(a) To generate a 1 T magnetic field inside the solenoid, we need 7.96 x 10⁶ turns.
(b) If we had an iron core inside the solenoid with relative permeability of 64,000, the number of turns would be 124 turns.
What is the number of turns of the solenoid?
The number of turns of the solenoid is determined by applying the following equation for magnetic field strength at the center of the solenoid.
B = μnI
where;
μ is the permeability of free space = 4π x 10⁻⁷ T/AI is the current = 1 mA = 0.001 AB is magnetic field strength = 1 Tn is number of turns per lengthn = B/ μI
N/L = B/μI
N = (BL)/μI
where;
L is the length of the solenoidn = (1 x 0.01) / (4π x 10⁻⁷ x 0.001)
n = 7.96 x 10⁶ turns
If we had an iron core inside the solenoid with relative permeability of 64,000, the number of turns would be calculated as;
N = (BL)/(μI x μr)
where;
μr is the relative permeabilityN = (1 x 0.01) / (4π x 10⁻⁷ x 0.001 x 64,000)
N = 124 turns
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Which force causes motion?
Motion is caused due to external Force.
The universe contains multiple fundamental forces, including gravity, electromagnetic force, and weak and strong nuclear forces. However, when it comes to the motion of common objects, the forces of importance are primarily gravity, friction, and applied force.
The vector sum of all the forces acting on an object is the net force. That is, the net force is the sum of all forces, taking into mind that a force is a vector, and two forces of identical size and opposing direction cancel each other out.
When you apply force to an object, it moves. However, there is a little more to the story. Newton's second rule of motion asserts that you must total up all of the forces acting on a system to determine what will happen to it.
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If the maximum tension the rope can with- stand before breaking is 132.3 N, what is the maximum tangential speed the ball can have?
Answer in units of m/s.
The Maximum tangential speed the ball can have would be = 5.3m/s.
What is tangential speed?A tangential speed is defined as the speed of an object that has an angular velocity with respect to an instantaneous velocity.
The formula used to calculate the maximum tension;
T = mv²/r
Where T = Maximum tension = 132.3N
M = mass= 4kg
r = radius = 0.86m
V= tangential speed = x
Make v the subject of formula;
V = √Tr/m
V = √ 132.3 × 0.86/4
V = √113.778/4
V= √28.4445
V = 5.3 m/s.
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Complete question:
An athlete swings a 4.00 kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.860 m at an angular speed of 0.660 rev/s. If the maximum tension the rope can withstand before breaking is 132.3 N, what is the maximum tangential speed the ball can have?
what is the conclusion for the physics lesson acceleration and free falling objects grade 9
The simple conclusion I can make from the task given above is that all the objects in the universe possess constant acceleration under the influence of a free fall is actually due to gravity.
How objects free falling objects has the same acceleration under the influence of gravity.It has been practically proven that all objects or bodies; regardless of their masses have the same acceleration as long as they are under a free fall as a result of the Earth's gravitational force.
So therefore, it can now be deduced with understanding that all free falling objects have the same acceleration due to gravity.
Complete question:
What conclusion can you make on acceleration and free falling objects grade?
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Johnny lets a 0.5 kg ball roll on the floor of the classroom. The ball gradually slows down. Draw a free body diagram and calculate the acceleration of the ball
The free body diagram of the ball as shown shows al the forces that acts on the ball as it rolls on the floor.
What is the free body diagram of the ball?We know that a free body diagram is the diagram that shows the forces that act on an object. Force is a vector quantity thus we must consider the magnitude and the direction of the force. An object can be acted upon by a system of forces. The system of forces would only cause the object to move when the forces are unbalanced. If the system of forces is balanced, the object would not move at all.
In this case, we have a ball that is rolling on a floor. There are four main forces that are acting on the ball as we can see from the free body diagram. These are;
1) The weight of the ball that acts downwards
2) The normal reaction that acts upwards
3) The force that moves the ball forward
4) The force of friction that resists the forward motion of the ball.
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4. In a physics lab, Kate and Rob use a hanging mass and pulley system to exert a 2.45 N
rightward force on a 0.500-kg cart to accelerate it across a low-friction track. If the total
resistance force to the motion of the cart is 0.72 N, then what is the cart's acceleration?
Fgrav = 4.90 N; Fnorm = 4.90 N; Fnet = 1.73 N, then the acceleration of the cart is (a) = 3.46 m/s/s,
What is acceleration and its types?Acceleration is defined as a vector quantity, the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. It can be either positive, negative, or zero depending upon the velocity and its direction. Three types of acceleration are Uniform acceleration, non-uniform acceleration, and average acceleration.
Formula
{a} = v - v0/t =Δv/Δ t
{a} = average acceleration
v = final velocity
v_0 = starting velocity
t = elapsed time
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which of the following are decomposition reactions?
a. CH^4 (g) + 20^2 (g) ->CO^2 (g) + 2H^2O (g)
b. CaCO^3 (s) -> CaO (s) + CO^2 (g)
c. N^2 (g) + 3H^2 (g) -> 2NH^3 (g)
d. 2H^2O (i) -> 2H^2 (g) + O^2 (g)
Check all that apply
The correction options indicating a decomposition reaction are:
B. CaCO₃ -> CaO + CO₂D. 2H₂O -> 2H₂ + O₂What is a decomposition reaction?This a reaction in which a compound breaks down into smaller elements or compound by the application of heat. Example is given below:
AB₂ -> A + B₂
We can see that AB₂ decomposed to produce A and B₂
With the above information in mind, we can easily determine which reaction is decomposition reaction from the given options.
The options from the question are:
A. CH₄ + 2O₂ -> CO₂ + 2H₂OB. CaCO₃ -> CaO + CO₂C. N₂ + 3H₂ -> 2NH₃D. 2H₂O -> 2H₂ + O₂Observing the given options with the knowledge of decomposition reaction, we can conclude that the correct options are:
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How much energy must a stove transfer to completely heat 1g of liquid water from 1o C to 25o C?
The energy needed by a stove to transfer heat completely to 1 g of liquid water fro 1 °C to 25 °C is 100.37 J.
What is energy?Energy is the ability or the capacity to do work.
To calculate the amount of energy, we use the formula below.
Formula:
Q = cm(t₂-t₁).............. Equation 1Where:
Q = Amount of energyc = Specific heat capacity of the waterm = mass of the watert₂ = Final temperaturet₁ = Initial temperatureFrom the question,
Given:
m = 1 g = 0.001 kgc = 4182 J/kg°Ct₁ = 1 °Ct₂ = 25 °CSubstitute these values into equation 1
Q = 0.001(4182)(25-1)Q = 100.37 JHence, The energy required is 100.37 J.
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Taking into account the definition of calorimetry, the energy that a stove must transfer to completely heat 1 g of liquid water from 1 °C to 25 °C is 100.416 J.
Definition of calorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
When heat added or removed from a substance causes a temperature change in it without affecting its molecular structure, it is called sensible heat.
So, the expression that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.c is the specific heat substance.ΔT is the temperature variation.Energy in this caseIn this case, you know:
Q= ?c= 4.184 J/gCm= 1 gΔT= Tfinal - Tinitial= 25 C - 1 C= 24 CReplacing in the definition of calorimetry:
Q = 4.184 J/gC× 1 g× 24 C
Solving:
Q= 100.416 J
Finally, the energy needed is 100.416 J.
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Use the equation GPE = mx 9.8 m/sxh to calculate the gravitational potential of a 10-kg
sack of groceries on a shelf 1 m above the floor?
A 10-kg bag of goods on a shelf one meter above the ground has a gravitational potential of GPE= (10 kg)(9.8 m/s2) (1 m) GPE= 98 J
How to compute gravitational potential energyThe formula for gravitational force is P.E. = mgh, where m represents the mass in kilograms, ga is the acceleration caused by gravity (9.8 m/s2 at the earth's surface), and h is the height in meters. Keep in mind that the gravitational potential energy is measured in the same units as kinetic energy, namely kg m2/s2.
What exactly is gravitational potential?The amount of labor required to dispense a body of unit mass form infinity to a certain point in a body's gravitational field is known as the gravitational potential. It is designated with the letter V.
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function of a transformer in electrical circuits
Explanation:
There two types of transformers which are mainly stepup and step down transformers
the former is used for increasing voltage while the latter is used for reducing voltage
What is the critical angle for light traveling from ice (n=1.309) into air?
a. 39.8⁰
c. 59.8⁰
b. 49.8⁰
d.
69.8°
Answer:
b. 49.8
Explanation:
θc = sin^-1(1/1.309) = 49.81
science class is conducting an investigation to see how gravity affects objects of different masses. They drop three balls from the same height. They
me how long it takes the balls to hit the ground. What are the students comparing? (1 point)
O the time it takes for each ball to fall
O the height from which each ball is dropped
O the gravitational attraction of each ball
O the mass of each ball
Answer:
the gravitational attraction of each ball, so technically the others too lol
which public health policies help prevent communical diseases
A car is traveling 20m/s around a right hand curve. The passenger is at a radius of 5m and the driver is at radius of 6m. What is the centripetal acceleration felt by each?
The exact centripetal acceleration experienced by passenger ∝ₙ and driver ∝ⁿ is 80m/s² & 66.67m/s² respectively.
Mathematically , Centripetal acceleration ∝= v²/r
In the given question velocity will be same for passengers and driver because of common frame.
But the radius is different since distance from each points of frame to the Centre of road will vary. so their centripetal acceleration will differ.
∝= v²/r using this we can find out the exact centripetal acceleration experienced by passenger ∝ₙ and driver ∝ⁿ
∝ₙ= 20²/5= 80m/s²
∝ⁿ=20²/6= 66.67m/s²
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A cylinder is rolling along the ground at 2m/s . It comes to a hill and starts going up.Assuming no losses to friction, how high does it get before it stops
The maximum height reached by the cylinder at the given initial velocity is 0.2 m.
What is the maximum height travelled by the cylinder?
The maximum height travelled by the cylinder is calculated by applying the following kinematic equation as shown below.
v² = u² - 2gh
where;
u is the initial velocity of the cylinderv is the final velocity of the cylinder at the maximum heighth is the maximum height travelled by the cylinderg is acceleration due to gravityAt maximum height, the final velocity of the cylinder = 0
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u²/2g
h = (2²) / (2 x 9.8)
h = 0.2 m
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Metals are great conductors because
the electrons in the atoms are tightly bound and unable to move between other atoms
the electrons are able to move freely between the different energy levels within the atom
their atoms can move freely between other atoms
their atoms are tightly bound in their shells, which makes them unable to move between other atoms
Metals are great conductors because the electrons are able to move freely between the different energy levels within the atom.
What are conductors?
A substance or material that has the capability of conducting electricity or allows the passage of electricity to flow through it is known as conductor or electric conductor. The electrical charge carriers i.e., electrons or ions move easily from one atom to another when a voltage is applied on it.
The outer bound electrons of the metals are loosely bound as the nucleus gets very less attracted on the electrons present on the outermost shell and because of this the charge carriers in them can move the current applied easily when there is a potential difference. Therefore, metals are considered to be the best conductors.
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A Car Starts from rest and accelerate at the rate of
5m/s' for 8 See It then travels at this speed for another lasse
fer which it was brought to rest in 4sec:
The maximum velocity attained by the car
the time taken to cover the first 18seconds
Calculate the average speed of the Car
When a car is at rest, it begins to accelerate at a pace of 8 Sec at 5 m/s It then continues moving at same speed for another lap after coming to rest in 4 seconds.
The maximum velocity attained by the car, the velocity would be 8m/s.
Initial velocity, u= 0m/s
Distance travelled in 8 sec would be
s= u ×t+ 1/2at²
= 1/2 ×5 ×(8)²
= 160m
Velocity after t= 4sec
= 2×4= 8m/s
What is average velocity?Average velocity is defined as the change in position or displacement (x) divided by the time intervals (t) during which the change occurs. Based on the direction of the displacement, the average velocity might either be positive or negative. The unit of measure for average velocity in the SI is meters per second (m/s or ms-1).
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The total energy of a system remains___.
Answer:
It remains Stationary
Explanation:
stationary.
A person with a weight of 190 N sits on a box with a weight of 20 N, what is the normal force on the box?
The normal force on the box is 210 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Normal force on the box = total Weight of box and person = 210 N.
The normal force on the box is 210 N.
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If a Mack truck and a Honda Civic have a head-on collision, which vehicle will experience the greater force of contact? The greater impulse? The greater change in momentum? The greater acceleration? Discuss how a failure to distinguish between these concepts leads to difficulties in understanding physics!
The Honda Civic is the car that would have greater impulse, momentum change and acceleration due to Collison.
What is the impact?The term impulse has to do with the product of force and time. The impact is literally the force that acts on an object for a short time. We know that the mass of the object is very important when we are discussing the impulse on the object.
When there is a head-on collision that occurs between the Mack truck and a Honda Civic, the Honda Civic would have the greater impulse and the greater change in momentum and thus the greater acceleration.
If we do not understand the concept of the effect of momentum and the acceleration of an object, we would not be able to understand the basic interaction that occur between objects using the principles of physics.
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Suppose a star has a luminosity of 6.0×1026 watts and an apparent brightness of 1.5×10−12 watt/m2 . How far away is it? Give your answer in both kilometers and light-years.
Use the inverse square law for light to answer each of the following question.
The distance of this star in kilometers is equal to 5.64 × 10¹⁸ kilometers. Also, the distance of this star in light-years is equal to 626.67 light-years.
How to calculate the distance of light?Mathematically, the inverse square law for light can be used for calculating its luminosity at a distance by using this mathematical expression:
d = √(L/4πF)
Where:
d represents the distance of light.L represents the luminosity of light.F represents the apparent brightness of light.Substituting the given parameters into the formula, we have;
Distance in kilometers, d = √(6.0 × 10²⁶/4 × 3.142 × 1.5 × 10⁻¹²)
Distance in kilometers, d = √(6.0 × 10²⁶/1.885 × 10⁻¹¹)
Distance in kilometers, d = √3.183 × 10³⁷
Distance in kilometers, d = 5.64 × 10¹⁸ kilometers.
For the distance in light-years, we would divide the distance in kilometers by 9.0 × 10⁻¹⁵:
Distance in light-years = 5.64 × 10¹⁸/9.0 × 10¹⁵
Distance in light-years = 626.67 light-years.
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A physicist steps on a piece of gum. The gum exerts a constant non conservative force of 3 newtons as she picks up her foot. If her foot is 1 kg how much force would she have to exert to accelerate her foot vertically at 6 m/s2?
A) 15 newtons
B) 18 newtons
C) 28 newtons
D) 22 newtons
E) 25 newtons
The Force exerted by the physicist as she steps on a piece of gum is 18 Newtons and the right option is B) 18 Newtons.
What is force?Force can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N) or kilogram- meter-per-seconds (kgm/s).
To calculate the amount of force she would exert, we use the formula below.
Formula:
F = F'+mg+ma............. Equation 1Where:
F = Amount of force she would exertF' = The gum's non conservative forcem = Mass of her foota = Accelerationg =Acceleration due to gravityFrom the question
Given:
F' = 3 Nm = 1 kga = 6 m/sg = 9 m/s²Substitute these values into equation 1
F = 3+(1×9)+(1×6)F = 3+9+6F = 18 NewtonsHence, the force exerted by the physicist is 18 N.
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Considering that W = AE, what force(s)
cause the Work to change the skiers KE, to
0 Joules?
Potential energy is lost as the skier starts to descend the hill, while kinetic energy, or the energy of motion, is gained. The skier increases her speed as she decreases height (and thereby potential energy) (and thus gains kinetic energy).
What elements influence kinetic energy?Mass and speed are the two main determinants of kinetic energy. Because an object's motion is influenced by its velocity as well as its mass, though mass is the more crucial factor.
You are working against inertia when you accelerate an object. The change in the object's kinetic energy is equal to that work. Starting with the common equation for work against inertia, it is possible to prove that the relationship exists.
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Astronauts in training are subjected to extreme acceleration forces by the centripental forces in againt centrifuge the radius of the centrifuge appriximately 5m calculate the approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s
The approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s is 3.94 KN
ac = v² / r
v = 2 π r / T
ac = Centripetal acceleration
v = Linear / Tangential velocity
T = Time period
r = Radius
r = 5 m
T = 2 s
v = 2 * 3.14 * 5 / 2
v = 15.7 m / s
ac = 15.7 * 15.7 / 5
ac = 49.298 m / s²
Fc = m ac
m = Mass
m = 80 kg
Fc = 80 * 49.298
Fc = 3943.8 N
Fc = 3.94 KN
Therefore, the approximate centripetal force on the astronaut is 3.94 KN
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How fast would the moon need to travel in order to escape the gravitational pull of Earth, if Earth has a mass of 5.98 x 10^24 kg and the distance from Earth to the moon is 3.84 x 10^8 m?
Answer: 14.41*10^2 m/s
Explanation:
let, V be the escape velocity of the moon.
M be the mass of the earth.
r be the distance between the moon and the earth.
G be the universal gravitational constant.
And G = 6.67428*10^-11 m^3kg^-1 s^-2
here, given in the question that
The earth has a mass of 5.98*10^24 kg.
so, M = 5.98*10^24 kg.
And the distance from the earth to the moon is 3.84*10^8 m.
so, r = 3.84*10^8 m.
now, we know,
V = √2GM/r
V = √(2 * 6.67428*10^-11* 5.98 * 10^24 )/ 3.84*10^8
V = √79.82*10^13/3.84*10^8
V = √20.78*10^5
V = 14.41*10^2 m/s
Why is it important for your measurements that the track is level for rolling motion in physics?
It is important for the measurements that the track is level for rolling motion in physics because the rolling objects only move on the tract that is leveled correctly.
What do you mean by rolling motion?The rolling motion is a fusion of translational motion and rotational motion. For a body, the motion of the center of mass is the adaptation motion of the body. During the rolling motion of a body, the exterior contact gets disfigured a little temporarily. A combination of translational and rotational motions happens during the rolling motion of an object. To define rolling motion, we must recognize the forces like angular momentum and torque. It is a merger of two types of motion i.e. translational and rotational motion. The translational motion of a body is the movement of the whole body from one place to another.
So we can conclude that Rolling motion is that usual combination of encircling and translational motion that we see everywhere and every day.
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In the remote version of the lab you completed this week’s students both their own ramps. One student made their room from a board game that was lifted 0.215m on one end. The length of the box is 0.400m. Starting from rest, they let a solid wall with a radius of 0.0535 m and a mass of 1.20 kg roll down the ramp without slipping.
Question: When the ball reaches the bottom of the homemade ramp what is its speed? SHOW WORKING OUT
The speed ball when it reaches the bottom of the homemade ramp is 1.68 m/s.
What is the speed of the ball at the bottom of the ramp?The speed of the ball at the bottom of the ramp is determined by applying the principle of conservation of energy as follows;
total kinetic energy = total potential energy
rotational kinetic energy + translational kinetic energy = total potential energy
¹/₂Iω² + ¹/₂mv² = mgh
where;
I is the moment of inertia of the ballv is the speed of the ballω is the angular speed of the ballm is mass of the ball¹/₂I(v/r)² + ¹/₂mv² = mgh
¹/₂Iv²/r² + ¹/₂mv² = mgh
I = ¹/₂mr²
¹/₂(¹/₂mr²)v²/r² + ¹/₂mv² = mgh
¹/₄mv² + ¹/₂mv² = mgh
¹/₄v² + ¹/₂v² = gh
v² + 2v² = 4gh
3v² = 4gh
v² = 4gh/3
v = √(4gh/3)
where;
h is the height g is accelerationv = √(4 x 9.8 x 0.215/3)
v = 1.68 m/s
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In a dentist’s x-ray machine, electrons may be subjected to a net force of 1X10-13 The mass of an electron is about 1X10-30 kg. What is the acceleration of the electrons? How long does it take the electrons to be accelerated from rest across a gap of 10 cm?
The net force on the electron is F = 1X10-13 N.
The mass of the electron is m = 1X10-30 kg.
The distance covered by an electron is S = 10 cm.
The acceleration of an electron can be calculated as:
F = ma
a = F/m
Substitute the values in the above expression.
[tex]a = (\frac{1 * 10^{-13}N }{1* 10^{-30kg} } ) \\[/tex]
a = [tex]1*[/tex][tex]10^{-17} m/s^{2}[/tex]
Thus. the acceleration of the electron is. [tex]a = 1*10^{-17} m/s^{2}[/tex]
The expression of time taken by the electron is given by,
S = ut + [tex]\frac{1}{2} at^{2}[/tex]
Here, u is the electron's initial velocity, whose value is zero because the electron is initially at rest.
Substitute the values in the above expression.
(10cm x 1m/100cm) = 0 x t + 1/2 x (1 x [tex]10^{17}[/tex] m/s²) x t²
(0.1m) x 2 = (1 x [tex]10^{17}[/tex] m/s²)x t²
[tex]t = \sqrt{\frac{0.2m}{(1*10^{17} m/s^{2} )} }[/tex]
t = 1.414 x [tex]10^{-9}[/tex]s
Thus, the time taken by the electrons to be accelerated from rest is t = 1.414 x [tex]10^{-9}[/tex]s
Electrons are accelerated from rest by a potential difference of V volts. The speed of individual electrons in metal wires is typically millions of kilometers per hour. In contrast, drift velocities are typically only a few meters per hour, while signal velocities are 100 million to 1 billion kilometers per hour.
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The number of protons, neutrons, and electrons determines all of the
_____ of that atom.
match each burn type with an appropriate treatment
Answer:
Burn symptoms vary depending on the severity or degree of the burn. Symptoms are often worse during the first few hours or days after the burn. Burn symptoms include:
Blisters.
Pain.
Swelling.
White or charred (black) skin.
Peeling skin.
Explanation:
How are burns managed or treated?
Burn treatment varies depending on the cause and severity. You need to keep all burns clean and apply proper bandages/dressing depending on the severity of the wounds. Treating the person’s pain is key: inadequate control can interfere with wound care.
Continue to check wounds for signs of infection and other long term issues, such as scarring and tightening of the skin over joints and muscles, which makes them difficult to move.
Treatments by burn type include:
First-degree burns: Run cool water over the burn. Don’t apply ice. For sunburns, apply aloe vera gel. For thermal burns, apply antibiotic cream and cover lightly with gauze. You can also take over-the-counter pain medication.
Second-degree burns: Treatment for second and first-degree burns is similar. Your healthcare provider may prescribe a stronger antibiotic cream that contains silver, such as silver sulfadiazine, to kill bacteria. Elevating the burned area can reduce pain and swelling.
Third-degree burns: Third-degree burns can be life-threatening and often require skin grafts. Skin grafts replace damaged tissue with healthy skin from another of uninjured part of the person’s body. The area where the skin graft is taken from generally heals on its own. If the person does not have enough skin available for graft at the time of injury, a temporary source of graft can come from a deceased donor or a human-made (artificial) source but these will eventually need to be replaced by the person’s own skin. Treatment also includes extra fluids (usually given intravenously, with an IV) to keep blood pressure steady and prevent shock and dehydration.
Third-degree burns that are deep and affect a large portion of the skin are very serious and can be life-threatening. Even first- and second-degree burns can become infected and cause discolouration and scarring. First-degree burns don’t cause scarring.
Potential complications of third-degree burns include:
Arrhythmia, or heart rhythm disturbances, is caused by an electrical burn.
Dehydration.
Disfiguring scars and contractures.
Oedema (excess fluid and swelling in tissues).
Organ failure.
Pneumonia.
Seriously low blood pressure (hypotension) may lead to shock.
Severe infection that may lead to amputation or sepsis.
Which of the following is an example of Newton's third law of motion?
A) Izzie's bicycle hits a curb and she falls forward onto the grass.
B) A tissue and a rock are dropped from a ladder. The rock exerts a greater force when it hits the ground.
C) Kyle sits at the base of a water slide, another person on the slide pushes him forward into the pool.
D) Tires from a bike push against the road, and the road pushes back.
Answer:
D
Explanation:
bike and road show equal and oppisite reaction