Physics High School


7. An object can be accelerating even if its speed is
constant if it
(a) comes to a stop
(b) is not possible
(C) changes direction
(d) moves in a straight line​

Answers

Answer 1

Answer:

I think that the answer might be d

Answer 2

Answer:

D

Explanation:

If a car is moving very fast in a straight road or a highway in such a way that it has reached its limits as soon as it is going that fast it can break it limit

Related Questions

Which applications, either for diagnostic purposes or for therapeutic purposes, do not involve ionizing radiation? Check all that apply.

Answers

Answer: I do not know (is this an RP question? ;-;)

Explanation:

Answer:

Applications in which ionizing radiation are not used are  

MRI

ultrasound

laser surgery

Explanation:

hope its right

bestfriend

An object is located 20.0 cm from a convex lens. The lens focuses light at a
distance of 10.0 cm. What is the image distance?

A. 6.67 cm
B. -6.67 cm
C. -20.0 cm
D. 20.0 cm

Answers

The Answer Is :  D. 20.0 cm

My Reason : These types of problems can all be solved using the lens or mirror equation.

1/20 +1/q= 1/10

q=20 cm

The image is formed behind the lens at 2f or the center of curvature.

It is real, inverted, and the same size as the object

The Answer Is: D. 20.0 cm

Explanation: I did the test :)

How is our magnetic field made?

Answers

Answer:

REVENGE

Explanation:

HAHAAHAHAAHAHAHA

Which equation could not be used to determine straight line acceration?

Answers

Answer:

the answer for the question is the last option

A car increases from 15 km/s to 45 km/s in 5 seconds. Calculate the average acceleration of the car during these 5 seconds. (2 points) A. 6 km/s2 B. 12 km/s2 C. 30 km/s2 D. 60 km/s2​

Answers

A is the correct answer

A toy radio-controlled car races around a circular track in a time of 2 MINUTES, with a speed of 5.25 m/s. What is the radius of the
circular track? (will give brainliest)

Answers

Answer:

The radius will be "100.31 m". A further solving is given below.

Explanation:

The given values are:

Time,

T = 2 minutes

i.e.,

 = 120 seconds

Speed,

V = 5.25 m/s

As we know

⇒  [tex]T=\frac{2 \pi R}{V}[/tex]

then,

⇒  [tex]R=\frac{TV}{2 \pi}[/tex]

On substituting the given values, we get

⇒      [tex]=\frac{120\times 5.25}{2\times 3.14}[/tex]

⇒      [tex]=\frac{630}{6.28}[/tex]

⇒      [tex]=100.31 \ m[/tex]

What is the momentum of a 200 kg truck travelling at 20 m/s?

Answers

Answer:

p = 4000 kg-m/s

Explanation:

Given that,

The mass of a truck, m = 200 kg

Speed of the truck, v = 20 m/s

We need to find the momentum of the truck. The formula for momentum is given by :

p = mv

so,

[tex]p=200\times 20\\\\p=4000\ kg-m/s[/tex]

So, the momentum of the truck is equal to 4000 kg-m/s.

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