Arnold has 4 pitchers. Each pitcher holds [tex]\frac{7}{8}[/tex] gallon of juice. Which equation can Arnold use to determine the number of gallons of juice in the pitchers?

Answer:

It is better to have a variety of plants because if the species of plants die out, the whole ecosystem becomes extinct.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Isolate by the x from one side of the equation.

First, you have to switch sides.

[tex]\sf{2+x\geq 26}[/tex]

Then, subtract by the 2 from both sides.

[tex]\sf{2+x-2\geq 26-2}[/tex]

Solve.

Subtract.

[tex]26-2=24[/tex]

[tex]\large\boxed{x\geq 24}[/tex]

The answer should be false.

Answer: 6r^3 - 15r

Step-by-step explanation:

(3r) (2r^2 - 5)

Distribute.

6r^3 - 15r

Hope this helped.

Answer:

14

Step-by-step explanation:

Answer:

14 flashes.

Step-by-step explanation:

1 minute = 60 seconds

x minutes = 45 seconds.

1/x = 60/45                           Cross multiply

60x = 45                               Divide by 60

x = 45/60

x = .75

10 1/2 minutes = 10.5 minutes.

x flashes / 10.5 minutes = 1 flash / 0.75 minutes   Multiply by 10.5

x = 10.5/0.75

x = 14

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Answer:

  False

Step-by-step explanation:

The terms of a geometric series would have a common ratio. The terms of this series do not. (The differences increase by 1 each time, so it is a quadratic series.)

False, the series is not geometric.

Answer:

We are given with the series

6 + 8 + 11 + 15 + 20 + 26

Since

the series is increasing by +1. So, it will be not a geometric series

[tex] \\ [/tex]

Answer: I thihnk it's 1x10^-2

Step-by-step explanation: This equals 0.1, and 6^-2 is equal to 0.1....the rest of the answers are either too big or too small

Answer:

-3/4

Step-by-step explanation:

In slope-intercept form, the slope is the coefficient of x.

Answer:

x<-4

Step-by-step explanation:

x+9<5

-9 -9

x<-4

1. subtract the 9 on both sides to have x alone

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Answer:

  -4

Step-by-step explanation:

The dot product is the sum of products of corresponding coefficients.

  u·v = (4)(-1) +(0)(2) = -4

  u·v = -4

Answer:

Package 3

Step-by-step explanation:

Package 1,

No. of plates = 5

Cost = $38.75

Cost of 1 plate = [tex]\dfrac{38.75}{5}=\$7.75[/tex]

Package 2,

No. of plates = 8

Cost = $58

Cost of 1 plate = [tex]\dfrac{58}{8}=\$7.25[/tex]

Package 3,

No. of plates = 14

Cost = $94.5

Cost of 1 plate = [tex]\dfrac{94.5}{14}=\$6.75[/tex]

The cost of 1 plate in package 3 is the least. It means she should buy package 3.

Answer:

11/8 and 21/16

Step-by-step explanation:

3 x 1 = 3

4 x 2= 8

3/8+3/4(convert to eighth's)

3/8+6/8=11/8

1 1/8 = 9/8

9 x 1 = 9

8 x 2 = 16

9/16+3/4(convert to sixteenth's)

9/16+12/16

21/16

---

hope it helps

=3/4 × 1/2 + 3/4

=3/8 + 3/4

=9/8

2nd questions ans

=1×1/2 + 3/4

=1/2 + 3/4

=5/4

Answer:

1. the team of Liverpool FC has the shortest player because the minimum is 64.

2. ny Knicks has the tallest player with a height of 84.

3. the NY Knicks box has the largest IQR because 82 - 74 = 8.

MS. A is wrong bc the 75% of players are taller than 74 inches.

Step-by-step explanation:

Fun Fact that has nothing to do with this:

The Beatles meet in Liverpool.

Answer:

The smaller box, 12 oz, costs less per oz than the larger 20 oz box.

Step-by-step explanation:

$4.59 divided by 20 = $0.2295 per oz

$2.52 divided by 12 = $0.21 per oz

Answer:

[tex]y = 75[/tex]

Step-by-step explanation:

Given

[tex]y\ \alpha\ \ x[/tex]

[tex]y=24; x =16[/tex]

Required

Find y when [tex]x = 50[/tex]

We have:

[tex]y\ \alpha\ \ x[/tex]

Express as equation

[tex]y = kx[/tex]

Solve for k

[tex]k = \frac{y}{x}[/tex]

When [tex]y=24; x =16[/tex]

[tex]k = \frac{24}{16}[/tex]

[tex]k = \frac{3}{2}[/tex]

When [tex]x = 50[/tex], we have:

[tex]y = kx[/tex]

[tex]y = \frac{3}{2} * 50[/tex]

[tex]y = 75[/tex]

Answer:

[tex]\displaystyle 2[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2} \hookrightarrow \frac{\frac{2}{3}\pi}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow \frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{6}}{\frac{\pi}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{6} \hookrightarrow \frac{2}{\frac{\pi}{3}}\pi \\ Amplitude \hookrightarrow 2[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2cos\:\frac{\pi}{3}x + \frac{1}{2},[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will horisontally shift and map the graph onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle 2\:units[/tex]to the left, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph FORWARD [tex]\displaystyle 2\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{2} = \frac{\frac{2}{3}\pi}{\frac{\pi}{3}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -2cos\:(\frac{\pi}{3}x - \frac{2}{3}\pi) + \frac{1}{2}.[/tex]Intermediate, we have two sine graphs to deal with [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -2sin\:\frac{\pi}{3}x + \frac{1}{2}.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle \frac{1}{2}\:unit[/tex]to the left, which means that in order to match the leftward sine graph, we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{2}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you get [tex]\displaystyle \boxed{\frac{1}{2}} = \frac{\frac{\pi}{6}}{\frac{\pi}{3}}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -2sin\:(\frac{\pi}{3}x - \frac{\pi}{6}) + \frac{1}{2}.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit [tex]\displaystyle [-2\frac{1}{2}, \frac{1}{2}],[/tex]from there to [tex]\displaystyle [3\frac{1}{2}, \frac{1}{2}],[/tex]they are obviously [tex]\displaystyle 6\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 6.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = \frac{1}{2},[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

Step-by-step explanation:

180 = x + 135 + x + 65

-20 = 2x

-10 = x

x = -10

GF = 55°

Answer:

D. 0.62

Step-by-step explanation:

I calculated it logically

what about using 20-30-40-5

Step-by-step explanation:

the sequence is that you are skipping ten to get the second nb which is 30 and keep on going on to get 50

Answer:

20x^2 +19xy+3y^2

Step-by-step explanation:

See Image below :)

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Answer:

  20x² +19xy +3y²

Step-by-step explanation:

Use the distributive property.

  (4x +3y)(5x +y)

  = 4x(5x +y) +3y(5x +y)

  = 20x² +4xy +15xy +3y²

Collect terms.

  = 20x² +19xy +3y²

Answer:

32768

Step-by-step explanation:

Each question has 2 options.

On a true/false test with one question, there are 2¹, or 2 possible answers

On a test with 2 questions, there are 2², or 4 possible answers.

On a test with 3 questions, there are 2³, or 8 possible answers.

So, 2¹⁵ = 32768 possible ways.

Answer:

$8518.40

Step-by-step explanation:

FV = PV(1+r)^n

FV = future value

PV = present value

r = rate

n = # of years

Value in 2 yrs = 11,000 x (1 - 0.12)^2 = 8518.4

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Answer:

Step-by-step explanation:

The measure of an arc of a circle is the same as the measure of the central angle it subtends. That is, arc RS has the same measure as central angle RPS, which is marked as 100°.

Of course, the total of all central angles, hence all arcs, of a circle is 360°. A diameter of a circle cuts the circle in half, so each semicircle has a central angle measure and arc measure of 180°.

Any arc that is more than a semicircle is called a "major" arc. If it is less than a semicircle, it is a "minor" arc. Arcs RS and ST are minor arcs.

As always in geometry, the whole is the sum of the parts, so arcs RS and ST are supplementary. They total the measure of semicircle RST, which is 180°. Then ST = 180° -RS = 180° -100° = 80°.

__

Additional comment

Usually, an arc identified only by its end points is a minor arc. If the major arc is intended, then it will either be described as "major arc RS" or a point on the major arc will be given, as "arc RTS". The measure of arc RTS is 280°.

Given:

The graph of a line a.

To find:

The slope of the line a.

Solution:

Slope formula:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

From the given graph it is clear that the line a passes through the points (-1,1) and (0,-2). So, the slope of the line a is:

[tex]m=\dfrac{-2-1}{0-(-1)}[/tex]

[tex]m=\dfrac{-3}{1}[/tex]

[tex]m=-3[/tex]

The slope of the line a is -3. Therefore, the correct option is C.

Answer:

here,

38+X=180 (being straight line)

or,X=180-38

therefore, X=142 ans,,,

Answer: Possibly -4

Step-by-step explanation:

But wait for others to check I’m not fully sure

Answer:

HL theorem

Step-by-step explanation:

since NP⊥OM, so, L H is a right angle.

and NM = OP as hypotenuse

HL theorem

NP is perpendicular to OM

NM =OP given

So the triangles are congruent