Army needs to order a shade for a triangle-shaped window has a base of 6 feet and a height of 4 feet.what is the area of the shade

Answer:

4

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Answer:

35

Step-by-step explanation:

9Kg =63N

5Kg=X (Cross Multiple)

=X×9 =5×63

divide both sides by 9

X=5×63

---------

9

=35

Answer:

35 N

Step-by-step explanation:

let w = weight of object

and m = mass of object

w = mk   where k is the constant of proportion

63 = 9k

k = 7

So, w = 7m

w = 7(5) = 35 N

Answer:

13.9 ft

Step-by-step explanation:

Since the triangle is a right triangle we can use pythagoreom theorm.

16^2=8^2+a^2 (a is the unknown side)

256= 64+a^2

192= a^2

Square root both sides and you get around 13.9 ft

Answer:

0.8,0.91,1/10,3/100

0.6,0.9,0.21,0.35,7/10,11/100

0.2,0.5,1/10,0.44,8/100

Step-by-step explanation:

Answer:

0.8,0.91,1/10,3/100

0.6,0.9,0.21,0.35,7/10,11/100

0.2,0.5,1/10,0.44,8/100Step-by-step explanation: IVE DONE THIS BEFORE TOO

Answer:

The 16oz is a better deal

Step-by-step explanation:

32 = 2 * 16

buying 2 packages of 16 oz cost

0.79 * 2 = 1.58

1.58 < 2.09

The 16oz is a better deal

Answer:

The 16 oz package.

Step-by-step explanation:

Make the 16 oz a 32 oz so we can compare the prices

Mutiply 0.79 X 2 = 1.58

The 16 oz is because you can buy it twice making it a 32 oz for less than the orginal 32 oz.

(Compared side by side)

2.09 > 1.58

hope this helped!

Answer:

Step-by-step explanation:

Answer:

X= -8/3

Step-by-step explanation:

Answer:

Part A: [tex]12x+16\leq 580[/tex]

Part B: $47 per month

Step-by-step explanation:

Part A: 12 months in a year. Pays x amount of $ per year, with an additional $16 initiation fee. He wants to spend less than $580 total a year. Thus, [tex]12x+16\leq 580[/tex].

Part B: Solve the inequality for x.

$580 - $16 = $564

x = $564/12 = $47

Hope this helps! :)

Answer1/4  hope this help

Step-by-step explanation:

Answer:

The Monument is taller than the child by 174.125 meters

Step-by-step explanation:

The Monument in Santiago measures 175 meters. A child measures 87.5 centimeters.

Step 1

Convert child's height to meters

100cm = 1 m

87.5 cm = x

Cross Multiply

100cm × x = 87.5 cm × 1m

x = 87.5 cm × 1m/100cm

x = 0.875m

Step 2

How much is the Monument taller than the child?

This is calculated by subtracting Child's height from Monument height

= 175 m - 0.875m

= 174.125 m

Therefore, the Monument is taller than the child by 174.125 m

Answer:

arc BD = 100

Step-by-step explanation:

arc BD = arc CA because ∠AOC = ∠BOD (vertical angles)

arc BD = 100

Answer: 8,500

Step-by-step explanation:

Answer:

8250 mL

Step-by-step explanation:

Multiply the volume value by 1000

Answer:

Vajsjke

Step-by-step explanation:

ggzodxkdfdjhs

Answer: 2 5/12

Step-by-step explanation:

Trey bought 3¾ pounds of apples from the grocery store. Corinne bought 1⅓ pounds of grapes from the grocery store.

To know how many more pounds of fruit that Trey bought, we have to find the difference between the value given above and this will be:

= 3¾ - 1⅓

= 3 9/12 - 1 4/12

= 2 5/12

Trey bought 2 5/12 pounds more.

Answer:

6 crickets

Step-by-step explanation:

First day:  20% of 10 is (.20)(10) = 2, so there were 10 - 2 = 8 crickets left.

Second day: 25% of 8 is (.25)(8) = 2, so there were 8 - 2 = 6 crickets left.

Answer:

10

Step-by-step explanation:

Answer:

6.00

Step-by-step explanation:

Take a better pic and i will explain in comment

Answer:

here is ur answer.....

hope it helped u and ur gf......

Answer:

There should be a rule

Step-by-step explanation:

Replace the x values from the question with the rule given and you will get your answer

Answer:

The angle of elevation from the ground to the plane is 11.5 degrees

Step-by-step explanation:

Given -

Horizontal distance from the point of takeoff to which the plane flies in a straight line = 4000 feet

The vertical distance travelled from the ground to the plane is 800 feet

Angle of Elevation

[tex]Sin X= \frac{800}{4000} \\X = Sin^{-1}\frac{800}{4000}\\X = 11.5[/tex]

The angle of elevation from the ground to the plane is 11.5 degrees

Answer:

1

Step-by-step explanation:

For any triangle, you only need to know 3 pieces of information out of the 6 angles and sides to solve for the rest of the triangle.

Answer:

Rational

Step-by-step explanation:

Rational. It can be expressed as a fraction, which is the definition of a rational number.

Hope this Helps!

-2 is rational

This is because every negative integer is a negative rational number.

We know that -1 = -1/1, -2 = -2/1, -3 = -3/1, -4 = -4/1 and so on …….

In other words, any negative integer n can be written as n = n/1, here n is negative and 1 is positive.

So, negative 2 is rational.

Answer:

an=yearn−year−0.17n+0.34

Step-by-step explanation:

Answer:

68%

Step-by-step explanation:

17% × 4

68%

Answer:

15.87%

Step-by-step explanation:

We start with getting the z score

Mathematically , we have this as;

z-score = (x-mean)/SD

where x = 114

z-score = (114-100)/14 = 14/14 = 1

So we want to calculate the probability values that are greater than 1

We can use the standard normal distribution table

so we have P(z> 1) = 0.15866

in percentage, we multiply by 100 and that gives 15.866 which is 15.87 people

Answer:

at least a score of 68

Step-by-step explanation:

(85+73+94+q)/4 ≥ 80

(252 + q)/4 ≥ 80

multiply each side by 4 to get:

252 + q ≥ 320

q ≥ 68

Answer:

88 units

Step-by-step explanation:

[tex] In\: \triangle OBR \:\&\: \triangle OWN[/tex]

BR || WN (Given)

Therefore,

[tex] \angle OBR \cong \angle OWN[/tex] (Alternate angles)

[tex] \angle BOR \cong \angle WON[/tex] (Vertical angles)

[tex] \therefore \triangle OBR \sim \triangle OWN[/tex] (AA postulate)

[tex] \therefore \frac{OR}{ON} =\frac{BR}{WN} [/tex] (csst)

[tex] \therefore \frac{OR}{56} =\frac{24}{42} [/tex]

[tex] \therefore \frac{OR}{56} =\frac{4}{7} [/tex]

[tex] \therefore OR =\frac{4\times 56}{7} [/tex]

[tex] \therefore OR ={4\times 8} [/tex]

[tex] \therefore OR =32 [/tex]

RN = OR + ON

RN = 32 + 56

RN = 88 units

Answer:

Hello! I know I am late but here is the answer for anyone else who might need it.

D. 1/2-i√3/2

Step-by-step explanation:

I got it right on edge. Hope this helps!

The value of given expression is [tex]\frac{1}{2}-\frac{\sqrt{3} i}{2}[/tex].

What is binomial theorem?

The expression of the form (a+b)^n is expand by binomial theorem.

The expansion is [tex](a+b)^{n}=\sum_{r=0}^{n}{ }^{n} C_{r} a^{n-r} b^{r}[/tex].

Use a=1/2 and b=[tex]b=\frac{i\sqrt{3} }{2}[/tex] into the expansion of binomial.

[tex]\left(\frac{1}{2}+\frac{\sqrt{3} i}{2}\right)^{5}=\sum_{k=0}^{5}\left(\begin{array}{l}5 \\k\end{array}\right)\left(\frac{1}{2}\right)^{5-k}\left(\frac{\sqrt{3} i}{2}\right)^{k}[/tex]

When k=0 then, [tex]\left(\begin{array}{l}5 \\0\end{array}\right)\left(\frac{1}{2}\right)^{5-0}\left(\frac{\sqrt{3} i}{2}\right)^{0}=\frac{5 !}{(5-0) ! 0 !}\left(\frac{1}{2}\right)^{5-0}\left(\frac{\sqrt{3} i}{2}\right)^{0}=\frac{1}{32}[/tex]

When k=1 then, [tex]\left(\begin{array}{l}5 \\1\end{array}\right)\left(\frac{1}{2}\right)^{5-1}\left(\frac{\sqrt{3} i}{2}\right)^{1}=\frac{5 !}{(5-1) ! 1 !}\left(\frac{1}{2}\right)^{5-1}\left(\frac{\sqrt{3} i}{2}\right)^{1}=\frac{5 \sqrt{3} i}{32}[/tex]

When k=2 then, [tex]\left(\begin{array}{l}5 \\2\end{array}\right)\left(\frac{1}{2}\right)^{5-2}\left(\frac{\sqrt{3} i}{2}\right)^{2}=\frac{5 !}{(5-2) ! 2 !}\left(\frac{1}{2}\right)^{5-2}\left(\frac{\sqrt{3} i}{2}\right)^{2}=-\frac{15}{16}[/tex]

When k=3 then, [tex]\left(\begin{array}{l}5 \\3\end{array}\right)\left(\frac{1}{2}\right)^{5-3}\left(\frac{\sqrt{3} i}{2}\right)^{3}=\frac{5 !}{(5-3) ! 3 !}\left(\frac{1}{2}\right)^{5-3}\left(\frac{\sqrt{3} i}{2}\right)^{3}=-\frac{15 \sqrt{3} i}{16}[/tex]

When k=4 then, [tex]\left(\begin{array}{l}5 \\4\end{array}\right)\left(\frac{1}{2}\right)^{5-4}\left(\frac{\sqrt{3} i}{2}\right)^{4}=\frac{5 !}{(5-4) ! 4 !}\left(\frac{1}{2}\right)^{5-4}\left(\frac{\sqrt{3} i}{2}\right)^{4}=\frac{45}{32}[/tex]

When k=5 then, [tex]\left(\begin{array}{l}5 \\5\end{array}\right)\left(\frac{1}{2}\right)^{5-5}\left(\frac{\sqrt{3} i}{2}\right)^{5}=\frac{5 !}{(5-5) ! 5 !}\left(\frac{1}{2}\right)^{5-5}\left(\frac{\sqrt{3} i}{2}\right)^{5}=\frac{9 \sqrt{3} i}{32}[/tex],

Now we will add all the results to get the expansion of given expression,

[tex]\left(\frac{1}{2}+\frac{\sqrt{3} i}{2}\right)^{5}=\frac{1}{32}+\frac{5 \sqrt{3} i}{32}-\frac{15}{16}-\frac{15 \sqrt{3} i}{16}+\frac{45}{32}+\frac{9 \sqrt{3} i}{32}[/tex]

On simplifying,

[tex]\left(\frac{1}{2}+\frac{\sqrt{3} i}{2}\right)^{5}=\frac{1}{2}-\frac{\sqrt{3} i}{2}[/tex]

Therefore, the value of given expression is [tex]\frac{1}{2}-\frac{\sqrt{3} i}{2}[/tex].

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