The lower and upper control limits that the manufacturer should use in the resulting control chart are LCL = 0.023,UCL = 0.043
To calculate the lower and upper control limits for the control chart, we need to use the following formula:
Lower control limit (LCL) = average proportion of defects - 3 x square root of [(average proportion of defects x (1 - average proportion of defects)) / sample size]
Upper control limit (UCL) = average proportion of defects + 3 x square root of [(average proportion of defects x (1 - average proportion of defects)) / sample size]
Using the given information, we can plug in the values to get:
LCL = 0.01 - 3 x square root of [(0.01 x 0.99) / 30] = -0.023
UCL = 0.01 + 3 x square root of [(0.01 x 0.99) / 30] = 0.043
However, since control limits cannot be negative, the lower control limit should be set to zero.
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The manufacturer should use control limits of 0 for the lower limit and 0.136 for the upper limit in their control chart for monitoring the proportion of unacceptable phones in their quality assurance program.
Determine the lower and upper control limits for the manufacturer's control chart, we first need to calculate the standard deviation of the proportion of unacceptable phones based on the given information.
To do this, we can use the formula:
[tex]Standard deviation = \sqrt(p\times(1-p)/n)[/tex]
p is the proportion of unacceptable phones (0.01), and n is the sample size (30 phones per day for 7 days = 210 total phones).
Plugging in these values, we get:
[tex]Standard deviation = \sqrt(0.01\times(1-0.01)/210) = 0.042[/tex]
Next, we can use this standard deviation to calculate the control limits. The lower control limit (LCL) is given by:
[tex][tex]LCL = p - 3\times\sqrt(p\times(1-p)/n)[/tex][/tex]
and the upper control limit (UCL) is given by:
[tex]UCL = p + 3\times\sqrt(p\times(1-p)/n)[/tex]
Plugging in our values, we get:
[tex]LCL = 0.01 - 3\times0.042 = -0.075[/tex]
[tex]UCL = 0.01 + 3\times0.042 = 0.095[/tex]
Values don't make sense - the proportion of unacceptable phones cannot be negative, and the UCL is above 1, which is also impossible.
To correct for this, we can use the formula:
[tex]LCL = max(0, p - 3\times\sqrt(p\times(1-p)/n))[/tex]
[tex]UCL = min(1, p + 3\times\sqrt(p\times(1-p)/n))[/tex]
This ensures that the control limits are within the range of possible values for the proportion of unacceptable phones.
Plugging in our values with this formula, we get:
[tex]LCL = max(0, 0.01 - 3\times0.042) = 0[/tex]
[tex]UCL = min(1, 0.01 + 3\times0.042) = 0.136[/tex]
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2. Which sequence of transformations takes the graph of y = k(x) to the graph of
y=-k(x + 1)?
A. Translate 1 to the right, reflect over the x-axis, then scale vertically by a factor of 1/2
B. Translate 1 to the left, scale vertically by 1/2 , then reflect over the y-axis.
C. Translate left by 1/2, then translate up 1.
D. Scale vertically by 1/2, reflect over the x-axis, then translate up 1.
The correct answer is option B. Translate 1 to the left, scale vertically by 1/2, then reflect over the y-axis.
What does term "transformation of a graph" means?The process of modifying the shape, location, or features of a graph is often referred to as graph transformation. Graphs are visual representations of mathematical functions or data point connections, often represented on a coordinate plane.
Translations, reflections, rotations, dilations, and other changes to the look of a graph are examples of graph transformations.
For the given problem, Transformation to get the desired result can be carried out as:
Translate '1' to the left: The transformation "x + 1" in "-k(x + 1)" shifts the graph horizontally to the left by 1 unit.Scale vertically by '1/2' : The 1/2 factor in "-k(x + 1)" vertically scales the graph, compressing it vertically.Reflect over the y-axis: The minus sign before "k" in "-k(x + 1)" reflects the graph over the y-axis, flipping it horizontally.Hence, to convert the graph of "y = k(x)" to the graph of "y = -k(x + 1)," the correct sequence of transformations is to translate 1 unit to the left, scale vertically by 1/2, and then reflect across the y-axis, which is option B.
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a random sample of n equal to 64 scores is selected from a normally distributed population with mu equal to 77 and sigma equal to 21. what is the probability that the sample mean will be less than 79? hint: this is a z-score for a sample.
The probability of the sample mean being less than 79 is 77.64%
In order to solve the given problem we have to take the help of Standard error mean
SEM = ∑/√(n)
here,
∑ = population standard deviation
n = sample size
hence, the z-score can be calculated as
z = ( x' - μ)/σ/√(n)
here,
x' = sample mean
μ = population mean
σ = population standard deviation
n = sample size
adding the values into the formula
SEM = σ / √(n)
= 21/√64
= 2.625
z = (x' - μ)/SEM
= (79-77)/2.625
= 0.76
now, using standard distribution table we find that probability of a z-score is less than 0.77 then converting it into percentage
0.77 x 100
= 77%
The probability of the sample mean being less than 79 is 77.64%
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A bottle of water that is 80°F is placed in a cooler full of ice. The temperature of the water decreases by 0. 5°F every minute. What is the temperature of the water, in degrees Fahrenheit, after 5 1/2
minutes? Express your answer as a decimal
After 5 and a half minutes, the temperature of the water will be 77°F.
In this scenario, we are given that the initial temperature of the water is 80°F. We also know that the temperature of the water decreases by 0.5°F every minute. We want to find out what the temperature of the water will be after 5 and a half minutes.
To solve this problem, we need to use a bit of math. We know that the temperature of the water is decreasing by 0.5°F every minute. So after 1 minute, the temperature of the water will be 80°F - 0.5°F = 79.5°F. After 2 minutes, the temperature will be 79.5°F - 0.5°F = 79°F. We can continue this pattern to find the temperature after 5 and a half minutes.
After 5 minutes, the temperature of the water will be 80°F - (0.5°F x 5) = 77.5°F. And after another half minute (or 0.5 minutes), the temperature will decrease by another 0.5°F, so the temperature will be 77.5°F - 0.5°F = 77°F.
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dora drove east at a constant rate of 75 kph. one hour later, tim started driving on the same road at a constant rate of 90 kph. for how long was tim driving, before he caught up to dora? a. 5 hours b. 4 hours c. 3 hours d. 2 hours
Tim was driving for 5 hours before he caught up to Dora.
The answer is (a) 5 hours.
To solve this problem, we can use the formula:
distance = rate × time
Let's denote the time Tim drove as t hours.
Since Dora started driving one hour earlier, her driving time would be (t + 1) hours.
Dora's distance: 75 kph × (t + 1)
Tim's distance: 90 kph × t
Since Tim catches up to Dora, their distances will be equal:
75(t + 1) = 90t
Now we can solve for t:
75t + 75 = 90t
75 = 15t
t = 5.
The answer is (a) 5 hours.
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sally works in hr at a company with 20 full-time employees in one location. what employee census data should sally gather to prepare for a benefits bid? race, gender, and ethnicityage, marital status, and number of childrendisability and veteran statustenure and education levels
To prepare for a benefits bid, Sally should census gather data on the age, marital status, and number of children of the 20 full-time employees.
This information will help Sally determine what types of benefits would be most appealing to the employees and what types of benefits might be necessary to attract and retain talent.
Additionally, Sally should gather data on the tenure and education levels of the employees to help her understand what types of benefits might be necessary to incentivize employees to stay with the company long-term and to attract highly educated candidates.
Finally, Sally should consider gathering data on disability and veteran status to ensure that the company is providing adequate support for those employees who may require additional assistance.
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9) Given f-¹(x)=-3x+2, write an equation
that represents f(x).
as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solving for "y", let's do so for this inverse, since finding the inverse of the inverse, will give us the original function :)
[tex]f^{-1}(x)=-3x+2\implies y~~ = ~~-3x+2\hspace{5em}\stackrel{\textit{quick switcheroo}}{x~~ = ~~-3y+2} \\\\\\ x-2=-3y\implies \cfrac{x-2}{-3}=y\implies \cfrac{2-x}{3}=y=f(x)[/tex]
an imaginary circle that goes through both retinae and the fixation point is known as
The Vieth-Müller Circle is an imaginary circle that passes between both retinae and the fixation point.
The Vieth-Müller Circle is an ophthalmology concept that depicts an imaginary circle that passes across the foveas (the primary points of the retinae that are responsible for acute, detailed vision) and the fixation point (the point at which the eyes are directed).
The Vieth-Müller Circle is significant because it helps to explain the phenomenon of binocular vision, which is the ability to perceive depth and three-dimensional space using both eyes together. The circle aids in the definition of the equivalent locations on the two retinae, which are sites that receive visual field information and are critical in combining the images from the two eyes into a single, three-dimensional perception.
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The imaginary circle that passes through both retinae and the fixation point is called the horopter. The horopter is important in visual perception as it represents the set of points in space that stimulate corresponding points on each retina, which is necessary for binocular vision and depth perception.
The Horopter is an imaginary circle that passes through both retinae and the fixation point. In this context:
1. "Imaginary" refers to the fact that the Horopter is a theoretical concept rather than a physical object.
2. "Retinae" are the light-sensitive layers at the back of both eyes, which play a crucial role in processing visual information.
3. "Fixation" is the point where both eyes are focused on a single object in the visual field.
In brief, the Horopter represents a collection of points in the 3D space that are perceived as having the same depth or distance as the fixation point. It helps in understanding binocular vision and depth perception, as points on the Horopter contribute to forming a single, fused image from both eyes.
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A container built for transatlantic shipping is constructed in the shape of a right
rectangular prism. Its dimensions are 4 ft by 9.5 ft by 13 ft. If the container is entirely
full and, on average, its contents weigh 0.05 pounds per cubic foot, find the total
weight of the contents. Round your answer to the nearest pound if necessary
Thus, the on average the contents weight for the transatlantic shipping is found as 24.7 pounds.
Explain about the rectangular prism:a solid, three-dimensional object with six rectangular faces.It is a prism due to its uniform cross-section along its whole length.Volume is a unit of measurement for the amount of 3-dimensional space a thing occupies. Cubic units are used to measure volume.Given dimension of rectangular prism
Length l = 4ft
width w = 9.5 ft
height h = 13 ft
Volume of rectangular prism = l*w*h
V = 4*9.5*13
V = 494 ft³
Now,
1 ft³ = 0.05 pounds
So,
weight of 494 ft³ = 494*0.05 pounds
weight of 494 ft³ = 24.7 pounds
Thus, the on average the contents weigh for the transatlantic shipping is found as 24.7 pounds.
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You roll a six sided die 30 times. A 5 is rolled 8 times. What is the theoretical probability of rolling a 5? What is the experimental probability of rolling a 5?
The theoretical and experimental probability of rolling a 5 are 1/6 and 4/15 respectively.
How do we derive the probability?We will calculate the theoretical probability by substituting 30 for the number of favorable outcomes as the die is rolled 30 times with one option each for 30 rolls and 180 for total number of outcomes in theoretical probability formula.
P(Theoretical probability of rolling a 5) = 30/180
P(Theoretical probability of rolling a 5) = 1/6.
The experimental probability is calculated by substituting 8 for the number of time the event occurs and 30 for the total number of trials.
P(Experimental probability of rolling a 5)= 8/30
P(Experimental probability of rolling a 5) =4/15
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the applet is selecting random samples from the town's population this year. what do we assume is true about this population of babies?
When the applet selects random samples from the town's population of babies, we assume that the population is large enough and diverse enough to accurately represent the characteristics and traits of the entire population.
We assume that the selection of the random samples is unbiased and that every member of the population has an equal chance of being selected for the sample.
Based on your question, we are discussing random samples taken from a town's population of babies this year. When selecting random samples from this population, we assume the following:
1. The population of babies is well-defined and includes all babies born in the town within the specified year.
2. The random samples are representative of the entire population, meaning that each baby has an equal chance of being selected in the sample.
3. The samples are independent, meaning that the selection of one baby does not influence the selection of another.
These assumptions ensure that the results obtained from the random samples can be generalized to the entire population of babies in the town for this year.
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By assuming these conditions are met, we can perform statistical analyses on the random samples and make valid inferences about the entire population of babies in the town.
When an applet is selecting random samples from a town's population of babies this year, we typically assume the following about the population:
Independence:
Each baby selected in the sample is independent of the others, meaning that the outcome of one selection does not affect the outcome of another selection.
Randomness:
The applet chooses babies from the population in a random manner, ensuring that every baby has an equal chance of being selected.
Representativeness:
The random samples selected are representative of the entire population, meaning that the samples accurately reflect the characteristics of the town's population of babies as a whole.
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true or false: a linear programming problem can have an optimal solution that is not a corner point. select one: true false
It is true that a linear programming problem can have an optimal solution that is not a corner point.
How given statement is true? Explain further?In linear programming, the optimal solution represents the point where the objective function is optimized while still satisfying all the constraints.
In some cases, the optimal solution may occur at a corner point of the feasible region, where two or more of the constraints intersect.
However, it is possible for the optimal solution to occur at a point that is not a corner point, but rather lies on an edge or a line segment of the feasible region.
This can occur when the objective function is parallel to one of the constraint lines or when there are redundant constraints that limit the feasible region.
Therefore, it is true that a linear programming problem can have an optimal solution that is not a corner point.
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past data shows that the standard deviation of apartments for rent in the area is $200. suppose we want a 98% confidence interval with margin of error of 50. what sample size do we need?
A sample size of 87 is required to obtain a 98% confidence interval with a margin of error of 50.
How to calculate sample size?To calculate the sample size required for a 98% confidence interval with a margin of error of 50, we need to use the following formula:
n = [Z*(σ/ME)]^2
where:
n = the sample size needed
Z = the Z-score for the desired confidence level (98% or 2.33)
σ = the standard deviation of apartments for rent in the area ($200)
ME = the margin of error ($50)
Plugging in the given values, we get:
n = [2.33*(200/50)]^2
n = [9.32]^2
n ≈ 86.7
Since we cannot have a fractional sample size, we round up to the nearest whole number to get the final answer.
Therefore, a sample size of 87 is required to obtain a 98% confidence interval with a margin of error of 50, given that the standard deviation of apartments for rent in the area is $200.
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19.
Solve the problem.
2
Find the critical value XR corresponding to a sample size of 5 and a confidence
level of 98%.
(1 point)
O11.143
00.297
13.277
00.484
The critical value of the chi-square distribution corresponding to a sample size of 5 and a confidence level of 98% is given as follows:
0.297 and 13.277.
How to obtain the critical value?To obtain a critical value, we need three parameters, given as follows:
Distribution.Significance level.Degrees of freedom.Then, with the parameters, the critical value is found using a calculator.
The parameters for this problem are given as follows:
Chi-square distribution.1 - 0.98 = 0.02 significance level.5 - 1 = 4 degrees of freedom.Using a chi-square distribution calculator, the critical values are given as follows:
0.297 and 13.277.
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Please answer the question in the pdf. I just need the values for A, B, and C. I am offering 15 points. Thanks.
Recall the equation provided in the pdf:
(125x ^ 3 * y ^ - 12) ^ (- 2/3) = (y ^ [A])/([B] * x ^ [c])
find A B and C.
The answer will be:
A = 8/3B = 3/4C = 8/3Checkout the calculation of the exponentialWe can solve this problem using the rules of exponents and algebraic manipulation.
Starting with the left-hand side of the equation:
(125x^3 * y^-12)^(-2/3)
Using the rule that (a * b)^c = a^c * b^c, we can rewrite the expression as:
125^(-2/3) * x^(-2) * y^(8)
Simplifying further, we can use the fact that a^(-n) = 1/(a^n) to get:
1/(5^2 * x^2 * y^8/3)
Now, we can see that the denominator on the right-hand side of the equation must be 5^2 * x^2 * y^8/3. To find the numerator, we need to simplify the expression y^A. Comparing exponents, we see that:
y^A = y^(8/3)
Therefore, we need to find a value of A such that A = 8/3. Solving for A, we get:
A = 8/3
Now, we can write the equation as:
y^(8/3)/(5^2 * x^2 * y^8/3) = y^(8/3)/(25 * x^2 * y^(8/3))
Comparing exponents again, we see that we need to find values of B and C such that:
B * C = 2
and
-8/3 = -C
Solving for C, we get:
C = 8/3
Substituting this value of C into the first equation, we get:
B * 8/3 = 2
Solving for B, we get:
B = 3/4
Therefore, the solution is:
A = 8/3
B = 3/4
C = 8/3
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Find the surface area and width of a rectangular prism with height of 6 cm, length of 5 cm, and the
volume of 240 cm³.
Answer:
236 cm^2 and 8 cm
Step-by-step explanation:
width=w
240=6(5)(w)
w=8 cm
area=2[(6)(5)+(6)(8)+(5)(8)]
area=236 cm^2
PLEASE HELP DUE TODAY
Answer:
y=-1/12x+61/12
Step-by-step explanation:
y=-1/12x+61/12
Write the functions in standard form:
h(x)=2(x-3)²-9
h(x)=
p(x) = -5(x + 2)² + 15
p(x)=
Answer:
[tex]h(x)=2x^2-12x+9[/tex], [tex]p(x)=-5x^2-20x-5[/tex]
Step-by-step explanation:
To get to the standard form of a quadratic equation, we need to expand and simplify. Recall that standard form is written like so:
[tex]ax^2+bx+c[/tex]
Where a, b, and c are constants.
Let's expand and simplify h(x).
[tex]2(x-3)^2-9=\\2(x^2+9-6x)-9=\\2x^2+18-12x-9=\\2x^2+9-12x=\\2x^2-12x+9[/tex]
Thus, [tex]h(x)=2x^2-12x+9[/tex]
Let's do the same for p(x).
[tex]-5(x+2)^2+15=\\-5(x^2+4+4x)+15=\\-5x^2-20-20x+15=\\-5x^2-5-20x=\\-5x^2-20x-5[/tex]
Thus, [tex]p(x)=-5x^2-20x-5[/tex]
help me please like right now as soon as possible write the answer in terms of pi and round the answer to the nearest hundredths place I will give branliest
Thus, the total surface area of cylinder is found to be 480π sq. cm.
Explain about the surface area of cylinder:A cylinder's surface area is made up of its two congruent, parallel circular sides added together with its curved surface area. You must determine the Base Area (B) and Curved Surface Area in order to determine the surface area of a cylinder (CSA).
As a result, the base area multiplied by two and the area of a curved surface add up to the surface area or total surface of a cylinder.
Given data:
radius r = 8 cm
Height h = 22 cm
Total surface area of cylinder = 2*area of circle + area of curved cylinder
TSA = 2πr² + 2πrh
TSA = 2π(8)² + 2π(8)(22)
TSA = 2π(64) + 2π(176)
TSA = 128π + 352π
TSA = 480π sq. cm.
Thus, the total surface area of cylinder is found to be 480π sq. cm.
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Complete question-
Find the surface area of the cylinder with radius of 8 cm and height of 22 cm. write the answer in terms of pi and round the answer to the nearest hundredths place.
Given this snippet of code, what is the value of x after executing the last statement? int x = 10, *y; y = &x; y = y + 1; *y = 100;
The value of x after executing the last statement is still 10.
After executing the last statement, the value of x is still 10. The snippet of code declares an integer variable x and a pointer variable y that points to the address of x. Then, y is incremented by 1 (which means it now points to the next memory location after x). Finally, the value 100 is assigned to the memory location pointed to by y, which is actually beyond the memory allocated for variable x. This can lead to unexpected behavior, but since the value of x is never modified directly, its value remains unchanged at 10.
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A spinner with repeated colors numbered from 1 to 8 is shown. Sections 1 and 8 are purple. Sections 2 and 3 are yellow. Sections 4, 5, and 6 are blue. Section 7 is red. Spinner divided evenly into eight sections with three colored blue, one red, two purple, and two yellow. Determine the theoretical probability of the spinner not landing on red, P. 0.125 0.250 0.675 0.875
The theoretical probability of the spinner not landing on red is 0.875.
How to determine the theoretical probability of the spinner not landing on redThe total number of sections on the spinner is 8, out of which only one section is red. Therefore, the probability of the spinner landing on red is:
P(Red) = 1/8
The probability of the spinner not landing on red would be the probability of landing on any other section, which is:
P(Not Red) = 1 - P(Red) = 1 - 1/8 = 7/8
Therefore, the theoretical probability of the spinner not landing on red is 7/8 or 0.875 in decimal form.
So, the correct answer is: 0.875.
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Answer:
D
Step-by-step explanation:
The Olympic record for the men's 50-meter freestyle is 21.91 seconds. Express this speed in meters per second
Answer:
50 meters/21.91 seconds = 2.282 m/sec
During a flood, there were 6000 acres of land under water. After 2 days, only 3375 acres of land were under water. Assume that the water receded at an exponential rate. Write a function to model this situation that has a B-value of 1.
where t is measured in days, and A(t) represents the amount of flooded land at time t. This function has a B-value of -0.3118.
To model the situation of the flood, we can use an exponential decay function, which represents the decreasing amount of flooded land over time. The function can be written as:
[tex]A(t) = A0 * e^{(-kt)}[/tex]
where A(t) is the amount of flooded land at time t, A0 is the initial amount of flooded land, k is a constant representing the rate of decay, and e is the mathematical constant approximately equal to 2.718.
To determine the value of k, we can use the given information that after 2 days, only 3375 acres of land were under water. Substituting t = 2 and A(t) = 3375 into the equation above, we get:
[tex]3375 = A0 * e^{(-2k)[/tex]
We also know that initially, there were 6000 acres of land under water. Substituting A0 = 6000 into the equation above, we get:
Dividing both sides by 6000, we get:
ln(0.5625) = -2k[tex]ln(0.5625) = -2k[/tex]
Taking the natural logarithm of both sides, we get:
[tex]ln(0.5625) = -2k[/tex]
Solving for k, we get:
[tex]k = -ln(0.5625)/2[/tex]
k ≈ 0.3118
Therefore, the function to model the situation of the flood is:
[tex]A(t) = 6000 * e^{(-0.3118t)}[/tex]
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the profit p (in dollars) generated by selling x units of a certain commodity is given by the function p ( x ) = - 1500 + 12 x - 0.004 x ^ 2 What is the maximum profit, and how many units must be sold to generate it?
The profit (p) is $7500 generated by selling 1500 units of a certain commodity is given by the function p ( x ) = - 1500 + 12 x - 0.004 x²
To maximize our profit, we must locate the vertex of the parabola represented by this function. The x-value of the vertex indicates the number of units that must be sold to maximize profit.
We may use the formula for the x-coordinate of a parabola's vertex:
x = -b/2a
where a and b represent the coefficients of the quadratic function ax² + bx + c. In this situation, a = -0.004 and b = 12, resulting in:
x = -12 / 2(-0.004) = 1500
This indicates that when 1,500 units are sold, the profit is maximized.
To calculate the greatest profit, enter x = 1500 into the profit function:
P(1500) = -1500 + 12(1500) - 0.004(1500)^2
P(1500) = -1500 + 18000 - 9000
P(1500) = $7500
Therefore, the maximum possible profit is $7,500 and it is generated when 1,500 units are sold.
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To achieve this maximum profit, exactly 1500 units must be sold.
To find the maximum profit and the number of units needed to generate it, we can use the given profit function p(x) = -1500 + 12x - 0.004x^2. We need to find the vertex of the parabola represented by this quadratic function, as the vertex will give us the maximum profit and the corresponding number of units.
Step 1: Identify the coefficients a, b, and c in the quadratic function.
In p(x) = -1500 + 12x - 0.004x^2, the coefficients are:
a = -0.004
b = 12
c = -1500
Step 2: Find the x-coordinate of the vertex using the formula x = -b / (2a).
x = -12 / (2 * -0.004) = -12 / -0.008 = 1500
Step 3: Find the maximum profit by substituting the x-coordinate into the profit function p(x).
p(1500) = -1500 + 12 * 1500 - 0.004 * 1500^2
p(1500) = -1500 + 18000 - 0.004 * 2250000
p(1500) = -1500 + 18000 - 9000
p(1500) = 7500
So, the maximum profit is $7,500, and 1,500 units must be sold to generate it.
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Using the graph, determine the coordinates of the x-intercepts of the parabola.
Answer:
x = -5, x = 1
As (x, y) coordinates, the x-intercepts are (-5, 0) and (1, 0).
Step-by-step explanation:
The x-intercepts are the x-values of the points at which the curve crosses the x-axis, so when y = 0.
From inspection of the given graph, we can see that the parabola crosses the x-axis at x = -5 and x = 1.
Therefore, the x-intercepts of the parabola are:
x = -5x = 1As (x, y) coordinates, the x-intercepts are (-5, 0) and (1, 0).
1. suppose we know that the average weight of coyotes is 14.5kg with a standard deviation of 4kg. what is the probability of trapping a coyote that is 17kg or larger?
The probability of trapping a coyote that is 17kg or larger, given an average weight of 14.5kg and a standard deviation of 4kg is approximately 0.2743 or 27.43%.
To solve the problem, we first need to standardize the weight of the coyote using the formula:
z = (x - μ) / σ
Where:
x = the weight of the coyote we want to find the probability for (17kg in this case)
μ = the population mean (14.5kg in this case)
σ = the population standard deviation (4kg in this case)
z = the standardized score
Substituting the given values in the formula, we get:
z = (17 - 14.5) / 4
z = 0.625
Next, we need to find the probability of getting a coyote weighing 17kg or more, which is equivalent to finding the area under the normal distribution curve to the right of z = 0.625. We can use a standard normal distribution table or a calculator to find this probability.
Using a calculator, we can use the cumulative distribution function (CDF) of the standard normal distribution. The CDF gives the area under the curve to the left of a specified z-score. Since we want the area to the right of z = 0.625, we can subtract the CDF from 1 to get the area to the right.
Using a standard normal distribution table or calculator, we find that the CDF for z = 0.625 is approximately 0.734. Therefore, the area to the right of z = 0.625 is 1 - 0.734 = 0.266 or 26.6%.
Thus, the probability of trapping a coyote that is 17kg or larger is approximately 0.266 or 26.6%.
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Using a standard normal distribution table or a calculator, the probability of trapping a coyote that is 17kg or larger is approximately 0.266 or 26.6%.
What exactly is a standard normal distribution?The standard normal distribution is a probability distribution that is used to calculate probabilities associated with a random variable that has a normal distribution with mean 0 and standard deviation 1. Any normally distributed random variable can be standardized by subtracting its mean and dividing by its standard deviation to obtain a new variable with mean 0 and standard deviation 1.
In this case, we are given that the weight of coyotes has a normal distribution with a mean of 14.5kg and a standard deviation of 4kg. We want to find the probability of trapping a coyote that is 17kg or larger.
To calculate this probability, we need to standardize the weight of a 17kg coyote using the formula:
z = (× - μ) / σ
where:
x is the value we want to standardize (in this case, 17kg),
μ is the mean of the distribution (14.5kg),
σ is the standard deviation of the distribution (4kg).
Substituting the values we have:
[tex]z =\frac{(17 - 14.5)}{4} = 0.625[/tex]
This value of 0.625 is the z-score for a coyote weighing 17kg. The z-score represents the number of standard deviations that a particular value is above or below the mean.
Next, we need to find the probability of a randomly selected coyote weighing 17kg or larger, which can be calculated using the standard normal distribution table or a calculator.
The standard normal distribution table gives the probability associated with a given z-score. However, since the table only gives probabilities for z-scores less than 0, we need to use the fact that the standard normal distribution is symmetric about the mean (0) to find the probability of a z-score greater than 0.625.
Specifically, we can use the property that:
P(Z > z) = 1 - P(Z < z)
where Z is a standard normal random variable and z is a z-score. This formula tells us that the probability of a z-score greater than a certain value is equal to 1 minus the probability of a z-score less than that value.
Using this formula, we can calculate:
P(Z > 0.625) = 1 - P(Z < 0.625)
We can look up the value of P(Z < 0.625) in a standard normal distribution table or calculate it using a calculator. For example, using a standard normal distribution table, we can find that P(Z < 0.625) = 0.734.
Substituting this value into the formula, we get:
P(Z > 0.625) = 1 - 0.734 = 0.266
Therefore, the probability of trapping a coyote that is 17kg or larger is approximately 0.266 or 26.6%.
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Solve for x to make A||B.
A = x + 12
B = x + 48
X = [?]
Answer:
Step-by-step explanation:= x+48=180 ( linier pair )
= x=180-48
= x=132
= x+12=180 (liner pair)
= x=180-12
= x=168
The solid below is dilated by a scale factor of 1/2. Find the volume of the
solid created upon dilation.
24
26
10
34
Answer: 4080
Step-by-step explanation:
First you have to find the area of the triangle. 24*10 = 240. 240/2 = 120. Then you multiply the area of the triangle and multiply it by 34. 120 * 34 = 4080. This means the answer is 4080
Solve for x. -7.6 -1.2 + X 0.5
Help please? I just need an answer. A clear explanation earns brainliest.
the simplified form of expression is: -(x² + 2x - 2)/((x+2)*(x+4))
what is expression ?
In mathematics, an expression is a combination of numbers, variables, operators, and/or functions that represents a mathematical quantity or relationship. Expressions can be simple or complex
In the given question,
To evaluate the expression 1/(x+2) - (x+1)/(x+4), we need to find a common denominator for the two terms. The least common multiple of (x+2) and (x+4) is (x+2)(x+4).
So, we can rewrite the expression as:
(1*(x+4) - (x+1)(x+2))/((x+2)(x+4))
Expanding the brackets, we get:
(x+4 - x² - 3x - 2)/((x+2)*(x+4))
Simplifying the numerator, we get:
(-x² - 2x + 2)/((x+2)*(x+4))
Therefore, the simplified expression is:
-(x² + 2x - 2)/((x+2)*(x+4))
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The right triangle shown is enlarged such that each side is multiplied by the value of the hypotenuse, 3y. Find the expression that represents the perimeter of the enlarged triangle. TRIANGLE AND ANSWER CHOICES BELOW!
Answer:
c.
Step-by-step explanation:
The original triangle has two sides with length 4x each, and the hypotenuse has length 3y.
After the enlargement, each of the sides with length 4x becomes 3y × 4x = 12xy, and the hypotenuse becomes 3y × 3y = 9y^2.
Therefore, the perimeter of the enlarged triangle is the sum of the lengths of its three sides:
12xy + 12xy + 9y^2 = 24xy + 9y^2 = 9y^2 + 24xy
So the answer is (C) 9y^2 + 24xy.