Anya is wrapping gift boxes in paper. Each gift box is a rectangular prism. The larger box has a length, width, and height twice as large as the smaller box. Which statement shows the relationship between the surface areas of the gift boxes?A. The larger gift box has a surface area 2 times as large as the smaller gift box.B. The larger gift box has a surface area 4 times as large as the smaller gift box.C. The larger gift box has a surface area 6 times as large as the smaller gift box.D. The larger gift box has a surface area 8 times as large as the smaller gift box.thank you ! :)

Anya Is Wrapping Gift Boxes In Paper. Each Gift Box Is A Rectangular Prism. The Larger Box Has A Length,

Answers

Answer 1

The surface area of a rectangular prism is calculated using the formula:

[tex]\begin{gathered} SA=2LW+2LH+2WH \\ or \\ SA=2(LW+LH+WH) \end{gathered}[/tex]

Let us assume that this is the surface area of the smaller box.

Now, let's represent the surface area of the bigger box by doubling the dimensions of the smaller box.

[tex]SA_{big}=2(2L\cdot2W+2L\cdot2H+2W\cdot2H)[/tex]

Let's simplify this by factoring out the common factors.

[tex]\begin{gathered} SA_{b\imaginaryI g}=2(2L\cdot2W+2L\cdot2H+2W\cdot2H) \\ \\ SA_{b\imaginaryI g}=2\cdot2\cdot2(L\cdot W+L\cdot H+W\cdot H) \\ \\ SA_{big}=4\cdot2(LW+LH+WH) \\ \\ SA_{big}=4SA \end{gathered}[/tex]

So the answer is option B (The larger gift box has a surface area 4 times as large as the smaller gift box).


Related Questions

1024 km are equal to how many cm?

Answers

Answer:

1024 km are equal to 102400000 cm

Explanation:

There are a hundred thousand centimeters in one kilometer, this would help us convert 1024 km to cm, as required.

Let x denote the value of 1024 km in cm.

1 km = 100000 cm

1024 km = x cm

Then we have:

x = 1024 * 100000

= 102400000

Therefore, there are 102400000 cm in 1024 km.

Which of the following is the standard equation of the ellipse with vertices at (3, 0) and (13, 0) and an eccentricity of four fifths question mark

quantity x minus 8 end quantity squared over 25 plus y squared over 9 equals 1
quantity x plus 8 end quantity squared over 9 plus y squared over 25 equals 1
quantity x minus 8 end quantity squared over 100 plus y squared over 64 equals 1
quantity x plus 8 end quantity squared over 64 plus y squared over 100 equals 1

Answers

The ellipse equation is given by option a: quantity x minus 8 end quantity squared over 25 plus y squared over 9 equals 1.

What is termed as the ellipse?An ellipse does have an eccentricity less than one and reflects the locus of points whose distances from the ellipse's two foci are a constant value. The shape of the an egg in two dimensions and running monitoring in a sports stadium are two simple examples of ellipses in our daily lives.

The equation for an ellipse of centre is:

(x - x₀)²/a² + (y - y₀)²/b² = 0.

The values a and b are determined by the vertices and eccentricity.

That has vertices at (3, 0) and (13, 0) , resulting in:

x₀ = 13 + 3 / 2 = 8

y₀ = 0 + 0 /2 = 0

a = 13 - 3/2 = 5

a² = 25

It has the eccentricity of 4/5, so:

4/5 = c/a

c = 4

Thus, b is given by the following equation:

c² = a² - b²

b² = a² - c²

b² = 25 - 16

b² = 9

The ellipse's equation is:

(x - 14)²/25 + (y )²/9 = 1.

Thus, the equation of ellipse is "quantity x minus 8 end quantity squared over 25 plus y squared over 9 equals 1."

To know more about the ellipse, here

https://brainly.com/question/16904744

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When Steve woke up his temperature was 102 F. Two hours later is was 3 degrees lower. What is his temperature now?

Answers

[tex]99^{\circ}[/tex]

1) Considering that when He woke up the temperature was 102ºF and then there was a decrease in the temperature by we can write out the following:

[tex]102^{\circ}-3^{\circ}=99^{\circ}[/tex]

Note that the temperature decreased by exactly 3º.

2) Hence, the answer is 99ºF

Please help me with this question thank you very much

Answers

[tex]\begin{gathered} 5+5=10 \\ _{\text{ }}and \\ 5+5+n=10+n \end{gathered}[/tex]

The equations are equivalent by the equality property of addition, which states that if we add the same quantity to both sides of an equation, then our equation remains the same. Since john is adding n to both sides, the equation remains the same and therefore, they are equivalent.

Find the area of the figure. (Sides meet at right angles.)2 cm2 cm5 cmcmc7 cm

Answers

In the given figure, there are two squares and one rectangle.

The side of one square is , 2 cm

Therefore, the area of square is,

[tex]A_1=2^2[/tex][tex]A_1=4cm^2[/tex]

The side of other square is, 5 cm.

Therefore, the area of square is,

[tex]A_2=5^2[/tex]

The area of square is ,

[tex]A_2=25cm^2[/tex]

Similarly, the area of rectangle is,

[tex]A_3=5\times2[/tex][tex]A_3=10cm^2[/tex]

Therefore, the area of figure is,

[tex]A=A_1+A_2+A_3[/tex][tex]A=\text{ 4}+25+10[/tex][tex]A=39cm^2[/tex]

The area of f

The denominator of a fraction is one more than three times

Answers

Given:-

The denominator of a fraction is one more than three times and if 8 is added to the neumerator and the demominator then the solution is 1/2.

To find the equation.

So now the given fraction is,

[tex]\frac{x}{1+3x}[/tex]

So now we add. so we get,

[tex]\frac{x+8}{1+3x+8}=\frac{1}{2}[/tex]

So now we get,

[tex]\frac{x+8}{3x+9}=\frac{1}{2}[/tex]

So this is the required solution.

iDentify the equation of the circle that has its center at (-27, 120) and passes through the origin A. (x−27)^2+(y+120)^2=123 B. (x+27)^2+(y−120)^2=123 C. (x−27)^2+(y+120)^2=15129 D. (x+27)^2+(y−120)^2=15129

Answers

The equation of a circle with radius r centered at (h,k) is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

If the circle passes through the origin, then we have:

[tex]r^2=h^2+k^2[/tex]

Then, for a circle centered at (-27,120) passing through the origin, we have:

[tex]\begin{gathered} r^2=(-27)^2+120^2 \\ r^2=15129 \\ (x+27)^2+(y-120)^2=15129 \end{gathered}[/tex]

Answer: D

the figure Shown is the base of a right solid that is 10 meters high corners that look square are square find the latter will surface of the solid dimensions are in metres

Answers

let's find the area by parts

red is the first part

we need the area of the red square an substract the mid-circle area

square is A=bxh

so A=2x4=8

the area of the circle is A=pi x r2

so the area of the circle is A=pi x 4 and the middle is 2pi

the total red area is

[tex]\begin{gathered} Ar=8-2\pi \\ \end{gathered}[/tex]

green part

te area is A=bxh, the heigth is 4 like the diameter of the circle and the base is 8 less 2 (of the radius) and less 4(of the base

Graph the rational functiony=x^2-3/x-1. Both branches of the rational function pass through which quadrant?Quadrant 2Quadrant 3Quadrant 4Quadrant 1

Answers

Answer:

Quadrant 1

Explanations:

Given the rational function

[tex]y=\frac{x^2-3}{x-1}[/tex]

From the function, you can see that the vertical asymptotes of the function is at x = 1 (the point where the denominator is zero),

The quadratic numerator also shows that the curves cuts the x-axis at two points as shown in the graph below;

From the graph shown, you can see that the both branches of the function pass through the Quadrant 1. For other quadrants, either one of none of he branches passes through

h + 1.8 =11.9 and how do I check my answer on that

Answers

EXPLANATION

Given the equation h + 1.8 = 11.9

Subtracting -1.8 to both sides:

h = 11.9 - 1.8

Adding like numbers:

h = 10.1

We can check the answer by substituting on the equation as follows:

10.1 + 1.8 = 11.9

Adding numbers:

11.9 = 11.9

As the numbers are equal, the equation is well done.

find the value of X that would prove j || k. state the converse that justifies your answer.

Answers

Let's begin by listing out the given information:

Lines j & k are parallel. Both are intersected by a transversal line

Both angles in the picture are congruent. As such, the value of x is:

[tex]\begin{gathered} 14x-25=129 \\ 14x=129-25 \\ 14x=104 \\ x=\frac{104}{14}=7.4286\approx7.43 \\ x\approx7.43 \end{gathered}[/tex]

The converse of j || k is k || j (k is parallel to j)

Which of the folding statements of true of the functions below? F(x)=(x-1)(x-3)2(x-3)2

Answers

a) the multiplicity of x=3, or (x-3), is 2. That means, this zero repeats twice.

b) one of the roots is x=3, not x=-3

c) odd function: f(-x)=-f(x)

f(-x) = (-x-1)^2(-x-3)^2

(x^2 + 2x + 1 ) (x^2 +6x +9)

-f(x)=-(x-1)^2(x-3)^2

=-(x^2-2x+1)(x^2-6x+9)

f(-x) is not equal as -f(x)

d) If we graph the function, we will see that it range is y>0

For this reasion, statement A is true.

The two polygons are similar. Write a proportion and solve for x. I just need help with 13

Answers

EXPLANATION

The appropiate relationship is

[tex]\frac{x}{3}=\frac{6}{4}[/tex]

Multiplying both sides by 3:

[tex]x=3\cdot\frac{6}{4}[/tex]

Simplifying terms:

[tex]x=\frac{9}{2}[/tex]

The answer is x=9/2 or 4.5

this is not a graded test it my homework asap

Answers

The given expression is

100^a x 1000^b

Recall,

100 = 10^2

1000 = 10^3

Thus, the expression would be

10^2a x 10^3b

We would apply one of the rules of exponents which is expressed as

a^b x a^c = a^(b + c)

By applying this rule, we have

10^(2a + 3b)

By comparing it with 10^w, we have

w = 2a + 3b

What is the formula if the speed is missing? *A. s=t/dB. s=d/tC. s=t+dD. s=d x tFind the area of a trapezoid with bases of 4cm and 6cm, height of 5cm? *A. 120 sq.cmB. 60 sq.cm.C. 50 sq.cm.D. 25 sq.cm.

Answers

Answer:

Explanations:

Lesson 3 Problem-solving Practice Adding Linear Expressions 2. Heather was building a scale model of the Pentagon for her history class. 7" P= (246) 3. A mailing st mailing env a variety of 4 centimete Write and the perime (2x + 3) in a. Write and simplify an expression to represent the perimeter of Heather's scale model. 4. Find the perimete b. Find the perimeter of the model if x = 2:

Answers

Since a pentagon is 5 sided, the perimeter would be:

[tex]5(2x+3)\rightarrow10x+15[/tex]

Using x = 2 , we would get:

[tex]10(2)+15=20+15=35[/tex]

Please explain how to solve this problem and Please explain step by step explanation.
Determine whether the intermediate value theorem guarantees that the function has a zero on the given interval.

f (x) = x3 - 2x2 + 16x + 28; [4, 5]
A Yes
B No

Answers

Answer:  B)  no

==========================================================

Explanation:

The interval we're working with is [4,5] aka [tex]4 \le \text{x} \le 5[/tex]

We'll plug the endpoints of said interval into the f(x) function

Let's start with x = 4

[tex]f(\text{x}) = \text{x}^3-2\text{x}^2+16\text{x}+28\\\\f(4) = (4)^3-2(4)^2+16(4)+28\\\\f(4) = 124\\\\[/tex]

The actual result doesn't matter. All we care about is if the value is positive or negative. We see that f(4) is positive.

Now plug in x = 5

[tex]f(\text{x}) = \text{x}^3-2\text{x}^2+16\text{x}+28\\\\f(5) = (5)^3-2(5)^2+16(5)+28\\\\f(5) = 183\\\\[/tex]

The value of f(5) is positive as well.

Unfortunately we don't have enough info to determine if f(x) has a root in the interval [4,5]

We would need either of the following conditions

f(4) negative and f(5) positivef(4) positive and f(5) negative

In other words, we need the signs of f(4) and f(5) to alternate. One needs to be positive, the other negative. This is to guarantee that the f(x) curve crosses the x axis at some point. Think of it like a river or a road. The continuous road can't magically jump over the x axis without crossing it.

But because f(4) and f(5) don't differ in sign, this means we don't know if f(x) ever dips below the x axis. It might as shown in figure 1, but it may not as indicated in figure 2. There's simply not enough information.

Select the interval where g is negativeA:2< x < 3B: 3 < x < 4C: 4 < x < 5D: none of the above

Answers

To select the interval where g is negative:

From the graph,

We observe that

The interval where g is negative is,

[tex]-4So, the correct option is,[tex]2Therefore, the co

what is the equation (05) (3,0)

Answers

I’m not entirely sure what can of equation you are asking to be answered but if it is a y-intercept formula then the answer would be:

The way I found this answer is by first finding the slope of the two points. I can do this by using the Slope formula which is = (y2 - y1) / (x2 - x1), this can also be phrased as Point 2, in this case (3,0) minus Point 1 (0, 5)

After plugging in the numbers (0,5) and (3,0) into the formula I get:

0-5/3-0 = -5/3

After identifying the slope I begin to then plug in the slope and one of the two Points (either 0,5 or 3,0) on the graph into a different equation, the slope-intercept formula y = mx + b (by the way, m stands for the slope in this equation so m is equal to the slope or m = slope)

After I plug in the numbers I get:

y = mx + b

5 = -5/3(0) + b

5 = b

The answer to this problem should be:

y = -5/3(x) + 5

m arc Ab=80°find the length

Answers

Solution

For this case we know the diameter:

D= 9 ft

Then the radius is:

r= 9/2 ft

Then we can use the following formula

[tex]\text{mAB}=2\pi r(\frac{\theta}{360})[/tex]

Then the measure would be:

[tex]\text{mAB}=2\pi\cdot\frac{9}{2}(\frac{80}{360})=2\pi[/tex]

4Solve each problem to color the picture! Type your answers in the box56.78Orange The worlds tallest house ofcards measured 8 meters tall and wasbuilt in Dallas, Texas. There areapproximately 5 meters in 16 feet.What was the heightof the house ofcards in feet?91011121315Yellow30Purple 10.517Green35Red2419Blue228.6Orange

Answers

Since the given information says, there are approximately 5 meters in 16 feet, we need to find the height in feet of the house of cards which is 8 meters tall

We need to find X in feet.

X = 8 * 16 / 5 = 25.6 ft

Is the point (3,-2) a solution to the system of equations?

Answers

Answer:

Explanation:

What we have to do is to make a substitution of the coordinates into the two given equations

If we have a match with the values on the right sides of the equality signs of both equations, then the point is a solution to the system

Thus, we substitute x = 3 and y = -2

We have:

[tex]\begin{gathered} 3(3)\text{ +4(-2) = 9-8 = 1} \\ 2(3)-5(-2)\text{ = 6+10 = 16} \end{gathered}[/tex]

Now, as we can see, the point worked for the first equation but did not work for the second

Ultimately, what that means is that the point is not a solution to the system of equations

As the number of years decreases from 2 to 1 in the following graph, does the population increase, decrease, or remain the same?

Answers

Given the graph of Time Vs. Population, you can identify that the x-axis represents the Time (in years), and the y-axis represents Population (in thousands),

Notice that, in this case, when:

[tex]x=2[/tex]

The corresponding y-value is:

[tex]y=4[/tex]

And when:

[tex]x=1[/tex]

The y-value is:

[tex]y=6[/tex]

Therefore, you can identify that as the number of years decreases from 2 to 1, the population increases.

Hence, the answer is: First option.

The pair of square pyramids are similar. Use the given information to find the scale factorof the smaller square pyramid to the larger square pyramid.The scale factor is :)(Type whole numbers.)

Answers

If the scale factor of one figure to another one is k, then the ratio of their volumes is equal to:

[tex]k^3[/tex]

The volume in cubic inches of the smaller pyramid is 27, while the volume of the bigger pyramid is 343. Then:

[tex]k^3=\frac{27}{343}[/tex]

Take the cubic root to both members of the equation to isolate k:

[tex]\begin{gathered} \Rightarrow k=\sqrt[3]{\frac{27}{343}} \\ =\frac{\sqrt[3]{27}}{\sqrt[3]{343}} \\ =\frac{3}{7} \end{gathered}[/tex]

Therefore, the scale factor of the smaller pyramid to the larger pyramid, is:

[tex]\frac{3}{7}[/tex]

I keep getting kicked out every time a tutor goes to answer my question.

Answers

(C) translation 8 units right

Explanation

given the fuction:

[tex]f(x)=x[/tex]

was transformed to obtain

[tex]g(x)=x-8[/tex]

so, the transformation to the patern function was subtract 8

Step 2

when you subtrac a value k to the function´s argument the function is shifted to the rigth, so the answer is

(C) translation 8 units right

I hope this helps you

To find the measure of

Answers

Let us first get the value of z,

[tex](2z-3)^0+(5z-6)^0=180^0[/tex][tex]\begin{gathered} 2z-3^0+5z-6^0=180^0 \\ \text{collec like terms,} \\ 2z+5z-3^0-6^0=180^0 \end{gathered}[/tex][tex]\begin{gathered} 7z-9^0=180^0 \\ 7z=180^0+9^0 \\ 7z=189^0 \end{gathered}[/tex][tex]\begin{gathered} z=\frac{189^0}{7} \\ z=27^0 \end{gathered}[/tex]

Hence, the value of z is 27°.

Let us now solve for the measure of angle M,

[tex]m\angle M=(5z-6)^0[/tex][tex]\begin{gathered} \text{where z=27}^0 \\ \text{substitute the value of z into the expression and find the angle M} \end{gathered}[/tex][tex]m\angle M=(5\times27-6)^0[/tex][tex]\begin{gathered} =135^0-6^0 \\ m\angle M=129^0 \end{gathered}[/tex]

Hence, the value of the measure of angle M is 129°.

Sasha goes to buy groceries. She buys two packages of corn (99€ per package),three gallons of milk ($2.90 per gallon), and a loaf of bread ($1.29). She givesthe clerk $20.00 for her purchases. How much change does Sasha get back?

Answers

First, multiply the price of each item by the number of items to find the total amount of money spent on each:

2 packages of corn for $0.99 each

[tex]2\times0.99=1.98[/tex]

3 gallons of milk for $2.90 each

[tex]3\times2.90=8.70[/tex]

A loaf of bread: $1.29

Then, add all the quantities to find the total price for all the purchases:

[tex]1.98+8.70+1.29=11.97[/tex]

Substract the total price of the purchases from $20.00 to find the amount of change that Sasha gets back:

[tex]20.00-11.97=8.03[/tex]

Therefore, the amount of money that she gets back, is:

[tex]8.03[/tex]

x² + 2x = 0 To resolve

Answers

we have the quadratic equation

[tex]x^2+2x=0[/tex]

Solve the quadratic equation

Solve by factoring

Factor x

[tex]x(x+2)=0[/tex]

The values of x are

x=0x=-2

HELP ME PLEASEEEEEEEEEEEEE

Answers

Answer: B At most 45 cakes

Step-by-step explanation:

Given, 5x + 15 ≤ 240

⇒ x + 3 ≤ 48 [Dividing by 5 on both sides]

⇒ x ≤ 45 [Subtracting 3 from both sides]

that means the bakery makes less than or equal to 45 cakes. the most cakes they can make is 45. So they make at most 45 cakes a day

The point (4,3) is rotated 180° about the origin. What are the coordinates of this point after therotation?

Answers

ANSWER:

(-4, -3)

STEP-BY-STEP EXPLANATION:

We have the following point:

[tex](4,3)[/tex]

A 180° rotation complies with the following rule:

[tex]\begin{gathered} P(x,y)\rightarrow P^{\prime}(-x,-y) \\ \text{therefore, in this case:} \\ (4,3)\rightarrow(-4,-3) \end{gathered}[/tex]

The point after the rotation is (-4, -3)

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