ASCD is a parallelogram. Determine whether each statement must be true. Select Yes
or No for each statement
B

Answer:

[tex]A.[/tex]

[tex]Domain = \{-6,-4,0\}[/tex]

Step-by-step explanation:

Given

[tex]\{(-6, 3), (-4, 5), (0, 0)\}[/tex]

Required

The domain

A function is represented as:

[tex]\{(x_1,y_1), (x_2,y_2), ....... (x_n,y_n)\}[/tex]

Where the domain is: [tex](x_1,x_2,....,x_n)[/tex]

So, in [tex]\{(-6, 3), (-4, 5), (0, 0)\}[/tex]

The domain is:

[tex]Domain = \{-6,-4,0\}[/tex]

Answer:

The correct solution is "7.3%".

Step-by-step explanation:

It seems that the given question is incomplete. Find below the attachment of the complete and appropriate query.

According to the question,

The total married couples are,

= 55,550,000

where,

Both native = 79.5%

Both foreign = 13.2%

Now,

The percentage of couple that is one native as well as one foreign will be:

= [tex]100-79.5-13.2[/tex]

= [tex]7.3[/tex] (%)

Answer:

LCL = 4.72

UCL = 18.08

Step-by-step explanation:

Sample size, n = 20

Sample _ tread wear, x __ Range

1 ______ 33.67 ___ 14

2______ 26.33 ___ 17

3 _____ 29.67 ____ 9

4 ______ 21 ______ 8

5 ______ 34 ______ 9

6 ______ 39.67 ___ 6

7 ______ 22.33 ___ 12

8 ______ 28.67 ___ 6

9 ______ 36 ______8

10 _____ 25.33 ___ 13

11 _____ 32.33 ____14

12 _____ 22.33 ___ 6

13 _____ 24.33 ___ 15

14 _____ 31.67 ___ 26

15 _____ 24 _____ 11

16 ____ 34.33 ____ 12

17 ____ 32 _______ 8

18 ____ 33.33 ____ 11

19 ____ 25 _______11

20 ___ 27.33 _____12

Sample mean, xbar = Σx / n = 29.167

Rbar = ΣR/ n = 11.4

The R chart control limit is given by :

Rbar(1 - 3(d3/d2))

From the R chart :

d3 = 0.729 ; d2 = 3.735

Hence,

LCL = 11.4(1 - 3(0.729/3.735))

LCL = 11.4(0.4144578) =

LCL = 4.72481892 = 4.72

UCL = 11.4(1 - 3(0.729/3.735))

UCL = 11.4(1.5855421)

UCL = 18.075180 = 18.08

Answer:

10^9/10^5

Step-by-step explanation:

2^3 = 8 x 2^6= 64 8 x 64 = 512

This is equal 10^9 / 5 ^ 9

Answer:

The following below are those that shows the correct values for then median-fit method of the restaurant relationship between the number of tables seated (x) and the total number of cups of complementary salsa served (y):

O.  The middle summary point is (52, 103.75).

O.  The right summary point is (63, 160).

O.  The middle summary point is (52, 103.75).

Step-by-step explanation:

Answer:

B.) The middle summary point is (52, 110.5).

D.) The slope of the line of best fit is 2.14.

Step-by-step explanation:

Just did the assignment on Edg 2022 (Linear Regression Methods)

Answer:

trata de usar común un like para que puedes hacer frío

Answer:

600W = C

Step-by-step explanation:

First we must identify the relationship between weight of gold and cost of gold.

We can do this by dividing cost by corresponding weight.

7200 / 12 = 600

13200 / 22 = 600

19200 / 32 = 600

each proportion has an outcome of 600

Therefore Cost = Weight times 600 or C = 600W

Answer:

D)   73.5º

Step-by-step explanation:

Law of sines

sinQ/15 =sin50.1/12

multiply both sides by 15

sinQ = sin50.1/12 * 15

sinQ = 0.958956439769124

Q = arcsin0.958956439769124

Q = 73.5º

Answer:

d

Step-by-step explanation:

The inverse of a conditional statement, makes both the hypothesis and conclusion or "p" and "q" negative. In other words, it adds a not to both sides.

So the inverse of "If p, then q" would be "If not p, then not q."

"If the measure of angle 1 does not equal 60 degrees, then angle 1 is not acute."

Answer:

75% of all students have GPAs between 1.5 and 3.5

Step-by-step explanation:

11% of all students at this high school have GPA of 3.5 of higher:

This means that a GPA of 3.5 is in the 100 - 11 = 89th percentile, that is, a student that gets a GPA of 3.5 has a higher GPA than 89% of students.

14% have GPAs of 1.5 or lower.

This means that a GPA os 1.5 is in the 14th percentile, that is, a student that gets a GPA of 1.5 has a higher GPA than 14% of students.

What percentage of all students have GPAs between 1.5 and 3.5?

Percentile of 3.5 subtracted by the percentile of 1.5.

89 - 14 = 75%.

75% of all students have GPAs between 1.5 and 3.5

Answer:

0.75 = 75% probability that she knewthe answer to that question

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Answered correctly.

Event B: Knew the answer.

Probability of answering correctly:

0.5(knows the answer)

1/3 of 1 - 0.5 = 0.5(didn't know but guessed correctly). So

[tex]P(A) = 0.5 + 0.5\frac{1}{3} = 0.6667[/tex]

Probability of answering correctly and knowing the answer:

0.5, which means that [tex]P(A \cap B) = 0.5[/tex].

What is the probability that she knew the answer to that question?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.5}{0.6667} = 0.75[/tex]

0.75 = 75% probability that she knewthe answer to that question

Answer:

There are 16 servings in the bottle.

Step-by-step explanation:

The equation for the amount of juice left in the bottle is:

y = 128 - 8*x

Where x is the number of servings of juice poured from the bottle.

The total number of servings that are in the bottle is the value of x such that we have y = 0 (because in that point, we do not have more juice left)

Then we need to solve:

y = 0 = 128 - 8*x

8*x = 128

now we can just divide both sides by 8

x = 128/8 = 16

There are 16 servings in the bottle.

Answer: D. 18

Step-by-step explanation:

Euler's formula is Faces + Vertices = Edges + 2

Faces = Edges - vertices + 2

Faces = 39-23 + 2 = 18

Euler's formula is given by the formula F + V = E + 2. The number of faces in the given object is 18.

Euler's formula is given by the formula F + V = E + 2, in which F is the number of faces, V is the number of vertices, and E is the number of edges. For instance, a cube fits this formula since it has 6 faces, 8 vertices, and 12 edges.

The number of vertices and edges in the object is 23 and 39, respectively. Therefore, using Euler's formula the number of faces can be written as,

F + V = E + 2

F + 23 = 39 + 2

F = 39 + 2 - 23

F = 18

Hence, the number of faces in the given object is 18.

Learn more about Euler's Formula here:

https://brainly.com/question/6459192

#SPJ2

Answer:

32

Step-by-step explanation:

so because there is 1 cup of  kernels which makes 4 cups of pop corn and there are 8 cups of crenels you would multiply 8 and 4.

Answer:

MT is congruent to MS

Step-by-step explanation:

Answer:

[tex]MT[/tex]≅[tex]MS[/tex]

Step-by-step explanation:

Because line MN is a perpendicular bisector, and point on the bisector will be equidistant from the end points of the segment it bisects.

Answer:

value we donnot know so we try to find it by equations

Answer:

Any number of possibilities...

Step-by-step explanation:

Answer:

In mathematics, a unit circle is a circle of unit radius—that is, a radius of 1. Frequently, especially in trigonometry, the unit circle is the circle of radius 1 centered at the origin in the Cartesian coordinate system in the Euclidean plane.

Step-by-step explanation:

Answer:

El círculo unitario se divide en 4 partes, denominadas cuadrantes. El primer cuadrante (I) está formado por los ejes xey positivos. El primer cuadrante (I) está formado por los ejes xey positivos. Si dibujamos cualquier radio del círculo unitario en el primer cuadrante, el ángulo con el eje x positivo puede tener cualquier valor entre 0 y 90 °.

Answer: hello your question is incomplete below is the missing part

Determine the proportion of radishes grown without fertilizers with weight less than 50grams

answer : p( x < 50 ) = 0.84

Step-by-step explanation:

Radish grown in without fertilizers ( normally distributed )

mean = 40 g

standard deviation = 10 g

Radish grown with fertilizers ( normally distributed )

Mean = 140 g

standard deviation = 40 g

Determine the proportion of radishes grown without fertilizers with weight less than 50 grams

lets assume x = radish without fertilizers

                    y = radish with fertilizers

hence

p( x < 50 )  = P (  (x-μ / б)  < [tex]\frac{50-40}{10}[/tex]  )

                  = p ( z < 1 ) = 0.5 + p ( 0 < z < 1 )

                                   p( x < 50 ) = 0.5 + 0.3413 = 0.8413

attached below is the distribution related to this solution

Answer:

10 miles

Step-by-step explanation:

Given

The attached grid

Required

The distance between Oden and Lundy

See attachment for modified grid

From the newly attached grid, we have:

[tex]d^2 = 6^2 + 8^2[/tex] ---- Pythagoras theorem

This gives:

[tex]d^2 = 36 + 64[/tex]

[tex]d^2 = 100[/tex]

Take positive square roots of both sides

[tex]d = \sqrt{100[/tex]

[tex]d = 10[/tex]

Hence, the distance is 10 miles

Answer:

a) 0.324 = 32.4% probability that exactly 3 drivers text while driving if a police officer pulls over five drivers

b) 0.0276 = 2.76% probability the next driver texting while driving that the police officer pulls over is the fifth driver.

Step-by-step explanation:

For each driver pulled, there are only two possible outcomes. Either they are texting, or they are not. The probability of a driver being texting is independent of any other drivers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

It is estimated that 52% of drivers text while driving.

This means that [tex]p = 0.52[/tex]

A. What is the probability that exactly 3 drivers text while driving if a police officer pulls over five drivers?

This is [tex]P(X = 3)[/tex] when [tex]n = 5[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 3) = C_{5,3}.(0.52)^{3}.(0.48)^{2} = 0.324[/tex]

0.324 = 32.4% probability that exactly 3 drivers text while driving if a police officer pulls over five drivers.

B. What is the probability the next driver texting while driving that the police officer pulls over is the fifth driver?

None of the first four([tex]P(X = 0)[/tex] when [tex]n = 4[/tex]), and then the fifth, with 52% probability. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{4,0}.(0.52)^{0}.(0.48)^{4} = 0.0531[/tex]

0.0531*0.52 = 0.0276

0.0276 = 2.76% probability the next driver texting while driving that the police officer pulls over is the fifth driver.

Answer:

Step-by-step explanation:

X squared over 6

+

2x cubed over 3

Answer:

x^2/6 + 2x^3/3

Step-by-step explanation:

I used (m)athway to simplify the expression

Answer:

The 2nd box is the 1st box is not

Step-by-step explation:

it just is thi sway

Answer:

nooe!

Step-by-step explanation:

the first set ads up to 133/120 whike the second ads up to 2 so they aren't :)

Answer:

[tex]Product = \frac{3}{5}ab[/tex]

Step-by-step explanation:

Given

[tex]-\frac{3}{7}a[/tex]

[tex]-\frac{21}{15}b[/tex]

Required

The product

The product is:

[tex]Product = -\frac{3}{7}a * -\frac{21}{15}b[/tex]'

Cancel out the negative signs

[tex]Product = \frac{3}{7}a * \frac{21}{15}b[/tex]

Simplify fractions

[tex]Product = \frac{1}{7}a * \frac{21}{5}b[/tex]

[tex]Product = \frac{1}{1}a * \frac{3}{5}b[/tex]

[tex]Product = \frac{3}{5}ab[/tex]

Answer:

6 is the median of the data set.

Step-by-step explanation:

First, write all the numbers out.

1, 2, 3, 3, 4, 4, 5, 5, 5, 6, 6, 6, 6, 7, 7, 7, 8, 8, 8, 9, 9, 11

Next, highlight the one that is in the middle.

1, 2, 3, 3, 4, 4, 5, 5, 5, 6, 6, 6, 6, 7, 7, 7, 8, 8, 8, 9, 9, 11

If you have an even amount of numbers, or two numbers in the middle you have to find the mean between those numbers but because they are both 6 the median is still 6.

Have a wonderful day! :)

[tex]\sf \left(\sqrt{2}\right)^3\\\\\\\\\boxed{\sf \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}}\\\\\\\\\sf \left(2^{\frac{1}{2}}\right)^3\\\\\\\\\boxed{\sf\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} }\\\\\\\\\sf \sf 2^{\frac{1}{2}\cdot \:3}\\\\\\\\\sf 2^{\frac{3}{2}}\\\\\\\\\sf 2^{\frac{3}{2}}=2^{1+\frac{1}{2}}\\\\\\\\\sf 2^{1+\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Apply\:exponent\:rule}:\quad \:x^{a+b}=x^ax^b}\\\\\\\\\sf[/tex]

[tex]\sf 2 ^1\cdot \:2^{\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Refine}}\\\\\\\\\boxed{\sf =2\sqrt{2}}[/tex]