This String method removes beginning and ending spaces of the given string.
Solactone
Answer:
The trim() method will remove both leading and trailing whitespace from a string and return the result. The original string will remain unchanged. If there is no leading or trailing whitespace to be removed, the original string is returned. Both spaces and tab characters will be removed.
This is very useful when comparing user input with existing data. A programmer often racks his brain for hours trying to figure out why what he enters is not the same as a stored string, only to find out that the difference is only a trailing space. Trimming data prior to comparison will eliminate this problem.
Answer:
String result = str. trim(); The trim() method will remove both leading and trailing whitespace from a string and return the result.
Explanation:
A venture tube is used to measure the flow rate of a liquid in a pipe (liquid density is 800 kg/m3). The pipe has a diameter of 10 cm and the smallest diameter of the venture has a diameter of 4 cm. A manometer with a manometer fluid of mercury (specific weight of 133 kN/m3) is used to calculate the flow rate which is connected to the venture section such that one leg is far upstream and the second leg is at the minimum diameter of the venture tube. If the flow rate is 0.05 m3/s determine the elevation change in the manometer fluid.
a. 14.6 m
b. 9.28 m
c. 4.64 m
d. 2.32 m
Answer:
[tex]\triangle h=4.935m[/tex]
Explanation:
From the question we are told that:
Liquid density [tex]\rho=800[/tex]
Diameter of pipe [tex]d=4cm \approx 0.004m[/tex]
Diameter of venture [tex]d=10cm \approx 0.010m[/tex]
Specific weight of mercury P_mg [tex]133 kN/m^3[/tex]
Flow rate [tex]r=0.05 m^3/s[/tex]
Area A:
[tex]A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\[/tex]
Generally the Bernoulli's equation is mathematically given by
[tex]\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\[/tex]
Where
[tex]V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}[/tex]
Therefore
[tex]P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})[/tex]
Generally the equation for pressure difference b/w manometer fluid is given as
[tex]P_1-P_2=(p_mg-pg)\triangle h[/tex]
Therefore
[tex](p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})[/tex]
[tex]\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}[/tex]
[tex]\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}[/tex]
[tex]\triangle h=4.935m[/tex]
Therefore elevation change is mathematically given by
[tex]\triangle h=4.935m[/tex]
Users of E85 see a drop in gas mileage because ethanol can't produce the same
amount of energy gasoline can. How much of a drop do they see?
Select one:
a. They see a 10-20% drop in gas mileage
b. The statement is wrong. There is no drop in gas mileage.
c. They see a 30-40% drop in gas mileage
d. They see a 20-30% drop in gas mileage
Answer:
A
Explanation:
Due to ethanol's lower energy content, FFVs operating on E85 get roughly 15% to 27% fewer miles per gallon than when operating on regular gasoline, depending on the ethanol content.
The electron concentration in silicon at T = 300 K is given by
n(x) = 10^16exp(-x/18) cm^-3
where x is measured in μm and is limited to 0 ≤ x ≤ 25 μm. The electron diffusion coefficient is Dn = 25 cm2/s and the electron mobility is μn = 960 cm2/V-s. The total electron current density through the semiconductor is constant and equal to Jn = -40 A/cm2. The electron current has both diffusion and drift current components. Determine the electric field as a function of x which must exist in the semiconductor.
Answer:
[tex]E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m[/tex]
Explanation:
From the question we are told that:
Temperature of silicon [tex]T=300k[/tex]
Electron concentration [tex]n(x)=10^{16}\exp (\frac{-x}{18})[/tex]
[tex]\frac{dn}{dx}=(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})[/tex]
Electron diffusion coefficient is [tex]Dn = 25cm^2/s \approx 2.5*10^{-3}[/tex]
Electron mobility is [tex]\mu n = 960 cm^2/V-s \approx0.096m/V[/tex]
Electron current density [tex]Jn = -40 A/cm^2 \approx -40*10^{4}A/m^2[/tex]
Generally the equation for the semiconductor is mathematically given by
[tex]Jn=qb_n\frac{dn}{dx}+nq \mu E[/tex]
Therefore
[tex]-40*10^{4}=1.6*10^{-19} *(2.5*10^{-3})*(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})+(10^{16}\exp (\frac{-x}{18}))*1.6*10^{-19}*0.096* E[/tex]
[tex]E=\frac{-2.5*10^-^7 exp(\frac{-x}{18})+40*10^{4}}{1.536*10^-4exp(\frac{-x}{18} )}[/tex]
[tex]E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m[/tex]
Explain the importance of wearing appropriate protective clothing and equipment (PPE), and keeping the work area safe and tidy
Answer:
The wearing of appropriate protective clothing and equipment (PPE) and the keeping of the work area safe and tidy achieve the following for the employees and employers: safety from physical and biological harm that may occur as a result of their contact with the work environment; reduces the cost of insurance and other risk management activities.
Explanation:
The personal protective equipment (PPE) is a safety equipment that protects workers from health or safety risks at their various workplaces. The main purpose is to reduce the workers' exposure to environmental hazards. PPE reduces accidents, improves the health of workers, and reduces the spread of contagious diseases. Above all, it creates safe, secure, and healthy work environments for all.