As the normal contact force increases, the friction force also increases.
The friction force is proportional to the normal force, according to the formula: [tex]F_{friction} = \mu F_{normal}[/tex]
where [tex]F_{friction}[/tex] is the friction force,
μ is the coefficient of friction, and
[tex]F_{normal}[/tex] is the normal force.
Therefore, if the normal force increases, the friction force will also increase proportionally. The coefficient of friction remains constant for a given pair of materials in contact, so it does not change with the normal force.
The weight of the object does affect the normal force, but it does not affect the relationship between the normal force and the friction force.
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what astronomical event would be observed on the moon at the time the earth observed a lunar eclipse?
A lunar eclipse is an astronomical event where the Earth's shadow is cast onto the moon.
During a lunar eclipse, observers on the Earth would see the moon becoming dimmer and turning a reddish color, while observers on the moon would witness the Earth casting a shadow onto its surface.
The Earth is between the moon and the sun during a lunar eclipse, blocking the direct sunlight that normally illuminates the moon. This causes the moon to become dimmer and take on a reddish hue as indirect sunlight is refracted off of the Earth's atmosphere.
On the moon, observers would be able to see the Earth's shadow slowly moving across its surface. As the Earth's shadow covers the moon, the entire lunar surface will become darkened and take on a reddish hue. This is because indirect sunlight from the sun is refracted off of the Earth's atmosphere, providing a soft, red illumination to the moon's surface.
During a lunar eclipse, therefore, observers on the Earth and on the moon will witness the same kind of astronomical event.
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a double-slit with slit a width of 0.15 mm is placed 2.3 m from a viewing screen. how far is the first dark fringe from the middle screen when a light of wavelength 450 nm falls on the double-slit?
The first dark fringe is located approximately 7.35 mm from the central maximum on the screen.
The location of the first dark fringe can be found using the formula:
y = (mλD) / d
where y is the distance from the central maximum to the first dark fringe, m is the order of the fringe (m = 1 for the first dark fringe), λ is the wavelength of light, D is the distance from the double-slit to the screen, and d is the slit spacing (which is the sum of the slit width and the distance between the centers of the two slits).
The slit width is given as 0.15 mm = 0.00015 m, and the wavelength of light is 450 nm = 0.00045 m. The distance from the double-slit to the screen is 2.3 m.
To find the slit spacing, we need to know the distance between the centers of the two slits. If the double-slit is a single piece with two slits, the distance between the centers of the slits is usually given as the width of the slits plus the distance between them. If this information is not provided, we can assume that the distance between the centers of the slits is approximately equal to the width of each slit. Therefore, we can estimate the slit spacing as:
d ≈ 2 × 0.00015 m = 0.0003 m
Substituting the values into the formula, we get:
[tex]y = (1 × 0.00045 m × 2.3 m) / 0.0003 m[/tex]
y ≈ 7.35 m
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how large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 150 m m at a speed of 121 km/h k m / h ?
The coefficient of static friction, μs, between the tires and the road needs to be greater than the centripetal acceleration divided by the gravitational acceleration.
In this case, the centripetal acceleration can be calculated as ac = [tex](v^2)/r[/tex], where v is the speed and r is the radius of the curve. Therefore, the required coefficient of static friction μs = ac/g, where g is the gravitational acceleration, should be greater than μs = [tex](121 km/h)^2[/tex] / (150m) / [tex]9.81m/s^2[/tex] ≈ 0.93.
This means that the coefficient of static friction should be greater than 0.93 in order for the car to be able to round a level curve of radius 150 m at a speed of 121 km/h. This coefficient of static friction is necessary to counteract the centripetal force, allowing the car to round the curve without slipping.
If the coefficient of static friction is not large enough, the car will not be able to round the curve at the speed specified.
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g a research rocket is launched from boulder straight towards the south. how would the coriolis effect change the path of the rocket?
For a rocket launched southward from Boulder, the Coriolis effect would cause it to drift to the east, leading to a curved flight path rather than a straight one.
The Coriolis effect is an important force to consider when launching a research rocket from Boulder. The Coriolis effect is the result of Earth's rotation and will cause any object moving along the surface of the Earth to veer to the right in the Northern hemisphere and to the left in the Southern hemisphere.
This effect is most noticeable for objects traveling long distances, such as a rocket. As it continues to fly south, the Coriolis force will continue to act upon it, increasing the curvature of its path. The magnitude of the Coriolis force depends on the speed of the object and its distance from the poles. Therefore, the more time the rocket has to travel, the more it will be deflected from its intended path.
The Coriolis effect is an important factor to consider for any research rocket launch. It has the potential to affect the accuracy and success of the mission and must be taken into account when planning a launch trajectory.
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Complete Question:
A research rocket is launched from Boulder straight towards the south. How would the Coriolis effect change the path of the rocket?
Questions are in photo. Need actual answers and worked out. Pls and thank you.
Based on the above, 3.75 x 10¹² electrons have been added to the glass rod.
What is the electrons about?To determine the number of electrons added to the glass rod, we need to know the charge of a single electron. One electron has a charge of -1.6 x 10⁻¹⁹ C.
Charge added to the glass rod = -0.6 μC = -0.6 x 10-⁶ C
Number of electrons added to the glass rod = (charge added to the rod) / (charge of a single electron)
Number of electrons added to the glass rod = (-0.6 x 10⁻⁶ C) / (-1.6 x 10⁻¹⁹C) = 3.75 x 10¹² electrons
Therefore, 3.75 x 10¹² electrons have been added to the glass rod.
For the second question, we can use Coulomb's law to determine whether the pith ball and metal plate are attracted or repulsed. Coulomb's law states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them where
The force between the pith ball and the metal plate is:
F = k x q1 x q2 / r²
Pugging the value in the formula, the answer will be: F = -0.135 N.
The negative sign indicates that the force is attractive, so the pith ball and metal plate are attracted to each other.
For the third question, the force on the negatively charged object from problem 2 is 0.135 N, in the direction towards the positively charged pith ball.
For the fourth question, the force on the positively charged object from problem 2 is also 0.135 N, in the direction towards the negatively charged metal plate.
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See text below
You rub a glass rod with a piece of fur. If the rod now has a charge of -0.6 μC, how many electrons have been added to the rod?
A suspended pith ball possessing +10 μC of charge is placed 0.02 m away from a metal 'plate possessing -6 μC of charge. Are these objects attracted or repulsed?
What is the force on the negatively charged object from problem 2?
• What is the force on the positively charged object from problem 2?
a fragment of a current-carrying wire has a cross-sectional area that increases as shown. 1) if the current that flows through the wire is uniform, where is the drift velocity the greatest?
According to the given statement, if the current that flows through the wire is uniform, the drift velocity is the greatest at the section of wire with diameter d.
As the current is uniform throughout the wire, so the current through a given cross-sectional area is the same. Also, the current density, J is given by:
J = I/A
where I is the current and A is the cross-sectional area of the wire. Thus, if the area of the cross-section of the wire is more, the current density will be less. The current density is inversely proportional to the area of the wire, i.e. J ∝ 1/A. Hence, the drift velocity is inversely proportional to the current density, i.e. v[tex]_d[/tex] ∝ 1/J.
Thus, the drift velocity is greater where the cross-sectional area is less. So, the drift velocity is greater at the section of wire with diameter d.
So, the answer is at the section of wire with diameter d
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a star simultaneously emits red light, blue light, x-rays, and radio waves in the direction of the earth. which will arrive first?
The answer is that the radio waves will arrive first at the Earth when a star emits red light, blue light, x-rays, and radio waves.
This is due to the fact that radio waves are long-wavelength electromagnetic radiation. As a result, they are less likely to be impeded or absorbed by the intervening space medium, and they can propagate without being affected by any other disturbances in the cosmos.
Furthermore, radio waves are not influenced by the earth's atmosphere, which is responsible for interfering with the passage of light rays to the surface of the earth. In other words, radio waves can traverse enormous distances in space without being obstructed or attenuated by any physical barrier.
Light rays, on the other hand, propagate via a straight line, which is known as the line of sight. Light rays may be deflected or absorbed by cosmic dust, gas clouds, or other materials found in interstellar space. This may cause them to travel in different directions, which might cause them to be redirected from their initial path. As a result, light rays must contend with these obstacles before reaching the earth, which may cause them to be weakened or distorted by the time they arrive.
Similarly, X-rays are also electromagnetic radiation but they are absorbed by interstellar matter. They are also affected by magnetic fields, and they might be redirected from their path as a result of the interstellar medium. This might cause them to be slowed down and travel a longer distance, making their journey longer.
Thus, radio waves will arrive first because of their long wavelength and low interaction with cosmic matter.
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g what is the expected acceleration of the cart if its mass is 220 g and two masses of 250 g each are added to it. a mass of 60 g is placed in the mass hanger of 5 g.
The expected acceleration of the cart when two masses of 250 g are added to it, and a mass of 60 g is placed in the mass hanger of 5 g, given that its mass is 220 g is 1.55 m/s².
What is acceleration?
Acceleration is the change in velocity with respect to time. It can be defined as the rate at which the velocity of a body changes with respect to time. It is denoted by "a".
Mass is the amount of matter in a body or object. It is a scalar quantity, which is denoted by "m".
acceleration: a = (v - u) / t
Where; a = acceleration
v = final velocity
u = initial velocity
t = time taken
The expected acceleration of the cart:
Mass = Mass of cart + Mass of 2 masses
Mass = 220 g + (2 × 250 g)
Mass = 720 g
The total mass hanging on the mass hanger:
Mass on hanger = Mass of hanger + Mass on a hanger
Mass on hanger = 5 g + 60 g
Mass on hanger = 65 g
The net force acting on the system.
Net force = (Mass on hanger + Mass) × gNet force
= (65 g + 720 g) × 9.8 m/s²
Net force = 7.06 N
The expected acceleration of the cart;
a = F / ma
= (7.06 N) / (720 g)
a = (7.06 N) / (0.72 kg)a
= 9.81 m/s² × (7.06 / 0.72)a
= 1.55 m/s²
Therefore, the expected acceleration of the cart when two masses of 250 g are added to it, and a mass of 60 g is placed in the mass hanger of 5 g, given that its mass is 220 g is 1.55 m/s².
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how do extrusive igneous rocks form
Answer:
igneous rock is produced when magma exits and cools above (or very near) the Earth's surface. These are the rocks that form at erupting volcanoes and oozing fissures.
a 500g pot of water at room temperature (20c) is placed on a stove. how much heat is required to change this water to steam at 100c
To change 500g of water at room temperature (20°C) to steam at 100°C, you will need to add 1128.500 kJ of heat. This is because water requires a certain amount of heat energy, called the 'latent heat of vaporization', to turn from a liquid to a gas.
Mass of water (m) = 500g
Initial temperature ([tex]T_i[/tex]) = 20°C
Final temperature ([tex]T_f[/tex]) = 100°C
The heat of vaporization ([tex]H_{vap}[/tex]) = 2260 J/g.
To calculate the amount of heat required to convert 500 g of water at room temperature to steam at 100°C, we will use the formula:
[tex]Q = m \times H_{vap}\\Q = 500 g \times 2260 J/g\\Q = 1128500 J[/tex]
Therefore, it would take 1130000 J of heat to change this water to steam at 100°C.
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how much heat is lost through a 3' x 5' single-pane window with a storm that is exposed to a temperature differentia
The amount of heat lost through a 3' x 5' single-pane window with a storm that is exposed to a temperature differential is 108 BTU per hour.
The U-factor is a measure of how well a window insulates against heat transfer. The lower the U-factor, the better the window insulates.
The temperature difference is the difference between the inside and outside temperatures.The area of the window is the size of the window.Using these factors, we can calculate the rate of heat loss through the window in units of BTUs per hour.
Assuming a U-factor of 1.2 and a temperature difference of 60°F, the calculation would be:
Heat Loss = 1.2 BTU/(hrft^2F) x 15 ft^2 x 60°F
Heat Loss = 108 BTU/hour
Therefore, the heat lost through the window is 108 BTU per hour.
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Complete Question:
How much heat is lost through a 3' × 5' single-pane window with a storm that is exposed to a 60 Fahrenheit temperature differential?
TRUE or FALSE – Energy can be transferred from Kinetic Energy (KE) to Potential Energy (PE) and vice versa.
True, energy can be transferred from kinetic energy (KE) to potential energy (PE) and vice versa
Can energy be transferred from Kinetic Energy (KE) to Potential Energy (PE) and vice versa?The principle of the conservation of energy states that energy cannot be created or destroyed but can only transferred or transformed from one form to another.
When an object is in motion, it has kinetic energy, and when it is at rest, it has potential energy.
When the object moves from a stationary position to a position in motion, some of its potential energy is converted into kinetic energy.
Conversely, when the object moves from a position in motion to a stationary position, some of its kinetic energy is converted into potential energy.
Hence, the statement is TRUE.
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what must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 700 n/c ?
The charge (sign and magnitude) of a particle of mass 1.45 g must be for it to remain stationary when placed in a downward-directed electric field of magnitude 700 n/c is -1.029x10⁻⁴ C.
The magnitude of the charge must be equal to the magnitude of the electric field (700 n/c).
Therefore, we can write:-mg = qE
where, m = 1.45g = 1.45 x 10⁻³ kg
E = 700 N/cm = 1.45 x 10⁻³ kg x 9.81 m/s²
= 0.01419 N (Weight of the particle)
q = -1.029 x 10⁻⁴ C
To remain stationary when placed in a downward-directed electric field of magnitude 700 n/c, the charge (sign and magnitude) of a particle of mass 1.45 g must be negative.
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4. if the electric field of an electromagnetic wave is oscillating along the z-axis and the magnetic field is oscillating along the x-axis, in what possible direction is the wave traveling?
The possible direction in which an electromagnetic wave is traveling if the electric field is oscillating along the z-axis and the magnetic field is oscillating along the x-axis is the y-axis.
An electromagnetic wave is composed of two mutually perpendicular fields that oscillate perpendicular to the direction of the wave's propagation. They are the electric field and the magnetic field. An electromagnetic wave is created when a charged particle is accelerated. These waves can travel through a vacuum or any medium, including air and water, at the speed of light.
In this scenario, the electric field of the wave oscillates along the z-axis, while the magnetic field oscillates along the x-axis. As a result, the wave's propagation direction must be perpendicular to both fields. As a result, the wave must be propagating along the y-axis.This is why it's critical to comprehend the interplay between electric and magnetic fields in the context of electromagnetic waves.
It's also critical to recognize that an electromagnetic wave's direction of propagation is always perpendicular to the oscillation directions of the two fields, which are mutually perpendicular to each other.
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joshua sees two different colored stars in the night sky. based on his observations, what can joshua infer about the two stars?
Based on Joshua's observation that he sees two different colored stars in the night sky, he can infer that the two stars have different temperatures.
When Joshua sees two different colored stars in the night sky, he can infer that the two stars have different temperatures. This is because the colors of stars depend on their temperatures. When a star is blue, it means that it's hotter than a star that is yellow or red.
As a result, Joshua can infer that the two stars have different temperatures due to their colors.A star's temperature is determined by its color. The color of a star is determined by its surface temperature.
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skateboarder begins down a ramp at a speed of 1.0 m/s. after 3 seconds, her speed has increased to 4.0 m/s. calculate her acceleration
The acceleration of the skateboarder while going down the ramp is found to be 1m/s².
The skateboarder began to go down the ramp and that at a speed of 1.0m/s. After 3 seconds it is found that the speed of the skater is increased to 4.0m/s.
We can use the equation,
V = U+at, where, V is final speed, a is acceleration, t is time and U is initial speed.
Putting all the values,
4 = 1 +a(3)
a = 3/3
a = 1m/s²
The acceleration of the skateboarder is 1m/s².
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what was the ratio of a weight to its just noticeable difference weight when they were lifted what was the ratio of a weight to its just noticeable difference weight when the weight were placed in the subject's hands?
According to Weber's Law, the ratio of a weight to its just noticeable difference weight when placed in the subject's hands is 1 : 40.
The ratio of a weight to its just noticeable difference weight when it is lifted by a subject is 1 : 40. This implies that if the weight of an object is x, the minimum additional weight that can be added to it and be noticed by a subject is x/40.The ratio of a weight to its just noticeable difference weight when the weight is placed in the subject's hands is 1:20.
This implies that if the weight of an object is x, the minimum additional weight that can be added to it and be noticed by a subject when it is placed in their hands is x/20. The Weber-Fechner Law applies in this scenario. It is a relationship between the intensity of a stimulus and its perceived strength that states that the sensation is proportional to the logarithm of the stimulus' intensity.
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if the force of friction opposing the motion is 18 n, what force f (in n) is the person exerting on the mower? (enter the magnitude.)
The force f (in n) the person is exerting on the mower is 18 n.
The force of friction opposing the motion refers to the force that acts in the opposite direction to the motion of an object and makes it harder to move.
According to the given statement, the force of friction opposing the motion is equal to the force f (in N) the person is exerting on the mower.
This indicates that the person's pushing force must be equal to the force of friction opposing the motion for the mower to move at a constant speed.
Using the above information, we can calculate the force f (in N) that the person is exerting on the mower as 18 n since it is equal to the force of friction opposing the motion.
Therefore, the person must push with a force f (in N) of 18 n to overcome the friction and maintain a constant speed for the mower.
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what is the relationship between weight and best range airspeed (vbr) and best endurance airspeed (vbe)?
The relationship between weight and best range airspeed (VBR) and best endurance airspeed (VBE) is that both VBR and VBE increase with an increase in weight.
What is best range airspeed (VBR)? Best range airspeed (VBR) refers to the airspeed at which an aircraft can cover the maximum possible distance with minimum fuel consumption. At this airspeed, the lift-to-drag ratio is the highest.
What is best endurance airspeed (VBE)? Best endurance airspeed (VBE) refers to the airspeed at which an aircraft can remain in the air for the longest possible time with minimum fuel consumption. At this airspeed, the lift-to-drag ratio is the highest.
Relationship between weight and VBR and VBE is that both VBR and VBE increase with an increase in weight.
An increase in weight means an increase in the required lift to keep the aircraft in the air. As a result, the airspeed at which the lift-to-drag ratio is the highest increases.
This is why both VBR and VBE increase with an increase in weight.
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a gun fires a bullet vertically into a 1.40-kg block of wood at rest on a thin horizontal sheet.if the bullet has a mass of 26.8 g and a speed of 230 m/s , how high will the block rise into the air after the bullet becomes embedded in it?
The block will rise to a height of approximately 4.36 cm after the bullet becomes embedded in it.
We can use the principle of conservation of momentum to solve this problem. The total momentum of the system (bullet + block) before the collision is,
p_before = m_bullet * v_bullet
where m_bullet is the mass of the bullet and v_bullet is its speed.
After the collision, the bullet becomes embedded in the block, so the total mass of the system is,
m_total = m_bullet + m_block
The velocity of the combined bullet-block system after the collision can be calculated using the conservation of momentum,
p_before = p_after
m_bullet * v_bullet = (m_bullet + m_block) * v_after
where v_after is the velocity of the combined bullet-block system after the collision.
Solving for v_after,
v_after = (m_bullet * v_bullet) / (m_bullet + m_block)
Now, we can calculate the kinetic energy of the bullet-block system just after the collision,
KE_after = (1/2) * (m_bullet + m_block) * v_after^2
The initial kinetic energy of the bullet is,
KE_before = (1/2) * m_bullet * v_bullet^2
The difference between these two energies represents the energy that has been transferred to the block,
delta_KE = KE_before - KE_after
This energy is used to raise the block to a certain height h. If we assume that all of this energy is converted into potential energy, then we can write,
delta_KE = m_block * g * h
where g is the acceleration due to gravity.
Solving for h,
h = delta_KE / (m_block * g)
Substituting the expressions for delta_KE, m_block, v_bullet, and v_after,
h = [(1/2) * m_bullet * v_bullet^2] / [(m_bullet + m_block) * g]
Substituting the given values,
h = [(1/2) * 0.0268 kg * (230 m/s)^2] / [(0.0268 kg + 1.40 kg) * 9.81 m/s^2] = 0.0436 m
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a flashlight bulb carries a current of 0.32 a for 82 s . part a how much charge flows through the bulb in this time?
Answer:
Q = I t definition of current
Q = .32 Coul/sec * 82 sec = 26.2 coul
Suppose you were to compare three stars with the same surface temperature. If star A is a giant star, star B is a supergiant star, and star C is a main sequence star, order the three stars in terms of increasing radius. a. Star C, Star A, Star B b. Star B, Star A, Star C c. Star A, Star C, Star B d. Star B, Star C, Star A
If star A is a giant star, star B is a supergiant star, and star C is a main sequence star, the order of the three stars in terms of increasing radius is Star A, Star C, Star B.
A giant star is a luminous star that is considerably larger and brighter than the sun. The distinction between giant and dwarf stars is primarily determined by their luminosity, and giant stars are more luminous. They are not, however, larger in diameter than dwarf stars. Their size is the outcome of a high luminosity-to-mass ratio.
A supergiant star is a massive star with a luminosity that is many times greater than that of a giant star. As a result, a supergiant star is much larger than a giant star. However, supergiant stars have a similar surface temperature as giant stars.
Sequence stars are stars that spend most of their lives in the primary sequence of stars. A main-sequence star is a star that is in the hydrogen-burning phase of its evolution. It is in a state of hydrostatic equilibrium, meaning that the gravitational force holding the star together is balanced by the pressure generated by the thermonuclear fusion taking place in its core.
The stars will have the following order in terms of increasing radius: Star A, Star C, Star B if star A is a giant star, star B is a supergiant star, and star C is a main sequence star, and they all have the same surface temperature.
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measurements show a certain star has a very high luminosity (100,000 x the sun's) while its temperature is quite cool (3500 k). how can this be?
The star might be quite large in size, with a much larger surface area than the sun. This would increase its luminosity despite its cooler temperature.
The star has a high luminosity (100,000 x the sun's) and a cool temperature (3500 K) because of its size.
A star's luminosity is proportional to its size, so if a star is very large, it can have a high luminosity even if it is relatively cool.
Another possibility is that the star is in a phase of its life cycle where it has expanded and cooled, such as a red giant or supergiant, but still retains a high luminosity due to its large size.
These stars have relatively low surface temperatures, but their large sizes give them very high luminosities.
Therefore, this star is likely very large and thus has a very high luminosity despite its low temperature.
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if a 2000-kg car traveling at 30 m/s hits a wall and comes to a complete stop in 0.03 seconds, how much force was applied to the car?
If a 2000-kg car traveling at 30 m/s hits a wall and comes to a complete stop in 0.03 seconds the force that was applied to the car is 6,000,000 N
The force applied to the car can be calculated using the formula:
Force = (mass x change in velocity) / time
Here, the mass of the car is 2000 kg, the initial velocity is 30 m/s, the final velocity is 0 m/s (since the car comes to a complete stop), and the time taken is 0.03 seconds.
Substituting these values, we get:
Force = (2000 kg x (0 m/s - 30 m/s)) / 0.03 s
Force = -6,000,000 N
The negative sign indicates that the force is acting in the opposite direction to the motion of the car. So, the force applied to the car by the wall is 6,000,000 N.
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a microwave oven sets up a standing wave of wavelength 12.2 cm c m between two parallel conducting walls 48.8 cm c m apart. find the wave frequency.
The frequency of the standing wave set up by the microwave is 8 GHz (or 8 × 10^9 Hz).
What is Wavelength?
The wavelength of the microwave is 12.2 cm, and the distance between the two parallel walls is 48.8 cm.
frequency is:
f = v/λ
where `v` is the velocity of the wave and `λ` is the wavelength of the wave.
to calculate the velocity of the microwave:
`v = 2dƒ`
where `d` is the distance between the two walls and `ƒ` is the frequency.
Substituting the given values,`
v = 2(0.488)ƒ`.
Rearranging the equation for `ƒ`,
'ƒ = v/2d`.
Substituting `v` and `d` with the values given in the question:
`ƒ = (2 × 0.488) / (2 × 0.122)`.
Simplifying the expression,
`ƒ = 8`.
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Need help badly, please answer!
Answer:
i will change this answer when you attach a picture with it
Explanation:
a light has the frequency of 4.74 x 1014 sec-1 (hz). what is the wavelength? please show all the steps and all of your work when you upload your final answer.
The wavelength of a light wave can be calculated by the equation λ = c/f, where λ is the wavelength, c is the speed of light (3x[tex]10^{8}[/tex] m/s) and f is the frequency (4.74 x [tex]10^{14}[/tex] [tex]sec^{-1}[/tex]). Therefore, the wavelength of the light wave is 6.32 x [tex]10^{-7}[/tex] m.
The given frequency is 4.74 x 1014 sec-1. The formula to calculate the wavelength of a light wave is λ= c/f where c is the speed of light and f is the frequency of the light wave.
Therefore, λ= c/f= (3.00 x [tex]10^{8}[/tex] m/s)/(4.74 x [tex]10^{14}[/tex] [tex]sec^{-1}[/tex])= 6.32 x [tex]10^{-7}[/tex] m or 632 nm (rounding to three significant figures).
The wavelength of light is 6.32 x [tex]10^{-7}[/tex] m or 632 nm (rounding to three significant figures).
Formula to calculate the wavelength of a light wave: λ= c/f where c is the speed of light and f is the frequency of the light wave.
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a photon in the rest frame of a star has a wavelength of 780 nm. an observer on earth measures it to be at a wavelength of 768 nm. the star is then:
The star is moving away from the observer. An observer on the Earth measured the wavelength of a photon as 768 nm, while the photon's rest wavelength was 780 nm.
What is the Doppler effect?
According to the Doppler effect, if the wavelength of the wave is measured at different positions, it will shift. In this situation, the observer on the Earth is seeing a shift in the photon's wavelength due to the motion of the star.
To be more specific, when the star moves away from the observer, the observer observes an increase in the wavelength. Therefore, the star is moving away from the observer.
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what principle states that the buoyant force experienced by an object is exactly equal to the weight of the fluid displaced?
The principle that states that the buoyant force experienced by an object is exactly equal to the weight of the fluid displaced is known as Archimedes' Principle. What is Archimedes' Principle? Archimedes' Principle is a scientific law that explains how objects behave in fluids (liquids and gases).
The buoyant force of an object in a fluid is equal to the weight of the fluid displaced by the object according to this principle. This principle is valid for any fluid and any object as long as the buoyancy and weight of the object and fluid are calculated correctly.
The force that causes objects to float or sink in fluids is known as buoyancy. The buoyant force on an object is the net upward force exerted by the fluid in which the object is submerged.
When an object is immersed in a fluid, the fluid exerts an upward force on the object. This buoyant force opposes the weight of the object and causes it to float if the buoyant force is greater than the weight of the object.
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how many kwh k w h of energy does a 600- w w toaster use in the morning if it is in operation for a total of 6.0 min m i n ?
The answer are energy used by the 600-watt toaster for 6.0 min is 0.06 kWh (kilowatt-hours).
To solve the problem, we must first calculate the power of the toaster and the time it is in use. The toaster's power is given to be 600 watts, and the time it's in use is 6 minutes.
The formula for calculating energy is given below. Energy = Power x Time Energy = 600 x 6 Joules
Using the conversion factor, we can convert joules to kilowatt-hours (kWh).1 kWh = 3.6 x 10^6 J
Now, we can find out the energy used in kilowatt-hours.
Energy = 600 x 6 / (3.6 x 10^6) kWh Energy = 0.06 kWh
Hence, the energy used by the 600-watt toaster for 6.0 min is 0.06 kWh (kilowatt-hours).
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