Answer:
x=20 seats, y=29 seats
Step-by-step explanation:
y-x=9 y=9+x
2x+y=69 solve by substitution
2x+9+x=69
3x=69-9 3x=60
x=60/3=20 (small van)
y=9+x
y=29 (large van)
Answer : 20 in small , 29 in big as big van has 9 small van
Question 5 of 10
Which of the following is the converse of the statement "If it is summer, then
it is warm outside"?
A. If it is warm outside, then it is summer.
B. If it is not warm outside, then it is summer.
O
C. If it is warm outside, then it is not summer.
D. If it is not warm outside, then it is not summer.
hs
Answer:
If it is warm outside, then it is summer
Step-by-step explanation:
To find the converse, interchange the hypothesis and the conclusion
"If it is summer, then it is warm outside"
If it is warm outside, then it is summer
Answer:
A. If it is warm outside, then it is summer
Step-by-step explanation:
statement "If it is summer, then it is warm outside" : warm=summer
A. If it is warm outside, then it is summer. : warm = summer ✓
B. If it is not warm outside, then it is summer. : not warm = summer x
C. If it is warm outside, then it is not summer. : warm =not summer x
D. If it is not warm outside, then it is not summer. : not warm = not summer x
calculate the area and leave your answer in term of pie
Answer: [tex]2.25\sqrt{3}[/tex]
Not sure what you mean by terms of pi, unless you want us to find the area of the sector, not the triangle.
Step-by-step explanation:
Assuming you mean the area of the triangle...
First draw an altitude from the 120 degree angle to the opposite base. You will find that the altitude will also be a median. This forms 2 30-60-90 right triangles. Thus, the height of the altitude is 1.5 and the base of the triangle is 1.5*root3. Thus, the base of the triangle is [tex]3\sqrt{3}[/tex] and the height is 1.5. Thus, the area of the triangle is [tex]2.25\sqrt{3}[/tex]
1. Following is the Receipt and Payment A/c. of a club for the year ended 31-03-2014.
Receipt ₹ Payment ₹
To Balance b/d 75,000 By Salaries 22,000
To Subscription By office expenses 8,000
2012-13 35,000 By Sports equipment
2013-14 9,50,000 (Purchased on 1-10-2013) 6,00,000
2014-15 55,000 10,40,000 By Telephone charges 12,000
To Donation 90,000 By Electricity charges 18,000
To Entrance Fees 60,000 By Travelling Expenses 6,000
To Locker rent 20,000 By 10% Fixed Deposit
To Donation for Building 1,50,000 (made on 1-07-2013) 7,00,000
By balance c/d. 69,000
14,35,000 14,35,000
Additional information:
a) Outstanding subscription for 2013-14 ₹80,000. Outstanding salaries as on 1-04-2013 were ₹2,000 and as on 31-03-2014 were ₹4,000.
b) One third of Entrance fee to be treated as General income.
c) Locker rent rate is ₹2,000 per month.
d) Depreciation on sports equipment 10% p.a.
Prepare Income and Expenditure A/c. for the year ending 31-03-2014.
Answer:
Excess of income over expenditure is ₹1,185,500.
Step-by-step explanation:
Note: The data in this question are merged together. They are therefore sorted before answering this question. See the attached pdf file for the sorted question.
The question is now answered as follows:
Question: Prepare Income and Expenditure A/c. for the year ending 31-03-2014.
Answer and explanation:
Note: See the attached excel file for the Income and Expenditure A/c. for the year ending 31-03-2014.
Both receipts and payments account and income and expenditure account are prepared by not-for-profit organizations such as charity organizations, human right campaign, clubs, etc.
Receipts and payments account is an account gives a summary of all the cash transitions, cash received and paid, that the organization engaged in during a particular period. It is similar to the cash book prepared by profit making organizations. The receipts and payments account is prepared in or to determine the balance of cash in hand or at bank or bank overdraft at the end of the period.
Income and expenditure account is an account gives a summary of all incomes and expenses of an organization during a particular period. It is similar to the trading and profit and loss account prepared by profit making organizations. The income and expenditure account is prepared in order to determine whether there is a surplus or a deficit balance during the period.
A spinner has six spaces that are all the same size. Three spaces are yellow, two are red, and one is blue. If the spinner is spun 150 times, it should land on yellow about ___ times, on red about ___ times, and on blue ___ times.
The spinner should land on yellow about 75 times, on red about 50 times, and on blue about 25 times.
How to solve the probabilityYellow: 3 spaces out of 6, so the probability is 3/6 = 1/2
Red: 2 spaces out of 6, so the probability is 2/6 = 1/3
Blue: 1 space out of 6, so the probability is 1/6
multiplying the probability of each color by 150:
Yellow: 1/2 * 150 = 75 times
Red: 1/3 * 150 = 50 times
Blue: 1/6 * 150 = 25 times
Terefore The spinner should land on yellow about 75 times, on red about 50 times, and on blue about 25 times.
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Suppose that Mike invests $5000 into an account that pays 12% interest compounded
continuously. He wants to know how many years it will take for his investment to double and be worth
$10,000. Can Mike solve the following equation to find his answer? Why or why not?
2 = e 120. Solve the equation listed in the question above for t. First find the exact answer. Then
approximate your answer to three decimal places
Answer:
t = log(2)/0.12 years (exact value)
= 5.776 years (to three decimal places)
Step-by-step explanation:
The future value of an amount P at continuous interest rate i% for t years can be calculated using the continuous interest formula:
FV = Pe^((i)t)
where e is the Euler's constant = 2.7182818284....
We're given
10000 = 5000 e^((0.12)t)
simplify
2 = e^(0.12t) ........................ see below
[ please compare if this is the same as the one shown in the original question, the formula posted as "2 = e 120" does not look right, probably because of typographical difficulties, then answer if the equation given in the question can be used to solve the problem]
take (natural) log using the power property of logarithms
log(2) = 0.12t log(e)
using natural log, log(e) = 1
log(2) = 0.12t
simplify
t = log(2)/0.12 years (exact value)
To obtain the time (in years)
t = log(2)/0.12 = 0.6931/0.12 = 5.7762 years
Check using the rule of 72 (approximate)
72/12(%) = 6,
Since continuous interest accumulates interest faster, so 5.8 years sound reasonable.
La suma de dos números es 50 y la diferencia es 22. ¿Cuáles son los números?
Answer:
(3,2)
Step-by-step explanation:
Just took the test
What is the product of 7/16 and -6/13 I will make you the brainlest
Answer:
[tex]\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}[/tex]
Step-by-step explanation:
[tex]\frac{7}{16} *\frac{-6}{13} = \frac{-42}{208}[/tex] . First multiply 7*-6=-42.
Then do 16*13=208.
Simplify by dividing both by 2.
You get [tex]\frac{-42}{208}=\frac{-21}{104}[/tex].
Your final simplified answer is [tex]\frac{-21}{104}[/tex]
I hope this helps!
The length of time a full length movie runs from opening to credits is normally distributed with a mean of 1.9 hours and standard deviation of 0.3 hours. Calculate the following: A random movie is between 1.8 and 2.0 hours. A movie is longer than 2.3 hours. The length of movie that is shorter than 94% of the movies
Answer:
0.260.911.43Step-by-step explanation:
given data
mean = 1.9 hours
standard deviation = 0.3 hours
solution
we get here first random movie between 1.8 and 2.0 hours
so here
P(1.8 < z < 2 )
z = (1.8 - 1.9) ÷ 0.3
z = -0.33
and
z = (2.0 - 1.9) ÷ 0.3
z = 0.33
z = 0.6293
so
P(-0.333 < z < 0.333 )
= 0.26
so random movie is between 1.8 and 2.0 hours long is 0.26
and
A movie is longer than 2.3 hours.
P(x > 2.3)
P( [tex]\frac{x-\mu }{\sigma}[/tex] > [tex]\frac{2.3-\mu }{\sigma}[/tex] )
P (z > [tex]\frac{2.3-1.9 }{0.3}[/tex] )
P (z > 1.333 )
= 0.091
so chance a movie is longer than 2.3 hours is 0.091
and
length of movie that is shorter than 94% of the movies is
P(x > a ) = 0.94
P(x < a ) = 0.06
so
P( [tex]\frac{x-\mu }{\sigma }[/tex] < [tex]\frac{a-\mu }{\sigma }[/tex] )
[tex]\frac{a-1.9 }{0.3 } = -1.55[/tex]
a = 1.43
so length of the movie that is shorter than 94% of the movies about 1.4 hours.
29 point plus brainiest
The function f(x) = −x2 − 7x + 30 shows the relationship between the vertical distance of a diver from a pool's surface f(x), in feet, and the horizontal distance x, in feet, of a diver from the diving board. What is a zero of f(x), and what does it represent?
x = 10; the diver hits the water 10 feet away horizontally from the board.
x = 3; the diver hits the water 3 feet away horizontally from the board. x = 10; the diver jumps in the pool at 10 feet per second.
x = 3; the diver jumps in the pool at 3 feet per second.
this is your answer..................
In how many ways can you arrange 4 different colored balls? 4,8,4!,3!,5!
Answer:
We can arrange 4 different colored balls in 24 ways.
Step-by-step explanation:
We have to find the number of ways in which we can arrange 4 different colored balls.
Firstly, we have to decide that either we use Permutation or we use Combination.
A Permutation is used when the order of arranging the numbers matters while on the other hand, a combination is used when the order of arranging the numbers doesn't matter.
So, in our question; the ordering matters to us as a ball which is placed in the first place can't be put again put in other places.
Number of ways of arranging 4 different colored balls = [tex]^{4}P_4[/tex]
= [tex]\frac{4!}{(4-4)!}[/tex] {[tex]\because ^{n} P_r = \frac{n!}{(n-r)!}[/tex] }
= 4! = [tex]4 \times 3 \times 2\times 1[/tex]
= 24 ways
Hence, we can arrange 4 different colored balls in 24 ways.
A cylindrical container with a radius of 5 cm and a height of 14 cm is completely filled with liquid. Some of the liquid from the cylindrical container is poured into a cone–shaped container with a radius of 6 cm and a height of 20 cm until the cone–shaped container is completely full. How much liquid remains in the cylindrical container? (1 cm3 = 1 ml)
Answer:
Volume left in the cylinder if all the cone is made full:
[tex]\bold{345.72 \ ml }[/tex]
Step-by-step explanation:
Given
Radius of cylinder = 5 cm
Height of cylinder = 14 cm
Radius of cone = 6 cm
Height of cone = 20 cm
To find:
Liquid remaining in the cylinder if cone is made full from cylinder's liquid.
Solution:
We need to find the volumes of both the containers and find their difference.
Volume of cylinder is given by:
[tex]V_{cyl} = \pi r^2h[/tex]
We have r = 5 cm and
h = 14 cm
[tex]V_{cyl} = \dfrac{22}{7} \times 5^2\times 14 = 1100 cm^3[/tex]
Volume of a cone is given by:
[tex]V_{cone} = \dfrac{1}{3}\pi r^2h = \dfrac{1}{3}\times \dfrac{22}{7} \times 6^2 \times 20 = \dfrac{1}{3}\times \dfrac{22}{7} \times 36 \times 20 = 754.28 cm^3[/tex]
Volume left in the cylinder if all the cone is made full:
[tex]1100-754.28 =345.72 cm^3\ OR\ \bold{345.72 \ ml }[/tex]
Identify the zeros of f(x)= (x-7)(x+4)(3x-2) Choices:
Answer:
second option
Step-by-step explanation:
Given
f(x) = (x - 7)(x + 4)(3x - 2)
To find the zeros let f(x) = 0, that is
(x - 7)(x + 4)(3x - 2) = 0
Equate each factor to zero and solve for x
x - 7 = 0 ⇒ x = 7
x + 4 = 0 ⇒ x = - 4
3x - 2 = 0 ⇒ 3x = 2 ⇒ x = [tex]\frac{2}{3}[/tex]
zeros are x = - 4, x = [tex]\frac{2}{3}[/tex], x = 7
Which one of the following would most likely have a negative linear correlation coefficient? A. the value of a car compared to its age B. the points scored by a basketball player compared to his minutes played C. the height of a woman compared to her age D. the hours of daylight in a city throughout The year
Answer:
B. the points scored by a basketball player compared to his minutes played
Step-by-step explanation:
hamid has three boxes of different fruits. Box A weighs 5/4 kg more than Box B and Box C weighs 41/4 kg more than Box B. The total weight of the three boxes is 195/4 kg. What is weight of box a
Answer:
The answer is 39 kg
Step-by-step explanation:
We are looking for the weight of box A so we will use the number given to use for Box A.
We also have the total which is 194/4 kg
If we divide 195 by 5 we will get 39 kg
But to check if your answer is correct also divide 195 by 41 and that will give us 4.75 kg
And if you add the two answers up your will get 43.75 kg
Now we need to find the weight of Box B to see if our answer is correct
When you subtract 43.75 from 195 you will get 151.25
When we will add 43.75 to 151.25 you will get 195
So the answer is correct, the answer is 39 Kg
***Will mark all right answers brainliest*** A certain type of bacteria is being grown on a Petri dish in the school’s biology lab. Inez does some measurements and determines that the area of the bacteria covering the Petri dish is doubling each day. She started the bacteria colony on February 9 and predicts that it will cover the entire Petri dish by February21 . If 100% of the Petri dish is covered after 12 days have passed, what percentage was covered on the starting day? Use your equation from part (b) plz explain
Answer:
On day 0 (starting day), the percentage of petri dish occupied by bacteria was 2.44%
Step-by-step explanation:
Rate of growth = 2 (i.e. doubles every day)
Petri dish was filled to 100% on day 12.
Let
P(0) = percentage of Petri dish occupied on day 0, then
equation of percentage a function of time in x days
P(x) = P(0)*r^x ......................(1)
where
100% = P(12) = p(0) * 2^12 = 4096 P(0)
=>
P(0) = 100% / 4096 = 0.0244%
Next, to find percentage on February 14 (Valentine's day!)
Day 0 is February 9, so February 14 is the fifth day, so x=5.
Substitute x=5 in equation (1) above,
P(x) = P(0)*r^x
P(5) = P(0)*2^5
P(5) = 0.0244*2^5 = 0.0244*32 = 0.781%
Ans. the 0.781% of the petri dish was filled with bacteria after 5 days on February 14th.
Answer:
0.0244%
Step-by-step explanation:
A = p(1 + r)^t
The future amount is 100, for 100 percent. From February 9 to February 21, there are 12 days. The rate of growth is 100% since the amount doubles each day. t = 12, for 12 days. p = beginning percentage.
100 = p(1 + 1)^12
log 100 = log [p(1 + 1)^12]
2 = log p + 12 log 2
log p = 2 - 12 log 2
p = 10^(2 - 12log 2)
p = 0.0244
Answer 0.0244%
Which of the following shows the true solution to the logarithmic equation 3 log Subscript 2 Baseline (2 x) = 3 x = negative 1 x = 1 x = negative 1 and x = 1 x = 0, x = negative 1, and x = 1
Answer:
x = 1
Step-by-step explanation:
Using the rules of logarithms
log [tex]x^{n}[/tex] ⇔ n log x
[tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]
Given
3[tex]log_{2}[/tex] (2x) = 3
[tex]log_{2}[/tex] (2x)³ = 3
(2x)³ = 2³
8x³ = 8 ( divide both sides by 8 )
x³ = 1 ( take the cube root of both sides )
x = 1
Answer:
x=1 is the correct answer
Step-by-step explanation:
got it right on edge!!!!
Help please!!!!!!!!!!!!
Answer:
1/3
Step-by-step explanation:
Let's say you picked the blue one first. You have a 2/3 chance of doing that, and now you're left with 2. Now, to pick the green one, you have a 1/2 chance. Multiply that and you see that you have a 1/3 chance of picking it last.
Answer:
1/3.
Step-by-step explanation:
The probability that the red cube WON'T be picked on the first draw is 2/3. This is because there is a 1/3 probability of picking a green cube, added to a 1/3 probability of picking a blue cube.
The probability that the red cube WON'T be picked on the second draw is 1/2. This is because one cube has already been picked, so there are two remaining. You can only pick one of the two.
(2/3) * (1/2) = (2 * 1) / (3 * 2) = 2 / 6 = 1/3.
Hope this helps!
what is the range of the function: h(x)=x+1/x^2 - 7x+10
Answer:
(-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)
Step-by-step explanation:
To make it easier to differentiate, we'll rewrite the function as ...
h(x) = 2/(x-5) -1/(x-2)
Then the derivative is ...
h'(x) = -2/(x-5)^2 +1/(x-2)^2
This will be zero when ...
-2(x-2)^2 +(x-5)^2 = 0
-2(x^2 -4x +4) +(x^2 -10x +25) = 0
-x^2 -2x +17 = 0
x^2 +2x +1 = 17 +1
x +1 = ±√18 = ±3√2
x = -1 ±3√2
The values of the function at these locations are ...
h(-1-3√2) = -1 +(2/3)√2 ≈ -1.9428
h(-1+3√2) = -1 -(2/3)√2 ≈ -0.0572
Then the range of h(x) is ...
(-∞, -1-(2/3)√2] ∪ [-1+(2/3)√2, ∞)
Suppose a geyser has a mean time between eruptions of 72 minutes. Let the interval of time between the eruptions be normally distributed with standard deviation 23 minutes. Complete parts (a) through (e) below.
(a) What is the probability that a randomly selected time interval between eruptions is longer than 82minutes? The probability that a randomly selected time interval is longer than 82 minutes is approximately nothing. (Round to four decimal places as needed.)
(b) What is the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 minutes? The probability that the mean of a random sample of 13 time intervals is more than 82 minutes is approximately nothing. (Round to four decimal places as needed.)
(c) What is the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes? The probability that the mean of a random sample of 34 time intervals is more than 82 minutes is approximately nothing. (Round to four decimal places as needed.)
(d) What effect does increasing the sample size have on the probability? Provide an explanation for this result. Fill in the blanks below. If the population mean is less than 82 minutes, then the probability that the sample mean of the time between eruptions is greater than 82 minutes ▼ increases decreases because the variability in the sample mean ▼ decreases increases as the sample size ▼ decreases. increases.
(e) What might you conclude if a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes? Select all that apply.
A. The population mean may be less than 72.
B. The population mean must be more than 72, since the probability is so low.
C. The population mean cannot be 72, since the probability is so low.
D. The population mean is 72, and this is just a rare sampling.
E. The population mean may be greater than 72.
F. The population mean is 72, and this is an example of a typical sampling result.
G. The population mean must be less than 72, since the probability is so low.
Answer:
(a) The probability that a randomly selected time interval between eruptions is longer than 82 minutes is 0.3336.
(b) The probability that a random sample of 13-time intervals between eruptions has a mean longer than 82 minutes is 0.0582.
(c) The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes is 0.0055.
(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.
(e) The population mean must be more than 72, since the probability is so low.
Step-by-step explanation:
We are given that a geyser has a mean time between eruptions of 72 minutes.
Also, the interval of time between the eruptions be normally distributed with a standard deviation of 23 minutes.
(a) Let X = the interval of time between the eruptions
So, X ~ N([tex]\mu=72, \sigma^{2} =23^{2}[/tex])
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time = 72 minutes
[tex]\sigma[/tex] = standard deviation = 23 minutes
Now, the probability that a randomly selected time interval between eruptions is longer than 82 minutes is given by = P(X > 82 min)
P(X > 82 min) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{82-72}{23}[/tex] ) = P(Z > 0.43) = 1 - P(Z [tex]\leq[/tex] 0.43)
= 1 - 0.6664 = 0.3336
The above probability is calculated by looking at the value of x = 0.43 in the z table which has an area of 0.6664.
(b) Let [tex]\bar X[/tex] = sample mean time between the eruptions
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time = 72 minutes
[tex]\sigma[/tex] = standard deviation = 23 minutes
n = sample of time intervals = 13
Now, the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 minutes is given by = P([tex]\bar X[/tex] > 82 min)
P([tex]\bar X[/tex] > 82 min) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{82-72}{\frac{23}{\sqrt{13} } }[/tex] ) = P(Z > 1.57) = 1 - P(Z [tex]\leq[/tex] 1.57)
= 1 - 0.9418 = 0.0582
The above probability is calculated by looking at the value of x = 1.57 in the z table which has an area of 0.9418.
(c) Let [tex]\bar X[/tex] = sample mean time between the eruptions
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean time = 72 minutes
[tex]\sigma[/tex] = standard deviation = 23 minutes
n = sample of time intervals = 34
Now, the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes is given by = P([tex]\bar X[/tex] > 82 min)
P([tex]\bar X[/tex] > 82 min) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{82-72}{\frac{23}{\sqrt{34} } }[/tex] ) = P(Z > 2.54) = 1 - P(Z [tex]\leq[/tex] 2.54)
= 1 - 0.9945 = 0.0055
The above probability is calculated by looking at the value of x = 2.54 in the z table which has an area of 0.9945.
(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.
(e) If a random sample of 34-time intervals between eruptions has a mean longer than 82 minutes, then we conclude that the population mean must be more than 72, since the probability is so low.
Answer:
The probability that a randomly selected time interval between eruptions is longer than 82minutes = [tex]0.3336[/tex]The probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 minutes = [tex]0.0594[/tex]The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 minutes = [tex]0.0057[/tex]Step-by-step explanation:
From the given data
mean, u = 72
Standard deviation [tex]\rho[/tex] = 23
A) Probability that a randomly selected time interval between eruptions is longer than 82minutes
[tex]P (x > 82) = P[\frac{x-u}{\rho} > \frac{82-72}{23}]\\\\P (x > 82) = P[z > 0.43]\\\\P (x > 82) = 0.3336[/tex]
B)
[tex]P (x > 82) = P[\frac{x-u}{\frac{\rho}{\sqrtn}} > \frac{82-72}{\frac{23}{\sqrt{13}}}]\\\\P (x > 82) = P[z > 1.5676]\\\\P (x > 82) = 0.0594[/tex]
C)
[tex]P (x > 82) = P[\frac{x-u}{\frac{\rho}{\sqrtn}} > \frac{82-72}{\frac{23}{\sqrt{34}}}]\\\\P (x > 82) = P[z > 2.5351]\\\\P (x > 82) = 0.0057\\\\[/tex]
D) If the mean is less than 82minutes, then the probability that the sample mean of the time between eruptions is greater than 83 minutes decrease because the variability in the sample mean decrease as the sample size increases
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To work out the area in m² of material required for a pair of curtains, a seamstress squares the height of the window in m and adds 0.5.
a) What area of material is required for a window of height 1.2meters?
b) What area of material is required for a window of height p meters?
c) if the area of material required is 2.75m²,what is the height of the window?
Answer:
a. Area = 1.94m²
b. Area = (p² + 0.5)m²
c. Height = 1.5m
Step-by-step explanation:
Given
Let H represents Height and A represents Area
From the first and second statements, we have that:
[tex]A = H^2 + 0.5[/tex]
a. Calculating Area When Height = 1.2
[tex]A = H^2 + 0.5[/tex]
Substitute 1.2 for H
[tex]A = 1.2^2 + 0.5[/tex]
[tex]A = 1.44 + 0.5[/tex]
[tex]A = 1.94[/tex]
Hence, the area is 1.94m²
b. Calculating Area When Height = p
[tex]A = H^2 + 0.5[/tex]
Substitute p for H
[tex]A = p^2 + 0.5[/tex]
Hence, the area is (p² + 0.5)m²
c. Calculating Height When Area = 2.75m²
[tex]A = H^2 + 0.5[/tex]
Substitute 2.75 for A
[tex]2.75 = H^2 + 0.5[/tex]
Subtract 0.5 from both sides
[tex]2.75 - 0.5 = H^2 + 0.5 - 0.5[/tex]
[tex]2.75 - 0.5 = H^2[/tex]
[tex]2.25 = H^2[/tex]
Take Square Root of both sides
[tex]\sqrt{2.25} = \sqrt{H^2}[/tex]
[tex]\sqrt{2.25} = H[/tex]
[tex]1.5 = H[/tex]
[tex]H = 1.5[/tex]
Hence, the height is 1.5m
FI = 20 IH = 19. Calculate the length of GI
Answer:
7.55
Step-by-step explanation:
3/x = x/19
x² = 57
x = 7.54983....
HELP HELP HELP,The length of the one of the legs of a right triangle is 8m and the hypotenuse is 12m. Which of the following choices is the length of the other leg? 5 4 5 None of these choices are correct.
Answer:
4[tex]\sqrt{5}[/tex]
Step-by-step explanation:
the third leg is of the length 4[tex]\sqrt{5}[/tex]
A climbing structure needs to be built in the shape of a square-based pyramid. Look at the diagram below. What is the perimeter of the flat, orange shape? PLEASE HELP A GIRL OUT
Answer:
40 m
Step-by-step explanation:
The perimeter of the flat, orange shape is the sum of all the sides that forms a boundary around the shape.
The shape is made up of 4 triangles having 2 equal side lengths each, which surrounds the center square.
Each side length of the triangle, that forms a boundary round the shape = 5 m.
There are 8 of this equal side length.
Perimeter = 8(5m) = 40 m
Simplify: 34w-(-8w)
Answer: 42w
Step-by-step explanation:
Subtracting a negative is like adding.
MATH HELP ME ASAP!!!!
Answer: Zak - Resp after 24 months = $4,344.00
Zak - Technology Fund after 24 months = $1,102.98
Zak's Technology Fund has enough money to buy a laptop.
Zak's Savings (Resp) will last less than 6 months
Step-by-step explanation for Zak:
January - June 2019
$15/hr x 20 hr x 4 wks x 6 months = $7200 Gross Income
Resp (15%): $7200(0.15) = $1080CPP(5%): $7200(0.05) = $360EI(2%): $7200(0.02) = $144Taxable Income is $7200 - $1080 = $6120 (Annual Income $12,240)
Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,120-$4,500)(0.08) = $129.60→ $7,200 - ($1080 + $360 + $144 + $0 + $129.60) = $5,486.40 Net Income
Tech Fund (5%): $5486.40(0.05) = $274.32
Food Expense (30%): $5486.40(0.3) = $1,645.92
Clothing Expense (30%): $5486.40(0.3) = $1,645.92
Entertainment Expense (25%): $5486.40(0.25) = $1,371.60
Miscellaneous Expense (10%): $5486.40(0.1) = $548.64
Other Expenses: $5,212.08
July - December 2019 (excluding August)
$16/hr x 20 hr x 4 wks x 5 months = $6400 Gross Income
Resp (15%): $6400(0.15) = $960CPP(5%): $6400(0.05) = $320EI(2%): $6400(0.02) = $128Taxable Income is $6400 - $960 = $5440 (Annual Income $11,560)
Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($5,440-$4,500)(0.08) = $75.20→ $6,400 - ($960 + $320 + $128 + $0 + $75.20) = $4,916.80 Net Income
Tech Fund (5%): $4916.80(0.05) = $245.84
Food Expense (30%): $4916.80(0.3) = $1,475.04
Clothing Expense (30%): $4916.80(0.3) = $1,475.04
Entertainment Expense (25%): $4916.80(0.25) = $1,229.20
Miscellaneous Expense (10%): $4916.80(0.1) = $491.68
Other Expenses: $4,670.96
January - June 2020
$17/hr x 20 hr x 4 wks x 6 months = $8160 Gross Income
Resp (15%): $8160(0.15) = $1224CPP(5%): $8160(0.05) = $408EI(2%): $8160(0.02) = $163.20Taxable Income is $8160 - $1224 = $6936 (Annual Income $13,872)
Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,936-$4,500)(0.08) = $194.88→ $8,160 - ($1224 + $408 + $163.20 + $0 + $194.88) = $6,169.92 Net Income
Tech Fund (5%): $6169.92(0.05) = $308.50
Food Expense (30%): $6169.92(0.3) = $1,850.98
Clothing Expense (30%): $6169.92(0.3) = $1,850.98
Entertainment Expense (25%): $6169.92(0.25) = $1,542.48
Miscellaneous Expense (10%): $6169.92(0.1) = $616.98
Other Expenses: $5,861.42
July - December 2020 (excluding August)
$18/hr x 20 hr x 4 wks x 5 months = $7200 Gross Income
Resp (15%): $7200(0.15) = $1080CPP(5%): $7200(0.05) = $360EI(2%): $7200(0.02) = $144Taxable Income is $7200 - $1080 = $6120 (Annual Income $13,056)
Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,120-$4,500)(0.08) = $129.60→ $7,200 - ($1080 + $360 + $144 + $0 + $129.60) = $5,486.40 Net Income
Tech Fund (5%): $4916.80(0.05) = $274.32
Food Expense (30%): $5486.40(0.3) = $1,645.92
Clothing Expense (30%): $5486.40(0.3) = $1,645.92
Entertainment Expense (25%): $5486.40(0.25) = $1,371.60
Miscellaneous Expense (10%): $5486.40(0.1) = $548.64
Other Expenses: $5,212.08
[tex]\boxed{\begin{array}{l|r|r|r|r||r}\underline{ZAK}&\underline{Jan-Jun'19}&\underline{Jul-Dec'19}&\underline{Jan-Jun'20}&\underline{Jul-Dec'20}&\underline{Totals\quad }\\Gross&\$7200.00&\$6400.00&\$8160.00&\$7200.00&\$28960.00\\Resp&\$1080.00&\$960.00&\$1224.00&\$1080.00&\$4344.00\\Net&\$5486.40&\$4916.80&\$6169.92&\$5486.40&\$22059.52\\Other&\$5212.08&\$4670.96&\$5861.42&\$5212.08&\$20956.54\\Tech&\$274.32&\$245.84&\$308.50&\$274.32&\$1102.98\end{array}}[/tex]
Which set of points does NOT represent a function?
OA) (8,5), (7,5), (6,5), (5,5)
O B) (3,-5), (3, -1), (3, 2), (3, 4)
OC) (-2,3), (-3,2), (2, -3), (3, -2)
OD) (4, -1), (5, 1), (-1,4), (1,5)
Answer:
Answer A does not represent a function(I think)
Step-by-step explanation:
Because the Y-coordinates are the same.
22. “n is less than 15 and greater than or equal to 3”
Complete the following steps to receive full credit for this question:
• The inequality translated in numerical form
• The solution graphed on a number line
• The solution in interval form
Answer:
3 ≤ n < 15
not nnot nyes nyes nyes nyes nyes nyes nyes nyes nyes nyes nyes nyes nnot n1-2. not n
3-4. yes n
5-6. yes n
7-8. yes n
9-10. yes n
11-12. yes n
13-14. yes n
15-16. not n
Step-by-step explanation:
Everything on this side is less than, < but everything on this side is greater.
Everything on this side could be equal or less, ≤ but everything on this side is
not.
I'm had a hard time with the number line, but imagine a line going through the periods and there being a dot where the yes ns end, and start.
Intervals has each point represent more than one number making the line shorter.
Determine the solution to the following set of linear equations by using the graph below
a) 2x + y = 5
2x - 2y = 2
Answer:
(2,1)
Step-by-step explanation:
Well first we single out y or x in one of the equations,
we’ll use 2x + y = 5 and single out y.
2x + y = 5
-2x to both sides
y = -2x + 5
So we can plug in -2x + 5 into y in 2x - 2y = 2.
2x - 2(-2x + 5) = 2
2x + 4x - 10 = 2
combine like terms,
6x - 10 = 2
Communicarice property
+10 to both sides
6x = 12
divide 6 to both sides
x = 2
If x is 2 we can plug 2 in for x in 2x + y = 5.
2(2) + y = 5
4 + y = 5
-4 to both sides
y = 1
(2,1)
Thus,
the solution is (2,1).
Hope this helps :)
In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music, if the total of 55 students got medals and only 6 students got medals in the three categories ,how many students get medals in exactly two of these categories?
Answer:
210
Step-by-step explanation:
Given:
Medals in sports = 40
Medals in dance = 25
Medals in music = 212
Total students that received medals = 55
Total students that received medals in all three categories = 6
Required:
How many students get medals in exactly two of these categories?
Take the following:
A = set of persons who got medals in sports.
B = set of persons who got medals in dance
C = set of persons who got medals in music.
Therefore,
n(A) = 40
n(B) = 25
n(C) = 212
n(A∪B∪C)= 55
n(A∩B∩C)= 6
To find how many students get medals in exactly two of these categories, we have:
n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)
=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)
n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)
Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)
Using equation 1:
=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18
Substitute values in the equation:
= 40 + 25 + 212 + 6 − 55 − 18
= 283 - 73
= 210
Number of students that get medals in exactly two of these categories are 210
Which two features of igneous rocks are determined by their cooling rate?
color and shininess
shininess and hardness
hardness and crystal size
crystal size and rock texture
Answer:
crystal size and rock texture D
Step-by-step explanation:
:)
Hence, the option (D) is the correct answer i.e., crystal size and rock texture.
What is the texture?
The texture is defined as a tactile quality of an object's surface. It appeals to our sense of touch, which can evoke feelings of pleasure, discomfort, or familiarity.
The texture of an igneous rock is dependent on the rate of cooling of the melt slow cooling allows large crystals to form, fast coolng yields small crystals.
Hence, the option (D) is the correct answer i.e., crystal size and rock texture.
To know more about the texture
https://brainly.com/question/14375831
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