A 0.6 kg basketball moving 7.2 m/s to the right collides with a 0.04 kg tennis
ball moving 22 m/s to the left. After the collision, the tennis ball is moving
32.7 m/s to the right. What is the velocity of the basketball after the collision?
Assume an elastic collision occurred.
A. 10.9 m/s to the right
B. 10.9 m/s to the left
C.3.6 m/s to the left
D. 3.6 m/s to the right

Answers

Answer 1

Answer:b

Explanation:

Answer 2

The final velocity of the basketball after it undergoes collision with the tennis ball is 6.49m/s.

What is Final velocity?

The final velocity is a vector quantity which measures the speed and direction of a moving object after it has reached its maximum acceleration and distance.

Given data,

mass of basket ball (m₁) = 0.6kg

mass of tennis ball (m₂) = 0.04kg

velocity of basket ball (v₁) = 7.2m/s

velocity of  tennis ball (v₂) = 22m/s

velocity of basket ball (v₃) =?

velocity of  tennis ball (v₄) = 32.7m/s

We already know that the expression for elastic collision is given as

m₁v₁ +m₂v₂ = m₁v₃ + m₂v₄

Substituting these values, we get

0.6 × 7.2 + 0.04 × 22 = 0.6 × x + 0.04 × 32.7

4.32 + 0.88 = 0.6x + 1.308

Solving for x we have,

3.892 = 0.6x

x = 3.892 /0.6

x=6.49m/s

Therefore, the velocity of the basketball after the collision is 6.49m/s.

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Related Questions

Select the correct answer.
Which scientist discovered the relationship between electricity and magnetism?
OA.
Nikola Tesla
OB
Alessandro Volta
OC.
Hans Christian Oersted
OD
Isaac Newton

Answers

Answer:

Hans Christian Oersted

Explanation:

Object has a mass of 35g and a density of 5g/cm3.
What is the volume? *

Answers

Answer:

The answer is 7.0 mL

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 35 g

volume = 5 g/cm³

We have

[tex]volume = \frac{35}{5} \\ [/tex]

We have the final answer as

7.0 mL

Hope this helps you

what are Newton's 3 laws

Answers

Answer:

Newton 3 laws

Explanation:

1.object will not change its motion unless a force acts on it . 2.the force on an object is equal to it's time mass on acceleration. 3. When 2 o jecys interact they apply forces to each other of equal.

Answer- In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Hope this helps:)


What is the average velocity of a boy moving from initial position of 4 m to a final position of 8 min 20 s. Show steps of solving:


please please heeeeelp​

Answers

9514 1404 393

Answer:

  0.2 m/s

Explanation:

The average velocity is the change in position divided by the change in time:

  (8 m -4 m)/(20 s) = (4/20) m/s = 1/5 m/s = 0.2 m/s

The boy's average velocity is 0.2 m/s.

A mountain biker is climbing a steep 20° slope at a constant speed. The cyclist and bike have a combined weight of 800 N. What can you say about the magnitude of the normal force of the ground on the bike?

Answers

Answer:

Normal force = 751.75 N

Explanation:

It is given that,

The combined weight of the cyclist and the bike is 800 N

We need to find the magnitude of the normal force of the ground on the bike. It can be given by the formula as follows :

[tex]N=mg\cos\theta[/tex]

mg = W, combined weight of cyclist and bike

[tex]N=W\cos\theta\\\\N=800\times \cos(20)\\\\N=751.75\ N[/tex]

So, the magnitude of the normal force of the ground on the bike is 751.75 N.

The magnitude of the normal force of the ground on the bike is 751.752 N

The formula for that will be used to calculate the normal force of the ground on the bike is expressed as:

[tex]N= Fcos \theta[/tex]

F is the combined weight

[tex]\theta[/tex] is the angle of inclination

Given the following paramters

F = 800 N

[tex]\theta[/tex] = 20 degrees

Substitute the given parameters into the formula:

[tex]N=800 \times cos20^0\\N=800 \times 0.9397\\N=751.752N[/tex]

Hence the magnitude of the normal force of the ground on the bike is 751.752 N

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What is a factor in an experiment that can be changed or it can be kept the same?

Answers

Answer:  If you are performing an experiment on the effect of spraying plants with different chemicals, you would try to maintain the same pressure and maybe the same volume when spraying your plants. The independent variable is the one factor that you are changing. It is one factor because usually in an experiment you try to change one thing at a time.

Explanation:

Centripetal acceleration must involve a change in

Answers

Answer:

Centripetal acceleration must involve a change in a. an object's tangential speed.

Explanation:

Centripetal acceleration must involve a change in direction of motion of the object.

What is centripetal acceleration?

centripetal acceleration is the acceleration of a body traversing a circular path. Because velocity is a vector quantity (that is, it has both a magnitude, the speed, and a direction), when a body travels on a circular path, its direction constantly changes and thus its velocity changes, producing an acceleration. The acceleration is directed radially toward the center of the circle.

In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.

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Which statement describes S waves? A. They move side to side.B.They arrive betore P waves. C. They travel through liquids D. They occur at Earth's surtace.​

Answers

Answer: they move side to side

Explanation:

i took the test

Calculate the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I. (Note the loop and wire are not in electrical contact.)

Answers

Answer:

The magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14

Explanation:

The magnetic field at center of a circular loop is given by

[tex]B = \frac{\mu _{o}I }{2R}[/tex]

Where B is the magnetic field

[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)

[tex]I[/tex] is the current

and [tex]R[/tex] is the radius

For the magnetic field of a long straight wire, it is given by

[tex]B = \frac{\mu _{o}I }{2\pi R}[/tex]

Where B is the magnetic field

[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)

[tex]I[/tex] is the current

and [tex]R[/tex] is the distance from the wire

Then, to calculate the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I, that will be

[tex]\frac{\mu _{o}I }{2R} \div \frac{\mu _{o}I }{2\pi R}[/tex]

= [tex]\frac{\mu _{o}I }{2R} \times \frac{2\pi R }{\mu _{o}I}[/tex]

= [tex]\pi[/tex]

(NOTE: [tex]\pi[/tex] = 3.14)

Hence, the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14.

What is the momentum of a 76–kilogram horse running at a speed of
45 kilometers/hour?

A.
2.5 × 102 kilogram·meters/second
B.
3.4 × 104 kilogram·meters/second
C.
3.4 × 103 kilogram·meters/second
D.
9.5 × 102 kilogram·meters/second

Answers

Answer:

Option D, is closest to the answer = 950.

Answer: D. 9.5x102 kilogram.meters/second

Explanation:

correct for plato

SOMEONE PLEASE PLEASE HELP QUICK PICTURE INCLUDED

Answers

Answer:

A

Explanation:

Switches are used to block electrical currents, thus needing to be made out of insulating material.

An airplane flying at 119 m/s is accelerated uniformly at the rate of 0.5 m/s2 for 10
seconds. What is its final speed?

Answers

Answer:

124m/s

Explanation:

v=u+at

v=119+(0.5×10)

v=119+5

v=124m/s

Will ice melt faster in salt, sugar or water?

Answers

Answer:

Water because the salt will just make it colder and the sugar won't do anything

Someone please makeup a hypothesis for me rq make it make sense!

Answers

If the slope is downward, and the marbles are going downward, then there will be little work to be done when moving the marbles. Hope this helps :)

A 10 [kg] object is dropped from rest. a. How far will it drop in 2 [s]?

Answers

Answer:

y=0.5 g t^2

=0.5*10*2^2

=20 m

In what climates would you expect soil to form fastest? Why?

Answers

Answer:

Soils develop faster in warm, moist climates and slowest in cold or arid ones. Rainfall is one of the most important climate factors in soil formation.

Please mark me brainliest!

Hope this helped God bless :)

Soil formation occurs more swiftly in warm, humid areas than it does in cold or arid ones.One of the most crucial climatic variables for the formation of soil is rainfall. The breakdown of large soil particles into smaller ones is accelerated by creatures such as bacteria, plants, and animals.

What climates soil to form fastest?

The rate of chemical reactions is accelerated by rising temperature, which also accelerates soil formation. Faster plant and bacterial growth in warmer climates aids in the weathering of materials and the formation of soils.

The formation of soil is another indirect effect of climate on organisms. Weathering is accelerated by precipitation and warm temperatures, which increases the amount of soil development. Rainfall increases the amount of organic matter, lowers pH, accelerates the leaching of basic ions, moves mud, etc.

Therefore, In warm, wet regions, soil development happens more quickly than in cold or arid ones. One of the most crucial climatic variables for the formation of soil is rainfall.

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A speed skater moving across frictionless ice at 8.8 m/s hits a 6.0 m -wide patch of rough ice. She slows steadily, then continues on at 5.8 m/s . What is her acceleration on the rough ice?

Answers

Recall that

v² - u² = 2 ax

where u and v are initial and final velocities, respectively; a is acceleration; and ∆x is the distance traveled (because the skater moves in only one direction).

So we have

(5.8 m/s)² - (8.8 m/s)² = 2 a (6.0 m)

a = ((5.8 m/s)² - (8.8 m/s)²) / (12 m)

a = -3.65 m/s²

A net force of 275 N accelerates a 18.0 kg mass. What is the resulting acceleration? (5 points)

Answers

Answer:

The answer is 15.28 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

where

m is the mass

f is the force

We have

[tex]a = \frac{275}{18} \\ = 15.277777...[/tex]

We have the final answer as

15.28 m/s²

Hope this helps you

Page
1
of 3
0
ZOOM
3. A cat is moving at 18 m/s when it accelerates at 4 m/s? for 2 seconds. What is his new
velocity?

Answers

Answer:

26 m/s

Explanation:

v = u + at

Given that,

u(initial speed) = 18 m/sa (acceleration) = 4m/s^2t ( time) = 2s

and v ( final velocity) = ?

v = 18 + ( 4 × 2)

v = 18 + 8

v = 26 m/s

This is about acceleration, velocity and all that mumbo jumbo

Which best depicts the data?

1, From 0 to 2 seconds, Anna experienced negative acceleration.
2, From 3 to 6 seconds, Elan accelerated while Anna did not.
3, From 6 to 8 seconds, Elan accelerated faster than Anna.
4, From 8 to 10 seconds, Elan experienced negative acceleration.

Answers

Answer:

[tex]3. \: From \: 6 \: to \: 8 \: seconds, \: Elan \: \\ accelerated \: \: faster \: than \: Anna. [/tex]

A 2070 kg space station orbits Earth at an altitude of 5.37×105 m. Find the magnitude of the force with which the space station attracts Earth. The ma

Answers

Answer:

9.9 × 10^-16N

Explanation:

Given that a 2070 kg space station orbits Earth at an altitude of 5.37×105 m. Find the magnitude of the force with which the space station attracts Earth. 

Calculating the gravitational field strength.

g = Gm/R^2

Where G = 6.67408 × 10-11 m3 kg-1 s-2

g =(6.67408 × 10-11 × 2070)/5.37 × 10^5

g = 1.38069×10^-7 / 2.88369^11

g = 4.788×10^-19 m/s

Force F = mg

Substitute g into the formula

F = 2070 × 4.79×10^-19

F = 9.9 × 10^-16N


Which of the following is an example of homeostasis?

Answers

Answer:

Humans' internal body temperature is a great example of homeostasis. ...

Glucose is the most basic form of sugar, and the only type the body can use directly. ...

When bacteria or viruses that can make you ill get into your body, your lymphatic system kicks in to help maintain homeostasis.

Explanation:

how is the process of finding the mass of a gas different from that of finding the mass of a liquid why is the difference necessary​

Answers

Because gas and liquid are both different things

1) A rigid tank contains 2 kg of 134a refrigerant at 800 kPa and 120°C. Determine tank volume and total internal energy.

Answers

Answer:

V = 0.07525 [m³]

U  = 655.74 [kJ]

Explanation:

To solve this problem we must use the superheated refrigerant table for refrigerant 134a. The attached image shows the specific volume and specific internal energy values for a pressure of 800 [kPa] and a temperature of 120 [°C].

m = mass =2 [kg]

the specific volume = v = 0.037625 [m³/kg]

The volume of the tank can be found using the following expression:

V = v*m

V = 0.037625*2 = 0.07525 [m³]

The Specific internal energy = u = 327.87 [kJ/kg]

U = u*m

U = 327.87*2 = 655.74 [kJ]

Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost much more, but last far longer and use much less electricity. According to one study of these bulbs, a compact bulb that produces as much light as a 100 W incandescent bulb uses only 23.0 W of power. The compact bulb lasts 10000 hours, on the average, and costs $ 12.00, whereas the incandescent bulb costs only $ 0.76, but lasts just 750 hours. The study assumed that electricity cost $ 0.090 per kilowatt-hour and that the bulbs were on for 4.0 h per day.

Required:
a. What is the total cost (including the price of the bulbs) to run each bulb for 3.0 years?
b. How much do you save over 3.0 years if you use a compact fluorescent bulb instead of an incandescent bulb?
c. What is the resistance of a "100-W" fluorescent bulb?

Answers

Answer:

a

[tex]The  \ price \  for \   Compact\ fluorescent\ bulbs \ is  \ C_T  = \$ 21.067\\The   \ price \  for \    incandescent\ bulb \ is \ C_t  = \$ 43.98[/tex]

b

[tex]The \  amount  \  saved \ is  \ C_S =  \$ 22.913[/tex]

c

[tex]The \ resistance \  is \ R =  626.1 \Omega[/tex]

Explanation:

From the question we are told that

   The power used by incandescent bulb [tex]P_r  =  23.0 W[/tex]

    The power used by  Compact fluorescent bulb [tex]P_p  =  100W[/tex]

     The life span of  Compact fluorescent bulb is  [tex]t = 1000 \  hours[/tex]

    The  prices of   Compact fluorescent bulb is [tex]C_c = \$ 12 [/tex]

    The  prices of incandescent bulb is [tex]C_i = \$ 0.76 [/tex]

     The life span of   incandescent bulb is  [tex]t_k = 750   \ hours[/tex]

      The cost of electricity is [tex]C_e =  \$ 0.090/ kilowatt-hour = \frac{0.090}{1000} = \$0.00009 / W / h[/tex]

    The duration of daily bulb usage is [tex]t_d  =  4 \  hours[/tex]

     

Generally 3 years of bulb usage  in hours is mathematically evaluated as

    [tex]t_3 =  3 *  365 *  t_d[/tex]

=>   [tex]t_3 =  3 *  365 *  4[/tex]

=>   [tex]t_3 =  4380 \ h [/tex]

Generally the cost to power a 23W bulb for the above duration  is mathematically represented as

 [tex]Z = 23 *  t_3 * C_e[/tex]

=>   [tex]Z = 23 *  4380 * 0.00009[/tex]

=>   [tex]Z = \$ 9.0667[/tex]

The number of Compact fluorescent bulbs required to  achieve this about of time is mathematically represented as

       [tex]N  =  \frac{t_3}{ t}[/tex]

=>  [tex]N  =  \frac{4380}{1000}[/tex]

=>   [tex]N  = 0.438 [/tex]

=>  [tex]N  \approx  1 [/tex]

The total cost of  usage  for the Compact fluorescent bulb   is  mathematically represented as

      [tex]C_T  =  Z +C_c[/tex]

=>   [tex]C_T  =  9.0667 +12[/tex]

=>   [tex]C_T  = \$ 21.067 [/tex]    

The number of  incandescent bulbs required to  achieve this about of time is mathematically represented as

       [tex]M =  \frac{t_3}{ t_k}[/tex]

=>  [tex]M  =  \frac{4380}{750}[/tex]

=>   [tex]M  = 6 [/tex]

Generally the cost to power a 100W bulb for the above duration  is mathematically represented as

 [tex]Z = 100 *  t_3 * C_e[/tex]

=>   [tex]Z = 100 *  4380 * 0.00009[/tex]

=>   [tex]Z = \$ 39.42[/tex]

The total cost of  usage  for the incandescent bulbs    is  mathematically represented as

      [tex]C_t  =  C_e + [6 *C_i][/tex]

=>   [tex]C_t  =  39.42 + [0.76 *  6][/tex]

=>   [tex]C_t  = \$ 43.98[/tex]    

Generally the total amount saved is mathematically represented as

   [tex]C_S =  C_t - C_T[/tex]

=>   [tex]C_S =  43.98 - 21.067[/tex]

=>   [tex]C_S =  \$ 22.913[/tex]

Generally the resistance of the Compact fluorescent bulb is  

    [tex]R =  \frac{V^2}{P}[/tex]

    [tex]R  =  \frac{120^2}{23}[/tex]

[tex]R =  626.1 \Omega[/tex]

What would be the speed of an object just before hitting the ground if dropped 91.5 meters

Answers

Answer:

about 42.35 m/s

Explanation:

Use the equation for accelerated motion (g), and with zero initial velocity that doesn't include time:

[tex]v_f^2=v_i^2+2\,a\,\Delta x[/tex]

which for our case would reduce to:

[tex]v_f^2=v_i^2+2\,a\,\Delta x\\v_f^2=0+2\,9.8\,(91.5)\\v_f^2= 1793.4\\v_f=\sqrt{1793.4} \\v_f \approx 42.35[/tex]

then the velocity just before hitting would be about 42.35 m/s

Which example illustrates Newton's first law?

Answers

Answer: The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law. The motion of a kite when the wind changes can also be described by the first law.

Explanation:

Write the vectors labeled A, B and C with rectangular coordinates.

Answers

Focus on vector A. Start at the base of the vector which is at (1,1)

Then notice how we have to move 3 units to the right and 2 units up to get to the tip of the vector where the arrow is located. So this is at (4,3)

The fact that we moved 3 units to the right and 2 units up means that vector A is <3, 2>

So we'll type 3 in the first box and 2 in the second box.

======================================================

We use the same idea for vector B

Start at the base and move to the tip. Doing so has us move 1 unit left and 3 units down.

Vector B = <-1, -3>

We type -1 in the first box, and -3 in the second box.

======================================================

Finally onto vector C

Start at the base (0,0). To move to the tip, we need to go 3 units left and 3 units up

Vector C = <-3, 3>

-3 goes in the first box and 3 goes in the second box

======================================================

In general, vectors are useful to tell us a specific direction in which to go. They're useful in physics to determine how exactly a force is being applied, or how a particle is moving.

A 65.25 kg person holding a steel ball stands motionless on a frozen lake.
The person then throws the ball, which propels the person at 1.25 m/s to the
right and the ball 4.05 m/s to the left. If the initial momentum of the system is
zero, what is the mass of the steel ball?

Answers

Answer:

20.14 KG

Explanation:

apex keepy o heads up stay positive don't stress over something useless big future 4 all of yall!

The mass is 20.14 kg

why cats cannot run on smoth table​

Answers

Answer:

bc of their paw pads, they don't get the traction they need in order to be able to get a firm grip to push off of on the table for each bound

Explanation:

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