1 Loudness and pitch are two important properties of a musical sound.
a If a musician plays a softer note, which property has been changed,
loudness or pitch?
b If the musician makes the note lower, which property has been
changed, loudness or pitch?

Answer:

Having more plants performing photosynthesis could help reduce the amount of carbon dioxide in the atmosphere.

Explanation:

sample answer

The plants can be used in the future to help counteract some human

emissions they absorb carbon dioxide from the air and release oxygen.

It is a process carried out by photosynthetic autotrophic organisms, such as plants, algae and some prokaryotes. These organisms capture sunlight, convert it into chemical energy, which will be used to produce organic compounds, based on water and carbon dioxide.

Trees, like other plants, in the process called photosynthesis, absorb carbon dioxide from the air and release oxygen. They also make the air wetter and cooler. In this way, plants contribute to the good quality of the air we breathe.

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Answer:

Explanation:

Let v be the velocity of object ,

Given that mass of object , m=100 g=  

1000

100

​

kg=0.1 kg

& kinetic energy of object =20 J

K.E  =  

2

1

​

 mv  

2

20=  

2

1

​

×0.1v  

2

⟹v  

2

=400

⟹v=20 m/s

Answer:Thus for n=1 number of electrons is 2 and for n=2 the number of electrons is 8. Hence the electronic configuration of the element X is 2,8,6 and its atomic number is 16. In the Modern Periodic Table, the element Sulphur has atomic number 16. So, the solution is that the element X is Sulphur and it is non metallic.

Answer:

Explanation:

Answer: Thus for n=1 number of electrons is 2 and for n=2 the number of electrons is 8. Hence the electronic configuration of the element X is 2,8,6 and its atomic number is 16. In the Modern Periodic Table, the element Sulphur has atomic number 16. So, the solution is that the element X is Sulphur and it is non metallic.

Formulas change from F to degree C : C = (F – 32) / 1.8

so we have (176-32) /1.8= 80 oC

Formulas change from F to degree K : K = 5 / 9 x (F – 32) + 273.15

so we have 5/9 x (176-32) + 273.15 = 353 oK

ok done. Thank to me :>

Answer:

2000 and 156300

jade it jawaban nya

Answer:

If and only if the object has 0 speed. Any other case is a no.

Explanation:

In increasing math complexity:

If the graph of a distance/time is a straight line with a non-zero slope it means that the velocity-time graph is an horizontal line where every point has the same second coordinate, equal to the value of the slope of the first line (ie, if the first line has equation [tex]y=2t[/tex] the second line will have equation [tex]y=2[/tex] - I'm using y to denote either the distance or the speed, read it as "the non-time variable")

If the graph of a speed/time is a straight line, the graph of the distance/time is the area of the region of space beneath the straight line in the first graph, ie a triangle. And as you increase the sides of that triangle keeping the angles fixed, you get a parabolic curve.

Bonus case: if [tex]v(t)= 0; d(t) = 0[/tex], they are both straight lines, they both pass through the origin, and they are the exact same line.

With calculus (or: math becomes fun after you add the alphabet to it)

You are asking if the answer of the IVP

[tex]\left \{ {{x'=x} \atop {x(0)=0}} \right.[/tex]

is a linear function. The answer is: besides the obvious [tex]x(t)'=x(t)=0 \ \forall t[/tex] there are no other solutions, linear or otherwise.

Answer:

a

Explanation:

if forces on an object are balanced a moving object continues to move at the same speed and in the same direction

Hi there!

We can begin by doing a summation of forces. Let the acceleration be positive in the direction of the DOWNWARD movement of the hanging block.

(A)

The system will flow in the direction of the hanging block's movement downwards.

(B)

Summation of forces of block on incline:

∑F = -M₁gsinФ + T

Summation of forces of hanging block:

∑F = M₂g - T

Sum both summations:

∑F =  -M₁gsinФ + T + M₂g - T

∑F = M₂g -M₁gsinФ

According to Newton's Second Law:

∑F = ma

Thus:

(M₁ + M₂)a = M₂g -M₁gsinФ

[tex]a = \frac{M_2g -M_1gsin\theta}{M_1 + M_2}[/tex]

Plug in the values:

[tex]a = \frac{(5 * 9.8) -(8 * 9.8 * sin30)}{8 + 5} = \large\boxed{0.754 m/s^2}[/tex]

(C)

Calculate the rope's tension using one of the above equations:

∑F₂ = M₂g - T

Rearrange for T:

T = M₂g - m₂a

Plug in values:

T = 5(9.8) - 5(0.754) = 45.23 N

Hi there!

We can begin by summing forces acting on the load:

∑F = T - Mg (where g ≈10 m/s²)

ma = T - Mg

We can plug in the given values to solve:

ma = 2000 - 175(10)

175a = 250  

a = 250/175 = 1.43 m/s² UPWARDS

Answer:

a = 1.63 m/s^2

Explanation:

m = 176kg

Ft = 2000N

  2000 = 175 (9.8) +175(a)

    2000   = 1715 +175a

    -1715       -1715

285 = 175a

175     175

a = 1.63m/s^2  

Answer:

Chemical modification of starch is based on the chemical reactivity of the constituent glucose monomers which are polyhydroxyl and can undergo several reactions. Starch can undergo reactions such as hydrolysis, esterification, etherification and oxidation.

Explanation:

Hope this helps!

The question is fishing for "balanced force".

But the description in the question is terrible.

Hi there!

For an object moving in a circle:

Centripetal force = ∑F = mv²/r

Thus:

56 = mv²/r

Rearrange to solve for velocity:

√(56r/m) = v

√(56 × 21)/650 = 1.345 m/s

Answer:

Explanation:

have a good day

Answer:

ETotal=38505J

Explanation:

Known values:

m=150kg

h=20m

v=11m/s

KE=mv^2/2

PE=mgh

ETotal=PE+KE

KE=(150(11^2))/2

KE=9075

PE=150(9.81)(20)

PE=29430

ETotal=9075+29430

ETotal=38505J

(a) The normal force on the sleigh is 596.36 N.

(b) The magnitude and direction of acceleration of the sleigh is 3.2 m/s² upwards.

The given parameters;

The normal force on the sleigh is calculated as follows;

[tex]F_n = mg \times cos(\theta)\\\\F_n = 63 \times 9.8 \times cos(15)\\\\F_n = 596.36 \ N[/tex]

The magnitude and direction of acceleration of the sleigh is calculated as follows;

[tex]\Sigma F= ma\\\\F - mgsin(\theta) - F_f = ma\\\\F - mgsin(\theta) - \mu F_n = ma\\\\510\ - \ 63 \times 9.8 \times sin15 \ -\ 0.25\times 596.36 = 63a\\\\201 .11 = 63a\\\\a = \frac{201.11}{63} \\\\a = 3.2 \ m/s^2 \ upwards[/tex]

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Answer:

Nuclear Fusion

Explanation:

At large distances, two nuclei repel one another because of the repulsive electrostatic force between their positively charged protons. If two nuclei can be brought close enough together, however, the electrostatic repulsion can be overcome by the attractive nuclear force, which is stronger at close distances.

We are able to walk toward because b) we push on the ground.

_

_

_

[tex] 😘 \: 😉 \: 😈 \; 😫 \: 😤 \: 😡 \: 😘[/tex]

Answer:

11.1

Explanation:

2 hours 15 mins = 2 1/4 hours

2 1/4 hours = 25 miles

1 hour = 25 ÷ 2 1/4 = 25 ÷ 9/4 = 25 x 4/9 = 11.1 miles

The kinetic energy of the toy before hitting the ground is 294.3 J

From the question given above, the following data were obtained:

Mass (m) = 3 Kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.81 m/s²

Before the toy will hit the ground, the potential and kinetic energy of the toy will be the same.

KE = PE = mgh

KE = 3 × 9.81 × 10

Therefore, the kinetic energy of the toy is 294.3 J

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Answer:

i think its going to be 150 because its half of 300

Explanation:

Hi there!

[tex]\large\boxed{F_{A} = -5000N}}[/tex]

For an object to be moving at constant velocity:

∑F = 0 (The sum of the forces acting on the object MUST be 0 N)

We can do a summation of forces for this helicopter in the HORIZONTAL direction:

∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0

Thus, if we substitute in the given value for Ft:

Ft = -Fa

5000N = -Fa

Fa = -5000N

Answer:

Yes

Explanation:

It's still the same orange with the same amount of stuff.

Answer:

25A°C=2L

35A°C=? More

=35/25×2L

=7/5×2L

=14L/5

=2.8L

Answer:   F = (200 kg + 70 kg) * 4 m/s² = 270 kg* 4m/s² = 1080 N

Answer:

F = 1080 N

Explanation:

Answer:

Energy = Power × Time

[tex]{ \tt{E = ( \frac{60}{1000} ) \times ( \frac{5}{60}) }} \\ \\ { \tt{E = 0.005 \: kwh {}^{ } }}[/tex]

Answer:

One of Canada's best-known poems, “In Flanders Fields” was written on May 2, 1915, when Canadian serviceman John McCrae was stationed at an army hospital in Flanders, Belgium, during World War I.

Explanation:

Explanation:

In everyday use and in kinematics, the speed of an object is the magnitude of the rate of change of its position with time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Answer:

A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding

Answer:

the graph plotted based on your data, you did not mention what are the variables on the x-axis and y- axis . and the graphs can be three small graphs of different material of one quality i.e. thickness or length

hope it helps

Explanation:

Answer:

I'm not a genius ok?

Explanation:

1. Radar communication, Analysis of the molecular and atomic structure, telephone communication

2. c