An Introduction To Chemistry

 

Answer Sheet

 

 

Please provide your answer in the answer sheets!

 

 

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An Introduction To Chemistry

 

 

1. During his distinguished career this scientist received two unshared Nobel prizes. One for chemistry and one for peace.

Alfred Nobel

Marie Currie

Linus Pauling

Albert Einstein

 

2. The study of matter and the changes it undergoes describes the science of ______.

physics

mathematics

chemistry

biology

 

3. The _________ is the fundamental unit of matter.

atom

compound

nucleus

proton

 

4. The atom is composed of three subatomic particles known as _____, ____ and _______.

neutrals, electives and peeons

quarks, alpha rays and xenons

electrons, protozoans and electricals

protons, neutrons and electrons

 

5. Protons are _________ charged particles found in the nucleus of an atom.

neutrally

positively

negatively

brighltly

 

6. Electrons are ________ charged particles that orbit the nucleus of an atom.

negatively

positively

neutrally

brighltly

 

7. Neutrons are ________ particles found in the nucleus of an atom.

negatively charged

positively charged

uncharged

brightly

 

8. An ion is an atom or molecule that ___________.

is electrically neutral

is composed of two or more elements

is man made

carries a charge

 

9. Which of the following chemical species is a cation?

Cl-

H+

Au

HCO3-

 

10. The atomic number of an atom or element describes the number of _______.

electrons orbiting the nucleus

neutrons in the nucleus

alpha particles in the nucleus

protons in the nucleus

 

11. Mass is proportional to the number of _________ that make up an object.

atoms

cells

neutrons

protons

 

12. Weight is best described as _____________.

the number of atoms in an object

the pull of gravity on matter

the electrical charge on an ion

the number of electons in an atom

 

13. Atoms of any one type of element, such as gold, all posess the same number of _______.

electrons

neutrons

protons

nuclei

 

14. There are currently _______ known elements.

65

98

112

152

 

15. Element _______ are one or two letter abbreviations for the names of the elements.

numbers

atomic numbers

symbols

characters mass

 

16. Two or more elements that combine as a result of a chemical reaction form _____.

atoms

ions

mixtures

compounds

 

17. An example of a mixture would be __________.

a bar of pure gold

the air we breathe

sodium chloride salt

pure water

 

18. The three states of matter are ________, ________ and _________.

atoms, molecules and compounds

atoms, compounds and mixtures

solids, liquids and gases

solids, gases and steam

 

19. The least dense and most energetic of the three states of matter is ____.

the gaseous state

the liquid state

the solid state

the elemental state

 

20. All measurements must consist of both ____________.

a size and a shape

a price and a volume

a number and a unit

a color and a number

 

21. Density is a physical property that refers to _____________.

the number of atoms in an object

the weight of an object

the mass of an object relative to its volume

the weight of an object relative to its cost

 

22. A kilogram is equal to ________ grams.

1

10

100

1,000

 

23. There are _______ centimeters in a meter.

1

10

100

1,000

 

24. Measurements are _________ because of equipment error and human judgment.

useless

uncertain

perfect

inaccurate

 

25. The number 221.5 contains ______ significant figure(s).

1

2

3

4

 

26. The number .001 contains ______ significant figure(s).

1

2

3

4

 

27. The number 226 would be scientifically noted as ______.

226

2.26 x101

2.26 x 102

22.6 x 101

 

28. The figure .005 would be scientifically noted as _______.

5 x 10-1

5 x 10-2

5 x 10-3

5 x 10-4

 

29. Elements or atoms are arranged on the periodic table in the order of increasing ________.

atomic mass

atomic weight

atomic number

atomic symbols

 

30. A substance that weighs 10 grams and has a volume of 2 cm3 would have a density of ______.

5 g/cm3

10g/cm3

2g/cm3

15g/cm3

 

31. The terms Kelvin, Celsius and Fahrenheit all correspond to units of _______.

density

hardness

volume

temperature

 

32. The ________ is the SI standard unit for measurements of length.

cetimeter

foot

meter

yard

 

33. One kilogram is equal to approximately ________ pounds.

1.2

2.2

3.2

4.2

 

 

 

 

 

 

 

 

 

 

 

 

 ​

Answers

Answer 1

1. C. Linus Pauling

2. C. chemistry

3. A. atom

4. D. protons, neutrons and electrons

5. B. positively

6. A. negatively

7. C. uncharged

8. D. carries a charge

9. C. Au

10. D. protons in the nucleus

11. A. atoms

12. B. the pull of gravity on matter

13. C. protons

14. C. 112

15. C. symbols

16. D. compounds

17. C. sodium chloride salt

18. C. solids, liquids, and gases

19. A. the gaseous state

20. C. a number and a unit

21. B. the weight of an object

22. D. 1,000

23. C. 100

24. B. uncertain

25. D. 4

26. A. 1

27.C. 2.26 x 102

28. C. 5 x 10-3

29. C. atomic number

30. A. 5 g/cm3

31. D. temperature

32. C. meter

33. B. 2.2


Related Questions

You want to produce a casting of sterling silver that is silver plus 13 atomic% copper. Pure silver is too soft for many applications and adding 13 atomic% copper strengthens the silver without significantly changing the color. To produce the sterling silver casting, you are going to melt commercially available pure silver and copper in a furnace, and then you will pour the liquid metal mixture into a mold. The following questions relate to this alloy. (a) In selecting a furnace, what must be the minimum value of the high-temperature capability of your selected furnace

Answers

Answer:

1085° C

Explanation:

From the phase diagram of Ag-Cu shown below:

The minimum value of the high-temp required to be selected for the furnace is: 1085° C

This is on the grounds that the furnace should be chosen to such an extent that it should melt any sort of possible material including pure Cu that melts and liquefies at the temperature of 1085° C.

Our most recent mass extension happened about 65million years ago. Describe the effects of this event.

Answers

Answer:

To explain what caused this mass extinction, scientists have focused on events that would have altered our planet's climate in dramatic, powerful ways. The leading theory is that a huge asteroid or comet slammed into Earth 65 million years ago, blocking sunlight, changing the climate and setting off global wildfires.

5. Element X exists as diatomic molecules.
In which group of the Periodic
Table is X placed?
A. Group O
B.
Group I
C.
Group II
D.
Group VII​

Answers

Element X Exists as diatomic molecules . In which group of the Periodic Table is X placed ?

Group VII

Group VII - elements are Fluorine , Chlorine , Bromine and Iodine .

They exist in diatomic molecules as F2 , Cl2 , Br2 and I2 .

What is the main difference between rain and hail?

Answers

Answer:

Rain is a liquid and hail is a solid.

2.56 x 10^13 molecules of HgO equates to how many moles of HgO?

Answers

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

[tex]n = \frac{2.56 \times {10}^{13} }{6.02 \times {10}^{23} } \\ \\ \\ = 4.25 \times {10}^{ - 11} \: \: \: moles[/tex]

Hope this helps you

Give the systematic (IUPAC) name for each molecule. This molecule has the condensed formula C H 3 C O C H 3. The oxygen atom has a double bond to the center carbon. systematic (IUPAC) name: This molecule has the condensed formula C H 3 C H 2 C H 2 C O C H 3. The oxygen atom has a double bond to carbon. systematic (IUPAC) name:

Answers

Answer: The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.

Explanation:

The basic rules for naming of organic compounds are :

1. First select the longest possible carbon chain. The longest possible carbon chain should include the carbons of double or triple bonds or functional group.For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

2. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and ketones by adding the suffix -one.;

3. The numbering is done in such a way that the carbon containing the functional group gets the lowest number. While writing the name, the word root is given first , followed by the position of carbon containing the functional group followed by the suffix.

The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.

When a thermometer is heated, the red liquid inside the thermometer moves up. This is mainly because:
A. The red liquid is thin.
B. The molecules of the liquid move faster and get a little further apart.
C. Hot liquid is lighter.
D. The glass of the thermometer gets hot.

Answers

C. Hot liquid is lighter.

The thermometers with red liquid usually depicts a kerosene based column with red dye. It is more safe than mercury thermometer. The red liquid inside the thermometer moves up due to the molecules of the liquid move faster and get a little further apart. The correct option is B.

What is thermometer?

The device which is used to measure the temperature is defined as the thermometer. It can measure the temperature of a solid such as food, a liquid like water and a gas like air.

The thermometers which are developed for clinical purposes are called clinical thermometers. It can also measure the temperature of human body. It is a long narrow glass tube which contain a bulb and consists of mercury at the end.

When a thermometer is heated, the molecules present in the liquid inside the thermometer get a little further apart. Because the liquid takes up more space. So the red line moves up in the tube.

Thus the correct option is B.

To know more about thermometer, visit;

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Biological membranes are selectively permeable, allowing certain molecules to cross the membrane, but not others. Classify the molecules or ions depending on how they cross a biological membrane. Note that some of these examples may also utilize active transport to traverse a membrane. However, this question is limited to passive transport processes only. Match the followings with each others

a. Simple Diffusion
b. Facilitated Diffusion

1. steroid hormones
2. K+
3. N2
4. Glucose

Answers

Answer:

Following are the solution to these question:

Explanation:

Simple diffusion implies which molecules can move across a cell membrane instead of using the incorporated protein structure channels. Its flow of molecules across these canals is enabled by diffusion. It has steroid hormones and N2.

Facilitated diffusion of molecules via cell membranes, or active transportation, which would be the random mass transit process of molecules or ions via unique cellular membranes from the transmembrane. It has K+ and Glucose.

Which material is likely to slow the flow of electric charges the most? Explain.

Answers

Answer:

copper hiiiiiiiiiiiii

Is anyone good at chemistry if so can someone help me please ?

(NO LINKS)

Answers

In general, salts (formed during a neutralization reaction) are ionic compounds that are soluble in water and dissociate in solution into ions that conduct electricity. Out of the six statements given, there are three related statements that rehash the foregoing, and there are three related statements that are collectively incorrect.

Statements A, B, and D are (generally) true regarding salts formed during a neutralization reaction. When you consider that the net ionic equation of many acid-base neutralization reactions is H⁺(aq) + OH⁻(aq) → H₂O(l), the counterions of the H⁺(aq) and OH⁻(aq) are the aqueous spectator ions that comprise the salt. These ions are electrolytes, as they are charged species that can carry a current in solution; they are ionic compounds by definition since they're composed of cations and anions; and, as aqueous species, they're clearly dissolved in water.

Statements C, E, and F, as a whole, generally aren't true of such salts.

What is total distance traveled?
What is the displacement (change in positions) ​

Answers

Answer:

Exercise 1

a)  140 m

b)  100 m

c)  180 m

d) 140 m

Exercise 2

a) 20 yards

b) 30 yards

c) 20 yards

d) 55 yards

Exercise 3

a)  11 Kilometers

b) 7 Kilometers

Explanation:

Exercise 1

Distance from B to C = 140 m

Distance from  to D = 100 m

Total distance = 100+40+40 = 180 m

Total displacement i.e. distance between A and D is 140 m

Exercise 2

a) Distance from B to C = 35 -15 = 20 yards

b) Distance from C to D  = 5 + 35  = 30 yards

c) Distance from B to D = 5 + 15 = 20 yards

d) Displacement = 5 + 50 = 55 yards

Exercise 3

a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers

b) Displacement = 5-2 + 4 = 7 Kilometers

If there is sufficient water in the reaction system, how many grams of KOH can be produced from 22.2 g of K?

Answers

Answer: 31.9 g of KOH can be produced from 22.2 g of KOH

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles[/tex]  

[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]  

According to stoichiometry :

2 moles of [tex]K[/tex] produce = 2 moles of [tex]KOH[/tex]

Thus 0.57 moles of [tex]K[/tex] will produce=[tex]\frac{2}{2}\times 0.57=0.57moles[/tex]  of [tex]KOH[/tex]

Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g[/tex]

Thus 31.9 g of KOH can be produced from 22.2 g of KOH

Calculate the pH of a solution prepared by dissolving 1.60 g of sodium acetate, CH3COONa, in 50.0 mL of 0.10 M acetic acid, CH3COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1.75 x 10^-5.

Answers

Answer:

pH = 5.35

Explanation:

Given 1.60 grams sodium acetate (NaOAc(aq))*** added to 50ml of 0.10M acetic acid (HOAc(aq)) solution.

Applying common ion effect keeping in mind that the addition of NaOAc provides the common-ion (OAc⁻).

      HOAc(aq) ⇄          H⁺(aq)            +                 OAc⁻(aq)

 I      0.10m          1.32 x 10⁻³M ≈ ∅M*     (1.6g/82.03g/mol) / 0.050L = 0.39M

 C       -x                         +x                                0.39M + x ≈ 0.39M**

 E    0.10M - x                  x                                    0.39M

       ≈ 0.10M

Ka = [H⁺][OAC⁻]/[HOAC] => [H⁺] = Ka·[HOAc] / [OAc⁻]

[H⁺] = (1.75 X 10⁻⁵)(0.10) / (0.39) = 4.5 x 10⁻⁶M

∴ pH = -log[H⁺] = -log(4.5 x 10⁻⁶) = -(-5.35) = 5.35

_______________________________________________

* [H⁺] before adding NaOAc = SqrRt(Ka · [HOAc]) = SqrRt(1.75 x 10⁻⁵· 0.10) = 1.32 x 10⁻³M. Since this concentration value is so small, the initial [H⁺] is assumed to be zero molar (∅M).

** The added [H⁺] is negligible and dropped in the ICE table. That is, adding ~[H⁺] in the order of 10⁻³M does not change the H⁺ ion concentration sufficiently to affect problem outcome and is therefore dropped in the ICE table.

*** Acetic Acid and Sodium Acetate are frequently written HOAc and NaOAc where the OAc⁻ anion is the acetate ion (CH₃COO⁻) for brevity.

The pH of the solution measures the acid of the liquid throughout the molar concentration of hydrogen ions in a solution.

[tex]\bold{CH_3COONa \ mass = 1.60\ g}\\\\[/tex]

Solution Volume (V) [tex]=50.0\ mL =0.05\ L\\\\[/tex]

[tex]\bold{CH3COONa \ molarity =0.10\ M }[/tex]

[tex]\bold{\text{Calculating the CH3COONa moles} =\frac{mass}{molar\ mass}}[/tex]

                                                       [tex]= \frac{1.60\ g}{82.03\frac{g}{mol}} \\\\=0.0195\ mol\\\\[/tex]

[tex]\bold{M = \frac{ \text{amount of solute moles} } { \text{solution volume in L} }}[/tex]

     [tex]= \frac{0.0195\ mol}{0.05\ L}\\\\ =0.39\ M[/tex]

Using Henderson Hasselbach equation:

[tex]\bold{pH = -\log K_{a} + \log{[salt]}{[acid]}}\\\\[/tex]

     [tex]=\bold{ -\log (1.75\times 10^{-5}) + \log ( \frac{0.39}{0.10}) }\\\\=\bold{ 4.757 + \log (3.9)}\\\\=\bold{ 4.757 + 0.5910}\\\\=\bold{ 5.348}\\\\=\bold{ 5.35}\\[/tex]

So, the final answer is "5.35".

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A ___________ ion is made of 2 or more atoms of different elements
O nuclear
O polyatomic
O magnetic
O mono-atomic

Answers

Answer: polyatomic

Explanation:hope you find helpful

A polyatomic is made of 2 or more atoms of different elements.

b) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
constant pressure?
C2H5OH burning in a simple alcohol lamp is -1277.3kJ/mol​

Answers

Answer:

Explanation:

You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.

This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.

Hhheppppp fffaaast
Mixture of water and LEAD SULPHATE is an example of Homogeneous mixture Select one : True O False​

Answers

Answer:

False

Explanation:

Lead sulfate is insoluble in water and sinks in water

(sorry if it's wrong)

What is the IUPAC name for the compound shown?

Answers

2-methyl-1,4-dibutal. That could be wrong but it looks right to me. Sorry if it isn’t righ

what are the two changes of state occurs during distillation​

Answers

Answer:

The changes of state occur during distillation are boiling followed by condensation. The liquid is converted into its vapor phase at its boiling point and the vapor is then condensed back to liquid on cooling.

Explanation:

Heart me pls

An inventor claims to have developed a new perfume that lasts a long time because it doesn't evaporate. Comment on this claim.
a. This would be impossible to make because the perfume would have to be pressurized in order to not evaporate.
b. This product is sure sweep the market making many happy customers.
c. In order to smell something, the molecules must evaporate and reach your nose. If the new perfume doesn't evaporate, it will not have an odor.
d. A perfume that does not evaporate could be toxic since the molecules never leave the skin.

Answers

Answer:

C

Explanation:

Perfume needs to evaporate in order to smell.  If this perfume didn't evaporate, it would stay as a liquid and never smell.  

It wouldn't be D, as no toxic perfumes is sold.

It's not A because perfume doesn't have to be pressurized in order to not evaporate.

It's not B, as it is a hasty conclusion to the claim.  Plus, if the perfume did have an odor, even while not evaporating, the sales would be low as the product is that good.  

How many moles are in 4.28 x 1023 atoms of carbon?

Answers

Answer:

0.711 moles C

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 4.28 × 10²³ atoms C

[Solve] moles C

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up:                                                                                                     [tex]\displaystyle 4.28 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})[/tex][DA] Divide [Cancel out units]:                                                                        [tex]\displaystyle 0.710727 \ moles \ C[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.710727 moles C ≈ 0.711 moles C

Identify the reactants and products in the following chemical equation: Zn +2HCl --> ZnCl2 + H2 *
20 points
A: Reactants: Zn & HCl Products: ZnCl2 & H2
B: Reactants: ZnCl2 & H2 Products: Zn & HCl
C: Reactants: Zn & H2 Products: ZnCl2 & HCl

Answers

Answer:

A.

Explanation:

zinc and hydrochloric acid reacts to form zinc chloride and hydrogen.

hope it helps. :)

Molecules on the surface of the ice escaping into the water happen in ————.

A. Boiling
B. Freezing
C. Condensation
D. Melting
E. Sublimation

Answers

D melting hope this was right

Given this slope equation, calculate the x-intercept (the point at which y = 0).

y = 0.523x + 16.8

Answers

Answer:

The answer is (-31.58, 0) when rounded to 2 decimal places.

2. A plant growing in response to the sunlight.
Gravitropism

Phototropism

Thigmotropism

Hydrotropism

Answers

Answer:

Phototropism.

Explanation:

Phototropism is the phenomenon of plants growing in response to light. This is a response to the plants to align or steer towards the source of sunlight, thereby becoming the 'path' to their growth.

The term "photo" means light and "tropism" means "growth" or movement towards". So, we can safely say that phototropism is the scientific and natural phenomenon of plants growing towards or in response to the sunlight.

Thus, the correct answer is phototropism.

Which substance has the highest ph?

A. Tomato
B. Unpolluted rainwater
C. Ammonium hydroxide
D. Orange juice

Answers

Answer:

c ammonium hydroxide nh4oh has higher ph value and its a base

plz mark me branliest

Answer:

c) ammonium hydroxide

Explanation:

ammonium hydroxide nh4oh has higher ph value, and it is an alkaline

if eleanor starts with 25.00 ml of a weak acid (the concentration is 0.1084 m), then how many ml of 0.1817 m naoh has to be added to reach the equivalence point

Answers

Answer:

14.91 mL

Explanation:

Assuming the weak acid is monoprotic, we can solve this problem using the equation:

C₁V₁=C₂V₂

Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.

We input the data:

25.00 mL * 0.1084 M = 0.1817 M * V₂

And solve for V₂:

V₂ = 14.91 mL

The volume of 0.1817 M NaOH has to be added to reach the equivalence point is 14.91 mL.

How we calculate the volume?

Volume for the given solution will be calculated from the below equation:

M₁V₁ = M₂V₂, where

M₁ = Molarity of weak acid = 0.1084 M

V₁ = volume of weak acid = 25 mL

M₂ = molarity of NaOH = 0.1817 M

V₂ = volume of NaOH = to find?

On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.1084)(25) / (0.1817) = 14.91 mL

Hence required volume is 14.91 mL.

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the maximum amount of copper sulfate that can be dissolved in 45.0g of water at 70C is 20.0g. what is the solubility of copper sulfate at that temperature?
(in grams per 100g water)​

Answers

Answer:

That depends on the amount. Solubility is the maximum amount of salt dissolved in 100 g of water. So, if the amount is within limit, then yes. Solubility of anhydrous copper sulfate is 24.3 g/100 g water, so it is not bad. Put it in perspective, the solubility of NaCl is about 35 g/100 g water at room temperature. If the amount of copper sulfate is unknown, qualitative I'd say solid copper sulfate will dissolve in water completely.

Explanation:

If you use the pentahydrate CuSO4.5H2O then the solubility at 20°C is 20.8g/100ml H2O

If you use the anhydride, CuSO4. then the solubility at 20°C is 36.2g/100ml H2O

When 4.088 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.82 grams of CO2 and 2.829 grams of H2O were produced.

In a separate experiment, the molecular weight of the compound was found to be 78.11 amu. Determine the empirical formula and the molecular formula of the hydrocarbon.

Answers

Answer:

Empirical formula: CH

Molecular formula: C₆H₆

Explanation:

Based on the combustion of a hydrocarbon, the moles of CO₂ = Moles of Carbon in the hydrocarbon and the moles of H₂O = 1/2 moles of hydrogen in the hydrocarbon.

The empirical formula is the simplest whole number of atoms present in a molecule. With the moles of C and H we can find empirical formula:

Moles C -Molar mass CO₂ = 44.01g/mol-:

13.82g * (1mol / 44.01g) = 0.314 moles C

Moles H -Molar mass H₂O = 18.01g/mol-:

2.829g H₂O * (1mol / 18.01g) = 0.157 moles H₂O * (2mol H / 1mol H₂O) = 0.314 moles of H

The ratio of moles H: moles C:

0.314 moles / 0.314 moles = 1

That means empirical formula is:

CH

With the molecular weight and empirical formula we can find the molecular formula:

Molar mass CH = 12.01g/mol+1.01g/mol = 13.02g/mol

As the molecular weight of the molecule is 78.11amu = 78.11g/mol, there are:

78.11g/mol / 13.02g/mol = 6 times the empirical formula in the molecular formula

That means molecular formula is:

C₆H₆

Two gases helium and x are released from one end of an evacuated long cylinder at the same time if it takes helium atoms 3 times faster than gas X to effuse from one end. What is gas X?

Answers

Answer:

Hypoflorous acid, HOF

Explanation:

From the question, we're told that the helium atoms effuses 3 times than the said gas X.

We can determine the rate of effusion by using the formula

r is inversely proportional to 1/√M, where M is the molecular mass of the gas.

And also,

r is inversely proportional to 1/t, where t is the time taken for effusion.

From both formulas I listed, we can conclude that t is directly proportional to √M. And thus we proceed.

The molecular mass of Helium is 4.

tHe = tX/3, where tx is the time taken for the unknown gas X

As of yet, we don't know the molecular mass of X. Next, we say that

tX/tHe =√Mx/MHe

3 = √Mx/4

If we square both the sides, to remove the square root, we have

9 = Mx/4

Mx = 36

The molecular mass of the unknown gas X is 36.

Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3

Answers

Answer:  4.22 grams of solute is there in 278 ml of 0.038 M [tex]Fe_2(SO_4)_3[/tex]

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in L

Now put all the given values in the formula of molality, we get

[tex]0.038M=\frac{n}{0.278L}[/tex]

[tex]n=0.0105mol[/tex]  

mass of  [tex]Fe_2(SO_4)_3[/tex] = [tex]moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g[/tex]

Thus 4.22 grams of solute is there in 278 ml of 0.038 M [tex]Fe_2(SO_4)_3[/tex]

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