Answer the following questions
1- How to Calculate Power?
2- What is the units of Power?
3- Write a solved example?

1) The heat is 10,800 J

2) The heat is 2400 J

3) The time is 100 s

The heating effect of current, also known as Joule heating or resistive heating, is a phenomenon where electrical energy is converted into heat when an electric current flows through a material that has resistance.

1) We know that;

H = I^2rt

H = (3)^2 * 4 * 5 * 60

H = 10,800 J

2) H = (V^2/R)t

H = (10)^2/5 * 2 * 60

H = 2400 J

3) H =(V^2/R)t

t = H/(V^2/R)

t = H * R/V^2

t = 4 * 10^3 * 10/20^2

t = 100 s

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The distance an object travels in a unit of time is called the speed of the object. SI. the unit of speed is meter per second (ms−1).

Speed ​​is measured in relation to distance compared to the time it took to cover the distance. Speed ​​is a scalar quantity because it only has  direction and not magnitude.  There are four types of speeds and they are:

Even speed
Variable speed
Average speed
Instantaneous speed
Constant velocity: An object is at a constant velocity when the object travels the same distance in equal intervals of time.
Variable speed: an object is said to have variable speed when the object travels varying distances at regular intervals.
Average speed: Average speed is defined as the constant speed obtained by the ratio of the total distance traveled by the object to the total time spent on the object.  Instantaneous velocity: When an object is moving with a variable velocity, the velocity of that object at any instant of time is called instantaneous velocity.
Speed ​​measurement
A speedometer is used to measure the speed of vehicles. An odometer is used to measure the distance traveled. Speed ​​can also be calculated using a gragraphph. A distance-time graph helps to understand the speed of an object.

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A-the minimum coefficient of friction is 0.18 ,B- it is unreasonable, C-no premises is inconsistent.

(a) Calculation of the minimum coefficient of friction needed for a car to negotiate an unbanked 50.0 m radius curve at 30.0 m/s:  A car moving with a velocity of 30.0 m/s in a circular path of radius 50.0 m negotiates an unbanked curve. Hence, the force required to move a car in a circular path is the frictional force between the wheels of the car and the road.

The minimum coefficient of friction needed for a car to negotiate an unbanked 50.0 m radius curve at 30.0 m/s is given by:μmin = tanθ= v² / rgWhere,μmin is the minimum coefficient of frictionv is the velocity of the carr is the radius of the curveg is the acceleration due to gravity θ is the angle of banking.

As the curve is unbanked, the angle of banking is 0°.∴ μmin = v² / rg= (30.0 m/s)² / (50.0 m × 9.81 m/s²)= 0.183 or 0.18 (approx)

(b)The result of 0.18 is not unreasonable.

(c) None of the premises is unreasonable or inconsistent.

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When an item must be moved 36 meters in 14 seconds using 726 watts of electricity, its mass is 28.8 kg.(c) is the right option.

Any quantity in mechanics may be defined in terms of mass, length, length time. The letter m stands for kilogram, which represents mass in the SI. Contrary to popular belief, relativistic mass must always be thought of when moving at speeds that are near to the lightest possible speed.

The Power is provided with p = 726 watt.

The Time is 14 seconds.

d = 36 m is the distance traveled.

Use the provided formula to calculate power.

p = W / t

p = m * g * h / t (w = m * g * h)

726 = m * 9.8 * 36 / 14 ( g = 10 m/s^2)

m = 28. 8kg.

As a result, the object's mass 36 m in 14 s equals 28.8 kg even when an item needs 726 watts of electricity to move it.

The mass of it as an item, a key indication of the volume of both the thing's contents, is used to calculate its inertia, a fundamental attribute. Descriptions of weight might appear circular because it's such a fundamental concept and difficult to express in words of every other concept.

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Answer:

Answer:please mark as brainliest

The impulse that acts on the shoe during its collision with the wall is -15 kg*m/s (to the left).

Calculation steps:

The initial momentum of the shoe, p1 = mv1 = 0.3 kg * 20 m/s = 6 kgm/s (to the right)

The final momentum of the shoe, p2 = mv2 = 0.3 kg * (-30 m/s) = -9 kgm/s (to the left)

The change in momentum, Δp = p2 - p1 = -9 kgm/s - 6 kgm/s = -15 kg*m/s (to the left)

Therefore, the impulse acting on the shoe during its collision with the wall is J = Δp = -15 kg*m/s (to the left)

What is impulse?

Impulse refers to the change in momentum of an object when a force is applied to it for a certain amount of time. It is defined as the product of the force and the time for which it acts on an object. Mathematically, impulse can be expressed as:

J = F * Δt

where J is the impulse, F is the force applied, and Δt is the time for which the force acts.

What is momentum?

Momentum is a physical quantity that measures the motion of an object. It is defined as the product of an object's mass and velocity. In other words, momentum = mass x velocity.

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A boat float on the surface of the lake sends a signal summer force vertically down to the water the sooner trace is 0. 007 sand the speed of sound is 1,500m/s. 21 meters deep is the water.

The time it takes for the sound wave to travel from the boat to the bottom of the lake and back is given by:

t = 2d/v

Where:

d = depth of the water

v = speed of sound in water (1,500 m/s)

We can solve for d by rearranging the equation as:

d = v × t/2

Where:

t = the time it takes for the sound wave to travel from the boat to the bottom of the lake and back, which is equal to twice the time it takes for the sound wave to travel from the boat to the bottom of the lake.

The time it takes for the sound wave to travel from the boat to the bottom of the lake is given by:

t = d/v

Where:

d = distance traveled by the sound wave (which is equal to the depth of the water)

v = speed of sound in water (1,500 m/s)

We can substitute this expression for t into the equation for d to get:

d = v × d/2v

Simplifying this expression, we get:

d/0.007 = 2 × 1500

d = 21 meters

Therefore, the depth of the water is approximately 21 meters.

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Answer:

Fission occurs when a neutron slams into a larger atom, forcing it to excite and split into two smaller atoms—also known as fission products. Additional neutrons are also released that can initiate a chain reaction. When each atom splits, a tremendous amount of energy is released.

Explanation:

Answer:

Fission

Explanation:

this happens when the neutrons an atoms slams into a larger atom, forcing it to split into two smaller atoms

To calculate the magnitude of the linear momentum for each of the cases, you need to use the following equation:

Linear momentum (p) = mass (m) x velocity (v)

Case (a): Linear momentum (p) = 1.67 x 10-27 kg x 5.00 x 106 m/s = 8.35 x 10-22 kg m/s

Case (b): Linear momentum (p) = 0.015 kg x 300 m/s = 4.5 kg m/s

Case (c): Linear momentum (p) = 75.0 kg x 10.0 m/s = 750 kg m/s

Case (d): Linear momentum (p) = 5.98 x 1024 kg x 2.98 x 104 m/s = 1.78 x 1029 kg m/s

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The position of the image of the object would be 7.5 cm behind the mirror.

The focal lengths of all convex mirrors are negative and are given by the following formula:

1/f = - (1/R)

where:

Substituting for R in the equation, we are going to have:

1/f = -1/20 cm

f = -20 cm

Next, we can make use of the mirror formula to find the position of the image along the plane of the mirror:

The mirror formula goes thus:

1/f = 1/do + 1/di

where 'do' is the object distance and di is the image distance.

Substituting the values of f and di:

1/-20 cm = 1/12 cm + 1/di

Thus:

di = -7.5 cm

That the di is negative is an indication that the image is a virtual one that forms behind the mirror. In other words, the position of the image is 7.5 cm behind the mirror.

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Answer:

50m/s.

Explanation:

Answer:

[tex]V_f=50m/s[/tex]

Explanation:

Use the the formula for final velocity (kinematic equation):

[tex]V_f=V_i+at[/tex]

Final velocity = Initial velocity + acceleration times time

Given values:

Rest - indicates 0 initial velocity

Acceleration - 10 m/s^2

Time - 5 seconds

Insert the given values:

[tex]V_f=0+5\times10[/tex]

[tex]V_f=50m/s[/tex]

Answer:

B. herbivore.

Explanation:

Meadow voles primarily consume plants, such as grasses, herbs, and bark, although they may also eat insects occasionally. As a result, their niche in an ecosystem is that of a herbivore, which is an organism that consumes primarily plants.

Answer: The Earth is an oblate spheroid, meaning it is roughly spherical in shape but flattened at the poles and bulges at the equator. This shape has been scientifically proven through centuries of evidence and observations. While some people may claim that the Earth is flat, this idea is not supported by scientific evidence.

The speed of a harmonic wave traveling in a medium is given by the product of its wavelength and frequency, i.e.,

v = λ f, where v is the velocity of the wave, λ is the wavelength, and f is the frequency. In this case, the given amplitude of the wave is not needed to calculate the speed. We can simply use the wavelength and frequency provided to find the velocity. Substituting the given values, we get: v = (1.09 m) × (649 Hz) = 706.41 m/s. Therefore, the speed with which the wave travels is 706.41 m/s. Note that the unit of velocity in SI is meters per second (m/s).

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When two rope segments pull up on the load in the single movable pulley, the optimal mechanical advantage is 2. This sort of pulley does not change the direction of the applied force, but it does increase it by a factor of two.

There are two methods for calculating a pulley system's mechanical advantage.

The mechanical advantage may be calculated simply by counting the number of falls (or active lifting ropes) that are really attached to the load. You may also split the effort distance by the load distance.

Assuming an ideal rope and pulley system with a mechanical advantage of  [tex]2.00[/tex] , the output load that can be lifted with an input force of [tex]200 N[/tex] can be calculated using the formula:

Output force = Input force x Mechanical advantage

Where the mechanical advantage is given as [tex]2.00[/tex]  .

Thus, the output force is:

Output force [tex]= 200 N \times 2.00 = 400 N[/tex]

Therefore, with an input force of [tex]200 N[/tex]  , the rope and pulley system can lift an output load of up to [tex]400 N[/tex] .

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The ratio of diameter of lenses to its focal length is referred as the f-number or f-stop

The ratio of diameter of lenses to its focal length is referred to as the f-number or f-stop. It is a fundamental parameter that describes the aperture of a lens, which determines the amount of light that can pass through the lens. The f-number is calculated by dividing the focal length of the lens by the diameter of the aperture, which is the opening that controls the amount of light entering the lens.

A smaller f-number indicates a larger aperture, which allows more light to enter the lens, resulting in a brighter image and a shallower depth of field. Conversely, a larger f-number indicates a smaller aperture, which allows less light to enter the lens, resulting in a darker image and a greater depth of field.

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The speed of the sled and the two people immediately after the collision is approximately 15.8 m/s.

The conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the sled and the two people form a closed system, because there are no external forces acting on them.

Let's define the initial state as before the collision, and the final state as after the collision. In the initial state, the sled and the 76 kg person have a momentum of:

p1 = (76 kg)(20 m/s) = 1520 kg·m/s

The second person is stationary, so their momentum is zero:

p2 = 0 kg·m/s

The total momentum before the collision is therefore:

p1i = p1 + p2 = 1520 kg·m/s + 0 kg·m/s = 1520 kg·m/s

In the final state, the two people and the sled move together with a common velocity, which we'll call v. The total mass of the system is:

m = 76 kg + 20 kg = 96 kg

The total momentum after the collision is:

p1f = m v

By the conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision:

p1i = p1f

1520 kg·m/s = 96 kg × v

Solving for v, we get:

v = 1520 kg·m/s / 96 kg ≈ 15.8 m/s

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The current flowing through each wire is the experiment's independent variable because it is the one that the experimenter is actively manipulating and controlling.

The resistance is influenced by the wire's thickness, so the thicker the wire, the lower the resistance. Because less water can flow through a narrower pipe in a given length, there is more resistance in a narrower pipe.

Due to the alloy composition of nichrome wire, its resistance is quite high. Because of this, it generates a lot of heat when current flows through it, making it extremely hot to the touch.

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For Machine 1  ideal mechanical advantage is 4, for machine 2 the IMA is 8 and for the machine 3 the IMA is 4. The load the machines can lift is 400N, 800N and 200N respectively.

The ideal mechanical advantage of a machine is an important factor in determining its efficiency and usefulness. The higher the IMA, the easier it is to lift heavy loads with less effort. However, it is important to note that the actual mechanical advantage (AMA) may differ from the ideal due to various factors such as friction and other mechanical losses. Therefore, it is essential to consider both IMA and AMA when evaluating the performance of a machine.

Machine 1:

Ideal Mechanical Advantage (IMA) = Load / Effort

IMA = 400 N / 100 N

= 4

Machine 2:

IMA = Load / Effort

IMA = 800 N / 100 N

= 8

Machine 3:

IMA = Load / Effort

IMA = 200 N / 50 N

= 4

In simple terms, the ideal mechanical advantage (IMA) of a machine is the ratio of the load it can lift to the effort or force needed to lift it. In other words, it is the number of times a machine multiplies the force or effort applied to it.

For Machine 1, the IMA is 4, which means that the machine can lift a load that is four times heavier than the applied force. Therefore, if you apply 100 N of force to the machine, it can lift a load of up to 400 N.

For Machine 2, the IMA is 8, which means that it can lift a load that is eight times heavier than the applied force. If you apply 100 N of force to this machine, it can lift a load of up to 800 N.

For Machine 3, the IMA is 4, which means that it can lift a load that is four times heavier than the applied force. If you apply 50 N of force to this machine, it can lift a load of up to 200 N.

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Suppose that Reid weighs 72 kg. 2. The mouse macaque of India is the shortest primate on Earth, with an average weight of just 30.0 g. Imagine that this lemur swings 

What does the statistical term "average" mean?

Average. In everyday speech, a average is a specific number chosen to represent a collection of figures. In various settings, various average ideas are utilized. The word "average" frequently refers to the mathematical mean, which is the total of the values divided by the number of numbers being averaged. Statistical terms: mean, median

What are the several definitions of average?

In various settings, various average ideas are utilized. The word "average" frequently refers to the mathematical mean, which is the total of the integers divided by the amount of numbers being averaged. Mean, average, and mode all are considered measures of normal distribution in statistics, and in common parlance, any of these could be referred to as an average figure.

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Answer:

yes if you can only install a magnetic force into the bar

A roller-coaster car is towed up an incline at a steady speed of 0.500 m/s by a chain parallel to the surface of the incline. the slope is 3.00%. ignoring friction, the magnitude of the force exerted on the car by the chain is: 5908.7 N

The magnitude of the force exerted on the roller-coaster car by the chain is equal to the net force on the car, which is equal to the sum of the force due to gravity and the force due to the incline. Since the roller-coaster car is moving at a steady speed, the net force on the car must be equal to zero.

Using Newton's second law of motion, we can calculate the force due to gravity (Fg) and the force due to the incline (Fi) in order to determine the magnitude of the force exerted on the car by the chain.

The force due to gravity (Fg) can be calculated as Fg = m * g, where m is the mass of the roller-coaster car and g is the acceleration due to gravity. Therefore, Fg = 604 kg * 9.8 m/s2 = 5902.8 N.

The force due to the incline (Fi) can be calculated as Fi = m * g * sinθ, where m is the mass of the roller-coaster car, g is the acceleration due to gravity, and θ is the angle of the incline. The angle of the incline is equal to the slope of the incline divided by 100. Therefore, θ = 3.00% / 100 = 0.03 radians.

Therefore, [tex]Fi = 604 kg * 9.8 m/s2 * sin(0.03) = 5.9 N.[/tex]

Therefore, the magnitude of the force exerted on the car by the chain is equal to the sum of the force due to gravity and the force due to the incline. [tex]F = Fg + Fi = 5902.8 N + 5.9 N = 5908.7 N.[/tex]

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The tension T in the string just after the objects are released must be equal and opposite to the accelerations of each mass.

The statement refers to a physical principle known as Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

In the context of the given statement, it means that the tension (T) in the string, which is the force transmitted through the string, must be equal in magnitude and opposite in direction to the accelerations of each mass.

When objects are released and allowed to move under the influence of gravity, they may be connected by a string or rope. As the objects accelerate due to the force of gravity, the tension in the string changes to keep the objects connected and moving together.

According to Newton's third law, the tension in the string must be equal and opposite to the accelerations of each mass.

If one of the objects has a greater acceleration, the tension in the string must be higher on that side to counteract the greater acceleration.

Similarly, if one of the objects has a lower acceleration, the tension in the string must be lower on that side. This ensures that the net force on each object is balanced and that they move together without breaking the string.

This is because Newton's Second Law states that the sum of the forces on an object is equal to the mass times the acceleration: F = ma. Therefore, the tension T must be the same for both masses, since their accelerations must be equal and opposite.

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Answer:

12.928 kJ

Explanation:

To calculate the energy required to melt a substance, we use the formula:

Q = m * ΔHfus

where Q is the energy required, m is the mass of the substance, and ΔHfus is the heat of fusion, which is the amount of energy required to melt one gram of the substance.

For methane, the heat of fusion is 0.202 kJ/g. We can calculate the amount of energy required to melt 64g of methane as follows:

Q = m * ΔHfus

Q = 64g * 0.202 kJ/g

Q = 12.928 kJ

Therefore, it takes approximately 12.928 kJ of energy to melt 64g of methane at 90K.

The mass of the planet is approximately [tex]7.87 x 10^23 kg.[/tex]

We can use the formula for the gravitational force between two masses:

[tex]F = G * (m1 * m2) / r^2[/tex]

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them. In this case, the person's weight on the planet is equal to the force of gravity between the person and the planet: F = 75 N. The person's mass is 80 kg, so their weight on Earth would be:

[tex]W = m * g = 80 kg * 9.8 m/s^2 = 784 N[/tex]

We can set these two forces equal to each other and solve for the mass of the planet: [tex]75 N = G * (80 kg * m_planet) / (r_planet)^2\\[/tex]We can rearrange this equation to solve for the mass of the planet:

[tex]m_planet = (75 N * (2500 km)^2) / (G * 80 kg)\\[/tex]

where[tex]G = 6.674 x 10^-11 N*m^2/kg^2[/tex]is the gravitational constant.

Plugging in the values, we get: m_planet = [tex](75 N * (2500 km)^2) / (6.674 x 10^-11 N*m^2/kg^2 * 80 kg)[/tex]

m_planet = [tex]7.87 x 10^23 kg[/tex]

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Metamorphosis refers to the process of development and change in the body form of certain animals as they grow from juveniles to adults.

Explain the types of metamorphosis?

Metamorphosis is classified into two types: complete and incomplete.

1. Complete metamorphosis:

Complete metamorphosis is a developmental process in which the juvenile form of an animal goes through four distinct stages: egg, larva, pupa, and adult. In this type of metamorphosis, the juvenile form looks completely different from the adult form in terms of appearance, behavior, and habitat.

Animals that undergo complete metamorphosis include:

a) Butterflies and moths: The egg hatches into a caterpillar (larva) that feeds and grows rapidly. The larva then forms a pupa or chrysalis, where the body undergoes a complete transformation into an adult butterfly or moth.

b) Flies: The egg hatches into a worm-like maggot (larva) that feeds and grows. The maggot then transforms into a pupa, and finally, an adult fly emerges.

c) Beetles: The egg hatches into a grub (larva) that feeds and grows. The grub then transforms into a pupa, and finally, an adult beetle emerges.

Incomplete metamorphosis:

Incomplete metamorphosis is a developmental process in which the juvenile form (nymph) of an animal resembles the adult in appearance and habitat, but is smaller and lacks wings. The nymph goes through several stages of growth and molting before reaching adult form.

Animals that undergo incomplete metamorphosis include:

a) Grasshoppers: The egg hatches into a nymph that resembles the adult grasshopper but lacks wings. The nymph goes through several molts and growth stages before developing wings and reaching the adult stage.

b) Cockroaches: The egg hatches into a nymph that resembles the adult cockroach but lacks wings. The nymph goes through several molts and growth stages before developing wings and reaching the adult stage.

c) Dragonflies: The egg hatches into a nymph that lives in water and resembles the adult dragonfly but lacks wings. The nymph goes through several molts and growth stages before developing wings and emerging from the water as an adult dragonfly.

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The correct answer for a) the rocket was 19,671.65 meters (or 19.67 km) from the ground when the boosters turned off, b) rocket's upward acceleration while its boosters were firing was 11.7 m/s^2, c) the boosters were firing for 58.04 seconds, d)  the rocket is in the air for a total of 199.38 seconds

a) To find the distance from the ground when the boosters turned off, we can use the formula for displacement in terms of initial velocity, acceleration, and time:
d = v_i*t + 0.5*a*t^2

We know the initial velocity (v_i) is 0 m/s, the acceleration (a) is 11.7 m/s^2, and the final velocity (v_f) is 679 m/s.

We can use the formula v_f = v_i + a*t to find the time (t) that the boosters were firing:

679 m/s = 0 m/s + 11.7 m/s^2 * t

t = 58.04 s

Now we can plug this time into the displacement formula:

d = 0 m/s * 58.04 s + 0.5 * 11.7 m/s^2 * (58.04 s)^2

d = 19,671.65 m

So the rocket was 19,671.65 meters (or 19.67 km) from the ground when the boosters turned off.

b) The prototype rocket's upward acceleration while its boosters were firing was 11.7 m/s^2, as given in the question.

c) As calculated in part a), the boosters were firing for 58.04 seconds.

d) To find the total time the rocket is in the air, we need to find the time it takes to reach its maximum height and the time it takes to fall back to the ground.

We can use the formula d = v_i*t + 0.5*a*t^2 again, with the initial velocity (v_i) being 679 m/s, the acceleration (a) being -9.8 m/s^2 (due to gravity), and the displacement (d) being the difference between the maximum height and the height when the boosters turned off:

42.3 km - 19.67 km = 22.63 km = 22,630 m

22,630 m = 679 m/s * t + 0.5 * -9.8 m/s^2 * t^2

Solving this quadratic equation gives us two solutions for t, but only one is positive:

t = 70.67 s

So the time it takes to reach the maximum height is 70.67 seconds.

The time it takes to fall back to the ground is the same, since the initial and final velocities are the same but in opposite directions. Therefore, the total time the rocket is in the air is:

t_total = 58.04 s + 70.67 s + 70.67 s = 199.38 s

So the rocket is in the air for a total of 199.38 seconds before striking the ground.

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