Answer:
1. telescope
2.
[tex]f = \frac{r}{2} [/tex]
[tex]f = \frac{r}{2} [/tex]f- focal length
[tex]f = \frac{r}{2} [/tex]f- focal length r- the radius of curvature of the mirror
[tex] \frac{1}{f} = \frac{1}{p} + \frac{1}{l} [/tex]
p-the distance of the object from the vertex of the mirror
l-the distance of the figure from the vertex of the mirror
write short note : power
Answer:
In physics, power is the amount of energy transferred or converted per unit time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.
SI unit: watt (W)
Derivations from other quantities: P = E/t; P = F·v; P = V·I; P = τ·ω
In SI base units: kg⋅m2⋅s−3
Answer:
As a student, what are your insights about this lesson? Write an essay on your
toughts about the types of drugs/subtance of abuse, discussing its description and
effects
A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.
Answer:
The speed of the knife after passing through the target is 9.33 m/s.
Explanation:
We can find the speed of the knife after the impact by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]
Where:
[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg
[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg
[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s
[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s
[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?
[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)
Taking as a positive direction the direction of the knife movement, we have:
[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]
[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]
Therefore, the speed of the knife after passing through the target is 9.33 m/s.
I hope it helps you!
two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
Answer:
2 possible answers:
1# 2.5 Ω (when the resistors are in parallel)
2# 10 Ω (when the resistors are in series)
Explanation:
there are two possible answers for this:
1# if the resistors are in parallel in the circuit
then:
1/R-equivalent=1/5+1/5
1/R-equivalent=2/5
R-equivalent=5/2=2.5 Ω
2# if the resistors are in series in the circuit
then:
R-equivalent=5+5
R-equivalent=10 Ω
Two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
If connected in series :
R = R1 + R2
R = 5 + 5
R = 10 ohms
If connected in parallel :
R = 1/R1 + 1/R2
R = 1/ 5 + 1/5
= 2 / 5
= 2.5 ohms
What is equivalent resistance ?
"The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated." Essentially, the circuit is designed either in Series or Parallel. Electrical resistance shows how much energy one needs when you move the charges/current through your devices.
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if up is up and down is down isn't downside up , upside down
Answer:
No they arent because they are opposite to each other.
Which conversion can take place in a transformer
A. An electric current into a magnetic field
B. Electric energy into mechanical energy
C. Mechanical energy into electric energy
D. A lower voltage into a higher voltage
Answer:
D. A lower Voltage into a higher
Which device helps safely transmit electricity from the power plant to your
home?
Answer:
A. Transformer
Explanation:
it’s correct
How do y’all solve this
Answer:
you Subtract
Explanation:
A = 6
B = 6
C = 0
D = 5
9-3= 6
13-7=6
11-11=0
6-1=5
Simple hope it helps
1. A temperature of 162 °F is equivalent to what temperature in kelvins?
(a) 373 K
(b) 288 K
(C) 345 K
(d) 201 K (e) 308 K
345k
Because the formula for our Fahrenheit is Kevin = 5 * (°Fahrenheit + 459.67)
9.
what are the materials that you have illustrated?
Answer:
An illustration is a decoration, interpretation or visual explanation of a text, concept ... such as posters, flyers, magazines, books, teaching materials, animations, video games and films.
Explanation:
HELP ASAP PLEASE Comparing the types and amounts of EM radiation in an object could help scientists determine an object's what? structure age chemical composition all of the above are correct
Answer: Its all of the above
Explanation:
I had the same question and got it correct
A cardboard box has four forces acting upon it, as shown in the diagram below. What is the magnitude of the unknown force, Funknownacting on the box if the box is accelerating at 2.0 m/s 2 to the right?
(Answer choices)
A. 5N
B.6N
C.10 N
D. 11N
Question number 11 how did we found the answer ?
Answer:
Option A. 57.14 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 100 Ω
Resistor 2 (R₂) = 400 Ω
Resistor 3 (R₃) = 200 Ω
Equivalent Resistor (Rₚ) =?
The equivalent resistor in the above circuit can be obtained as follow:
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = 1/100 + 1/400 + 1/200
Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown
1/Rₚ = (4 + 1 + 2)/400
1/Rₚ = 7/400
Invert
Rₚ = 400/7
Rₚ = 57.14 Ω
For a satellite to orbit Earth at a constant distance, its centrifugal acceleration
must be equal and opposite Earth's gravitational acceleration. If a satellite is
to orbit at a constant distance from Earth at a circular radius of 8,300,000 m,
what is the required velocity of the satellite? (Assume the acceleration due to
Earth's gravity is 5.6 m/s2 at this altitude.)
A. 7043 m/s
B. 8239 m/s
C. 7576 m/s
D. 6818 m/s
If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,300,000, the required velocity of the satellite is 8239m/s.
What is a satellite?
Most spacecraft, with the exception of passive satellites, contain a means of generating electricity for the technology they carry, such as solar panels or radioisotope thermoelectric generators (RTGs). The majority of satellites also feature transponders, which are a type of ground station communication system. The most common satellites, small CubeSats, use a standardised bus to reduce costs and labour. Satellites of a similar type can cooperate with one another to form constellations.To know more about satellite, click the link given below:
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Mike is deciding which route to take to the beach. If he takes the highway, he can travel at an average velocity of 100 km/hr for 17 km. If he takes surface streets, he can travel at an average velocity of 70 km/hr for 10 km. Which is the faster route for Make to take?
Answer: Highway
Explanation:
The sum of the initial and final velocity is divided by 2 to find the average. The average velocity calculator uses the formula that shows the average velocity (v) equals the sum of the final velocity (v) and the initial velocity (u), divided by 2.
Which wave type could move in the empty space between the Sun and the Earth
Answer:
Electromagnetic waves
What is the wavelength associated with an electron with a velocity of 4.8X10s m/s? (Mass of the electron is 9.1X10-31kg)?
Answer:
1.52 nm
Explanation:
Using the De Broglie wavelength equation,
λ = h/p where λ = wavelength associated with electron, h = Planck's constant = 6.63 × 10⁻³⁴ Js and p = momentum of electron = mv where m = mass of electron = 9.1 × 10⁻³¹ kg and v = velocity of electron = 4.8 × 10⁵ m/s
So, λ = h/p
λ = h/mv
substituting the values of the variables into the equation, we have
λ = h/mv
λ = 6.63 × 10⁻³⁴ Js/(9.1 × 10⁻³¹ kg × 4.8 × 10⁵ m/s)
λ = 6.63 × 10⁻³⁴ Js/(43.68 × 10⁻²⁶ kgm/s)
λ = 0.1518 × 10⁻⁸ m
λ = 1.518 × 10⁻⁹ m
λ = 1.518 nm
λ ≅ 1.52 nm
Which of the following statements describes the law of inertia?
O A. The force of friction on an object is proportional to the normal
force.
O B. Objects remain in the same state of motion unless a force acts on
them
O c. For every action force there is an equal and opposite reaction
force.
D. Net force is equal to mass times acceleration
Answer:
B. objects remain in the same state of motion unless a force acts on them
Explanation:
Sana nakatulong
Answer: B) objects remain in the same state of motion unless a force acts on them
Explanation:
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The net force on a body = mass of object × acceleration of the object
The first option "Objects remain in the same state of motion unless a force acts on them" is an implication of the first law of motion .
The second option "For every action force there is an equal and opposite reaction force" is an implication of the third law of motion.
The last option from the given list "Net force is equal to mass times acceleration" is an implication of the second law of motion.
do fish get thirsty????
Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.00R from the disk. Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.00 . Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what percentage will you decrease the electric field magnitude at P?
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
[tex]\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)[/tex])
[tex]\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)[/tex]
Similarly;
[tex]\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)[/tex]
However; the relative difference is: [tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}[/tex]
[tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}[/tex]
[tex]= 0.2828 \\ \\ \mathbf{\simeq 29\%}[/tex]
A train is travelong at 22 m/s when the condutor gets a radio call about a car stalled on the tracks. He hits the emergancy brake and the train comes to a halt in 135 sevonds several meters before the car. What was the train's accleration during the emergency?
Answer:
final velocity = 0
because the train stoped
so,
acceleration = (v - u) ÷ tacceleration = (0 - 22) ÷ 135acceleration = -22 ÷ 135acceleration = -0.162 m/s²A 1.8-kg object is attached to a spring and placed on frictionless, horizontal surface. A force of 40 N stretches a spring 20 cm from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations. a) Find the force constant of the spring. b) Find the total energy of the oscillating system. c) Where will the object be from the equilibrium position when its velocity is -2.0 m/s (negative 2 m/s)
Answer:
a) k = 200 N/m
b) E = 4 J
c) Δx = 6.3 cm
Explanation:
a)
In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:[tex]F = - k * \Delta x (1)[/tex]
where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).Solving for k:[tex]k =- \frac{F}{\Delta x} =-\frac{40 N}{-0.2m} = 200 N/m (2)[/tex]
b)
Assuming no friction present, total mechanical energy mus keep constant.When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:[tex]U = \frac{1}{2}* k* (\Delta x)^{2} (3)[/tex]
Replacing k and Δx by their values, we get:[tex]U = \frac{1}{2}* k* (\Delta x)^{2} = \frac{1}{2}* 200 N/m* (0.2m)^{2} = 4 J (4)[/tex]
c)
When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).So, we can write the following expression:[tex]\frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2} = \frac{1}{2}*k*\Delta x^{2} (5)[/tex]
Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:[tex]\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2} = 4J (6)[/tex]
⇒ [tex]\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} = 4J - 3.6 J = 0.4 J (7)[/tex]
⇒ [tex]\Delta x_{1} = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)[/tex]
Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a concave line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds positive number of meters downward to some later time 0 meters.
It's the one that has a concave line running upward.
Answer:
its the middle one
Explanation:
i did it on edge 2021
Tin is more active than lead.
O A. True O B. False
Answer:
It would be false
Explanation:
Lead is more reactive if thats what you mean
8. Cart 1 with mass of 2kg moving at +6m/s collides with cart 2 with a mass of 1kg,
which is at rest. If cart 1 moves at +2m/s after the collision, what is the velocity of
cart 2 after the collision? (include correct units, or you get no credit)
Answer:its 2kg
Explanation:
Two vehicles are approaching an intersection. One is a 2600 kgkg pickup traveling at 17.0 m/sm/s from east to west (the −x−x- direction), and the other is a 1300 kgkg sedan going from south to north (the +y−+y− direction at 24.0 m/sm/s ). Part A Find the xx -component of the net momentum of this system. pxpx = nothing kg⋅m/skg⋅m/s SubmitRequest Answer Part B Find the yy-component of the net momentum of this system. pypy = 0 kg⋅m/skg⋅m/s SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C What is the magnitude of the net momentum?
Answer:
a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) the magnitude of the net momentum is 54102.5 kgm/s
Explanation:
Given the data in the question;
a) x-component of the net momentum of this system.
the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up
so;
Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]
Px = 44200 kgm/s [tex](-x)[/tex]
Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) y-component of the net momentum of this system
Also, momentum along y-axis is entirely provided by the sedan
Py = 1300 kg × 24.0 m/s [tex](y)[/tex]
Py = 31200 kgm/s [tex](y)[/tex]
Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) magnitude of the net momentum?
magnitude of the net momentum P = √( Px² + Py² )
so we substitute
P = √( (44200)² + (31200)² )
P = √( 2927080000 )
P = 54102.5 kgm/s
Therefore, the magnitude of the net momentum is 54102.5 kgm/s
On a distance-time graph, what is shown when the curve is flat going from left to the right?
A. a negative speed
B. no speed
C. a positive speed
D. It does not mean anything.
Answer:
The aswers is C
Explanation:
What do all clouds contain the some amount of
Answer:
A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud.
Explanation:
How do these terms relate to what is being attempted when making a nuclear
bomb (quick, explosive effect) as opposed to a nuclear power plant (controlled
steady production of energy)?.
Answer:
More than four-fifths of the single points of light we observe in the night sky are actually two or more stars orbiting together. The most common of the multiple star systems are binary stars, systems of only two stars together.o
According to Newton's law of cooling, the rate at which an object's temperature changes is directly proportional to the difference in temperature between the object and the surrounding medium. If T(t) represents the temperature of the object (CC) at time t (in hours), and T5 represents the constant temperature of the surrounding medium, then the differential equation best describing the rate of change in the temperature of the object is:
Answer:
dT(t)/dt = k[T5 - T(t)]
Explanation:
Since T(t) represents the temperature of the object and T5 represents the temperature of the surroundings, according to Newton's law of cooling, the rate at which an object's temperature changes is directly proportional to the difference in temperature between the object and the surrounding medium, that is dT(t)/dt ∝ T5 - T(t)
Introducing the constant of proportionality
dT(t)/dt = k[T5 - T(t)]
which is the desired differential equation
Answer:
dT/dt = k[T5 - T]
Explanation:
DT/dt represents rate of change in temperature for Celsius degrees per hour. Its proportional to the difference in temperature between the object and the Surrounding medium. This means either dT/Dt =k (T-TS) or dT/dt=k(TS-T) with k being some positive constant of proportionality which depends on the object.
We can see that dT/dt = k(T-T5) has temperature increasing when the temperature of the object T is greater than the surrounding medium (T5).
The equation dT/dt=k(T5-T) has the temperature increasing when the object (T) is less than the temperature of the surrounding medium. Therefore the differential equation best describing the rate of change in temperature of the object is dT/dt=k(T5-T) for some positive constant of proportionality k.
A motorcyclist is moving 24.5 m/s
away from a stationary siren, and
hears an 894 Hz sound. What is
the frequency of the siren when the
cyclist is stationary?
(Hint: 894 Hz is the Doppler-shifted
frequency)
(Speed of sound = 343 m/s)
(Unit = Hz)
w
Answer:962 hz
Explanation: got it right on acellus
The frequency of the siren when the cyclist is stationary will be 963 Hz.
What is frequency ?The frequency of a wave is the number of cycles per second.
FRom the doppler effect,
f =f'[ (V+Vs/V-Vo) ]
Here, doppler shifted frequency f' = 894 Hz, Source is stationary, Vs =0. Velocity of observer Vo = 24.5m/s and velocity of sound wave V = 343m/s
Substitute the value into the expression , we get
f = 894 x [(343/343 - 24.5)}
f = 963 Hz
Thus, the frequency of the siren when the cyclist is stationary is 963 Hz.
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