Blue bird began at location (6,0) and hit the ground at (26,0). Find the
quadratic equation for his flight path.

Answers

Answer 1

The quadratic equation for his flight path is y = a(x² - 32x + 156) where a is a constant if the Blue bird began at location (6,0) and hit the ground at (26,0).

What is a quadratic equation ?

Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

We know the standard form of a quadratic function:

y = ax² + bx + c

Plug x = 6 and y = 0

0 = 36a + 6b + c ...(1)

Plug x = 26, and y = 0

0 = 676a + 26b + c ...(2)

From the equation (1) and equation (2) find the value of b and c

b = -32a

c = 156a

Plug this values in the standard form of a quadratic equation:

y = ax² + (-32a)x + 156a

y = a(x² - 32x + 156)

The above quadratic equation represents the flight path.

Let's take the value of a = -1

y = -1(x² - 32x + 156) (refer attached picture for the path of the graph)

Thus, the quadratic equation for his flight path is y = a(x² - 32x + 156) where a is a constant if the Blue bird began at location (6,0) and hit the ground at (26,0).

Learn more about quadratic equations here:

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Blue Bird Began At Location (6,0) And Hit The Ground At (26,0). Find Thequadratic Equation For His Flight

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Step-by-step explanation:

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Answers

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