathrm{Given}[/tex],

[tex] \mathrm{Discount\% = 20\%}[/tex]

[tex] \mathrm{Marked \: price = 1250}[/tex]

[tex] \mathrm{Now \: let's \: find \: the \: discount \: amount}[/tex]

[tex] \mathrm{discount \: amount = dis\% \: of \: MP}[/tex]

[tex] \mathrm { = 20\% \: of \: 1250}[/tex]

[tex] \mathrm{ = 250}[/tex]

[tex] \mathrm{let's \: find \: the \: selling \: price}[/tex]

[tex] \mathrm{ = MP \: - \: discount \: amount}[/tex]

[tex] \mathrm{ = 1250 - 250}[/tex]

= $ [tex] \mathrm{1000}[/tex]

[tex] \mathrm{lets \: find \: the \: Vat \: amount}[/tex]

[tex] \mathrm{vat \: amount = vat\% \: of \: sp}[/tex]

[tex] \mathrm{ = 12.5\% \: of \: 1000}[/tex]

= $ [tex] \mathrm{ 125}[/tex]

[tex] \mathrm{Now \: finally \: let's \: find \: the \: selling \: price \: with \: vat}[/tex]

[tex] \mathrm{selling \: price \: + \: vat \: amount}[/tex]

[tex] \mathrm{ = 1000 + 125}[/tex]

= $ [tex] \mathrm{1125}[/tex]

Therefore, The final sale of the necklace is $ 1125

Hope I helped

Best regards!

Answer:

6n=48

Step-by-step explanation:

product means multiplication

6×n=48

6n=48

An equation that shows this relationship is: A. 6n = 48.

In order to solve this word problem, we would assign a variable to the unknown number, and then translate the word problem into an algebraic equation as follows:

Let the variable n represent the unknown number.

Based on the statement "The product of 6 and a number is 48," we can logically deduce the following algebraic equation;

6 × n = 48

6n = 48

n = 48/6

n = 8.

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Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

[tex]p_{1}(t) = 1[/tex], [tex]p_{2}(t)= t^{2}[/tex] and [tex]p_{3}(t) = 3 + 3\cdot t[/tex]:

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0[/tex]

[tex](\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1} + 3\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2} = 0[/tex]

[tex]\alpha_{3} = 0[/tex]

Whose solution is [tex]\alpha_{1} = \alpha_{2} = \alpha_{3} = 0[/tex], which means that the set of vectors is linearly independent.

[tex]p_{1}(t) = t[/tex], [tex]p_{2}(t) = t^{2}[/tex] and [tex]p_{3}(t) = 2\cdot t + 3\cdot t^{2}[/tex]

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0[/tex]

[tex](\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1}+2\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2}+3\cdot \alpha_{3} = 0[/tex]

Since the number of variables is greater than the number of equations, let suppose that [tex]\alpha_{3} = k[/tex], where [tex]k\in\mathbb{R}[/tex]. Then, the following relationships are consequently found:

[tex]\alpha_{1} = -2\cdot \alpha_{3}[/tex]

[tex]\alpha_{1} = -2\cdot k[/tex]

[tex]\alpha_{2}= -2\cdot \alpha_{3}[/tex]

[tex]\alpha_{2} = -3\cdot k[/tex]

It is evident that [tex]\alpha_{1}[/tex] and [tex]\alpha_{2}[/tex] are multiples of [tex]\alpha_{3}[/tex], which means that the set of vector are linearly dependent.

[tex]p_{1}(t) = 1[/tex], [tex]p_{2}(t)=t^{2}[/tex] and [tex]p_{3}(t) = 3+3\cdot t +t^{2}[/tex]

[tex]\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0[/tex]

[tex]\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2}+ \alpha_{3}\cdot (3+3\cdot t+t^{2}) = 0[/tex]

[tex](\alpha_{1}+3\cdot \alpha_{3})\cdot 1+(\alpha_{2}+\alpha_{3})\cdot t^{2}+3\cdot \alpha_{3}\cdot t = 0[/tex]

The following system of linear equations is obtained:

[tex]\alpha_{1}+3\cdot \alpha_{3} = 0[/tex]

[tex]\alpha_{2} + \alpha_{3} = 0[/tex]

[tex]3\cdot \alpha_{3} = 0[/tex]

Whose solution is [tex]\alpha_{1} = \alpha_{2} = \alpha_{3} = 0[/tex], which means that the set of vectors is linearly independent.

The set of vectors A and C are linearly independent.

Answer:

Z (The one on the bottom right)

Step-by-step explanation:

You said that the y intercept goes down by 1 unit which makes only W and Z possible.

The slope is 1/2 and if you multiply that by -4 the new slope is -2 which means the change in y is -2 every time the change in x is 1. Which perfectly fits Z and if you have any questions please ask me with the comments!

To make it easier, you can convert 7/20 to a decimal, and as a decimal it is 0.35. 0.42*0.35=0.147, so .42*7/20=0.147.

Answer:

0.147

Step-by-step explanation:

0.42 * 7/20

Well, 0.42 = 42/100. Now we have both numbers as fractions.

We can simplify 42/100 to 21/50

Therefore we have 7/20 * 21/50

To multiply fractions multiply the numerators together and multiply the denominators together.

This gives: 147 / 1000

Which is equal to 0.147

Therefore 0.42 * 7/20 = 0.147

Answer:

Step-by-step explanation:

In algebra, we always need to follow a set of steps that involve undoing the operations that led to the equation to reveal the value of x.

e < -12

(Since we divided by a negative number, we must reverse the inequality sign.)

(-1/6)(-12) > 2

2 > 2 ✅

Now we check a number less than -12, such as -14.

(-1/6)(-14) > 2

2 1/3 > 2 ✅

Answer:

x=3 or/and x= -7/3

Step-by-step explanation:

+1= +1

3x = 9

9 divided by 3 is x= 3

+1= +1

3x = -7

-7 divided by 3 is x= -7/3

Answer:

[tex]\huge\boxed{x=3\ \vee\ x=-\dfrac{7}{3}}[/tex]

Step-by-step explanation:

[tex]|a|=\left\{\begin{array}{ccc}a&\text{for}\ a\geq0\\-a&\text{for}\ a<0\end{array}\right\\\\|a|=k\to a=k\ \vee\ a=-k\ \text{for}\ k>0\\==========================\\\\|3x-1|=8\iff3x-1=8\ \vee\ 3x-1=-8\\\\\begin{array}{cccc}3x-1=8&\vee&3x-1=-8&\text{add 1 to both sides}\\3x-1+1=8+1&\vee&3x-1+1=-8+1\\3x=9&\vee&3x=-7&\text{divide both sides by 3}\\\dfrac{3x}{3}=\dfrac{9}{3}&\vee&\dfrac{3x}{3}=\dfrac{-7}{3}\\x=3&\vee&x=-\dfrac{7}{3}\\\end{array}[/tex]

Answer:  = approx 0.2006

Step-by-step explanation:

The probability that first 1 randomly selected  calculator is defective is

P(1st defect)= 42/(42+20)=42/62=21/31

If the first calculator is defective the residual number of defective calculators is 42-1=41. The residual total number  number of calculators is 62-1=61

So the probability that second calculator is defected

P(2nd defective)=41/61

If both previous calculators are defective the residual number of defective calculators is 42-2=40.  Total residual number of calculators is 62-2=60

So the probability that third calculator is defected

P(3rd defective)=40/60=2/3

Finally the probability that also fourth calculator is defective is 39/59

P(4th defective)=39/59

The resulted probability that all 4 calculators are defective is

P(all 4 are defective)= P(1st defect)* P(2nd defect) * P(3rd defect)* P(4th defect)=21*41*2*39/(31*61*3*59)=67158/334707=0.200647... = approx 0.2006

Answer:

d) The t-distribution with 5 degrees of freedom must be used

Step-by-step explanation:

For cases of Normal Distribution where the variance is unknown and the sample size n is smaller than 30, we must use the t-student distribution.

The shape of the curve for t-student is bell-shape (flatter and with wider tails than the bell shape of normal distribution.

Actually, when we deal with t-student distribution we are dealing with a family of curves that will become closer and closer to the bell shape of the normal distribution as the degree of freedom increases. From values of n =30( and bigger),  we can assume that the curve of t-student is the same as for normal distribution

Answer:

a. B1 is better than B2.

Step-by-step explanation:

Hyperplane is a geometric shape which has subspace whose dimension is one less than ambient space. Hyperplane that maximizes the margin it will have better generalization. Margin is calculated by [tex]\frac{2}{||W||}[/tex]. The correct option is a.

Answer:

A

Step-by-step explanation:

Answer:

The graph at the bottom left in your group of possible answers.

Step-by-step explanation:

Notice that the original given graph corresponds to the equation:

[tex]y=2x+1[/tex]

since the line's slope is 2/1 = 2 and the y-intercept is at the point (0, 1).

So if one modifies the equation multiplying the current slope by 1/2, and the y intercept increased by 3 units, Then the new function would be:

[tex]y=x+4[/tex]

A line of slope 1 and y-intercept at (0, 4)

Notice that the graph at the bottom left in your possible answers is representing such function.

Answer:

Answer Y: or Bottom Left of Given Answers

Step-by-step explanation:

Answer:

40091.

Step-by-step explanation:

Multiply 40.091 by 10 three times to get the answer.

40.091 * 10 = 400.91

400.91 * 10 = 4009.1

4009.1 * 10 = 40091.

The expression 40.091 x 10³ can be represented as 40091.

The term xⁿ, read as x to the power n, shows an exponent n, which implies x is multiplied by itself n times.

In the question, we are asked to arrange the cards showing '.', '0', '0', '1', '4', and '9', to show the solution to the expression 40.091 x 10³.

Now, 10³ is 10 to the power 3, where 3 is the exponent, so 10 is multiplied by itself 3 times = 10*10*10 = 1000.

Now, the expression 40.091 x 10³ = 40.091 * 1000 = 40091.

∴ The expression 40.091 x 10³ can be represented as 40091.

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Answer:

5 years

Step-by-step explanation:

Principal Amount to be paid=$4500

Interest rate = 2%

Number if Times compounded= number of years

Number of years = x

Among total= $5010

A= p(1+r/n)^(nt)

But n= t =x

A= p(1+r/x)^(x²)

5010=4500(1+0.02/x)^(x²)

5010/4500 = (1+0.02/x)^(x²)

1.11333=( 1+0.02/x)^(x²)

Using trial and error method the number of years maximum to give approximately $5010 is 5 years

Answer:

a = 8.1

Step-by-step explanation:

Firstly, since we have a triangle, automatically, we have 3 interior angles

Mathematically the sum of these angles = 180

A + B + C = 180

27 + 25 + C = 180

52 + C = 180

C = 180-52

C = 128

We use the sine rule to find a

The sine rule posits that the ratio of a side to the sine of the angle facing that side is equal for all the sides of a triangle

Thus, mathematically according to the sine rule;

c/Sin C = a/Sin A

14/sin 128 = a/sin 27

a = 14sin27/sin 128 = 8.0657

which to the nearest tenth is 8.1

Answer:

  10%

Step-by-step explanation:

Using the given formula with the given data, we have ...

  efficiency = output work / input work

  = (10 J)/(100 J) = 0.10 = 10%

Answer:

A) 10%

Step-by-step explanation:

10/100=10

The correct answer is 180 oranges

Explanation:

In mathematics, a ratio expresses two or more numbers that are related. In the case fo the ration 9: 40 this expresses 9 oranges are used to serve fruit salad for 40 people. Now, if you need to determine what is the number of oranges not for 40 people but for 800 people you can use cross multiplication. This process is explained below:

[tex]\frac{9}{40} = \frac{x}{800}[/tex]   - 1. Multiply  9 x 800 and 40 x x (cross multiplication)

[tex]7200 = 40x[/tex] - 2. Solve the equation by diving 7200 into 40

[tex]\frac{7200}{40} = x[/tex]

[tex]x = 180[/tex] - 3. 180 represents the number of oranges to serve 800 people, which   can be expressed as 180: 800

Answer:

Step-by-step explanation:

Confidence interval for the population mean is expressed by the formula;

CI = xbar ± Z(S/√n) where;

xbar is the sample mean = 12.5

Z is the z score at 99% confidence = 2.576

S is the standard deviation = √variance

S = √2.4 = 1.5492

n is the sample size = 25

Substituting the given values into the formula given above,

CI = 12.5 ± 2.576(1.5492/√25)

CI = 12.5 ± 2.576(0.30984)

CI = 12.5 ± 0.7981

CI = (12.5-0.7981, 12.5+0.7981)

CI = (11.2019, 12.7981)

Hence the 99% confidence interval for the population mean is 11.2≤[tex]\mu[/tex]12.8 (to 1 decimal place)

A 99% confidence interval for the population mean will be "11.2 [tex]\leq[/tex] 12.8".

According to the question,

Sample mean, [tex]\bar x[/tex] = 12.5

Z score at 99%, Z = 2.576

Standard deviation, S = √Variance

                                    = √2.4

                                    = 1.5492

Sample size, n = 25

We know the formula,

Confidence interval, CI = [tex]\bar x \ \pm[/tex] Z ([tex]\frac{S}{\sqrt{n} }[/tex])

By substituting the given values, we get

                                        = 12.5 [tex]\pm[/tex] 2.576 ([tex]\frac{1.5492}{\sqrt{25} }[/tex])

                                        = 12.5 [tex]\pm[/tex] 2.576 (0.30984)

                                        = 12.5 [tex]\pm[/tex] 0.7981

Now,

                                   Cl = (12.5 - 0.7981, 12.5 + 0.7981)

                                        = (11.2019, 12.7981) or,

                                        = (11.2, 12.8)

Thus the above answer is appropriate.        

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Answer:

B. (1,7)

Step-by-step explanation:

We can substitute the x and y values of each coordinate into the inequality and test if they work.

Let's start with A, 5 being y and 0 being x .

[tex]5 > |0|+5\\5> 0+5\\5 > 5[/tex]

5 IS NOT greater than 5, they are the exact same, so A is out.

Let's try B, 1 being x and 7 being y.

[tex]7 > |1| + 5\\7 > 1 + 5\\7 > 6[/tex]

7 IS greater than 6, so B. (1,7) does work for this inequality!

Let's do C for fun, when 7 is x and 1 is y.

[tex]1 > |7| + 5\\1>7+5\\1>12[/tex]

1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.

Therefore B. (1,7) works for the inequality of [tex]y > |x|+5[/tex].

Hope this helped!

Answer:

[tex]\large \boxed{\bf \sf \ \ \ 7x-9 = 3(x+2) \ \ \ }[/tex]

Step-by-step explanation:

Hello,

x represents this number and we know that

the difference between seven times this number and 9

   7*x - 9

is equal to three times the sum of this number and 2

   3(x+2)

So we can write

[tex]7x-9 =3(x+2) \\\\7x-9 =3x+6 \ \ \text{distributive law} \\\\7x-9-3x=3x+6-3x =6 \ \ \text{subtract 3x} \\\\4x-9+9=6+9 \ \text{add 9} \\\\4x=15 \ \ \text{divide by 4} \\\\ \boxed{x=\dfrac{15}{4}}\\[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you