Answer: 270 chocolates
Step-by-step explanation:
Given the following :
Number of 5-year Olds = 5
Number of 6-year Olds = 5
Number of 7-year Olds = 5
Number of chocolates received by each child = 3 times as many chocolate as their age.
Number of chocolates received by 5-year Olds = 3 × 5 = 15 chocolates
Number of chocolates received by 6-year Olds = 3 × 6 = 18 chocolates
Number of chocolates received by 7-year Olds = 3 × 7 = 21 chocolates
Total Number of chocolates received by 5-year Olds = 5 * 15 = 75 chocolates
Total Number of chocolates received by 6-year Olds = 5 * 18 = 90 chocolates
Total Number of chocolates received by 7-year Olds = 5 * 21 = 105 chocolates
Totak number of chocolates altogether :
(75 + 90 + 105) = 270 chocolates
describe the end behavior f(x)=5x^4+3x^2-1.
Simplify.
N4 x N7 over n5
Answer:
[tex]n^6[/tex].
Step-by-step explanation:
[tex]n^4 * \frac{n^7}{n^5}[/tex]
= [tex]n^4 * n^{7 - 5}[/tex]
= [tex]n^4 * n^2[/tex]
= [tex]n^{4 + 2}[/tex]
= [tex]n^6[/tex].
Hope this helps!
Plzzzzz Help I really need help
A Line Segment has the points (1,-2), and (3,-2). What are the new points after its dilated by a scale factor of 3/2 or 1.5
Answer:
(1.5,-3) and (4.5,-3)
Step-by-step explanation:
Triangle ABC has vertices at A(2,5), B(4,11) and C(-1,6). Determine the angles in this triangle.
I need this solved using vectors please
Answer:
The angles are
∠A = 90°, ∠B = 26.56°, ∠C = 63.43°
Step-by-step explanation:
We have that the angles of a vector are given as follows;
[tex]cos\left ( \theta \right ) = \dfrac{\mathbf{a\cdot b}}{\left | \mathbf{a} \right |\left | \mathbf{b} \right |}[/tex]
Whereby the vertices are represented as
A= (2, 5, 0), B = (4, 11, 0), C = (-1, 6, 0),
AB =(4, 11, 0) - (2, 5, 0) = (2, 6, 0) , BA = (-2, -6, 0)
BC = (-1, 6, 0) - (4, 11, 0) = (-5, -5, 0), CB = (5, 5, 0)
AC = (-1, 6, 0) - (2, 5, 0) = (-3, 1, 0), CA = (3, -1, 0)
θ₁ = AB·AC
a·c = a₁c₁ + a₂c₂ + a₃c₃ = 2×(-3) + 6×1 = 0
Therefore, θ₁ = 90°
BA·BC = (-2)×(-5) + (-6)×(-5) = 40
[tex]{\left | \mathbf{}BA \right |\left | \mathbf{}BC \right |}[/tex] = (√((-2)² + (-6)²)) × (√((-5)² + (-5)²)) = 44.72
cos(θ₂) = 40/44.72 = 0.894
cos⁻¹(0.894) =θ₂= 26.56°
CA·CB = 5×3 + 5×(-1) = 10
[tex]{\left | \mathbf{}CA \right |\left | \mathbf{}CB \right |}[/tex] = (√((3)² + (-1)²)) × (√((5)² + (5)²)) = 22.36
10/22.36 = 0.447
cos(θ₃) = 0.447
θ₃ = cos⁻¹(0.447) = 63.43°.
9/10 of the weight of a loaf of bread comes from the flour used in its baking. 2/9 of the weight is the protein what fraction of the weight is protein?
Answer:
1/5
Step-by-step explanation:
2/9 * 9/10 = 2/10 = 1/5
Please help! "Create a real-life scenario involving an angle of elevation or depression. Draw an appropriate diagram and explain how to solve your example."
Answer:
Height of the kite = 86.60 meter (Approx)
Step-by-step explanation:
The angle of elevation to see a kite from a stone lying to the ground is 60 degrees. If a thread is tied with a kite and a stone, then that thread is 100 meters long, find the height of the kite.
Given:
Length of thread = 100 meter
Angle of elevation = 60°
Find:
Height of the kite.
Computation:
Using trigonometry application:
Height of the kite / Length of thread = Sin 60°
Height of the kite / 100 = √3 / 2
Height of the kite = [√3 / 2]100
Height of the kite = 50√3
Height of the kite = 86.60 meter (Approx)
In the figure, m∠CED = m∠A. Complete the following proportions: ED/ A F= CE/? = CD/?
Answer:
The completed proportions are;
ED/A_F = CE/CA = CF/CD
Step-by-step explanation:
The given m∠CED = m∠A
∴ Angle ∠CDE = Angle ∠A_FC, (corresponding angles)
Angle ∠ECD = Angle ∠ACF (reflexive property)
Triangle ΔDCE is similar to triangle ΔACF (Angle Angle Angle (AAA) similarity)
In triangle ΔDCE and triangle ΔACF
m∠A is bounded by CA and A_F
m∠CED is bounded by CE and ED
∠DCE is bounded by CE and DE
∠C is bounded by CA and CF
Based on the orientation of the two triangles, we have
ED is the corresponding side to A_F, CD is the corresponding side to CF, CE is the corresponding side to CA
Therefore, we have;
ED/A_F = CE/CA = CF/CD.
Write an equation for the line that is parallel to the given line and that passes through the given point. y=34x−9;(−8,−18)
Answer:
Step-by-step explanation:
eq. of line parallel to y=34x-9 is y=34 x+k
∵ it passes through (-8,-18)
∴-18=34×-8+k
k=-18+272
k=254
so reqd. eq. is y=34 x+272
Please give me the correct answer her please
Answer:
9.3 inStep-by-step explanation:
m∠UTV = 112° ⇒ m∠WTV = 180° - 112° = 68°
sin(68°) ≈ 0.9272
sin(∠WTV) = WV/TV
WV/10 ≈ 0.9272
WV ≈ 9.272
WV ≈ 9.3
A smaller number is 3 less than half a larger number. The larger number is 10 times 1 less than the smaller number. Let x represent the smaller number, and let y represent the larger number. Which equations can be used to model the situation? Check all that apply. x = one-half y minus 3 2 x minus y = negative 6 2 x minus y = negative 3 x = one-half (y minus 3) y = 10 (x minus 1)
Answer: x=one-half y minus
Step-by-step explanation:
Answer:
x=1/2 y-3
Step-by-step explanation:
The table below lists some of the characteristics of the houses on Katrina’s street. Characteristics of Homes For Sale on Katrina’s Street Bedrooms Acres of land Sale price Appraised value Property tax 2 0.17 $230,000 $200,000 $1,220 2 0.20 $210,000 $220,000 $1,232 3 0.20 $275,000 $250,000 $1,400 4 0.24 $275,000 $275,000 $1,540 4 0.52 $360,000 $310,000 $1,736 4 0.75 $350,000 $320,000 $1,792 5 1.23 $375,000 $350,000 $1,960 Which relationship describes a function?
Answer:
your welcome and hope this helps
The principal feature of the redesigned checks is a series of printed instructions that the company hopes will help merchants confirm a check’s authenticity, which includes reminders to watch the endorsement, compare signatures, and view the watermark while holding the check to the light.
(A) which includes reminders to watch the endorsement, compare signatures, and view
(B) which include reminders for watching the endorsement, to compare signatures and view
(C) by including reminders for watching the endorsement, comparing signatures, and viewing
(D) including reminders to watch the endorsement, comparing signatures and viewing
(E) including reminders to watch the endorsement, compare signatures, and view
Answer:
(E) including reminders to watch the endorsement, compare signatures, and view
Step-by-step explanation:
The principle features that will help the company to confirms checks authenticity. It include endorsements and compare the signatures with the designated signatories. If the signatures are matched correctly with the assigned signatories the check is hold in light to view the watermark on it.
find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)
Answer: [tex]4\sqrt{3}[/tex] .
Step-by-step explanation:
Distance formula : Distance between points (a,b) and (c,d) is given by :-
[tex]D=\sqrt{(d-b)^2+(b-a)^2}[/tex]
Distance between points [tex](-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3})[/tex].
[tex]D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}[/tex]
Hence, the correct option is [tex]4\sqrt{3}[/tex] .
HELP ME PLEASSSSEE On a winter morning, the temperature before sunrise was -10℉. The temperature then rose by 1℉ each hour for 7 hours before dropping by 2℉ each hour for 3 hours. What was the temperature, in degrees Fahrenheit, after 10 hours?
Answer:
3 degrees F
Step-by-step explanation:
if the temperature rose 1* for 7 hours, times 1 by 7. which is 7 and add to -10. which is -3. then, since the temperature rose by 2* for 3 hours, times 2 by 3 which is 6 and add to -3, which is 3.
i hope this helped?
1. A test-tube has a diameter of 3cm. How many turns would a piece of thread of length
90.42cm make round the test tube. (Taken= =).
(3marks)
So if we think of a test tube, it looks sort of like a cylinder. This means that its cross-section would be a circle. To find out how many turns a piece of thread would make around the test tube, we need to find the circumference of the test tube, then divide the length of the string by the circumference.
Step 1) Find the circumference
C = pi x diameter
C = 3.14 x 3
C = 9.42
Step 2) Divide the length of the string by the circumference
90.42 / 9.42 = 9.5987
The string would make approximately 9.60 turns around the test tube.
Hope this helps!! :)
A square and a regular heptagon are coplanar and share a common side $\overline{AD}$, as shown. What is the degree measure of exterior angle $BAC$? Express your answer as a common fraction.
Answer:
[tex]\angle BAC = 141\frac{3}{7} ^{\circ}[/tex]
Step-by-step explanation:
The interior angle of a regular heptagon = = 900/7° = 128.57°
Therefore, angle DAB = 128.57°
The interior angle of the square = 90°
Therefore, angle DAC = 90°
Therefore, we have
angle DAB+ angle DAC + angle BAC = 360° (sum of angles at a point (A))
Angle BAC = 360° - angle DAB - angle DAC = 360° - 900/7° - 90° = 990/7°
Angle BAC = 141.43°
Expressing 141.43° as a common fraction gives;
[tex]141.43 ^{\circ}= \dfrac{990}{7} ^{\circ}=141\frac{3}{7} ^{\circ}[/tex]
[tex]\angle BAC = 141\frac{3}{7} ^{\circ}[/tex]
The degree measure of exterior angle BAC is [tex]141\frac{3}{7}^\circ[/tex]
Given, A square and a regular heptagon are coplanar as shown in below figure attached.
We have find the exterior angle of BAC.
We know that, The formula that gives the interior angle measure for a regular polygon with any number of sides is,
[tex]\frac{180(n-2)}{n}[/tex] where n is the number of sides.
Since the heptagon has 7 no. of sides.
So regular heptagon's interior angle measures,
[tex]\frac{180(7-2)}{7}=128\frac{4}{7}[/tex]
Hence [tex]\angle A[/tex] will be[tex]128\frac{4}{7}[/tex] degrees.
We know that a square's interior angle is 90 degrees and a heptagon's interior angle is 128.57 degrees. We will subtract those from 360 degrees to find angle BAC.
[tex]\angle BAC = 360 - (\angle A + 90)\\[/tex]
[tex]\angle BAC = 360 - (128\frac{4}{7} + 90)\\\angle BAC=141\frac{3}{7} ^\circ[/tex]
Hence the degree measure of exterior angle BAC is [tex]141\frac{3}{7}^\circ[/tex].
For more details on Exterior angle follow the link:
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please help!!!!!!!!!!!
Answer:
The x value of the point 1/4 the distance from point C to point D is -0.25
Step-by-step explanation:
The given information are;
The location of point C = (1, 2)
The location of point D = (-4, -2)
The point 1/4 from point C to point D is the point 3/4 from point D to point C
Which gives;
The coordinate at point D + 3/4× The difference between the coordinates of point C and point D
Which is (-4 + 3/4×(1 - (-4), - 2 + 3/4×(2 - (-2))
Which gives;
(-4 + 3.75, -2 + 3) and (-0.25, 1)
The coordinates of the point 1/4 the distance from point C to point D is (-0.25, 1)
Therefore, the x value of the point 1/4 the distance from point C to point D = -0.25.
An annual salary is $45000. His tax free allowances total $13000. He has to pay a tax of 20% on his taxable income.
The tax payable is?
Answer:
6400
Step-by-step explanation:
Taxable amount=45000-13000=32000
tax=32000*20/100
=6400
10. Read the following word problem, then choose which linear equation models the problem.
The length of a rectangle is six feet more than twice the width. The rectangle’s perimeter is 84 feet. Find the width and length of the rectangle.
A. 2w + 6 + w = 84
B. 2(2w + 6) + 2w = 84
C. 2(2w +6) • (2w) = 84
D. (2w + 6) • (w) = 84
Answer:
D. ( 2w+6). (w)
i tried my best
hope this is the answer
stay at home stay safe
which equation represents the line that is perpendicular yo y=3/2x+1 and passes through (-12,6)
Answer:
y = -2/3x - 2
Step-by-step explanation:
Step 1: Find slope m of perpendicular line
Simply take the negative reciprocal of the given line
m = -2/3
y = -2/3x + b
Step 2: Find b
6 = -2/3(-12) + b
6 = 8 + b
b = -2
Step 3: Rewrite perpendicular equation
y = -2/3x - 2
(a) Complete the statements below about the graphs of y = -x and y=x.
Compared to the graph of y=x, the graph of y=-x is Choose one
Compared to the graph of y=x, the graph of y = -x intersects the y-axis at Choose one
2
(b) Complete the statements below about the graphs of y=x+
and y=x.
3
2
Compared to the graph of y = x, the graph of y=x+ 5 is Choose one
2
Compared to the graph of y=x, the graph of y=x+
3
intersects the y-axis at Chonse one
a higher point
the same point.
a lower point
Х
?
Answer:
this. question is not clear please send clear question
We can conclude that -
Graphs pass through the origin. (y = x) has a slope of +1 while (y = - x) has a slope of -1. The y - intercept of both the graphs will be 0.What is the general equation of a Straight line?The general equation of a straight line is -
[y] = [m]x + [c]
where -
[m] is slope of line which tells the unit rate of change of [y] with respect to [x].
[c] is the y - intercept i.e. the point where the graph cuts the [y] axis.
y = mx also represents direct proportionality. We can write [m] as -
m = y/x
OR
y₁/x₁ = y₂/x₂
We have the following two functions -
y = -x
AND
y = x
Refer to the graphs attached for both the functions -
y = - x and y = x
The graphs as seen pass through the origin. One graph (y = x) has a slope of +1 while the other one (y = - x) has a slope of -1. The y - intercept of both the graphs will be 0.
We can conclude that -
Graphs pass through the origin. (y = x) has a slope of +1 while (y = - x) has a slope of -1. The y - intercept of both the graphs will be 0.To solve more questions on straight line, visit the link below-
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n the diagram below, points $A,$ $E,$ and $F$ lie on the same line. If $ABCDE$ is a regular pentagon, and $\angle EFD=90^\circ$, then how many degrees are in the measure of $\angle FDE$?
[asy]
size(5.5cm);
pair cis(real magni, real argu) { return (magni*cos(argu*pi/180),magni*sin(argu*pi/180)); }
pair a=cis(1,144); pair b=cis(1,72); pair c=cis(1,0); pair d=cis(1,288); pair e=cis(1,216);
pair f=e-(0,2*sin(pi/5)*sin(pi/10));
dot(a); dot(b); dot(c); dot(d); dot(e); dot(f);
label("$A$",a,WNW);
label("$B$",b,ENE);
label("$C$",c,E);
label("$D$",d,ESE);
label("$E$",e,W);
label("$F$",f,WSW);
draw(d--f--a--b--c--d--e);
draw(f+(0,0.1)--f+(0.1,0.1)--f+(0.1,0));
[/asy]
Answer:
18
Step-by-step explanation:
Each interior angle of a regular pentagon is 108 degrees. So Angle AED is 108 degrees. Since Angle AEF is a straight line (180 degrees), Angle FED is 72. This is because 180-108 = 72. Now, since a triangle has a total of 180 degrees, we add 72 and 90, because those are the 2 degrees we have calculated. This gives us a total of 162. Now, we subtract 162 from 180 to find out the degree of Angle FDE. This is 18. So our final answer is 18.
Sidenote: I hope this answer helps!
The properties of a pentagon and the given right triangle formed by
segments EF and FD give the measure of ∠FDE.
Response:
∠FDE = 18°Which properties of a pentagon can be used to find ∠FDE?The given parameters are;
A, E, F are points on the same line.
ABCDE is a regular pentagon
∠EFD = 90°
Required:
The measure of ∠FDE
Solution:
The points A and E are adjacent points in the pentagon, ABCDE
Therefore;
line AEF is an extension of line side AE to F
Which gives;
∠DEF is an exterior angle of the regular pentagon = [tex]\frac{360 ^{\circ}}{5}[/tex] = 72°∠EFD = 90°, therefore, ΔEFD is a right triangle, from which we have;
The sum of the acute angles of a right triangle = 90°
Therefore;
∠DEF + ∠FDE = 90°
Which gives;
72° + ∠FDE = 90°
∠FDE = 90° - 72° = 18°
∠FDE = 18°
Learn more about the properties of a pentagon here:
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Jane exchanged £100 for 216 Swiss francs. After buying a meal and a present to take home,she had 70 francs left.How much is this in £?
Answer:
£32.4
Step-by-step explanation:
£100 = 216 Swiss francs
x = 70 francs
70 x 100=7000/216=32.4
Maya is interning at a law firm over the summer and is paid by the hour. If her hourly wage is $52, which equation represents the proportional relationship between the wages she earns (w) and the number of hours (h)?
Answer: w= 52h
Step-by-step explanation:
Given: Maya is interning at a law firm over the summer and is paid by the hour.
Her hourly pay = $52
i.e. She is paid $52 per hour.
Let the wages she earns is denoted by 'w' and the number of hours is denoted by 'h'.
Now, (Total wages earned) = (hourly pay) x (Number of hours)
w = (52) (h)
⇒ w= 52h
Hence, the equation represents the proportional relationship between the wages she earns (w) and the number of hours (h): w= 52h
Answer:52h
Step-by-step explanation: tried got it right
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minus 9 x EndFraction minus StartFraction x + 1 Over x squared minus 9 EndFraction StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction StartFraction (x + 5) (x + 4) Over x cubed minus 9 x EndFraction StartFraction negative 2 x + 11 Over x cubed minus 12 x minus 9 EndFraction StartFraction 3 (x + 2) Over x squared minus 3 x EndFraction
Answer:
[tex] \frac{(x + 5)(x + 2)}{ {x}^{3} - 9x } [/tex]First option is the correct option.
Step-by-step explanation:
[tex] \frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 } [/tex]
Factor out X from the expression
[tex] \frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9} [/tex]
Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] , factor the expression
[tex] \frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)} [/tex]
Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )
[tex] \frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)} [/tex]
Multiply the parentheses
[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)} [/tex]
When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression
[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)} [/tex]
Distribute -x through the parentheses
[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x }{x(x - 3)(x + 3)} [/tex]
Using [tex] {a}^{2} - {b}^{2} = (a + b)(a - b)[/tex] , simplify the product
[tex] \frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)} [/tex]
Collect like terms
[tex] \frac{ {x}^{2} + 7x + 15 - 5}{x( {x}^{2} - 9)} [/tex]
Subtract the numbers
[tex] \frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)} [/tex]
Distribute x through the parentheses
[tex] \frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x} [/tex]
Write 7x as a sum
[tex] \frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x } [/tex]
Factor out X from the expression
[tex] \frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x} [/tex]
Factor out 2 from the expression
[tex] \frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x } [/tex]
Factor out x + 5 from the expression
[tex] \frac{(x + 5)(x + 2)}{ {x}^{3} - 9x } [/tex]
Hope this helps...
Best regards!!
The difference of the expression [tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex] is [tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]
The expression is given as:
[tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex]
Factorize the denominators
[tex]\frac{2x + 5}{x(x -3)} - \frac{3x + 5}{x(x^2 - 9)} - \frac{x + 1}{x^2 - 9}[/tex]
Apply the difference of two squares to the denominators
[tex]\frac{2x + 5}{x(x -3)} - \frac{3x + 5}{x(x - 3)(x + 3)} - \frac{x + 1}{(x - 3)(x + 3)}[/tex]
Take LCM
[tex]\frac{(2x + 5)(x + 3) - 3x - 5 -x(x + 1) }{x(x - 3)(x + 3)}[/tex]
Expand the numerator
[tex]\frac{2x^2 +6x + 5x + 15 - 3x - 5 -x^2 - x }{x(x - 3)(x + 3)}[/tex]
Collect like terms
[tex]\frac{2x^2 -x^2 - x +6x + 5x - 3x+ 15 - 5 }{x(x - 3)(x + 3)}[/tex]
Simplify
[tex]\frac{x^2+7x+ 10 }{x(x - 3)(x + 3)}[/tex]
Factorize the numerator
[tex]\frac{(x+5)(x+ 2) }{x(x - 3)(x + 3)}[/tex]
Expand the denominator
[tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]
Hence, the difference of the expression [tex]\frac{2x + 5}{x^2 -3x} - \frac{3x + 5}{x^3 - 9x} - \frac{x + 1}{x^2 - 9}[/tex] is [tex]\frac{(x+5)(x+ 2) }{x^3- 9x}[/tex]
Read more about equivalent expressions at:
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What is m∠A? please help
Answer: 50 degrees
Step-by-step explanation:
180-85=95
180-145=35
interior angle sum for a triangle is 180 degrees, so 180=95+35+a
m of angle A is 50 degrees
You are testing the claim that the mean GPA of night students is greater than the mean GPA of day students. You sample 30 night students, and the sample mean GPA is 2.36 with a standard deviation of 0.96 You sample 60 day students, and the sample mean GPA is 2.19 with a standard deviation of 0.66 Calculate the test statistic, rounded to 2 decimal places
Answer:
Z = 0.87
Explanation:
Given the following data;
Sample 1:
n1 = 30
Mean, X = 2.36
Standard deviation, Ox = 0.96
Sample 2:
n2 = 60
Mean, Y = 2.19
Standard deviation, Oy = 0.66
The formula for test statistics for two population is;
[tex]Z = \frac{X-Y}{\sqrt{(\frac{Ox^2} {n_1} } +\frac{Oy^2}{n_2} )}}[/tex]
Substituting the values, we have;
[tex]Z = \frac{2.36-2.19}{\sqrt{(\frac{0.96^2} {30} +\frac{0.66^2}{60} )}}[/tex]
[tex]Z = \frac{0.17}{\sqrt{(\frac{0.9216} {30} +\frac{0.4356}{60} )}}[/tex]
[tex]Z = \frac{0.17}{\sqrt{(0.03072 +0.00726)}}[/tex]
[tex]Z = \frac{0.17}{\sqrt{0.03798}}[/tex]
[tex]Z = \frac{0.17}{0.19488}[/tex]
Z = 0.8723
The test statistics to 2 d.p is 0.87
Therefore, Z = 0.87
Pls solve ASAP!! Review the attachment and solve. Pls hurry!
Answer:
A. 3
Step-by-step explanation:
ΔDEC is bigger than ΔABC by 5. For the hypotenuse, 25 is 5 times bigger than 5.
So, side DE on ΔDEC has to be 5 times bigger than side AB on ΔABC.
If side AB equals 3, side DE equals 18 - 3, which is 15.
15 is five times bigger than 3, so the answer is A. 3.
Hope that helps.
Which equation represents a line that is perpendicular to line FG? A. y=-1/2x+5 B. y=1/2x+2 C. y=-2x-3 D. y=2x-6
The equation of line which is perpendicular to the line FG is
y = -2x -3.
What is equation of line?
The equation of line is an algebraic form of representing the set of points, which together form a line in a coordinate system.
Formula for finding the equation of line from two points [tex](x_{1} ,y_{1} ) and (x_{2}, y_{2} )[/tex][tex](y -y_{1}) = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } (x-x_{1} )[/tex]
What is the slope of two perpendicular lines?If [tex]m_{1}[/tex] be the slope of one line, then the slope of the perpendicular line is [tex]\frac{-1}{m_{1} }[/tex].
What is the slope intercept form of a line ?The slope intercept form of the line is given by y = mx + b
Where, m is the slope of a line.
According to the given question
We have a line FG and the coordinates of points F and G are (-5,1) and (9,8) respectively.
Therefore, the slope of the line FG = [tex]\frac{8-1}{9+5}=\frac{7}{14} =\frac{1}{2}[/tex]
⇒ The slope of the line which is parallel to line FG is -2
Now, from the given option of the equation of line , y = -2x -3 has a slope of -2 .
Hence, the equation of line which is perpendicular to the line FG is
y = -2x -3.
Learn more about the equation of a perpendicular line here:
https://brainly.com/question/20712656
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I need help!
- 7(x + 2) = 21
Answer:
x = -5
Step-by-step explanation:
-7(x + 2) = 21
Divide each side by -7
-7/-7(x + 2) = 21/-7
x+2 = -3
Subtract 2 from each side
x+2-2 = -3-2
x = -5
Answer:
x = -5
Step-by-step explanation:
distribute: -7x-14 = 21
add 14 to both sides
divide by -7
x = -5