anyone know how to do this

Answer:

Negative electric charges

.........

Explanation:

Option B..... ...

Answer:

None of them. It would be 30-Love.

Explanation:

0 points is Love

1 point is 15

2 points is 30

3 points is 40

Answer:

Lol nice

Explanation:

Answer:

[tex]M=1.72Am^2[/tex]

[tex]T=1.810N-m[/tex]

Explanation:

From the question we are told that:

Radius [tex]r=0.0435[/tex]

Number of turns [tex]N=40turns[/tex]

Current [tex]I= 7.25 A[/tex]

Magnetic Field [tex]B=1.05T[/tex]

Generally the equation for magnetic moment M is mathematically given by

 [tex]M=NIA[/tex]

 Where

  [tex]A= Surface Area[/tex]

  [tex]A=\pi(r)^2[/tex]

  [tex]A=3.142*(0.0435)^2[/tex]

  [tex]A=5.95*10^{-3}[/tex]

Therefore the magnetic moment  is given as

 [tex]M=NIA[/tex]

 [tex]M=40*7.25*5.95*10^{-3}[/tex]

 [tex]M=1.72Am^2[/tex]

Generally the equation for Torque on the coil T is mathematically given by

[tex]T=M*B[/tex]

[tex]T=1.72*1.05[/tex]

[tex]T=1.810N-m[/tex]

Therefore torque on coil T is given a

[tex]T=1.810N-m[/tex]

Answer:

Calculate the wavelength associated with an electron with energy 2000 eV.

Sol: E = 2000 eV = 2000 × 1.6 × 10–19 J

Answer:

Copper

Explanation:

Copper is the least resistant because it is the best conductor of electricity in the options mentioned.

Answer:

force on the electron is upwards

Explanation:

The magnetic force is given by the relation

        F = q v x B

the bold indicates vectors, we can write the module of this expression

        F = q v  B sin θ

the direction of the force is given by the right hand rule.

If we have a positive charge, the flea points in the direction of velocity, in this case towards the inside of the page.

fingers extended in the direction of the magnetite field, in our case to the right and

the palm gives the direction of the force for a positive charge, for a negative charge it is in the opposite direction. The palm points downwards, so the force on the electron is upwards

Answer:

The same current flows through each resistor in series. Individual resistors in series do not get the total source voltage, but divide it. The total resistance in a series circuit is equal to the sum of the individual resistances: RN(series)=R1+R2+R3+…

Answer:

c

Explanation:

the gas pedal gives the engine the fuel it needs to give the car the power to go

Answer:

the required distance is 89.125 m

Explanation:

Given the data in the question;

we know that, sound intensity B in decibels of sound is;

β(dB) = 10log₁₀( [tex]I[/tex] / [tex]I_0[/tex] )

where intensity [tex]I[/tex] = power / area carried by wave

[tex]I_0[/tex] = 10⁻¹² W/m² { minimum threshold intensity }

Now,

intensity [tex]I[/tex] = power / area carried by wave = P/A = P/4πr² { spherical  }

given that; β = 80.0 dB and P = 10 W

so

β(dB) = 10log₁₀( [tex]I[/tex] / [tex]I_0[/tex] )

we substitute

80 = 10log₁₀( P / 4πr²× [tex]I_0[/tex])

80 = 10log₁₀( 10 / 4πr²× 10⁻¹² )

8 = log₁₀(10) - log₁₀( 4πr²× 10⁻¹² )  

8 = 1 - log₁₀( 4πr²× 10⁻¹² )

8 - 1 = -log₁₀( 4πr²× 10⁻¹² )

7 = -log₁₀( 1.2566 × 10⁻¹¹ × r² )

7 = -[ log₁₀( 1.25 × 10⁻¹¹) + log₁₀( r² ) ]

7 = -[ -10.9 + log₁₀( r² ) ]

7 = 10.9 - log₁₀( r² )

-log₁₀( r² ) = 7 - 10.9

-log₁₀( r² )  = - 3.9

log₁₀( r² ) = 3.9

2log₁₀r = 3.9

log₁₀r  = 3.9 /2

log₁₀r = 1.95

r = 89.125 m

Therefore, the required distance is 89.125 m

Answer:

L₀ = 0.0022 m = 2.2 mm

Explanation:

Here, we will use the length contraction formula from the theory of relativity presented by Einstein:

[tex]L = L_o\sqrt{1-\frac{v^2}{c^2}}[/tex]

where,

L = Relative length = 1.57 mm = 0.00157 m

L₀ = actual length at rest = ?

c = speed of light

v = relative speed = 70% of c = 0.7 c

Therefore,

[tex]0.00157\ m = L_o\sqrt{1-\frac{(0.7\ c)^2}{c^2} }\\\\L_o = \frac{0.00157\ m}{\sqrt{1-0.49}}[/tex]

L₀ = 0.0022 m = 2.2 mm

a) The speed of the bead at B is 11.79m/s.

b) The change in mechanical energy due to friction as it  moves from B to C is 36.064 J.  

If we drop the object from the shelf or release the spring, that potential energy is converted back into kinetic energy. Kinetic energy can also be transferred from one body to another in a collision, which can be elastic or inelastic.

a)

Potential energy is converted  to kinetic energy

[tex]\frac{1}{2} mv^2=mgh\\\\v=\sqrt{2gh} \\\\v_B=\sqrt{2(9.8)(7.1-0)} \\\\v_B=11.79m/s[/tex]

The speed of the bead at B is 11.79m/s.

b)

[tex]W = mg(h_A) - mg(h_B) = 0.8(9.8)(7.1 - 2.5) = 36.064 J\\\\W=36.064J[/tex]

The change in mechanical energy due to friction as it  moves from B to C is 36.064 J.

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Answer: deceleration of [tex]1.904\ rad/s^2[/tex]

Explanation:

Given

Car is traveling at a speed of u=20 m/s

The diameter of the car is d=70 cm

It slows down to rest in 300 m

If the car rolls without slipping, then it must be experiencing pure rolling i.e. [tex]a=\alpha \cdot r[/tex]

Using the equation of motion

[tex]v^2-u^2=2as\\[/tex]

Insert [tex]v=0,u=20,s=300[/tex]

[tex]0-(20)^2=2\times a\times 300\\\\a=\dfrac{-400}{600}\\\\a=-\dfrac{2}{3}\ m/s^2[/tex]

Write acceleration as [tex]a=\alpha \cdot r[/tex]

[tex]-\dfrac{2}{3}=\alpha \times 0.35\\\\\alpha =-\dfrac{2}{1.05}\\\\\alpha =-1.904\ rad/s^2[/tex]

So, the car must be experiencing the deceleration of [tex]1.904\ rad/s^2[/tex].

The angular accelaration of a car traveling at 20.0 m/s on tires with a diameter of 70.0 cm, when car slows down to rest after traveling 300.0 m is 1.91 m/s

Angular acceleration: This can be defined as the rate of change of angular velocity. The s.i unit of angular acceleration is  rad/s²

In other to solve the problem above, we will use the formula for calculating angular acceleration

a = αr.............. Equation 1

Where a = acceleration of the car's tires, α = angular acceleration of the car's tires, r = radius of the car's tires

Therefore,

α = a/r................. Equation 2

But, we need to calculate a using the equations of motion

v² = u²+2as................ Equation 3

Where v = final velocity = 0 m/s (rest), u = initial velocity= 20m/s, s = distance = 300 m

Substitute these values into equation 3

0² = 20²+2(300²)a

-400 = 600a

a = -400/600

a = -0.67 m/s²

going back to equation 2,

Given: r = 70/2 = 35 cm = 0.35 m

Substitute this values into  equation 2,

α = -0.67/0.35

α = -1.91 rad/s²

Hence, the magnitude of the angular acceleration is 1.91 rad/s²

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Answer:

In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium.

Explanation:

I hope this helped you

(Sorry If it didn't)

Answer:

D

Explanation:

D ok ok ok ok bye

The correct statement is that the alcohol has lower boiling point than water. The correct option is B.

At the boiling point, the pressure exerted by the surroundings on a liquid equals the pressure exerted by the liquid's vapor, under this condition, adding heat outcomes in the transformation of the liquid into its vapor without raising the temperature.

The boiling point of alcohol is low. Because there is less hydrogen bonding between ethanol molecules than between water molecules.

The ethanol requires less energy to vaporize than water, and water has a higher boiling point than ethanol.

The boiling point of a liquid can be known by utilizing the capillary method, that encompasses placing an inverted capillary in the liquid of interest as well as heating it.

Thus, the correct option is B.

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Answer:

mmmm im going to say B but i’m not sure

Explanation:

Electromagnetic waves can travel through air and unlike ocean waves or sound waves they do not need physical molecules for like a medium to travel

Answer:

It can travel in various wavelengths. brainliest?

Explanation:

The evidence that reveals about the light is that  It can travel in various wavelengths.

It is the wave property that should be blending of the wave related to the corners.

At the time when the wave is bending so it passed via the openings.

Also, the light diffracted via the small slits and it should be shown to arise in the water waves and the sound waves.

hence, the first option is correct.

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Answer:

A&B

Explanation:

Answer:

Chemical to mechanical(b) and Chemical to Thermal(a)

Answer:

    vₐ = v_c  [tex]( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )[/tex]

Explanation:

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

          Em₀ = K + U = ½ m v_c² - G Mm / R

final point. At a very distant point

         Em_f = U = - G Mm / R₂

energy is conserved

           Em₀ = Em_f

           ½ m v_c² - G Mm / R = - G Mm / R₂

           v_c² = 2 G M (1 /R -  1 /R₂)

if we consider the speed so that it reaches an infinite position R₂ = ∞

           v_c = [tex]\sqrt{\frac{2GM}{R} }[/tex]

now indicates that the mass and radius of the planet changes slightly

            M ’= M + ΔM = M ( [tex]1+ \frac{\Delta M}{M}[/tex] )

            R ’= R + ΔR = R ( [tex]1 + \frac{\Delta R}{R}[/tex] )

we substitute

           vₐ = [tex]\sqrt{\frac{2GM}{R} } \ \frac{\sqrt{1+ \frac{\Delta M}{M} } }{ \sqrt{1+ \frac{ \Delta R}{R} } }[/tex]

let's use a serial expansion

           √(1 ±x) = 1 ± ½ x +…

we substitute

         vₐ = v_ c ( [tex](1 + \frac{1}{2} \frac{\Delta M}{M} ) \ ( 1 - \frac{1}{2} \frac{\Delta R}{R} )[/tex])

we make the product and keep the terms linear

        vₐ = v_c  [tex]( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )[/tex]

The minimum escape speed, vc , for an object launched from the surface of the planet will be    [tex]v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})[/tex]

The escape velocity is defined as the velocity required to send the object out of the gravitational influence of the earth.

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

    [tex]E_{mo} = K + U = \dfrac{1}{2} m v_c^2 - \dfrac{G Mm} { R}[/tex]

final point. At a very distant point

      [tex]E_{mf} = U = \dfrac{- G Mm }{ R_2}[/tex]

energy is conserved

         [tex]E{mo} = E{mf}[/tex]

          [tex]\dfrac{1}{2}m v_c^2 - \dfrac{G Mm} {R} = \dfrac{- G Mm }{ R_2}[/tex]

[tex]v_c^2 = 2 G M (\dfrac{1} {R} - \dfrac{ 1 }{R_2})[/tex]

if we consider the speed so that it reaches an infinite position R₂ = ∞

[tex]v_c = \sqrt{\dfrac{2GM}{R}[/tex]

now indicates that the mass and radius of the planet changes slightly

[tex]M ’= M + \Delta M = M(1+\dfrac{\Delta M}{M})[/tex]  

[tex]R ’= R + \Delta R = R (1+\dfrac{\Delta R}{R} )[/tex]

we substitute

   [tex]vₐ = \sqrt{\dfrac{2GM}{R} }\dfrac{\sqrt{1+\dfrac{\Delta M}{M}}} {\sqrt{1+\dfrac{\Delta R}{R}}}[/tex]

let's use a serial expansion

√(1 ±x) = 1 ± ½ x +…

we substitute

      [tex]v_a=v_c(1+\dfrac{1}{2}\dfrac{\Delta M}{M})(1-\dfrac{1}{2}\dfrac\Delta R}{R})[/tex]

Hence the minimum escape speed, vc , for an object launched from the surface of the planet will be    [tex]v_a=v_c(1+\dfrac{1}{2}(\dfrac{\Delta M}{M}-\dfrac{\Delta R}{R})[/tex]

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Answer:

d. - 2.50 N

Explanation:

- 2.50 N is the net force that Marisa applied on the sled. Marisa applied force in order to stop the sled and requires less amount of force due to its lower mass. The value of force is negative because the force is applied in opposite direction of the sled's movement. The value of force is positive when it is applied in the direction of the object's motion so the value of force is - 2.50 N which is applied in opposite direction of the body's motion.

Answer:

O C. Its particles vibrate slightly.

Explanation:

At absolute zero, atoms would occupy the lowest energy state.They move much less than at higher temperatures, but they still have small vibrations at absolute zero.

Answer:

The answer is B its particles have no kinetic energy

Explanation:

trust the big brain

Answer:

Decreases

Explanation:

I think this is right tell me if it's wrong.

Answer:

Increases.

Explanation:

The density of the second medium increases, the angle of refraction also increases because of higher density of the medium. In more denser medium, there is more resistance for the light ray so it bends more as compared to less denser medium in which less bending of light ray occur. The angle of refraction increases when the density of medium is more than the previous medium so we can say that the angle of refraction increases due to increase in density of another medium.

Explanation:

It will be B.Its particles have no kinetic energy.

Answer:

one beta particle

Explanation:

Since the atomic number of 131_I_53 increases by one to 131_Xe_54, we have the release of a beta particle since only a beta particle can cause a change in atomic number without a change in mass number. Since a beta particle is one electron, ₋₁⁰e, our nuclear equation is

¹³¹I₅₃ → ¹³¹X₅₄ + ₋₁⁰e

The atomic and mass numbers on both sides are balanced

mass number 131 = 131 + 0 = 131

atomic number 53 = 54 - 1 = 53

Thus a beta particle is emitted

Answer:

Option C: Third Class

Explanation:

This is third class because the effort or the input force is in the middle between the fulcrum and the load.

To solve this, we must be knowing each and every concept related to lever.  Therefore,  due to the effort or input force being in the center between the edge as well as the load, the supplied lever is of 3rd class. The correct option is option C.

A lever is a basic device that consists of a beam or stiff rod located at a set tight, or edge. It is used to apply force to a load and often offers a mechanical advantage.

A stiff object that can rotate about a spot on itself is called a lever. The three types of levers are categorized according to where the edge, weight, and effort are located. Due to the effort or input force being in the center between the edge as well as the load, the supplied lever is of  3rd class.

Therefore,  the correct option is option C.

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Answer:

[tex]\boxed {\boxed {\sf D.\ 6.4\ m/s^2}}[/tex]

Explanation:

We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.

First, we can find the force of the first, 8 kilogram object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=m \times a[/tex]

The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.

Substitute these values into the formula.

[tex]F= 8 \ kg * 1.6 \ m/s^2[/tex]

Multiply.

[tex]F= 12.8 \ kg*m/s^2[/tex]

Now,  use the force we just calculated to complete the second part of the problem. We use the same formula:

[tex]F= m \times a[/tex]

This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.

Substitute the values into the formula.

[tex]12.8 \ kg*m/s^2= 2 \ kg *a[/tex]

Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.

[tex]\frac {12.8 \ kg*m/s^2}{2 \ kg}= \frac{2\ kg* a}{2 \ kg}[/tex]

[tex]\frac {12.8 \ kg*m/s^2}{2 \ kg}=a[/tex]

The units of kilograms cancel.

[tex]\frac {12.8}{2}\ m/s^2=a[/tex]

[tex]6.4 \ m/s^2=a[/tex]

The acceleration is 6.4 meters per square second.