Answer:
what do you mean by this I don't get it
Please Help!
In the diagram, secant AP intersects the circle at points A and B, and secant CP intersects the circle at points C and D. The lines intersect outside the circle at point P.
What is the length of AP?
(There are no answer options you must enter the correct value)
Answer AP might be 12
Step-by-step explanation:
The length of AP when secant AP intersects the circle at points A and B, and secant CP intersects the circle at points C and D. is 12 units.
The length of AP can be found using the following steps:
Draw a radius from the center of the circle to point P.
Let the radius intersect secant AP at point E.
Since AP and PE are secant segments, they share a common external tangent at point P.
Therefore, the two triangles, APE and BPF, are similar triangles.
The ratio of corresponding sides in similar triangles is equal, so:
AP/PB = PE/PF
We know that PB = 5 and PF = 20, so:
AP/5 = PE/20
Solving for AP, we get:
AP = 5 * 20/5 = 20
The diagram shows the two similar triangles, APE and BPF. The two triangles are similar because they share a common external tangent at point P. The ratio of corresponding sides in similar triangles is equal, so we can use the ratio of AP to PB to find the length of AP.
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The radius of a semicircle is 4 miles. What is the semicircle's area?
Answer:
8[tex]\pi[/tex] miles or 25.133 miles
Step-by-step explanation:
your radius is 4 miles.
The area of a circle is A= [tex]\pi r^{2}[/tex]
Therefore, the area of this circle is [tex]4^{2} \pi[/tex], or 16[tex]\pi[/tex]
Half of this area, because what you're looking for is a semi-circle, is:
8[tex]\pi[/tex] (exact) or 25.133 (rounded) miles.
. A sample of bacteria cells in a petri dish increases by 50% every hour. A scientist
starts with a sample of 30 bacteria cells. Write an equation that can be used to
determine the number of cells after x hours.
2. how many bacteria cells will be present in the dish after 3 hours?
3.how many bacteria cells will be present after 12 hours?
Answer:
you first divide fifty out of one hundred then we multiply it by thirty
(15 points )
Find the x in the problem
(x−1)^2=9
Show steps if you can :)
Answer:
x=4 or x= -2
Step-by-step explanation:
(x-1)(x-1)
x(x-1)-1(x-1)
x^2-x-x+1
x^2-2x+1=9
x^2-2x+1-9=0
x^2-2x-8=0
p= -8
s= -2
1------ -8
2------ -4
x^2+2x-4x-8=0
x(x+2)-4(x+2)
(x+2)(x-4)=0
x+2=0
x-4=0
x= -2
or
x=4
Which inequality is shown in the graph?
Answer:
Step-by-step explanation:
solve- cbb to work it out
➝ Hypotenuse of triangle ( a ) = 21.63 mm
➝ Hypotenuse of triangle ( b ) = 150 mm
➝ Hypotenuse of triangle ( c ) = 111.80 mm
[tex] \quad\rule{300pt}{1.5pt}\quad[/tex]
Solution:We have to find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.
Pythagoras theorem states that :" In a right angled triangle, the square of hypotenuse side is equal to the sum of square of other two sides "
[tex] \qquad \bull \:{\pmb{\mathfrak{ h^2 = b^2 + p^2}}}[/tex]
And we have to convert the answer to the units indicated in red i.e, in mm.
Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula
For triangle ( a )[tex] :\implies\qquad \sf{ h^2 = b^2 + p^2}[/tex]
[tex] :\implies\qquad \sf{ h =\sqrt{b^2 + p^2}}[/tex]
[tex] :\implies\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}[/tex]
[tex] :\implies\qquad \sf{ h= \sqrt{144 + 324}}[/tex]
[tex] :\implies\qquad \sf{ h = \sqrt{468}}[/tex]
[tex] :\implies\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}}[/tex]
For triangle ( b )[tex] :\implies\qquad \sf{ h^2 = b^2 + p^2}[/tex]
[tex] :\implies\qquad \sf{h =\sqrt{b^2 + p^2} }[/tex]
[tex] :\implies\qquad \sf{ h = \sqrt{(90)^2+(120)^2}}[/tex]
[tex] :\implies\qquad \sf{ h=\sqrt{8100+14400}}[/tex]
[tex] :\implies\qquad \sf{ h =\sqrt{22500}}[/tex]
[tex] :\implies\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} }[/tex]
For triangle ( c )[tex] :\implies\qquad \sf{h^2 = b^2 + p^2 }[/tex]
[tex] :\implies\qquad \sf{ h=\sqrt{b^2 + p^2}}[/tex]
[tex] :\implies\qquad \sf{ h =\sqrt{(100)^2)+(50)^2}}[/tex]
[tex] :\implies\qquad \sf{ h=\sqrt{10000+2500}}[/tex]
[tex] :\implies\qquad \sf{ h =\sqrt{12500}}[/tex]
[tex] :\implies\qquad \underline{\underline{\pmb{\sf{h = 111.80mm}}} }[/tex]
Hypotenuse of triangle ( a ) = 21.63 mm
Hypotenuse of triangle ( b ) = 150 mm
Hypotenuse of triangle ( c ) = 111.80 mm
Explanation :find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.
[tex]h^2 = b^2 + p^2[/tex]
And we have to convert the answer to the units indicated in red i.e, in mm.
Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula
[tex]For \: \: triangle ( a )
\qquad \sf{ h^2 = b^2 + p^2}[/tex]
[tex]\qquad \sf{ h =\sqrt{b^2 + p^2}}[/tex][tex]\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}[/tex][tex]\qquad\sf{h=\sqrt{ (12)^2 + (18)^2 }} \\ \\ \qquad \sf{ h= \sqrt{144 + 324}} \\ \\ \qquad \sf{ h = \sqrt{468}}
\\ \\\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}} \\ \\ For \: \: triangle ( b ) \qquad \sf{ h^2 = b^2 + p^2} \\ \\ \qquad \sf{h =\sqrt{b^2 + p^2} } \\ \\ \qquad \sf{ h = \sqrt{(90)^2+(120)^2}} \\ \\ \qquad \sf{ h=\sqrt{8100+14400}} \\ \\
\qquad \sf{ h =\sqrt{22500}} \\ \\\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} } \\ \\ For \: \: triangle ( c ) \qquad \sf{h^2 = b^2 + p^2 } \\ \\ \qquad \sf{ h=\sqrt{b^2 + p^2}} \\ \\\qquad\sf{ h=\sqrt{(100)^2)+(50)^2}} \\ \\\qquad\sf{ h=\sqrt{10000+2500}} \\ \\ \qquad \sf{ h =\sqrt{12500}} \\ \\
\qquad\underline{\underline{\pmb{\sf{h = 111.80mm}}} } [/tex]
Help!!! 8. Determine whether each pair of functions f and g are inverses. Explain your reasoning.
Answer:
I would say that a is NOT an inverse, however b is.
Step-by-step explanation:
If you look at the two tables for a, you can tell that every pair has swapped places (as they should) except 0 and 9. In which in the second table, what should be the 9 in the x row, is just another 0 in its place.
While if you look at the two tables for b, every single pair has been swapped like it should, meaning the second table is the inverse of the first table.
Hope this helps you btw. I'm sorry if it doesn't though.
In creating a new scale for the mercury thermometer, Anders Celsius initially set the boiling point of water at _____. A. 0° b. 32° c. 100° d. 273°.
The thermometer is a device that is used to measure the temperature gradient. Anders needs to set the boiling point of water at 100° C.
What is a thermometer?
The thermometer is a device that is used to measure the temperature gradient or the temperature of a body/object.
The boiling point of water is 100°C, therefore, Anders needs to set the boiling point of water at 100° C.
Thus, Anders needs to set the boiling point of water at 100° C.
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What ratio forms a proportion with 2/3?
A. 2/4 B. 3/4 C. 4/6 D. 3/2
Answer:
c
Step-by-step explanation:
because you can simplify 4/6 by 2.
2 goes into 4 twice and then 2 goes into 6 3 times
2/3
2 Which set of side lengths will form a triangle?
16 ft, 4 ft, 21 ft.
6 30 ft, 30 ft, 60 ft
12 ft, 12 ft, 20 ft
3ft, 5 ft, 10 ft
None of the above. To form a standard triangle, all 3 sides must be of equal length.
solve 2-6(1-x)=6-4(-x-2) for x
Answer:
x = 9
Step-by-step explanation:
Simplifying
2 + -6(1 + -1x) = 6 + -4(-1x + -2)
2 + (1 * -6 + -1x * -6) = 6 + -4(-1x + -2)
2 + (-6 + 6x) = 6 + -4(-1x + -2)
Combine like terms: 2 + -6 = -4
-4 + 6x = 6 + -4(-1x + -2)
Reorder the terms:
-4 + 6x = 6 + -4(-2 + -1x)
-4 + 6x = 6 + (-2 * -4 + -1x * -4)
-4 + 6x = 6 + (8 + 4x)
Combine like terms: 6 + 8 = 14
-4 + 6x = 14 + 4x
Solving
-4 + 6x = 14 + 4x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-4x' to each side of the equation.
-4 + 6x + -4x = 14 + 4x + -4x
Combine like terms: 6x + -4x = 2x
-4 + 2x = 14 + 4x + -4x
Combine like terms: 4x + -4x = 0
-4 + 2x = 14 + 0
-4 + 2x = 14
Add '4' to each side of the equation.
-4 + 4 + 2x = 14 + 4
Combine like terms: -4 + 4 = 0
0 + 2x = 14 + 4
2x = 14 + 4
Combine like terms: 14 + 4 = 18
2x = 18
Divide each side by '2'.
x = 9
Simplifying
x = 9
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
The school band director has a budget $4,428.00 to spend on the band room, instruments, music, and uniforms. There are four sections in the band: drum corps, woodwinds, horns, and color guard. She has received three offers.
Option 1. Repair and replace uniforms at $564.00 per section and spend $182.00 on music.
Option 2. Repair and replace uniforms at $593.00 per section and spend $78.00 on music.
Option 3. Repair uniforms at $287.00 per section, spend $856.00 for improving the acoustics in the band room, and spend $422.00 on music and repairing instruments.
The remainder of the money will be split evenly among the four sections for additional costs. Match each option with the amount of money each section will receive for additional costs.
Answer:
The amount of money left for each section to spend from the budget in additional costs if they follow exact of the
options is
Option 1-$497.5
Option 2 - $494.5
Option 3 - $500.5
The image to show the amounts to match to isn't attagged to the question, but these are the answers and they should
be matched accordingly.
Step-by-step explanation:
We first calculate the amount left per section after following each of the options.
Budget $4,428.00
Option 1.
Repair and replace uniforms at $564.00 per section and spend $182.00 on music.
There are 4 sections, hence, total amount spent in this option:
4(564) + 182 $2438
Amount of money left from the budget after spending= 4428-2438 = $1990
Amount left per section = (1990/4) =
$497.5
Option 2
ធ
Repair and replace uniforms at $593.00 per section and spend $78.00 on music.
There are 4 sections, hence, total amount spent in this option:
4(593) + 78 $2450
Amount of money left from the budget after spending= 4428 - 2450= $1978
Amount left per section = (1978/4)=
$494.5
Option 3
Repair uniforms at $287.00 per
section, spend $856.00 for improving the acoustics in the band room, and spend $422.00 on music and repairing instruments.
There are 4 sections, hence, total amount spent in this option:
4(287) + 856 +422 = $2426
Amount of money left from the budget
after spending = 4428-2426 = $2002
Amount left per section = (2002/4)= $500.5
Find the area of the trapezoid shown below. {?} square feet
Answer:
432
Step-by-step explanation:
– Using the order of operations, which operation should you perform last to evaluate this expression? (1 x 2.5) + (52-13) + (6.7 - 5) - (98+8) A Addition B Subtraction © Multiplication D Division
Considering the order of operations, the operation that should be performed last is given by:
B Subtraction.
What is the order of operations?The operations inside the parenthesis take precedence over every operation. Then, multiplication/division take precedence over sum/subtraction. If there are only multiplication/division or sum/subtraction, the precedence is from left to right.
In this problem, the expression is:
(1 x 2.5) + (52-13) + (6.7 - 5) - (98+8)
Solving the operations inside the parenthesis, the expression will be given by:
2.5 + 30 + 1.7 - 90
Only addition and subtraction, hence the order is from left to right, and the subtraction is done last, hence option B is correct.
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HELP PLEASE I NEED IT NOW.
Answer:
Below :)
Step-by-step explanation:
1) 5^2 = 25
2) 12^2 = 144
3) 9^2 = 81
4) 15^2 = 225
5) 8^2 = 64
6) 7^2 = 49
7) 20^2 = 400
8) 13^2 = 169
9) 30^2 = 900
10) 25^2 = 625
Knowing that ΔBIG ≅ ΔFNS, an angle pair that is NOT necessarily congruent is:
Knowing that ΔDAL ≅ ΔEKS, a side pair that is NOT necessarily congruent is:
solutions:
1) G ≅ F
2) DA ≅ ES
Explanation:
Q)1
ΔBIG ≅ ΔFNS
pairs that are congruent:
B ≅ FI ≅ NG ≅ SFrom the list given,
→ G ≅ F is not necessarily congruent.
Q)2
ΔDAL ≅ ΔEKS
pairs that are congruent:
DA ≅ EKAL ≅ KSDL ≅ ESFrom the list given,
DA ≅ ES is not necessarily congruent.
Usually the congruence is done according to naming
So
∆BIG≅∆FNS<B=F
<I=<N
<G=<S
Option A#2
Check the naming
∆DAL≅∆EKSSo
DA=EK
And DA may not be equal to ESSo option D
Solve for m.
m/9 + 2/3 =7/3
Answer:
m= 15
Step-by-step explanation:
[tex] \frac{m}{9} + \frac{2}{3} = \frac{7}{3} [/tex]
To solve for m, start by moving the constants (numbers that are not attached to any variable) to the other side of the equation.
[tex] \frac{m}{9} = \frac{7}{3} - \frac{2}{3} [/tex]
Simplify:
[tex] \frac{m}{9} = \frac{5}{3} [/tex]
Multiply both sides by 9:
[tex]m = \frac{5}{3} \times 9[/tex]
Crossing out 3 from the denominator and from 9:
m= 5(3)
m= 15
PLS HELP ME PLS I WILL MARK THE BRAINLIEST
Step-by-step explanation:
the area of a full circle (360°) is
pi×r²
r = 15 ft in our case
the area of a segment of a circle is the corresponding fraction of the whole circle area.
the angle of the shaded area is
360 - 332 = 28°
therefore, the area of the shaded area is
pi×15²×28/360 = pi×225×28/360 = pi×225×7/90 =
= pi×5×7/2 = 54.97787144... ft²
≈ 54.98 ft²
the area of the "ice rink" is the sum of a rectangle and a circle (which is split into 2 halves that are attached to both sides of the rectangle).
the radius of the circle is 7/2 = 3.5 meters.
the length of the rectangle in the middle is
18 - 2×3.5 = 18 - 7 = 11 meters.
so, the area of the rectangle is 11×7 = 77 m²
the area of the circle is
pi×r² = pi×3.5² = pi×12.25 = 38.48451001... m²
that means the total area is
77 + 38.48451001... = 115.48451... m² ≈ 115.48 m²
The following structure is composed of three right rectangular prisms: two that each measure 12 inches by 10 inches by 5 inches and one right rectangular prism that measures 10 inches by 8 inches by 36 inches. What is the total volume of the structure? Show your work and/or explain your reasoning..
The volume of the stucture made from three rectangular prism is 4080 ft³
What is volume?Volume is the amount of space occupied by a three dimensional shape or object.
The volume of the rectangular prism = length * width * height = 12 * 10 * 5 = 600 ft³
The volume of the other prism = length * width * height = 10 * 8 * 36 = 2880 ft³
Volume of the structure = 600 ft³ + 600 ft³ + 2880 ft³ = 4080 ft³
The volume of the stucture made from three rectangular prism is 4080 ft³
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PLS HELP ME I WILL MARK THE BRAINLIEST
#1
First the rectangle
L=18mB=7mArea
18(7)126m^2.For semicircle
d=7m=>r=3.5mArea
=πr^2/2=12.25π/2Total area
126+2(12.25π/2)126+12.25πm^2#2
r=15fttheta=332°=332×π/180=0.92πArea:-
r^2\theta15^2(0.92)207ft^2x = –8 –6x + 9y = 12 solve for substitution
Answer:
x= -8,y= -4
Step-by-step explanation:
Substitute x= -8
-6(-8)+9y=12
simplify
48+9y=12
isolate for y
y= -4
The solutions to the system of equations are:
x= -8 and y= -4
Ralph plotted the points (-4, 1) and (-4,-1) on a coordinate grid. What is the distance,
in units, between the points Ralph plotted?
a 1
B -2
C 2
D 0
4/9 x 5/6 simplest form
5/6 x 4/9 = 10/27 as a fraction form. The work for 5/6 times 4/9 as a fraction provides more insight of how to find what is 5/6 times 4/9 in fraction form and the different variations of such problems.
There is an isosceles triangle which is also a right triangle. Its area is 50 square inches. Find the length of the base of the triangle
Answer: 10 inches
Step-by-step explanation:
What is the simplified form of the following expression? 2 startroot 18 endroot 3 startroot 2 endroot startroot 162 endroot
The simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.
What is the simplified form of an equation?The simplified form of an equation is the simplest way of expressing the equation, by applying the required operations of mathematics.
The equation provided in the problem is,
[tex]2\sqrt{18}+3\sqrt{2}+\sqrt{162}[/tex]
Let the simplified form of the above expression is n. Thus,
[tex]n=2\sqrt{18}+3\sqrt{2}+\sqrt{162}[/tex]
Rewrite the equation to solve it further as,
[tex]n=2\sqrt{3\times3\times2}+3\sqrt{2}+\sqrt{9\times9\times2}\\n=2\sqrt{3^2\times2}+3\sqrt{2}+\sqrt{9^2\times2}[/tex]
The square of the term cancel out the square root of it. Thus,
[tex]n=2\times3\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=6\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=(6+3+9)\sqrt{2}\\n=18\sqrt{2}[/tex]
Thus, the simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.
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(ii) Two of the lights at the local stadium start flickering at 9:15 p.m. One of the lights flickers every 8
minutes and the other light flickers every 12 minutes. What time both lights flicker at the same time
again?
PLSS HELPPP
Answer:
At 9:39 they both will Flick
Step-by-step explanation:
so when the first light flicks it resets and starts counting to anthor 8 mins while the other takes 4 mins extra just keep adding till they both have same time
PLEASE HELP I DONT UNDERSTAND IVE BEEN TRYING FOR 15 MINS AND STILL DONT GET IT
Find the lengths of the missing sides in the triangle. Write your answers as integers or as decimals rounded to the nearest tenth. The diagram is not drawn to scale. (picture of diagram included)
The values of the length of the missing sides of triangle is x = 7√2 and y = 7.
What are special triangles?Special right triangles are right triangles with three determined interior angles and fixed side ratios. If one side is known in these right-angled triangles, we can find the value of the two missing sides. The 45°- 45°-90° triangle and the 30°- 60°-90° triangle are other names for the two unique right triangles. Before going further, let's review the fundamental characteristics of a right triangle.
One of the angles of a right triangle is 90 degrees, and the total of the other two angles is also 90 degrees. The triangle's hypotenuse, which is the longest side, is the side that faces the right angle.
From the given figure we observe that the two angles are 45 degree and 90 degree.
Using the angle sum property we have:
45 + 90 + third angle = 180
third angle = 45 degrees.
The triangle is thus a 45-45-90 triangle.
The sides of 45-45-90 triangle correspond to the lengths as x : x : x√2.
Here, the angle corresponding to 45 is 7.
Thus, y = 7 and x = 7√2.
Hence, the values of the length of the missing sides of triangle is x = 7√2 and y = 7.
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Gabrielle is saving money for a vacation. Each week she save $40. Let a represent the total amount of money Gabrielle saves, and let w represent the number of weeks. How much money would she save from 1 to 7 weeks?
Step-by-step explanation:
A = 40w
To Calculate how much she would get in 7 weeks
Substitute w = 7 into A = 40w
⇒ A = 40(7)
⇒ A = 280
Gabrielle would save $280 in 7 weeks
Nick and his family travel by train to New York City.
The clocks show when the train leaves the station and when it arrives in New York City.
How long is the train ride?
Answer:4:15
Step-by-step explanation:
EZ
let l be the line through A(4,-3) and B(t,-2) that is parallel to the line through P(-2,4) and Q(4,-1) find the value of t
Answer:
t = [tex]\frac{14}{5}[/tex]
Step-by-step explanation:
Parallel lines have equal slopes.
calculate the slope m of PQ and then equate the slope of AB to slope of PQ
calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = P (- 2, 4 ) and (x₂, y₂ ) = Q (4, - 1 )
[tex]m_{PQ}[/tex] = [tex]\frac{-1-4}{4-(-2)}[/tex] = [tex]\frac{-5}{4+2}[/tex] = - [tex]\frac{5}{6}[/tex]
now calculate slope of AB
with (x₁, y₁ ) = A (4, - 3 ) and (x₂, y₂ ) = B (t, - 2 )
[tex]m_{AB}[/tex] = [tex]\frac{-2-(-3)}{t-4}[/tex] = [tex]\frac{-2+3}{t-4}[/tex] = [tex]\frac{1}{t-4}[/tex]
equating the slopes gives
[tex]\frac{1}{t-4}[/tex] = - [tex]\frac{5}{6}[/tex] ( cross- multiply )
5(t - 4) = - 6
5t - 20 = - 6 ( add 20 to both sides )
5t = 14 ( divide both sides by 5 )
t = [tex]\frac{14}{5}[/tex]