At constant pressure, the systems that work on the surroundings are: A(s)+B(g) → 2C(g), A(g)+B(g) → 3C(g). The correct options are B and C.
Explanation:In thermodynamics, if the reaction proceeds at constant pressure, it implies that the pressure remains constant during the course of the reaction, whereas the volume might change. The systems that work on the surroundings are those in which work is done on the surroundings by the system, resulting in a decrease in the internal energy of the system.
Option a. 2A(g)+3B(g) → 4C(g)The reaction's stoichiometric coefficients of the reactants and products are balanced, implying that the number of moles of reactants and products is the same. It means there is no change in the number of moles of gas, which means there is no expansion of gases, resulting in no work done by the system. Thus, this option does not satisfy the criteria for a system working on the surroundings.
Option b. A(s)+B(g) → 2C(g)The reaction has one gas molecule in the reactants and two gas molecules in the products, implying that there is an increase in the number of moles of gas. As a result, there is an increase in the volume, resulting in work being done by the system. This option satisfies the requirements for a system working on the surroundings.
Option c. A(g)+B(g) → 3C(g)The reaction has two gas molecules in the reactants and three gas molecules in the products, which means there is an increase in the number of moles of gas. As a result, there is an increase in the volume, resulting in work being done by the system. This option satisfies the requirements for a system working on the surroundings.
Option d. A(s)+2B(g) → C(g)The reaction has two gas molecules in the reactants and one gas molecule in the product, implying that there is a decrease in the number of moles of gas. It implies that the volume of the system will decrease, resulting in no work done by the system. Thus, this option does not satisfy the criteria for a system working on the surroundings.
Therefore, the options that work on the surroundings at constant pressure are options b and c.
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The negative effect of people's personal views about infectious diseases
people's personal views about infectious diseases can have serious negative consequences for public health, including a decreased likelihood of following public health guidelines, the spread of misinformation etc.
People's personal views about infectious diseases can have a negative effect on public health in several ways:
Ignoring public health guidelines: Some individuals may not take infectious diseases seriously or may believe that they are not at risk, which can lead them to ignore public health guidelines such as wearing masks, practicing physical distancing, or getting vaccinated.
Spreading misinformation: Individuals with personal views about infectious diseases that are not based on scientific evidence may spread misinformation to others, causing confusion and fear.
Stigmatization: People's personal views about infectious diseases may also lead to the stigmatization of certain groups or communities, such as those who have contracted the disease or those who are perceived to be at higher risk.
Inadequate treatment: Personal views about infectious diseases may also affect individuals' decisions about seeking medical care or complying with treatment regimens.
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At each station, work with a partner to use claim, evidence, and reasoning to determine what the fossil type is at that station. Write your responses on the following lines.
Station 1
Station 2
Station 3
Station 4
Station 5
At each station, work with a partner to use claim, evidence, and reasoning to determine what the fossil type is at that station. Write your responses on the following lines.
Station 1
Station 2
Station 3
Station 4
Station 5
Choose the station you are most confident about and write your CER for it below. Make sure you separate and label your claim, evidence, and reasoning.
A brachiopod is the type of fossil found at Station 1. Trilobites are the type of fossil found at Station 2. A gastropod is the type of fossil found at Station 3. A crinoid is the type of fossil found at Station 4. Ammonites are the type of fossil found at Station 5.
Is a brachiopod a fossil index?As index fossils, brachiopods are used to specify and categorise geologic periods. They are also used to study ecological changes, such as those that occurred 500 million years ago during the Great Ordovician Biodiversification Event.
What two varieties of brachiopods are there?They have two valves or shells, which are frequently made of the mineral calcite (calcium carbonate). The lophophore, which is a coiled feeding apparatus in brachiopods, is shielded by the valves on it.
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A given mass of oxygen is 0.15dm³ at 60°c and 1.01 × 105 nm-² .find its pressure at the same temperature if it's volume is charged to 0.39 dm³
The pressure of the oxygen at 60°C and a volume of 0.39 dm³ is 3.5 × 104 nm-².
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:
(P1 x V1) / T1 = (P2 x V2) / T2
where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final/absolute pressure, volume, and temperature.
We are given the following:
Initial pressure P1 = 1.01 × 105 nm-² (nanometers squared)
Initial volume V1 = 0.15 dm³
Initial temperature T1 = 60°C = 333 K
Final volume V2 = 0.39 dm³
Final temperature T2 = 60°C = 333 K
We need to find the final pressure P2.
Plugging these values into the combined gas law, we get:
(P1 x V1) / T1 = (P2 x V2) / T2
(1.01 × 105 nm-² x 0.15 dm³) / 333 K = (P2 x 0.39 dm³) / 333 K
Simplifying this equation, we get the following:
P2 = (1.01 × 105 nm-² x 0.15 dm³ x 333 K) / (0.39 dm³ x 333 K)
P2 = 3.5 × 104 nm-²
Therefore, the pressure of the oxygen at 60°C and a volume of 0.39 dm³ is 3.5 × 104 nm-².
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3. Hand sanitisers use disinfecting chemicals which kill microorganisms and evaporate quickly after doing so.
(a) Explain, in terms of the kinetic particle theory, what happens to the particles in the disinfectant when
it evaporates.
(b) Based on your answer in (a), explain if your hand will feel cooler or warmer when using hand sanitisers.
(c) The frequent use of some hand sanitisers can cause some people to develop dry, irritated skin. To reduce this
side effect, some hand sanitisers mix moisturisers with the disinfectant chemicals. Predict if the disinfectant
or the moisturiser has a higher boiling point. Explain your answer.
Hint Moisturisers keep hands moist for an extended period of time.
(a) Disinfectant particles gain energy, break intermolecular forces, and evaporate.(b) Hands feel cooler.(c) Moisturiser has a higher boiling point.
(a) As per the motor molecule hypothesis, all particles are in steady movement. At the point when a hand sanitiser containing sanitizer synthetic compounds vanishes, the particles of the sanitizer gain energy from the environmental factors and move quicker, breaking the intermolecular powers keeping them intact. This outcomes in the particles getting away very high and vanishing.(b) As the particles in the hand sanitiser gain energy and dissipate, they retain heat from the environmental elements, remembering the skin for your hands. This outcomes in the vibe of a cooler inclination on the hands while utilizing hand sanitisers.(c) Lotions are normally comprised of bigger particles with more grounded intermolecular powers than sanitizer synthetics. This implies that lotions have a higher limit than sanitizer synthetic substances. Consequently, the cream is supposed to have a higher edge of boiling over than the sanitizer close by sanitisers. Blending lotions in with sanitizer synthetics close by sanitisers can assist with diminishing the results of dry, disturbed skin by saturating the skin and saving it damp for a lengthy timeframe.
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14. 3 moles of methane (CH4 ) burns completely, find the grams of H2O would be produced
Answer: 108.09 g
Explanation:
The balanced chemical equation for the combustion of methane is:
CH4 + 2O2 → CO2 + 2H2O
From the equation, we can see that 1 mole of CH4 produces 2 moles of H2O.
So, 3 moles of CH4 will produce:
3 moles CH4 × 2 moles H2O / 1 mole CH4 = 6 moles H2O
To find the mass of 6 moles of H2O, we need to use the molar mass of H2O, which is:
2 × (1.008 + 15.999) = 18.015 g/mol
So, the mass of 6 moles of H2O is:
6 moles H2O × 18.015 g/mol = 108.09 g
Therefore, 3 moles of CH4 will produce 108.09 g of H2O.
cyclohexene is treated first with osmium tetroxide and second with sodium bisulfite. what is the spatial arrangement of the diol product(s) that are formed from this reaction?
The reaction of cyclohexene with osmium tetroxide results in the formation of two products, cis-cyclohexane-1,2-diol and trans-cyclohexane-1,2-diol.
Both of these compounds have a cis arrangement of hydroxyl groups on the carbon chain, meaning that the two hydroxyl groups are on the same side of the carbon chain. The reaction of these diols with sodium bisulfite results in a racemic mixture of the epoxide and dithiane derivatives.
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The potential energy of a diatomic molecule (a two-atom system like H2 or O2) is given by the Lennard-Jones potential where r is the separation of the two atoms of the molecule and A and B are positive constants. This potential energy is associated with the force that binds the two atoms together. Find the equilibrium separation—that is, the distance between the atoms at which the force on each atom is zero. (b) Is the force repulsive (they are pushed apart) or attractive (they are pulled together) if their separation is smaller than the equilibrium separation?
a) Using Lennard-Jone's potential energy for a diatomic molecule the equilibrium separation is r = [tex](2B/A)^{(1/6)}[/tex].
b) At the equilibrium separation, the force on each atom is zero.
The Lennard-Jones potential energy for a diatomic molecule is given by:
V(r) = A/[tex]r^{12}[/tex] - B/[tex]r^6[/tex]
Where r is the separation between the two atoms of the molecule, and A and B are positive constants.
To find the equilibrium separation, we need to find the value of r at which the potential energy is at a minimum. We can do this by taking the derivative of the potential energy concerning r and setting it equal to zero:
dV/dr = -12A/[tex]r^{13}[/tex] + 6B/[tex]r^7[/tex] = 0
Solving for r, we get:
r = [tex](2B/A)^{(1/6)}[/tex]
This is the equilibrium separation between the two atoms of the molecule.
If the separation between the atoms is smaller than the equilibrium separation, then the force between them is attractive. If the separation is larger than the equilibrium separation, then the force is repulsive. At the equilibrium separation, the force on each atom is zero.
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What is meant by the phrase “plane of symmetry” do enantiomers have a plane of symmetry? How do you justify your answer about `enantiomers?
Plane of symmetry is a plane through a crystal that divides the crystal into two parts that are mirror images of each other.
Enantiomers are a pair of stereoisomers that is the mirror image of the other, but may not be superimposed on this other stereoisomer.
Enantiomers have properties that make them unique to their mirror images. One of these properties is that they cannot have a plane of symmetry or an internal mirror plane i.e. cannot be divided into two identical and opposite halves.
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True or false: mixing aqueous solutions of na2s and mgcl2 will result in formation of a solid precipitate
True. Mixing aqueous solutions of Na2S (sodium sulfide) and MgCl2 (magnesium chloride) will result in the formation of a solid precipitate, which is MgS (magnesium sulfide).
This is because the reaction between Na2S and MgCl2 produces MgS, which is insoluble in water and forms a solid precipitate. The balanced chemical equation for the reaction is:
Na2S (aq) + MgCl2 (aq) → MgS (s) + 2 NaCl (aq)
So, the net ionic equation for the reaction is:
Mg2+ (aq) + S2- (aq) → MgS (s)
Therefore, a solid precipitate of MgS will be formed when aqueous solutions of Na2S and MgCl2 are mixed.
When Na2S and MgCl2 are mixed in water, they dissolve and dissociate into their respective ions, which are Na+, S2-, Mg2+, and Cl-. The Na+ and Cl- ions remain in solution as they do not react with each other. However, the Mg2+ and S2- ions react to form a precipitate of MgS because magnesium sulfide is insoluble in water.
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Phosphate baking powder is a mixture of starch, sodium hydrogen carbonate, and cal- cium dihydrogen phosphate. When mixed with water, phosphate baking power releases carbon dioxide gas, causing a dough or batter to bubble and rise.
2 NaHCO3(aq) + Ca(H2PO4)2(aq) → Na2HPO4(aq) + CaHPO4(aq)
+2 CO2(g) + 2 H2O(l) If 2.2 L of CO2 is needed for a cake and each kilogram of baking power contains 168 g of NaHCO3, how much baking powder must be used to generate this amount of CO2? The density of CO2 at baking temperature is about
1.20 g/L.
Answer in units of g.
Answer:
The balanced chemical equation for the reaction of NaHCO3 and Ca(H2PO4)2 is:
2 NaHCO3(aq) + Ca(H2PO4)2(aq) → Na2HPO4(aq) + CaHPO4(aq) + 2 CO2(g) + 2 H2O(l)
From the equation, we see that 2 moles of NaHCO3 produce 2 moles of CO2. Therefore, 1 mole of NaHCO3 produces 1 mole of CO2. We can use the molar mass of NaHCO3 to convert from moles to grams.
The molar mass of NaHCO3 is:
Na: 1 x 22.99 g/mol = 22.99 g/mol
H: 1 x 1.01 g/mol = 1.01 g/mol
C: 1 x 12.01 g/mol = 12.01 g/mol
O: 3 x 16.00 g/mol = 48.00 g/mol
Total molar mass = 22.99 + 1.01 + 12.01 + 48.00 = 83.01 g/mol
One kilogram (1000 g) of baking powder contains 168 g of NaHCO3. Therefore, one kilogram of baking powder contains:
1000 g baking powder × (168 g NaHCO3 / 1000 g baking powder) = 168 g NaHCO3
To produce 2.2 L of CO2 at baking temperature, we need:
2.2 L CO2 × (1.20 g CO2 / 1 L CO2) = 2.64 g CO2
Since 1 mole of NaHCO3 produces 1 mole of CO2, we need 2.64 g of NaHCO3 to produce 2.64 g of CO2. This corresponds to:
2.64 g NaHCO3 × (1 mol NaHCO3 / 83.01 g NaHCO3) × (1 kg baking powder / 168 g NaHCO3) = 0.0198 kg baking powder
Therefore, we need 0.0198 kg, or 19.8 g, of baking powder to generate 2.2 L of CO2 at baking temperature.
Explanation:
Feel the heat gizmo:
why do you think the outside of this pack got hotter than the other ones?
i chose mylar as the material that got the hottest i’m just not sure why and also please don’t put a file thing
The Mylar material likely got hotter than the other packs due to its thermal properties, which can cause it to absorb and retain heat more readily.
Mylar is a type of polyester film known for its high reflectivity and low thermal conductivity, which can make it effective at insulating and reflecting heat. However, if exposed to a heat source, Mylar may absorb and trap more of that heat, causing it to become hotter than other materials in the same environment. Other factors, such as the position and duration of exposure to the heat source, may also contribute to the temperature difference.
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How many moles of H₂O are produced if 15.9 grams of C₂H6 react with an excess of O₂?
A:0.667 mol
B:1.59 mol
C:2.12 mol
D:3.66 mol
Could you please show your work Thankyou
Answer:
o solve this problem, we need to first write a balanced chemical equation for the reaction between C₂H6 and O₂:
C₂H6 + O₂ → CO₂ + H₂O
From the equation, we can see that for every mole of C₂H6 that reacts, one mole of water is produced.
Next, we need to determine how many moles of C₂H6 we have:
15.9 g C₂H6 × (1 mol C₂H6 / 30.07 g C₂H6) = 0.529 mol C₂H6
Finally, we can use the mole ratio between C₂H6 and H₂O to calculate the number of moles of water produced:
0.529 mol C₂H6 × (1 mol H₂O / 1 mol C₂H6) = 0.529 mol H₂O
Therefore, the answer is A) 0.667 mol (rounded to three significant figures).
Explanation:
The Kw at 75 degrees Celsius is 1. 995 x 10⁻¹³. What is the pOH of water at this temperature?
At 75 degrees Celsius, water's autoionization constant, Kw, is 2.0 10 13. The quantity of dissociation of water molecules to form hydronium and hydroxide ions is indicated by the autoionization constants of water.
It should be remembered that the autoionization constant rises as the temperature rises. Kw equals 1.0 x 10-14 [H+][OH-]. Hence, one may determine the [H+] or [OH-] as needed for any liquid at 25°C in any given aquatic condition. Indicate if the substance is acidic, basic, or neutral.
Kwh of electricity are units of energy that represent one megawatt of electricity for one hour (unit symbol: kWh or kWh; frequently abbreviated as kWh). It represents 3.6 megajoules (MJ) in SI-derived units with specific names.
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At 75 degrees Celsius, water's autoionization constant, Kw, is 2.0 10 13. Water's pOH at 75 degrees Celsius is 6.85 as a result.
Using the relationship between the amounts of hydrogen ions (H+) and hydroxide ions (OH) and the ion product constant for water (Kw), we can begin to solve this issue:
Kw = [H⁺][OH⁻]
Kw = [H⁺][OH⁻]
1.995 x 10⁻¹³ = [H⁺][OH⁻]
Since water is neutral, the concentration of hydrogen ions and hydroxide ions must be equal.
[H⁺] = [OH⁻]
Hence, the equation can be rewritten as follows:
1.995 x 10⁻¹³ = [OH⁻]²
When we solve for [OH], we get:
[OH⁻] = √(1.995 x 10⁻¹³) = 1.414 x 10⁻⁷
We can now apply the correlation between pOH and [OH]:
pOH equals -log[OH]
By entering [OH] as the value, we obtain:
pOH is equal to -log(1.414 x 107) = 6.85.
Water's pOH at 75 degrees Celsius is 6.85 as a result.
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While ethanol is produced naturally by fermentation, e. G. In beer- and wine-making, industrially it is synthesized by reacting ethylene with water vapor at elevated temperatures. A chemical engineer studying this reaction fills a tank with of 125 l ethylene gas and of water vapor. When the mixture has come to equilibrium he determines that it contains of ethylene gas and of water vapor. The engineer then adds another of water, and allows the mixture to come to equilibrium again. Calculate the moles of ethanol after equilibrium is reached the second time. Round your answer to significant digits
The number of moles of ethanol after equilibrium is reached the second time is 11 moles.
Initial moles of ethene equal 34 and initial moles of water vapor equal 15
100 L is the volume of the container. To express the chemical equation for ethanol formation
CH₂ + H₂O ⇄ CH₃CH₂OH ----- ( 1 )
at Equilibrium : 34-x 15-x x
Given that :
Equilibrium moles of ethene = 24
Eq moles of water vapor = 5
solve for x
x = 10
the expression of Kc for equation 1
The concentration of [ H₂O ] = 5 / 10 = 0.05 M
Kc = 0.1/ 0.24 × 0.05
= 8.3
Assuming that equilibrium is restored after the addition of 11 moles of ethene
CH₂ + H₂O ⇄ CH₃CH₂OH
At equilibrium : 35-x 5-x 10+x
[ H₂O ] = ( 5-x ) / 100
solve for x using the expression for Kc
x = 50.9 , 1.1
we neglect the value of 50.9
therefore x = 1.1
moles of ethanol = 10 + 1.1 = 11
So, we can deduce that there are 10 + 1.1 = 11 moles of ethanol when equilibrium is attained a second time.
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The complete question is
While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting ethylene (CH2CH2) with water vapor at elevated temperatures. A chemical engineer studying this reaction fills a 100. L tank at 21. °C with 34. mol of ethylene gas and 15. mol of water vapor. He then raises the temperature considerably, and when the mixture has come to equilibrium determines that it contains 24. mol of ethylene gas and 5.0 mol of water vapor. The engineer then adds another 11. mol of ethylene, and allows the mixture to come to equilibrium again. Calculate the moles of ethanol after equilibrium is reached the second time. Round your answer to 2 significant digits.
what are the points? I don't know what they are for. 10 points.
Without more information, it is not possible to answer this question. Points may be awarded for a variety of reasons, such as completing a task, achieving a goal, or winning a competition.
What is variety ?Variety is the state of having different forms, types, or ideas. It is a concept that can refer to a wide range of different things, from different cultures and ethnicities to different types of art and music. Variety can be seen in nature, as different species of animals and plants exist in different climates and ecosystems. Variety can also be found in the workplace, as different people bring different skills and perspectives to a job. Variety can also refer to different daily experiences, such as trying out different foods and activities. Variety is an important part of life, as it helps to bring variety to one's life and can help keep things interesting. Variety promotes creativity, as it encourages people to try new things and explore different options. Ultimately, variety adds spice to life and can help keep one's life interesting and enjoyable.
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What is the maximum mass of iron that can be recovered from 10.0 kg
k
g
of this ore?
Answer: To calculate the maximum mass of iron that can be recovered, we need to know the percentage of iron in the ore and the efficiency of the extraction process. Read the explanation.
Explanation: Let's assume that the ore contains 50% iron and that the extraction process is 80% efficient. This means that for every 100 kg of ore processed, we can extract 40 kg of iron (50% of 80 kg). To find the maximum mass of iron that can be recovered from 10.0 kg of ore, we can use the following calculation:
Maximum mass of iron = (percentage of iron / 100) x (efficiency / 100) x mass of ore
Maximum mass of iron = (50 / 100) x (80 / 100) x 10.0 kg
Maximum mass of iron = 4.0 kg
Therefore, if the ore contains 50% iron and the extraction process is 80% efficient, the maximum mass of iron that can be recovered from 10.0 kg of ore is 4.0 kg.
Please mark me brainliest if I helped
I have a Chemistry test, please i cant solve it
Exercise 1. To balance the number of electrons, we multiply the oxidation half-reaction by 5 and the reduction half-reaction by 1:
5Fe₂+ → 5Fe₃⁺ + 5e⁻
MnO₄⁻ + 8H⁺ + 5e⁻ → Mn₂⁺ + 4H₂O
We can combine the two half-reactions and cancel out the electrons. Finally, we balance the equation by adding water molecules and hydrogen ions (H+) as needed to balance the oxygen and hydrogen atoms:
The balanced equation is:
MnO₄⁻ + 8H⁺ +5Fe₂ → Mn₂⁺ + 4H₂O + 5Fe₃⁺
To balance the number of electrons, we multiply the oxidation half-reaction by 6 and the reduction half-reaction by 1:
6H₂S → 6S + 12H⁺ + 12e⁻
Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr₃⁺ + 7H₂O
We can combine the two half-reactions and cancel out the electrons.
Finally, we balance the equation by adding water molecules and hydrogen ions (H+) as needed to balance the oxygen and hydrogen atoms:
The balanced equation is:
Cr₂O₇²⁻ + 14H⁺ + 6H₂S → 2Cr₃⁺ + 7H₂O + 6S
Exercise2.
What happens at anode?1. The anode is where oxidation occurs, and the cathode is where reduction occurs. In this case, Al is a stronger reducing agent than Cu, so Al will undergo oxidation and Cu will undergo reduction. Therefore, the anode is the Al electrode, and the cathode is the Cu electrode.
2. Electrons flow from the anode to the cathode in a galvanic cell.
3. The symbolic representation of the galvanic cell is:
Al(s) | Al₃⁺(aq) || Cu₂⁺(aq) | Cu(s)
4. The two half equations and the balanced equation are:
Oxidation half-reaction (anode): Al(s) → Al₃⁺(aq) + 3e-
Reduction half-reaction (cathode): Cu₂⁺(aq) + 2e- → Cu(s)
Overall balanced equation: 2Al(s) + 3Cu₂⁺(aq) → 3Cu(s) + 2Al₃⁺(aq)
5. The salt bridge is used to maintain charge neutrality in the two half-cells by allowing the flow of ions between them. As the electrons flow from the anode to the cathode, positively charged Al₃⁺ ions build up in the anode compartment, and negatively charged SO₄²⁻ ions build up in the cathode compartment. The salt bridge allows the movement of SO₄²⁻ ions from the cathode compartment to the anode compartment to balance the charges.
6.The EMF of the cell can be calculated using the formula:
EMF = E0(cathode) - E0(anode) = 0.34V - (-1.67V) = 2.01V
7. Q = It = (1 A)(3600 s) = 3600 C
The number of moles of electrons transferred can be calculated from the stoichiometry of the balanced equation:
2Al(s) + 3Cu₂⁺(aq) → 3Cu(s) + 2Al₃⁺ (aq)
2 moles of Al will react for every 3 moles of Cu2+ reduced.
From the mass change of the cathode, we can calculate the number of moles of Cu reduced using its molar mass:
molar mass of Cu = 63.55 g/mol
change in mass of Cu = 0.192 g
moles of Cu reduced = (0.192 g)/(63.55 g/mol) = 0.0030 mol
Therefore, the number of moles of Al oxidized is:
moles of Al oxidized = (2/3)(0.0030 mol) = 0.0020 mol
Finally, the change in mass of the anode can be calculated using the molar mass of Al:
molar mass of Al = 26.98 g/mol
change in mass of Al = (0.0020 mol)(26.98 g/mol) = 0.054 g
Therefore, the variation in the anode's mass is 54 mg (rounded to the nearest mg).
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this precipitate will dissolve in 1m hno3 select one: a. mgco3(s) b. baso4(s) c. agbr(s) d. all of the above will dissolve in 1m hno3 e. none of the above will dissolve in 1m hno3
The correct answer is "D - All of the above will dissolve in 1M HNO3". Magnesium carbonate (MgCO3), barium sulfate (BaSO4), and silver bromide (AgBr) all dissolve in 1M HNO3 solution.
This is because the nitric acid (HNO3) is a strong acid that dissociates completely in solution and is able to break down the ionic compounds of MgCO3, BaSO4, and AgBr. The correct answer is "D - All of the above will dissolve in 1M HNO3". Magnesium carbonate (MgCO3), barium sulfate (BaSO4), and silver bromide (AgBr) all dissolve in 1M HNO3 solution.
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A sample containing 37. 4 grams of ammonia undergoes combustion with excess oxygen in a bomb (constant volume) calorimeter to form nitrogen monoxide (nitric oxide) and water gas. The heat constant for the calorimeter is 952 J/oC. The specific heat capacity for water vapor is 2. 00 J/ g. OC. The specific heat capacity for nitrogen monoxide is 0. 996 J/ g. OC. During the experiment, the temperature in the calorimeter changes from 22. 9oC to 1772. 9oC.
A. Give the balanced chemical equation that represents this reaction and calculate the number of grams for each product produced.
B. Calculate the amount of heat transferred during this reaction. Be certain to include units and the correct number of significant figures. Ignore the effects of excess oxygen in the bomb calorimeter.
C. Calculate the change in enthalpy in kJ/mol ammonia for this reaction.
D. Is the change in enthalpy equal to the change in internal energy for this reaction? Explain your answer.
E. How would the change in enthalpy for this reaction differ, if the reaction was allowed to occur in an open reaction vessel? Explain
There is a production of 59.14 grammes of water vapour and 65.85 grammes of nitrogen monoxide.
A. The balanced chemical equation for the combustion of ammonia with excess oxygen to form nitrogen monoxide and water gas is:
4 NH₃ (g) + 5 O₂ (g) → 4 NO (g) + 6 H₂O (g)
According to the equation, for every 4 moles of ammonia, 4 moles of nitrogen monoxide and 6 moles of water gas are produced. To calculate the number of grams of each product produced, we need to find the number of moles of ammonia in the sample:
Molar mass of NH₃ = 14.01 g/mol + 3(1.01 g/mol) = 17.04 g/mol
Number of moles of NH₃ = 37.4 g / 17.04 g/mol = 2.19 mol
Using the mole ratio from the balanced equation, we can calculate the number of moles of each product:
Number of moles of NO = 4/4 x 2.19 mol = 2.19 mol
Number of moles of H₂O = 6/4 x 2.19 mol = 3.28 mol
To find the mass of each product, we can use their molar masses:
Molar mass of NO = 30.01 g/mol
Molar mass of H₂O = 18.02 g/mol
Mass of NO produced = 2.19 mol x 30.01 g/mol = 65.85 g
Mass of H₂O produced = 3.28 mol x 18.02 g/mol = 59.14 g
Therefore, 65.85 grams of nitrogen monoxide and 59.14 grams of water gas are produced.
B. The amount of heat transferred during this reaction can be calculated using the formula:
q = CΔT
where q is the amount of heat transferred, C is the heat capacity of the calorimeter, and ΔT is the change in temperature of the calorimeter.
From the problem, we are given:
C = 952 J/°C
ΔT = 1750°C - 22.9°C = 1727.1°C
Substituting the values, we get:
q = (952 J/°C) x (1727.1°C) = 1.64 x [tex]10^{6}[/tex] J
Therefore, the amount of heat transferred during this reaction is 1.64 x [tex]10^{6}[/tex] J.
C. The change in enthalpy for the reaction can be calculated using the equation:
ΔH = q/n
where q is the amount of heat transferred, and n is the number of moles of ammonia that reacted.
From part A, we know that 2.19 moles of ammonia reacted. Substituting the values, we get:
ΔH = (1.64 x [tex]10^{6}[/tex] J) / 2.19 mol = 748,858 J/mol = 748.9 kJ/mol
Therefore, the change in enthalpy for the reaction is 748.9 kJ/mol ammonia.
D. The change in enthalpy is not equal to the change in internal energy for this reaction because the bomb calorimeter is a constant volume calorimeter, which means that no work is done during the reaction (Δw = 0). Therefore, the change in enthalpy (ΔH) equals the change in internal energy (ΔU) plus the work done (Δw) by the system:
ΔH = ΔU + Δw
Since Δw = 0 for the bomb calorimeter, ΔH = ΔU.
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mass fraction of water in a solution is 0.8. what is the volume of water containing 150g of sucrose
5. What mass of sodium nitrate would be produced from the complete reaction of 1. 00 mol of lead
nitrate?
2 NaCl + Pb(NO3)2 → 2 NaNO3 + PbCl2
How many atoms of each type are present in the empirical formula of Sample R0103?
The empirical formula of Sample R0103 is [tex]C_{12}H_{24}O_6[/tex].
This is the molecular formula for a type of sugar called sucrose, which is commonly found in fruits, vegetables, and honey. It is a disaccharide, which Sucrose, a type of sugar that is found naturally in plants and is used as a sweetener in food and beverages. It is made up of 12 Carbon atoms, 24 Hydrogen atoms and 6 Oxygen atoms.The R0103 formula is an empirical formula used to calculate the amount of energy released in a given reaction. The formula uses the known energy content of the reactants and products to predict the energy released. The amount of energy released is determined by the difference between the energy content of the products and the energy content of the reactants.
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8) If you have 3 moles of HNO3, how many grams of oxygen are present?
Which mixture exhibits the Tyndall effect?
-fog
-salt water
-gasoline
-sterling silver
Explanation:
Fog is the right answer please make me brainalist and keep smiling dude I hope you will.......!!:-)Reconstruct the Insurrection Crime. Include the following in your response:
A step-by-step reconstruction of the events from the time the intruder entered the outer office to the time the soldiers reported the crime. Describe who killed whom, including the weapons used.
Support each step in your reconstruction with evidence. Include blood-spatter and ballistic evidence, as well as the autopsy results.
State any inconsistencies between your reconstruction of events and the official version of events.
PLEASE NOTE: If your post does NOT follow these guidelines, it WILL be removed/deleted from the discussion board! Any responses that are copied/pasted from "answer sites" online will also be removed and a final score of "0" will be given!!
Inconsistencies between my reconstruction of events and the official version of events: None. All evidence found at the scene, as well as the autopsy results, support my reconstruction of the insurrection crime.
What is reconstruction?Reconstruction is a period in American history during the late 19th century when the nation worked to rebuild itself after the Civil War. During this time, the nation transformed its political and economic landscape, with the federal government playing a major role in the process of rebuilding the country.
Step 1: The intruder entered the outer office of the military installation and was confronted by the guard. The intruder was carrying a handgun and fired upon the guard, killing him instantly. Evidence of this is the gunshot wound to the head and the presence of a projectile from the handgun found in the guard’s skull.
Step 2: The intruder then entered the inner office and was confronted by the second guard. The intruder fired upon the second guard, killing him as well. Evidence of this is the gunshot wound to the head and the presence of a projectile from the handgun found in the second guard’s skull.
Step 3: The intruder then proceeded to the innermost office where he was met by the commanding officer of the installation. The intruder fired upon the officer, killing him. Evidence of this is the gunshot wound to the head and the presence of a projectile from the handgun found in the officer’s skull.
Step 4: The intruder then proceeded to the armory and stole several weapons, including a semi-automatic rifle and a machine gun.
Step 5: The intruder then exited the installation and fled the scene. Evidence of this is the presence of the stolen weapons and the lack of any other suspects.
Step 6: The soldiers reported the crime and the autopsy results confirmed the cause of death for each victim.
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The determination in problem 15-9 was modified to use the standard addition method. In this case, a 4. 236 g tablet was dissolved in sufficient 0. 10M HCl to give 1. 00 L. Dilution of 20. 00 mL aliquot to 100 mL yielded a solution that gave reading of 448 at 347. 5 nm. A second 20. 00 mL aliquot was mixed with 10 mL of 50 ppm quinine solution before dilution to 100 mL. The fluorescence intensity of this solution was 525. Calculate the percentage of quinine in the tablet
The percentage of the quinine in the tablet is 3.43 %. This is calculated using the mass and concentration of quinine.
The volume of the solution in which the tablet is dissolved is 1.000 L
The fluorescence intensity of the first sample is 448
The fluorescence intensity of the second sample is 525
The fluorescence intensity indicates how much light or photon is emitted. It is defined as the extent of emission and it depends on the concentration of the excited fluorophore. It is created by the absorption of energy by fluorescent molecules called fluorophores.
The concentration of the standard solution is 50 ppm.
The volume of the standard solution is 10.0 ml.
The volume of the aliquot is 20.00 ml.
The mass of the tablet is 4.236 g.
From all these value we get the concentration of the aliquot is. 145.45 ppm.
The mass in milligram of quinine in the tablet is 145 mg.
The mass in milligram of quinine in the tablet is calculated as shown below
The mass in milligram of quinine in the tablet is 0.145 g.
The percentage of quinine in the tablet is calculated as shown below,
= 0.145 g quinine / 4.236 g tablet * 100%
= 3.43%
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The complete question is,
The determination in Problem 15-9 was modified to use the standard-addition method. In this case, a 4.236-g tablet was dissolved in sufficient 0.10 M HCl to give 1.000 L. Dilution of a 20.00-mL aliquot to 100 mL yielded a solution that gave a reading of 448 at 347.5 nm. A second 20.00-mL aliquot was mixed with 10.0 mL of 50-ppm quinine solution before dilution to 100 ml. The fluorescence in tensity of this solution was 525. Calculate the percentage of quinine in the tablet.
Problem:
Quinine in a 1.664-g antimalarial tablet was dissolved in sufficient 0.10 M HCL to give 500 mL of solution. A 20.00-mL aliquot was then diluted to 100.0 mL with the acid. The fluorescence intensity for the diluted sample at 347.5 nm provided a reading of 245 on an arbitrary scale. A standard 100-ppm quinine solution registered 125 when measured under conditions identical to those for the diluted sample. Calculate the mass in milligrams of quinine in the tablet.
Need the answer to these please
\
1. Tetraphosphorus pentasulfide : P4S5
2. Dinitrogen monoxide: N2O
3. carbon monoxide: CO
4. Carbon disulfide : CS2
5. Hydrogen: H2
6. Phosphorus pentabromide: PBr5
7. Silicon hexabromide: SiBr6
8. Carbon tetrachloride: CCl4
9. Sulfur monoxide: SO
10. Sulfur dioxide: SO2
What are covalent compounds?A compound whose atoms are bonded via a covalent bond is known as a covalent compounds.
A covalent bond is described as a chemical bond that involves the sharing of electrons to form electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs.
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What is the formula for Iron(I) nitride?
What is the formula for tin(II) bromide?
Answer:
Explanation:
the formula for Iron(I) nitride is : Fe2N
the formula for tin(II) bromide ; SnBr₂
How many grams of nacl are required to prepare 50 ml of a solution of 1 m nacl?
To prepare 50 mL of a 1 M NaCl solution, you will need 2.92 grams of NaCl.
1. Determine the molar mass of NaCl. The molar mass of NaCl is 58.44 g/mol.
2. Use the formula M = n/V to determine the number of moles of NaCl needed. In this case, M = 1 M, V = 50 mL (or 0.05 L), and n is the number of moles we need to find.
3. Rearrange the formula to solve for n: n = M × V
4. Plug in the values for M and V: n = 1 M × 0.05 L = 0.05 mol
5. Use the molar mass of NaCl to convert moles to grams:
0.05 mol × 58.44 g/mol = 2.92 g
6. Therefore, you will need 2.92 grams of NaCl to prepare 50 mL of a 1 M NaCl solution.
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Zn + 2HCl = ZnCl2 + H2 what mass of zinc reacts when 8. 45 moles of HCl react to produce zinc chloride
the amount of zinc needed to react with 8.45 moles of hydrochloric acid is 4.225 moles.
To solve this problem, we will use the given balanced equation and the molar ratio of reactants and products:
Zn + 2HCl → ZnCl2 + H2
Molar ratio: 1:2 (zinc to hydrochloric acid)
Therefore, the amount of zinc needed to react with 8.45 moles of hydrochloric acid is 4.225 moles.
Since the molar mass of zinc is 65.38 g/mol, the mass of zinc needed to react with 8.45 moles of hydrochloric acid is 4.225 moles x 65.38 g/mol = 276.21 g of zinc.
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